Land surveyors outlined a park as shown. What is the area of the park?

Answer: (a)

Step-by-step explanation:

Given

There are 5 squads for an athletic scrimmages

If each team played 2 matches

Total no of matches will be

[tex]\Rightarrow \dfrac{5(5-1)}{2}\times 2=20\ \text{matches}[/tex]

So, 20 matches are played in 2 hours

Each match takes

[tex]\Rightarrow \dfrac{120}{20}=6\ \text{minute}[/tex]

Option (a) is correct.

Answer:

The number that comes after 144five is:

= 200five.

Step-by-step explanation:

Adding 1 to 144 base 5 will result in:

144

+  1

= 200

b) To obtain the next number that comes after 144five, add 1five to 144five.  Since the numbers are in base 5, 1five added to 4five will result in 0 with 1 carried backward.  When 1 is added to the next 4, the result will be 0 with 1 carried backward.  1 added to 1 = 2, all in base 5.  Figures in base 5 cannot exceed 4.  The usual numbers for a base 5 operation are 0, 1, 2, 3, and 4.

Answer:

a) IQ scores of 94.2 and below represent the bottom 35%.

b) An IQ score of 110.1 represents the 3rd quartile.

c) IQ scores of 124.7 and higher are in the top 5%.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 100 and a standard deviation of 15.

This means that [tex]\mu = 100, \sigma = 15[/tex]

(a) Find the IQ scores that represent the bottom 35%.

The 35th percentile and below, in which the 35th percentile is X when Z has a p-value of 0.35, so X when Z = -0.385.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-0.385 = \frac{X - 100}{15}[/tex]

[tex]X - 100 = -0.385*15[/tex]

[tex]X = 94.2[/tex]

IQ scores of 94.2 and below represent the bottom 35%.

(b) Find the IQ score that represents the 3rd Quartile.

This is the 100*3/4 = 75th percentile, which is X when Z has a p-value of 0.75, so X when Z = 0.675.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]0.675 = \frac{X - 100}{15}[/tex]

[tex]X - 100 = 0.675*15[/tex]

[tex]X = 110.1[/tex]

An IQ score of 110.1 represents the 3rd quartile.

(c) Find the IQ score for the top 5%.

IQ scores of at least the 100 - 5 = 95th percentile, which is X when Z has a p-value of 0.95, so X when Z = 1.645.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]1.645 = \frac{X - 100}{15}[/tex]

[tex]X - 100 = 1.645*15[/tex]

[tex]X = 124.7[/tex]

IQ scores of 124.7 and higher are in the top 5%.

9514 1404 393

Answer:

  (x, y) = (0, 0), (1/3, 0), (1/4, 5/24)

Step-by-step explanation:

It is often helpful to write equations in general form. That way, factoring and use of the zero product rule can find solutions.

  x = 1.5x(1 -x) -0.6xy . . . . given

  1.5x -1.5x² -0.6xy -x = 0 . . . . . subtract x

  0.5x -1.5x² -0.6xy = 0 . . . . . . . collect terms

  0.1x(5 -15x -6y) = 0 . . . . . . . . factor; [eq1]

__

  y = y +2xy -0.5y . . . . . . given

  y +2xy -0.5y -y = 0 . . . . . subtract y

  -0.5y +2xy = 0 . . . . . . . . . . collect terms

  -0.5y(1 -4x) = 0 . . . . . . . factor; [eq2]

__

Solutions to [eq1] will be ...

  x = 0

  15x +6y = 5 . . . . . . a set of possible solutions

Solutions to [eq2] will be ...

  y = 0

  1 -4x = 0   ⇒   x = 1/4

Then (x, y) pairs that will satisfy both equations simultaneously are ...

  (x, y) = (0, 0), (1/3, 0), (1/4, 5/24)

__

In the attached graph, solutions to [eq1] are the red lines; solutions to [eq2] are the green lines. Then simultaneous solutions to both equations are found at the intersection points of red and green lines.

Answer:

Step-by-step explanation:

Answer:

see below

Step-by-step explanation:

We know that distance = rate * time

100 meters = 8 m/s * time

100 = 8t

Divide each side by 8

100/8 = 8t/8

12.5 = t

If we know the rate and the time, we can find the distance

d = rt

Answer:

60 is the larger number

Step-by-step explanation:

Let the two numbers be a and y

x+y = 90

x-y = 30

Add the two equations together

x+y = 90

x-y = 30

-----------------

2x = 120

Divide by 2

2x/2 =120/2

x = 60

x+y =90

60+y = 90

y = 90-60

y = 30

The numbers are 60 and 30

Answer:

Solution given:

f(x)=5x-3

let

y=f(x)

y=5x-3

interchanging role of x and y

x=5y-3

x+3=5y

y=[tex]\frac{x+3}{5}[/tex]

$o,

f-¹(x)=[tex]\frac{x+3}{5}[/tex]

we conclude that

f-¹(x)≠g(x)

Each pair of function are not inverses.

g(x)=x/5+3

let g(x)=y

y=x/5+3

interchanging role of x and y

x=y/5+3

x-3=y/5

doing crisscrossed multiplication

5(x-3)=y

y=5x-15

g-¹(x)=5x-15

So

g-¹(x)≠f-¹(x)

Each pair of function are not inverses.

Given that,

→ f(x) = 5x-3

Then y = f(x),

→ y = 5x-3

Now we can interchange role of x and y,

→ x = 5y-3

Then use the cross multiplication,

→ x+3 = 5y

→ y = x+3/5

Now the inverse is,

→ f-¹(x) = x+3/5

We can go to the conclusion that,

→ f-¹(x) ≠ g(x)

So, each pair of function is not inverse.

Answer:

[tex]LCM = 21[/tex]

Step-by-step explanation:

Given

[tex]-\frac{3}{5}y + \frac{1}{7}= \frac{1}{3}y -\frac{2}{3}[/tex]

Required

LCM of the constant terms

Collect like terms

[tex]\frac{1}{3}y+\frac{3}{5}y = \frac{1}{7}+\frac{2}{3}[/tex]

The constant terms are on the right-hand side

To combine them, we simply take the LCM of the denominator, i.e. 7 and 3

The prime factorization of 3 and 7 are:

[tex]3 = 3[/tex]

[tex]7 = 7[/tex]

So:

[tex]LCM = 3 * 7[/tex]

[tex]LCM = 21[/tex]

Answer:

[tex]P=\$276646.153[/tex]

Step-by-step explanation:

Time [tex]T=30years[/tex]

Rate [tex]r=0.325\%[/tex]

Payment per month [tex]P=\$ 900[/tex]

Generally the equation for Principle  is mathematically given by

[tex]M=\frac{P r}{1-(1+r)^{-n}}[/tex]

[tex]900=\frac{P \frac{0.325}{100}}{1-(1+( \frac{0.325}{100}))^{- 30*12}}[/tex]

[tex]P=\frac{900*100*0.99}{0.325}[/tex]

[tex]P=\$276646.153[/tex]

Answer:

m = 20 * n

Step-by-step explanation:

The money that he earns is equal  the amount earned per lawn times the amount of lawns that he mows

m = 20 * n

Answer:

60 = 3 x 20

Step-by-step explanation:

60 = m

3 = c

20 = n

Answer:

in this case it is just multiplying the two items together

the THIRD CHOICE...

3x(x^2-5x-9)

3x^3 -15x^2 -27x

Step-by-step explanation:

Answer:

3x^3-15x^2-27x

Step-by-step explanation:

the function f (gx) means you have to substitute the function of gx in the function of fx were there's x

3x(x^2-5x-9)

3x^3-15x^2-27x

I hope this helps

Answer:

The manufacturer should advertise 11720 pages.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 12450, standard deviation of 570:

This means that [tex]\mu = 12450, \sigma = 570[/tex]

How many pages should the manufacturer advertise for each cartridge if it wants to be correct 90 percent of the time?

They should advertise the 10th percentile, which is X when Z has a p-value of 0.1, so X when Z = -1.28. Then

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-1.28 = \frac{X - 12450}{570}[/tex]

[tex]X - 12450 = -1.28*570[/tex]

[tex]X = 11720[/tex]

The manufacturer should advertise 11720 pages.

Answer:

See Below.

Step-by-step explanation:

We can write a two-column proof.

Statements:                                                Reasons:

[tex]\displaystyle 1)\, F\text{ is the midpoint of } AE[/tex]                           Given

[tex]\displaystyle 2) \, \overline{FA} \cong \overline{FE}[/tex]                                                  Definition of Midpoint

[tex]\displaystyle 3) \, AB\parallel DE[/tex]                                                   Given

[tex]\displaystyle 4)\, \angle B \cong \angle D[/tex]                                                  Alt. Int. Angles Are Congruent  

[tex]\displaystyle 5)\, \angle A \cong E[/tex]                                                     Alt. Int. Angles Are Congruent      

[tex]\displaystyle 6) \, \Delta BFA \cong \Delta DFE[/tex]                                      AAS Congruence

Answer: See Below

Step-by-step explanation:

Concept:

Here, we need to know the idea of alternative interior angle, alternative exterior angle, and corresponding angles.

Alternative interior angle: a pair of angles on the inner side of each of those two lines but on opposite sides of the transversal.

Alternative exterior angle: a pair of angles on the outer side of each of those two lines but on opposite sides of the transversal.

Corresponding angle: A pair of angles that occupy the same relative position at each intersection where a straight line crosses two others.

All three kinds of angles above occur to be congruent (equal) when the lines are parallel to each other.

If you are still confused, please refer to the attachment below for a graphical explanation

Solve:

PART ONE

a) Name two pairs of alternative exterior angles: ∠1 and ∠7 / ∠2 and ∠8

b) Name two pairs of corresponding angles: ∠1 and ∠5 / ∠2 and ∠6

c) Name two pairs of alternative interior angles: ∠4 and ∠6 / ∠3 and ∠5

PART TWO

a) If the measure of angle 7 is 52°, what is the measure of angle 1?

b) If the measure of angle 8 is 112°, then what is the measure of angle 3?

Hope this helps!! :)

Please let me know if you have any questions

Discounted price = $60

Discount = 60%

Let the usual price be x.

So, x - (60% of x) = $60

=> x - [(60/100) × x] = $60

=> x - (60x/100) = $60

=> x - (3x/5) = $60

=> (5x/5) - (3x/5) = $60

=> 2x/5 = $60

=> 2x = $60 × 5

=> 2x = $300

=> x = $300/2

=> x = $150

So, the usual price is $150.

Economists found that amount of corruption in a country is correlated to the Gross domestic products of the country.

Whenever there is high corruption in a country it leads to great negative impacts on the economic growth of that country.

The equation represents the the corruption score for every dollar per capita rise.

The slope of the equation will represent the GDP per capita of a country with corruption score of zero.

The correct answer is C.

C. The GDP per capita of a country with a corruption score of zero.

Answer:

Disjoint is the correct answer.

Answer:

1/11

Step-by-step explanation:

We are asked to find the natural log of

[tex] \sqrt[11]{e} [/tex]

Convert to fractional exponent

[tex] ln(e {}^{ \frac{1}{11} } ) [/tex]

Apply Log of Power rule

[tex] \frac{1}{11} ln(e) [/tex]

Natural log of e is 1 so

[tex] \frac{1}{11} \times 1 = \frac{1}{11} [/tex]

Answer:

[tex]\frac{1}{11}[/tex]

Step-by-step explanation:

First, remember that the ln function is just a log function with a base of e. Here's how it looks

[tex]ln(x) =log_{e}(x)[/tex]

[tex]ln(\sqrt[11]{e} ) = log_{e}(\sqrt[11]{e} )[/tex]

We can take this one step further if we realize that we can rewrite the square root as a simple power to a fraction!

[tex]log_{e}(e^{\frac{1}{11} } )[/tex]

Solving the equation above is really simple. All that function is really saying is can we raise e to some number, where the result would be e^(1/11)? In other words find x.

[tex]e^{x} = e^{\frac{1}{11} }[/tex]

Well x has to be 1/11 in that case. And that ends up being our final answer.

[tex]log_{e}(e^{\frac{1}{11} } ) = \frac{1}{11}[/tex]

Answer:

Step-by-step explanation:

I posted a pic to show you what this looks like so you have some idea of what it is I'm talking about in the explanation of how to find the side length of the rhombus. Knowing that this is a rhombus, all the sides are the same length.

Looking at the pic below, you can see that I divided the length of AC in 2 equal parts to get that the base of the right triangle I extracted below that is 8; the height is 6. We can find the side marked with a ? by using Pythagorean's Theorem; namely:

[tex]??^2=6^2+8^2[/tex] and

[tex]??^2=36+64[/tex] and

[tex]??^2=100[/tex] so

? = 10

The length of the sides of the rhombus is 10.

Answer:

C 4,12,36 108

Step-by-step explanation:

the answer is above.

Answer:

C

Step-by-step explanation:

G.P= a,ar,ar^2,ar^3,...,

a1=4

a2=4×3=12

a3=4×9=36

a4=4×27=108

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

same as the person above plato 2022'

Answer:

.

e

Step-by-step explanation:

.

9514 1404 393

Answer:

  110°

Step-by-step explanation:

The sum of angles of a triangle is 180°.

  (8x -10) +(2x) +(3x -5) = 180

  13x -15 = 180

  13x = 195

  x = 15

The largest angle is ...

  8x -10 = 8(15) -10 = 110 . . . . degrees

Answer:

Red on the 5th draw = 0.0907

Step-by-step explanation:

The first to fourth selections are all the same.

Blue + white = 12 + 6 = 18

The total number of marbles is 11 + 12 + 6 = 29

P(~ red) for the first four times = (18/29)^4 = 0,1484

Now on the 5th time, the first red is 11/18

So the Probability is 0.1484 * 11/18 = 0.0907

Answer: (760 - 676. 40) × 100 ÷ 760 = 11%

Step-by-step explanation:

Answer:

11% decrease

Step-by-step explanation:

Concepts:

Solving:

Let's find the percent change by using the formula.

1. Formula for Percent Change

2. Plug in the values of NV and OV

3. Simplify

Therefore, our percent decrease is 11% decrease.

Answer:

[tex]sin(0)=opposite/hypotenuse,cos(0)=adjacent/hypotenuse[/tex]

[tex]sin(60)=\frac{x}{8\sqrt{5} } ,\:\:cos(60)=\frac{y}{8\sqrt{5} }[/tex]

[tex]\frac{\sqrt{3} }{2} =\frac{x}{8\sqrt{5} } \:\:\:\:\frac{1}{2} =\frac{y}{8\sqrt{15} }[/tex]

[tex]2x=8\sqrt{5} \times\sqrt{3} \:\;\:\:2y=1\times8\sqrt{15}[/tex]

[tex]2x=\frac{8\sqrt{15} }{2} \:\:\:\:2y=8\sqrt{15}[/tex]

[tex]x=8\sqrt{15} /2\:\:\: y=8\sqrt{15} /2[/tex]

[tex]x=4\sqrt{15}[/tex]    [tex]y=4\sqrt{15}[/tex]

OAmalOHopeO

Answer:

24.5

Step-by-step explanation:

using Pythagorean theorem

[tex]a^{2} +b^{2} =c^{2} \\[/tex]

Since we know the hypotenuse, we can change up the theorem into [tex]c^{2} -b^{2} =a^{2}[/tex]

[tex]35^{2} -25^{2} =a^{2}[/tex]

1225-625=[tex]a^{2}[/tex]

[tex]\sqrt{a^{2} } =24.5[/tex]