Instructions: Find the missing side of the triangle.
25
20
х
X =

Answer:

∠ DCV = ∠ VBD = 50°

Step-by-step explanation:

The inscribed angles DCV and VBD are half the measure of their intercepted arcs, that is

∠ DCV = [tex]\frac{1}{2}[/tex] DV = [tex]\frac{1}{2}[/tex] × 100° = 50°

∠ VBD = [tex]\frac{1}{2}[/tex] DV = [tex]\frac{1}{2}[/tex] × 100° = 50°

Answer:

By translating the function cos(x) 90 degrees to the right.

Step-by-step explanation:

The sine function is just the cosine function translated 90 degrees to the right. You can see the visualization below. They overlap.

If you're wondering why the diagram shows a shift in

[tex]\pi / 2[/tex]

That's just the equivalent to 90 degrees in radians.

Answer:

12x^3-9x^2+4x-3

3(4x^3-1)-(9x^2+4x)

therefore option A is right

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Countless symmetry axis of a parabola is vertical line which divides the parabola into two congruent halves.

The axis of symmetry always passes through vertex of parabola. These will cause the plane to divide into two parts.

The geometric shape may have countless symmetry axis. This actually divides the shape into two halves and creates a mirror like effect.

The x-coordinate of vertex is equation of axis symmetry of parabola. Lets say if we take an example of quadratic equation which is ,

y = ax^2 + bx + c , here in this equation the axis of symmetry is vertical line which is x = - b^2 a

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Answer:

.1273 mi = 627.2 feet

c = 2[tex]\pi[/tex]r

.4 = 2[tex]\pi[/tex]r

r = [tex]\frac{.4}{2\pi }[/tex]

r = [tex]\frac{.2}{\pi }[/tex]

d = [tex]\frac{.4}{\pi }[/tex]

d = .1273 mi = 627.2 feet

Step-by-step explanation:

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Answer:

230 children

Step-by-step explanation:

Answer:

1/4

Step-by-step explanation:

2/5 divided by 8/5 is the same as 2/5 * 5/8. we cross out the same 5's to get 2/8. We simplify that to 1/4.

1/4 is our answer.

Answer:

16/5x

Step-by-step explanation:

as there is 2 5x so it will be 2 by 5x +6+ 8 by 5x

next there is two 5x and it will be 1 5x

then we will add 2+6+8=16

and there is already 5x ..simple.

hope it will help

Answer:

x= 10

Step-by-step explanation:

(whole secant) x (external part) =  (whole secant) x (external part)

(8+x) * 8 = (9+-3+x) * 9

8(8+x) = 9(6+x)

Distribute

64+8x=9x+54

Subtract 8x from each side

64 = x+54

Subtract 54 from each side

10 =x

Answer:

36 degrees

Step-by-step explanation:

10 corners/sides.

the sum of all exterior angles in a polygon is always 360 degrees.

so, one exterior angle here is 360/10 = 36 degrees

Answer:

Step-by-step explanation:

Algebra level

Answer:

total pages = 20

Step-by-step explanation:

60% of an unknown number is 12

Let the unknown number (total pages) be x.

60/100 of x = 12

60/100 * x = 12

3/5 x = 12

x = 12 * 5/3

x = 20

Answer:

[tex]y = 2x + 7[/tex]

Step-by-step explanation:

Use Point Slope Form since we are given the slope and coordinates. Why is the slope 2x?

In Depth: Parallel lines never touch so they are Lines that have same slope but different y intercept. An example is a square. A square has four parallel sides. The upper and lower sides will never touch because they are the same slope and they both have a finite distance vertically between them.

Back to the question, let use the Point Slope Form,

[tex]y - y_{1} = m(x - x_{1})[/tex]

Where y1 is the y coordinate of the given point, m is the slope and x is the x coordinates of the given points.

Substitute

[tex]y - ( - 1) = 2(x - ( - 4)[/tex]

[tex]y + 1 = 2(x + 4)[/tex]

Simplify

[tex]y + 1 = 2x + 8[/tex]

[tex]y = 2x + 7[/tex]

Answer:

Step-by-step explanation:

first

3/10 & 7/10

second

5/9 & 4/9

Answer:

Answer:

The answer is d.) 4^18

Answer:

y = -1/3x + 5

Step-by-step explanation:

First you want to find the slope with the formula y2-y1/x2-x1.

4-6/3-(-3)

-2/6

-1/3

Second you want to substitute one point and the slope to find the y-intercept.

6 = -3(-1/3) + b

6 = 1 + b

5 = b

Third you can fill in the information we solved for.

y = -1/3x + 5

Best of Luck!

Answer:

x = ±i ,  x=1

Step-by-step explanation:

(x^2+1)(x-1)=0

Using the zero product property

x^2 +1 = 0   x-1= 0

x^2 = -1       x=1

Taking the square root of the equation on the left

sqrt(x^2) = sqrt(-1)

x = ±i   where  i is the imaginary number

We still have x=1 from the equation on the right

Here we have a quadratic function and we want to find the value of a constant with a given restriction.

We will find that c = 8.

So we have the function:

[tex]f(x) = -2c + cx - x^2[/tex]

We know that:

[tex]f(5)^{-1} = -1 = \frac{1}{-2c + c\cdot 5 - (5)^2}[/tex]

Notice that the above equation means that:

[tex]-2c + c\cdot5 - (5)^2 = -1[/tex]

Then we just need to solve the above equation for c:

[tex]-2c + 5c - (5)^2 = -1\\\\(-2 + 5)\cdot c - 25 = -1\\\\3\cdot c = -1 + 25\\\\3\cdot c = 24\\\\c = 24/3 = 8[/tex]

So we found that the value of c is 8.

This means that the function is:

[tex]f(x) = -16 + 8\cdot x - x^2[/tex]

You can see the graph below:

If you want to learn more, you can read:

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Answer:

Heights of 29.5 and below could be a problem.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches.

This means that [tex]\mu = 32, \sigma = 1.5[/tex]

There may be a problem when a child is in the top or bottom 5% of heights. Determine the heights of 2-year-old children that could be a problem.

Heights at the 5th percentile and below. The 5th percentile is X when Z has a p-value of 0.05, so X when Z = -1.645. Thus

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-1.645 = \frac{X - 32}{1.5}[/tex]

[tex]X - 32 = -1.645*1.5[/tex]

[tex]X = 29.5[/tex]

Heights of 29.5 and below could be a problem.

Answer:

rational number

Step-by-step explanation:

a rational number can be written as a/b where a and b are integers

23/17 = a/b where a = 23 and b = 17

This is a rational number

Answer:

I think it would be

A .39

I hope that it helps you

Answer:

64 cm³

Does the answer help you?

Answer:

Hello,

Step-by-step explanation:

[tex]\dfrac{f(x)}{3} =\dfrac{x^4+x^3+x^2+1}{(x-1)(x+2)} \\\\=\dfrac{(x^2+3)(x-1)(x+2)-3x+7}{(x-1)(x+2)} \\=x^2+3-\dfrac{3x-7}{(x-1)(x+2)} \\\\=x^2+3-\dfrac{3}{x-1} +\dfrac{1}{(x-1)(x-2)} \\\\\dfrac{f(x)}{3}-\dfrac{3x^2+9}{3} =-\dfrac{3}{x-1} +\dfrac{1}{(x-1)(x-2)} \\\\\\ \lim_{x \to +\infty} (\dfrac{f(x)}{3}-\dfrac{3x^2+9}{3} )\\\\=0+0=0\\\\\\P(x)=-x^2-3[/tex]

Answer:

[tex]g(x)=-3x^2-9[/tex]

Explanation:

[tex]3\frac{x^4+x^3+x^2+1}{x^2+x-2}[/tex]

+[tex]\frac{p(x)(x^2+x-2)}{x^2+x-2}[/tex]

We need p(x) need to be a degree 2 polynomial so the numerator of the second fraction is degree 4. Our goal is to cancel the terms of the first fraction's numerator that are of degree 2 or higher.

So let p(x)=ax^2+bx+c.

[tex]3\frac{x^4+x^3+x^2+1}{x^2+x-2}[/tex]

+[tex]\frac{p(x)(x^2+x-2)}{x^2+x-2}[/tex]

Plug in our p:

[tex]3\frac{x^4+x^3+x^2+1}{x^2+x-2}[/tex]

+[tex]\frac{(ax^2+bx+c)(x^2+x-2)}{x^2+x-2}[/tex]

Take a break to multiply the factors of our second fraction's numerator.

Multiply:

[tex](ax^2+bx+c)(x^2+x-2)[/tex]

=[tex]ax^4+ax^3-2ax^2[/tex]

+[tex]bx^3+bx^2-2bx[/tex]

+[tex]cx^2+cx-2c[/tex]

=[tex]ax^4+(a+b)x^3+(-2a+b+c)x^2+(-2b+c)-2c[/tex]

Let's go back to the problem:

[tex]3\frac{x^4+x^3+x^2+1}{x^2+x-2}[/tex]

+[tex]\frac{ax^4+(a+b)x^3+(-2a+b+c)x^2+(-2b+c)x-2c}{x^2+x-2}[/tex]

Let's distribute that 3:

[tex]\frac{3x^4+3x^3+2x^2+3}{x^2+x-2}[/tex]

+[tex]\frac{ax^4+(a+b)x^3+(-2a+b+c)x^2+(-2b+c)x-2c}{x^2+x-2}[/tex

So this forces [tex]a=-3[/tex].

Next we have [tex]a+b=-3[/tex]. Based on previous statement this forces [tex]b=0[/tex].

Next we have [tex]-2a+b+c=-3[/tex]. With [tex]b=0[/tex] and [tex]a=-3[/tex], this gives [tex]6+0+c=-3[/tex].

So [tex]c=-9[tex].

Next we have the x term which we don't care about zeroing out, but we have [tex]-2b+c[/tex] which equals [tex]-2(0)+-9=-9[/tex].

Lastly, [tex]-2c=-2(-9)=18[/tex].

This makes [tex]p(x)=-3x^2-9[/tex].

This implies [tex]g(x)\frac{(-3x^2-9)(x^2+x-2)}{x^2+x-2}[/tex] or simplified [tex]g(x)=-3x^2-9[/tex]

Answer:

[tex]4\sqrt{5}[/tex]

Step-by-step explanation:

In order to solve this problem, we can use the pythagorean theorem, which is

a^2 + b^2 = c^2, where and b are the legs of a right triangle and c is the hypotenuse. Since we are given the leg lengths, we can substitute them in. So, where a is we can put in a 4 and where b is we can put in an 8:

a^2 + b^2 = c^2

(4)^2 + (8)^2 = c^2

Now, we can simplify and solve for c:

16 + 64 = c^2

80 = c^2

c = [tex]\sqrt{80}[/tex]

Our answer is not in simplified radical form because the number under is divisible by a perfect square, 16. We can divide the inside, 80,  by 16, and add a 4 on the outside, as it is the square root of 16:

c = [tex]4\sqrt{5}[/tex]

The length of the hypotenuse in the given right triangle, with legs measuring 4 and 8, is approximately 8.94.

To find the length of the hypotenuse in a right triangle, we can use the Pythagorean theorem. According to the theorem, in a right triangle, the square of the hypotenuse's length is equal to the sum of the squares of the lengths of the other two sides.

In this case, let's label the lengths of the legs as 'a' and 'b', with 'a' being 4 and 'b' being 8. The hypotenuse, which we need to find, can be represented as 'c'.

Applying the Pythagorean theorem, we have:

[tex]a^2 + b^2 = c^2[/tex]

Substituting the given values:

[tex]4^2 + 8^2 = c^2[/tex]

16 + 64 = [tex]c^2[/tex]

80 = [tex]c^2[/tex]

To find the length of the hypotenuse 'c', we need to take the square root of both sides:

√80 = √ [tex]c^2[/tex]

√80 = c

The square root of 80 is approximately 8.94.

Therefore, the length of the hypotenuse in the given right triangle, with legs measuring 4 and 8, is approximately 8.94.

To know more about  hypotenuse , here

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28

How?

We can see that 28 is the lowest common multiple also it is <30

Answer: 28.

Step-by-step explanation: 28 is divisible by 4: 28 / 4 = 7. 28 is divisible by 14: 28 / 14 = 2. And 28 is less than 30