Let $DEF$ be an equilateral triangle with side length $3.$ At random, a point $G$ is chosen inside the triangle. Compute the probability that the length $DG$ is less than or equal to $1.$
Answers
[tex]|\Omega|=(\text{the area of the triangle})=\dfrac{a^2\sqrt3}{4}=\dfrac{3^2\sqrt3}{4}=\dfrac{9\sqrt3}{4}\\|A|=(\text{the area of the sector})=\dfrac{\alpha\pi r^2}{360}=\dfrac{60\pi \cdot 1^2}{360}=\dfrac{\pi}{6}\\\\\\P(A)=\dfrac{\dfrac{\pi}{6}}{\dfrac{9\sqrt3}{4}}\\\\P(A)=\dfrac{\pi}{6}\cdot\dfrac{4}{9\sqrt3}\\\\P(A)=\dfrac{2\pi}{27\sqrt3}\\\\P(A)=\dfrac{2\pi\sqrt3}{27\cdot3}\\\\P(A)=\dfrac{2\pi\sqrt3}{81}\approx13.4\%[/tex]
Answer:
13.44%
Step-by-step explanation:
For DG to have length of 1 or less, point G must be contained in a sector of a circle with center at point D, radius of 1, and a central angle of 60°.
The area of that sector is
[tex]A_s = \dfrac{n}{360^\circ}\pi r^2[/tex]
[tex]A_s = \dfrac{60^\circ}{360^\circ} \times 3.14159 \times 1^2[/tex]
[tex] A_s = 0.5254 [/tex]
The area of the triangle is
[tex] A_t = \dfrac{1}{2}ef \sin D [/tex]
[tex]A_t = \dfrac{1}{2}\times 3 \times 3 \sin 60^\circ[/tex]
[tex] A_t = 3.8971 [/tex]
The probability is the area of the sector divided by the area of the triangle.
[tex]p = \dfrac{A_s}{A_t} = \dfrac{0.5254}{3.8971} = 0.1344[/tex]
Related Questions
Scouts of ABC school made to run around a regular hexagonal ground fig 9, of perimeter 270 m .If they started running from point X and covered two fifth (2/5th) of the total distance.Which side of the ground will they reach?
Answers
Answer:
Scouts are on the third side in the sense they are running
Step-by-step explanation:
A regular hexagonal shape of perimeter 270 has each side of 270/6 = 45
Let´s call d the run distance then
d = 2/5 * 270 d = 108 m
We don´t have fig 9 available therefore if X is a vertex in the hexagon or at the middle point of one side, scouts are 108 m from the starting point which means they had run 2,4 sides of the hexagon. If X is not either a vertex or a middle point of a side then, we have two solutions for the question depending on the sense the scouts took when began the run (clockwise or counterclockwise)
La fuerza necesaria para evitar que un auto derrape en una curva varía inversamente al radio de la curva y conjuntamente con el peso del auto y el cuadrado de la velocidad del mismo. Supongamos que 400 libras de fuerza evitan que un auto que pesa 1600 libras derrape en una curva cuyo radio mide 800 si viaja a 50mph. ¿Cuánta fuerza evitaría que el mismo auto derrapara en una curva cuyo radio mide 600 si viaja a 60mph ?
Answers
Answer:
768 libras de fuerza
Step-by-step explanation:
Tenemos que encontrar la ecuación que los relacione.
F = Fuerza necesaria para evitar que el automóvil patine
r = radio de la curva
w = peso del coche
s = velocidad de los coches
En la pregunta se nos dice:
La fuerza requerida para evitar que un automóvil patine alrededor de una curva varía inversamente con el radio de la curva.
F ∝ 1 / r
Y luego con el peso del auto
F ∝ w
Y el cuadrado de la velocidad del coche
F ∝ s²
Combinando las tres variaciones juntas,
F ∝ 1 / r ∝ w ∝ s²
k = constante de proporcionalidad, por tanto:
F = k × w × s² / r
F = kws² / r
Paso 1
Encuentra k
En la pregunta, se nos dice:
Suponga que 400 libras de fuerza evitan que un automóvil de 1600 libras patine alrededor de una curva con un radio de 800 si viaja a 50 mph.
F = 400 libras
w = 1600 libras
r = 800
s = 50 mph
Tenga en cuenta que desde el
F = kws² / r
400 = k × 1600 × 50² / 800
400 = k × 5000
k = 400/5000
k = 2/25
Paso 2
¿Cuánta fuerza evitaría que el mismo automóvil patinara en una curva con un radio de 600 si viaja a 60 mph?
F = ?? libras
w = ya que es el mismo carro = 1600 libras
r = 600
s = 60 mph
F = kws² / r
k = 2/25
F = 2/25 × 1600 × 60² / 600
F = 768 libras
Por lo tanto, la cantidad de fuerza que evitaría que el mismo automóvil patine en una curva con un radio de 600 si viaja a 60 mph es de 768 libras.
Find the amplitude of y = -2 sin x
Answers
Answer:
Amplitude = 2
Step-by-step explanation:
The amplitude of this sine wave is 2 denoted by the coefficient -2 in front of the sin(x). The negative of the coefficient denotes that the sine wave is the opposite of the standard sine wave.
Cheers.
What is the reason: if a+c=b+c then a=b
Answers
Step-by-step explanation:
Example 1:
a+c=b+c then a=b
First let the value of a and b be different (not equal)
a=5
b=7
c=10
a+c=b+c
5+10=7+10
15≠17
Example 2:
Let the value a and b be equal (the same)
a=5
b=5
c=10
a+c=b+c
5+10=5+10
15=15
So when,
a+c and b+c is equal, a and b are always equal.
Hope this helps ;) ❤❤❤
Answer:
a=b
Step-by-step explanation:
Reason:
a+c=b+c
a-b=c-c
c-c would be 0
if a-b=c-c=0
a-b=0
Only if a=b can a-b=0
You can also take it as:
b-a=c-c (a+c=b+c)
b-a=0=c-c
Therefore b=a
By the way even I am a BTS army
what is y when X is 5? The Graph below shows the answer. Y=2 when X=10
Answers
━━━━━━━☆☆━━━━━━━
▹ Answer
Y = 1
▹ Step-by-Step Explanation
[tex]\frac{10}{2} = \frac{5}{y} \\\\10/5 = 2\\2/2 = 1\\\\Y =1[/tex]
Hope this helps!
CloutAnswers ❁
━━━━━━━☆☆━━━━━━━
what is the coefficient of the variable in the expression 4-3x
Answers
As per the question,
We have to find what's the coefficient.
Let's start to seperate the expression.
Here,
x is the variable,
4 is a number.
-3 is also a number.
4, -3x
The number with x here is -3 in (-3x) as the coefficient is (-3) in the given equation.
Answer:
Hey there!
Rearrange the expression to: -3x+4
The coefficient would be -3.
Let me know if this helps :)
3.03 times 10^-3 in scientific nation
Answers
Answer:
3.03 • 10⁻³ is scientific notation
0.00303 is decimal form
The fuel efficiency of one type of car is recorded in a scatterplot where the amount of gas used, x (in gallons), is paired with the distance traveled, y (in miles), for various trips. The equation for the line of best fit for the data is y = 28x. How can the y-intercept and slope of this line be interpreted
Answers
Answer:
The answer can be interpreted by the distance moved by each gallon :))
Step-by-step explanation:
Answer:
D.
Step-by-step explanation:
Just took it. Edg 2020. Hope this helps :)
5
What is the equation, in point-slope form, of the line that
is parallel to the given line and passes through the point
(-3, 1)?
4
3
2
(-3, 1)
42.27
1
5 4 3 2 1
2 3 4 5 x
y-1=-{(x+3)
y-1=-{(x + 3)
y-1= {(x + 3)
y-1= {(x + 3)
(-2, 4)
Answers
Answer: [tex]y-1=\dfrac32(x+3)[/tex]
Step-by-step explanation:
Slope of a line passes through (a,b) and (c,d) = [tex]\dfrac{d-b}{c-a}[/tex]
In graph(below) given line is passing through (-2,-4) and (2,2) .
Slope of the given line passing through (-2,-4) and (2,2) =[tex]\dfrac{-4-2}{-2-2}=\dfrac{-6}{-4}=\dfrac{3}{2}[/tex]
Since parallel lines have equal slope . That means slope of the required line would be .
Equation of a line passing through (a,b) and has slope m is given by :_
(y-b)=m(x-a)
Then, Equation of a line passing through(-3, 1) and has slope = is given by
[tex](y-1)=\dfrac32(x-(-3))\\\\\Rightarrow\ y-1=\dfrac32(x+3)[/tex]
Required equation: [tex]y-1=\dfrac32(x+3)[/tex]
What is the value of this expression? (the best answer receives a brainiest)
Answers
Answer:
answer is D
Step-by-step explanation:
2^4=16
16+(16-12)=20
over
(6+9)/(7-4)
15/3=5
so the new equation is 20/5=4
Answer:
D. 4
Step-by-step explanation:
Order of Operations: BPEMDAS
Step 1: Exponents
[tex]\frac{16 + (16 -3(4))}{(6+9)/(7-4)}[/tex]
Step 2: Parenthesis
[tex]\frac{16 + (16 -12)}{15/3}[/tex]
Step 3: Parenthesis
[tex]\frac{16 + 4}{15/3}[/tex]
Step 4: Divide
[tex]\frac{16 + 4}{5}[/tex]
Step 5: Add
[tex]\frac{20}{5}[/tex]
Step 6: Divide
4
The diagonal of rhombus measure 16 cm and 30 cm. Find it's perimeter
Answers
Answer:
P = 68 cmStep-by-step explanation:
The diagonals of the rhombus divide it into 4 congruent right triangles.
So we can use Pythagorean theorem to calculate side of a rhombus.
[tex](\frac e2)^2+(\frac f2)^2=s^2\\\\e=30\,cm\quad\implies\quad\frac e2=15\,cm\\\\f=16\,cm\quad\implies\quad\frac f2=8\,cm\\\\15^2+8^2=s^2\\\\s^2=225+64\\\\s^2=289\\\\s=17[/tex]
Perimeter:
P = 4s = 4•17 = 68 cm
Peter attempted to use the divide-center method to find the line of best fit on a scatterplot.
What was his mistake?
He had a different number of points to the left of the vertical line than to the right of the vertical line.
He had a different number of points above the line of best fit than below the line of best fit.
He didn’t approximate the center of the cluster located on the left side of the vertical line and of the cluster located on the right side of the vertical line.
He didn’t connect the centers of the clusters on the left side and right side of the vertical line to produce the line of best fit.
Answers
Answer:
He had a different number of points to the left of the vertical line than to the right of the vertical line.
Step-by-step explanation:
Divide-center method is the method which involves dividing the data on the graph into two equal parts and then fin the line of best fit. The center of each group is approximated and then a line is constructed between two centers which is estimated as line of best fit.
55.5% repeating as a decimal
Answers
Answer:
55.5 ÷ 100 = 0.555
Step-by-step explanation:
When you ask, "What is 55.5 as a decimal?", we assume you want to know what 55.5 percent is as a decimal. In other words, 55.5 percent converted to decimal.
First, we will tell you why it is useful to know 55.5 as a decimal.
Normally, to calculate 55.5 percent, you would multiply a number by 55.5 percent and then you would take the product of that and divide it by 100 to get the answer.
Instead, you can simply multiply a number by 55.5 as a decimal to get the answer.
55.5 percent means 55.5 per hundred. Therefore, to get 55.5 as a decimal, all you have to do is divide 55.5 by 100 like so:
55.5 ÷ 100 = 0.555
Answer:
55.5% = 0.555
Step-by-step explanation:
55.5% = 55.5/100 = 0.555
Find the value of x.
Answers
Answer:
x = 20
Step-by-step explanation:
Intersecting Chords Theorem: ab = cd
Step 1: Label our variables
a = x
b = x - 11
c = x - 8
d = x - 5
Step 2: Plug into theorem
x(x - 11) = (x - 5)(x - 8)
Step 3: Solve for x
x² - 11x = x² - 8x - 5x + 40
x² - 11x = x² - 13x + 40
-11x = -13x + 40
2x = 40
x = 20
Answer: x=20
Step-by-step explanation:
[tex]ab=cd[/tex]
[tex]x(x - 11) = (x - 5)(x - 8)[/tex]
[tex]x^2 - 11x = x^2 - 13x + 40[/tex]
[tex]x^2 - 11x = x^2 - 8x - 5x + 40[/tex]
[tex]-11x = -13x + 40\\2x = 40\\x = 20[/tex]
Find the area of the following shape. Show all work
Answers
Best way to solve this is by using
[tex] \sqrt{s(s - a)(s - b)(s - c)} [/tex]
[tex]where \: s = \frac{a + b + c}{2} [/tex]
s=(12+8+17)/2
=18.5
using the formulae
area =43.5
HELP ASAP
[tex]Given that $33^{-1} \equiv 77 \pmod{508}$, find $11^{-1} \pmod{508}$ as a residue modulo 508. (Give an answer between 0 and 507, inclusive.)[/tex]
Answers
===================================================
Work Shown:
[tex]33^{-1} \equiv 77 \text{ (mod 508)}\\\\(3*11)^{-1} \equiv 77 \text{ (mod 508)}\\\\3^{-1}*11^{-1} \equiv 77 \text{ (mod 508)}\\\\3*3^{-1}*11^{-1} \equiv 3*77 \text{ (mod 508)}\\\\11^{-1} \equiv 231 \text{ (mod 508)}\\\\[/tex]
Notice how 33*77 = 2541 and 11*231 = 2541
[tex]2541 \equiv 1 \text{ (mod 508)}[/tex] since 2541/508 has a remainder of 1.
So effectively [tex]33*77 \equiv 1 \text{ (mod 508)}[/tex] and [tex]11*231 \equiv 1 \text{ (mod 508)}[/tex]
Please help,thanks!(:
Answers
Answer:
<4=<2
x+30=2x+15
x=15
therefore <4=(15)+30
=45°
PROVE THAT:
cos 20° - sin 20° = \sqrt{2}sin25°
Answers
Answer:
See below.
Step-by-step explanation:
[tex]\cos(20)-\sin(20)=\sqrt{2}\sin(25)[/tex]
First, use the co-function identity:
[tex]\sin(90-x)=\cos(x)[/tex]
We can turn the second term into cosine:
[tex]\sin(20)=\sin(90-70)=\cos(70)[/tex]
Substitute:
[tex]\cos(20)-\cos(70)=\sqrt{2}\sin(25)[/tex]
Now, use the sum to product formulas. We will use the following:
[tex]\cos(x)-\cos(y)=-2\sin(\frac{x+y}{2})\sin(\frac{x-y}{2})[/tex]
Substitute:
[tex]\cos(20)-\cos(70)=-2\sin(\frac{20+70}{2})\sin(\frac{20-70}{2})\\\cos(20)-\cos(70) =-2\sin(45)\sin(-25)\\\cos(20)-\cos(70)=-2(\frac{\sqrt{2}}{2})\sin(-25)\\ \cos(20)-\cos(70)=-\sqrt{2}\sin(-25)[/tex]
Use the even-odd identity:
[tex]\sin(-x)=-\sin(x)[/tex]
Therefore:
[tex]\cos(20)-\cos(70)=-\sqrt{2}\sin(-25)\\\cos(20)-\cos(70)=-\sqrt{2}\cdot-\sin(25)\\\cos(20)-\cos(70)=\sqrt{2}\sin(25)[/tex]
Replace the second term with the original term:
[tex]\cos(20)-\sin(20)=\sqrt{2}\sin(25)[/tex]
Proof complete.
Which of the following images shows a scale copy of the trapezoid using a scale factor of 1/2
PLEASE HELP
Answers
Answer:
1
Step-by-step explanation:
split the shape to triangle and a rectangle
the rectangle at the original trapezoid has 2 squares in width and 3 squares for height multiply those numbers by 1/2 you will get 1 square for width and 1.5 squares for the height which is showen in option 1
THIS IS THE HARDEST WORK ON EART SOMEONE HELP ME
Answers
Answer:
a) 2 h 45 min
b) 2 h 50 min
c) 2 h 20 min
d) 3 h 20 min
Step-by-step explanation:
Answer:
a) hours: 9 hours 15 minutes
minutes: 555
b) hours: 9hours 10 minutes
minutes: 550
c) hours: 2hours 20 minutes
minutes: 140
d) hours: 3 hours 20 minutes
minutes: 200
Step-by-step explanation:
Black Diamond Ski Resort charges $25 for ski rental and $10 an hour to ski. Bunny Hill Ski Resort charges $50 for ski rental and $5 an hour to ski. Create an equation to determine at what point the cost of both ski slopes is the same.
Answers
Answer:
25 + 10h = 50+5h
Step-by-step explanation:
Black Diamond Ski Resort
25 + 10h
Bunny Hill Ski Resort
50+5h
We want when they are equal
25 + 10h = 50+5h
Answer:
10x + 25 = 5x + 50
Step-by-step explanation:
Use slope-intercept form to graph each system of equations and solve each system.
Answers
Answer:
(0,3), graph is attached.
Step-by-step explanation:
We know that the first equation will increase 2 points in y for every 1 x, since the constant next to x is 2. We also know it's y-intercept will be 3.
As for the second equation, we know it will have no y and instead run through the y=3 line, crossing every value of x.
Graphing this, we see that these lines intersect at (0,3) so that's the solution to this system.
Hope this helped!
land and sea corporation has just purchased some shoreline property, and according to their calculations it will cost 2.5 times as much to develop the land as much as it did to buy it. If land and sea believe it will end up spending a combined total of $13,457,500 on both the land and its developments, how much must be the land alone have cost?
Answers
Answer:
5,383,000 / *improvments cost 8,074,500
Step-by-step explanation:
if 2.5 is by 'times' then,
13,457,500 / 2.5 =
5,383,000
Which means the cost of the land is 5,383,000
To check just multiply:
5,383,000 x 2.5 = 13,457,500
*Extra
13,457,500 - 5,383,000
= the cost of improvements = 8,074,500
Hope this helps, and have a good day :)
Answer:
$3,845,000
Step-by-step explanation:
Land cost = lDevelopment cost = dTotal cost = $13,457,500As per given:
d= 2.5 lThen total is:
l+2.5l= 134575003.5l= 13457500l= 13457500/3.5l= $3845000Cost of the land alone is $3,845,000
How to do this question plz answer me step by step plzz plz plz plz plz plz plz plz
Answers
Answer:
288.4m
Step-by-step explanation:
This track is split into a rectangle and two semi-circles.
We can find the length of the semi-circles by finding its circumference with the formula [tex]2\pi r[/tex].
[tex]2\cdot3.14\cdot30\\188.4[/tex]
However this is half a circle, so:
[tex]188.4\div2=94.2[/tex].
There are two semi-circles.
[tex]94.2\cdot2=188.4[/tex]
Since there are two legs of 50m each, we add 100 to 188.4
[tex]188.4+100=288.4[/tex]m
Hope this helped!
Answer:
Step-by-step explanation:
To solve for the perimeter, we first look at the rectangle in the middle. the length is 50m, and there are two sides to it, so: 50 * 2 = 100m for the top and bottom of the track.
For the circle, we can see the diameter is 30m. To solve for the circumference, we need to use the formula 2πr.
15 * 2π ≈ 94.2477796077
We add that to 100m and get:
194.2477796077
Weather balloons burst at an altitude of 27.5 km. What is the altitude in meters?
Answers
Answer:
27500
Step-by-step explanation:
meters are 100 times more than kilometers hope this helps:)
A power failure on the bridge of a Great Lakes freighter has resulted in the ship's navigator having to do her own calculations. She measures the angle between the ship's course and a lighthouse on shore as 32°. After the ship has travelled 1500 m, she measures the angle to be 72°. Determine if the ship was closer to or farther from the lighthouse at the second sighting, and by what distance. (4 marks)
It is impossible to measure the length of a particular swamp directly. Kendra put a stake in the ground and measured from the stake to opposite ends of the swamp, the results being 410 m and 805 m. She measured the angle between the distances to be 57°. What is the length of the swamp? (4 marks)
Answers
Answer:
1) The ship is closer
2) 675.73 m
Step-by-step explanation:
1) The given parameters are;
The initial angle between the ship's course and the lighthouse = 32°
The final angle between the ship's course and the lighthouse = 72°
The distance traveled by the sip between he two positions = 1500 m
Therefore we have a triangle formed between the distance covered by the ship and the two distances of the ship from the lighthouse, a and b
Where;
a = The initial distance fro the lighthouse
b = The final distance fro the lighthouse
The angles of the triangle are
32°, (180 - 72) = 108° and 180 - 32 - 108 = 40°
By sine rule we have;
1500/(sin(40)) = a/(sin(108)) = b/(sin(32)) =
Therefore, a = sin(108°) × 1500/(sin(40°)) = 2219.37 m
b = (sin(32°)) × 1500/(sin(40°)) = 1236.61 m
Therefore, a > b
The initial distance fro the lighthouse > The final distance fro the lighthouse, which shows that the ship is closer
2) By cosine rule we have
a² = b² + c² - 2× b×c×cos(A)
Where the given measurements by Kendra are;
410 m and 805 m with an included (in between) angle of 57°, we have;
Let b = 410 m, c = 805 m, and A = 57°, we have;
a² = 410^2 + 805^2 - 2× 410×805×cos(57 degrees) = 456608.77 m²
a = The length of the stream = 675.73 m.
Autumn runs a farm stand that sells peaches and grapes. Each pound of peaches sells
for $2 and each pound of grapes sells for $4. Autumn sold 35 more pounds of grapes
than pounds of peaches and made $200 altogether. Graphically solve a system of
equations in order to determine the number of pounds of peaches sold, 2, and the
number of pounds of grapes sold, y.
Answers
Answer:
She sold 10 pounds of peaches and 45pounds of grapes
Step-by-step explanation:
X= pounds of peaches
x+35=pounds of grapes
2x+4(x+35)=200
2x+4x+140=200
6x=200-140
6x=60
x=10
She sold 10 pounds of peaches and 45pounds of grapes. (Sorry, can’t help you graph it.)
Given quadrilateral MATH is similar to quadrilateral ROKS calculate the value of MH Picture is below
Answers
=====================================================
Explanation:
The double tickmarks for quadrilateral MATH show that MA = TH. Since TH is 5 units long, this makes MA the same length as well.
For quadrilateral ROKS, we have RO = 15. For "MATH" and "ROKS" we have "MA" and "RO" as the first two letters of each four-letter sequence; meaning that MA and RO correspond together.
The ratio of the corresponding segments is RO/MA = 15/5 = 3.
The larger quadrilateral has each side length 3 times longer than the smaller quadrilateral's corresponding side lengths.
--------------
In short,
larger side = 3*(smaller side)
--------------
Using this scale factor of 3, we can find MH
larger side = 3*(smaller side)
RS = 3*(MH)
21 = 3*MH
3*MH = 21
MH = 21/3
MH = 7
please help me i offered all my points and this is really important!!! The question is attached.
Answers
Answer:
25[tex]\sqrt{3}[/tex] +60
Step-by-step explanation: The first thing you need to do is realize that, this figure is a isosceles trapezoid due to the markings on each side.
So now we know both sides are 10.
We also know the the top two angles are congruent to each other and so are the bottom two angles due to the trapezoid being isosceles.
So the top two angles are 120 degrees and bottom two angles are 60 degrees.
It seems like we can't find the sides, let's try drawing two lines from each top angle all the way down to form two right triangles.
Wow, these two triangles are special right triangles in the form of
30 - 60 - 90 degrees.
shorter side = n
longer side = n[tex]\sqrt{3}[/tex]
hypotenuse = 2n
So, 2n = 10
n = 5 for the short side
The bottom base is 4[tex]\sqrt{3}[/tex] + 5 + 5 = 10 + 4[tex]\sqrt{3}[/tex]
The longer side is 5[tex]\sqrt{3}[/tex].
The area of trapezoid = (base1 + base2)/2 * height
= (4[tex]\sqrt{3}[/tex] + 10 + 4[tex]\sqrt{3}[/tex])/2 * 5[tex]\sqrt{3}[/tex] = (10 + 8[tex]\sqrt{3}[/tex])/2 * 5[tex]\sqrt{3}[/tex] = (5+4[tex]\sqrt{3}[/tex])*5[tex]\sqrt{3}[/tex] = 25[tex]\sqrt{3}[/tex] +60
So, 25[tex]\sqrt{3}[/tex] + 60 is our answer.
Answer:
60 +25√3
Step-by-step explanation:
In the figure of the isosceles trapezoid below, the angles at C and D are supplementary to the given angle, so are 60°. That makes triangle BDE a 30°-60°-90° right triangle, which has side length ratios ...
DE : BE : BD = 1 : √3 : 2 = 5 : 5√3 : 10
Triangle BDE can be relocated to the other end of the figure to become triangle CAD'. Then the area of concern is that of the rectangle with height 5√3 and length 5+4√3. The area is then ...
Area = lh = (5√3)(5 +4√3) = 5·5√3 +5·4·3
Area = 60 +25√3 . . . square units
_____
In the figure, 6.93 = 4√3, and 8.66 = 5√3, 16.93 = 10+4√3.
every rational number is a
a. whole number b. natural number c. integer d. real number
Answers
Greetings from Brasil...
a - whole number
FALSE
3/5, for example isnt a whole number
b. natural number
FALSE
0,457888..., for example isnt a natural number
c. integer
FALSE - like a
d. real number
TRUE
The set of real numbers contains the set of rational numbers
ℝ ⊃ ℚ
