Juan is selling fruit baskets and pencils for his
fundraisers. He started his fundraising early and has 12
weeks to reach his goal of selling $300.00 worth of
goods to pay for his trip's cost.
If Juan uses the table shown to represent all of his
data, what interval for the weeks would you use in
column 1 so that all 12 weeks are represented?
Week.labels:
X1, 2, 3, 4
2, 4, 6, 8
3, 6, 9, 12
1, 3, 6, 10

Answer:

[tex]x=6[/tex]

Step-by-step explanation:

We want to solve the equation:

[tex]\displaystyle \log_6(2x-6)+\log_6x=2[/tex]

Recall the property:

[tex]\displaystyle \log_bx+\log_by=\log_b(xy)[/tex]

Hence:

[tex]\log_6(x(2x-6))=2[/tex]

Next, recall that by the definition of logarithms:

[tex]\displaystyle \log_b(a)=c\text{ if and only if } b^c=a[/tex]

Therefore:

[tex]6^2=x(2x-6)[/tex]

Solve for x. Simplify and distribute:

[tex]36=2x^2-6x[/tex]

We can divide both sides by two:

[tex]x^2-3x=18[/tex]

Subtract 18 from both sides:

[tex]x^2-3x-18=0[/tex]

Factor:

[tex](x-6)(x+3)=0[/tex]

Zero Product Property:

[tex]x-6=0\text{ or } x+3=0[/tex]

Solve for each case. Hence:

[tex]x=6\text{ or } x=-3[/tex]

Next, we must check the solutions for extraneous solutions. To do so, we can simply substitute the solutions back into the original equations and examine its validity.

Checking x = 6:

[tex]\displaystyle \begin{aligned} \log_{6}(2(6)-6)+\log_{6}6&\stackrel{?}{=} 2 \\ \\ \log_6(12-6)+(1)&\stackrel{?}{=}2 \\ \\ \log_6(6)+1&\stackrel{?}{=}2 \\ \\ 1+1=2&\stackrel{\checkmark}{=}2\end{aligned}[/tex]

Hence, x = 6 is indeed a solution.

Checking x = -3:

[tex]\displaystyle\begin{aligned} \log_6(2(-3)-6) + \underbrace{\log_6-3}_{\text{und.}} &\stackrel{?}{=} 2\\ \\ \end{aligned}[/tex]

Since the second term is undefined, x = -3 is not a solution.

Therefore, our only solution is x = 6.

Answer:

x = 6

Step-by-step explanation:

The given logarithmic equation is ,

[tex]\implies log_{6}(2x - 6) + log_{6}x = 2[/tex]

We can notice that the bases of both logarithm is same . So we can use a property of log as ,

[tex]\bf \to log_a b + log_a c = log_a {( ac)} [/tex]

So we can simplify the LHS and write it as ,

[tex]\implies log_{6} \{ x ( 2x - 6 )\} = 2 [/tex]

Now simplify out x(2x - 6 ) . We get ,

[tex]\implies log_6 ( 2x^2 - 6x ) = 2 [/tex]

Again , we know that ,

[tex]\bf \to log_a b = c , a^c = b [/tex]

Using this we have ,

[tex]\implies 2x^2 - 6x = 6^2 \\\\\implies 2x^2 - 6x -36 = 0 [/tex]

Now simplify the quadratic equation ,

[tex]\implies x^2 - 3x - 18 = 0 \\\\\implies x^2 -6x + 3x -18=0\\\\\implies x( x -6) +3( x - 6 ) = 0 \\\\\implies (x-6)(x+3) = 0 \\\\\implies x = 6 , -3 [/tex]

Since logarithms are not defined for negative numbers or zero , therefore ,

[tex]\implies 2x - 6 > 0 \\\\\implies x > 3 [/tex]

Therefore the equation is not defined at x = -3 . Hence the possible value of x is 6 .

[tex]\implies \underline{\underline{ x \quad = \quad 6 }}[/tex]

Answer:

a=1

b=-5

c=6

Step-by-step explanation:

ax^2+bx+c=0

Is the formula used for this question.

The given function is the same as y = 1x^2 + (-5x) + 6

Compare it to the form y = ax^2+bx+c, and we have the following:

a = 1

b = -5

c = 6

Answer:

The answer would be

Step-by-step explanation:

you multiple 8 and 5 then you multiple 12 (inches) then subtract the inch that makes up 12 let me know if you need help

Answer:

12,-2

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

plss pa brainliest me thanks

Answer:

Dilated pupils

Long periods of wakefulness

Loss of appetite

Overconfidence

Over-excitement

Paranoia

Runny nose or frequent sniffles

White powder around nostrils

Legal issues

Missing or being late to work

Financial problems

Mood swings

Irritability

Depression

Answer:

x = 5

arcEF = 58degrees

arcGH = 55degrees

Step-by-step explanation:

Find the diagram attached

The sum of angle on the straight line EH is 180degrees

Hence arcEF+ arcFG + arcGH = 180

10x+8 + 67 + 11x = 180

21x + 75 = 180

21x = 180 - 75

21x = 105

x = 105/21

x = 5

Since EF = 10x+8

arcEF = 10(5) + 8

arcEF = 50+8

arcEF = 58degrees

Also, arcGH = 11x

arcGH = 11(5)

arcGH = 55degrees

Answer:

d=3

Step-by-step explanation:

13d=39

d=39/13

d=3

Hello!

6d + 7d = 39 <=>

<=> 13d = 39 <=>

<=> d = 39 : 13 <=>

<=> d = 3 => 6 × 3 + 7 × 3 = 39

Good luck! :)

Answer:

to get the slope. take the change of y axis value divide by the change of x axis value

Step-by-step explanation:

w = 34° (alternate interior angles)

x = 34° (vertically opposite angles)

y = 101°

z = 79° (corresponding angles)

Answer:

1  4/5

Step-by-step explanation:

3/4 ÷ 5 /12

Copy dot flip

3/4 * 12/5

Rewriting

3/5 * 12/4

3/5 * 3

9/5

1 4/5

Answer:

€3,551.05

Step-by-step explanation:

31*29=899

899*3.65=€3,551.05

the school will get an estimate of €3,551.05

Answer:

there are 6 units

hope this help

Answer:

x = 63.9

Step-by-step explanation:

We have:

[tex]\frac{QR}{sin35}[/tex] = [tex]\frac{78}{sin90}[/tex]

=> QR × sin90 = 78 × sin35

=> QR × sin90 = 44.7

=> QR = 44.7

But, we also have: [tex]x^{2}[/tex] + [tex]QR^{2}[/tex] = [tex]78^{2}[/tex] <=> [tex]x^{2}[/tex] + [tex]44.7^{2}[/tex] = [tex]78^{2}[/tex] <=> [tex]x^{2}[/tex] = 6084 - 1998.09

=> [tex]x^{2}[/tex] = 4085.91

=> x = [tex]\sqrt{4085.91}[/tex] = 63.9211.. = 63.9

<3 Have a nice day!!

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

B/c  the bigger triangle is a copy of the smaller we can say

8[tex]\sqrt{3}[/tex] / 12  = x / 8[tex]\sqrt{3}[/tex]

then, solve for x

8[tex]\sqrt{3}[/tex](8[tex]\sqrt{3}[/tex]/12) = x

(64 *3) 12 = x

192 /12 = x

16 = x

nice,  the first answer looks good , then :P

Answer:

16

Step-by-step explanation:

Answer:

C) 3 times the sq root of 3

Step-by-step explanation:

In a right angle triangle, the COS is definned as the ajacent side over the hypotenuse. So

COS 60 = JK/JL

COS 60 = JK/(6*sq root 3)

.5 = JK/(6*3**1/2)

JK = .5 *(6*3**1/2)

JK = 3*3**1/2

Answer:

rs. 81

Step-by-step explanation:

given,

mp. = 1620

sp. = 1539

now,

discount = mp - s.p = 1620 - 1539 = 81

Answer:

2 ( Option A )

Step-by-step explanation:

The given integral to us is ,

[tex]\longrightarrow \displaystyle \int_0^1 5x \sqrt{x}\ dx [/tex]

Here 5 is a constant so it can come out . So that,

[tex]\longrightarrow \displaystyle I = 5 \int_0^1 x \sqrt{x}\ dx [/tex]

Now we can write √x as ,

[tex]\longrightarrow I = \displaystyle 5 \int_0^1 x . x^{\frac{1}{2}} \ dx [/tex]

Simplify ,

[tex]\longrightarrow I = 5 \displaystyle \int_0^1 x^{\frac{3}{2}}\ dx [/tex]

By Power rule , the integral of x^3/2 wrt x is , 2/5x^5/2 . Therefore ,

[tex]\longrightarrow I = 5 \bigg( \dfrac{2}{5} x^{\frac{5}{2}} \bigg] ^1_0 \bigg) [/tex]

On simplifying we will get ,

[tex]\longrightarrow \underline{\underline{ I = 2 }}[/tex]

Answer:

y = - 35

Step-by-step explanation:

Expressing as a fraction , that is

[tex]\frac{y}{-7}[/tex] = 5 ( multiply both sides by - 7 to clear the fraction )

y = - 35

9514 1404 393

Answer:

  3.31227766..., irrational

Step-by-step explanation:

  3/20 +√10 = 0.15 + 3.16227766017...

The root of 10 is irrational, so adding that to a rational number will give an irrational sum.

The sum is about 3.31227766017..., an irrational number.

Answer:

A

Step-by-step explanation:

Answer:

41

Step-by-step explanation:

Answer:

Step-by-step explanation:

Use the formulas that allow us to find the point that divides the segment into a ratio which is

[tex]x=\frac{bx_1+ax_2}{a+b}[/tex]  and  [tex]y=\frac{by_1+ay_2}{a+b}[/tex] where a is 1 (comes from the ratio) and b is 3 (comes from the ratio as well). Filling in:

[tex]x=\frac{3(9)+1(6)}{1+3}=\frac{27+6}{4}=\frac{33}{4}[/tex] and then y:

[tex]y=\frac{3(-1)+1(-10)}{1+3}=\frac{-3-10}{4}=-\frac{13}{4}[/tex] so the coordinates in question are

[tex](\frac{33}{4},-\frac{13}{4})[/tex]

Answer:

Step-by-step explanation:

the answer would be (7,-7)

Answer:

Hello there,

The correct answer to this question would be D 1/6

Step-by-step explanation:

I had took the test and it said it was correct.

Anyways hope this helps

if the answer is correct pls mark Brainliest

thank you, have a nice day

Answer:

in jh ynhtym

hunt ghb JBL iggmmjuu ki ju nu j

Hello,

we are going to use the theorem of the bissectrice. (if this word is good in english)

[tex]\dfrac{KL}{LM} =\dfrac{KN}{NM} \\\\\dfrac{8}{x} =\dfrac{14}{20-x} \\\\8(20-x)=14x\\\\160-8x=14x\\\\22x=160\\\\x=\frac{160}{22} \\\\x=\frac{80}{11} \\\\\\x=7.\overline{27}[/tex]

Answer:

% change in perimeter = 43. 44 %

% change in area = 16 %

Step-by-step explanation:

initial perimeter of the rectangle = 2(2p + p)

= 6p

initial area of the rectangle = 2p × p

= 2p²

therefore,

= 2p + 0.8p = 2.8 p

= p - 0.4p

= 0.6 p

= 3.4 p

= 1.68 p²

% change in perimeter

[tex] = \frac{6p - 3.4p}{6p} \times 100 \\ = \frac{2.6p}{6p} \times 100 \\ = 43.33\%[/tex]

% change in area

[tex] \frac{2 {p}^{2} - 1.68 {p}^{2} }{2 {p}^{2} } \times 100 \\ = \frac{0.32}{2} \times 100 \\ = 16\%[/tex]

Answer:

1 hour

Step-by-step explanation:

hope it helps ....