Một con lắc lò xo gồm 1 quả nặng có m= 0,2kg treo vào lò xo có độ cứng k= 100N/m, cho vật dao động điều hoà theo phương thẳng đứng với biên độ A= 1,5 cm. Lực đàn hồi cực đại có giá trị

Answers

Answer 1
Honestly same man I think it’s b
Answer 2
!!!!!!!!!!!!!!!!!!!
Mt Con Lc L Xo Gm 1 Qu Nng C M= 0,2kg Treo Vo L Xo C Cng K= 100N/m, Cho Vt Dao Ng Iu Ho Theo Phng Thng

Related Questions

What would be the acceleration in a body moving with uniform velocity and why?​

Answers

Explanation:

The derivative of a constant term is always 0. So the acceleration of the body would be zero. Hence, the acceleration of a body moving with uniform velocity will always be zero.

hope it helps you

A man sees a deer in the road and slams on his brakes. If he is traveling at 45.2 m/s and comes to a stop in 2.74 s, what is his acceleration? O -6:02 m/s2 -0.0606 m/s2 -47.9 m/s2 0 -16.5 m/s2 ​

Answers

Answer:

16.50 m/s²

Explanation:

initial velocity(u)=45.2 m/s

final velocity(v)= 0 (it stops)

time taken(t)= 2.74 s

now,we have

acceleration(a)= (v-u)/t

= (0-45.2 m/s)/2.74s

= -45.2 m/s / 2.74s

= -16.50 m/s²

Answer:

[tex]\boxed {\boxed {\sf -16.5 \ m/s^2}}[/tex]

Explanation:

We are asked to find the acceleration of a man driving. Acceleration is the change in velocity over the change in time. Acceleration is calculated with the following formula.

[tex]a= \frac{v_f- v_i}{t}[/tex]

The driver's initial velocity is 45.2 meters per second. His final velocity is 0 meters per second because he came to a stop. He stopped in 2.74 seconds.

[tex]\bullet \ v_f= 0 \ m/s \\\bullet \ v_i= 45.2 \ m/s \\\bullet \ t= 2.74 \ s[/tex]

Substitute these values into the formula.

[tex]a= \frac{0 \ m/s - 45.2 \ m/s }{ 2.74 \ s}[/tex]

Solve the numerator by subtracting.

[tex]a= \frac{- 45.2 \ m/s }{ 2.74 \ s}[/tex]

[tex]a= -16.49635036 \ m/s^2[/tex]

The original measurements of velocity and time have 3 significant figures, so our answer must have the same. For the number we calculated, that is the tenths place. The 9 in the hundredth place tells us to round the 4 in the tenths place up to a 5.

[tex]a \approx -16.5 \ m/s^2[/tex]

The acceleration is approximately -16.5 meters per second squared. The acceleration is negative because the man slowed down and came to a stop.

A 210 Ohm resistor uses 9.28 W of power. How much current flows through the resistor? (unit=A)

Answers

Answer:

.21

Explanation:

i see everyone got it wrong so ill give you the answer, good luck :)

A simple machine has efficiency 90%. What does it mean? No machine has 109 efficiency,why?​

Answers

Answer:

Efficiency of a machine is 90% this means that the total energy produced to the machine only 90% is useful and given as a output.

Machines are not 100% efficient because some of the work done by a machine is used to overcome friction

Clois what is the weight of a body in the earth, if its weig is 5Nin moon?

Answers

Explanation:

because the moon has less mass than earth, the force due to gravity at the lunar surface is only about 1/6 that on earthso,the weight of a body on earth is 6×5N =30N

factor that affect gravitation

Answers

1) Two major factors, mass and distance, affect the strength of gravitational force on an object.

2) Most common factors that affect gravity are mass of the body, distance from centers, shape of bodies,etc. Gravity is a binding force, always acting to bind any material closure and closure inwards. If we think this way, then gravity is maximum at its centre and decreases slowly away from its centre.

hope it helps you

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have a nice day

define Archemedics principle?​

Answers

THIS IS YOUR ANSWER :

Archimedes’ principle, physical law of buoyancy, discovered by the ancient Greek mathematician and inventor Archimedes, stating that any body completely or partially submerged in a fluid (gas or liquid) at rest is acted upon by an upward, or buoyant, force, the magnitude of which is equal to the weight of the fluid displaced by the body.

☺✍️HOPE IT HELPS YOU ✍️☺

Question 7 of 25
Which two chemical equations are balanced?
O A. 2PBrg + 3Cl2 - 2PC13 + 3Br2
O B. 2Na+ MgCl2
2NaCl + Mg
-
C. 2LIOH + 2H2S - Li2S + 2H20
D. 2AgNO3 + NaCl - NaNO3 + 2AGCI

Answers

Answer:

2PBr₃ + 3Cl₂ → 2PCl₃ + 3Br₂

2Na + MgCl₂ → 2NaCl + Mg

Explanation:

A balanced chemical equation is a chemical equation that have an equal number of elements of each type on both sides of the equation

Among the given chemical reactions, we have;

2PBr₃ + 3Cl₂ → 2PCl₃ + 3Br₂

In the above reaction;

The number of phosphorus, P, on either side of the equation = 2

The number of bromine atoms, Br, on either side of the equation = 6

The number of chlorine atoms, Cl, on either side of the equation = 6

Therefore, the number of elements in the reactant side and products side of the reaction are equal and the reaction is balanced

The second balanced chemical reaction is 2Na + MgCl₂ → 2NaCl + Mg

In the above reaction, there are two sodium atoms, Na,  one magnesium atom and two chlorine atoms on both sides of the reaction, therefore, the reaction is balanced

86,400 seconds into day​

Answers

Answer:

60×60×24=86,400

Explanation:

i.e. 86,400 secs is 1 day

1 hour = 60 minutes

1 minute = 60 seconds

1 day = 24 hours

60 min. × 60 sec. × 24 hr.

60 × 60 × 24 = 86,400 seconds

∴ 86,400 seconds = 1 day

(2) Why do spring balance shows wrong reading after they had been uses for a long time?​

Answers

This is because of continuous usage, the wire loses its elasticity and dose not regain it original dimension

Answer:

When a spring balance has been used for a long time, the spring in the balance fatigued and there is loss of strength of the spring. In such a case, the extension in the spring is more for a given load and hence the balance gives wrong readings.

(9x10^2) + (1x10^2)
10x10^4
10x10^3
1x10^4
1x10^3

Answers

Answer:

10 x 10⁴

I hope it's helps you

Answer:

Yes

Explanation:

Object A has a mass of 5 kg and a velocity of 6 m/s to the east while Object 1 point B has a mass of 12 kg and velocity 0.6 m/s also to the east. What is the momentum of the system? (Let east be positive)
help plss I got family

Answers

Answer:

Momentum of system = 37.2 Kgm/s.

Explanation:

Given the following data;

Mass A = 5 kgVelocity A = 6 m/sMass B = 12 kgVelocity B = 0.6 m/s

To find the momentum of the system;

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

Momentum = mass * velocity

For object A;

Momentum A = 5 * 6

Momentum A = 30 Kgm/s

For object B;

Momentum B = 12 * 0.6

Momentum B = 7.2 Kgm/s

Next, we would determine the momentum of this system using the formula;

Momentum of system = Momentum A + Momentum B

Substituting the values into the formula, we have;

Momentum of system = 30 + 7.2

Momentum of system = 37.2 Kgm/s.

In a lunar experiment, a 950-g aluminum (920 J/(°Ckg)) sphere is dropped from the space probe while is 75 m above the Lunar ground. If the sphere’s temperature increased by 0.11°C when it hits the ground, what percentage of the initial mechanical energy was absorbed as thermal energy by the aluminum sphere?

Answers

Answer:

13.759 % of the initial mechanical energy is lost as thermal energy.

Explanation:

By the First Law of Thermodynamics we know that increase in internal energy of the object ([tex]U[/tex]), in joules, is equal to the lost amount of the change in gravitational potential energy ([tex]U_{g}[/tex]), in joules:

[tex]\frac{x}{100} \cdot \Delta U_{g} = \Delta U[/tex] (1)

Where [tex]x[/tex] is the percentage of the energy loss, no unit.

By definition of the gravitational potential energy and internal energy, we expand this equation:

[tex]\frac{x\cdot m \cdot g \cdot h}{100} = m\cdot c\cdot \Delta T[/tex] (1b)

Where:

[tex]m[/tex] - Mass of the object, in kilograms.

[tex]g[/tex] - Gravitational acceleration, in meters per square second.

[tex]h[/tex] - Initial height of the object above the lunar ground, in meters.

[tex]c[/tex] - Specific heat of aluminium, in joules per degree Celsius-kilogram.

[tex]\Delta T[/tex] - Temperature increase due to collision, in degree Celsius.

If we know that [tex]m = 0.95\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], [tex]h = 75\,m[/tex], [tex]c = 920\,\frac{J}{kg\cdot ^{\circ}C}[/tex] and [tex]\Delta T = 0.11\,^{\circ}C[/tex], then the percentage of energy loss due to collision is:

[tex]x = \frac{100\cdot c\cdot \Delta T}{g\cdot h}[/tex]

[tex]x = \frac{100\cdot \left(920\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (0.11\,^{\circ}C)}{\left(9.807\,\frac{m}{s^{2}} \right)\cdot (75\,m)}[/tex]

[tex]x = 13.759\,\%[/tex]

13.759 % of the initial mechanical energy is lost as thermal energy.


State one effect of increase in heat for a temperature range of 50°C to 100°C
on Plastic

Answers

Answer:

why is fraction called a necessary evil

The heat for a temperature in plastic increases at the range of 50°C to 100°C then the plastic decreases its stiffness or flexural modulus.

It is given that the temperature is increased from 50°C to 100°C that means temperature is increasing.

It is required to state the effect of increase in heat on plastic.

What will be the effect of increase in heat for a temperature range of 50°C to 100°C on Plastic?

The plastic starts to lose its stiffness or we say that it converts into a softened material as long as we increase the temperature of the material.

So if we increase the temperature too much or exceed above the limit of temperature range then it will distort.

Also there are many qualities that can be affected by increasing the temperature like mechanical property, material fatigue or chemical phenomenon.

Therefore, the heat for a temperature range of 50°C to 100°C

Plastic increases then the plastic decreases its stiffness or flexural modulus.

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D 2. Which of the following is an example of a specific goal?
O I want to lose weight.
I want to get stronger.
O I want to be able to walk one mile in 15 minutes.
I want to improve my speed.

Answers

I want to improve my speed

Answer:

D

Explanation:

How do we aquire knowledge in science?

Answers

Answer:

By studying.

By paying attention to what the teacher is saying.

That's the way to receive knowledge.

HAVE A GREAT DAY

Explanation:

Please give me that little crown...

AND REMEMBER TO SMILE

Given: F = k· m. g
Solve for "k"

Answers

Answer:

[tex]F = kmg \\ k = \frac{F}{mg} [/tex]

Explanation:

F = k . m . g

=> F = k . mg

[tex] = > k = \frac{F}{mg} (ans)[/tex]

Phương trình chuyển động thẳng đều của một chất điểm có dạng: x = 2t – 10. (x: km, t: h). Quãng đường đi được của chất điểm sau 2h là bao nhiêu?

Answers

Answer:

Distance cover in 2  hour = 6 kilometer

Explanation:

Given equation:

x = 2t - 10

where

x = kilometer

t = hour

Find:

Distance cover in 2  hour

Computation:

T = 2

So,

x = 2t - 10

x = 2(2) - 10

x = 4 - 10

x = -6

Distance cover in 2  hour = 6 kilometer

Answer:

The distance is 6 km.

Explanation:

The equation of uniform linear motion of a particle has the form: x = 2t – 10. (x: km, t: h). What is the distance traveled by the particle after 2 hours?

x = 2t - 10

distance traveled after t = 2 hours

Substitute t = 2 in the given expression

x = 2 x 2 - 10

x = 4 - 10

x = - 6 km

So, the distance is 6 km.

Tick (3) the correct statement about electrostatic charges.
(a) Earthing causes positive charges to flow from the object to the ground.
(b) Similar types of electric charges attract one another.
(c) An electroscope is used to determine the presence of electrostatic charges.

Answers

Answer:

similar type of electric charges attract one another

I think this is a coorect staement

Answer:

C ) An electroscope is used to determine the presence of electrostatic charges

the scientist who gives the definition of work

Answers

Answer:

Work, in physics, measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement. ... To express this concept mathematically, the work W is equal to the force f times the distance d, or W = fd.

Please help me with these I might need more than only 1 person to answer ​

Answers

Explanation:

a) copper

b) olive oil

Hope it helps✌✌

A ball is dropped from the roof of a 25-m-tall building. What is the velocity of the object when it touches the ground? Suppose the ball is a perfect golf ball and it bounces such that the ve locity as it leaves the ground has the same magnitude but the op posite direction as the velocity with which it reached the ground How high will the ball bounce? Now suppose instead that the ball bounces back to a height of 20 m. What was the velocity with which it left the ground?

Answers

Answer:

a)  [tex]h=25m[/tex]

b)  [tex]v=19.8m/sec[/tex]

Explanation:

From the question we are told that:

Height [tex]h=25m[/tex]

Bounce Height [tex]h'=20m[/tex]

Generally the Kinematic equation is mathematically given by

[tex]V=\sqrt{2gh}\\\\V=\sqrt{2*9.81*25}[/tex]

[tex]V=22.1m/sec[/tex]

Therefore Height

[tex]h=\frac{V^2}{2g}\\\\h=\frac{22.1^2}{2*9.81}[/tex]

[tex]h=25m[/tex]

b)

Generally the Kinematic equation is mathematically given by

[tex]v^2=2ah[/tex]

[tex]v^2=2*9.8*20[/tex]

[tex]v=\sqrt{2*9.8*20}[/tex]

[tex]v=19.8m/sec[/tex]

1. Una carga Q1 = + 12 μC se coloca a una distancia r = 0.024 m desde una carga Q2 = + 16 μC. a) Determina la magnitud de la fuerza electrostática que actúa sobre las dos cargas, Q1 y Q2. b) ¿Es la fuerza la atracción o repulsión? 2. Determina la intensidad del campo eléctrico a una distancia radial de r = 48 mm desde una carga de Q = 24 μC. 3. Una carga Q1 = 24 mC se coloca a una distancia r = 0.032 m desde una carga Q2 = - 12 μC. a. Determina la cantidad de energía potencial eléctrica que tiene la carga Q1. b. Determina el potencial eléctrico en la posición de Q2.

Answers

Answer:

1. a. 3,000 N

b. Repulsión

2. 46.875 × 10⁶ N/C

3. a. 81,000 J

b. 6.75 × 10⁹ V

Explanation:

1. Los parámetros dados son;

Q₁ = +12 μC, Q₂ = +16 μC

La distancia entre las cargas, r = 0.024

La magnitud de la fuerza electrostática, F, entre cargas se da como sigue;

[tex]F = k \times \dfrac{Q_1 \cdot Q_2}{r^2}[/tex]

Donde, k = constante de Coulomb = 9.0 × 10⁹ N · m² / C²

Por lo tanto, obtenemos;

F = 9.0 × 10⁹ × 12 × 10⁻⁶ × 16 × 10⁻⁶ / 0.024² = 3.000

La magnitud de la fuerza electrostática, entre las cargas, F = 3000 N

(b) Dado que tanto Q₁ como Q₂ son cargas positivas, y las cargas iguales se repelen entre sí, la fuerza es la repulsión.

2) La intensidad de un campo eléctrico, E, se da como sigue;

[tex]E = \dfrac{k \cdot Q}{r^2}[/tex]

La magnitud de la carga, Q = 24 μC

La distancia donde se mide el campo, r = 48 mm = 0.048 m

Por lo tanto, E = 9.0 × 10⁹ × 12 × 10⁻⁶ / 0.048² = 46,875,000 N / C

La intensidad de un campo eléctrico, E = 46,875,000 N / C = 46.875 × 10⁶ N / C

3. La magnitud de las cargas son;

Q₁ = 24 mC

Q₂ = -12 μC

La distancia entre las cargas, r = 0.032 m

un. El potencial eléctrico de una carga, [tex]U_E[/tex] , se da de la siguiente manera;

[tex]U_E = k \times \dfrac{Q_1 \cdot Q_2}{r}[/tex]

Por lo tanto;

[tex]U_E[/tex] = 9.0×10⁹ × 24 × 10⁻³ × (-12) × 10⁻⁶ /0.032 = -81,000

La energía potencial eléctrica entre la carga, Q₁ y Q₂= -81,000 J

b. El potencial eléctrico de Q₁ en Q₂, V₁ = [tex]k \times \dfrac{Q_1 }{r}[/tex]

Por lo tanto, V₁ = 9.0×10⁹ × 24 × 10⁻³/0.032 = 6.75 × 10⁹

El potencial eléctrico de Q₁ en Q₂, V₁ = 6.75 × 10⁹ V

Which type of electromagnetic wave is deliberately used in some
circumstances to cause damage to living cells in the human body?
A. Infra-red
B. Gamma rays
C. Microwaves
D. Radio waves.

Answers

Gamma rays

used in radiotherapy

.............................

Answers

Dot, dot, dot, dot, lol

A skipper on a boat notices wave crests passing his anchor chain every 5.6 s . He estimates the distance between wave crests to be 16 m . He also correctly estimates the speed of the waves. Find this speed.

Answers

Answer:

v = 2.85 m/s

Explanation:

Given that,

A skipper on a boat notices wave crests passing his anchor chain every 5.6 s.

The distance between wave crests to be 16 m.

We need to find the speed of the waves. The speed of a wave can be calculated by the formula as follows :

[tex]v=f\lambda\\\\v=\dfrac{\lambda}{T}\\\\v=\dfrac{16}{5.6}\\\\v=2.85\ m/s[/tex]

So, the speed of the wave is 2.85 m/s.

Define derived unit with example​

Answers

Answer:

A derived unit is a SI unit of measurement comprised of a combination of the seven base units. Like SI unit of force is the derived unit, newton or N where N=s21×m×kg. There are some commonly used derived units which includes: 1. Pressure = AreaForce=m2N.

Explanation:

What is the centripetal acceleration of a point on the perimeter of a bicycle wheel diameter 70.0 cm when the bike is moving 8.0 m/s? (160 m/s)

Answers

It’s 180 m/s^2 dude. I think I have you in my class lol.

The centripetal acceleration of an object is due to the changing velocity in a circular path and the centripetal acceleration of the bicycle is 182.85 m/s².

What is Centripetal acceleration?

Centripetal acceleration of an object can be defined as the property of the motion of an object which is traversing a circular path. Any object which is moving in a circular path and has an acceleration vector pointed towards the center of that circular path is known as Centripetal acceleration.

The centripetal acceleration of an object can be calculated by the formula:

ac = v²/ r

where, ac = centripetal acceleration,

v = velocity of the object,

r = radius of the circular path

The centripetal acceleration of the object will be:

ac = (8)²/ r

radius = diameter/ 2

radius = 70/ 2

radius = 35cm or 0.35 m

ac = 64/ 0.35

ac = 182.85 m/s²

Therefore, the centripetal acceleration of the bicycle will be 182.85 m/s².

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The T-chart compares the average temperature and humidity of two different environments. Which of the following correctly labels the environments?

a t-chart with one column labeled A listing: High humidity: 70%, Temperature Range: 2 degrees Celsius (35 degrees Fahrenheit) in the winter to 24 degrees Celsius (75 degrees Fahrenheit); and another column labeled B listing: Low humidity (13-15%), Temperature Range: -18 degrees Celsius (-1 degrees Fahrenheit) to 49 degrees Celsius (120 degrees Fahrenheit)

A is a desert, and B is a tundra.
A is a grassland, and B is a desert.
A is a tundra, and B is a rainforest.
A is a tundra, and B is a swamp.

Answers

Answer:

A turndra B rainforest

Explanation:

Assuming Faraday constant to be 96500c/mol and relative atomic mass of copper 63,calculate the mass of copper liberated by 2A current in 5min.ans 0.196gm ​

Answers

Answer: The mass of copper liberated is 0.196 g.

Explanation:

The oxidation half-reaction of copper follows:

[tex]Cu\rightarrow Cu^{2+}+2e^-[/tex]

Calculating the theoretical mass deposited by using Faraday's law, which is:

[tex]m=\frac{M\times I\times t(s)}{n\times F}[/tex] ......(1)

where,

m = actual mass deposited = ? g

M = molar mass of metal = 63 g/mol

I = average current = 2 A

t = time period in seconds = 5 min = 300 s (Conversion factor: 1 min = 60 sec)

n = number of electrons exchanged = 2

F = Faraday's constant = 96500 C/mol

Putting values in equation 1, we get:

[tex]m=\frac{63 g/mol\times 2A\times 300s}{2\times 96500 C/mol}\\\\m=0.196g[/tex]

Hence, the mass of copper liberated is 0.196 g.

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On November 1, Equipment had a beginning balance in the Office Supplies account of . During the month, purchased of office supplies. At November 30, Equipment had of office supplies on hand.Required: The Office Supplies T-account has been opened for you. Post the beginning balance and purchase of office supplies. Please help me. Taylor pays $5.25 for 5 yard of frabric.Whats the cost per yard?Thank you! how to locate square root 100 on number line Find hypotenuse,perpendicular and base A political campaign manager must decide whether to emphasize television advertisements or letters to potential voters in a reelection campaign. Describe the production function for campaign votes. A. Campaign managers produce campaign votes. B. Reelection campaigns produce campaign votes. C. Television advertisements and campaign votes produce letters to potential voters. D. Television advertisements and letters to potential voters produce reelection campaigns. E. Television advertisements and letters to potential voters produce campaign votes. How might information about this function (such as the shape of the isoquants) help the campaign manager plan strategy? A. If the marginal rate of technical substitution of television advertisements for letters to potential voters is constant, then the campaign manager should use a combination of the two inputs. B. If television advertisements and letters to potential voters are perfect complements, then the campaign manager should use them in fixed proportions. C. If television advertisements and letters to potential voters are perfect substitutes, then the campaign manager should use them in fixed proportions. D. If the isoquant curves for television advertisements and letters to potential voters are convex, then the campaign manager should use only the cheaper input per vote. E. If the isocost lines for television advertisements and letters to potential voters are convex, then the campaign manager should use a combination of the two inputs. PLEASE HELP ASAPI WILL MARK BRAINLIEST apply the dristrbutie property to factor out the greatest common factor of (8)(x)-20 The NLRA was created in order to give workers the right to Use the remainder term to find the minimum order of the Taylor polynomial, centered at 0, that is required to approximate the following quantity with an absolute error no greater than 10^-2.1.06.n>= __________ Binford Corporation's contribution margin ratio is 58%, and its fixed monthly expenses are $94,000. Assume that the company's sales for May are expected to be $178,000.Required:Estimate the company's net operating income for May, assuming that the fixed monthly expenses do not change. Two representative elements are in the same period of the periodic table. 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After completing a study, the digital marketing specialist found that the average number of hashtags used by a marketing agency in a social media post is 7.9 hashtags on average.As the digital marketing specialist sets up a hypothesis test to determine if their belief is correct, what is their claim?a. The average number of hashtags used in a social media post from a marketing agency is different than 7 hashtags.b. The average number of hashtags used in a social media post from a marketing agency is different than 7.9 hashtags.c. Marketing agencies use too many hashtags in a social media post.d. The average number of hashtags used in a social media post from a marketing agency is 7 hashtags. Help please anyone??? Use the distributive property to rewrite this expression, then simplify the new expression, if possible.-3(y+2) Presented below are definitions of certain terms. Select the appropriate term from the dropdown list. Definitions 1. 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