Let A represent the area in square feet, and h represent the height in feet. Identify which variable depends on which in the formula.

the area of a trapezoid with base lengths of 7 feet and 11 feet

Answer:

Step-by-step explanation:

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

µ ≤ 10

For the alternative hypothesis,

µ > 10

The inequality sign indicates that It is a right tailed.

Since the population standard deviation is not given, the distribution is a student's t.

Since n = 35,

Degrees of freedom, df = n - 1 = 35 - 1 = 34

t = (x - µ)/(s/√n)

Where

x = sample mean = 14.44

µ = population mean = 10

s = samples standard deviation = 4.45

t = (14.44 - 10)/(4.45/√35) = 5.9

We would determine the p value using the t test calculator. It becomes

p < 0.00001

Since alpha, 0.01 > than the p value, then we would reject the null hypothesis. Therefore, At a 1% level of significance, we can conclude that the true mean is greater than 10.

Answer:

It is x

Step-by-step explanation:

Answer:

x times y- q

Step-by-step explanation:

You can use the letters they give you on the answer choices. My answer makes sense because you multiply 48 times 15 and then subtract 32 from it

Answer:

x=5

Step-by-step explanation:

x, x+7, x+8 must be a Pythagorean triple for it to make a right triangle. The only Pythagorean triple fitting these numbers is 5, 12, 13 so x must be 5.

Answer:

5

Step-by-step explanation:

Because this is a right triangle, you know that by the Pythagorean theorem:[tex]\sqrt{(x+7)^2+x^2}=x+8[/tex]

Squaring both sides to get rid of the square root:

[tex](x+7)^2+x^2=(x+8)^2[/tex]

Expanding all of the parentheses:

[tex]x^2+14x+49+x^2=x^2+16x+64[/tex]

Combine like terms:

[tex]x^2-2x-15=0[/tex]

Factor:

[tex](x-5)(x+3)=0[/tex]

Since x cannot be negative, it is equal to 5. Hope this helps!

Answer:

  about 5.613 seconds

Step-by-step explanation:

Using the quadratic formula to find the value of t when h = 0, we have ...

  at² +bt +c = 0

  t = (-b±√(b²-4ac))/(2a)

  t = (-72±√(72² -4(-16)(100)))/(2(-16))

  t = (-72±√11584)/-32 = (9±√181)/4

Only the positive value of t is of interest.

  The coin will hit the stream after (9+√181)/4 seconds ≈ 5.613 seconds.

Answer

the answer is -56

Step-by-step explanation:

I don't usually do calculus on Brainly and I'm pretty rusty but this looked interesting.

We have to turn K into the limits of integration on our integrals.

Clearly 0 is the lower limit for all three of x, y and z.

Now we have to incorporate

x+y+z ≤ 1

Let's do the outer integral over x.  It can go the full range from 0 to 1 without violating the constraint.  So the upper limit on the outer integral is 1.

Next integral is over y.  y ≤ 1-x-z.   We haven't worried about z yet; we have to conservatively consider it zero here for the full range of y.  So the upper limit on the middle integration is 1-x, the maximum possible value of y given x.

Similarly the inner integral goes from z=0 to z=1-x-y

We've transformed our integral into the more tractable

[tex]\displaystyle \int_0^1 \int_0^{1-x} \int _0^{1-x-y} (x^2-z^2)dz \; dy \; dx[/tex]

For the inner integral we get to treat x like a constant.

[tex]\displaystyle \int _0^{1-x-y} (x^2-z^2)dz = (x^2z - z^3/3)\bigg|_{z=0}^{z= 1-x-y}=x^2(1-x-y) - (1-x-y)^3/3[/tex]

Let's expand that as a polynomial in y for the next integration,

[tex]= y^3/3 +(x-1) y^2 + (2x+1)y -(2x^3+1)/3[/tex]

The middle integration is

[tex]\displaystyle \int_0^{1-x} ( y^3/3 +(x-1) y^2 + (2x+1)y -(2x^3+1)/3)dy[/tex]

[tex]= y^4/12 + (x-1)y^3/3+ (2x+1)y^2/2- (2x^3+1)y/3 \bigg|_{y=0}^{y=1-x} [/tex]

[tex]= (1-x)^4/12 + (x-1)(1-x)^3/3+ (2x+1)(1-x)^2/2- (2x^3+1)(1-x)/3[/tex]

Expanding, that's

[tex]=\frac{1}{12}(5 x^4 + 16 x^3 - 36 x^2 + 16 x - 1)[/tex]

so our outer integral is

[tex]\displaystyle \int_0^1 \frac{1}{12}(5 x^4 + 16 x^3 - 36 x^2 + 16 x - 1) dx[/tex]

That one's easy enough that we can skip some steps; we'll integrate and plug in x=1 at the same time for our answer (the x=0 part doesn't contribute).

[tex]= (5/5 + 16/4 - 36/3 + 16/2 - 1)/12[/tex]

[tex]=0[/tex]

That's a surprise. You might want to check it.

Answer: 0

The 96% confidence interval for the proportion of all shrubs of this species that will resprout after fire is approximately 0.1274 to 0.5042.

Here, we have,

To estimate the proportion of all shrubs of this species that will resprout after fire with 96% confidence, we will use the formula for a confidence interval for a proportion.

The formula for the confidence interval for a proportion (p) is given by:

CI = p ± Z * √(p * (1 - p) / n)

where:

CI is the confidence interval

p is the sample proportion (resprouted specimens / total specimens)

Z is the critical Z-score corresponding to the desired confidence level (96% confidence level corresponds to a Z-score of approximately 1.750)

n is the sample size (total number of specimens)

Given information:

Total number of specimens (n) = 19

Number of specimens that resprouted after fire = 6

Now, calculate the sample proportion (p):

p = (number of specimens that resprouted) / (total number of specimens)

p = 6 / 19 ≈ 0.3158 (rounded to four decimal places)

Now, calculate the critical Z-score for a 96% confidence level (use a Z-table or calculator):

Z ≈ 1.750

Now, calculate the margin of error (E):

E = Z * √(p * (1 - p) / n)

E = 1.750 * √(0.3158 * (1 - 0.3158) / 19)

E ≈ 0.1884 (rounded to four decimal places)

Finally, calculate the confidence interval:

CI = p ± E

CI = 0.3158 ± 0.1884

The 96% confidence interval for the proportion of all shrubs of this species that will resprout after fire is approximately 0.1274 to 0.5042.

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Answer:

Which expression is equivalent to 3 over 175

I would say try - C or D

Answer:

You ugly i wanna fight on sight

Step-by-step explanation:

Answer:

x=4 and y=3

Step-by-step explanation:

put one of the equations in slope form and solve

Answer:x=4 y=3

Step-by-step explanation:

5x-4y=8.............(1)

2x+y=11................(11)

From (11) y=11-2x

Substitute y=11-2x in 5x-4y=8

5x-4y=8

5x-4(11-2x)=8

Open bracket

5x-44+8x=8

Collect like terms

5x+8x=8+44

13x=52

Divide both sides by 13

13x/13=52/13

x=4

Substitute x=4 in 2x+y=11

2(4)+y=11

8+y=11

Collect like terms

y=11-8

y=3

Answer:

x > 25

Step-by-step explanation:

x+25> 50

Subtract 25 from each side

x+25-25 >50-25

x > 25

Answer:

x>25

Step-by-step explanation:

x+25>50

1. Subtract 25 from both sides of the equation

x+25>50

  -25  -25

x>25

Answer:

You have to use this equation: [tex]a^{2} + b^{2} -c^{2}[/tex]

Step-by-step explanation:

C is the hypotenuse but you need another one  so you got to do

[tex]x^{2} +8^{2} =17^{2}[/tex]

now you have to find [tex]x^{2}[/tex] which is

[tex]x^{2} = 17^{2} - 8^{2}[/tex]

[tex]x^{2} = 289 - 64[/tex]

[tex]x^{2} = 225[/tex]

[tex]x = \sqrt{255}[/tex]

[tex]x = 15[/tex]

Answer:

17.9

Step-by-step explanation:

Answer:

27

Step-by-step explanation:

Input 5 for all x-values.

If that is an equal sign...

1/9*(3^5)

With PEMDAS, exponents are done before multiplication.

1/9*243

= 27

Answer:

[tex]k-m=b[/tex]

[tex]b-m=diff[/tex]

Step-by-step explanation:

If there are total of k students in a class, and m of those students are girls, the total amount of boys would be:

[tex]k-m=b[/tex]

(Where k, m, b are variables that represent the total number of students, the amount of girls and the amount of boys respectively)

As the amount of girls subtracted from the total amount would leave you with the amount of boys.

There would be:

[tex]b-m[/tex] more boys than girls.

If there were 10 total students in the class and 3 of those students were girls, lets use our above equations to see if they are correct - and if we get the expected amounts of:

7 boys in the class, and 4 more boys than there are girls.

[tex]k-m=b\\10-3=7\\7=7[/tex]

This is correct, as we expected this amount.

[tex]b-m=diff\\7-3=4[/tex]

The difference between them is 4, so this is correct.

Answer:440

Step-by-step explanation:

F=440(2)h/12 h=6

F=440 x 2 x 6/12

F=(440 x 2 x 6) ➗ 12

F=5280 ➗ 12

F=440

The answer in length

The length is used to measure the distance between to end points or edges. so 17 meters measurement represent the length.

Its the sum of length of the sides used to made the given figure.

Talia is going to put a new carpet in her house. She measure's one side of her living room and finds it measures 17 meters.

Area is what is on the inside.

The perimeter is the outside of the hole thing.

Hence, the length is used to measure the distance between to end points or edges.

so 17 meters measurement represent the length.

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Answer:

22,950 units³

Step-by-step explanation:

All you have to do is:

[tex]\frac{3}{4} *60*15*34=\\45*15*34=\\675*34=\\\\22,950[/tex]

Answer:

2.4c = 3.24

Step-by-step explanation:

Answer:

it is 4 ounces + 18 ounces

Answer:

[tex]r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}[/tex]

The value of r is always between [tex]-1 \leq r \leq 1[/tex]

And we have another measure related to the correlation coefficient called the R square and this value measures the % of variance explained between the two variables of interest, and for this case we have:

[tex]r^2 = 0.8^2 = 0.64[/tex]

So then the best conclusion for this case would be:

c. the fraction of variation in weights explained by the least-squares regression line of weight on height is 0.64.

Step-by-step explanation:

For this case we know that the correlation between the height and weight of children aged 6 to 9 is found to be about r = 0.8. And we know that we use the height x of a child to predict the weight y of the child

We need to rememeber that the correlation is a measure of dispersion of the data and is given by this formula:

[tex]r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}[/tex]

The value of r is always between [tex]-1 \leq r \leq 1[/tex]

And we have another measure related to the correlation coefficient called the R square and this value measures the % of variance explained between the two variables of interest, and for this case we have:

[tex]r^2 = 0.8^2 = 0.64[/tex]

So then the best conclusion for this case would be:

c. the fraction of variation in weights explained by the least-squares regression line of weight on height is 0.64.

Answer:

3

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile [tex](Q_1)[/tex]

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile [tex](Q_3)[/tex]

Terms in arranged in ascending order:

[tex]57,60,60,61,62,62,63,63,64[/tex]

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

[tex]Q_1[/tex] is median of terms [tex]57,60,60,61[/tex]

Number of terms (n) = 4

Median = [tex]\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60[/tex]

So, [tex]Q_1=60[/tex]

So, 25% of the heights of a team is less than 60 inches

[tex]Q_3[/tex] is the median of terms [tex]62,63,63,64[/tex]

Median = [tex]\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63[/tex]

So, [tex]Q_3=63[/tex]

So, 75% of the heights of a team is less than 63 inches

Interquartile range = [tex]Q_3-Q_1=63-60=3[/tex]

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

Answer:

i think ...

Step-by-step explanation:

symmetric distribution  usually be a bell shape distribution .

most likely the median = mean = 60

The required value of 60 could be the median of the distribution. Option B is correct.

The mean of the values is the ratio of the total sum of values to the number of values.

When a dataset is ordered, the median is the value that is exactly in the middle. It is a measure of central tendency that distinguishes between the lowest and top 50% of data.

Here,
The mean of a symmetric distribution is 60.
Since for the symmetric data and rational data, the mean is equal to the median,
So Mean = Median
Median = 60

Thus, the required value of 60 could be the median of the distribution.

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Answer:

the angle is acute angle

Answer:

The type of angle shown is an acute angle

Step-by-step explanation:

there are 4 main types of angles. this is an acute angle as it is less than 90°.

Types of angles:

The 4 main types of angles are: acute, obtuse, right angles, reflex angles.

Acute angles- Acute angles are angles less than 90°.

Obtuse Angles-Obtuse angles are angles greater than 90° but less than 180°.

Right Angles- Right angles are angles of 90°.

Reflex Angles- Reflex angles are angles greater than 180° but less than 360°.

Answer:

$353.28

Step-by-step explanation:

Answer: Yes

Step-by-step explanation:

It isn't an

1 an improper fraction

Less than the denominator

Therefore, three thirds or 3/3 is one whole fraction

Rly hope I helped!

☆꧁Ashlin꧂☆

Answer:yes he his correct

Step-by-step explanation:

3/3=1

Answer:

The attendance was 198 children, 90 students and 99 adults.

Step-by-step explanation:

We define:

c: children attendance

s: students attendance

a: adult attendance

The equation that describes the total ticket sales is:

[tex]5c+7s+12a=2808[/tex]

We also know that the children attendance doubles the adult attendance:

[tex]c=2a[/tex]

The third equation is the seating capacity, which we assume is full:

[tex]c+s+a=387[/tex]

We start by replacing variables in two of the equations:

[tex]c=2a\\\\s=387-c-a=387-2a-a=387-3a[/tex]

Then, we solve the remaining equation for a:

[tex]5c+7s+12a=2808\\\\5(2a)+7(387-3a)+12a=2808\\\\10a+(2709-21a)+12a=2808\\\\10a+12a-21a=2808-2709\\\\a=99[/tex]

Then, we solve for the other two equations:

[tex]c=2a=2*99=198\\\\s=387-3a=387-3*99=387-297=90[/tex]

The attendance was 198 children, 90 students and 99 adults.