Jason wants to fill a cylindrical water tank to its full capacity. He knows that the volume of the tank is equal to the product of , the square of the radius of the tank, and the height of the tank. Jason measured the height of the tank and found it to be 15 feet. He also measured the radius of the cylindrical tank and found it to be 10 feet. If Vrepresents the volume of the cylindrical tank, then which of the following equations can be used to calculate the volume of the tank? ​

Answer:

or,x*10=5*6

or, 10x=30

or,x=30/10

or,x=3

X/6 = 5/10 // - 5/10

X/6-(5/10) = 0

X/6-1/2 = 0

1/6*X-1/2 = 0 // + 1/2

1/6*X = 1/2 // : 1/6

X = 1/2/1/6

X = 3

X = 3

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https://www.geteasysolution.com/

Answer:

5 lawns

Step-by-step explanation:

Firstly, the equation is 25x + 10 = 135

Ezri makes $25 for every lawn she mows (25x) and has an automatic $10 per day (10). In order to make $135 we take what she makes each day and set it equal to 135.

To solve, we subtract 10 from both sides to create 25x = 125. We then divide 25 from both sides to get x=5. This means that Ezri needs to mow 5 lawns in order to make $135.

I hope this is helpful to you!

**To anyone out there seeing this - let me know if you think I made a mistake and I will fix it.**

d. 12ft

Answer:

Solution given:

∆ABC is similar to∆MBN

since their corresponding side are proportional.

so

AB/MB=AC/MN

[since AM=BM=4ft

AB=AM+BM=4+4=8ft]

8/4=AC/6

doing crisscrossed multiplication

2*6=AC

AC=12ft

Step-by-step explanation:

We want to find how many miles per minute Joe runs. This means, we need to simplify the equation:

[tex]\frac{12 mi}{84 min}[/tex]

so that the number on the bottom is 1. How do we do that?

Simple.

Just divide 12 / 84

Answer:

Joe runs approx. 0.143 miles per minute.

Lo siento mucho, necesito los puntos porque estoy en una prueba.

Answer:

x = 5/2

Step-by-step explanation:

4x-1=9

Add 1 to each side

4x-1+1=9+1

4x = 10

Divide by 4

4x/4 = 10/4

x = 5/2

Answer:

385

Step-by-step explanation:

Answer:

100000

Step-by-step explanation:

100000x80=8m

Answer:

[tex]P(x = 1) = 0.33[/tex]

[tex]P(y = 2) = 0.42[/tex]

Step-by-step explanation:

Given

                    y

x [tex]\begin{array}{cccc}P(x,y) & {0} & {1} & {2} & {0} & {0.10} & {0.03} & {0.02} & {1} & {0.06} & {0.20} & {0.07} & {2} & {0.05} & {0.14} & {0.33}\ \end{array}[/tex]

Solving (a)

[tex]P(x = 1)[/tex]

To do this, we simply add all data where x = 1

So, we have:

[tex]P(x = 1) = P(x=1|y=0) + P(x=1|y=1) + P(x=1|y=2)[/tex]

[tex]P(x = 1) = 0.06 + 0.20 + 0.07[/tex]

[tex]P(x = 1) = 0.33[/tex]

Solving (b)

[tex]P(y = 2)[/tex]

To do this, we simply add all data where y = 2

So, we have:

[tex]P(y = 2) = P(x=0|y=2) + P(x=1|y=2) + P(x=2|y=2)[/tex]

[tex]P(y = 2) = 0.02 + 0.07 + 0.33[/tex]

[tex]P(y = 2) = 0.42[/tex]

In a unit circle a line reaching from origin to the circle's circumference specifies the trigonometric functions.

A point where the line which comes from origin to the circumference intersecting it has coordinates [tex](\cos\theta,\sin\theta)[/tex].

In our case [tex]\theta=45^\circ[/tex] which lifts the line up by 45 degrees and makes it intersect circumference at [tex](\cos45^\circ,\sin45^\circ)[/tex].

In the upper right quadrant the angle between x and y axis is 90 degrees so a line coming in at angle of 45 degrees would split the quadrant in half, that means sine and cosine 45 degrees will be equal.

As you may noticed a point has coordinates cos, sin which means the distance between 0 and y coordinate where the point on a circle is, is called [tex]\cos\theta=\cos45^\circ[/tex].

Because cosine 45 degrees is so simple in interpretation it has a known value of [tex]\cos45^\circ=\sin45^\circ=\frac{\sqrt{2}}{2}[/tex].

Hope this helps :)

Answer:

Step-by-step explanation:

[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]

Answer:

y= -6x-6, I think, hope it helped

Step-by-step explanation:

Answer:

Step-by-step explanation:

Never mind the minus for a second. What is the approximate value of sqrt(50)?

Isn't it about 7 or just a tiny bit over?

That's the answer here. Find the square root first, and then add the minus.

<o==o==o==o==o==o==o==o

  -7  -6  -5  -4  - 3  - 2  - 1    0

Answer:

[tex]10^{-3} \times10^{k} =10^{-3} =\frac{1}{10^{3} }[/tex]

[tex]10^{-3+1+k} =10^{-3}[/tex]

[tex]10^{-2+k} =10^{-3}[/tex]

Therefore, [tex]-2+k=-3[/tex]

[tex]k=-3+2[/tex]

[tex]k=-1[/tex]

OAmalOHopeO

Answer:

answer of question number 1 is 2400, 2880, 3600 respectively.

answer of question number 2 is 1384 and 1680.

Step-by-step explanation:

100×24=2400

120×24=2880

150×24=3600

692×2=1384

420×4=1680

Answer:

B half the circumference or pi r

Step-by-step explanation:

The base of the parallelogram is pi r

To form the parallelogram the triangles are  removed from the bottom half of the circle and moved to flip the gaps in the top half.

Answer:

48 m^3

Step-by-step explanation:

If the scale factor of linear dimensions between two solids is k, then the scale factor for areas is k^2, and the scale factor of volumes is k^3.

Let's call the solid with 16 m^2 of area solid A, and the other one solid B.

The scale factor of areas from, A to B is (100 m^2)/(16 m^2) = 25/4

In other words, multiply the area of the solid A by 25/4 to get the area of solid B.

Let's check: 16 m^2 * 25/4 = 16 * 25/4 m^2 = 4 * 25 m^2 = 100 m^2

We do get 100 m^2 for solid B, so the area scale factor of 25/4 is correct.

The area scale factor is k^2, so we have:

k^2 = 25/4

We solve for k:

k = 5/2

Now we cube both sides to get k^3, the scale factor of volumes.

k^3 = 5^3/2^3

k^3 = 125/8

Let V = volume of smaller solid, solid A.

V * 125/8 = 750 m^3

V = 750 * 8/125 m^3

V = 48 m^3

Answer:

6x^4−2x^3+26x^2+x+14

Step-by-step explanation:

−x^3+26x^2−7x−13+6x^4−x^3+8x+27

= 6x^4−x^3−x^3+26x^2−7x+8x−13+27

= 6x^4−2x^3+26x^2+x+14

Answer:

Step-by-step explanation:

= -x3+ 26x2- 7x-13+6x4-x3+8x+27

=6x4-2x3+26x2+x+14

Answer:

V≈50.27cm³

Step-by-step explanation:

Using the formulas

V=πr2h

3

l=r2+h2

Solving forV

V=1

3πr2l2﹣r2=1

3·π·42·52﹣42≈50.26548cm³

The expression equivalent to x(y)^(2/9) is option D.  x [tex]\sqrt[9]{y^{2} }[/tex].

Expressions are mathematical statements which consist of two or more terms and terms are connected to each other using mathematical operators like addition, multiplication, subtraction and so on.

The given expression is x(y)^(2/9).

We have to find the equivalent expressions of this.

We can write the exponent 2/9 as 2 × 1/9.

So, x(y)^(2/9) = x(y)^(2 × 1/9)

We have the power of a power rule,

(xᵃ)ᵇ = xᵃᵇ

Using this rule,

(y)^(2 × 1/9) = (y²)^(1/9)

So, x(y)^(2/9) = x (y²)^(1/9)

Also, we have,

[tex]\sqrt[n]{x}[/tex] = [tex](x)^{\frac{1}{n}}[/tex]

So, (y²)^(1/9) = [tex]\sqrt[9]{y^{2} }[/tex]

x(y)^(2/9) = x [tex]\sqrt[9]{y^{2} }[/tex]

Hence the equivalent expression is  x [tex]\sqrt[9]{y^{2} }[/tex].

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Your question is incomplete. The complete question is as follows.

Answer:

3

Step-by-step explanation:

3 = 9 \:th \\ 1 = 3 \\ 3 \times 3 = 9 \\ 9 \div 3 = 3 \\ so \: that \: answer \: is \: 3

Answer:

10/16=5/8

6+6+4=16

The probability is 5/8

Answer: 7x + 9y >_ (more or equal) 314

X + Y <_ ( less or equal) 35

Step-by-step explanation:

Answer:

h+s≤35 and 7h + 9s >_314

Step-by-step explanation:

This value is approximate.

====================================================

Explanation:

We have a normal distribution with these parameters

The goal is to find the area under the curve from x = 68 to x = 158, where x is the number of text messages sent per day. So effectively, we want to find P(68 < x < 158).

Let's convert the score x = 68 to its corresponding z score

z = (x-mu)/sigma

z = (68-128)/30

z = -60/30

z = -2

This tells us that the score x = 68 is exactly two standard deviations below the mean mu = 128.

Repeat for x = 158

z = (x-mu)/sigma

z = (158-128)/30

z = 30/30

z = 1

This value is exactly one standard deviation above the mean

-------------------------------------------

The problem of finding P(68 < x < 158) can be rephrased into P(-2 < z < 1)

We do this because we can then use the Empirical rule as shown in the diagram below.

We'll focus on the regions between z = -2 and z = 1. This consists of the blue 13.5% on the left, and the two pink 34% portions. So we will say 13.5% + 34% + 34% = 81.5%

Approximately 81.5% of the the population sends between 68 and 158 text messages per day. This value is approximate because the percentages listed in the Empirical rule below are approximate.

Answer:

C. 81.5%

Step-by-step explanation:

Since this is a right triangle, we can use one of the three main trigonometric functions: sine, cosine or tangent.

Remember: SOH-CAH-TOA

Looking from the given angle, we want to find the opposite side and we know the hypotenuse. Therefore, we should use sine.

sin(51) = BC / 58

BC = 58 x sin(51)

BC = 45.1 units

Hope this helps!

Step-by-step explanation:

Hey there!

From the above given figure;

Angle CAB = 51°

AB = 58

Taking Angle CAB as reference angle we get;

Perpendicular (p) = BC= ?

Hypotenuse (h) = 58

Now;

Taking the ratio of sin we get;

[tex] \sin( \alpha ) = \frac{p}{h} [/tex]

[tex] \sin(51) = \frac{bc}{58} [/tex]

Simplify it;

0.7771459*58 = BC

Therefore, BC = 45.0744.

Hope it helps!

Answer:

True

Step-by-step explanation:

Integers are always whole numbers

negative, 0, positive:: whole numbers

Answer:

Option B.)

Step-by-step explanation:

Just took the test and got 100% :]

The system of logarithmic equation is graphed and the point of intersection of the equation is log₃ ( 5x ) = log₅ ( 2x + 8 ) is A ( 1.0 , 1.4 )

Graphs behave differently at various x-intercepts. Sometimes the graph will cross over the x-axis at an intercept. Other times the graph will touch the x-axis and bounce off.

Identify the even and odd multiplicities of the polynomial functions' zeros.

Using end behavior, turning points, intercepts, and the Intermediate Value Theorem, plot the graph of a polynomial function.

The graphs cross or are tangent to the x-axis at these x-values for zeros with even multiplicities. The graphs cross or intersect the x-axis at these x-values for zeros with odd multiplicities

Given data ,

Let the solution to the logarithmic equation be represented as A

Now , the value of A is

log₃ ( 5x ) = log₅ ( 2x + 8 )

On simplifying , we get

log₃ ( 5x ) = log₁₀ ( 5x ) / log₁₀ ( 3 )

log₅ ( 2x + 8 ) = log₁₀ ( 2x + 8 ) / log₁₀ ( 5 )

Substituting the logarithmic quantities , we get

log₁₀ ( 5x ) / log₁₀ ( 3 ) = log₁₀ ( 2x + 8 ) / log₁₀ ( 5 )

On cross multiplying , we get

log₁₀ ( 5x ) / log₁₀ ( 2x + 8 ) = log₁₀ ( 3 ) / log₁₀ ( 5 )

( 5x ) / ( 2x + 8 ) = 3/5

On cross multiplying , we get

25x = 6x + 24

Subtracting 6x on both sides , we get

19x = 24

Divide by 19 on both sides , we get

x = 1.26

Therefore , the approximate values of the function on graphing is A ( 1.0 , 1.4 )

Hence , the solution of function from graphing is A ( 1.0 , 1.4 )

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Answer:

Your wrong, it's 65%.

Step-by-step explanation:

The reason why: You can calculate the percentage by dividing the number of accepted students by the total of business students, 65/100 which equals 65%.

yw :)

The probability that a student was accepted is 5.0% since option  b be the correct answer.

Probability is the branch of mathematics concerning numerical descriptions of how likely an event is to occur, or how likely it is that a proposition is true. The probability of an event is a number between 0 and 1,

We have to find out the probability of the selection of a student applied for the business program.

We know that, Probability= Total number of events occurred÷ Total number of possible outcomes/events

So, Probability that a student applying to the business program got selected= No of accepted students for business program÷Total number of students applied for business program=65÷100=0.65For converting a number into percentage we multiply the number by 100 that is 0.65*100=65%So, probability that a student applying for business program gets selected is 65%.

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Answer:

i need the graph

Step-by-step explanation:

.

Answer:

A is correct

Step-by-step explanation: