Answers
Related Questions
When dribbling you should?
a. Use both feet.
b.Use frequent small touches of the ball.
C.Protect the ball with your body.
D. All of the above.
Answers
1. Which elements would likely have similar properties: two elements in the same group, or two elements in the same period?
2. Fill in the table below with the correct classification of element.
Left side:
Right side:
Zigzag line:
3. Use the periodic table to answer this question: Are the properties of rubidium (Rb) more like those of cesium (Cs) or those of strontium (Sr)? Explain your answer.
4. Use the periodic table at the bottom of the page to identify the elements in the following compounds:
PBS:
KBr:
Rao:
5. Use the periodic table to determine whether each element is a metal or a nonmetal:
Sodium (Na):
Krypton (Kr):
Phosphorus (P):
Answers
Answer:
3. Cs, they are in the same group, mainly sharing characteristics.
Explanation:
The elements in the same group have similar properties. The properties of rubidium is similar to those of strontium because, both are in second group.
What are groups in periodic table ?In periodic table, all elements are classified into different periods and groups. The vertical columns in the table is called groups and the horizontal rows are called periods.
The elements in a group have same number of valence electrons and similar chemical and physical properties. For example rubidium and strontium are second group elements and they show similarity in properties.
The elements in the compound, PbS are lead and sulphur and that in KBr are potassium and bromine. Elements in RaO are radium and oxygen. Among the given elements sodium is a metal and krypton and phosphorus are non metals or gases.
Find more on periodic table:
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Please help me and I will mark you the brainiest
Answers
Answer:
Right direction (i.e towards B).
Explanation:
From the question given above, we can see that the car is accelerating in the left direction (i.e towards D).
Friction is the force that tends to oppose the motion of an object. Since the car is moving in the left direction (i.e towards D) then, the frictional force acting on the wheel will be in the opposite direction i.e right direction (i.e towards B).
What is the speed of a car that
accelerates at a rate of 10 m/s2 for a
total of 25 seconds?
Answers
Answer:
250 m/sExplanation:
The speed of the car can be found by using the formula
v = a × twhere
a is the acceleration
v is the speed
t is the time
From the question we have
v = 10 × 25
We have the final answer as
250 m/sHope this helps you
when a car suddenly stops,the objects in the backseat are thrown forward.this is explained by-
A.Newton's first law of motion
B.Newton's second law of motion
C.Newton's third law of motion
D.the universal law of gravitation
Answers
Answer:law of interia(1st law)
Explanation:
Write an equation of the line in slope-intercept form.
Please explain.
Answers
Answer:
y = [tex]-\frac{1}{4}[/tex]x + 3
Explanation:
The equation of a straight line is given as:
y = mx + c
y and x are the coordinates
m is the slope
c is the y -intercept
The y-intercept = 3;
Slope = [tex]\frac{y_{2} - y_{1} }{x_{2} - x_{1} }[/tex]
x₁ = 0
x₂ = 4
y₁ = 3
y₂ = 2
Slope = [tex]\frac{2-3}{4 -0 }[/tex] = [tex]-\frac{1}{4}[/tex]
y = mx + c
y = [tex]-\frac{1}{4}[/tex]x + 3
On the moon, the gravity is 1/6 that of Earth. While on the moon, Buzz Aldrin carried on his back a support system that would weigh over 1760 N on Earth. a) What did the backpack weigh on the moon? b) What was its mass on the moon? please show the work
Answers
Answer:
a) 293.[tex]\bar 3[/tex] N
b) Approximately 179.41 kg
Explanation:
The given parameters are;
The gravity (gravitational acceleration) on the moon = 1/6 × The gravity on Earth
The weight of the support system Buzz Aldrin carries = 1760 N
a) Given that the weight of the support system on Earth = Mass of the support system, m × Gravity, g (Acceleration due to gravity) = m·g
The weight of the support system on Earth = m·g
We have;
The gravity on the moon = 1/6 × g
∴ The weight of the support system on the moon = Mass of the support system, m × 1/6 × g = m·g/6
∴ The weight on the of the support system on the moon = m·g/6 = 1/6 × m·g = 1/6 × m·g = 1/6 × The weight of the support system on Earth
The weight on the of the support system on the moon = 1/6 × 1760 N = 880/3 N = 293.[tex]\bar 3[/tex] N
b) The mass, m, of the support system on the moon = The mass, m, of the support system on Earth
The mass, m, of the support system on Earth = Weight of the support system/(Gravity(acceleration due to gravity))
∴ The mass, m, of the support system on Earth = 1760/9.81 ≈ 179.41 kg
∴ The mass, m, of the support system on the moon ≈ 179.41 kg.
can someone help rn please!! thank you sm!!
Answers
Mass is the measure of its resistance to acceleration when net force is applied
Pounds and Kilograms definitely cannot be the answer
So the only logical answer is weight
Hope this helps
A man travels 25 kilometers in 15 minutes. A police officer stops him and
writes a ticket for speeding. The posted speed limit is 80 kilometers per
hour. Did the man exceed the posted speed limit?
Answers
Answer:
yes
Explanation:
cuz 15x2=30 30x2=60 60=1 hour, and the limited is 80 km per hour
15=25
15x4=60 25x4=100
so yes
he was going 100km per hour
PLZ EXPLAIN THE EQUATION AND I WILL GIVE BRAINLIST You are out and about in the country and your father sees a rock that he really wants in the yard. Now you must get the very heavy rock into the back of a truck. The truck bed is 3 feet off the ground. Your father pulls out a 5-foot plank and begins to set up a ramp. At the same time, you (who know about mechanical advantage!) have found a plank that is 8 feet long, and you show it to your father. Which plank will give you the most mechanical advantage? Calculate the MA for each plank
Answers
Answer:
The 8 foot long plank
Explanation: hope this helps :)
Los satélites de televisión giran alrededor de la Tierra en una órbita de 42370 km de radio. a) ¿Cuánto vale la aceleración de la gravedad en esa órbita? (Resultado: g = 0,22 m/s2 ) b) ¿Cuánto pesará allí un satélite de 1200 kg? (Resultado: P = 264 N) Datos: G = 6,67 10-11 Nm2 /kg masa de la Tierra: 6 1024 kg
Answers
Answer:
(a) La aceleración de la gravedad en esa órbita es 0.22 [tex]\frac{m}{s^{2} }[/tex]
(b) Un satélite de 1,200 kg pesará allí 264 N.
Explanation:
(a) Cada punto del espacio tiene un valor del campo proporcional a la función, siguiendo el modelo de gravitación de Newton:
[tex]g=G*\frac{m}{r^{2} }[/tex]
donde m será masa, r la distancia entre los objetos y G la constante de gravitación universal, cuyo valor es [tex]G=6.672*10^{-11}\frac{N*m^{2} }{kg }[/tex]
En este caso:
m= 6*10²⁴ kgr=42,370 km= 42,370,000 mReemplazando:
[tex]g=6.672*10^{-11}\frac{N*m^{2} }{kg }*\frac{6*10^{24}kg }{(42,370,000 m)^{2} }[/tex]
Resolviendo, obtenes:
g= 0.22 [tex]\frac{m}{s^{2} }[/tex]
La aceleración de la gravedad en esa órbita es 0.22 [tex]\frac{m}{s^{2} }[/tex]
(b) La ley fundamental de la dinámica o segunda ley de Newton expresa que la fuerza neta que es aplicada sobre un cuerpo es proporcional a la aceleración que adquiere en su trayectoria. Esto se expresa matemáticamente como:
F= m*a
en donde F es fuerza neta , m la masa y a la aceleración.
El peso es la fuerza que ejerce la gravedad sobre una masa, por lo que se obtiene de manera análoga a la fuerza:
P=m*g
En este caso la masa m tiene un valor de 1,200 kg y la gravedad g un valor de 0.22 [tex]\frac{m}{s^{2} }[/tex].
Reemplazando:
P=1,200 kg*0.22 [tex]\frac{m}{s^{2} }[/tex]
Resolviendo:
P= 264 N
Un satélite de 1,200 kg pesará allí 264 N.
20. Show that an acceleration of 0.67 m/s/s is the result if a force of 1000N is exerted on a 1500 kg
car.
Answers
Explanation:
Given parameters:
Mass of the car = 1500kg
Force applied = 1000N
Acceleration = 0.67m/s²
Unknown:
Proof that the acceleration will result from the applied force on the car
Solution:
According to newton's second law of motion,
Force = mass x acceleration
So;
Acceleration = [tex]\frac{Force }{mass}[/tex]
Now insert the parameters and solve;
Acceleration = [tex]\frac{1000}{1500}[/tex] = 0.67m/s²
We have shown that the acceleration is 0.67m/s²
When the energy of a wave increases, what happens to the amplitude?
Answers
Answer:
The energy transported by a wave is directly proportional to the square of the amplitude. So whatever change occurs in the amplitude, the square of that effect impacts the energy. This means that a doubling of the amplitude results in a quadrupling of the energy.
Explanation:
When the energy of a wave increases, the amplitude also increases. This is because the amplitude of the wave is directly proportional to the energy of a wave.
What is the amplitude of a wave?The amplitude of a wave may be defined as the maximum displacement or distance moved by a point on a vibrating body or wave measured from its equilibrium position. It is equal to one-half the length of the vibration path.
It is the principle of physics that when the amplitude of the wave is higher, the energy also gets higher. To summarise, waves carry energy. The amount of energy they carry is related to their frequency and their amplitude. The higher the frequency, the more energy, and the higher the amplitude, the more energy.
Therefore, when the energy of a wave increases, the amplitude also increases. This is because the amplitude of the wave is directly proportional to the energy of a wave.
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Calculate the density of a rock that has a mass of 32 grams and a volume of
4.5 mL.
Answers
Answer:
85.2ml
Explanation:
Adhira loves to ride her bike around the neighborhood. She starts riding 1.2 miles at 30° S of E. Then, she rides another 2.0 miles at 20° W of S. Next, she rides 1.6 miles at 30° S of W. And finally, she rides 2.6 miles at 15° W of N. What is her final displacement from her starting point?
Answers
Answer:
D = 1.8677 miles , θ = 24.28º at South of West
Explanation:
This is an exercise in adding vectors, the easiest way to solve them is to decompose the vectors and add each component algebraically. Let's use trigonometry
first displacement. d = 1.2 miles to 30º south of East
cos ( 360-30) = cos (-30) = x₁ / d
sin (-30) = y₁ / d
x₁ = d cos (-30)
y₁ = d sin (-30)
x₁ = 1.2 cos (-30) = 1,039 miles
y₁ = 1.2 sin (-30) = -0.6 miles
second shift. d = 2.0 miles to 20º West of South
cos (270-20) = x₂ / d
cos (250) = y₂ / d
x₂ = 2.0 cos 250 = -0.684 miles
y₂ = 2.0 sin250 = -1.879 miles
Third displacement. d = 1.6 miles to 30º South of West
cos (180 + 30) = x₃ / d
sin (210) = y₃ / d
x₃ = 1.6 cos 210 = -1.3856 miles
y₃ = 1.6 sin 210 = -0.8 miles
Fourth displacement. d = 2.6 miles to 15º West of North
cos (90 + 15) = x₄ / d
sin (105) = y₄ / d
x₄ = 2.6 cos 105 = -0.6729 miles
y₄ = 2.6 sin 105 = 2,511 miles
having all the components we add
x-axis (West-East direction)
X = x₁ + x₂ + x₃ + x₄
X = 1.039 -0.684 - 1.3846 - 0.6729
X = -1.7025 miles
Y = y₁ + y₂ + y₃ + y₄
Y = -0.6 -1.879 -0.8 +2.511
Y = -0.768
The modulus of this displacement is we use the Pythagorean theorem
D = √ (X² + Y²)
D = √ (1.7025² + 0.768²)
D = 1.8677 miles
let's use trigonometry to find the direction
tan θ = Y / X
θ = tan⁻¹ Y / x
θ = tan⁻¹ (0.768 / 1.7025)
θ = 24.28º
as the two components are negative this angle is in the third quadrant
therefore in cardinal direction form is
θ = 24.28º at South of West
What is the mass of a falling rock if it produces a force of 147 N with an acceleration of 9.8 m/s2?
Answers
Answer:
15 kgExplanation:
The mass of the object can be found by using the formula
[tex]m = \frac{f}{a} \\ [/tex]
f is the force
a is the acceleration
From the question we have
[tex]m = \frac{147}{9.8} \\ [/tex]
We have the final answer as
15 kgHope this helps you
Which statement is supported by the information in the diagram and table below?
Answers
Answer:
a
Explanation:
a
Annie has 100 mL of honey. The honey has a mass of 145 g. What is the density of the honey?
Answers
Answer:
The answer is 1.45 g/mLExplanation:
The density of a substance can be found by using the formula
[tex]density = \frac{mass}{volume} \\ [/tex]
From the question we have
[tex]density = \frac{145}{100} \\ [/tex]
We have the final answer as
1.45 g/mLHope this helps you
Unit 2 kinetic energy mastery test
Answers
Answer: kinetic energy is Energy of motion.
Explanation:
An object with a mass of 15 kg accelerates 10.0 m/s2 when an unknown force is applied to it. What is the
amount of the force
Answers
Answer:
f=mass × acceleration
=15×10
=150
hey pls help with this HDJSJDH im rlly bad at this kinda stuff :,) i'll mark the correct answer brainliest
Answers
The cue exerts force onto the white ball which pushes the blue ball into the direction of the hole.
Answer:
A. Cue, White Ball, Blue Ball
Explanation:
Visualize in which order things are being hit
What role does a resistor play in an electrical circuit
Answers
Answer: It opposes the flow of electrons.
Explanation: just did the quiz on
Answer:
It transforms the electrical energy of the electrons into other forms of energy
Explanation:
did quiz
Which of the following is true regarding mixtures? a. One substance not combined with any other substances. b. Two or more substances physically mixed and can be separated. c. Two or more substances that are impossible to separate d. One substance that forms a compound alone.
Answers
Answer:
aerga
dggzsd
Explanation:
szsdrgzsedg
The mass of the sun is 1.9891030 kg and the mass of the Earth is 5.9721024kg. If the Earth’s acceleration toward the sun is 0.0059 m/s/s, what is the sun’s acceleration toward the Earth?
Answers
Answer:
this is the answer according to my calculations
Explanation:
0.001.9
An unknown substance from planet X has a density of 10 g/mL. It occupies a volume of 80 mL. What is the mass of this unknown substance?
Answers
Answer:
800 mL
Explanation:
D*V=M
You pick out the numbers as well as what it is they represent from the word problem/explanation, then from there plug them in to the equations. Once you do that, you get your product and have the answer.
10*80= 800
A skydiver jumps from a plane and falls for 5 seconds before reaching his terminal velocity. During this 5 seconds interval, describe his acceleration before reaching terminal velocity?
Answers
Answer:
His acceleration during the first five seconds before reaching terminal velocity = (W - D)/m
Explanation:
The terminal velocity is the maximum steady velocity attained by a body falling freely with increasing velocity from rest in a fluid, such as air or water
The net force, F acting on the body falling through the fluid is given as follows;
F = Weight force, W, from gravity - Drag force, D, from the fluid
F = W - D
Given that F = Mass, m × Acceleration, a, we have;
F = m × a
The acceleration, a = F/m = (W - D)/m
His acceleration during the first five seconds before reaching terminal velocity = (W - D)/m.
A 5.0kg concrete block accelerates down a 34 degree slope at 4.2 m/s^2. Find the Coefficient of friction between the block and the slope.
Answers
Answer:
The coefficient of friction between the block and the slope is 0.16.
Explanation:
We can find the coefficient of friction between the block and the slope by using Newton's second law:
[tex] \Sigma F = ma [/tex]
[tex]P_{x} -\mu N = ma[/tex]
[tex] mgsin(\theta) - \mu mgcos(\theta) = ma [/tex] (1)
Where:
m: is the mass of the block = 5.0 kg
a: is the acceleration = 4.2 m/s²
θ: is the angle = 34°
μ: is the coefficient of friction =?
g: is the gravity = 9.81 m/s²
By entering the above values into equation (1) we have:
[tex] gsin(\theta) - \mu gcos(\theta) = a [/tex]
[tex] \mu = \frac{gsin(\theta) - a}{gcos(\theta)} = \frac{9.81 m/s^{2}*sin(34) - 4.2 m/s^{2}}{9.81 m/s^{2}*cos(34)} = 0.16 [/tex]
Therefore, the coefficient of friction between the block and the slope is 0.16.
I hope it helps you!
HELP PLEASE
A load is a device that changes electrical energy into other forms of energy. Which load converts electrical energy into thermal energy by passing an electric current through a high-resistance material?
A.
Hand-powered generator
B.
Toaster
C.
Fan
D.
Electrical drill
Answers
Answer:
A toaster because you plug it up for electric energy and heat to toast it
What is thought to make the earth behave as if it contained a huge bar magnet?
Answers
Pls I need help ASAP
Answers
Answer:
i dont undertsnad what do u ned hep wit?
Explanation:
