In the diagram, q1= +8.0 C, q2= +3.5 C, and q3 = -2.5 C. q1 to q2 is 0.10 m, q2 to q3 is 0.15 m. What is the net force on q2? Label sign for charges (+ or -). (Unit = N). pls help?

In The Diagram, Q1= +8.0 C, Q2= +3.5 C, And Q3 = -2.5 C. Q1 To Q2 Is 0.10 M, Q2 To Q3 Is 0.15 M. What

Answers

Answer 1

Answer:

f(t) =  28,7 [N]

Explanation: IMPORTANT NOTE: IN PROBLEM STATEMENT CHARGES ARE IN C (COULOMBS) AND IN THE DIAGRAM IN μC. WE ASSUME CHARGES ARE IN μC.

The net force on +q₂  is the sum of the force of +q₁  on +q₂ ( is a repulsion force since charges of equal sign repel each other ) and the force of -q₃ on +q₂ ( is an attraction force, opposite sign charges attract each other)

The two forces have the same direction to the right of charge q₂, we have to add them

Then

f(t) = f₁₂ + f₃₂

f₁₂ = K * ( q₁*q₂ ) / (0,1)²

q₁  = + 8 μC     then   q₁ = 8*10⁻⁶ C

q₂ =  + 3,5 μC  then  q₂ = 3,5 *10⁻⁶ C

K = 9*10⁹  [ N*m² /C²]

f₁₂ = 9*10⁹ * 8*3,5*10⁻¹²/ 1*10⁻²   [ N*m² /C²]* C*C/m²

f₁₂ = 252*10⁻¹ [N]

f₁₂ = 25,2 [N]

f₃₂ =  9*10⁹*3,5*10⁻⁶*2,5*10⁻⁶ /(0,15)²

f₃₂ =  78,75*10⁻³/ 2,25*10⁻²

f₃₂ =  35 *10⁻¹

f₃₂ =  3,5 [N]

f(t) =  28,7 [N]

Answer 2

Answer:

facts

Explanation:


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Answers

Energy

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A wave carries energy from one place to another. Mechanical waves carry energy through a material medium.

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A wave is a phenomenon that flows across a material medium without leaving any lasting mark.

Mechanical or electromagnetic waves can be used to classify them. Transverse and longitudinal are the two main forms.

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Answers

The x-component of the vector is 36.55 m.

Components of vectors

The components of a vector include both x and y components. The x-component is determined along x-axis, while y-component is determined along y-axis.

Vx = Vcosθ

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X-components of the vector

The x-component of the vector is calculated as follows;

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Answers

Answer:

Procedural is the answer

hope this helps

Answer: Procedural

Explanation: It states in the question that he developed a procedure! If this was something you have heard before, this is definitely the answer. Goodluck! ☺️

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Answers

Answer:

Both Thomson and Rutherford used charged particles in their experiments.

Explanation:

Theo both used charged particles

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0.0086 watts
OB.
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O C.
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Answers

Answer:

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Answers

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used to measure mass

Answers

Measuring mass with a balance

━━━━━━━☆☆━━━━━━━

▹ Answer

Kg is the unit used to measure mass.

▹ Step-by-Step Explanation

Kg stands for kilogram, and is the SI unit used to measure mass.

Hope this helps!

CloutAnswers ❁

━━━━━━━☆☆━━━━━━━

What is the average velocity of atoms in 2.00 mol of neon (a monatomic gas)
at 308 K? Use the equation: -mv2
2
For m, use 0.02000 kg. Remember that R = 8.31 J/(mol-K).
= ER
3
2
nRT
A. 1540 m/s
B. 876 m/s
C. 87.6 m/s
O D. 15,400 m/s

Answers

Answer:

v = 876 m/s

Explanation:

It is given that,

Number of mol of Neon is 2 mol

Temperature, T = 308 K

Mass, m = 0.02 kg

Value of R - 8.31 J/mol-K

We need to find the average velocity of atoms in 2.00 mol of neon. Neon is a monoatomic gas. Let v is the velocity. So,

[tex]\dfrac{1}{2}mv^2=\dfrac{3}{2}nRT\\\\v=\sqrt{\dfrac{3nRT}{m}} \\\\v=\sqrt{\dfrac{3\times 2\times 8.314\times 308}{0.02}} \\\\v=876.47\ m/s[/tex]

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I think it is 887m/s I hope this helps if not I’m really sry
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