Is the graph increasing, decreasing, or constant?
​

A parallel line would contain the same slope and have a different y-intercept.

Using the slope of the original line you would start with:

Y = -5x + b, where b is the new y-intercept.

Using the given point replace x and y and solve for b:

-9 = -5(-4) + b

Simplify:

-9 = 20 + b

Subtract 20 from both sides

-29 = b

Now replace b in the equation to get:

Y = -5x -29

Answer 3. -7.5 is located to the left of 6.5 on a number line oriented from left to right.

Answer:

Step-by-step explanation:

Correct choice is C

[tex]\\ \sf\longmapsto \dfrac{2x}{3}-7=5[/tex]

[tex]\\ \sf\longmapsto \dfrac{2x-21}{3}=5[/tex]

[tex]\\ \sf\longmapsto 2x-21=5(3)[/tex]

[tex]\\ \sf\longmapsto 2x-21=15[/tex]

[tex]\\ \sf\longmapsto 2x=15+21[/tex]

[tex]\\ \sf\longmapsto 2x=36[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{36}{2}[/tex]

[tex]\\ \sf\longmapsto x=18[/tex]

Answer:

y=mx+b

b is the y intercept

b=0, so 0 is the y intercept

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]\frac{sinxcos^3x-cos xsin^3x}{cos^42x-sin^42x} \\=\frac{sin x cos x(cos^2x-sin ^2 x)}{(cis^2 2x+sin^2 2x)(cos^2 2x-sin ^22x)} \\=\frac{2sin x cos x cos 2x}{2(1)(cos 4x)} \\=\frac{sin 2x cos 2x}{2 cos 4x} \\=\frac{2 sin 2x cos 2x}{4 cos 4x} \\=\frac{sin 4x}{4 cos 4x} \\=\frac{1}{4} tan 4x[/tex]

Answer:

hope it help you

Step-by-step explanation:

mark me brailiest answer

Answer:

x=0,1,±2

Step-by-step explanation:

x^3(x^2-5)=-4x

x^2(x^2-5)=-4

Take x^2=a, we have

a*(a-5)=-4, a^2-5a+4=0, (a-1)(a-4)=0, a=1,4

x^2=0, 1, 4. x=0,1,±2

Answer:

x = 1 and x = 2

Step-by-step explanation:

[tex] {x}^{5} - 5 {x}^{3} = - 4x \\ {x}^{4} - 5 {x}^{2} + 4 = 0 \\ ( {x}^{2} - 4)( {x}^{2} - 1)=0[/tex]

x² = 4 or x² = 1

Since x > 0, the negative integers are rejected and the solutions to this equations are x = 1 and x = 2

Answer:

420.31

Step-by-step explanation:

A

.Rs.420.31

20ejjdj

Answer:

I think A rs 420.31 is right answet

Answer:

1,3,5

Step-by-step explanation:

81 is a perfect square so it can be written as an integer

11.8 is rational because it can be written as a fraction (107/9)

sqrt(6) isn't a perfect square so it is irrational

3/7 is a fraction so it is rational

8.57 is a terminating decimal so it is rational

Answer:

x = -4

Step-by-step explanation:

[tex]3(x-5)=5x-(3-x)\\\\3x-15=5x-3+x\\\\3x-15=6x-3\\\\-15=3x-3\\\\-12=3x\\\\-4=x[/tex]

Step-by-step explanation:

[tex]3(x - 5) = 5x - (3 - x) \\ 3x - 15 = 5x - 3 + x \\ 3x - 5x - x = - 3 + 15 \\ - 3x = 12 \\ x = \frac{12}{ - 3} \\ x = - 4[/tex]

I hope it helped U

stay safe stay happy

2x - 22 < -8

Add 22 to both sides

2x < 14

Divide both sides by 2

X < 7

Answer:

[tex]2x-22<-8[/tex]

Add 22 to both sides

[tex]2x-22+22<-8+22[/tex]

[tex]2x<14[/tex]

Divide both sides by 2

[tex]\frac{2x}{2}<\frac{14}{2}[/tex]

[tex]x<7[/tex]

OAmalOHopeO

Answer:

4.4 mm

Step-by-step explanation:

Answer:

C) -1.255

Step-by-step explanation:

We are tasked to solve for the residual value given that when x equals 29, y will be equals to 27.255. But, when it is tested, y actual value is 26. The formula in solving residual is shown below:

Residual value = Observed value - predicted value

Residual value =  26 - 27.255

Residual values = -1.255

The answer is -1.255 for residual value.

Answer:

Adrenaline: A stress hormone produced within the adrenal gland that quickens the heart beat, strengthens the force of the heart's contraction, and opens up the bronchioles in the lungs, among other effects. The secretion of adrenaline is part of the human 'fight or flight' response to fear, panic, or perceived threat.

Step-by-step explanation:

From the given information; Let the unknown different positive integers be (a, b, c and d).

An integer is a set of element that are infinite and numeric in nature, these numbers do not contain fractions.

Suppose we make an assumption that (a) should be the greatest value of this integer.

Then, the other three positive integers (b, c and d) can be 1, 2 and 3 respectively in order to make (a) the greatest value of the integer.

Therefore, the average of this integers = 9

Mathematically;

[tex]\mathbf{\dfrac{(a+b+c+d)}{4} =9}[/tex]

[tex]\mathbf{\dfrac{(a+1+2+3)}{4} =9}[/tex]

[tex]\mathbf{\dfrac{(6+a)}{4} =9}[/tex]

By cross multiplying;

6+a = 9 × 4

6+a = 36

a = 36 - 6

a = 30

Therefore, we can conclude that from the average of four positive integers which is equal to 9, the greatest value for one of the selected integers is equal to 30.

Learn more about integers here:

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The greatest value for one of the four positive integers is 30.

To find the largest positive integer, you have to minimize the other three positive integers.

Find the average of the four positive integers and equate it to the given value of the average.

[tex]\frac{6 + y}{4} = 9\\\\6+ y = 36\\\\y = 36-6\\\\y = 30[/tex]

Thus, the greatest value for one of the positive integers is 30

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The perimeter = sum of all sides

= 120 + 80 + 50

= 250

So 250 - 3

247

Left space for gate

Now cost of fencing = Rs 20/per meter

= 247 × 20

= Rs 4,940

Now the area of the triangular park can be found using heron's formula

S = (a+b+c)/2

S = (120+80+50)/2

S = 250/2

S = 125

Now

Herons formula = √s(s-a)(s-b)(s-c)

√125(125-120)(125-80)(120-50)

√125(5)(45)(70)

√5×5×5×5×5×3×3×5×14

After Making pairs

5×5×5×3√14

375√14

Therefore 375√14m is the area of the triangular park

Must click thanks and mark brainliest

$\sf\underline\bold{Answer:}$

$\space$

$\sf\underline\bold{Step-by-Step:}$

$\space$

$\sf\bold{Given(In \:the\:Q):}$

$\space$

$\sf\bold{To \: find:}$

$\space$

$\sf\small{☆Area\:to\:be\:planted=Area \: of \: ∆ABC}$

$\space$

$\sf\underline\bold{Calculating\:area\:of\:∆ABC:}$

$\space$

Use heron's formula to find the area of the triangle.

$\space$

$\mapsto$ $\sf\small{Heron's\:formula=}$

[tex]\sf\sqrt{s(s-a)(s-b)(s-c)}[/tex]

$\space$

$\sf\bold{Now,find\:semi\:parameter:-}$

$\sf\small{Perimeter\:of\:the\:∆=120+80+50=250}$

$\sf\small{Semi-Perimeter:}$ $\sf\dfrac{250}{2}$ $\sf\small{=125m}$

$\space$

$\sf\small{Substitute \: the\:values\:in\:heron's\:formula:}$

$\sf{Area\:of\:the\:∆:-}$

$\mapsto$ [tex]\sf\sqrt{125(125-120)(125-80)(125-50)}[/tex]

$\space$

$\mapsto$ $\sf\sqrt{125\times(5)\times(45)\times(75)}$

$\space$

$\mapsto$ $\sf\small\sqrt{2109375}$ $\sf\small{=375}$ $\sf\small\sqrt{15}$

$\space$

$\longmapsto$ $\sf\underline\bold\purple{1452.56m^2}$

______________________________

$\sf\underline\bold{Now,find\:the\:cost\:of\:fencing:}$

$\sf{Cost\:of\:fencing-}$

$\space$

$\sf\underline{Hence,the\:gardener\:has\:to\:fence:}$

$\space$

So,total cost of fencing at the rate of Rs.20 per m:-

___________________________________

Step-by-step explanation:

a fraction of a number out of 100%

Answer and step-by-step explanation:

Percent (%) means per 100

A percentage is a number or ratio expressed as a fraction of 100

Example 50% of 8 = 8*50/100 = 4

Answer:

Below

Step-by-step explanation:

Part A: -1 and 2.5

Part B: The vertex is a minimum

Part C: tbh, I'm not quite sure about this part but just use parts A and B to answer :)

(you can also use the website desmos. com/calculator as a graphing calculator)

Given the five number summary, christina has scored 70 marks which is equal to the median of the test scores, therefore about [tex]\frac{1}{2}[/tex] class scored higher than her and  [tex]\frac{1}{2}[/tex] class scored lower than her, making option (d) correct.

The five number summary is the descriptive summary of a data where in you are provided the lowest observation, first quartile, median, third quartile and the maximum observation.

Here, the first quartile is the observation which lies at a point in the ordered data that 25% observations are lesser than it and 75% are greater than it.

the median is the observation which lies at a point in the ordered data that 50% observations are lesser than it and 50% are greater than it.

the third quartile is the observation which lies at a point in the ordered data that 75% observations are lesser than it and 25% are greater than it.

As given in the data,

Christina's marks = 70

median marks = 70

christina's marks = median marks

therefore, by definition of median, about half class scored lower than christina and half more than her.  

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The complete question is given below:

Given the five number summary  as:

minimum = 2

first quartile = 50

median = 70

third quartile = 85

maximum = 96

Christina earned 70 on the test. Describe how the scores of Christina's

classmates compared to Christina's score.

A. about 1/4 scored higher, about 3/4 scored lower

B. about 314 scored higher, about 1/2 scored lower

C. about 3/4 scored higher, about 1/4 scored lower

D. about 1/2 scored higher, about 1/2 scored lower

The choose C. –2/15

(-2/15) +(-13/5) =(-13/5) +a/b

a/b = (-2/15)+(-13/5) - (-13/5)

a/b = (-2/15) - ( 39/15) +(39/15)

a/b = –2/15

I hope I helped you ^_^

Answer: option 3: a/b = (-2/15)

Step-by-step explanation:

See here when we solve this

(-2/15)+(-13/5) = (-13/5)+a/b

(-2/15) = (-13/5)+a/b-(-3/15)

(-2/15) = a/b

please click thanks and mark brainliest if you like :)

Answer:

Step-by-step explanation:

Given:

Isolate b:

Find b:

[tex]\\ \sf\longmapsto t+\dfrac{1}{2}b=Y[/tex]

[tex]\\ \sf\longmapsto \dfrac{1}{2}b=Y-t[/tex]

[tex]\\ \sf\longmapsto \dfrac{b}{2}=Y-t[/tex]

[tex]\\ \sf\longmapsto b=2(Y-t)[/tex]

[tex]\\ \sf\longmapsto b=2Y-2t[/tex]

You're going to have to break all of these identities into sin and cos, and then just resolve them like normal.

The expression [tex]\frac{tan x + cot x}{cosec x* cos x} = sec ^{2} x[/tex] is proved .

Trigonometric ratios are the ratios of the length of sides of a triangle. These ratios in trigonometry relate the ratio of sides of a right triangle to the respective angle.

formulas for trigonometric ratios is:

sin θ = 1/cosec θ

cos θ = 1/sec θ

tan θ = 1/cot θ

cosec θ = 1/sin θ

sec θ = 1/cos θ

cot θ = 1/tan θ

According to the question

[tex]\frac{tan x + cot x}{cosec x* cos x} = sec ^{2} x[/tex]

[tex]\frac{\frac{sin x}{cos x} + \frac{cos x}{sin x}}{\frac{1}{sin x}*cosx } = sec^{2} x[/tex]

[tex]\frac{\frac{sin^{2}x + cos^{2}x }{sinx cosx} }{\frac{cosx}{sinx} } = sec^{2} x[/tex]

[tex]\frac{\frac{1}{sinx cosx} }{\frac{cosx}{sinx} } = sec^{2} x[/tex]

[tex]\frac{\frac{1}{cosx} }{\frac{cosx}{1} } = sec^{2} x[/tex]

[tex]\frac{1}{cos^{2} x} =sec^{2} x[/tex]

[tex]sec^{2} x =sec^{2} x[/tex]

L.H.S = R.H.S

Hence, The expression [tex]\frac{tan x + cot x}{cosec x* cos x} = sec ^{2} x[/tex] is proved  .

To know more about trigonometric ratio here:

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$\sf\underline\bold\blue{Information\:given\:in\:the\:question:}$

$\space$

$\sf\underline\bold\blue{What\:we\:have\:to\:find?}$

$\space$

$\sf\underline\bold\blue{Answer:}$

$\space$

$\sf\underline\bold\blue{Calculations:}$

Here we have the value of the circle's diameter that is 20inches. So, first we have to calculate the radius of the circle using the formula :

$\mapsto$ $\sf\bold{Radius=}$ $\sf\dfrac{Diameter}{2}$

$\space$

$\sf\underline\bold\blue{Calculating\:the\:required\:values:}$

$\mapsto$ $\sf\bold{Radius=}$ $\sf\dfrac{20}{2}$

$\sf{Convert \: to \: the\:lowest\:term(Divide),}$

$\mapsto$ $\sf\underline\bold{Radius=10}$

☆Now we know the value of the radius . So now let's calculate the area of the circle.

$\space$

$\sf\bold{Area\:of\:circle:}$ π$\sf{ r \: ^{2} }$

$\sf\bold{Evaluating \: the\:required\:values:}$

$\sf\bold{Area\:of\:circle=3.1415(10)^2}$

$\space$

$\sf\bold{Area\:of\:the\:circle=3.1415\times10\times10}$

$\sf\bold{Now,}$

$\sf\bold{Area\:of\:the\:circle:3.1415\times100}$

$\space$

$\sf\underline\bold\green{Thus,Area\:of\:the\:circle\: is \: 314.15}$

____________________________

Answer:

=2^5+5^5

=32+3125

=3157

Answer:

x2 + xy2 + y 4=（x+y^2)^2-xy^2

Step-by-step explanation:

Answer:

x=27

y=25

c=12

n=70

Step-by-step explanation:

a- x-10=17

isolate the x by adding 10 to both sides

x=27

b- y+7=32

isolate the y by subtracting 7 from both sides

y=25

c- 4c=48

isolate c by dividing both sides by 4

c=12

d- n/5=14

isolate the n by multiplying both sides by 5

n=70

Answer:

a) [tex]x-10=17[/tex]

Add 10 to both sides:-

----------

b) [tex]y+7=32[/tex]

Subtract 7 from both sides

------------

c) [tex]4c=48[/tex]

Divide both sides by 4

------------

d) [tex]\frac{n}{5}=14[/tex]

Multiply both sides by 5

OAmalOHopeO

I am trying to simplify a difference quotient with the form

f(x+h)−f(h)/h

if f(x)=2/x2 I have attempted to cancel out the denominator of the numerator by the least common denominator method. I know that I can solve this using implicit differentiation, but am trying to use the difference quotient to get the partial derivative

Here is my work so far:

f(x+h)−f(x)(h)

=f(2/(x+h)2)−f(2/x2)h

=(2/(x+h)2)−(2/x2)h

here I multiply by the LCD

=(2(x2)−2(x+h)2)/(x2(x+h)2)h

Here I expand out the top and cancel out 2x2

=(2x2−(2x2+4xh+2h2))/(x2(x+h)2)h

=−(4xh+2h2)/(x2(x+h)2))h

Here I think I should multiply by 1/h to get rid of the h on the bottom

I end up with:

=4xh+2h2hx2(x+h)2

factor out an h

=−4x+2hx2(x+h)2

Answer:

the answer is c

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

Hi there!

[tex]\large\boxed{\frac{1}{4}, -\frac{3}{2}}[/tex]

13y² + 10y - 3 = 5y²

Begin by moving all terms to one side:

13y² + 10y - 3 - 5y² = 0

Combine like terms:

8y² + 10y - 3 = 0

Factor using the guess-and-check method.

(4y - 1)(2y + 3) = 0

Set each factor equal to 0 to find the solutions:

4y - 1 = 0

4y = 1

y = 1/4

2y + 3 = 0

2y = -3

y = -3/2