Answer:
Jose has 5.2 meters of fabric left.
Step-by-step explanation:
5.6 - 0.4 = 5.2
HELP URGENT !!!!!!
what happens if the lines that are being cut by the transversal are not parallel
[tex]\int\limits^a_b {(1-x^{2} )^{3/2} } \, dx[/tex]
First integrate the indefinite integral,
[tex]\int(1-x^2)^{3/2}dx[/tex]
Let [tex]x=\sin(u)[/tex] which will make [tex]dx=\cos(u)du[/tex].
Then
[tex](1-x^2)^{3/2}=(1-\sin^2(u))^{3/2}=\cos^3(u)[/tex] which makes [tex]u=\arcsin(x)[/tex] and our integral is reshaped,
[tex]\int\cos^4(u)du[/tex]
Use reduction formula,
[tex]\int\cos^m(u)du=\frac{1}{m}\sin(u)\cos^{m-1}(u)+\frac{m-1}{m}\int\cos^{m-2}(u)du[/tex]
to get,
[tex]\int\cos^4(u)du=\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{4}\int\cos^2(u)du[/tex]
Notice that,
[tex]\cos^2(u)=\frac{1}{2}(\cos(2u)+1)[/tex]
Then integrate the obtained sum,
[tex]\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{8}\int\cos(2u)du+\frac{3}{8}\int1du[/tex]
Now introduce [tex]s=2u\implies ds=2du[/tex] and substitute and integrate to get,
[tex]\frac{3\sin(s)}{16}+\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{8}\int1du[/tex]
[tex]\frac{3\sin(s)}{16}+\frac{3u}{4}+\frac{1}{4}\sin(u)\cos^3(u)+C[/tex]
Substitute 2u back for s,
[tex]\frac{3u}{8}+\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{8}\sin(u)\cos(u)+C[/tex]
Substitute [tex]\sin^{-1}[/tex] for u and simplify with [tex]\cos(\arcsin(x))=\sqrt{1-x^2}[/tex] to get the result,
[tex]\boxed{\frac{1}{8}(x\sqrt{1-x^2}(5-2x^2)+3\arcsin(x))+C}[/tex]
Let [tex]F(x)=\frac{1}{8}(x\sqrt{1-x^2}(5-2x^2)+3\arcsin(x))+C[/tex]
Apply definite integral evaluation from b to a, [tex]F(x)\Big|_b^a[/tex],
[tex]F(x)\Big|_b^a=F(a)-F(b)=\boxed{\frac{1}{8}(a\sqrt{1-a^2}(5-2a^2)+3\arcsin(a))-\frac{1}{8}(b\sqrt{1-b^2}(5-2b^2)+3\arcsin(b))}[/tex]
Hope this helps :)
Answer:[tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{3arcsin(a) + 2a(1 - a^2)^\Big{\frac{3}{2}} + 3a\sqrt{1 - a^2}}{8} - \frac{3arcsin(b) + 2b(1 - b^2)^\Big{\frac{3}{2}} + 3b\sqrt{1 - b^2}}{8}[/tex]General Formulas and Concepts:
Pre-Calculus
Trigonometric IdentitiesCalculus
Differentiation
DerivativesDerivative NotationIntegration
IntegralsDefinite/Indefinite IntegralsIntegration Constant CIntegration Rule [Reverse Power Rule]: [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]
Integration Rule [Fundamental Theorem of Calculus 1]: [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]
U-Substitution
Trigonometric SubstitutionReduction Formula: [tex]\displaystyle \int {cos^n(x)} \, dx = \frac{n - 1}{n}\int {cos^{n - 2}(x)} \, dx + \frac{cos^{n - 1}(x)sin(x)}{n}[/tex]
Step-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx[/tex]
Step 2: Integrate Pt. 1
Identify variables for u-substitution (trigonometric substitution).
Set u: [tex]\displaystyle x = sin(u)[/tex][u] Differentiate [Trigonometric Differentiation]: [tex]\displaystyle dx = cos(u) \ du[/tex]Rewrite u: [tex]\displaystyle u = arcsin(x)[/tex]Step 3: Integrate Pt. 2
[Integral] Trigonometric Substitution: [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \int\limits^a_b {cos(u)[1 - sin^2(u)]^\Big{\frac{3}{2}} \, du[/tex][Integrand] Rewrite: [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \int\limits^a_b {cos(u)[cos^2(u)]^\Big{\frac{3}{2}} \, du[/tex][Integrand] Simplify: [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \int\limits^a_b {cos^4(u)} \, du[/tex][Integral] Reduction Formula: [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{4 - 1}{4}\int \limits^a_b {cos^{4 - 2}(x)} \, dx + \frac{cos^{4 - 1}(u)sin(u)}{4} \bigg| \limits^a_b[/tex][Integral] Simplify: [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{cos^3(u)sin(u)}{4} \bigg| \limits^a_b + \frac{3}{4}\int\limits^a_b {cos^2(u)} \, du[/tex][Integral] Reduction Formula: [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{cos^3(u)sin(u)}{4} \bigg|\limits^a_b + \frac{3}{4} \bigg[ \frac{2 - 1}{2}\int\limits^a_b {cos^{2 - 2}(u)} \, du + \frac{cos^{2 - 1}(u)sin(u)}{2} \bigg| \limits^a_b \bigg][/tex][Integral] Simplify: [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{cos^3(u)sin(u)}{4} \bigg| \limits^a_b + \frac{3}{4} \bigg[ \frac{1}{2}\int\limits^a_b {} \, du + \frac{cos(u)sin(u)}{2} \bigg| \limits^a_b \bigg][/tex][Integral] Reverse Power Rule: [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{cos^3(u)sin(u)}{4} \bigg| \limits^a_b + \frac{3}{4} \bigg[ \frac{1}{2}(u) \bigg| \limits^a_b + \frac{cos(u)sin(u)}{2} \bigg| \limits^a_b \bigg][/tex]Simplify: [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{cos^3(u)sin(u)}{4} \bigg| \limits^a_b + \frac{3cos(u)sin(u)}{8} \bigg| \limits^a_b + \frac{3}{8}(u) \bigg| \limits^a_b[/tex]Back-Substitute: [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{cos^3(arcsin(x))sin(arcsin(x))}{4} \bigg| \limits^a_b + \frac{3cos(arcsin(x))sin(arcsin(x))}{8} \bigg| \limits^a_b + \frac{3}{8}(arcsin(x)) \bigg| \limits^a_b[/tex]Simplify: [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{3arcsin(x)}{8} \bigg| \limits^a_b + \frac{x(1 - x^2)^\Big{\frac{3}{2}}}{4} \bigg| \limits^a_b + \frac{3x\sqrt{1 - x^2}}{8} \bigg| \limits^a_b[/tex]Rewrite: [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{3arcsin(x) + 2x(1 - x^2)^\Big{\frac{3}{2}} + 3x\sqrt{1 - x^2}}{8} \bigg| \limits^a_b[/tex]Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{3arcsin(a) + 2a(1 - a^2)^\Big{\frac{3}{2}} + 3a\sqrt{1 - a^2}}{8} - \frac{3arcsin(b) + 2b(1 - b^2)^\Big{\frac{3}{2}} + 3b\sqrt{1 - b^2}}{8}[/tex]Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Integration
Book: College Calculus 10e
The hypotenuse of a right triangle measures 14 cm and one of its legs measures 1 cm. Find the measure of the other leg. If necessary, round to the nearest tenth.
Answer:
b=14 cm
Step-by-step explanation:
Use pythagorean equation
A^2+b^2=c^2
1^2+b^2=14^2
1+b^2=196
b^2=195
b=13.964
A plane traveled 4425 miles with the wind in 7.5 hours and 3675 miles against the wind in the same amount of time. Find the speed of the plane in still air and the speed of the wind.
Answer:
540 and 50 respectively
Step-by-step explanation:
Let the speed of plane in still air be x and the speed of wind be y.
ATQ, (x+y)*7.5=4425 and (x-y)*7.5=3675. Solving it, we get x=540 and y=50
On Monday, Main Street station sells 40 tickets.
There are four types of ticket; infant, child, adult and senior.
The bar chart shows the number of infant, child and adult tickets sold.
How many Senior tickets sold ?
Find how many adult tickets were sold than child tickets ?
BOTH QUESTIONS ANSWER NEEDED PLES HELP
Answer:
0 senior tickets were sold
5 more adult tickets were sold than chil tickets
Step-by-step explanation:
You need to see the frequency of each bar
Answer by Gauthmath
The width of a rectangle is
3
inches less than the length. The perimeter is
54
inches. Find the length and the width.
please help asap!!!
Answer:
let length be x
b = x - 3
perimeter = 2( l + b)
54 = 2(x+x-3)
27 = 2x - 3
30 = 2x
x = 15
l = 15
b = 15 - 3
b = 12
A fruit company delivers its fruit in two types of boxes: large and small. A delivery of 3 large boxes and 5 small boxes has a total weight of 88 kilograms. A delivery of 12 large boxes and 2 small boxes has a total weight of 235 kilograms. How much does each type of box weigh?
Answer:
Step-by-step explanation:
We need a system of equations here. The first equation is that 3L boxes + 5s boxes (L = large and s = small) = 88 kg so
3L + 5s = 88
12L + 2s = 235 according to the other information given.
Solve the first equation for either L or s. I'll solve for L, just because:
3L = 88 - 5s and
L = [tex]\frac{88}{3}-\frac{5}{3}s[/tex] and sub that into the second equation for L:
[tex]12(\frac{88}{3}-\frac{5}{3}s)+2s=235[/tex] and if you distribute the 12 into the parenthesis you'll simplify it down a bit to
352 - 20s + 2s = 235 and combine like terms:
-18s= -117 so
s = 6.5 kg and plug that in to solve for L:
L = [tex]\frac{88}{3}-\frac{5}{3}(6.5)[/tex] and
L = 18.5 kg
An automobile went 84 miles on 6.5 gallons of gasoline. At this rate, how many gallons would be needed to travel 126 miles
Answer:
10 gallons
Step-by-step explanation:
84 ÷ 6.5 =12.9(The unit rate.)
Seeing as one gallon can get you 12.9 miles;
126÷12.9=9.7
So the answers 9.7 gallons, but if you need to round, then 10 to get a whole number.
Answer:
9.75
Step-by-step explanation:
We can write a ratio to solve
84 miles 126 miles
-------------- = -------------------
6.5 gallons x gallons
Using cross products
84 x = 6.5 * 126
84x=819
84x/84 = 819/84
x = 9.75
Use formula autocomplete to enter a sum function in cell B7 to calculate the total of cells in B2:B6
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=SUM(B2:B6)
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The formula adds all the values of selected cells and displays the results in different cell.
Learn more at https://brainly.com/question/24365931
1.8>4.7+w
Does anyone know what this may be ? Thank you very much .
Answer:
-2.9 > w
Step-by-step explanation:
1.8>4.7+w
Subtract 4.7 from each side
1.8-4.7>4.7-4.7+w
-2.9 > w
Answer:
w = -2.9
Step-by-step explanation:
Question two
The lengths of the sides of a triangle are in the ratio 2:3:4. The shortest side is 14cm long.
Find the lengths of the other two sides
Answer:
14 and 21 and 28
Step-by-step explanation:
2:3:4.
The shortest side is 14
14/2 = 7
Multiply each side by 7
2*7:3*7:4*7
14 : 21 : 28
Write this quadratic equation in standard form.
Answer:
-[tex]x^{2} + 3x -8 = 0[/tex]
Step-by-step explanation:
[tex]x^{2} + x -8 - 2x = 0[/tex] [tex]x^{2} + 3x -8 = 0[/tex]PLEASE ANSWER ASAP THANK YOU!!! How much money will be in a bank account after 3 years if $9 is deposited at an interest rate of 5% compounded annually? Round to the nearest dollar.....
Answer:
10 bucks
Step-by-step explanation:
Money=9*(1+0.05)^3
Money=9*(1.05)^3=10.41≈10
Solve the equation Axb by using the LU factorization given for A. Also solve Axb by ordinary row reduction. A , b Let Lyb and Uxy. Solve for x and y. nothing nothing Row reduce the augmented matrix and use it to find x. The reduced echelon form of is nothing, yielding x nothing.
Answer: Hello your question is poorly written attached below is the complete question
answer:
[tex]y = \left[\begin{array}{ccc}-4\\-11\\5\end{array}\right][/tex]
[tex]x = \left[\begin{array}{ccc}16\\12\\-40\end{array}\right][/tex]
Step-by-step explanation:
[tex]y = \left[\begin{array}{ccc}-4\\-11\\5\end{array}\right][/tex]
[tex]x = \left[\begin{array}{ccc}16\\12\\-40\end{array}\right][/tex]
attached below is the detailed solution using LU factorization
The sum of two positive integers is 19 and the product is 48
Answer:
16 and 3
Step-by-step explanation:
Let x and y represent the positive integers. We know that
[tex]x + y = 19[/tex]
[tex]xy = 48[/tex]
Isolate the top equation for the x variable.
[tex]x = 19 - y[/tex]
Substitute into the second equation.
[tex](19 - y)y = 48[/tex]
[tex]19y - {y}^{2} = 48[/tex]
[tex] - {y}^{2} + 19y = 48[/tex]
[tex] - {y}^{2} + 19y - 48[/tex]
[tex](y - 16)(y - 3)[/tex]
So our values are
16 and 3.
Which choice correctly shows the solution(s) of the equation x2 = 1442
A)
x= √144
B)
x=V12
X=-
-V144
D)
x = 1V144
Answer:
Step-by-step explanation:
If the 2s are exponents, you need to indicate this with "^":
x^2 = 144^2 means x² = 144²
x = ±√144² = ±144
Answer:
Step-by-step explanation:
f the 2s are exponents, you need to indicate this with "^":
x^2 = 144^2 means x² = 144²
x = ±√144² = ±144
integration of 3^x (1-3^(x+1)^9)dx
Step-by-step explanation:
the answer is in picture
Please Help!
Function: y=x^2+5x-7
Vertex: (___,___)
Solutions: (___,___) and (___,___)
* i thought the vertex was (-5/2,-53,4) but apparently i’m wrong since it keeps saying it* i need answers please
Answer:
Step-by-step explanation:
Help me solve please
(3a^4b/2b^3)^3
cube all the terms:
3^3 = 27
b^3
(a^4)^3 = a^(4*3) = a^12
2^3 = 8
(b^3)^3 = b^3*3 = b^9
27a^12b^3 / 8b^9
Divide the b terms to get the final answer:
27a^12 / 8b^6
Shortern this expression pls
Answer:
[tex]c =\frac{8}{3}[/tex]
Step-by-step explanation:
Given
[tex]c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}}[/tex]
Required
Shorten
We have:
[tex]c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}}[/tex]
Rationalize
[tex]c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7} * \frac{4 + \sqrt 7}{4 + \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}*\frac{4 - \sqrt 7}{4 - \sqrt 7}}[/tex]
Expand
[tex]c = \sqrt{\frac{(4 + \sqrt 7)^2}{4^2 - (\sqrt 7)^2}} + \sqrt{\frac{(4 - \sqrt 7)^2}{4^2 - (\sqrt 7)^2}[/tex]
[tex]c = \sqrt{\frac{(4 + \sqrt 7)^2}{16 - 7}} + \sqrt{\frac{(4 - \sqrt 7)^2}{16 - 7}[/tex]
[tex]c = \sqrt{\frac{(4 + \sqrt 7)^2}{9}} + \sqrt{\frac{(4 - \sqrt 7)^2}{9}[/tex]
Take positive square roots
[tex]c =\frac{4 + \sqrt 7}{3} + \frac{4 - \sqrt 7}{3}[/tex]
Take LCM
[tex]c =\frac{4 + \sqrt 7 + 4 - \sqrt 7}{3}[/tex]
Collect like terms
[tex]c =\frac{4 + 4+ \sqrt 7 - \sqrt 7}{3}[/tex]
[tex]c =\frac{8}{3}[/tex]
Suppose the distributor charges the artist a $40.00 cost for distribution, and the streaming services pays $4.00 per unit. (Note: One unit = one thousand streams)
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
Formula: y = 40x + 4 (Graph Attached)
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
After how many streams will you pay for the distributor charges? (Hint: this is where the line crosses the x-axis, round to the nearest thousand)
Answer:
356 streams
Step-by-step explanation:
From the graph, you will see that the line cross the x-axis at x = 8.8
Substitute into the expression y = 40x + 4
y = 40(8.8)+4
y = 352 + 4
y = 356
Hence the distributor charges will be paid for after 356 streams
Write an inequality for the shaded region shown in the figure.
Answer:
the equation of the circle is x^2 + y^2 < 36
NOT LESS OR EQUAL cause of the dotted lines
and the theory behind this is because the square root of 36 is +-6 so when the equation is less than +-6 the shade cannot go outside these point, if you know what i mean
hope that answers your question :)
.........................................................
Answer:
..............................what this
in a fruit punch drink,the 3 ingredients are apple juice,orange juice and cramberry juice.if 3/4 of the drink is apple juice and 1/10 is orange juice then write the ratio of cranberry juice to apple juice to orange juice in its simplest form
Answer:
3 : 15 : 2
Step-by-step explanation:
Let cranberry juice = x,
3/4 + 1/10 + x = 1
x = 3/20
Ratio = cranberry : apple : orange
= 3/20 : 3/4 : 1/10
= 3 : 15 : 2 (Times everything with 20)
What would be the equation for this word problem?
Jack drove y miles in 20 mins. If he continues at the same rate how many miles can he drive in the next 15 mins?
9514 1404 393
Answer:
d/15 = y/20
Step-by-step explanation:
At a given rate, distance is proportional to time. The distance d that Jack can drive in 15 minutes will be ...
d/15 = y/20 . . . . the equation
d = (3/4)y . . . . . the solution (multiply the above equation by 15, reduce)
what percent is equal to 7/25
Find the midpoint of the line segment defined by the points: (5, 4) and (−2, 1) (2.5, 1.5) (3.5, 2.5) (1.5, 2.5) (3.5, 1.5)
Answer:
[tex]\boxed {\boxed {\sf (1.5 , 2.5)}}[/tex]
Step-by-step explanation:
The midpoint is the point that bisects a line segment or divides it into 2 equal halves. The formula is essentially finding the average of the 2 points.
[tex](\frac {x_1+x_2}{2}, \frac {y_1+ y_2}{2})[/tex]
In this formula, (x₁, y₁) and (x₂, y₂) are the 2 endpoints of the line segment. For this problem, these are (5,4 ) and (-2, 1).
x₁= 5 y₁= 4 x₂= -2 y₂= 1Substitute these values into the formula.
[tex]( \frac {5+ -2}{2}, \frac {4+1}{2})[/tex]
Solve the numerators.
5+ -2 = 5-2 = 3 4+1 = 5[tex]( \frac {3}{2}, \frac{5}{2})[/tex]
Convert the fractions to decimals.
[tex](1.5, 2.5)[/tex]
The midpoint of the line segment is (1.5 , 2.5)
lim(x-0) (sinx-1/x-1)
9514 1404 393
Answer:
as written: the limit does not existsin(x-1)/(x-1) has a limit of sin(1) ≈ 0.841 at x=0Step-by-step explanation:
The expression written is interpreted according to the order of operations as ...
sin(x) -(1/x) -1
As x approaches 0 from the left, this approaches +∞. As x approaches 0 from the right, this approaches -∞. These values are different, so the limit does not exist.
__
Maybe you intend ...
sin(x -1)/(x -1)
This can be evaluated directly at x=0 to give sin(-1)/-1 = sin(1). The argument is interpreted to be radians, so sin(1) ≈ 0.84147098...
The limit is about 0.841 at x=0.
Simplify, write without exponents.
[tex]2*4^{2} *(128\frac{1}{4})[/tex]
[tex]_\sqrt[_]{_}[/tex]
a.) 8
b.) 20
c.) 2
d.) 64
e.) 4
f.) 16
it is helpful to you
According to government data, the probability than an adult never had the flu is 19%. You randomly select 70 adults and ask if he or she ever had the flu. Decide whether you can use the normal distribution to approximate the binomial distribution, If so, find the mean and standard deviation, If not, explain why. Round to the nearest hundredth when necessary.
Answer:
Since [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], the normal distribution can be used to approximate the binomial distribution.
The mean is 13.3 and the standard deviation is 3.28.
Step-by-step explanation:
Binomial probability distribution
Probability of exactly x successes on n repeated trials, with p probability.
Can be approximated to a normal distribution, using the expected value and the standard deviation.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
The standard deviation of the binomial distribution is:
[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]
Normal probability distribution
Problems of normally distributed distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex], if [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex].
The probability than an adult never had the flu is 19%.
This means that [tex]p = 0.19[/tex]
You randomly select 70 adults and ask if he or she ever had the flu.
This means that [tex]n = 70[/tex]
Decide whether you can use the normal distribution to approximate the binomial distribution
[tex]np = 70*0.19 = 13.3 \geq 10[/tex]
[tex]n(1-p) = 70*0.81 = 56.7 \geq 10[/tex]
Since [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], the normal distribution can be used to approximate the binomial distribution.
Mean:
[tex]\mu = E(X) = np = 70*0.19 = 13.3[/tex]
Standard deviation:
[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{70*0.19*0.81} = 3.28[/tex]
The mean is 13.3 and the standard deviation is 3.28.
