Mark buys a used car for $12,000. The value of the car depreciates 10% per year from the time he bought the car.
The value of Mark's car, V(t), can be represented by which of the following functions?
V(t) = –0.90t + 12,000
V(t) = –0.10t + 12,000
V(t) = 12,000(0.10)t
V(t) = 12,000(0.90)t

Step-by-step explanation:

Everything has been written ..

A answer b                      B answer c

Step-by-step explanation:

Answer:

It's C

Step-by-step explanation:

because there is a 90 degrees sigh behind it and those two angles need to add up to 90

Answer:

31

Step-by-step explanation:

b+59=90

b=90-59

b=31

hope it helps

Answer:

71

-133

Step-by-step explanation:

Given the polynomial :

3x³– 4x² + 7x + 5, when x = 3 and also when

x = –3.

Put x = 3

3(3)³– 4(3)² + 7(3) + 5

3(27) - 4(9) + 21 + 5

81 - 36 + 21 + 5

= 71

Put x = - 3

3(-3)³– 4(-3)² + 7(-3) + 5

3(-27) - 4(9) - 21 + 5

-81 - 36 - 21 + 5

= - 133

Answer:

Los costos de fabricación fijo y variables al 80 y 100% de su capacidad son:

80%:        Fijos  =  $169,000,000.00        Variables  =  $180,000,000.00

100%:        Fijos  =  $169,000,000.00        Variables  =  $225,000,000.00

Explicación:

Los costos totales de fabricación (CT) vienen dados por la suma de los costos fijos (CF) y los costos variables (CV), recordando que los costos fijos son aquellos en los que se incurre independientemente de que se esté operando o no; mientras que los costos variables son aquellos que dependen del nivel de actividad pues corresponden a consumibles en el proceso productivo.

En el caso estudio, se sabe que los costos variables de fabricación totalizan $180,000,000.00 al nivel de actividad de 80%. Ya que estos costos incrementan o disminuyen en relación con el nivel de actividad, planteamos una regla de tres simple para calcular los costos variables en los niveles de actividad 90% y 100%

Si al    80%    de actividad    ----------------    los CV son    $180,000,000.00

al    90%    de actividad        ----------------    los CV serán    x

x  =  [(90)(180,000,000.00)]/(80)  =  202,500,000.00

Los costos variables de fabricación al nivel de actividad de 90% son  $202,500,000.00

Si al    80%    de actividad    ----------------    los CV son    $180,000,000.00

al    100%    de actividad       ----------------    los CV serán    x

x  =  [(100)(180,000,000.00)]/(80)  =  225,000,000.00

Los costos variables de fabricación al nivel de actividad de 100% son  $225,000,000.00

Para conocer los costos fijos basta recordar que al nivel de actividad de 90% lo costos de fabricación totales son $371,500,000.00. Este monto es la suma de los costos fijos y los costos variables; así que:

CT  =  CV  +  CF             ⇒                CV  =  CT  -  CF          ⇒    

CV  =  371,500,000.00  -  202,500,000.00  =  169,000,000.00

Los costos fijos de fabricación son de $169,000,000.00

Conclusión:

Los costos de fabricación fijo y variables al 80 y 100% de su capacidad son:

80%:        Fijos  =  $169,000,000.00        Variables  =  $180,000,000.00

100%:        Fijos  =  $169,000,000.00        Variables  =  $225,000,000.00

Answer:

3 / 91

Step-by-step explanation:

Given :

Red balls = 3

Blue balls = 4

Green balls = 4

Yellow balls = 3

Total number of balls = (3+4+4+3) = 14

Sample space :

RR, BB, GG, YY, RB, BR, BG, GB, YG, GY, YR, RY, BY, YB, GR, RG

Probability of drawing two red balls without replacement :

1st draw :

P(red) = number of red balls / total number of balls

P(red) = 3/14

2nd draw :

P(red) = 2 / 13

Hence,

P(RR) = 3/14 * 2/13 = 6 / 182 = 3 / 91

Answer:

ok 200 we have to find 5% of 200 so since 200 is doable 100 we just multiply 5 by 2 to get 10

so out of the 200 people 10 of them have the mutation

Hope This Helps!!!

The answers isssssssss

$300

:)

Answer:

A

Step-by-step explanation:

Answer:

Answer is A

Step-by-step explanation:

Answer:

1

Step-by-step explanation:

Given the pulse rate for 12 students :

76 60 59 60 81 72 91 80 80 68 73 77

Creating class intervals ::

Width = 10

59, 60, 60, 68, 72, 73, 76, 77, 80, 80, 81, 91

Interval ____ Frequency

50 - 59 ______ 1

60 - 69 ______ 3

70 - 79 ______ 4

80 - 89 ______ 3

90 - 99 ______ 1

Frequebcy if the 50 - 59 class interval is 1

Answer:

3,964 ft

Step-by-step explanation:

555 / tan 8° = 555/0.14 = 3,964 ft

Step-by-step explanation:

Objective: Recall the properties.

a) 3+1=4

b) 3+7=7+3

c) 3+(7+4)=7+(3+4)

d). 3(7+4)=(3×7)+(3×4)

Answer:

6,825

Step-by-step explanation:

The principlal is #65,000

Rate, = 2%

= 2/100

= 0.02

Time= 5+0.25

= 5.25

Simple interest= 65,000×0.02×5.25

= 6,825

9514 1404 393

Answer:

  a(bc) = (ab)c

Step-by-step explanation:

The associative property of multiplication says the product is the same regardless of how the factors are grouped. That is demonstrated by the equality ...

  a(bc) = (ab)c

Step-by-step explanation:

Maple calculator used.........................

Answer:

Step-by-step explanation:

[tex]f(x)={x^2\sqrt{1+x}\over{(1+x^2)^{3\over{2}}}}\\\\f^\prime (x)=\frac{{{(x^2\sqrt{1+x})^\prime (1+x^2)^{\frac{3}{2}}+ (x^2\sqrt{1+x})}((1+x^2)^{\frac{3}{2}}})^\prime}{((1+x^2)^\frac{3}{2})^2}}}[/tex]

[tex](x^2 \sqrt{1+x})^\prime=2x\sqrt{1+x}+ \frac{x^2}{2\sqrt{1+x}}[/tex]

[tex]((1+x^2)^{\frac{3}{2}})^\prime=\frac{3}{2}(1+x^2)^{\frac{1}{2}} (2x)=3x(1+x^2)^{\frac{1}{2}}[/tex]

[tex]f^\prime(x)=\frac{\{(1+x^2)^{\frac{3}{2}}\}(2x\sqrt{1+x}+\frac{x^2}{2\sqrt{1+x}})+(x^2 \sqrt{1+x})(3x\sqrt{1+x^2})}{(1+x^2)^{3}}}[/tex]

[tex]\sqrt{1+x^2}=\sqrt{(1+x)(1-x)}[/tex]

[tex]f^\prime (x)=x\sqrt{1+x}~\frac{(1+x^2)^{\frac{3}{2}}(2+\frac{x^2}{2(1+x)})+3x^2\sqrt{1-x}}{(1+x^2)^3}[/tex]

Answer:

E is the subset of I

S is the subset of T

R ⊂ P

Step-by-step explanation:

Answer:

Step-by-step explanation:

yes

Answer:

V=πr2h /3

so we just substate and we get

V≈130.9

Answer: 130.83 units cubed

Step-by-step explanation:

The formula for finding the volume of a cone is [tex]\pi r^2\frac{h}{3}[/tex]

We will use 3.14 for pi.

[tex]3.14r^2\frac{h}{3}[/tex]

Now let's sub in our variables and solve

[tex]3.14(5^2)(\frac{5}{3})\\3.14(25)(\frac{5}{3})\\78.5(\frac{5}{3})\\130 \frac{5}{6}[/tex]

5/6 is about .83

130.83

Answer:

The number is four (4)

Step-by-step explanation:

look at the picture above, it explains everything

Answer:

The graph is in the second attached image.

Step-by-step explanation:

In the first attached image, you have three equation graphed, the first is in red color, it's the original equation:

I graphed this to obtain a clear relation between the equation and its derivatives, the second graphed equation is in blue color and it's the first derivative:

And at last, we have in green color the second derivative:

As you can see, you only need the first and the second derivatives in the exercise, by this reason, in the second attached image you have the graph as you need to show in this exercise.

Answer:

x = 10/11

Step-by-step explanation:

Your welcome! :)

Answer:

I say number 2 idrk so I hope I helped >-<

Answer:

m<1 = 60

m<2 = 30

m<3 = 80

Step-by-step explanation:

1. Solve for angle (1)

The sum of angles in any triangle is (180) degrees. As one can see, there is a (30) degree angle in this triangle, and a (90) degree angle. Bear in mind that the box around an angle indicates that it is a (90) degree angle. One can form an equation and solve for the unknown angle using this given information;

(30) + (m<1) + (90) = 180

Simplify,

120 + m<1 = 180

Inverse operations,

m<1 = 60

2. Solve for angle (2)

The vertical angles theorem states that when two lines intersect, the angles opposite each other are congruent. One can apply this theorem here by stating the following,

m<2 = 30

Thus one gets their answer, the measure of angle (2) must be (30) degrees by the vertical angles theorem.

3. Solve for angle (3)

As states above, the sum of angles in a triangle is (180) degrees. Since one has found the measure of angle (2), one can form an equation and solve for the measure of angle (3) using the given information, combined with the information found.

(m<2) + (70) + (m<3) = 180

Susbtitute,

30 + 70 + (m<3) = 180

Simplify,

100 + m<3 = 180

Invers eoperations,

m<3 = 80

Answer:

(1)

compound amount = 802.5 $

invest earned = 52.5 $

Step-by-step explanation:

total amount = 10000 $

let amount x invested in ventures A and remaining (1000-x) on ventures B

now,

6x/100 +23/400(1000-x ) = 588.75

{24x+23(1000-x)}/400 =588.75

x=235500-230000

x=5500

Amount invested on A = 5500$

Amount invested on B = 4500$

(2)

principle=750$

time= 1 year

effective invest rate = 7%

a) compound amount = p(1+(r/w)^t

=750{1+(7/100)}^1

=802.5$

b) invest earned = 802.5-700 = 52.5$

Answer:

I don't know what your school is doing but what happened to me was that I just waited for the test to be unlocked and I was working from home so I was able to keep my phone and I didn't need to be in a meeting

Answer:

81

Step-by-step explanation:

4 quarts = 1 gallon

there are 22 gallons so multiply 4 by 22

that equals 88 quarts then subtract 7

leaving you with 81 quarts

Step-by-step explanation:

obtuse angle is an angle whose measure is more than 90 degree but less than 180 degree..

So,

170°

Answer:

Alternate exterior

Step-by-step explanation:

Angles 2 and 7 are on exterior sides of the transversal and also are opposite to one another. They are classified as alternate exterior.

Answer:

alternate exterior angles

Step-by-step explanation:

2 and 7 are on opposite sides of the transversal so they are called alternate

They are on the outside of the parallel lines so the are called exterior

9514 1404 393

Answer:

  (d)  reflection about the x-axis, up 6 units

Step-by-step explanation:

The parent function y=1/x is multiplied by -1, which reflects it over the x-axis. Then 6 is added, which shifts it up 6 units.

The transformations are ...

  reflection about the x-axis, up 6 units