Martha, a first-grade teacher, is worried that if doesn't stay In at work to grade papers her principal will think she is lazy She is also worried that if she stays late at work her partner will be angry. This of conflict is known as

Answers

Answer 1
The type of conflict Character vs self
Answer 2

Answer:

Character vs self

Explanation:

The reason is because Martha is thinking to much about the negative things and it is making her feel like she is fighting her own body for control.


Related Questions

A 2 cm object is 10 cm from a convex lens that has a focal length of 4.4 cm. The image is 8 cm from the lens.

The height of the image, to the tenths place, is
cm.

Answers

Answer:

-1.6

Explanation:

e2021

The Height of an Image for a Convex Mirror is calculated by using magnification equation

m = h(i) / h(o)  = − d(i) / d(o) ,where  

the magnification index of the mirror, m

the height of the object, h(o)

the height of the image, h(i)

the distance between the object and the mirror, d(o)

the distance between the image and the mirror, d(i)

h(i)/ 2 = -8 / 10

h(i) = -1.6 cm.

What is convex mirror ?

"Convex Mirror is a curved mirror where the reflective surface bulges out towards the light source. This bulging out surface reflect light outwards and are not used to focus light."

What is magnification equation ?

"The formula for magnification is m=h(i)/h(o)=-d(i)/d(o). m is the total magnification; h(i) is the height of the image; h(o) is the height of an object; d(i) is the distance from the lens to the in focus projected image; d(o) is the distance of the object to the lens. The negative sign represents that the image is inverted."

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Calculate the momentum of a boat with a mass of 95kg moving at 2m/Ss

Answers

Answer:

190 kg m/s

Explanation:

Momentum = Velocity × Mass

→ Substitute in values

2 × 95 = 190 kg m/s

The momentum of the boat of mass 95 Kg moving at 2 m/s will be 190 Kg m/s.

What is Momentum?

Momentum is defined as the product of mass of velocity. Momentum is a vector quantity. Mathematically, we can write momentum as -

p = mv

It is also the measure of the impact force imparted by any moving object, when it comes in contact with some other body.

Given is a boat with a mass of 95 Kg moving at 2 m/s.

Mass [m] = 95 Kg

Velocity [v] = 2m/s

We can write the momentum as -

p = mv

Substituting values, we get -

Momentum [p] = 95 x 2 = 190 Kg m/s

p = 190 Kg m/s

Therefore, the momentum of the boat of mass 95 Kg moving at 2 m/s will be 190 Kg m/s.

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The speed of the wooden bar is changed so that the bar hits the water fewer times each second.

What happens to the frequency of the waves produced?

A. Increases
B. Does not change
C. Decreases

Answers

Answer:

c - the frequency of the waves decreases

A highway speed limit is posted as 90 km/hr. Is this average speed or instantaneous speed? Explain your answer.

Answers

Answer: instantaneous speed.

Explanation: A highway speed limit posted as 90km/hr would be the instantaneous speed because it’s just the speed for that moment.

Is a violin and battery potential energy?

Answers

Explanation:  

In physics, potential energy is the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors. Common types of potential energy include the gravitational potential energy of an object that depends on its mass and its distance from the center of mass of another object, the elastic potential energy of an extended spring, and the electric potential energy of an electric charge in an electric field. The battery is storing the energy but give it something to power and it'll give its energy to the object and a violin strings are like ruber band and if you play the violin it releases a new type of energy sound energy.

what voltage produces a current of 100 amps with a resistance of 50 ohms

Answers

[tex]\bf{ \underline{Given:- }}[/tex]

[tex] \sf• \: Current \: (I) = 100 \: Amps.[/tex]

[tex] \sf• \: Resistance \: (R) = 50 \: ohms[/tex]

[tex] \\ [/tex]

[tex]\bf{ \underline{To \:  Find:- }}[/tex]

[tex] \sf• \: Voltage \: (V)[/tex]

[tex] \\ [/tex]

[tex] \huge\bf{ \underline{Solution:- }}[/tex]

[tex] \bf \red{ \bigstar{ \: The \: formula \: of \: Voltage \: (V) = IR}}[/tex]

[tex] \rightarrow \sf V = 100 \times 50[/tex]

[tex] \rightarrow \sf V = 5000[/tex]

[tex] \\ [/tex]

[tex] \bf \purple{Therefore, \: Volatage \: is \: 5000 \: v.}[/tex]

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