In the absence of external force, the total momentum before a collision is equal to the total momentum after a collision.
In the absence of external force, the law of conservation of momentum states that the total momentum of a system remains constant before and after a collision. This fundamental principle is derived from Newton's third law of motion, which states that for every action, there is an equal and opposite reaction.
When two objects collide, they exert equal and opposite forces on each other, resulting in a transfer of momentum. Before the collision, the objects possess individual momenta based on their mass and velocity. The total momentum of the system is the vector sum of these individual momenta. During the collision, the objects interact and exert forces on each other, causing their momenta to change.
However, the total momentum of the system remains unchanged, as the gains and losses in momentum of individual objects cancel each other out.
Hence, the total momentum before the collision is equal to the total momentum after the collision. This principle is widely applicable in various fields, such as physics, engineering, and sports, and serves as a valuable tool in understanding and analyzing the dynamics of interacting objects.
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Ryan and Carson attended their church's youth retreat at Camp Paradise this past fall. On Saturday afternoon they took a walk out to the harbor and watched incoming waves from Lake Michigan rock the boating piers up and down. Ryan and Carson observed that the piers made a complete up and down vibration cycle in 6.6 seconds. The piers were positioned a distance of 24 meters apart. When one pier was at a high position, the neighboring pier was at a low position and there was exactly one wave crest between them. Determine the wavelength, frequency and speed of the waves.
The wavelength of the waves is 48 meters, the frequency of the waves is approximately 0.1515 Hz, and the speed of the waves is approximately 7.272 m/s.
To determine the wavelength, frequency, and speed of the waves, we can use the formula:
v = λf
where:
v is the speed of the wave,
λ is the wavelength of the wave, and
f is the frequency of the wave.
Given:
Time for one complete vibration cycle (T) = 6.6 seconds
Distance between piers (d) = 24 meters
First, we need to find the frequency (f) of the waves:
Since the time for one complete vibration cycle is equal to the period (T), we have:
T = 1/f
Rearranging the equation, we find:
f = 1/T
Substituting the given value:
f = 1/6.6
f ≈ 0.1515 Hz (rounded to four decimal places)
Next, we can find the wavelength (λ) of the waves:
λ = 2d
Substituting the given value:
λ = 2 * 24
λ = 48 meters
Finally, we can find the speed (v) of the waves:
v = λf
Substituting the calculated values:
v = 48 * 0.1515
v ≈ 7.272 m/s (rounded to three decimal places)
Therefore, the wavelength of the waves is 48 meters, the frequency of the waves is approximately 0.1515 Hz, and the speed of the waves is approximately 7.272 m/s.
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Research shows that a speaker's voice quality can affect an audience's evaluation more than the content of the speaker's speech. Group of answer choices False True
True. Research indicates that a speaker's voice quality can have a significant impact on the audience's evaluation, often more than the content of the speaker's speech.
Voice quality includes factors such as tone, pitch, volume, clarity, and overall vocal delivery. The way a speaker uses their voice can influence how their message is perceived and received by the audience. Even if the content of a speech is well-crafted and informative, poor or ineffective voice quality may hinder the audience's engagement and evaluation of the speaker. Therefore, it is crucial for speakers to pay attention to their voice quality and develop effective vocal skills to enhance their overall communication and connection with the audience.
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PLEASE ANSWER
Make the same observation of wave speed - the speed of the crest moving from left to right across the screen. Does this ten-fold increase in frequency - from
about 0. 1 Hz to about 10 Hz - have any noticeable and appreciable effect upon the wave speed? Explain
your answer and discuss your observations
While the frequency of a wave does not directly affect its wave speed, it can influence other wave properties.
The frequency of a wave is defined as the number of complete cycles or oscillations it completes in one second. The wave speed, on the other hand, refers to the speed at which the wave propagates through a medium.
In general, the frequency of a wave does not have a direct impact on its wave speed. Wave speed is primarily determined by the properties of the medium through which the wave is traveling, such as its density and elasticity.
Therefore, the ten-fold increase in frequency from about 0.1 Hz to about 10 Hz would not have a noticeable or appreciable effect on the wave speed itself. The wave speed would remain relatively constant unless there are changes in the properties of the medium.
However, it is worth noting that changes in frequency can affect other wave characteristics, such as wavelength and period. The wavelength is the distance between two consecutive crests or troughs of a wave, while the period is the time it takes for one complete cycle of the wave. These quantities are related to frequency through mathematical relationships.
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A runner goes for a run. On the first part of the run, she runs 2 miles in 13 minutes. On the second part of the run, she runs 3 km in 20
minutes. What is her average speed?
To calculate the average speed, we need to convert the distances and times into a consistent unit. Let's convert the distance in kilometers to miles for the second part of the run.
1 kilometer is approximately equal to 0.62137 miles. Therefore, 3 km is approximately 1.86411 miles.
Now, let's calculate the total distance and total time for the entire run:
Total distance = 2 miles + 1.86411 miles = 3.86411 miles
Total time = 13 minutes + 20 minutes = 33 minutes
Average speed is calculated by dividing the total distance by the total time:
Average speed = Total distance / Total time = 3.86411 miles / 33 minutes
To convert the average speed to a more common unit, let's convert minutes to hours:
33 minutes is equal to 33/60 = 0.55 hours
Average speed = 3.86411 miles / 0.55 hours ≈ 7.02657 miles per hour
Therefore, the runner's average speed for the entire run is approximately 7.03 miles per hour.
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Steam burns are pretty dangerous because there's often a lot of
thermal energy in the steam. When the steam hits you, it is going to
transfer some of that energy to you, cooling the steam. If a 6.4 kg cloud of
steam at 150 degrees, hits you and cools to 100 degrees, What is the loss
of heat energy? (no scientific notation)
The loss of heat energy when a 6.4 kg cloud of steam at 150 degrees Celsius hits you and cools to 100 degrees Celsius is 13,440,000 Joules.
To calculate the heat energy loss, we can use the formula:
Q = mcΔT
Where Q represents heat energy, m is the mass of the steam cloud (6.4 kg), c is the specific heat capacity of water (4,186 J/kg°C), and ΔT is the change in temperature (150°C - 100°C = 50°C).
Plugging in the values, we have:
Q = (6.4 kg) × (4,186 J/kg°C) × (50°C)
Q = 13,440,000 Joules
Therefore, the loss of heat energy when the steam cools from 150°C to 100°C is 13,440,000 Joules.
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A web browser is open on yur screen. The lengh of the monitor is x+7. The area of the browser windw is 24 inches. The dimensions of the browser window are x-2 and x. Find the length of the browser window x. Part B. The browser covers 3/13 of the screen. What are the dimensions of the screen
The length of the browser window (x) is 6. The dimensions of the screen are approximately 3 inches (width) and 18/13 inches (height).
Let's solve the equations step by step:
Part A:
The area of the browser window is given by the equation:
(x - 2) * x = 24
Expanding the equation:
[tex]x^{2}[/tex] - 2x = 24
Rearranging the equation to standard quadratic form:
[tex]x^{2}[/tex] - 2x - 24 = 0
Factoring the quadratic equation:
(x - 6)(x + 4) = 0
Setting each factor to zero:
x - 6 = 0 or x + 4 = 0
Solving for x:
x = 6 or x = -4
Since the length of the monitor cannot be negative, we discard the solution x = -4.
Therefore, the length of the browser window (x) is 6.
Part B:
The dimensions of the screen can be calculated using the length of the monitor (x+7) and the coverage ratio of the browser window (3/13).
The width of the screen is given by:
Width = (3/13) * (x + 7)
The height of the screen is given by:
Height = (3/13) * (x)
Substituting the value of x = 6:
Width = (3/13) * (6 + 7) = (3/13) * 13 = 3
Height = (3/13) * 6 = 18/13
Therefore, the dimensions of the screen are approximately 3 inches (width) and 18/13 inches (height).
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Use the equation to answer the prompt.
A student claims that the equation models beta-minus decay because the atomic number of the nucleus decreases by one. Ir
one or two sentences, explain the error in the student's reasoning,
The error in the student's reasoning is that they have conflated the concept of atomic number with the process of beta-minus decay.
While it is true that the atomic number of the nucleus decreases by one in beta-minus decay, this alone does not accurately model the entire process. Beta-minus decay is a specific type of radioactive decay in which a neutron in the nucleus is converted into a proton, emitting an electron (beta particle) and an antineutrino. This conversion results in the increase of the atomic number by one, not the decrease.
Therefore, the equation representing beta-minus decay should show an increase in the atomic number, not a decrease. The student's claim overlooks the fundamental mechanism of beta-minus decay and misinterprets the change in atomic number, leading to an incorrect understanding of the process.
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A projectile is launched horizontally from a height of 8. 0 m. The projectile travels 6. 5 m before hitting the ground. The velocity of the projectile the moment it was launched, rounded to the nearest hundredth, is m/s.
The initial velocity of a projectile launched horizontally can be calculated using the equation of distance covered horizontally (x) = Initial velocity (u) Time of flight (t). The horizontal component of the initial velocity can be determined by x = u t, t = 1.63 s, x = 6.5 mu = x / t = 6.5 m / 1.63 su = 3.99 m/s 4.00 m/s.
The initial velocity of the projectile that was launched horizontally can be calculated using the equation below: Distance covered horizontally (x) = Initial velocity (u) × Time of flight (t) where, Time of flight (t) can be found using the formula below: t = [2 × vertical height (h)] / g where ,g is the acceleration due to gravity = 9.8 m/s².The vertical height (h) of the projectile is 8.0 m. So the time of flight of the projectile will bet = [2 × 8.0 m] / 9.8 m/s²t = 1.63 s Therefore, the horizontal component of the projectile’s initial velocity can be determined by: x = u × tt = 1.63 s, x = 6.5 mu = x / t = 6.5 m / 1.63 su = 3.99 m/s ≈ 4.00 m/s. So, the projectile was launched horizontally with a velocity of 4.00 m/s (rounded to the nearest hundredth).Content loaded: The term “content loaded” is used to indicate that the contents of a webpage or app have finished loading and are ready for viewing or use.
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Two rows of fluorescent lamps are installed in an office on the same branch circuit, with each row drawing 12.5 amperes. The source voltage is 277 volts, and the total line resistance of the circuit conductors is 0.5 Ω. The wire used has a constant (k) of 12.6. What is the percentage of voltage drop? (Round the FINAL answer to one decimal place.)
According to the solving the percentage of voltage drop is 2.8%
Let V = Source voltage
= 277 volts
Let R = Total line resistance of the circuit conductors
= 0.5 Ω
Let A = Each row drawing
= 12.5 amperes
Let k = 12.6
The voltage drop formula is given by:
Vdrop = kRA
Where; Vdrop = Voltage drop
= Constant of the wire
= Total line resistance
A = Load Current
Putting the given values in the voltage drop formula, we get;
Vdrop = 12.6 x 0.5 Ω x (12.5 + 12.5) amps
Vdrop = 12.6 x 0.5 Ω x 25 amps
Vdrop = 7.875 volts
Percentage of Voltage drop = (Vdrop / V) x 100%= (7.875 / 277) x 100%
Percentage of Voltage drop = 2.8427 % ≈ 2.8%
Therefore, the percentage of voltage drop is 2.8%.
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A man weighing 70 kg runs alongside railroad tracks with a
velocity of 18 km/h, and jumps into a car of weight 100 kg
standing on the tracks. Calculate the velocity with which the
car and man will start moving.
a 2.06 m/s
b 1.47 m/s
С
2.31 m/s
d 3.02 m/s
The velocity with which the car and man will start moving is d.) 3.02 m/s. Hence, option d) is the correct answer. The formula for the momentum is p= mv.
Initially, the momentum of the man is given by: mv = 70 kg × (18 km/h) × (1 h/3600 s) × (1000 m/1 km)
= 35/18 m/s × 70 kg
= 1225/18 kg m/s
The momentum of the car is given by: p = mv
= 0 kg × v
= 0
Since the total momentum before the man jumps into the car is zero and the total momentum after the man jumps into the car is conserved, the total momentum is given by: mv + mv' = 0
where v' is the velocity of the car and man after they combine. Rearranging the equation above gives: v' = -mv / m' where m is the mass of the man and m' is the combined mass of the car and man: v' = -70 kg × 35/18 m/s / (70 kg + 100 kg)
= -35/26 m/s
≈ -1.35 m/s
Note that the negative sign implies that the velocity of the man is opposite to that of the car. The magnitude of the velocity is obtained by taking the absolute value: v' = 35/26 m/s ≈ 1.35 m/s
Therefore, the velocity with which the car and man will start moving is 3.02 m/s (to two decimal places).
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The international astronomical union has identified 88 what?.
The International Astronomical Union (IAU) has identified 88 constellations.
A constellation is an area of the celestial sphere as defined by the International Astronomical Union (IAU).
There are 88 constellations, each with a particular area and a list of stars associated with it. The majority of constellations are named after ancient Greek and Roman mythological characters, with a few named after animals, scientific instruments, and seasonal objects like planets and the zodiac, as well as a handful named after navigational tools and historical figures. The concept of constellations dates back thousands of years, and their use in astronomy has allowed astronomers to create a map of the sky and chart the motions of celestial objects.
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Lexy throws a dart with an initial velocity of 25 m/s at an angle of 60° relative to the ground. What is the approximate vertical component of the initial velocity? 0. 5 m/s 0. 87 m/s 12. 5 m/s 21. 7 m/s.
The approximate vertical component of the initial velocity is 21.7 m/s.
option D.
What is the approximate vertical component of the initial velocity?The approximate vertical component of the initial velocity is calculated by applying the following equation as follows;
Mathematically, the formula vertical component of velocity is given as;
Vy = V sinθ
where;
V is the magnitude of the initial velocityVy is the vertical component of the velocityθ is the direction of the initial velocityThe approximate vertical component of the initial velocity is calculated as;
Vy = 25 m/s x sin (60)
Vy = 21.7 m/s
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A stevedore slides a crate along a dock with a 50 kg horizontal force of 175 N. The opposing force of friction is 120 N. If started from rest, what is the crates’s final velocity after 0.5s?
To determine the crate's final velocity after 0.5 seconds, we can use the concept of Newton's second law of motion, which states that the net force acting on an object is equal to its mass multiplied by its acceleration.
In this scenario, the stevedore applies a horizontal force of 175 N to move the crate along the dock. However, there is also an opposing force of friction acting in the opposite direction, which has a magnitude of 120 N. The net force is the difference between these two forces, so we can calculate it as follows:
Net force = Applied force - Frictional force
Net force = 175 N - 120 N
Net force = 55 N
Now, using Newton's second law of motion, we can determine the acceleration of the crate. Rearranging the equation, we have:
Net force = mass * acceleration
55 N = 50 kg * acceleration
Solving for acceleration:
acceleration = 55 N / 50 kg
acceleration = 1.1 m/s²
Since we know the initial velocity of the crate is zero (as it starts from rest), and we want to find the final velocity after 0.5 seconds, we can use the equation of motion:
final velocity = initial velocity + (acceleration * time)
Plugging in the values:
final velocity = 0 + (1.1 m/s² * 0.5 s)
final velocity = 0.55 m/s
Therefore, the crate's final velocity after 0.5 seconds is 0.55 m/s. This means that after being subjected to a 175 N force and experiencing 120 N of friction, the crate gains a velocity of 0.55 m/s in the direction of the applied force.
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A 0.12-meter-long electromagnetic (radar) wave is emitted by a weather station and re ected from a nearby thunderstorm. Determine the frequency of the radar wave.
A 0.12-meter-long electromagnetic (radar) wave is emitted by a weather station and reflected from a nearby thunderstorm. The frequency of the radar wave is 2.5 GHz.
To determine the frequency of the radar wave, we can use the wave equation:
v = λf
Where:
v is the speed of light in a vacuum (approximately 3.00 x 10⁸ meters per second)
λ is the wavelength of the radar wave
f is the frequency of the radar wave
Given:
Wavelength (λ) = 0.12 meters
f = v / λ
Substituting the given values:
f = (3.00 x 10⁸ meters per second) / (0.12 meters)
f ≈ 2.5 x 10⁹ Hz
Therefore, the frequency of the radar wave is approximately 2.5 x 10⁹ Hz (or 2.5 GHz).
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A boy ties a stone to the end of a string which he then whirls above his head round a circular path of radius 2 metre. If the stone makes 10 oscillations in 4 seconds, calculate the angular and linear speed of the stone.
The angular and linear speed are 5π rads/ seconds and 10π meter/ seconds.
How to calculate the angular and the linear speedIn order to calculate the angular speed of the boy, we will use the equation below.
w =2πn/ T
Where
radius is 2 meter
number of oscillation is 10.
time is 4 s
So, we have
w = 2π * 10/4
w = 5π rads/ seconds.
To calculate the linear speed.
v = r *w
v = 2 * 5π
v = 10π meter/ seconds
Therefore, the angular and linear speed are 5π rads/ seconds and 10π meter/ seconds.
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The electron and proton of a hydrogen atom are separated by a distance of approximately 5.3 x 10^-11m. Find the magnitude of the electric and gravitational force between the two particles.
The magnitude of the electric force is 8.21 × 10⁻⁸ N and the gravitational force is 3.61 × 10⁻⁸ N. The electric force acting between the electron and proton of hydrogen atom is given by: Coulomb's Law of electrostatics, F = 1 / 4πε₀ × q₁q₂ / r².
Given that, Distance between the electron and proton of a hydrogen atom, r = 5.3 × 10⁻¹¹m, Mass of an electron, m₁ = 9.1 × 10⁻³¹ kg, Mass of a proton, m₂ = 1.67 × 10⁻²⁷ kg, Charge of an electron, q₁ = -1.6 × 10⁻¹⁹ C, Charge of a proton, q₂ = +1.6 × 10⁻¹⁹ C.
Where,ε₀ = permittivity of free space = 8.854 × 10⁻¹² C²/N m²
F = 1 / 4π (8.854 × 10⁻¹²) × (1.6 × 10⁻¹⁹)² / (5.3 × 10⁻¹¹)²
F = 8.21 × 10⁻⁸ N
The gravitational force acting between the electron and proton of hydrogen atom is given by:
Newton's Law of gravitation, F = G × m₁m₂ / r², Where, G = gravitational constant = 6.67 × 10⁻¹¹ N m²/kg²
F = (6.67 × 10⁻¹¹) × (9.1 × 10⁻³¹) × (1.67 × 10⁻²⁷) / (5.3 × 10⁻¹¹)²
F = 3.61 × 10⁻⁸ N
Therefore, the magnitude of the electric force is 8.21 × 10⁻⁸ N and the gravitational force is 3.61 × 10⁻⁸ N.
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3. A grating with 1555 lines/cm is illuminated with light of wavelength 565 nm. What
is the highest-order number that can be observed with this grating? (Hint:
Remember that sin can never be greater than 1 for a diffraction grating. )
important!
The highest-order number that can be observed with this grating using diffraction formula is 1/1555.
It is determined using the formula for diffraction: mλ = d sinθ. Where m is the order number, λ is the wavelength of light, d is the grating spacing, and θ is the angle of diffraction. In this case, the grating has 1555 lines/cm, which means the grating spacing is 1/1555 cm.
To determine the highest-order number, calculate m × (565 × 10^-9 meters) = (1/1555 cm) × sinθ, where θ must be less than or equal to 90 degrees to satisfy sinθ ≤ 1. Given the wavelength of light as 565 nm (or 565 × 10^-9 meters), we can proceed with the calculation. Since sinθ ≤ 1, the highest-order number (m) can be determined by substituting θ = 90 degrees into the equation: m = (1/1555 cm) × sin(90 degrees).
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an electric circuit contains a battery and a motor. what energy transformation occurs when the motor runs?
When a motor runs in an electric circuit, the primary energy transformation that takes place is the conversion of electrical energy into mechanical energy. This conversion is made possible by the interaction of electromagnetic forces within the motor.
Initially, the battery in the circuit supplies electrical energy to the motor. The electrical energy is in the form of a flow of electrons through the wires, creating an electric current. This current is directed through the motor's coils, which are usually made of conducting materials, such as copper wire, wrapped around a core.
As the electric current passes through the coils, it generates a magnetic field around them due to the principles of electromagnetism. The magnetic field interacts with the permanent magnets or electromagnets within the motor, resulting in a force that causes the motor's rotor (the moving part) to rotate.
The rotation of the rotor leads to the mechanical energy transformation. The electrical energy provided by the battery is converted into kinetic energy as the motor's shaft starts to turn. This kinetic energy can be harnessed to perform useful work, such as driving a fan, operating machinery, or propelling a vehicle.
In summary, the energy transformation that occurs when a motor runs in an electric circuit is the conversion of electrical energy into mechanical kinetic energy. This transformation enables the motor to perform various tasks and is fundamental to the operation of numerous devices and systems in our daily lives.
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A 20. Kilogram rock is lifted 7. 0 meters above the ground. What is the gravitational
potential energy of the rock?
The gravitational potential energy of the rock is 1,372 Joules.
The gravitational potential energy (PE) of an object can be calculated using the formula:
PE = m * g * h, where:
m is the mass of the object,
g is the acceleration due to gravity, and
h is the height or distance above the reference point.
In this case, the mass of the rock (m) is 20 kilograms, and the height (h) is 7.0 meters.
The acceleration due to gravity (g) is approximately 9.8 m/s².
Now we can calculate the gravitational potential energy:
PE = 20 kg * 9.8 m/s² * 7.0 m
PE = 1,372 Joules
Therefore, the gravitational potential energy of the rock is 1,372 Joules.
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A green laser pointer has a wavelength of 532 nanometers. Using the wave equation, what is the frequency of the light from the laser pointer?
1. 77 x 10^5 Hz
1. 88 x 10^14 Hz
5. 64 x 10^14 Hz
1. 60 x 10^4 Hz
(If you want to be in a physics B ig gc please cmmt)
The frequency of the light from the green laser pointer is [tex]5.64 x 10^14 Hz[/tex]. The correct option is C [tex]5.64 x 10^14 Hz[/tex].
The wave equation can be used to calculate the frequency of the light from a green laser pointer with a wavelength of 532 nanometers.
The wave equation is given by the formula: v = λfwhere v is the velocity of the wave, λ is the wavelength of the wave, and f is the frequency of the wave.
Rearranging the formula to solve for frequency: f = v/λwhere f is the frequency of the wave, v is the velocity of the wave, and λ is the wavelength of the wave. Since light travels at a constant speed in a vacuum (c), we can use this value for the velocity: v = c = 3.00 x 10^8 m/s (speed of light in vacuum)
To use this value, we need to convert the wavelength of the laser pointer from nanometers to meters.1 nanometer = 1 x 10^-9 meters532 nanometers = 532 x 10^-9 meters Substituting the values into the formula: f = v/λf = (3.00 x 10^8 m/s)/(532 x 10^-9 m)f = 5.64 x 10^14 Hz.
Therefore, the frequency of the light from the green laser pointer is 5.64 x 10^14 Hz. The correct option is 5.64 x 10^14 Hz.
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The water in the river moves with the speed 0.523 km/h. Alice and Bob can swim with the speed 2.62 km/h with respect to the water. They want to get from point A on one bank of the river to point B directly across on the other bank. Alice swims along the straight line AB, while Bob swims with a velocity perpendicular to the river and lets the flow take him some distance downstream. After that, he walks to point B along the river. What is the speed of his walk if he reaches point B at the same time as Alice
Alice and Bob's swimming speeds with respect to the water are 2.62 km/h each. Let Alice swim across the river straight from A to B while Bob swims perpendicular to the river and is carried some distance downstream by the flow.
Let's consider the distance Alice swims from A to B to be "d," which is the same as the distance Bob walks along the river from the point where he lands to B. Let the time taken by Alice be "t" (hours) to swim across the river straight from A to B, and let the distance Bob is carried by the river be "x."
Let's take "v" as the walking speed of Bob (km/h).Since Alice's and Bob's arrival time is the same at B, d/2.62 = (d-x)/(2.62)² + (x² + d²)¹/² / 0.523 ...(1) [Applying the Pythagorean theorem in the triangle ABC in the given diagram.]
d/2.62 = (d-x)/0.2734 + (x² + d²)¹/² / 0.523 ...(2) [Squaring both sides of (1)]Now, equating (1) and (2) and solving for "x," we have: x = 0.6 d
Substituting this value of "x" in (1), we get: d/2.62 = (0.4 d)/(2.62)² + (d² + 0.36 d²)¹/² / 0.523 ...(3)Substituting the values in equation (3), we get:0.38 d = 2.38d = 6.26 km
Therefore, Alice's time to swim across the river straight from A to B is: d/2.62 = 2.39 hours Now, substituting the value of "d" in (1), we have: v = 0.4×6.26/0.39 = 6.44 km/h Therefore, the speed of Bob's walk to reach point B is 6.44 km/h if he reaches point B at the same time as Alice.
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Josh is playing pool. During his shot, an orange billiard ball with a momentum of 135 g · m/s hits a green billiard ball at rest. After the collision, the orange billiard ball continues in the same direction with a momentum of 60 g · m/s. What is the momentum of the green ball right after the collision?
To solve this problem, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision should be equal to the total momentum after the collision, assuming no external forces are acting on the system.
Let's denote the momentum of the orange ball before the collision as p1, and the momentum of the green ball after the collision as p2.
Given:
Initial momentum of the orange ball (p1) = 135 g · m/s
Final momentum of the orange ball (p1') = 60 g · m/s
Momentum of the green ball after the collision (p2) = ?
Since momentum is a vector quantity, we need to consider both the magnitude and direction. In this case, the orange ball continues in the same direction after the collision, so the magnitude of its momentum decreases from 135 g · m/s to 60 g · m/s.
Using the principle of conservation of momentum:
p1 + 0 = p1' + p2
Substituting the given values:
135 g · m/s + 0 = 60 g · m/s + p2
Simplifying the equation:
p2 = 135 g · m/s - 60 g · m/s
p2 = 75 g · m/s
Now, we need to convert the momentum of the green ball from grams to kilograms:
1 g = 0.001 kg
p2 = 75 g · m/s * 0.001 kg/g
p2 = 0.075 kg · m/s
Therefore, the momentum of the green ball right after the collision is 0.075 kg · m/s.
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This illustration shows a map of land and water in a certain area. Students in that area measure the air temperature during the day and notice that the air over the land is much warmer than the air over the water. During the day, the students most likely observed the wind blowing in which direction? OPTIONS South to north North to south West to east East to west
Based on the observation that the air over the land is much warmer than the air over the water during the day, the students most likely observed the wind blowing from the water towards the land.
The movement of air from the water to the land is known as a sea breeze. During the day, the land heats up more quickly than the water due to differences in their heat capacities. As a result, the air over the land becomes warmer and rises, creating a lower pressure area. The cooler air over the water, which has higher pressure, then moves towards the land to replace the rising warm air, resulting in a wind blowing from the water to the land. Therefore, the wind is most likely blowing from the east to the west in this scenario.
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An elastic wire expands by 2cm when load of 40g hangs from it. What additional load will be required to cause a further extension of 4cm
What is the energy of a photon with a frequency of 1. 7 × 1017 Hz? Planck’s constant is 6. 63 × 10–34 J•s. 1. 1 × 10–17 J 1. 1 × 10–16 J 8. 3 × 10–16 J 8. 3 × 10–15 J.
The energy of the photon is determined as 1.1 x 10⁻¹⁶ J.
What is the energy of the photon?The energy of the photon is calculated by applying the following formula as follows;
E = hf
where;
h is the Planck's constantf is the frequency of the photonThe given parameters include;
frequency of the photon = 1. 7 × 10¹⁷ Hz
Planck’s constant is 6. 63 × 10⁻³⁴ J•s
The energy of the photon is calculated as follows;
E = 6. 63 × 10⁻³⁴ J•s x 1. 7 × 10¹⁷ Hz
E = 1.1 x 10⁻¹⁶ J
Thus, the energy of the photon is determined as 1.1 x 10⁻¹⁶ J.
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The specific heat of a solid Y is 11. 5 cal/g°C. A sample of this solid at
135 K is heated to 260 K. The solid absorbs 7. 90 kcals. What is the
sample of solid in grams?
The mass of the sample of solid Y is approximately 56.6 grams. "Solid" is a term used to describe a state of matter. In the context of materials, a solid refers to a substance that has a definite shape and volume.
To determine the mass of the sample of solid Y, we can use the equation:
Q = m * C * ΔT
Where:
Q is the heat absorbed (in calories)
m is the mass of the sample (in grams)
C is the specific heat capacity of the solid Y (in cal/g°C)
ΔT is the change in temperature (in °C)
Given:
Specific heat of solid Y (C) = 11.5 cal/g°C
Initial temperature (T₁) = 135 K
Final temperature (T₂) = 260 K
Heat absorbed (Q) = 7.90 kcals = 7.90 * 1000 cal
First, we need to convert the temperatures from Kelvin to Celsius:
T₁ = 135 K - 273.15 = -138.15 °C
T₂ = 260 K - 273.15 = -13.15 °C
Next, we can calculate the change in temperature:
ΔT = T₂ - T₁ = (-13.15 °C) - (-138.15 °C) = 125 °C
Now, we can substitute the values into the equation and solve for the mass (m):
Q = m * C * ΔT
7.90 * 1000 cal = m * 11.5 cal/g°C * 125 °C
Divide both sides of the equation by (11.5 * 125):
7.90 * 1000 cal / (11.5 cal/g°C * 125 °C) = m
m ≈ 56.6 grams
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Suppose the nozzle of the print head in an inkjet printer ejected ink droplets with a higher speed than normal. How would the strength of the field between the deflection plates need to be adjusted to accommodate this higher speed in order to ensure that the ink goes into the gutter?.
If the nozzle of the print head in an inkjet printer ejected ink droplets with a higher speed than normal, the strength of the field between the deflection plates would need to be adjusted to accommodate this higher speed to ensure that the ink goes into the gutter.
Inkjet printers utilize deflection plates to change the path of the ink droplets. In a situation where the nozzle of the print head ejects ink droplets at a higher velocity than normal, the deflection plates would require a stronger electric field to redirect the ink droplets to the gutter.
The electric field's strength applied to the deflection plates determines the ink droplets' direction, and the droplets can be directed to the print paper or gutter. The strength of the electric field is determined by the deflection plate's width and the voltage applied to it.
The force applied on the ink droplet depends on the charge of the droplet and the strength of the electric field applied to the deflection plates. The strength of the electric field must be adjusted to accommodate the droplets' increased velocity, and this would ensure that the ink goes into the gutter.
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Triangle FGH with vertices F(6, 6), G(8,8),
and H(8,3);
(a) Reflection: in the line. R = 5
(b) Translation: (x, y) - (x - 7, y-9)
The final image of the original triangle after reflection in the line R=5 and translation by (7,-9) is the triangle F"G"H" with vertices F"(11,-3), G"(9,-1), and H"(9,-12).
(a) Reflection is a transformation in which a shape is mirrored, or flipped over a line called the reflection line. In this problem, the reflection is to take place in the line, R = 5.
This line is vertical; therefore, it passes through points (5,0), (5,1), (5,2), and so on.
The reflection image of point F on the line R=5 is point F', where FF' is perpendicular to line R.
FF' intersects line R at point P, which is equidistant from F and F'.
Hence, the reflection image of F(6,6) on R=5 is F'(4,6).
Similarly, the reflection image of point G(8,8) on line R=5 is G'(2,8), and that of H(8,3) is H'(2,-3).
Therefore, the reflected triangle is F'G'H' with vertices F'(4,6), G'(2,8), and H'(2,-3).
(b) Translation: (x, y) - (x - 7, y-9)
Translation involves moving a shape to a new position without changing its size, shape, or orientation. The new position of each point is obtained by adding the translation vector (7,-9) to the coordinates of the corresponding point. The image of F'(4,6) after the translation is F"(11,-3).
Similarly, G'(2,8) maps to G"(9,-1), and H'(2,-3) maps to H"(9,-12).
The translated triangle is F"G"H" with vertices F"(11,-3), G"(9,-1), and H"(9,-12).
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PLEASE USE KINEMATIC EQUATION!
You are asked to do an experiment to measure g. You set up a device that drops a metal ball from
rest from a height of 1.650 m. Using an accurate timing device that detects the release of the ball
and its landing on the floor, you measure the average time of the falling ball to be 0.585s.
a. What do you measure the value of g as?
b. Write an explanation as to the error from the accepted value of 10 m/s^2 (or 9.8)
1. The value of g measured from the experiment is approximately 5.646 m/s^2.
How to solve for the experimentTo determine the value of acceleration due to gravity (g) using the given information, we can utilize the kinematic equation for the motion of a falling object:
h = 0.5 * g * t^2
where:
h is the height (1.650 m),
g is the acceleration due to gravity (what we want to find), and
t is the time taken (0.585 s).
a) To find the value of g, we rearrange the equation to solve for g:
g = 2h / t^2
Substituting the given values:
g = 2 * 1.650 m / (0.585 s)^2
g = 5.646 m/s^2
Therefore, the value of g measured from the experiment is approximately 5.646 m/s^2.
2. Air resistance: In real-world scenarios, the presence of air resistance can affect the motion of falling objects. The simplified equation used assumes no air resistance, which may result in a deviation from the accepted value.
Imperfect timing device: The accuracy of the timing device used in the experiment can introduce errors. Even small errors in measuring the time can lead to significant differences in the calculated value of g.
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A scientist does an experiment. The results of the experiment disagree with a major scientific theory.
What should the scientist do?
When the results of an experiment disagree with a major scientific theory, it is important for the scientist to follow a systematic and rigorous approach to understand and address the discrepancy. Here are some steps the scientist should consider:
1. Verify the experiment: Ensure that the experiment was conducted accurately and all variables were controlled properly. Check for any errors or potential sources of bias in the experimental setup or data collection process.
2. Repeat the experiment: Replicate the experiment multiple times to confirm the results and rule out any chance occurrences or anomalies. If the discrepancy persists, it strengthens the need for further investigation.
3. Review the existing theory: Thoroughly examine the major scientific theory that is being contradicted. Consider the strength of the theory, its supporting evidence, and its applicability to the specific experimental context.
4. Analyze the results: Conduct a detailed analysis of the experimental data, taking into account any potential confounding factors or alternative explanations. Look for patterns, correlations, and inconsistencies that could shed light on the discrepancy.
5. Seek peer review and collaboration: Engage with the scientific community by presenting the findings at conferences, publishing in reputable journals, and seeking feedback from peers. Collaborating with other scientists who have expertise in the field can provide valuable insights and guidance.
6. Conduct further research: Design follow-up experiments or studies to gather additional data and investigate the underlying mechanisms causing the discrepancy. Consider incorporating different methodologies or approaches to gain a more comprehensive understanding.
7. Refine or propose new theories: If the discrepancy persists and is supported by robust evidence, it may be necessary to refine or propose new theories that can better explain the experimental results. This could involve modifying existing theories or developing entirely new frameworks.
In summary, when experimental results disagree with a major scientific theory, it is crucial for the scientist to carefully evaluate and investigate the discrepancy, seek feedback from the scientific community, and consider the implications for existing theories. This iterative process contributes to the advancement of scientific knowledge and understanding.
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