My town has two cell phone providers. The provider Don’tTalkMuch charge is $80 per month plus 1 dollar per hour the provider TalkLots charges $20 per month plus 4 dollars per hour how much do you have to use your phone in a month in order for Don’tTalkMuch’s much is a deal to be better for you?

Answers

Answer 1

Answer:

The author have to use his/her phone less than 20 hours in a month in order for Don’tTalkMuch's is a deal to be better than TalkLots's is.

Step-by-step explanation:

Call X is the number of hours that the author uses on monthly basis.

Total bill value if the author uses Don’tTalkMuch service is $80 + $1 X.

Total bill value if the author uses TalkLots service is $20 + $4X

The total fees between 2 providers equal as:

$80 + $1 X = $20 + $4X => 3X = $60 => X = 20

Hence: The author have to use his/her phone less than 20 hours in a month in order for Don’tTalkMuch's is a deal to be better than TalkLots's is.


Related Questions

1. (a) Find the probability that a 90% free-throw shooter makes 10 consecutive free-throws, assuming that individual shots are independent.

Answers

Answer:

[tex]Probability = 0.35[/tex]

Step-by-step explanation:

Given

Probability of success free throw = 90%

Number of throw = 10

Required

Determine the probability of 10 consecutive free throws

Let p represents the given probability

[tex]p = 90\%[/tex]

Convert to decimal

[tex]p = 0.9[/tex]

Let n represents the number of throw

[tex]n = 10[/tex]

Provided that each throw is independent;

The probability of n consecutive free throw is

[tex]p^n[/tex]

Substitute 0.9 for p and 10 for n

[tex]Probability = 0.9^{10}[/tex]

[tex]Probability = 0.3486784401[/tex]

[tex]Probability = 0.35[/tex] (Approximated)

What will be the effect on the graph of y = Ixl if x is replaced with -x?

Answers

Answer:

If x is replaced with -x the graph will stay the same because the absolute value makes 2 values so a negative number and a positive one.

Step-by-step explanation:

Go search it up on desmos.

In the last 10 years, the population of Indonesia has grown at a rate of 1.12% per year to 258,316,051. If this rate continues, what will be the population in 10 more years? Round your answer to the nearest whole number.

Answers

Answer:

Final population after 10 years

= 288911718

Step-by-step explanation:

Present population p = 258,316,051

Rate of growth R%= 1.12%

Number of years t= 10 years

Number of times calculated n = 10

Final population A

= P(1+r/n)^(nt)

A= 258,316,051(1+0.0112/10)^(10*10)

A= 258,316,051(1+0.00112)^(100)

A= 258,316,051(1.00112)^100

A= 258,316,051(1.118442762)

A= 288911717.6

Approximately A= 288911718

Final population after 10 years

= 288911718

Simplify using calculator.. I'm not sure if i am putting it in the calculator right

Answers

Answer: D) 64

You would type in

32^(6/5)

Or you could type in

32^(1.2)

since 6/5 = 1.2

Either way, the final result is 64

Suppose that the function g is defined, for all real numbers, as follows.
find g(-5) g(1) g(4)​

Answers

Answers:g(-5) = 9/4g(1) = 3g(4) = 0

=================================================

Explanation:

The piecewise function shows that we have two cases. Either x = 1 or [tex]x \ne 1[/tex].

If x = 1, then g(x) = 3 as shown in the bottom row. This is why g(1) = 3.

If [tex]x \ne 1[/tex], then g(x) = (1/4)x^2-4

Plug x = -5 into this second definition

g(x) = (1/4)x^2-4

g(-5) = (1/4)(-5)^2-4

g(-5) = (1/4)(25)-4

g(-5) = 25/4 - 4

g(-5) = 25/4 - 16/4

g(-5) = 9/4

Repeat for x = 4

g(x) = (1/4)x^2-4

g(4) = (1/4)(4)^2-4

g(4) = (1/4)(16)-4

g(4) = 4-4

g(4) = 0

The value of the function at x = -5, x = 1, and x = 4 will be 2.25, 3, and 0, respectively.

What is a function?

A function is an assertion, concept, or principle that establishes an association between two variables. Functions may be found throughout mathematics and are essential for the development of significant links.

The functions are given below.

g(x) = (1/4)x² - 4, x ≠ 1

g(x) = 3, x = 1

The value of the function at x = -5 will be given as,

g(-5) = (1/4)(-5)² - 4

g(-5) = 25 / 4 - 4

g(-5) = 6.25 - 4

g(-5) = 2.25

The value of the function at x = 4 will be given as,

g(4) = (1/4)(4)² - 4

g(4) = 16 / 4 - 4

g(4) = 4 - 4

g(4) = 0

The value of the function at x = 1 will be given as,

g(1) = 3

The value of the function at x = -5, x = 1, and x = 4 will be 2.25, 3, and 0, respectively.

More about the function link is given below.

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HELP ASAP ROCKY!!! will get branliest.​

Answers

Answer:

y = 8x + 70

Step-by-step explanation:

Start with the third line.

x = 3, y = 94

Subtract 1 from x and 8 from y:

x = 2, y = 86; this is the second line

Subtract 1 from x and 8 from y:

x = 1, y = 78; this is the first line

Subtract 1 from x and 8 from y:

x = 0; y = 70

For selling 0 games, she earns $70.

y = mx + b

y = mx + 70

For each game she sells, her commission is $8.

y = 8x + 70

If f(x)=ax+b/x and f(1)=1 and f(2)=5, what is the value of A and B?

Answers

Answer:

[tex]\huge\boxed{a=9 ; b = -8}[/tex]

Step-by-step explanation:

[tex]f(x) = \frac{ax+b}{x}[/tex]

Putting x = 1

=> [tex]f(1) = \frac{a(1)+b}{1}[/tex]

Given that f(1) = 1

=> [tex]1 = a + b[/tex]

=> [tex]a+b = 1[/tex]  -------------------(1)

Now,

Putting x = 2

=> [tex]f(2) = \frac{a(2)+b}{2}[/tex]

Given that f(2) = 5

=> [tex]5 = \frac{2a+b}{2}[/tex]

=> [tex]2a+b = 5*2[/tex]

=> [tex]2a+b = 10[/tex]  ----------------(2)

Subtracting (2) from (1)

[tex]a+b-(2a+b) = 1-10\\a+b-2a-b = -9\\a-2a = -9\\-a = -9\\a = 9[/tex]

For b , Put a = 9 in equation (1)

[tex]9+b = 1\\Subtracting \ both \ sides \ by \ 9\\b = 1-9\\b = -8[/tex]

The ages of some lectures are 42,54,50,54,50,42,46,46,48 and 48.Calculate the:
(a)Mean Age.
(b)Standard deviation.

Answers

Answer:

The mean age is 48

The standard deviation is 4

Step-by-step explanation:

The answer is, (a) mean age is 48.

                          (b)  standard deviation is 4.

What is a mean age?Average age of the population calculated as the arithmetic mean.Another parameter determining the average age of the population is the median age.

What does standard deviation of age mean?In general, the standard deviation tells us how far from the average the rest of the numbers tend to be, and it will have the same units as the numbers themselves. If, for example, the group {0, 6, 8, 14} is the ages of a group of four brothers in years, the average is 7 years and the standard deviation is 5 years.

How do you find the mean age?To find the mean add all the ages together and divide by the total number of children.

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Construct a polynomial function with the following properties: fifth degree, 4 is a zero of multiplicity 3, −2 is the only other zero, leading coefficient is 2.

Answers

Answer:

[tex]\Large \boxed{\sf \bf \ \ 2(x-4)^3(x+2)^2 \ \ }[/tex]

Step-by-step explanation:

Hello, please consider the following.

Construct a polynomial function with the following properties...

... fifth degree

It means that the polynomial can be written as below.

[tex]a_5x^5+a_4x^4+a_3x^3+a_2x^2+a_1x+a_0 \ \text{ with }a_5\text{ different from 0}\\\\\text{ or } k(x-x_1)(x-x_2)(x-x_3)(x-x_4)(x-x_5) \\\\ \text{ with k different from 0 and } (x_i)_{1\leqi\leq 5 } \text { are the roots.}[/tex]

... 4 is a zero of multiplicity 3

We can write the polynomial as below.

[tex]k(x-4)(x-4)(x-4)(x-x_4)(x-x_5)=k(x-4)^3(x-x_4)(x-x_5)[/tex]

... −2 is the only other zero

Because this is the only other zero, we can deduce that -2 is a zero of multiplicity 2.

[tex]k(x-4)(x-4)(x-4)(x-x_4)(x-x_5)\\\\=k(x-4)^3(x-(-2))(x-(-2))\\\\=k(x-4)^3(x+2)^2[/tex]

... leading coefficient is 2.

Finally, it means that k = 2 and then the polynomial function is:

[tex]\large \boxed{2(x-4)^3(x+2)^2}[/tex]

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

A nutrition laboratory tested 25 "reduced sodium" hotdogs of a certain brand, finding that the mean sodium content is 310 mg with a standard deviation of 36 mg.
Construct a 95% confidence interval for the mean sodium content of this brand of hot dog and interpret a 95% level of confidence. Show all work

Answers

Answer:

The  95% confidence interval is  [tex]295.9 < \mu< 324.1[/tex]

A   95% level of confidence mean that there is 95%  chance  that the true population mean will be in this interval

Step-by-step explanation:

From the question we are told that

    The sample size is  [tex]n = 25[/tex]

    The mean is  [tex]\= x = 310 \ mg[/tex]

     The standard deviation is  [tex]\sigma = 36 \ mg[/tex]

Given that the confidence level is  95% then the level of significance is mathematically represented as

           [tex]\alpha = 100 - 95[/tex]

=>        [tex]\alpha = 5\%[/tex]

=>        [tex]\alpha = 0.05[/tex]

Next we obtain the critical value of  [tex]\frac{\alpha }{2}[/tex] from the normal distribution table , the value is  

           [tex]Z_{\frac{\alpha }{2} } =Z_{\frac{0.05 }{2} } = 1.96[/tex]

Generally the margin of error is mathematically represented as

        [tex]E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }[/tex]

substituting values

        [tex]E = 1.96 * \frac{36 }{\sqrt{25} }[/tex]

        [tex]E = 14.1[/tex]

The 95% level of confidence interval  is mathematically represented as

      [tex]\= x - E < \mu<\ \= x - E[/tex]

substituting values

     [tex]310- 14.1 < \mu< 310+ 14.1[/tex]

     [tex]295.9 < \mu< 324.1[/tex]

The  95% level of confidence mean that there is 95%  chance  that the true population mean will be in this interval

An architect is designing a gym for a new elementary
school. The gym will be 116 feet long and have an area of
6,960 square feet. What will be the width of the gym?

Answers

The width of the gym will be W=60 feet for the area of 6,960 square feet.

What is area?

Area is defines as the space covered by a surface in the two dimensional plane.

It is given that

Area of the gym =6960 square feet

Width of the gym = ?

Length of the gym=116 feet

The width of the gym will be calculated as

[tex]A=\L\times W\\\\\\6960=116\times W\\\\\\w=\dfrac{6960}{116}=60\ \ Feet[/tex]

hence the width of the gym will be W=60 feet for the area of 6,960 square feet.

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Multiply the following complex numbers:
(7+2i)(2+3i)

Please don’t guess

Answers

Answer:

14 + 25l + 6l^2

Step-by-step explanation:

(7 + 2i) (2 + 3i)

=> 14 + 4l + 21l + 6l^2

=> 14 + 25l + 6l^2

This is the correct answer

14+ 25|+ 6|^2 is the correct answer

The Airline Passenger Association studied the relationship between the number of passengers on a particular flight and the cost of the flight. It seems logical that more passengers on the flight will result in more weight and more luggage, which in turn will result in higher fuel costs. For a sample of 21 flights, the correlation between the number of passengers and total fuel cost was 0.668.


(1)
State the decision rule for 0.10 significance level: H0: Ï â‰¤ 0; H1: Ï > 0 (Round your answer to 3 decimal places.)


Reject H0 if t >
(2)
Compute the value of the test statistic. (Round your answer to 3 decimal places.)


Value of the test statistic

Answers

Answer:

Decision Rule:  To reject the null hypothesis if t > 1.328

t = 3.913

Step-by-step explanation:

The summary of the given statistics include:

sample size n = 21

the correlation between the number of passengers and total fuel cost r = 0.668

(1) We are tasked to state the decision rule for 0.10 significance level

The degree of freedom df = n - 1

degree of freedom df = 21 - 1

degree of freedom df = 19

The  null and the alternative hypothesis can be computed as:

[tex]H_o : \rho < 0\\ \\ Ha : \rho > 0[/tex]

The critical value for [tex]t_{\alpha, df}[/tex]  is  [tex]t_{010, 19}[/tex] = 1.328

Decision Rule:  To reject the null hypothesis if t > 1.328

The test statistics can be computed as follows by using the formula for t-test for Pearson Correlation:

[tex]t = r*\sqrt{ \dfrac{(n-2)}{(1-r^2)}[/tex]

[tex]t = 0.668*\sqrt{ \dfrac{(21-2)}{(1-0.668^2)}[/tex]

[tex]t = 0.668*\sqrt{ \dfrac{(19)}{(1-0.446224)}[/tex]

[tex]t = 0.668*\sqrt{ \dfrac{(19)}{(0.553776)}[/tex]

[tex]t = 0.668*5.858[/tex]

t = 3.913144

t = 3.913    to 3 decimal places

Find the product of
the sum of
3/5 and 1%
and​

Answers

Answer:

3/500

Step-by-step explanation:

3/5 x 1%

=> 3/5 x 1/100

=> 3/500

Hope it helps you

4. The general population (Population 2) has a mean of 30 and a standard deviation of 5, and the cutoff Z score for significance in a study involving one participant is 1.96. If the raw score obtained by the participant is 45, what decisions should be made about the null and research hypotheses?

Answers

Answer:

The null hypothesis is rejected and  research hypotheses is supported

Step-by-step explanation:

From the question we are told that

    The population mean is  [tex]\mu = 30[/tex]

     The standard deviation is [tex]\sigma = 5[/tex]

      The sample size is  n =  1

      The  cutoff Z score for significance is  [tex]Z_{\alpha } = 1.96[/tex]

       The mean score is  [tex]\= x = 45[/tex]

Generally the test hypothesis is mathematically represented as

            [tex]t = \frac{\= x - \mu }{ \frac{ \sigma }{\sqrt{n} } }[/tex]

=>         [tex]t = \frac{45 - 30 }{ \frac{ 5}{\sqrt{1} } }[/tex]

=>         [tex]t = 3[/tex]

From the obtained value  we can see that [tex]t > Z_{\alpha }[/tex]

Hence the null hypothesis is rejected and  research hypotheses is supported

           

 

Please answer this correctly without making mistakes

Answers

Answer:

so first convert to fraction so

9 3/4 = 39/4

so it was spread among 3

so this is division so you do 39/4 divided by 3

so you keep switch flip

which is  39/4 *1/3

answer is 13/4

Answer:

3 1/4 bags

Step-by-step explanation:

[tex]9\frac{3}{4}= \frac{(4 \times 9)+3}{4}= \frac{39}{4} \\\\\frac{39}{4} = 3 \:vegetable \: beds\\x \:\:\:= 1 \: vegetable \:bed\\\\3x = \frac{39}{4} \\\\\frac{3x}{3} = \frac{\frac{39}{4} }{3} \\\\x = \frac{13}{4} \\\\x = 3\frac{1}{4}[/tex]

The heights of North American women are nor-mally distributed with a mean of 64 inches and a standard deviation of 2 inches. a. b. c. What is the probability that a randomly selected woman is taller than 66 inches

Answers

Answer:

0.1587

Step-by-step explanation:

Given the following :

Mean (m) of distribution = 64 inches

Standard deviation (sd) of distribution = 2 inches

Probability that a randomly selected woman is taller than 66 inches

For a normal distribution :

Z - score = (x - mean) / standard deviation

Where x = 66

P(X > 66) = P( Z > (66 - 64) / 2)

P(X > 66) = P(Z > (2 /2)

P(X > 66) = P(Z > 1)

P(Z > 1) = 1 - P(Z ≤ 1)

P(Z ≤ 1) = 0.8413 ( from z distribution table)

1 - P(Z ≤ 1) = 1 - 0.8413

= 0.1587

Algebra Review

Write an algebraic expression for each verbal expression.

1. the sum of one-third of a number and 27

2. the product of a number squared and 4

3. Write a verbal expression for 5n^3 +9.

Answers

Answer:

Step-by-step explanation:

1. The sum of one-third of a number and 27

= [tex]\frac{1}{3}\times x +27\\= 1/3x +27[/tex]

2. The product of a number squared and 4

[tex]Let\:the\:unknown\: number\: be \:x\\\\x^2\times4\\\\= 4x^2[/tex]

3.Write a verbal expression for 5n^3 +9.

The sum of the product and of 5 and a cubed number and 9

Write the function in terms of unit step functions. Find the Laplace transform of the given function. f(t) = 5, 0 ≤ t < 7 −3, t ≥ 7

Answers

Rewrite f in terms of the unit step function:

[tex]f(t)=\begin{cases}5&\text{for }0\le t<7\\-3&\text{for }t\ge7\end{cases}[/tex]

[tex]\implies f(t)=5(u(t)-u(t-7))-3u(t-7)=5u(t)-8u(t-7)[/tex]

where

[tex]u(t)=\begin{cases}1&\text{for }t\ge0\\0&\text{for }t<0\end{cases}[/tex]

Recall the time-shifting property of the Laplace transform:

[tex]L[u(t-c)f(t-c)]=e^{-cs}L[f(t)][/tex]

and the Laplace transform of a constant function,

[tex]L[k]=\dfrac ks[/tex]

So we have

[tex]L[f(t)]=L[5u(t)-8u(t-7)]=5L[1]-8e^{-7s}L[1]=\boxed{\dfrac{5-8e^{-7s}}s}[/tex]

In this exercise you have to find the laplace transform:

[tex]L[f(t)]=\frac{5-8e^{-7s}}{s}[/tex]

Rewrite f in terms of the unit step function:

[tex]f(t)=\left \{ {{5, for 0\leq t\leq 7} \atop {-3, for t\geq 7}} \right. \\f(t)= 5(u(t)-u(t-7)-3u(t-7)=5u(t)-8u(t-7)[/tex]

Where:

[tex]u(t)= \left \{ {{1, t\geq 0} \atop {0, t<0}} \right.[/tex]

Recall the time-shifting property of the Laplace transform:

[tex]L[u(t-c)f(t-c)]= e^{-cs}L[f(t)][/tex]

and the Laplace transform of a constant function,

[tex]L[k]=\frac{k}{s}[/tex]

So we have:

[tex]L[f(t)]= L[5u(t)-8u(t-7)]= 5L[1]-8e^{-7s}L[1]= \frac{5-8e^{-7s}}{s}[/tex]

See more about Laplace transform at : brainly.com/question/2088771

Use the following recursive formula to answer the question.
A1=-3/2
an=an-1+1/2
what’s is a9?

Answers

Step-by-step explanation:

a2=a1+1/2=-1

a3=a2+1/2=-1/2, then we have common difference 0.5

a9=a1+(n-1)d

a9=-3/2+(8)0.5=5/2

If 2 x 2 + 13 x − 7 = 0 , then x could equal which of the following?

Answers

Hi there! :)

Answer:

x = 1/2 or -7.

Step-by-step explanation:

(I'm assuming the expression is 2x² + 13x - 7 = 0)

Factor the equation to solve for the possible values of "x":

2x² + 13x - 7 = 0

When factored, we get:

(2x - 1) ( x + 7) = 0

Use the Zero-Product property to solve for the roots:

2x - 1 = 0

2x = 1

x = 1/2.

-----------

x + 7 = 0

x = -7.

Therefore, possible values of x are x = -1/2, 7.

Answer:

x = 1/2     x=-7

Step-by-step explanation:

2 x^2  + 13 x − 7 = 0

Factor

(2x-1)(x+7)=0

Using the zero product property

2x-1 =0   x+7=0

2x=1       x =-7

x = 1/2     x=-7

Identify the inverse function of f(x) = VX - 2 + 3.

Answers

Answer:

[tex]\huge\boxed{f^{-1}(x) = (x-3)^2+2}[/tex]

Step-by-step explanation:

[tex]f(x) = \sqrt{x-2} + 3[/tex]

Replace y = f(x)

[tex]y = \sqrt{x-2} + 3[/tex]

Exchange x and y

[tex]x = \sqrt{y-2}+3[/tex]

Solve for y

[tex]x = \sqrt{y-2}+3[/tex]

Subtracting both sides by 3

[tex]x - 3 = \sqrt{y-2}[/tex]

Taking square on both sides

[tex](x-3)^2 = y -2[/tex]

Adding 2 to both sides

[tex]y = (x-3)^2+2[/tex]

Substitute y = [tex]f^{-1}(x)[/tex]

[tex]f^{-1}(x) = (x-3)^2+2[/tex]

Answer:

[tex] \boxed{ {f}^{ - 1} (x) = {(x - 3)}^{2} + 2}[/tex]

Option D is the correct option

Step-by-step explanation:

[tex] \mathsf{f(x) = \sqrt{x - 2} + 3}[/tex]

Replace f(x) with y

[tex] \mathsf{y = \sqrt{x - 2} + 3}[/tex]

Interchange variables

[tex] \mathsf{x = \sqrt{y - 2} + 3}[/tex]

[tex] \mathsf{{(x - 3)}^{2} = {( \sqrt{y - 2)} }^{2} }[/tex]

[tex] \mathsf{ {(x - 3)}^{2} = y - 2}[/tex]

[tex] \mathsf{ y = {(x - 3)}^{2} + 2}[/tex]

Replace y with f ⁻¹( x )

[tex] \mathsf{ {f}^{ - 1} (x) = {(x - 3)}^{2} + 2}[/tex]

Hope I helped!

Best regards!

23.24 divided by 2.8

Answers

Answer:

It's 8.3

Step-by-step explanation:

Answer:

8.3

Step-by-step explanation:

Evaluate the expression for q = -2. 8q=

Answers

Answer:

-16

Step-by-step explanation:

8q

Let q = -2

8*-2

-16

Can somebody explain how trigonometric form polar equations are divided/multiplied?

Answers

Answer:

Attachment 1 : Option C

Attachment 2 : Option A

Step-by-step explanation:

( 1 ) Expressing the product of z1 and z2 would be as follows,

[tex]14\left[\cos \left(\frac{\pi \:}{5}\right)+i\sin \left(\frac{\pi \:\:}{5}\right)\right]\cdot \:2\sqrt{2}\left[\cos \left(\frac{3\pi \:}{2}\right)+i\sin \left(\frac{3\pi \:\:}{2}\right)\right][/tex]

Now to solve such problems, you will need to know what cos(π / 5) is, sin(π / 5) etc. If you don't know their exact value, I would recommend you use a calculator,

cos(π / 5) = [tex]\frac{\sqrt{5}+1}{4}[/tex],

sin(π / 5) = [tex]\frac{\sqrt{2}\sqrt{5-\sqrt{5}}}{4}[/tex]

cos(3π / 2) = 0,

sin(3π / 2) = - 1

Let's substitute those values in our expression,

[tex]14\left[\frac{\sqrt{5}+1}{4}+i\frac{\sqrt{2}\sqrt{5-\sqrt{5}}}{4}\right]\cdot \:2\sqrt{2}\left[0-i\right][/tex]

And now simplify the expression,

[tex]14\sqrt{5-\sqrt{5}}+i\left(-7\sqrt{10}-7\sqrt{2}\right)[/tex]

The exact value of [tex]14\sqrt{5-\sqrt{5}}[/tex] = [tex]23.27510\dots[/tex] and [tex](-7\sqrt{10}-7\sqrt{2}\right))[/tex] = [tex]-32.03543\dots[/tex] Therefore we have the expression [tex]23.27510 - 32.03543i[/tex], which is close to option c. As you can see they approximated the solution.

( 2 ) Here we will apply the following trivial identities,

cos(π / 3) = [tex]\frac{1}{2}[/tex],

sin(π / 3) = [tex]\frac{\sqrt{3}}{2}[/tex],

cos(- π / 6) = [tex]\frac{\sqrt{3}}{2}[/tex],

sin(- π / 6) = [tex]-\frac{1}{2}[/tex]

Substitute into the following expression, representing the quotient of the given values of z1 and z2,

[tex]15\left[cos\left(\frac{\pi \:}{3}\right)+isin\left(\frac{\pi \:\:}{3}\right)\right] \div \:3\sqrt{2}\left[cos\left(\frac{-\pi \:}{6}\right)+isin\left(\frac{-\pi \:\:}{6}\right)\right][/tex] ⇒

[tex]15\left[\frac{1}{2}+\frac{\sqrt{3}}{2}\right]\div \:3\sqrt{2}\left[\frac{\sqrt{3}}{2}+-\frac{1}{2}\right][/tex]

The simplified expression will be the following,

[tex]i\frac{5\sqrt{2}}{2}[/tex] or in other words [tex]\frac{5\sqrt{2}}{2}i[/tex] or [tex]\frac{5i\sqrt{2}}{2}[/tex]

The solution will be option a, as you can see.

To the nearest tenth, what is the value of P(C|Y)? 0.4 0.5 0.7 0.8

Answers

Answer:

P(C|Y) = 0.5.

Step-by-step explanation:

We are given the following table below;

               X             Y               Z             Total

A             32           10             28              70

B              6             5              25              36

C             18            15              7                40

Total       56           30            60              146

Now, we have to find the probability of P(C/Y).

As we know that the conditional probability formula of P(A/B) is given by;

                    P(A/B) =  [tex]\frac{P(A \bigcap B)}{P(B)}[/tex]

So, according to our question;

P(C/Y) =  [tex]\frac{P(C \bigcap Y)}{P(Y)}[/tex]

Here, P(Y) = [tex]\frac{30}{146}[/tex] and P(C [tex]\bigcap[/tex] Y) =  [tex]\frac{15}{146}[/tex]  {by seeing third row and second column}

               

Hence, P(C/Y) =  [tex]\frac{\frac{15}{146} }{\frac{30}{146} }[/tex]

                       =  [tex]\frac{15}{30}[/tex]  = 0.5.

Answer: 0.5

Step-by-step explanation:

edge

G={3,7,8,9} h={2,5,7,8} what is the intersection of the sets

Answers

Answer:

The answer is { 7 , 8 }

Step-by-step explanation:

G = { 3 , 7 , 8 , 9 }

H = { 2 , 5 , 7 , 8 }

The intersection of any two or more sets are the members that occur in both sets.

To find the intersection of G and H look for the members that occur in both sets

From the question , the members that occur in both G and H are 7 and 8

So the intersection of the sets is

{ 7 , 8 }

Hope this helps you

i will rate you brainliest// What is the interquartile range (IQR) of {5.8, 8.5, 9.9, -0.8, -1.3, 2.3, 7.4, -1.9}?

Answers

Answer

arrange the element in increasing order

-1.9, -1.3, -0.8, 2.3, 5.8, 7.4, 8.5, 9.9

interquatile = Q3 - Q1

[tex] = \frac{7.4 + 8.5}{2} - \frac{ - 1.3 - 0.8}{2} [/tex]

[tex] = 7.95 + 1.05[/tex]

[tex] = 9[/tex]

Answer:

9.0

Step-by-step explanation:

i took the quiz

find the value of each variable and the measure of each angle​

Answers

Answer:

y = 90x = 302x° = 60°(y+x)° = 120°(y-x)° = 60°

Step-by-step explanation:

Adjacent angles are supplementary, so ...

  (y +x) +(y -x) = 180

  2y = 180 . . . . . . . . . simplify

  y = 90 . . . . . . . . . . . divide by 2

__

  2x +(y +x) = 180

  3x +90 = 180 . . . . substitute for y

  x + 30 = 60 . . . . . . divide by 3

  x = 30 . . . . . . . . . . subtract 30

__

With these values of x and y, the angle measures are ...

  2x° = 2(30)° = 60°

  (y+x)° = (90+30)° = 120°

  (y-x)° = (90-30)° = 60°

The Tran family and the Green family each used their sprinklers last summer. The water output rate for the Tran family's sprinkler was 35L per hour. The water output rate for the Green family's sprinkler was 40L per hour. The families used their sprinklers for a combined total of 50 hours, resulting in a total water output of 1900L. How long was each sprinkler used?

Answers

Answer:

Tran family's sprinkler was used for 20 hours

Green's  family's sprinkler was used for 30 hours

Step-by-step explanation:

Let the hours for which Tran family's sprinkler used is x hours

water output rate for the Tran family's sprinkler = 35L per hour

water output from  Tran family's sprinkler in x hours = 35*x L = 35x

Let the hours for which Green family's sprinkler used is y hours

water output rate for the Green family's sprinkler = 40L per hour

water output from  Green family's sprinkler in x hours = 40*y L = 40y

Given

The families used their sprinklers for a combined total of 50 hours

thus

x + y = 50 -------------------equation 1

y = 50-x

total water output of 1900L

35x+40y = 1900  -------------------equation 1

using  y = 50-x in equation 2, we have

35x + 40(50-x) = 1900

35x + 2000 - 40x = 1900

=> -5x = 1900 - 2000 = -100

=> x = -100/-5 = 20

y = 50-20 = 30

Thus,

Tran family's sprinkler was used for 20 hours

Green's  family's sprinkler was used for 30 hours

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