My question today is : The reaction of 11.9g go CHCl3 with excess chlorine produced 10.2g of CCl4, carbon tetrachloride. What is the percent yield

Answers

Answer 1

Answer:

66.7%

Explanation:

Step 1: Write the balanced equation

CHCl₃ + Cl₂ ⇒ CCl₄ + HCl

Step 2: Calculate the theoretical yield of CCl₄ from 11.9 g of CHCl₃

According to the balanced equation, the mass ratio of CHCl₃ to CCl₄ is 119.38:153.82.

11.9 g CHCl₃ × 153.82 g CCl₄/119.38 g CHCl₃ = 15.3 g CCl₄

Step 3: Calculate the percent yield of CCl₄

Given the experimental yield of CCl₄ is 10.2 g, we can calculate the percent yield using the following expression.

%yield = (exp yield/theo yield) × 100%

%yield = (10.2 g/15.3 g) × 100% = 66.7%


Related Questions

True or false: Boron contains 2s22p1 valence electrons, so only one p orbital is needed to form molecular orbitals.

Answers

Answer:

True

Explanation:

The valence orbitals of boron are 2s2 2p1. We have to recall that all the valence orbitals whether full or empty are involved in the formation of molecular orbitals.

The number of molecular orbitals formed is equal to the number of atomic orbitals that are combined.

Since there are two valence orbitals and there is only one p orbital among the valence orbitals, it is true that only one p orbital is needed to form molecular orbitals in boron.

Calculate the moment of inertia of a CH³⁵CL₃ molecule around a rotational axis that contains the C-H bond. The C-Cl bond length is 177pm and the HCCl angle is 107⁰f​

Answers

Answer:

The correct answer is "[tex]4.991\times 10^{-45} \ kg.m^2[/tex]".

Explanation:

According to the question,

[tex]R_{C-Cl} = 177 \ pm[/tex]

or,

         [tex]=1.77\times 10^{-10} \ m[/tex]

[tex]\alpha = 107^{\circ}[/tex]

[tex]m_{Cl}=34.97 \ m.u[/tex]

or,

      [tex]=34.97\times 1.66\times 10^{-27}[/tex]

      [tex]=5.807\times 10^{-26} \ kg[/tex]

The moment of inertia around the rotational axis will be:

⇒  [tex]I=3\times m_{Cl}\times (R_{C-Cl})^2 \ Sin^2 \alpha[/tex]

By putting the values, we get

       [tex]=3\times 5.807\times 10^{-26}\times (1.77\times 10^{-10})^2 \ Sin^2 (107)[/tex]

       [tex]=3\times 5.807\times 10^{-26}\times (1.77\times 10^{-10})^2\times 0.91452[/tex]

       [tex]=4.991\times 10^{-45} \ kg.m^2[/tex]

Assign priorities in the following set of substituents according to Cahn-Ingold-Prelog rules.
-OCH3 -Br -Cl -CH2OH
А B C D
(Provide your ranking through a string like abcd, starting with the one with the highest priority).

Answers

Answer:

Assign priorities in the following set of substituents according to Cahn-Ingold-Prelog rules.

-OCH3 -Br -Cl -CH2OH

Explanation:

To give priorities for the substituents that are attached to chiral carbon and  to assign either R or S-configuration the following rules were proposed:

1. The atom with the highest atomic number is given first priority.

2. If the Groups attached to chiral carbon are having the same first atom, then check for the atomic number of the second atom.

Among the given groups,

-Br has the highest atomic number, so it is given first priority.

Then, -Cl.

Then, -OCH3

and the last one is -CH2OH.

Hence, the order is :

BCAD.

Rank each of the following gases in order of increasing urms assuming equivalent amounts and all gases are at the same temperature and pressure where 1 has the lowest urms and 4 has the highest urms.

a. Gas 1 : H2S
b. Gas: He
c. Gas 3: NF3
d. Gas 4: H2O

Answers

the answer is option c

The Urms refers to the root mean square speed of the gas. The order of increasing Urms for the gases shown in the question; NF3 < H2S < H2O < He.

What is the Urms?

The Urms refers to the root mean square speed of the gas. This is ultimately dependent on the relative molecular mass of the gases when they are maintained at the same temperature.

Now, let us look at the order of increasing Urms for the gases shown in the question; NF3 < H2S < H2O < He.

Learnmore about Urms: https://brainly.com/question/365923

A chemical reaction occurring in a cylinder equipped with a moveable piston produces 0.601 mol of a gaseous product. If the cylinder contained 0.300 mol of gas before the reaction and had an initial volume of 2.16 L, what was its volume after the reaction

Answers

Answer:

4.33 L

Explanation:

Assuming ideal behaviour and that all 0.300 moles of gas reacted, we can solve this problem using Avogadro's law, which states that at constant temperature and pressure:

V₁n₂ = V₂n₁

Where in this case:

V₁ = 2.16 Ln₂ = 0.601 molV₂ = ?n₁ = 0.300 mol

We input the given data:

2.16 L * 0.601 mol = V₂ * 0.300 mol

And solve for V₂:

V₂ = 4.33 L

? Question
In an ozone molecule, the three atoms must be connected, so there must at least be a single bond between them. Place
dots in pairs around the oxygen atoms until each oxygen atom has eight valence electrons, starting with the atoms on the
outside and doing the central atom last if there are enough. Do not exceed the total number of valence electrons
identified in part A. Remember that the dashes between the oxygen atoms, which represent single bonds, each indicate
the presence of two valence electrons.

Answers

A is the answer

In an ozone molecule, the three atoms must be connected, so there must at least be a single bond between them. Place

dots in pairs around the oxygen atoms until each oxygen atom has eight valence electrons, starting with the atoms on the

outside and doing the central atom last if there are enough. Do not exceed the total number of valence electrons

identified in part A. Remember that the dashes between the oxygen atoms, which represent single bonds, each indicate

the presence of two valence electrons

Answer:

Explanation: i did it

Explain why ionic compounds have higher boiling points than covalent compounds.​

Answers

Answer:

because the have stronger electrostatic force

C3H8 is ________

A. unsaturated
B. saturated​

Answers

I believe it is saturated!

I hope this helps. Please mark me the Brainliest, it’s not necessary but I put time and effort into every answer and I would appreciate it greatly. Have a great day, stay safe and stay healthy ! :)

Question 1
1 pts
How many mols of bromine are present in 35.7g of
Tin(IV) bromate?

Answers

Answer:

n = 0.0814 mol

Explanation:

Given mass, m = 35.7g

The molar mass of Tin(IV) bromate, M = 438.33 g/mol

We need to find the number of moles of bromine. We know that,

No. of moles = given mass/molar mass

So,

[tex]n=\dfrac{35.7}{438.33}\\\\n=0.0814\ mol[/tex]

So, there are 0.0814 moles of bromine in 35.7g of  Tin(IV) bromate.

what is the molar masses for C8H10N2O4

Answers

Answer:

198.2 g/mol

Explanation:

C = 12.01 g/mol

H = 1.01 g/mol

N = 14.01 g/mol

O = 16.00 g/mol

(12.01 x 8) + (10 x 1.01) + (14.01 x 2) + (16.00 x 4) = 198.12 g/mol

What are the uses of Sulphuric acid?

Answers

Answer:

The major use of sulfuric acid is in the production of fertilizers, e.g., superphosphate of lime and ammonium sulfate. It is widely used in the manufacture of chemicals, e.g., in making hydrochloric acid, nitric acid, sulfate salts, synthetic detergents, dyes and pigments, explosives, and drugs.

The major use of sulfuric acid is in the production of fertilizers, e.g., superphosphate of lime and ammonium sulfate. It is widely used in the manufacture of chemicals, e.g., in making hydrochloric acid, nitric acid, sulfate salts, synthetic detergents, dyes and pigments, explosives, and drugs.

Which one of the following compounds shows red precipitate of Cu2O with the reaction of Fehling solution?

a. Vinegar c. Glycerine
b. Formalin d. Propanon​

Answers

Answer:

acetaldehyde

When acetaldehyde is heated with Fehling's solution, a red precipitate is formed.

Explanation:

PLEASE HELP FAST!!!

Which of the following is an acid? (3 points)
Be(OH)2
HCl
LiBr
NH3

Answers

Answer:

HCl

Explanation:

I took the test :)

Out of the following compounds , HCl is an acid as it has hydrogen as the proton donor.

Acids are defined as substances which on dissociation yield H+ ions , and these substances are sour in taste.

According to the number of H+ ions which are generated on dissociation acids are classified as mono-protic , di-protic ,tri-protic and polyprotic  acids  depending on the number of protons which are liberated on dissociation.

Acids are widely used in industries  for  production of fertilizers, detergents  batteries and dyes.They are used in chemical industries for production of chemical compounds like salts which are produced by neutralization reactions.

Learn more about acids,here:

https://brainly.com/question/29796621

#SPJ6

Which procedure could a student use to examine an intensive property of a rectangular block of wood
Find the mass.
Record the length. Measure the volume. Determine the density.

Answers

Answer:

density

Explanation:

The procedure that the student could use to examine an intensive property of a rectangular block of wood is to determine its density. Density is intensive because it is the ration between the mass and the volume.

Answer: find the mass option A

Explanation:

11) Methane and oxygen react to form carbon dioxide and water. What mass of water is formed if 0.80 g of methane reacts with 3.2 g of oxygen to produce 2.2 g of carbon dioxide

Answers


the mass of water formed is 1.8 g.

Pablo, whose mass is 60 kg, is moving along at a velocity of 8 m/s. How much kinetic energy does he have?

Answers

Answer:

1920 Joules

Explanation:

* means multiply

^ means exponent

kinetic energy is in Joules or J

kinetic energy = 1/2 * mass * (velocity)^2

kinetic energy = 1/2 * 60 * (8)^2

kinetic energy = 1/2 * 60 * (8*8)

kinetic energy = 1/2 * 60 * (64)

kinetic energy = 1920 Joules or 1920 J

Answer:

KE = 1920 J

General Formulas and Concepts:

Energy

Kinetic Energy Formula: [tex]\displaystyle KE = \frac{1}{2}mv^2[/tex]

m is mass (in kg)v is velocity (in m/s)

Explanation:

Step 1: Define

[Given] m = 60 kg

[Given] v = 8 m/s

Step 2: Find KE

Substitute in variables [Kinetic Energy Formula]:                                           [tex]\displaystyle KE = \frac{1}{2}(60 \ kg)(8 \ m/s)^2[/tex]Evaluate:                                                                                                           [tex]\displaystyle KE = 1920 \ J[/tex]

Topic: AP Physics 1 Algebra-Based

Unit: Energy

The following data were obtained using the same procedure as in your experiment. Using these data, calculate the percent malachite in the sample.
FW information (in g/mol): malachite = 221.11; CO2 = 44.01; H2O = 18.02
Mass of crucible: 23.8839 g Mass of crucible + sample: 26.0496 g
Mass of crucible + decomposed sample: 25.7013 g
One molecule of malachite decomposes to make:_______.
___________molecule(s) of copper oxide
___________molecule(s) of carbon dioxide
____________molecule(s) of water
a. 1, 2,2
b. 2, 1, 1
c. 1, 1, 1
d. 1,0.5, 0.5

Answers

Answer:

c

Explanation:

Please help meee! Chemistry!

Answers

P=18000000/6 zeros. not sure how to do rest

Explanation:

a) [tex]n = \dfrac{PV}{RT} = \dfrac{(1.8×10^7\:\text{Pa})(3\:\text{L})}{(8310\:\text{L•Pa/mol•K})(300\:\text{K})}[/tex]

[tex]\:\:\:\:\:\:\:= 21.7\:\text{mol}[/tex]

b) [tex]P = \dfrac{nRT}{V}[/tex]

[tex]\:\:\:\:\:\:\:\:\:= \dfrac{(50\:\text{mol})(8310\:\text{L•Pa/mol•K})(300\:K)}{(3\:L)}[/tex]

[tex]\:\:\:\:\:\:\:\:\:=4.2×10^7\:\text{Pa}[/tex]

Using the boh model of a He ion, what transition is most likelu to result in the emission of radiation with a wavelength of approximately 274 nm

Answers

Answer:

[tex]n=6\ to\ n=3[/tex]

Explanation:

From the question we are told that:

Wavelength [tex]\lambda=274 *10^{-9}m[/tex]

Bohr's constant [tex]R = 1.097 × 10^7 / m (or m−1)[/tex]

Helium atom [tex]z=2[/tex]

Generally the equation for Wavelength is mathematically given by

 [tex]\frac{1}{\lambda}=Rz^2(\frac{1}{nf^2}-\frac{1}{nf^2})[/tex]

 [tex]0.083=(\frac{1}{nf^2}-\frac{1}{nf^2})[/tex]

Therefore

The Range of n fall at

 [tex]n=6\ to\ n=3[/tex]

Which of the following statements correctly explains why bromination reactions are more selective than chlorination reactions.
a. bromine radical is less stable than chlorine radical, so it is more reactive and less choosy
b. bromine radical is more stable than chlorine radical, so it is more reactive and less choosy
c. bromine radical is more stable than chlorine radical, so it is less reactive and more choosy
d. bromine radical is less stable than chlorine radical, so it is less reactive and more choosy
e. relative radical stability is 3' radicals > 2" radicals> 1 radicals when bromine radicals snatch hydrogens from alkanes, but when chlorine radicals snatch hydrogens the resulting alkyl radical stability is 3 radicals < 2 radicals< 1' radicals

Answers

Answer: A bromine radical is more stable than chlorine radical, so it is less reactive and more choosy.

Explanation:

A chlorine atom being more electronegative in nature is able to attract a hydrogen atom more readily towards itself as compared to a bromine atom.

Since bromine is less electronegative in nature so bromine will be more selective as a hydrogen abstracting agent. As a result, bromine radical is more stable in nature than chlorine radical.

Thus, we can conclude that bromine radical is more stable than chlorine radical, so it is less reactive and more choosy.

When sugar is added to a sugar solution, the sugar dissolves. Which term describes the original sugar solution?​

Answers

Answer:

the answer is D .................

Typhoon signals rise due to what? wind speed or wind strength or both?​

Answers

Both it’s based on intensity, size of circulation and the forecast direction, and speed

In a pure metal, the electrons can be thought of as [ Select ] throughout the metal. Using molecular orbital theory, there [ Select ] an energy gap between the filled molecular orbitals and empty molecular orbitals. The [ Select ] orbitals are typically higher in energy and are mostly [ Select ] .

Answers

Answer:

Explanation:

In a pure metal, the electrons can be thought of as [concentrated] around atoms throughout the metal. Using molecular orbital theory, there [is ] an energy gap between the filled molecular orbitals and empty molecular orbitals. The [antibonding] orbitals are typically higher in energy and are mostly (filled]

What is the best explanation for why solid sodium chloride CANNOT conduct electricity and why molten sodium chloride can?

Answers

Answer: See explanation

Explanation:

The explanation for why solid sodium chloride can't conduct electricity while molten sodium chloride can is explained below:

Ionic compounds that are in their solid state like sodium chloride have their ions fixed in position. Due to this reason, the able to move, therefore we can say that the solid ionic compounds cannot be able to conduct electricity.

On the other hand, ionic compounds in their molten state, are free to flow unlike when they're in their solid state and therefore we can say that molten sodium chloride can be able to conduct electricity.

Draw the skeletal structure for: (E)-hept-5-en-2-one

Answers

Answer:

Draw the skeletal structure for: (E)-hept-5-en-2-one

Explanation:

The root word hept indicates that the given compound has seven carons in its longest chain.

-en- primary suffix indicates that the compound has one double bond in it.

2-one indicates that the compound has -C=O bond in the second carbon.

The prefix (E) indicates that the highest priority groups are on the opposite direction of the double bond.

The structure of the given molecule is:

The energy needed to collapse the H-bonding of ice is _____.

Answers

it depends on the widths of the recesses, and if it is causing the shelf to fracture and collapse into the sea, then a massive iceberg could be called from the life she,f and the ice shelf are way more important because it holds it up

The graph below shows how the temperature and volume of a gas vary when
the number of moles and the pressure of the gas are held constant. How can
the volume of the gas be increased if the pressure is constant?
v
т
A. By increasing the temperature
B. By letting the gas expand over time
C. By letting the gas contract over time
D. By decreasing the temperature

Answers

Answer:

D

Explanation:

PV =nRT

So V and T are inversely proportional

What is the name for CH 3 CH 2 COCHCH 3 CH(CH 3 ) 2 ?

Answers

Answer:

Butanoic acid

Explanation:

The IUPAC name of CH3CH2CH2COOH is:

The IUPAC name for a given compound is Butanoic acid.

Trình bày sự hình thành phân tử CCl4 (lai hoá sp3)

Answers

Gucgjfgdjgcycc fh(xsjfhghjkm

Name the following compound. Group of answer choices 2-methyl-4-pentyne 4-methyl-3-propyl-1-pentyne 3-isopropyl-1-hexyne 1-nonyne 4-propyl-5-hexyne

Answers

The question is incomplete, the complete question is shown in the image attached

Answer:

3-isopropyl-1-hexyne

Explanation:

Organic compounds can be named from the structure of the compound. The name reveals the arrangement of atoms and bonds in the molecule.

If we look at the compound in the question, we will notice that the parent chain contains six carbon atoms, the triple bond is located at position 1 and the isopropyl substituent is attached to carbon 3.

Hence the proper name of the compound becomes, 3-isopropyl-1-hexyne.

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