in the figure below the segments ST and SU are tangent to the circle centered at O given that SU=4.8 and OS=6 find OT

After considering the deposits and withdrawals, the account balance at the end of the month is $64.23.

To calculate the account balance at the end of the month, we need to add up all the deposits and withdrawals. The negative values represent withdrawals, while the positive values represent deposits.

Starting with an initial balance of $19.96, we can calculate the final balance by adding the amounts of the deposits and subtracting the amounts of the withdrawals.

Starting balance: $19.96

Deposits: $90.95, $11.16

Withdrawals: -$28.51, -$41.34, -$88.95

Adding the deposits: $19.96 + $90.95 + $11.16 = $122.07

Subtracting the withdrawals: $122.07 - $28.51 - $41.34 - $88.95 = $64.23

Therefore, the account balance at the end of the month is $64.23.

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Amy sold 50 boxes of Thin Mints and 80 boxes of Caramel Delights.

We assume Amy sold x boxes of Thin Mints and y boxes of Caramel Delights.

We will set up two equations:

Multiplying first equation by 5, we get:

5x + 5y = 650

Now, we subtract from second equation:

5x + 6y - (5x + 5y) = 730 - 650

y = 80

Substituting value of y into first equation:

x + 80 = 130

x = 130 - 80

x = 50

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The length of each side of the rectangle can be found by calculating the distance between the given coordinates.

The side lengths are 8 units and 6 units, respectively. The perimeter of the rectangle is the sum of all four side lengths, which is 28 units.

To find the length of each side of the rectangle, we calculate the distance between the given coordinates. Let's consider the coordinates M(1,1), N(1,9), P(7,9), and Q(7,1).

The side MN has coordinates (1,1) and (1,9). The vertical distance between these two points is 9 - 1 = 8 units.

The side NP has coordinates (1,9) and (7,9). The horizontal distance between these two points is 7 - 1 = 6 units.

The side PQ has coordinates (7,9) and (7,1). The vertical distance between these two points is 9 - 1 = 8 units.

The side QM has coordinates (7,1) and (1,1). The horizontal distance between these two points is 7 - 1 = 6 units.

Therefore, the length of each side of the rectangle is 8 units and 6 units.

The perimeter of a rectangle is the sum of all four side lengths. In this case, the perimeter is 8 + 6 + 8 + 6 = 28 units.

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The given options represent four different algebraic expressions in terms of x and y. We will determine which of these options represent a linear equation. The option that represents a linear equation is D.

y = x + 4. Linear equation in one variable is of the form,

ax + b = 0, where a and b are constants, and a ≠ 0.

The correct option is D.

It represents a straight line when plotted on a graph. The degree of the equation is 1. The slope of the line is given by -a/b and the y-intercept is given by -b/a. The solution of the equation is given by x = -b/a. Linear equation is also called first degree equation. The option D represents a linear equation of the form,

y = x + 4, where a = 1 and

b = 4.The degree of the equation is 1.

ax + b = 0.

where a and b are constants, and a ≠ 0. It represents a straight line when plotted on a graph. The degree of the equation is 1. The slope of the line is given by -a/b and the y-intercept is given by -b/a. The solution of the equation is given by x = -b/a. Linear equation is also called first degree equation. The option D represents a linear equation of the form,

y = x + 4, The solution of the equation is given by

x = -b/a. Linear equation is also called first degree equation. The option D represents a linear equation of the form,

y = x + 4, where

a = 1 and

b = 4. The degree of the equation is 1.

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The velocity ratio of the system is 9. To calculate the mechanical advantage of the system, we can use the formula Mechanical Advantage (MA) = Length of Effort Arm / Length of Load Arm

In this case, the length of the effort arm is the distance from the fulcrum to the end of the bar that the man applies effort, which is 0.50m. The length of the load arm is the distance from the fulcrum to the marble, which is 5.0m - 0.50m = 4.50m.

Therefore, the mechanical advantage is:

MA = 0.50m / 4.50m = 1/9

The minimum effort required to lift the load can be calculated using the formula:

Effort = Load / MA

In this case, the load is the weight of the marble, which is 700 kg, and the mechanical advantage is 1/9.

Therefore, the minimum effort required is:

Effort = 700 kg / (1/9) = 6300 N

Now, let's calculate the velocity ratio. Efficiency is defined as the ratio of useful work output to the total work input. Since the efficiency is given as 90%, the efficiency can be expressed as:

Efficiency = (Useful Work Output / Total Work Input) * 100%

In this case, the useful work output is the work done in lifting the load, which is the weight of the marble multiplied by the height it is lifted. The total work input is the effort applied multiplied by the distance it moves.

Let's assume the marble is lifted vertically by a height h.

Useful Work Output = Weight of Marble * Height Lifted = 700 kg * g * h

Total Work Input = Effort * Distance Moved = 6300 N * h

Efficiency = (700 kg * g * h / (6300 N * h)) * 100% = (700 / 6300) * 100% = 11.11%

The velocity ratio can be calculated as the reciprocal of the efficiency:

Velocity Ratio = 1 / Efficiency = 1 / 0.1111 = 9

Therefore, the velocity ratio of the system is 9.

In summary, the mechanical advantage of the system is 1/9, the minimum effort required to lift the load is 6300 N, and the velocity ratio is 9.

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The width is 1.1 meters. The width of the object is 1.1 meters, as it is 6 times shorter than the length of 6.6 meters.

To find the width of an object when given the length, we need to apply the given information that the width is 6 times shorter than the length.

Let's denote the width as "w." According to the given information, the width is 6 times shorter than the length. In other words, the width is equal to 1/6 of the length.

Mathematically, we can express this relationship as:

w = (1/6) * length

Substituting the given length of 6.6 meters into the equation, we can calculate the width:

w = (1/6) * 6.6

w = 1.1

Therefore, the width is 1.1 meters.

Based on the given information, the width of the object is 1.1 meters, as it is 6 times shorter than the length of 6.6 meters.

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The scale factor of the dilation used to transform polygon ABCD to polygon ABCD is 0.75.

To find the scale factor of a dilation, we can compare the corresponding side lengths of the original and transformed polygons.

Let's consider the side AB of polygon ABCD. The original coordinates of its endpoints are (0, -7) and (8, 8). The transformed coordinates of the endpoints are (6, -6) and (2, 1.5).

Using the distance formula, we can calculate the length of side AB in both the original and transformed polygons:

Original polygon:

Length of AB = sqrt((8 - 0)^2 + (8 - (-7))^2) = sqrt(64 + 225) = sqrt(289) = 17

Transformed polygon:

Length of AB = sqrt((2 - 6)^2 + (1.5 - (-6))^2) = sqrt((-4)^2 + (7.5)^2) = sqrt(16 + 56.25) = sqrt(72.25) = 8.5

Now, we can calculate the scale factor by dividing the length of the transformed side by the length of the original side:

Scale factor = Length of transformed AB / Length of original AB = 8.5 / 17 = 0.5

Therefore, the scale factor of the dilation used to transform polygon ABCD to polygon ABCD is 0.75. This means that all the side lengths of the transformed polygon are 0.75 times the length of the corresponding sides in the original polygon.

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The logarithm base 12 can be expressed as log12 or in exponential form as 12^x = y, where x is the exponent and y is the result.

The logarithm function is the inverse of exponentiation. It represents the exponent to which a given base (in this case, 12) must be raised to obtain a certain value. There are four different ways to express log12:

Logarithmic form: log12(y) - This notation indicates that the logarithm base 12 is being applied to a value y.

Exponential form: 12^x = y - In this form, the base 12 is raised to an exponent x to produce a value y.

Fractional exponent form: y^(1/12) - The fractional exponent represents the root of y with a base of 12. It is equivalent to log12(y).

Common logarithm form: log(y) / log(12) - If the logarithm base 12 function is not directly available, we can use the common logarithm (base 10) or any other logarithmic base and apply the change of base formula. The result is the logarithm of y divided by the logarithm of 12.

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In a rhombus, opposite sides are congruent, and opposite angles are congruent. Let's use this information to find the measures in the given rhombus JKLM.

MK = NL = 30 (given)

mZMKL = 41° (given)

Since opposite sides are congruent, we know that:

MJ = KL = 30 (opposite sides of the rhombus are congruent)

Since opposite angles are congruent, we can determine the measures of the other angles:

mZKLM = mZMKL = 41° (opposite angles are congruent)

Now, let's find the measure of angle J:

mZJKL = 180° - mZKLM (The sum of the angles in a quadrilateral is 360°, and mZKLM is given as 41°)

mZJKL = 180° - 41°

mZJKL = 139°

Therefore, the measures in the given rhombus JKLM are:

MK = NL = 30

MJ = KL = 30

mZMKL = mZKLM = 41°

mZJKL = 139°

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To solve the given problem we have to add the quantities of blue and yellow paint that were used by Gunther to make the mural.We are given that:Gunther used 3 3/5 pints of blue paint and 2 1/10 pints of yellow paint to make a mural.To add these two quantities we need to find a common denominator.

Here, the common denominator is 10.As such, we have to convert the mixed numbers to improper fractions.3 3/5 = (3 × 5 + 3)/5 = 18/5 2 1/10 = (2 × 10 + 1)/10 = 21/10Now, we can add the two fractions to get the total amount of paint used:18/5 + 21/10 = (36 + 21)/10 = 57/10 Therefore, Gunther used a total of 57/10 pints of paint to make the mural.Now, let's simplify this answer.

We can simplify the fraction by dividing both the numerator and denominator by the greatest common factor of 57 and 10, which is 1.57/10 = 5.7Thus, Gunther used 5.7 pints of paint to make the mural.In conclusion, Gunther used 3 3/5 pints of blue paint and 2 1/10 pints of yellow paint, or a total of 5.7 pints of paint to make the mural.

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The System Of Inequalities are : $3s + $12p ≤ $120

Let's represent the number of bags of soil as 's' and the number of plants as 'p'.

The given information can be translated into the following system of inequalities:

1. Cost inequality: $3s + $12p ≤ $120

  (The total cost of soil bags and plants should be less than or equal to $120.)

2. Plant requirement: p ≥ 5

  (Tre's mom wants at least 5 plants in her garden.)

Now, let's find two possible solutions that satisfy the given conditions:

Solution 1:

- Let's consider Tre purchasing 8 bags of soil (s = 8).

- Then, he can buy 5 plants (p = 5).

  (8 bags of soil cost $24, and 5 plants cost $60, which sums up to $84.)

Solution 2:

- Let's consider Tre purchasing 10 bags of soil (s = 10).

- Then, he can buy 6 plants (p = 6).

  (10 bags of soil cost $30, and 6 plants cost $72, which sums up to $102.)

These two solutions satisfy the conditions of at least 5 plants and a total cost of $120 or less.

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The subject that most requires attention would be Natural Sciences.

Option B is the correct answer.

We have,

It is subjective to determine which subject requires the most attention, as it depends on various factors such as educational goals, societal needs, and individual interests.

However, if we were to assign points based on general importance:

a) History - 1 point

b) Natural Sciences - 2 points

c) Civic and Ethical - 1 point

d) Geography - 1 point

Based on this allocation, the subject that most require attention would be Natural Sciences.

Thus,

The subject that most requires attention would be Natural Sciences.

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The complete question:

What is the subject that most require attention? *

2 points

a) History.

b) Natural Sciences.

c) Civic and Ethical.

d) Geography

Answer

there's 120 members in total

84 not pensioners

Explaination

36÷30% = 120

70% are not pensioners

so 70% × 120 = 84

or you could minus the pensioners from the total 120-36=84

The slope of the equation y = 7x^2 is 14x, not one of the given options.

The slope of a quadratic equation can be determined by finding its derivative with respect to x. In this case, we have y = 7x^2. To find the derivative, we apply the power rule of differentiation. The power rule states that if we have a term of the form ax^n, the derivative is given by nx^(n-1).

Applying the power rule to y = 7x^2, we get dy/dx = 2 * 7x^(2-1) = 14x. The slope of the equation is represented by the derivative, which in this case is 14x. It is important to note that the slope of a quadratic equation varies depending on the value of x. Therefore, the slope is not a constant value like the options given (-7, -5, 2, or 7). Instead, the slope is expressed as a function of x, which is 14x in this case.

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To find the value of x in the given problem, we can start by calculating the area of the rectangular box. The area of a rectangular box is given by the formula A = 2lw + 2lh + 2wh, where l represents the length, w represents the width, and h represents the height. In this case, the area is given as 29,946 in².

The first step is to substitute the given values into the formula:

29,946 = 2(x)(5x - 1) + 2(x)(2x + 3) + 2(5x - 1)(2x + 3).

Next, we simplify the equation and distribute the terms:

29,946 = 2(5x² - x) + 2(2x² + 3x) + 2(10x² + 15x - 2x - 3).

After combining like terms, we have:

29,946 = 10x² - 2x + 4x² + 6x + 20x² + 30x - 4x - 6.

Combining similar terms further, we get:

29,946 = 34x² + 40x - 6.

Now, we can rearrange the equation and set it equal to zero:

34x² + 40x - 29,946 = 0.

To solve this quadratic equation, we can either factor it or use the quadratic formula. However, since the equation is not easily factorable, we can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a).

By substituting the values a = 34, b = 40, and c = -29,946 into the quadratic formula, we can find the two possible values of x. However, since we are looking for a real-world length, we can discard any negative or non-real solutions.

After solving the equation, we find that x is approximately equal to 24.4 or x ≈ -29.36. Since negative values are not meaningful in the context of length, we can conclude that the value of x for which the rectangular box has the given area of 29,946 in² is approximately 24.4 inches.

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Answer:

y = 1.5x + 4

The slope is 1.5, and the y-intercept is 4.

When you start your walk at point D and then proceed to points E, B, C, and then back to D the the total distance traveled is 72 yards.

In the figure above, walking path BE intersects two sides of a park at their midpoints. One of the vertices of the rectangle is point D.

Starting at point D, walking path BE intersects two sides of the park at their midpoints. Then proceed to points E, B, C and back to D.

The rectangle has two sets of sides with equal length, and BD is a diagonal of the rectangle, so triangle ABD is a 45°-45°-90° right triangle.

As a result,

              AD = BD = 12 yards.

Likewise, triangle BDC is a 45°-45°-90° right triangle, so

            CD = BD

                    = 12 yards.

Therefore, the total distance traveled is 12 + 4 + 12 + 8 + 12 + 4 + 12 + 8 = 72 yards.

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The relative frequency of the dice landing on a six is 0.74 or 74%.

1. Given that a dice is rolled 50 times and it lands on six 37 times.

2. Use the formula for relative frequency: Relative Frequency = (Number of times the dice lands on a six) ÷ (Total number of times the dice is rolled).

3. Substitute the values into the formula: Relative Frequency of dice landing on six = 37/50 = 0.74 or 74%.

Conclusion: In summary, when a dice is rolled 50 times and it lands on six 37 times, the relative frequency of the dice landing on a six is calculated to be 0.74 or 74%.

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The correct factorization for x^8 - 625 is (x^4 - 25)(x^4 + 25). To factor the expression completely, we need to recognize that it is a difference of squares.

The difference of squares formula states that a^2 - b^2 can be factored as (a - b)(a + b). In this case, we have x^8 - 625, which can be expressed as (x^4)^2 - 25^2. Using the difference of squares formula, we can factor x^8 - 625 as (x^4 - 25)(x^4 + 25). The first factor, x^4 - 25, represents the difference of squares (x^4 - 5^2), which further factors to (x^2 - 5)(x^2 + 5). The second factor, x^4 + 25, is a sum of squares and cannot be further factored.

Therefore, the complete factorization of x^8 - 625 is (x^4 - 25)(x^4 + 25), which represents the product of the difference of squares and the sum of squares.

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The cost of painting all the cones is ₹ 384.34 (approx.)

Here, we have,

Given: The base diameter of the cone is 40 cm and its height is 1m.

Since the outer side of each cone is to be painted, the area to be painted will be equal to the curved surface area of the cone.

The curved surface area of a right circular cone with base radius(r) and slant height(l) is πrl

Slant height, l = √(r² + h²) where h is the height of the cone.

Diameter, d = 40cm = 40/100 m = 0.4m

Radius, r = 0.4/2m = 0.2m

Height, h = 1 m

Slant height, l = √(0.2)² + (1)²

= √0.04m² + 1m²

= √1.04 = 1.02m (given)

The curved surface area = πrl

= 3.14 × 0.2m × 1.02m

= 0.64056 m2

Curved surface area of 50 cones = 50 × 0.64056 m2 = 32.028 m2

Cost of painting of 50 cones at ₹ 12 per m2 = 32.028 × 12

= ₹ 384.34 (approx.)

Thus, the cost of painting all the cones is ₹ 384.34 (approx.)

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complete question:

A bus stop is barricaded from the remaining part of the road, by using 50 hollow cones made of recycled cardboard. Each cone has a base diameter of 40 cm and height 1 m. If the outer side of each of the cones is to be painted and the cost of painting is ₹ 12 per m2, what will be the cost of painting all these cones? (Use π = 3.14 and take √1.04 = 1.02)

The lengths of the sides of the triangle are approximately:

The two equal sides: 61/45 cm

The third side: 1089/405 cm

Let's assume that the two equal sides of the triangle are represented by "x" cm each. According to the given information, the third side is 1 1/3 cm longer than the other two sides.

So, the length of the third side can be represented as "x + 1 1/3" cm.

The perimeter of a triangle is the sum of all its sides. In this case, the perimeter is given as 5 2/5 cm.

Using this information, we can write the equation:

2x + (x + 1 1/3) = 5 2/5

To solve this equation, let's convert the mixed number 1 1/3 to an improper fraction.

1 1/3 = (3× 1 + 1) / 3 = 4/3

Substituting the value, we have:

2x + (x + 4/3) = 5 2/5

To simplify the equation, let's convert the mixed number 5 2/5 to an improper fraction.

5 2/5 = (5 ×5 + 2) / 5 = 27/5

Now, the equation becomes:

2x + (x + 4/3) = 27/5

Combining like terms, we have:

3x + 4/3 = 27/5

To eliminate the fractions, let's multiply both sides of the equation by the least common multiple (LCM) of the denominators, which is 15:

15 × (3x + 4/3) = 15 ×(27/5)

45x + 20 = 81

Subtracting 20 from both sides:

45x = 61

Dividing both sides by 45:

x = 61/45

So, the value of x is 61/45 cm. This represents the length of the two equal sides of the triangle.

Now, to find the length of the third side, we substitute x back into the expression:

x + 1 1/3 = (61/45) + 4/3

To add these fractions, we need to find a common denominator. The LCM of 45 and 3 is 45:

[(61/45) × (3/3)] + (4/3) = (183/135) + (4/3)

Now, we can add the fractions:

(183/135) + (4/3) = (549/405) + (540/405) = 1089/405

So, the length of the third side is 1089/405 cm.

Therefore, the lengths of the sides of the triangle are approximately:

The two equal sides: 61/45 cm

The third side: 1089/405 cm

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The weight in Newtons that the scale reads when the elevator is in different scenarios can be calculated using the formula W = mg, where W = weight, m=  mass, and g = the acceleration due to gravity.

a. When the elevator is at rest, there is no acceleration, so the weight will be equal to the gravitational force acting on the person. The weight can be calculated as W = mg, where m is the mass of the person (85 kg) and g is the acceleration due to gravity (approximately 9.8 m/s^2). Thus, the weight is W = 85 kg * 9.8 m/s^2.

b. the weight will remain the same as the gravitational force, which is calculated using the formula W = mg.  c. The acceleration is still zero, and the weight will be the same as the gravitational force, calculated using the formula W = mg.

d. We need to consider the net force acting on the person. The net force will be the sum of the gravitational force and the force due to the acceleration. The weight can be calculated as W = mg + ma, where m is the mass of the person (85 kg), g is the acceleration due to gravity (approximately 9.8 m/s^2), and a is the upward acceleration (3 m/s^2).

e. We calculate the weight similarly to case d. The weight is W = mg + ma, where m is the mass of the person (85 kg), g is the acceleration due to gravity (approximately 9.8 m/s^2), and a is the downward acceleration (-4 m/s^2) since it acts in the opposite direction.

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The problem requires adding two measurements in different units, 2 ft 5 in and 9 in. We need to determine the sum of these measurements.

To add the given measurements, we should first convert them to a consistent unit. In this case, we will convert everything to inches since the second measurement is already in inches.

1 foot is equal to 12 inches, so 2 ft is equal to 2 * 12 = 24 inches. Therefore, 2 ft 5 in can be written as 24 in + 5 in. Adding 24 in and 5 in, we get 29 in. Thus, the sum of 2 ft 5 in and 9 in is 29 inches. In conclusion, when we add 2 ft 5 in and 9 in, the result is 29 inches.

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The results can be explained by the process of diffusion. The water outside the Visking bag remained a yellow color because the diffusion process was slower for iodine particles.

So as to move from the higher concentration outside the bag to the lower concentration inside the bag. First, iodine solution was added to the water in the test-tube. Iodine is a solute and the water is the solvent.

During the 30 minutes, diffusion occurred, which is the movement of particles from an area of higher concentration to an area of lower concentration. In this case, the iodine particles inside the Visking bag diffused through the membrane into the surrounding water. This caused the water inside the Visking bag to turn blue-black as it became saturated with iodine.

However, the water outside the Visking bag remained a yellow color because the diffusion process was slower for iodine particles to move from the higher concentration outside the bag to the lower concentration inside the bag.

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Nicholas scooped a few gumballs into his bag and found that it weighed 0.76 pounds.

Nicholas's bag of gumballs weighs 0.76 pounds. This weight includes the combined mass of the gumballs and the bag itself. The weight measurement indicates the force exerted by the bag due to the gravitational pull of the Earth. To determine the weight of just the gumballs, Nicholas would need to subtract the weight of the bag from the total weight.

To find the weight of the bag, Nicholas could use a scale or balance to measure an empty bag of the same type. Once he knows the weight of the empty bag, he can subtract that weight from the total weight of the bag with the gumballs. The result will give him the weight of the gumballs alone.

It's important to note that the weight of the gumballs may vary depending on their size, density, and the material of the bag. Different types of gumballs may have different weights. To get an accurate measurement, Nicholas should use a precise weighing instrument and account for any external factors that could affect the weight, such as moisture or contaminants.

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Answer:

The correct answer is:

C.) 3000(1.035^(1/52))^t

This expression represents the equivalent exponential expression that identifies the weekly growth rate of the population. The exponent 1/52 represents the conversion from years to weeks, as there are 52 weeks in a year.

Step-by-step explanation:

The final image obtained after reflecting the triangle across the y-axis and translating it 5 units down is equivalent to reflecting the original triangle over the x-axis and then translating it 5 units down.

When we reflect the triangle across the y-axis, each point's x-coordinate is negated while the y-coordinate remains unchanged. This reflection essentially flips the triangle horizontally.

After reflecting the triangle, we then translate it 5 units down. This translation involves shifting each point of the triangle downward by 5 units along the y-axis.

Now let's consider the second transformation: reflecting the original triangle over the x-axis and then translating it 5 units down.

Reflecting the triangle over the x-axis means that each point's y-coordinate is negated while the x-coordinate remains unchanged. This reflection flips the triangle vertically.

After reflecting the triangle, we translate it 5 units down, which involves shifting each point of the triangle downward by 5 units along the y-axis.

By comparing the two sequences of transformations, we can see that they result in the same final image. First, we horizontally flip the triangle and then shift it downward, which is equivalent to first vertically flipping the triangle and then shifting it downward.

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Answer:

B. Translate 5 units down, and then reflect over the y-axis.

Step-by-step explanation:

The solution of the given system of equations is (2, -10).

The given system of equations is:

y = 4x - 5

We need to solve the system of equations given by

Step 1: We need to substitute

y = 4x - 5 into the second equation.

4x - y = 5 becomes

4x - (4x - 5) = 5

Simplifying the above equation will give us:-

y + 4x - 4x = 5 + 5y = -10

Hence, the solution of the given system of equations is

(x, y) = (2, -10).

Steps 2 and 3 to solve the system of equations are:

Step 2: Substitute

y = 4x - 5 into the second equation. This gives us:

4x - (4x - 5) = 5

Simplifying the above equation will give us:-

y + 4x - 4x = 5 + 5

Step 3: Solve the simplified equation to get the value of y.-

y = 10y = -10

Thus, the solution of the given system of equations is (2, -10).

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To make the theoretical and experimental probabilities closer, Jonas can increase the sample size by conducting more rolls of the 10-sided die. This will provide a more accurate representation of the theoretical probability.

By increasing the sample size, Jonas can gather more data points, which can help to reduce the impact of random variations and provide a more accurate representation of the theoretical probability. As the number of rolls increases, the experimental probability is more likely to approach the theoretical probability.

In this case, Jonas can conduct more rolls of the 10-sided die beyond the initial 20 rolls. The larger the number of rolls, the better the experimental probability will reflect the theoretical probability of rolling a 3. By increasing the sample size, Jonas can minimize the impact of outliers or chance occurrences that may have influenced the results in the initial 20 rolls, resulting in a closer alignment between the theoretical and experimental probabilities.

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The difference of the polynomials, we subtract one polynomial from the other. In this case, we have mn - (-11mn^3). The difference of the polynomials mn and -11mn^3 is 11mn^3 - mn.

To find the difference of the polynomials, we subtract one polynomial from the other. In this case, we have mn - (-11mn^3).

When subtracting the two polynomials, we distribute the negative sign to each term of the second polynomial:

mn + 11mn^3.

Next, we rearrange the terms in ascending order of the variable's exponent:

11mn^3 + mn.

Thus, the difference of the polynomials mn - 11mn^3 is 11mn^3 + mn. This expression represents a polynomial with the term 11mn^3 and the term mn, but no like terms can be combined further because the variables and exponents are different.

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