Answer:392
Step-by-step explanation:
a) It would take one machine 392 minutes.
b) It would take one machine 49 minutes.
Define the term proportion?Two ratios are said to be equal when a proportion is stated. When comparing two quantities, ratios are used to divide one quantity by the other.
a) Here given that, to produce a batch of newspaper 7 printing machines needed 56 minutes.
Using this relationship, we can set up a proportion:
as given, 7 printing machine needed = 56 minutes
So, 1 printing machine needed = 7 × 56 minutes = 392 minutes
Therefore, it would take one machine 392 minutes to produce the same batch of newspapers.
b) Similarly, to find out for 8 machines to produce the same batch of newspapers, we can use the same relationship:
1 printing machine needed = 392 minutes
So, 8 printing machine needed = (392 / 8) minutes = 49 minutes
Therefore, it would take one machine 49 minutes to produce the same batch of newspapers.
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if a data line on a graph slopes down as it goes to the right, it is depicting that group of answer choices the relationship between the variables on
When a data line on a graph slopes down as it goes to the right, it is depicting that the relationship between the variables on the graph is inverse.
An inverse relationship is a kind of correlation between two variables, in which one variable decreases while the other increases, or vice versa. An inverse relationship happens when one variable increases while the other decreases, or when one variable decreases while the other increases.
On a graph, when a data line slopes down as it goes to the right, this is an indication that the relationship between the variables on the graph is inverse. As the values of x increase, the values of y decrease. Therefore, we can conclude that there is an inverse relationship between x and y.
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What is the value of x in the triangle to the right? (7x+3) 85 50
Answer: x = 6
Step-by-step explanation:
(7x+3)+85+50 = 180
(7x+3)+135 = 180
7x+3 = 180 - 135 = 45
7x = 45-3 = 42
x = 42 / 7 = 6
x = 6
CONNAIS TU LES LIMITES ?
Answer:
yes
Step-by-step explanation:
imagine you took an assessment on your math ability at one time point and then the same assessment a month later. if your math ability was the same between time 1 and time 2, and nothing substantial happened during that time, such as getting a tutor, which type of reliability for the math ability assessment was achieved? group of answer choices
The test has demonstrated a good level of test-retest reliability.
If a student took an assessment on their math ability at one time point and then the same assessment a month later, with no substantial changes such as getting a tutor, and their math ability was the same between time 1 and time 2, then the assessment has achieved Test-Retest Reliability.Test-Retest Reliability: Test-Retest reliability is the measure of consistency of a test over time. A test has test-retest reliability if a person performs similarly on the same test taken at two different times.A reliable test must always provide consistent results. Therefore, if the math ability was the same between time 1 and time 2, and no substantial changes occurred during that time, then the test has demonstrated a good level of test-retest reliability.
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what is the expected count for women for the presence of aortic stenosis? a. 49.7 b. 59.3 c. 109 d. 57.7
The expected count for women for the presence of aortic stenosis is 57.7. The correct option is D.
What is aortic stenosis?Aortic stenosis is a cardiovascular ailment that causes the aortic valve in the heart to narrow, reducing blood flow from the heart to the rest of the body. Aortic stenosis usually progresses gradually and, in the beginning, may not produce any symptoms.
The severity of aortic stenosis is divided into four categories, ranging from mild to severe. People who are asymptomatic may require monitoring, whereas those who are symptomatic may need to undergo surgery or other procedures.
The expected count for women for the presence of aortic stenosis in this question refers to the number of women who have this condition according to a particular study or statistic.
Therefore, the correct option is D.
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Consider the following exponential probability density function. f(x) = 1/3 4 e^-x/3 for x > 0 a. Write the formula for P(x < x_0). b. Find P(x < 2). c. Find P(x > 3). d. Find P(x < 5). e. Find P(2 <.x <5).
The probability that x is less than 2 is approximately 0.4866. The probability that x is greater than 3 is approximately 0.3528. The probability that x is less than 5 is approximately 0.6321. The probability that x is between 2 and 5 is approximately 0.1455.
The given probability density function is an exponential distribution with a rate parameter of λ = 1/3. The formula for P(x < x_0) is the cumulative distribution function (CDF) of the exponential distribution, which is given by:
F(x_0) = ∫[0,x_0] f(x) dx = ∫[0,x_0] 1/3 * 4 * e^(-x/3) dx
a. Write the formula for P(x < x_0):
Using integration, we can solve this formula as follows:
F(x_0) = [-4e^(-x/3)] / 3 |[0,x_0]
= [-4e^(-x_0/3) + 4]/3
b. Find P(x < 2):
To find P(x < 2), we simply substitute x_0 = 2 in the above formula:
F(2) = [-4e^(-2/3) + 4]/3
≈ 0.4866
Therefore, the probability that x is less than 2 is approximately 0.4866.
c. Find P(x > 3):
To find P(x > 3), we can use the complement rule and subtract P(x < 3) from 1:
P(x > 3) = 1 - P(x < 3) = 1 - F(3)
= 1 - [-4e^(-1) + 4]/3
≈ 0.3528
Therefore, the probability that x is greater than 3 is approximately 0.3528.
d. Find P(x < 5):
To find P(x < 5), we simply substitute x_0 = 5 in the above formula:
F(5) = [-4e^(-5/3) + 4]/3
≈ 0.6321
Therefore, the probability that x is less than 5 is approximately 0.6321.
e. Find P(2 < x < 5):
To find P(2 < x < 5), we can use the CDF formula to find P(x < 5) and P(x < 2), and then subtract the latter from the former:
P(2 < x < 5) = P(x < 5) - P(x < 2)
= F(5) - F(2)
= [-4e^(-5/3) + 4]/3 - [-4e^(-2/3) + 4]/3
≈ 0.1455
Therefore, the probability that x is between 2 and 5 is approximately 0.1455.
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find the length of the cord pt.2
the length of chord in the circle is 13.5 units.
Pythagoras Theorem StatementAccording to Pythagoras' Theorem, the square of the hypotenuse side of a right-angled triangle equals the sum of the squares of the other two sides.The Perpendicular, Base, and Hypotenuse are the three angles that make up this triangle.
The Pythagoras Theorem formula is as follows from the definition:
Hypotenuse² = Perpendicular² + Base²
c² = a² + b²
From the figure, the hypotenuse, x of both triangle are same as both of them are radius of circle.
According to Pythagoras theorem,
x²=6.3²+11.9²
x²=181.3
x=√181.3
x=13.5
Hence, the length of chord in the circle is 13.5 units.
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I NEED HELP PLEASE !!
can i also get an easy explanation so i can know how to do the other problems pls
Answer:
Proofs attached to answer
Step-by-step explanation:
Proofs attached to answer
Which expressions are equivalent to (x−2)2
?
Select the correct choice
The expressions that are equivalent to (x-2)² is x² - 4x + 4. (option B)
Now, let's look at the expression (x-2)². This is a binomial expression that can be simplified by applying the rules of exponents. Specifically, we can expand this expression as follows:
(x-2)² = (x-2) * (x-2)
= x * x - 2 * x - 2 * x + 2 * 2
= x² - 4x + 4
So, the expression (x-2)² is equivalent to x² - 4x + 4.
However, the problem asks us to identify other expressions that are equivalent to (x-2)². To do this, we can use the process of factoring. We know that (x-2)² can be factored as (x-2) * (x-2). Using this factorization, we can rewrite (x-2)² as:
(x-2)² = (x-2) * (x-2)
= (x-2)²
So, (x-2)² is equivalent to itself.
Hence the correct option is (B).
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Complete Question:
Which expressions are equivalent to (x−2)²?
Select the correct choice.
A. (x + 2) (x - 2)
B. x² - 4x + 4
C. x² - 2x + 5
D. x² + x - 2x
In which condition vector a.b has the minimum value? Write it.
Answer:
if it is perpendicular to eacha other I e 0
solve( 3x^ 2)+2y +4=0
Answer:
Step-by-step explanation:
You can’t solve this equation as none of the numbers have the same coefficient to solve. If you wanted to solve for x and y, you will need two equations as there are two unknown variables in the equation and the only way to solve for x and y is to use simultaneous method which includes two equations.
urn contains 6 white, 5 red and 3 blue chips. A person selects 4 chips without replacement. Determine the following probabilities: (Show work. Final answer must be in decimal form.) a) P(Exactly 3 chips are white) Answer Answer b) P(The third chip is blue The first 2 were white) c) P(The fourth chip is blue Answer The first 2 were white) 6. Suppose we have a random variable X such that E[X]= 7 and E[X²]=58. Answer a) Determine the variance of X. b) Determine E[2X2 - 20X +5]
the variance of X is 9. b) Determine E [2X² - 20X +5]:
Using linearity of expectation, we can find E [2X² - 20X +5] as:
E [2X² - 20X +5] = 2E[X²] - 20E[X] + 5
by the question.
The number of ways to select the first 2 white chips is given by:
Number of ways = (6C2) (5C0) (3C0) = 15
The number of ways to select the third chip as blue given that the first 2 chips were white is given by:
Number of ways = (3C1) = 3
Therefore, the probability of selecting the third chip as blue given that the first 2 chips were white is:
P(The third chip is blue the first 2 were white) = Number of ways / Total number of ways = 3 / 350 = 0.0086 (rounded to 4 decimal places)
c) P(The fourth chip is blue the first 2 were white):
The number of ways to select the first 2 white chips is given by:
Number of ways = (6C2) (5C0) (3C0) = 15
The number of ways to select the third chip as non-white given that the first 2 chips were white is given by:
Number of ways = (8C1) = 8
The number of ways to select the fourth chip as blue given that the first 2 chips were white, and the third chip was non-white is given by:
Number of ways = (3C1) = 3
Therefore, the probability of selecting the fourth chip as blue given that the first 2 chips were white is:
P(The fourth chip is blue the first 2 were white) = Number of ways / Total number of ways = 8*3 / 350 = 0.0686 (rounded to 4 decimal places)
Suppose we have a random variable X such that E[X]= 7 and E[X²] =58.
a) Determine the variance of X:
The variance of X is given by:
Var[X] = E[X²] - (E[X]) ²
Substituting the given values, we get:
Var[X] = 58 - (7) ² = 9
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The first three terms of a sequence are given. Round to the nearest thousandth (if necessary). 2 , 5 , 8 ,Find the 41st term.
The 41st term of the sequence is 121.
What is a sequence?In mathematics, a sequence is a list of numbers or objects that follow a certain pattern or rule. A sequence's terms are typically identified by subscripts, like a1, a2, a3,..., an, where n denotes the number of terms in the sequence.
Sequences can be arithmetic, geometric, or neither, depending on terms follow a static difference, constant ratio, or neither of these series, respectively. Algebra uses geometric sequences to represent exponential development or decay whereas arithmetic sequences are frequently employed to model linear connections.
The given sequence is 2 , 5 , 8 , ...
The common difference is:
d = 5 - 2 = 3
The nth term of a sequence is given as:
an = a1 + (n-1)d
Substituting the value we have:
an = 2 + (n-1)3
an = 3n - 1
a41 = 3(41) - 1 = 122 - 1 = 121
Hence, the 41st term of the sequence is 121.
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The temperature recorded at Bloemfontein increased from -2 degrees C to 13 degrees C.what is the difference in temperature
Answer: 15
Step-by-step explanation:
13--2 = 13 + 2 = 15
Find the probability of
drawing a spade, then
drawing a face card out of a
deck
[tex]\huge\underline{\red{A}\green{n}\blue{s}\purple{w}\pink{e}\orange{r} →}[/tex]
P of spade = 1/4
P of face cards = 3/13
{P = probability}
Step-by-step explanation:
•Total cards in a deck = 52
No. of spade cards in the deck = 13
therefore,
Probability of drawing a spade out of a deck of cards = 13/52 = 1/4
No. of face cards in a deck = 3×4 = 12 (joker,king,queen)
therefore,
Probability of drawing a face card out of a deck of cards = 12/52 = 3/13
Hope it helps you ~the life of light bulbs is distributed normally. the variance of the lifetime is 225 and the mean lifetime of a bulb is 530 hours. find the probability of a bulb lasting for at most 540 hours. round your answer to four decimal places.
The probability of a bulb lasting for at most 540 hours is 0.7521, rounded to four decimal places.
The life of light bulbs is distributed normally. The variance of the lifetime is 225 and the mean lifetime of a bulb is 530 hours. Find the probability of a bulb lasting for at most 540 hours. Round your answer to four decimal places.
Using the z-score formula z = (x - μ) / σ, where x is the value in question (540 hours in this case), μ is the mean (530 hours in this case) and σ is the standard deviation (15 hours in this case), we can calculate the z-score:
z = (540 - 530) / 15
z = 10 / 15
z = 0.67
Using a z-table, we can look up the probability of a value being less than or equal to 0.67, which is 0.7521.
Therefore, the probability of a bulb lasting for at most 540 hours is 0.7521, rounded to four decimal places.
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Construct a triangle PQR such that PQ=8cm, PR=5cm and QR=6cm. Construct a circle which will pass through P, Q and R. What is the special name given to this circle?
Construct a triangle PQR with sides PQ=8cm, PR=5cm, and QR=6cm, then draw a circle passing through P, Q, and R. This circle is called the circumcircle of triangle PQR.
We draw a line segment PQ = 8 cm long. From point P, we draw a line segment PR = 5 cm long at an angle of 60 degrees to PQ. Then, we draw a line segment QR = 6 cm long joining points Q and R to complete the triangle. Next, we use a compass to draw a circle passing through points P, Q, and R. This circle is called the circumcircle or circumscribed circle of the triangle, which is the unique circle that passes through all three vertices of the triangle. The circumcircle has a special property that its center is equidistant from the three vertices of the triangle.
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Grant's art class had an exhibit with 45 pieces. 9 of the drawings were Grant's. What percent of the paintings were his?
Answer:
20%
Step-by-step explanation:0% of 4445=
1. Describe the historical data on Nando’s sales, including a discussion of thegeneral direction of sales and any seasonal tendencies that might beoccurring. 2. Discuss, giving your justifications, which time series forecasting techniquesare appropriate for producing forecasts with this data set. 3. Apply the appropriate forecasting techniques and compare the models basedon ex post forecasts. Choose the best model. 4. Use your chosen forecasting model to generate forecasts for each of themonths in year 2021. 5. Discuss how these forecasts might be integrated into the planning operationsand policy makings in NIH
In Rosettenville, a suburb of Johannesburg, South Africa, Robert Brozin and Fernando Duarte acquired the Chicken Land restaurant in 1987, launching Nando's.
The eatery was renamed Nando's in honor of Fernando. The restaurant incorporated influences from former Mozambican Portuguese colonists, many of whom had relocated to Johannesburg's southeast after their country gained independence in 1975. Expansion was an essential component of their vision from the beginning. Nando's had already grown from one restaurant in 1987 to four by 1990. It became increasingly difficult to implement a common strategy and decision-making became inefficient as new outlets were maintained as separate businesses.
In 1995, Nando's International Holdings (NIH) was established as a new international holding because managing this growingly complex global structure had become extremely challenging. The South African branch of Nando's Group Holdings (NGH) was successfully listed on the Johannesburg Stock Exchange on April 27, 1997. NGH was 54% owned by NIH, with the remaining 26% available to the general public and former joint venture partners. The main goals of the share offer and listing were to broaden the group's capital base and enable group restructuring.
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A company finds that if it charges x dollars for a cell phone, it can expect to sell 1,000−2x phones. The company uses the function r defined by r(x)=x⋅(1,000−2x) to model the expected revenue, in dollars, from selling cell phones at x dollars each. At what price should the company sell their phones to get the maximum revenue? x i tercept
The company should sell their phones for $250 each to get the maximum revenue.
What do you mean by maximum revenue?
Maximum revenue refers to the highest possible amount of income that can be generated from a particular product or service. In the context of the given problem, it means finding the price at which the company can sell its cell phones to earn the highest amount of revenue.
Finding the price at which the company should sell their phones to get the maximum revenue:
We need to find the vertex of the parabolic function [tex]r(x)=x(1,000-2x)[/tex], which represents the revenue as a function of the selling price.
To find the vertex of the function r(x), we need to first rewrite it in standard form by expanding the product:
[tex]r(x) = 1000x - 2x^2[/tex]
Now we can see that the function is a quadratic polynomial in standard form, with [tex]a=-2, b=1000[/tex], and [tex]c=0[/tex]. To find the x-coordinate of the vertex, we can use the formula:
[tex]x = -b / (2a)[/tex]
Substituting the values of a and b, we get:
[tex]x = -1000 / (2\times(-2)) = 250[/tex]
Therefore, the company should sell their phones for $250 each to get the maximum revenue. To find the maximum revenue, we can substitute this value of x into the function r(x):
[tex]r(250) = 250\times(1000-2\times250) = $125,000[/tex]
So the maximum revenue the company can expect to earn is $125,000 if they sell their phones for $250 each.
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what is the surface area of a cube if all sides are equal to 2
Suppose that a category of world class runners are known to run a marathon (26 miles) in an average of 146 minutes with a standard deviation of 11 minutes. Consider 49 of the races. Let x = the average of the 49 races. Part (a) two decimal places.) Give the distribution of X. (Round your standard deviation to two decimal places)Part (b) Find the probability that the average of the sample will be between 144 and 149 minutes in these 49 marathons. (Round your answer to four decimal places.) Part (c) Find the 80th percentile for the average of these 49 marathons. (Round your answer to two decimal places.) __ min Part (d) Find the median of the average running times ___ min
(a)The distribution of X (the average of the 49 races) follows a normal distribution with mean 146 minutes and standard deviation 11 minutes. (b)The probability of the average of the sample being between 144 and 149 minutes is 0.5854.(c)The 80th percentile for the average of these 49 marathons is 157.2 minutes.(d) The median of the average running times is 146 minutes.
Part(a) The distribution of X (the average of the 49 races) follows a normal distribution with mean 146 minutes and standard deviation 11 minutes. Part (b) The probability that the average of the sample will be between 144 and 149 minutes in these 49 marathons can be calculated using the z-score formula: z = (x - mean)/standard deviation
For x = 144, z = (144 - 146)/11 = -0.18
For x = 149, z = (149 - 146)/11 = 0.27,using the z-score table, the probability of the average of the sample being between 144 and 149 minutes is 0.5854 (0.4026 + 0.1828).
Part (c) The 80th percentile for the average of these 49 marathons can be calculated using the z-score formula: z = (x - mean)/standard deviation, For the 80th percentile, z = 0.84 (from z-score table). Therefore, x = 146 + (0.84 * 11) = 157.2 minutes. Part (d) The median of the average running times is 146 minutes. The median is the midpoint of the data which means half of the data is above the median and half of the data is below the median. Therefore, the median of the average running times is equal to the mean.
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Thabang save money by putting coins in a money box. The money box has 600 coins that consist of 20 cents and 50 cents
So calculate how many 50 cents pieces are in the container if there are 220 pieces of 20 cents
The number of 50 cents in the container is 380 fifty cents
How to find the number of 50 cents in the container?Since Thabang save money by putting coins in a money box. The money box has 600 coins that consist of 20 cents and 50 cents
To calculate how many 50 cents pieces are in the container if there are 220 pieces of 20 cents, we proceed as follows.
Let
x = number of 20 cents and y = number of 50 centsSince the total number of cents in the container is 600, we have that
x + y = 600
So, making y subject of the formula, we have that
y = 600 - x
Since x = 220
y = 600 - 220
= 380
So, there are 380 fifty cents
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Each section of the graphic organizer contains a vocabulary term or the possible
solution type for the system shown. Use the list below to complete the graphic
organizer. Some terms may be used more than once.
slope y-intercept linear equations
infinitely many solutions no solution one solution
System of
y= 3x+ 2
y= - 4x+ 2
Different
y= 2x+ 7
y= 2x- 4
Same
y= 6x+ 3
y= - x- 4
Number of solutions:
y= 4x+ 3
y= 4x- 1
Different
y= 3x+ 6
y= 3x+ 6
Same
y= 4x+ 3
y= 4x- 1
Number of solutions:
y= 3x+ 6
y= 3x+ 6
Number of solutions:
For the first equation with y = 3x + 2 and y = -4x + 2, the lines have the same slope, but a different y-intercept. This means that the lines are parallel and they will never intersect. Therefore, the system of equations has no solution.
For the second equation with y = 2x + 7 and y = 2x - 4, the lines have the same slope and the same y-intercept. This means that the lines are coincident and they will intersect at one point. Therefore, the system of equations has one solution.
For the third equation with y = 6x + 3 and y = -x - 4, the lines have a different slope and a different y-intercept. This means that the lines are not parallel and they will intersect at one point. Therefore, the system of equations has one solution.
For the fourth equation with y = 4x + 3 and y = 4x - 1, the lines have the same slope and the same y-intercept. This means that the lines are coincident and they will intersect at one point. Therefore, the system of equations has one solution.
For the fifth equation with y = 3x + 6 and y = 3x + 6, the lines have the same slope and the same y-intercept. This means that the lines are coincident and they will intersect at one point. Therefore, the system of equations
please help!! there are multiple parts that i dont get
Answer:
(a, b) alternate interior angles at M and N, and at A and B are congruent
(c) the triangles are congruent by SAS and by ASA (and MX = NX)
(d) angles are no longer congruent, so the triangles are not congruent. The radii are given as congruent, but the chords cannot be shown congruent.
Step-by-step explanation:
Given same-size circles A and B, externally tangent to each other at X, each with chords MX and NX, you want to know what can be concluded if AM║BN, and what is unprovable if those segments are not parallel.
Same-size circlesThe circles being the same size means all the radii are congruent. This is shown by the single hash marks in the attached diagram.
(a) AnglesAlternate interior angles where a transversal crosses parallel lines are congruent. If AM║BN, this means the angles marked with a single arc are congruent, and the angles marked with a double arc are congruent. These are the alternate interior angles at transversal MN and at transversal AB.
(b) Corresponding partsIf AM║BN, in addition to the given congruences, we also know ...
all radii are congruent — given in the problem statementangles M and N are congruent (see above)angles A and B are congruent (see above)the vertical angles at X are congruent to each other and to angles M and N (isosceles triangles) (AMBN is a parallelogram.)(c) Congruent triangles∆AMX ≅ ∆BNX by SAS or ASA (take your pick).
(d) Not parallelIf AM and BN are not parallel, MN is not a straight line through X, the angles at A and B are not congruent, and the angles at M and N are not congruent. (We assume segment AB still goes through X.)
__
Additional comment
Triangles MAX and NBX are isosceles, so their base angles are congruent. If X lies on MN, then AM and BN must be parallel, since the vertical angles at X will be congruent along with the other base angles at M and N. If AM and BN are not parallel, point X cannot lie on segment AB.
a random variable x has the following probability distribution. values of x -1 0 1 probability 0.3 0.4 0.3 (a) calculate the mean of x.
The mean (also called the arithmetic mean or average) is a measure of central tendency that represents the typical or average value of a set of data. The mean is calculated by summing up all the values in the data set and dividing by the number of values.
The mean of x is calculated by the following formula:
mean of x = ∑(x * P(x))
Where, ∑ = Summation operator
x = Value of random variable
P(x) = Probability of the corresponding value of x.
Let's calculate the mean of x using the formula provided above.
mean of x = (-1 × 0.3) + (0 × 0.4) + (1 × 0.3)
= -0.3 + 0 + 0.3
= 0
Therefore, the mean of x is 0.
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I need to show my work please help
Answer:
x=15
Step-by-step explanation:
use the side splitter theorem
(x-6)/x = 3/5 (cross-multiply)
3x=5(x-6) distributive property
3x=5x-30
2x = 30
x = 15
rotate M(-3,5) to 270 degrees
Answer:
Clockwise it would be (3,-5)
Step-by-step explanation:
Counterclockwise it would be (-3,-5)
hope this helps!
Please help I will give brainliest
The point that partitions segment AB in a 1:4 ratio is (-1/2, -1).
What is Segment?
In geometry, a segment is a part of a line that has two endpoints. It can be thought of as a portion of a straight line that is bounded by two distinct points, called endpoints. A segment has a length, which is the distance between its endpoints. It is usually denoted by a line segment between its two endpoints, such as AB, where A and B are the endpoints. A segment is different from a line, which extends infinitely in both directions, while a segment has a finite length between its two endpoints.
To find the point that partitions segment AB in a 1:4 ratio, we need to use the midpoint formula to find the coordinates of the point that is one-fourth of the distance from point A to point B. The midpoint formula is:
((x1 + x2)/2, (y1 + y2)/2)
where (x1, y1) and (x2, y2) are the coordinates of the two endpoints of the segment.
So, let's first find the coordinates of the midpoint of segment AB:
Midpoint = ((-3 + 7)/2, (2 - 10)/2)
= (2, -4)
Now, to find the point that partitions segment AB in a 1:4 ratio, we need to find the coordinates of a point that is one-fourth of the distance from point A to the midpoint. We can use the midpoint formula again, this time using point A and the midpoint:
((x1 + x2)/2, (y1 + y2)/2) = ((-3 + 2)/2, (2 - 4)/2)
= (-1/2, -1)
So, the point that partitions segment AB in a 1:4 ratio is (-1/2, -1).
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Answer:
Let's start by defining our variables:
Let x be the number of mahogany boards sold.Let y be the number of black walnut boards sold.Now, let's write the system of inequalities to represent the constraints:
The company has 260 boards of mahogany, so x ≤ 260.
The company has 320 boards of black walnut, so y ≤ 320.
The company expects to sell at most 380 boards, so x + y ≤ 380.
We cannot sell a negative number of boards, so x ≥ 0 and y ≥ 0.
Graphically, these constraints represent a feasible region in the first quadrant of the xy-plane bounded by the lines x = 260, y = 320, and x + y = 380, as well as the x and y axes.
To maximize profit, we need to write a function that represents the objective. The profit for selling one board of mahogany is $20, and the profit for selling one board of black walnut is $6. Therefore, the total profit P can be calculated as:
P = 20x + 6yTo maximize P, we need to find the values of x and y that satisfy the constraints and make P as large as possible. This is an optimization problem that can be solved using linear programming techniques.
The solution to this problem can be found by graphing the feasible region and identifying the corner point that maximizes the objective function P. However, since we cannot draw a graph here, we will use a table of values to find the maximum profit.
Let's consider the corner points of the feasible region:
Corner point (0, 0):
P = 20(0) + 6(0) = 0
Corner point (260, 0):
P = 20(260) + 6(0) = 5200
Corner point (0, 320):
P = 20(0) + 6(320) = 1920
Corner point (100, 280):
P = 20(100) + 6(280) = 3160
Corner point (200, 180):
P = 20(200) + 6(180) = 5520
Corner point (380, 0):
P = 20(380) + 6(0) = 7600
The maximum profit is $7600, which occurs when the company sells 380 boards of wood, all of which are mahogany.