Mathhhhhhhhhhhhhhhhhhhhhhhh Algebraaaaaaaa

Answer:

56

Step-by-step explanation:

that is the procedure above

The missing segment in the image below is 8.

The missing segment is the side length of the small triangle that is formed by the two red lines and the green line. We can find the length of this side length by using the Pythagorean Theorem.

The Pythagorean Theorem states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. In this case, the hypotenuse is the missing segment, and the other two sides are 4 and 5.

missing [tex]segment^2[/tex] = [tex]4^2[/tex] + [tex]5^2[/tex]

missing [tex]segment^2[/tex] = 16 + 25

missing [tex]segment^2[/tex] = 41

missing segment = √41

Therefore, the missing segment is √41.

Here are the steps in detail:

Identify the small triangle that is formed by the two red lines and the green line.

Label the sides of the triangle with the letters A, B, and C, where C is the missing segment.

Substitute the known side lengths into the Pythagorean Theorem.

Solve for the length of the missing segment.

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Answer:

None of these are correct.

Step-by-step explanation:

Multiplication property - Incorrect since no multiplication is involved

Subtraction property - Incorrect since no subtraction is involved

Reflexive property - This one's tough, but switching the order of the terms does not apply to the property

So, D is correct.

Complete Question

The complete Question is attached below

Answer:

Option D

Step-by-step explanation:

From the question we are told that:

Slant asymptote of [tex]y = 2x[/tex]

Vertical asymptote at [tex]x = 1,[/tex]

Points (0,6)

Generally the Denominator  is give as

With

Vertical Asymptote at

[tex]x -1=0[/tex]

Therefore

Denominator = (x-1)

Generally Slant asympote 2x Gives the Coefficient of the numerator

Therefore

The expression for a rational function f(x) that satisfies the conditions

[tex]F(x)=\frac{2x^2-2x-6}{x-1}[/tex]

Option D

Hi there!

[tex]\large\boxed{ 14.875}[/tex]

Our interval is from 0 to 3, with 6 intervals. Thus:

3 ÷ 6 = 0.5, which is our width for each rectangle.

Since n = 6 and we are doing a right-riemann sum, the points we will be plugging in are:

0.5, 1, 1.5, 2, 2.5, 3

Evaluate:

(0.5 · f(0.5)) + (0.5 · f(1)) + (0.5 · f(1.5)) + (0.5 · f(2)) + (0.5 · f(2.5)) + (0.5 · f(3)) =

Simplify:

0.5( -2.75 + (-3) + (-.75) + 4 + 11.25 + 21) = 14.875

Answer: (C) [tex]y+1=-2(x-2)[/tex]

Step-by-step explanation:

Slope: y = mx +b

By looking at the graph we can see that the slope has a rise of 2 and a run of -1 (aka. -2x) We can also tell that this has a y-intercept of 3

So our slope is: y = -2x + 3

Now you just have to find the answer that matches.

Answer:

Step-by-step explanation:

[tex]\frac{57}{40.3}=\frac{23}{QR} \\[/tex]

cross multiply

57(QR)=926.9

QR=16.26...

round to nearest tenth

QR=16.3

9514 1404 393

Answer:

  x = 4  or  x = 5

Step-by-step explanation:

Maybe you want to solve ...

  [tex]\dfrac{x-2}{x+2}-\dfrac{3}{x-2}=2\dfrac{x-11}{x^2-4}\\\\\dfrac{(x-2)^2-3(x+2)-2(x-11)}{x^2-4}=0\\\\\dfrac{x^2 -4x+4-3x-6-2x+22}{x^2-4}=0=\dfrac{x^2-9x+20}{x^2-4}\\\\{x^2-9x+20}=0=(x-5)(x-4)\ \Rightarrow\ x=\{4,5\}[/tex]

The solutions are x=4 and x=5.

_____

Additional comment

The Order of Operations requires that we interpret your input as ...

  x -(2/x) +2 -(3/x) -2 = (2(x -11)/x^2) -4

This is probably not what you want.

In order to get the interpretation we have used above, you need to use parentheses around any numerator or denominator containing arithmetic operations:

  (x -2)/(x +2) -3/(x -2) = 2(x -11)/(x^2 -4)

Answer:

3.6cm cubed

Step-by-step explanation:

First solve for both glasses' volumes.

Use l×w×h to plug in the numbers:

3.1×2×3=18.6

3.7×2×3=22.2

then subtract= 3.6

Answer:

3.6 [tex]cm^{3}[/tex]

Step-by-step explanation:

Volume for first container is 3.1 x 2 x 3 = 18.6

Volume for second container is 3.7 x 2 x 3 = 22.2

22.2 - 18.6 = 3.6

The value of COS Cx sin A by the given data is V3/4.

Trigonometric identities are the functions that include trigonometric functions such as sine, cosine, tangents, secant, and, cot.

Trigonometric ratio can be defined in terms of ratios of perpendicular, bases and hypotenuse. These are defined only in right angled triangles (triangles whose one angle is of 90 degree measure).

We are given that;

AB = 1, AC = 2 and BC = V3

Now,

To find the value of cos C x sin A, we need to use the trigonometric ratios of the right triangle.

We know that cos C = adjacent/hypotenuse = AB/AC = 1/2 and sin A = opposite/hypotenuse = BC/AC = V3/2.

cos C x sin A = (1/2) x (V3/2) = V3/4.

Therefore, by the trigonometric ratio the answer will be V3/4.

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Answer:

m=40

Problem:

If 7x^2 - mx-12 is equal to (7x + n)(x-6), where m and n are constants, find the value of m.

Step-by-step explanation:

We want to find n amd m such that

(7x+n)(x-6)=7x^2-mx-12.

Since (ax+b)(cx+d)=acx^2+(ad+bc)x+bd, then we need or should have the following:

(7x)(x)=7x^2

(7×-6+n×1)x=-mx

(n)(-6)=-12

The bottom equation tells us n=2 since 2(-6)=-12.

The first equation is already true.

Now we must solve (7×-6+n×1)x=-mx with n=2 for m.

That is we need to solve 7×-6+2×1=-m

Simplify and done -m=-42+2=-40 so m=40.

Let's do a check

7x^2 - mx-12 is equal to (7x + n)(x-6)

7x^2-40x-12 is equal to (7x+2)(x-6)

(7x+2)(x-6)=7x(x)+7x(-6)+2(x)+2(-6)

(7x+2)(x-6)=7x^2-42x+2x-12

(7x+2)(x-6)=7x^2-40x-12 and that is what we wanted.

Another way:

We want (7x+n)(x-6)=7x^2-mx-12 to be true for all x.

So if x=0 or for x=1, we want the equation to be true.

Insert x=0. This gives (n)(-6)=-12 which implies n=2.

(7x+2)(x-6)=7x^2-mx-12

Insert x=1. This gives (7+2)(1-6)=7-m-12.

Simplify both sides: 9(-5)=-m-5

Continue to simplify left side: -45=-m-5

Add 5 on both sides: -40=-m

Multiply both sides by -1: 40=m

2)0000==============]

Answer:

[tex] \frac{ - 8 - \sqrt{288} }{2 \times ( - 2)} = \frac{ - 8 -16.97 }{ - 4} = \frac{ - 24.97}{ - 4} = 6.2425[/tex]

Answer:

252

Step-by-step explanation:

Answer:

I think sqrt(74/3)

Step-by-step explanation:

I saw this problem before

Answer:

B

Step-by-step explanation:

when grouping the like terms the 20 will become a negative therefore -20-5 is -25 so the 5d has to be divided into -25 and not 15.. making the rest of the answer wrong.

-5-20=5d

-25/5=5d/5

-5=d

I hope this helps

Answer:

Step 2

Step-by-step explanation:

khan

Answer:

angle NQT equals angle STR

Step-by-step explanation:

You already have two angLes, you just need a side to be able to say the AAS Theorem. The answer is the remaining side to figure that out

Answer:

5500m..................

Answer:

x=19.27329

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp / hyp

tan 56 = x/ 13

13 tan 56 = x

x=19.27329

Answer:

-4√5

Step-by-step explanation:

-√5-3√5

-√5(1 + 3)

-4√5

Answer:

yup you're answer is correct

Answer:

0.01235

Step-by-step explanation:

we can solve for probability by using the formula;

favourable outcome/total number of outcomes

in this question, the number of favorable outcome = 3

the total number of outcomes = 3⁵

=  3x3x3x3x3 = 243

probability = 3/243

= 0.012345678

this can be approximated to be 0.01235

0.01235 is therefore the probability that all 5 customers would pick the same soft drink as their favorite drink.

Answer:

...-243, 729, -2187

Step-by-step explanation:

-3, 9, -27, 81, -243, 729, -2187

Everytime ×(-3)

-3×(-3)=9

9×(-3)=-27

-27×(-3)=81

Etc.

Answer:

94

Step-by-step explanation:

PQS = (7x - 6)°

SQR = (4x + 15)° since QS bisect PQR these two expressions must be equal

so

7x - 6 = 4x + 15 transfer like terms to the same side of the equation

7x - 4x = 15 + 6

3x = 21 divide both sides by 3

x = 7

also the sum of these two would give us the measure of PQR

7x + 4x + 15 - 6 = PQR

11x + 9 = PQR replace x with 7

11*7 + 9 = 86 this is the measure of angle PQR and also supplementary to PQT so the measure of PQT = 180 - 86

If QS bisects angle PQR. the m<PQT=94 °

Given :

Measure of angles    PQS = (7x - 6)° , and m angle SQR = (4x + 15)°

QS bisects angle PQR. So m<PQS=m<SQR

[tex]7x-6=4x+15\\Solve \; for \; x\\7x-4x-6=15\\3x-6=15\\3x=15+6\\3x=21\\divide \; by \;3 \\x=7[/tex]

Now we find out m<PQR

[tex]m<PQR=m<PQS+m<SQR\\m<PQR=7x-6+4x+14\\m<PQR=11x+8\\x=7\\m<PQR=11(7)+8=85[/tex]

We know that <PQR and <PQT  are linear pair of angles

The sum of linear pair of angles are supplementary

[tex]m<PQR+m<PQT=180\\86+m<PQT=180\\m<PQT=180-86\\m<PQT=94[/tex]

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Answer:

There were 44 students in each bus.

Step-by-step explanation:

357 - 5 = 352

352/8 = 44

Answer:

Step-by-step explanation:

Total students = 357

Total buses filled = 8

No of students traveled in car = 5

Remaining students = 357 - 5 = 352

Students in each bus = 352 ÷ 8 = 44 students

Answer:

[tex]GF=72[/tex]

Step-by-step explanation:

All triangles in the given figure are similar, from SAS. Notice that marked in the diagram, [tex]CD=DE=EF=FA[/tex].

For triangle [tex]\triangle CGF[/tex] was base [tex]GF[/tex], leg [tex]CF[/tex] contains three of these marked segments. In triangle [tex]\triangle CHE[/tex] with base [tex]HE[/tex], leg [tex]CE[/tex] has two of these marked segments. By definition, similar polygons have corresponding sides in a constant proportion. Therefore, the length of GF must be [tex]3/2[/tex] the length of EH. Since the length of EH is given as 48, we have:

[tex]GF=\frac{3}{2}EH, \\\\GF=\frac{3}{2}\cdot 48,\\\\GF=\boxed{72}[/tex]

Answer:

B one

Step-by-step explanation:

3y + 5 - 2y = 11

3y -2y + 5 = 11

Combine like terms

y + 5 = 11

Subtract  5 from both sides

y = 11 - 5

y = 6

So, Only one solution

Answer:

there is only 1 solution.

Step-by-step explanation:

We can solve the equation to find it's number of solutions, but we already know it only has 1 solution because it is a linear equation (y is raised to the first power).

3y + 5 − 2y = 11

y + 5 = 11

y = 6

This confirms that there is only 1 solution.-------