Answer:
The answer is B: ( g o f) (x) = ( x + 1)^2
Explanation:
⟹ (g ∘ f) (x) = g [f (x)]
Replace x in g(x) = x^2 with x+1
= ( x + 1 ) ^2
help please anyone ??
find t =?
please help me
Answer:
−7.361097448
Step-by-step explanation:
Find the particular solution of the differential equation passing through the given point.
(1+x2)dy=(x+1)ydx,(2,2)
Try this option, the answer is marked with red colour.
A news report suggested that an adult should drink a minimum of 4 pints of water per day.
Based on this report, determine the minimum amount of water an adult should drink,
in fluid ounces, per week.
9514 1404 393
Answer:
448
Step-by-step explanation:
(4 pt/da)×(7 da/wk)×(16 oz/pt) = 448 oz/wk
That would be 448 fluid ounces per week.
Could anyone help me please?
9514 1404 393
Answer:
4
Step-by-step explanation:
In order to evaluate f(g(-1)), you first need to find g(-1).
The graph of g(x) crosses the line x = -1 at y = 1, so g(-1) = 1.
The second step is evaluating f(1). The graph of f(x) crosses the line x=1 at y=4, so f(1) = 4.
f(g(-1)) = f(1) = 4
9.
slove this question
Answer:
[tex]\sqrt{x^2 + y^2}[/tex]
Step-by-step explanation:
to find diatance between AB
A(0 , 0) = (x1 , y1)
B(x , y) = (x2 , y2)
distance formula = [tex]\sqrt{(x2 - x1)^2 + (y2 - y1)^2}[/tex]
=[tex]\sqrt{(x - 0)^2 + (y - 0)^2}[/tex]
=[tex]\sqrt{x^2 + y^2}[/tex]
Find area of ABC. Plz help !!!
The hypotenuse of a right triangle is 13 ft long. The longer leg is 7 ft longer than the shorter leg. Find the side lengths of the triangle.
Answer:
The shorter leg is five feet, the longer leg is 12 feet, and the hypotenuse is 13 feet.
Step-by-step explanation:
Let the shorter leg be x.
Since the longer leg is seven feet longer than the shorter leg, the length of the longer leg can be modeled by (x + 7).
Since the triangle is a right triangle, we can use the Pythagorean Theorem, given by:
[tex]a^2+b^2=c^2[/tex]
Where a and b are the side lengths and c is the hypotenuse.
The hypotenuse is 13 and the legs are x and (x + 7). Substitute:
[tex](x)^2+(x+7)^2=(13)^2[/tex]
Square:
[tex]x^2+x^2+14x+49=169[/tex]
Simplify:
[tex]2x^2+14x-120=0[/tex]
We can divide both sides by two:
[tex]x^2+7x-60=0[/tex]
Factor:
[tex](x-5)(x+12)=0[/tex]
Zero Product Property:
[tex]x-5=0\text{ or }x+12=0[/tex]
Solve for each case:
[tex]x=5\text{ or } x=-12[/tex]
Since lengths cannot be negative, we can ignore the negative answer. So, our only solution is:
[tex]x=5[/tex]
The shorter leg is five feet, the longer leg will be (5 + 7) or 12 feet. And the hypotenuse is 13 feet as given.
What is the value of this number in decimal form?
Three hundred sixty-seven thousandths.
Step-by-step explanation:
the other answer is correct.
just for a little bit of explanation :
the first position after the decimal point is for tenths. the second position for hundredths. the third for thousandths. then ten-thousandths, hundred-thousandths, millionths, ...
so, you would need 1000 thousandths to have a 1 at the first position before the decimal point. everything less than that has to be a number after the decimal point. and thousandths have to end (writing from left to right) with the thousandths-position. hundredths with the hundredths-position and so on.
If M is the midpoint of AB, find the coordinates of A if M(-3, 5) and B(6, -11)
midpoint= (x, y)
where x=(x1 + x2)/2
y=(y1 + y2)/2
x1=-3, x2=6, y1=5, y2=-11
so x=(-3 + 6)/2= 3/2
y=(5 + -11)/2= (5-11)/2= -6/2= -3
so mid point =(3/2, -3)
hope this helps
the volume of a cone with a radius of 6 and slant height of 10
Answer:
21.161
Step-by-step explanation:
use Pythagoras theorem ti find your slant height
then you use your formula which
[tex]1 \3\pi {r }^{2} h[/tex]
Question 2
Find the volume.
Answer:
Volume of cone = 686π/3 or 718.67 in³
Step-by-step explanation:
Given the following data;
Radius, r = 7 in
Height, h = 14 inches
From the diagram, we can see that the object is a cone
To find the volume of a cone;
Mathematically, the volume of a cone is given by the formula;
[tex] V = \frac{1}{3} \pi r^{2}h[/tex]
Where;
V is the volume of the cone.
r is the radius of the base of the cone.
h is the height of the cone.
Substituting into the equation, we have;
[tex] Volume = \frac{1}{3} * \frac {22}{7} *7^{2}*14 [/tex]
[tex] Volume = \frac{1}{3} * 22 * 7 * 14 [/tex]
[tex] Volume = \frac{1}{3} * 2156 [/tex]
[tex] Volume = 718.67 [/tex]
Volume of cone = 718.67 in³ or 686π/3 in³
Cells use the hydrolysis of adenosine triphosphate, abbreviated as ATP, as a source of energy. Symbolically, this reaction can be written asATP(aq)+H2O(l)⟶ADP(aq)+H2PO−4 (aq)where ADP represents adenosine diphosphate. For this reaction, ΔG∘=−30.5kJ/mol.a. Calculate K at 25∘C .b. If all the free energy from the metabolism of glucoseC6H12O6(s)+6O2(g)⟶6CO2(g)+6H2O(l)goes into forming ATP from ADP, how many ATP molecules can be produced for every molecule of glucose?
Answer:
Step-by-step explanation:
From the given information:
ΔG° = -30.5 kJ/mol
By applying the following equation to calculate the value of K.
ΔG° =-RT㏑K
making ㏑ K the subject of the formula:
[tex]\mathtt{ In \ K} = \dfrac{\Delta G^0}{-RT}[/tex]
where;
Temperature at 25° C = (25 + 273)K
= 298K
R = 8.3145 J/mol.K (gas cosntant)
[tex]\mathtt{ In \ K} = \dfrac{-30.5 \times 10^{3}\ J /mol} {-(8.3145 \ J/mol. K \times 298 \ K}[/tex]
[tex]\mathtt{ In \ K} = \dfrac{-30.5 \times 10^{3}\ J /mol} {-2477.721 J/mol }[/tex]
㏑K = 12.309
[tex]K = e^{12.309}[/tex]
K = 221682.17
K = 2.22 × 10⁵
b) The reaction for the metabolism of glucose is given as:
[tex]C_6H_{12} O_6 + 6O_{2(g)} \to + 6CO_{2(g)} + 6H_2O_{(l)}[/tex]
From the above expression, let calculate the Gibbs free energy by using the formula:
[tex]\Delta G^0_{rx n }= \Delta G^0_{product}- \Delta G^0_{reactant}[/tex]
[tex]\Delta G^0_{rx n }= [6 \times \Delta G^0_{f}(CO_2) + 6 \times \Delta G^0_{f}(H_2O)] - [1 \times \Delta G^0_{f}(C_6H_{12}O_6) + 6 \times \Delta G^0_{f}(O_2)][/tex]
At standard conditions;
The values of corresponding compounds are substituted into the equation above:
Thus,
[tex]\Delta G^0_{rx n }= [6 \times (-394) + 6 \times (-237)] - [1 \times (-911) + 6 \times (0)] \ kJ/mol[/tex]
[tex]\Delta G^0_{rx n }= [-2364-1422] - [-911+0] \ kJ/mol[/tex]
[tex]\Delta G^0_{rx n }= -3786 +911 \ kJ/mol[/tex]
[tex]\Delta G^0_{rx n }= -2875 \ kJ/mol[/tex]
[tex]\Delta G^0_{rx n }= -2875000 \ J/mol[/tex]
Now, the no of ATP molecules generated = [tex]\dfrac{\Delta G^0 \text{of metabolism for glucose}}{\Delta G^0 \text{of hydrolysis for ATP}}[/tex]
= (-2875000 J/mol ) / -30500 J/mol
= 94.26
≅ 94 ATP molecules generated
You purchase a painting for 9,000 that has an appreciation rate of 12%. What is the growth
factor?
Answer:
Step-by-step explanation:
Answer:
$1080
Step-by-step explanation:
I think I am not sure
Help troll or report Help plsssss
Answer:
11. (a) 3/4+1/2=5/4
(b) 4/5= 8/10 , 16/20
12. 8 children don't like choc ice cream
Step-by-step explanation:
11. 3/4 +2/4=5/4(change 1/2 by making it the same as the one next to it)
12. 3/5 of 20 = 12
20-12=8
A bag of candy has equal numbers of candies in eight colors: blue, red,
brown, green, yellow, orange, pink, and black. If you eat them one by one,
what's the probability of getting your first red candy on or before the fifth
pick?
Answer:
the answer would be b I'm pretty sure
Find an equation of the circle that satisfies the given conditions. (Use the variables x and y.)
Center at the origin;
passes through (4, 6)
Answer:
[tex]x^2 + y^2 = 52[/tex]
Step-by-step explanation:
Distance between two points:
Suppose that we have two points, [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]. The distance between them is given by:
[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Equation of a circle:
The equation of a circle with center [tex](x_0,y_0)[/tex] and radius r has the following format:
[tex](x - x_0)^2 + (y - y_0)^2 = r^2[/tex]
Center at the origin;
This means that [tex]x_0 = 0, y_0 = 0[/tex]
So
[tex](x - x_0)^2 + (y - y_0)^2 = r^2[/tex]
[tex](x - 0)^2 + (y - 0)^2 = r^2[/tex]
[tex]x^2 + y^2 = r^2[/tex]
Passes through (4, 6)
The radius is the distance from this point to the center. So
[tex]r = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex]r = \sqrt{(4-0)^2+(6-0)^2}[/tex]
[tex]r = \sqrt{16+36}[/tex]
[tex]r = \sqrt{52}[/tex]
So
[tex]r^2 = 52[/tex]
Then
[tex]x^2 + y^2 = r^2[/tex]
[tex]x^2 + y^2 = 52[/tex]
In 42 - 15 = 27, the number 42 is called the
the number 15 is called the
and the number 27 is called
Answer:
The Answer to the Ultimate Question of Life, the Universe, and Everything is 42
Step-by-step explanation:
In this equation, the number 42 is called a minuend.
15 is a subtrahend because it is being subtracted from another number.
The number 27 would be called the difference.
Pls help luv y’a thx
If you are just given the two points it is the same formula. Find the midpoint between the points (4,-5) and (-4,5)
mid point =((4+(-4))/2,(-5+5)/2)
=(0,0)
The midpoint between the points (4, -5) and (-4, 5) is (0, 0).
To find the midpoint between two points ([tex]x_1, y_1[/tex]) and ([tex]x_2, y_2[/tex]), you can use the midpoint formula:
Midpoint = [tex]((x_1+ x_2)/2, (y_1+ y_2)/2)[/tex]
In this case, the two points are (4, -5) and (-4, 5).
So, the midpoint using the formula:
[tex]x_1[/tex] = 4
[tex]y_1[/tex] = -5
[tex]x_2[/tex]= -4
[tex]y_2[/tex] = 5
Midpoint
= ((4 + (-4)) / 2, (-5 + 5) / 2)
= (0 / 2, 0 / 2)
= (0, 0)
Therefore, the midpoint between the points (4, -5) and (-4, 5) is (0, 0).
Learn more about midpoint here:
https://brainly.com/question/24089949
#SPJ2
Surface Area of a Triangular Pyramid, please help!
Answer:
surface area of the triangular pyramid
=(1/2×9×7.8)+(3×1/2×9×12.3)
=35.1+166.05
=201.15 inch²
What’s the ara of each figure?
Answer:
433 in.²
Step-by-step explanation:
Divide the figure into 2 rectangles
Area of the figure = area of the bigger rectangle + area of smaller rectangle
✔️Area of bigger rectangle = L*W
L = 29 in.
W = 13 in.
Area of the bigger rectangle = 29*13
= 377 in.²
✔️Area of the smaller rectangle = L*W
L = 7 in.
W = 8 in.
Area of the bigger rectangle = 7*8
= 56 in.²
✅Area of the figure = 377 + 56 = 433 in.²
Answer to the question
Answer:
x = 4
Step-by-step explanation:
180 = 102 + 24x - 18
102 - 18 = 84subtract 84 from both sides96 = 24xdivide both sides by 44 = xA Driver’s Ed program is curious if the time of year has an impact on number of car accidents in the U.S. They assumethat weather may have a significant impact on the ability of drivers to control their vehicles. They take a randomsample of 150 car accidents and record the season each occurred in. They found that 27 occurred in the Spring, 39 inthe Summer, 31 in the Fall, and 53 in the Winter.
Required:
Can it be concluded at the 0.05 level of significance that caraccidents are not equally distributed throughout the year?
Answer:
p-value = 0.0145
Hence, Since p-value ( 0.0145 ) is less than significance level ( 0.05 )
we reject null hypothesis.
Therefore, there is sufficient evidence to conclude that Car accidents are NOT equally distributed throughout the year
Step-by-step explanation:
Given the data in the question;
Hypothesis;
Null hypothesis : H₀ : Car accidents are equally distributed throughout the year
Alternative hypothesis : Hₐ : Car accidents are NOT equally distributed throughout the year
significance level ∝ = 0.05
x ;
Spring = 27
Summer = 39
Fall = 31
Winter = 53
Test Statistics;
Chi Square = ∑[ (O – E)²/E ]
O E (O – E)²/E
Spring 27 37.4 2.94
Summer 39 37.4 0.06
Fall 31 37.4 1.1267
Winter 53 37.4 6.4067
Total 150 150 10.5334
so; z = ∑[ (O – E)²/E ] = 10.5334
{from table}
p-value = 0.0145
Hence, Since p-value ( 0.0145 ) is less than significance level ( 0.05 )
we reject null hypothesis.
Therefore, there is sufficient evidence to conclude that Car accidents are NOT equally distributed throughout the year
In this exercise we have to use probability knowledge to calculate the distribution during the year, so we find that:
There is sufficient evidence to conclude that car accidents are not equally distributed throughout the year.
Given the data in the question;
[tex]Null \ hypothesis: H_0[/tex][tex]Alternative \ hypothesis : H_a[/tex] [tex]Significance\ level = 0.05[/tex]Now the values given in the statement can be exemplified below as:
[tex]Spring = 27[/tex][tex]Summer = 39[/tex][tex]Fall = 31[/tex][tex]Winter = 53[/tex]In this way, we can assemble a table of values with the statistical data previously informed and using the formula given below:
[tex]Z=\sum[\frac{(O-E)^2}{E}][/tex]
[tex]Z = 10.5334[/tex]
So:
[tex]\ \ \ \ \ \ \ \ \ \ \ O \ \ \ \ \ E \ \ \ \ (O - E)^2/E\\Spring \ \ 27 \ \ 37.4 \ \ \ \ 2.94\\Summer \ 39 \ 37.4 \ \ \ \ 0.06\\Fall \ \ \ \ \ \ 31 \ 37.4 \ \ \ \ 1.1267\\Winter \ \ \ 53 \ 37.4 \ \ \ 6.4067\\Total \ 150 150 \ 10.5334[/tex]
Hence, Since pvalue ( 0.0145 ) is less than significance level ( 0.05 ), so we reject null hypothesis.
See more about probability at brainly.com/question/795909
Plz help I’ll award brainliest!!!
That is the same as writing [tex]10\sqrt{30}[/tex]
======================================================
Explanation:
The diagram shows that
AC = 60AD = 50That must mean DC = AC-AD = 60-50 = 10
We'll use this to help find BD as shown below
AD/BD = BD/DC
AD*DC = BD*BD .... cross multiply
(BD)^2 = AD*DC
BD = sqrt(AD*DC) ..... geometric mean formula
BD = sqrt(50*10)
BD = sqrt(500)
----------------------
Now apply the pythagorean theorem to find AB. Focus on triangle ABD.
(AD)^2 + (BD)^2 = (AB)^2
(AB)^2 = (AD)^2 + (BD)^2
(AB)^2 = (50)^2 + (sqrt(500))^2
(AB)^2 = 2500 + 500
(AB)^2 = 3000
AB = sqrt(3000)
AB = sqrt(100*30)
AB = sqrt(100)*sqrt(30)
AB = 10*sqrt(30)
Austin was budgeted $ 825 to spend on chairs for his upcoming event. If each chair costs $ 15 , how many chairs can he purchase?
Answer:
55 chairs
Step-by-step explanation:
825/15=55
I need help with this problem-
Answer:
wat
Step-by-step explanation:
What is the slope of a line perpendicular to the line containing the points (4,-7) and (-5,-1)? Express your answer as a common fraction.
40 POINTS!!!!!!
if not right i report
Answer:
3/2
Step-by-step explanation:
Slope 1 = (-1+7)/(-5-4) = 6/(-9) = -2/3
Slope 2 perpendicular to Slope 1 :
-1 ÷ -⅔ = 3/2
an arrow is shot vertically upward from a platform 33ft high at a rate of 174 ft/sec. when will the arrow hit the ground?
Answer:
h(t) = -16t2 + 186t + 43
at the ground h = 0
hence; -16t2 + 186t + 43 = 0
solving this quadratic equation using the quadratic formula ; a = -16, b = 186, c = 43 ; x = (-b +-(b2 - 4ac)1/2)/2a
gives t = 11.8 seconds to the nearest tenth (note that the negative root has no practical significance)
Step-by-step explanation:
Canterbury Cycles sells Harleys and pays each salesperson a commission of $800 for each cycle sold. During the month of December, a salesperson sold 3 cycles. The company pays commissions on the 5th day of the month following the sale. Which of the following statements is true?a. The salesperson will recognize commission revenue earned in the amount of 2400 in Decemberb. The company will recognize commission expense in the amount of $2,400 in December.c. The salesperson will recognize commission expense in the amount of $2,400 in January.d. The salesperson will recognize revenue in the same month that the cycle dealer recognizes expense.
Answer: The company will recognize commission expense in the amount of $2,400 in December
Step-by-step explanation:
Based on the information given in the question, the company will recognize commission expense in the amount of $2,400 in December.
A commission is regarded as a fee which is paid to a salesperson by a company in exchange for completing a sale.
It should be noted that in the accrual basis of accounting, commission should be recorded in the same period as when the sale generated was generated.
Answer:
b. The company will recognize commission expense in the amount of $2,400 in December.
Step-by-step explanation:
Based on the information given the statements that is true will be: THE COMPANY WILL RECOGNIZE COMMISSION EXPENSE IN THE AMOUNT OF $2,400 IN DECEMBER reason been that each salesperson were paid a commission in the amount of $800 for each cycle sold, which is 3 cycles during the month of December.
Calculation to determine the Commission Expense
Commission Expense=$800*3 cycles
Commission Expense=$2,400
Therefore The company will recognize commission expense in the amount of $2,400 in December.
