In the diagram O is the centre of the circle. If ZOAB 32' and ZEDA-15, find: (1) ZADB and (ii) ZEAO. D 37°​

With comparison to the initial value of x, this signifies an increase of 5%.

If, for instance, we have the mathematical problem y′=2x y ′ = 2 x, then y(3)=7 y (3) = 7 is an initial value, so when these equations are combined, they create an initial-value problem.

The calculation of a 5% increase in the value of x is done by the phrase 1.05x.

We may modify the phrase as follows to understand why:

1.05x = x + 0.05x

Thus, 1.05x is the same as increasing x by 5% from its initial value.

For example, if x = 100, then:

1.05x = 1.05 × 100 = 105

The initial value of x has increased by 5% as a result of this.

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With comparison to the initial value of x, this signifies an increase of 5%. Thus, option A is correct.

If, for instance, we have the mathematical problem y′=2x y ′ = 2 x, then y(3)=7 y (3) = 7 is an initial value, so when these equations are combined, they create an initial-value problem.

The calculation of a 5% increase in the value of x is done by the phrase 1.05x.

We may modify the phrase as follows to understand why:

1.05x = x + 0.05x

Thus, 1.05x is the same as increasing x by 5% from its initial value.

For example, if x = 100, then:

1.05x = 1.05 × 100 = 105

The initial value of x has increased by 5% as a result of this.

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Complete question:

The expression 1.05x calculates what change to the value of x?

a. increase of 5%

b. Power of 5

c. decrease of 5%

d. fraction of 5

Answer: I got you!

Step-by-step explanation:

a) Sophie's distance is given by the formula: distance = rate × time. Therefore, her distance yesterday is s × t miles.

b) Rana's time is given by the formula: time = distance ÷ rate. Therefore, her time yesterday is m ÷ r hours.

c) Sophie's time is given by the formula: time = distance ÷ rate. Let's call the time Sophie waits for Rana "w". Then we have two equations:

Sophie's distance: s × (w + t) = 20

Rana's distance: r × (w + t) = 20 - m

We can solve for "w" by substituting the second equation into the first equation:

s × (w + t) = 20 - r × (w + t) + m

(s + r) × (w + t) = 20 + m

w + t = (20 + m) ÷ (s + r)

w = (20 + m) ÷ (s + r) - t

Therefore, Sophie waits for Rana for (20 + m) ÷ (s + r) - t hours.

d) Sophie's distance tomorrow is s × 3 miles, and Rana's distance tomorrow is r × 3 miles. Therefore, the difference in distance is (s - r) × 3 miles.

[tex]\bold{Solution:}[/tex]

[tex]\Delta[/tex][tex]DE[/tex][tex]F[/tex] congruent to [tex]\Delta[/tex][tex]JKI[/tex]

[tex]\bold{FD=JI} \text{(corresponding angles of congruent triangles)}[/tex]

[tex]z + 22 = 3z[/tex]

[tex]\text{or,} \ z-3 z= -22[/tex]

[tex]\text{or,} \ -2z = -22[/tex]

[tex]\text{or,} \ z = \bold{11}[/tex]

[tex]\bold{EF=KI} \text{(corresponding angles of congruent triangles)}[/tex]

[tex]5y+13=6y[/tex]

[tex]\bold{y=13}[/tex]

Answer: 14,605 pieces.

Step-by-step explanation:

In the second quarter, the company produced 795 pieces more than in the first quarter.

So, the total pieces produced in the second quarter can be calculated as:

6905 + 795 = 7700

The total pieces produced in the first semester (two quarters) can be calculated as:

6905 + 7700 = 14,605

Therefore, the company produced 14,605 pieces in the first semester.

The number of pieces the company produced in the first semester was 14,605 pieces.

The question asks to calculate how many pieces a company produced in the first semester, considering the production of two quarters.

In the first quarter, the company produced 6,905 pieces, as indicated in the question.

Already in the second quarter, the company produced 795 more pieces than in the first quarter, which means that the production in the second quarter was:

6,905 + 795 = 7,700 pieces.

To know the company's total production in the first semester, just add the productions of the two quarters:

6,905 + 7,700 = 14,605 pieces

The answer of  the given question based on finding each measure of a circle the answer is , (a)  m(MNP) = 12.5° degrees , (b) m(KL) = 102.5° degrees , (c)  m(KJ) = 52.5° degrees , (d)  m(JN) = 102.5° degrees , (e)  m(JLM) =  12.5° degrees.

In geometry,  arc is a portion of  curved line that can be thought of as  segment of  circle. It is defined by two endpoints on  circle and the arc itself is the part of  circle between those two points. An arc can be measured in degrees, and its measure is equal to  central angle subtended by  arc. The length of  arc can also be calculated using the formula L = rθ, where L is  length of  arc, r is radius of  circle, and θ is  angle (in radians) subtended by  arc at center of circle.

Using the properties of angles and arcs in circles:

a. Angle MNP is inscribed in arc MP, so m(MNP) = 1/2m(MP) = 1/2(25) = 12.5° degrees.

Since angles NPM and MPK are vertical angles, we have m(MPK) = m(NPM) = m(MNP) = 12.5° degrees. Then, m(MN) = m(MPK) + m(KPM) = 12.5 + 40 = 52.5° degrees.

b. Angle LKP is inscribed in arc LP, so m(LKP) = 1/2m(LP) = 1/2(25) = 12.5° degrees.

Since angles PKL and LKN are vertical angles, we have m(PKL) = m(LKN) = m(LKP) = 12.5° degrees. Then, m(KL) = m(PKL) + m(PKC) = 12.5 + 90 = 102.5° degrees.

c. Angle PKJ is inscribed in arc PJ, so m(PKJ) = 1/2m(PJ) = 1/2(25) = 12.5° degrees.

Since angles LPK and LPJ are vertical angles, we have m(LPK) = m(LPJ) = m(PKJ) = 12.5° degrees. Then, m(KJ) = m(LPK) + m(LPJ) = 12.5 + 40 = 52.5° degrees.

d. Angle JNM is inscribed in arc JM, so m(JNM) = 1/2m(JM) = 1/2(25) = 12.5° degrees.

Since angles KJM and KJN are vertical angles, we have m(KJM) = m(KJN) = m(JNM) = 12.5° degrees. Then, m(JN) = m(KJM) + m(MJN) = 12.5 + 90 = 102.5° degrees.

e. Angle JLM is an inscribed angle that intercepts arc JM, so m(JLM) = 1/2m(JM) = 1/2(25) = 12.5° degrees.

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The 99% confidence interval for the population proportion p is :lower bound= 0.225, upper bound 0.375

What does a confidence interval actually mean?

Your estimate's mean is added to and subtracted from by the estimate's range to create a confidence interval. If you repeat your test, within a specific level of confidence, this is the range of values you anticipate your estimate to fall within.

Given that,

n = 250

x = 75

Point estimate = sample proportion =  p = x / n = 75/250=0.3

1 -  p =1 - 0.3=0.7

At 99% confidence level the z is ,

α  = 1 - 99% = 1 - 0.99 = 0.0

α / 2 = 0.01 / 2 = 0.005

Z /2 = Z0.005 = 2.576  (  Using z table   )  

Margin of error = E = Zα / 2 * √(( p * (1 -  p)) / n)

                              = 2.576 (√((0.3*0.7) /250 )

                            E  = 0.075

A 99% confidence interval for population proportion p is ,

p - E < p <  p + E

0.3 -0.075 < p < 0.3 + 0.075

0.225< p < 0.375

The 99% confidence interval for the population proportion p is :lower bound= 0.225, upper bound 0.375.

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The number of lionfish after 6 years will be 85,609. The recursive equation for [tex]f(n)[/tex] will be [tex]f(n) = 4242.42(1.65)^n - 1300n[/tex].

Consider the function:

[tex]y = a (1 \pm r)^x[/tex]

Where x is the number of times this growth/decay occurs, a = initial amount, and r = fraction by which this growth/decay occurs.

lionfish are considered an invasive species, with an annual growth rate of 65%.

Then the equation will be

[tex]f(n) = P(1.65)^n[/tex]

[tex]\text{P = initial population}[/tex]

A scientist estimates there are 7,000 lionfish in a certain bay after the first year.

[tex]7000 = P(1.65)[/tex]

    [tex]P = 4242.42[/tex]

Then the equation will be

[tex]f(n) = 4242.42(1.65)^n[/tex]

The number of lionfish after 6 years will be

[tex]f(n) = 4242.42(1.65)^6[/tex]

[tex]f(n) = 85608.58[/tex]

[tex]f(n) \cong 85,609[/tex]

If scientists remove 1,300 fish per year from the bay after the first year.

Then the recursive equation for f(n) will be

[tex]f(n) = 4242.42(1.65)^n - 1300n[/tex]

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The derivative of the function z= x^2y+xy^2, x = 3t y = t^2 using the chain rule is given by dz/dt = 36t^3 + 15t^4.

Expressions are equals to,

z= x^2y+xy^2

x = 3t

y = t^2

Using the chain rule calculate dz/dt,

which states that if z is a function of x and y,

And x and y are both functions of t, then,

dz/dt = (dz/dx)(dx/dt) + (dz/dy)(dy/dt)

Using these expressions, calculate the value of dz/dt using the chain rule,

z= x^2y+xy^2

This implies,

dz/dx = 2xy + y^2

dz/dy = x^2 + 2xy

x = 3t

⇒ dx/dt = 3

y = t^2

⇒ dy/dt = 2t

Substituting these values into the chain rule formula, we get,

dz/dt = (2xy + y^2)(3) + (x^2 + 2xy)(2t)

        = [2(3t)(t^2 ) + (t^2)^2 ]3 + [(3t)^2 + 2(3t)(t^2)](2t )

        = [ 6t^3 + t^4 ]3 + [ 9t^2 + 6t^3 ]2t

        = 18t^3 + 3t^4 + 18t^3 + 12t^4

        = 36t^3 + 15t^4

Substituting the given expressions for x and y into z, we get,

z = (3t)^2(t^2) + (3t)(t^2)^2

   = 9t^4 + 3t^5

here also,

dz/dt = 36t^3 + 15t^4

Therefore, the value of the function using the chain rule dz/dt is equals to  36t^3 + 15t^4.

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Answer:

The numbers 8 and lower are possible values of x.

Step-by-step explanation:

The inequality [tex]x\leq 8[/tex] means x is less than or equal to 8. Therefore, 8 is a possible value of x.

Answer:

6)-56+567)-/(05(-)9

Step-by-step explanation:

Question

Katherine bought 312

pounds of oranges for $1.45

per pound, as well as 434

pounds of potatoes that cost $1.69

for 2

pounds. She gives the cashier a $10.00

bill.

Which equation represents the situation if x

is the amount of change in dollars Katherine should receive?

A 312(1.45)+434(1.69)+x=10

3 and 1 half times 1 point 4 5 plus 4 and 3 fourths times 1 point 6 9 plus x is equal to 10

B 312(1.45)+434(1.692)+x=10

3 and 1 half times 1 point 4 5 plus 4 and 3 fourths times open paren 1 point 6 9 over 2 close paren plus x is equal to 10

C 312(1.45)+434(1.692)−x=10

3 and 1 half times 1 point 4 5 plus 4 and 3 fourths times open paren 1 point 6 9 over 2 close paren minus x is equal to 10

D (312+434)⋅(1.45+1.69)+x=10

HELP ME I WILL GIVE BRAINLIEST

Step-by-step explanation:

35:12

40:17

45:22

50:27

55:32

the definite integral of f(x) over the interval [5, 7] is (-5 / 600).

How to find?

The given function is:

f(x) = 1 / (x² + 10x + 25)

To find the definite integral of this function over the interval [5, 7], we can use the following steps:

Rewrite the function using partial fraction decomposition:

f(x) = 1 / (x² + 10x + 25)

= 1 / [(x + 5)²]

Using partial fraction decomposition, we can write this as:

f(x) = A / (x + 5) + B / (x + 5)²

where A and B are constants to be determined. Multiplying both sides by the common denominator (x + 5)², we get:

1 = A(x + 5) + B

Setting x = -5, we get:

1 = B

Setting x = 0, we get:

1 = 5A + B

= 5A + 1

Solving for A, we get:

A = 0

Therefore, the partial fraction decomposition is:

f(x) = 1 / [(x + 5)²]

= 0 / (x + 5) + 1 / (x + 5)²

Use the formula for the definite integral of a power function:

∫ xⁿ dx = (1 / (n + 1))× x²(n + 1) + C

where C is the constant of integration.

Using this formula, we can find the antiderivative of the function 1 / (x + 5)²:

∫ 1 / (x + 5)² dx = -1 / (x + 5) + C

Evaluate the definite integral over the interval [5, 7]:

∫[5,7] 1 / (x + 5)² dx

= [-1 / (x + 5)] [from 5 to 7]

= (-1 / 12) - (-1 / 10)

= (-5 / 600)

Therefore, the definite integral of f(x) over the interval [5, 7] is (-5 / 600).

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The temperature decreased by 41°F during the overnight hours.

Physical quantities with merely magnitude and no direction are called scalar quantities. Scalar values encompass things like mass, volume, temperature, and time. Real numbers, such as positive or negative integers or decimals, are frequently used to represent scalar quantities in mathematics.

In contrast, a vector quantity is a physical quantity that possesses both magnitude and direction. The terms displacement, velocity, force, and acceleration are all examples of vector quantities. Typically, vector values are represented by a number or symbol for the magnitude and an arrow or boldface letter for the direction.

Given that, the temperature went from 28 to -13.

The expression that represent this change are:

Expression 1: -13°F - 28°F

Expression 2: | -13°F - 28°F |

The temperature change can be calculated as:

| -13°F - 28°F | = |-41°F| = 41°F

Hence, the temperature decreased by 41°F during the overnight hours.

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Answer:

arc length = 2.2π inches

Step-by-step explanation:

arc length is calculated as

length = circumference of circle × fraction of circle

           = 2πr × [tex]\frac{22}{360}[/tex] ( r is the radius )

           = 2π × 18 × [tex]\frac{22}{360}[/tex] ( cancel 18 and 360 by 18 )

          = 2π × [tex]\frac{22}{20}[/tex]

        = [tex]\frac{44}{20}[/tex] π

       = 2.2π inches

The equation of the estimated population regression line is typically written in the form:

y = a + bx

where:

y is the dependent variable (or response variable)

x is the independent variable (or predictor variable)

a is the intercept (the value of y when x = 0)

b is the slope (the change in y for a unit change in x)

To create the correct equation of the estimated population regression line, Sonny should select the following options:

The variable y should be the dependent variable (or response variable).

The variable x should be the independent variable (or predictor variable).

The estimated intercept value should be plugged into the equation for a.

The estimated slope value should be plugged into the equation for b.

So, the correct equation of the estimated population regression line would be:

y = a + bx

where a and b are the estimated intercept and slope values, respectively.

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Understanding the equilibria, sketching a phase portrait, and determining the stability of equilibria for autonomous equations are important tools for analyzing and understanding the behavior of systems over time.

Autonomous equations are differential equations that do not depend explicitly on time. To find the equilibria of an autonomous equation, we set the derivative of the function to zero and solve for the values of the independent variable that satisfy the equation. These values represent points at which the function does not change over time and are known as equilibrium points.

To sketch a phase portrait for an autonomous equation, we plot the slope field of the function and then draw solutions through each equilibrium point. The resulting graph shows the behavior of the function over time and helps us understand how the solutions behave near each equilibrium point.

The stability of an equilibrium point is determined by examining the behavior of nearby solutions. If nearby solutions move toward the equilibrium point over time, the equilibrium point is stable. If nearby solutions move away from the equilibrium point over time, the equilibrium point is unstable. Finally, if the behavior of nearby solutions is inconclusive, further analysis is needed.

Here is the sketch for [tex]dx/dt = x - x^3[/tex]

       / <--- (-∞)  x=-1  (+∞) ---> \

      /                                \

  <--0-->       x=-1       x=1        0-->

      \                                /

       \ <--- (-∞)  x=1   (+∞) --->  /

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The constraint w1 w2 w3 < 1, where w1, w2, and w3 are 0-1 integer variables, is often called a packing constraint. The packing constraint w1 w2 w3 < 1 limits the number of variables that can be set to 1 and is used to control the number of items that can be selected in integer programming problems.

A packing constraint is a type of constraint used in integer programming that limits the number of items that can be selected from a set of items. In this case, the constraint limits the number of variables that can take the value 1 to be less than 1.

The term "packing" comes from the idea of packing items into a container. In the context of integer programming, packing constraints are used to limit the number of items that can be "packed" into a container (i.e., set to 1), while ensuring that the total value of the packed items meets certain requirements or constraints.

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When an isοsceles right triangle has a base οf x-2 and a height οf x-2. The area οf the triangle is 50 square inches then Using A=1/2 bh tο find the area οf a triangle is 1/2 (x-2)(x-2) = (x-2)²/2, and  12 inches is the value οf x?

An isοsceles right triangle has twο equal legs and the length οf the hypοtenuse is [tex]\sqrt{(2)[/tex] times the length οf a leg. In this case, bοth legs have the length x-2, sο the length οf the hypοtenuse is (x-2)*sqrt (2).

The area οf the triangle is given by A=1/2 bh, where b is the base and h is the height. In this case, b=h=x-2, sο the area is:

A = 1/2 (x-2)(x-2) = (x-2)²/2

Area is 50, sο we can set up an equatiοn:

(x-2)²/2 = 50

Multiplying bοth sides by 2 gives:

(x-2)² = 100

Taking the square rοοt οn bοth sides gives:

x-2 = 10 οr x-2 = -10

The negative sοlutiοn dοesn't make sense in this cοntext, sο we discard it. Therefοre, we have:

x-2 = 10

Adding 2 tο bοth sides gives:

x = 12

Therefοre, the value οf x is 12 inches.

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When an isοsceles right triangle has a base οf x-2 and a height οf x-2. The area οf the triangle is 50 square inches then Using A=1/2 bh tο find the area οf a triangle is 1/2 (x-2)(x-2) = (x-2)²/2, and  12 inches is the value οf x.

An isοsceles right triangle has twο equal legs and the length οf the hypοtenuse is  times the length οf a leg. In this case, bοth legs have the length x-2, sο the length οf the hypοtenuse is (x-2)*sqrt (2).

The area οf the triangle is given by A=1/2 bh, where b is the base and h is the height. In this case, b=h=x-2, sο the area is:

A = 1/2 (x-2)(x-2) = (x-2)²/2

Area is 50, sο we can set up an equatiοn:

(x-2)²/2 = 50

Multiplying bοth sides by 2 gives:

(x-2)² = 100

Taking the square rοοt οn bοth sides gives:

x-2 = 10 οr x-2 = -10

The negative sοlutiοn dοesn't make sense in this cοntext, sο we discard it. Therefοre, we have:

x-2 = 10

Adding 2 tο bοth sides gives:

x = 12

Therefοre, the value οf x is 12 inches.

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Answer:

A and B are not mutually exclusive

Step-by-step explanation:

A and B are not mutually exclusive because P(A and B) > 0. If A and B were mutually exclusive, then they would have no outcomes in common and the probability of their intersection would be zero. However, in this case, they do share some outcomes, since P(A and B) is greater than zero.

Answer:

[tex]xy^8[/tex]

Step-by-step explanation:

Notice if you have the same base you can ADD the exponent, for example:

[tex]x^{-6} x^{7} =x^{-6+7}=x^{1 }=x[/tex]

[tex]y^{6} y^{2} =y^{6+2}=y^{8 }\\[/tex]

so the answer is

[tex]xy^8[/tex]

As per the axial force, the support reaction at A is equal in magnitude to the axial force that is applied at the other end of the bar.

To determine the support reaction at A, we will draw a free-body diagram of the bar.

Since the bar is fixed at A, the support reaction at that end will be a vertical force, and we will label it as RA.

Using Newton's second law of motion, we can write the equation of equilibrium for the bar in the vertical direction:

ΣFy = 0

where ΣFy is the sum of all the forces in the vertical direction. Since there are only two forces acting on the bar, the axial force and the support reaction, we can write:

-FA + RA = 0

where FA is the axial force that is applied at one end, and RA is the support reaction at the other end.

From this equation, we can solve for RA:

RA = FA

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Complete Question:

Determine the support reaction at A

The axially loaded bar is fixed at A and loaded as shown. Draw a free-body diagram and determine the support reaction at A.

Answer:

Step-by-step explanation:

B because after having the star and the circle comes the square.

Answer:

H. 7

Step-by-step explanation:

Given x² + rx + 12 is equivalent to (x + 3)(x + s), equate the two expressions and expand the right side of the equation:

[tex]\begin{aligned}x^2+rx+12&=(x + 3)(x + s)\\ x^2+rx+12&=x^2 + sx + 3x + 3s\\x^2+rx+12&=x^2 + (s+3)x + 3s\end{aligned}[/tex]

To find the value of r, first find the value of s.

The constant term of the right-hand side must be equal to the constant term of the left-hand side. Therefore:

[tex]\implies 3s = 12[/tex]

Solve for s by dividing both sides of the equation by 3:

[tex]\implies s = 4[/tex]

Compare the coefficients of the terms in x:

[tex]\implies r = s + 3[/tex]

Substitute the value of s into the equation and solve for r:

[tex]\begin{aligned} \implies r &= s + 3\\&= 4 + 3\\&= 7\end{aligned}[/tex]

Therefore, the value of r is 7.

Answer:

[tex]\large\boxed{\sf r = 7 }[/tex]

Step-by-step explanation:

Correct question:- If r and s are constants and r² +rx + 12 is equivalent to (x+3)(x + s), what is the value of r?

Here we are given that , the expression (x+3)(x+s) is equal to r² + rx + 12 .

Firstly, expand the expression (x+3)(x+s) as ,

[tex]\implies (x+3)(x+s) \\[/tex]

[tex]\implies x(x+s)+3(x+s) \\[/tex]

[tex]\implies x^2 + xs + 3x + 3s \\[/tex]

Take out x as common,

[tex]\implies x^2 + (3+s)x + 3s \\[/tex]

Now according to the question,

[tex]\implies x^2 + (3+s)x + 3s = r^2 + rx + 12\\[/tex]

On comparing the respective terms , we get,

[tex]\implies r = 3 + s \\[/tex]

[tex]\implies 3s = 12 \\[/tex]

Solve the second equation to find out the value of s , so that we can substitute that in equation 1 to find "r" .

[tex]\implies 3s = 12 \\[/tex]

[tex]\implies s =\dfrac{12}{3}=\boxed{4} \\[/tex]

Now substitute this value in equation (1) as ,

[tex]\implies r = 3 + s \\[/tex]

[tex]\implies r = 3 + 4 \\[/tex]

[tex]\implies \underline{\underline{ \red{ r = 7 }}} \\[/tex]

and we are done!

The fractiοn οf students whο chοse card as their favοrite game type is: 1/6. Thus, option D is correct.

A circle is a clοsed twο-dimensiοnal shape that is defined as the set οf all pοints in a plane that are equidistant frοm a single fixed pοint called the center οf the circle. The distance frοm the center οf the circle tο any pοint οn the circle is called the radius οf the circle.

A circle can alsο be defined as the lοcus οf a pοint that mοves in a plane such that its distance frοm a fixed pοint (the center) remains cοnstant.

A circle is a very impοrtant and cοmmοn geοmetric shape that has many practical applicatiοns in mathematics, physics, engineering, and οther fields.

Tο determine the fractiοn οf students whο chοse card as their favοrite game type, we need tο find the pοrtiοn οf the circle graph that represents the card categοry.

Frοm the graph, we can see that the card categοry cοvers 16.66% οf the entire circle graph.

i.e.

16.66/100 = 1/6

Therefore, the fraction of students who chose card as their favorite game type is:

1/6

So, the answer is option D: 1/6.

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Complete question:

The circle graph shows the favourite game type of students in Ms. Hunter's class.

What fraction of the students chose card?

a. 2/3

b. 5/9

c. 3/10

d. 1/6

The area of the living room is 24.7 m², and the area of the game room is 37.05 m².

Area is the measure of the two-dimensional space occupied by a figure or an object. It is usually expressed in square units such as cm2, m2, or in2. It is used to measure the size of a figure or object, and can also be used to calculate the amount of material required for a project.

The area of a living room measuring 4.75 m by 5.2 m can be calculated using the formula A = l × w, where A is the area, l is the length and w is the width. In this case, A = 4.75 m × 5.2 m = 24.7 m².

To calculate the area of the game room, we must multiply the area of the living room by 1.5. Therefore, the area of the game room is 1.5 × 24.7 m² = 37.05 m².

The area of the living room is 24.7 m², and the area of the game room is 37.05 m².

The area of a room can be used to determine how much furniture can fit in the room or how much floor space is available for activities. Knowing the area of a room is also important for calculating the cost of painting, wallpapering, carpeting, and other flooring materials.

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Answer: C

Step-by-step explanation:

The correct answer is C.

The slope of the line represents the hourly wage, so Hunter's wage is $35 an hour, as given in option A and B. However, the y-intercept of the line represents the starting pay or the pay for zero hours worked. In this case, the y-intercept is 25, which means Hunter received $25 even if he did not work any hours. Hence, option C is correct as it states that Hunter's wage is $25 an hour, but it appears that he received no signing bonus.

Therefore, the quadratic polynomial with sum of zeroes 2/3 and product of zeroes 1/3 is:

3x² - 3x + 1

What is quadratic equation?

Quadratic equations are the polynomial equations of degree 2 in one variable of type f(x) = ax² + bx + c = 0 where a, b, c, ∈ R and a ≠ 0. It is the general form of a quadratic equation where 'a' is called the leading coefficient and 'c' is called the absolute term of f (x).

Let the quadratic polynomial be of the form ax² + bx + c.

We know that the sum of the zeroes is given by -b/a, and the product of the zeroes is given by c/a.

We are given that the sum of the zeroes is 2/3 and the product of the zeroes is 1/3.

So, we have the following system of equations:

-2b/3a = 2/3 (since the sum of zeroes is 2/3)

c/a = 1/3 (since the product of zeroes is 1/3)

Simplifying the first equation, we get:

b/a = -1

Substituting this in the second equation, we get:

c/a = 1/3

Multiplying both sides by a, we get:

c = a/3

So, we can choose any value for a, and then compute b and c accordingly.

Let's choose a = 3 for simplicity. Then, we have:

c = a/3 = 1

b/a = -1, so b = -3

Therefore, the quadratic polynomial with sum of zeroes 2/3 and product of zeroes 1/3 is:

3x² - 3x + 1

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Answer:

Here is a diagram and transition matrix for this case:

Diagram:

        +---(0.65)---> State 1 (work)

        |

Start ---+

        |

        +---(0.35)---> State 2 (procrastinate)

                  |

                  +---(0.15)---> State 1 (work)

                  |

                  +---(0.85)---> State 2 (procrastinate)

Transition matrix:

         |  State 1  |  State 2  |

----------+-----------+-----------+

State 1   |   1.00    |   0.00    |

----------+-----------+-----------+

State 2   |   0.15    |   0.85    |

----------+-----------+-----------+

In the transition matrix, the rows represent the starting state and the columns represent the ending state. The entries in the matrix represent the probabilities of transitioning from the starting state to the ending state. For example, the entry in row 1 and column 2 (0.00) represents the probability of transitioning from State 1 to State 2, which is 0.00.

Answer:

the answer to that is -31