The only like terms are StartFraction 2 x over 5 EndFraction and StartFraction x over 3 EndFraction.Like terms are those terms that have the same variables and the same exponent in them, and they can be combined or added.
Like terms are those terms that have the same variables and the same exponent in them, and they can be combined or added. From the given algebraic expressions, the like terms are:StartFraction 2 x over 5 EndFraction and StartFraction 2 x over 5 EndFraction2.2 and 5.2yStartFraction x over 3 EndFraction and StartFraction 2 x over 5 EndFraction
Given algebraic expression isStart Fraction 2 x over 5 EndFraction - 5.2y2. 2StartFraction x over 3 End FractionStart Fraction 2 x over 5 End Fraction and -5.2y are not like terms because the variable x is in different forms and y is also in different forms.So, the only like terms are StartFraction 2 x over 5 EndFraction and StartFraction x over 3 EndFraction.
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A 2. 0 kg box is released from rest at a height yo = 0. 25 m on a frictionless ramp. The box slides from the
ramp onto a rough horizontal surface with a friction coefficient puse = 0. 50.
m
Уо
How far does the box slide along the rough surface?
The box slides along the rough surface for a distance of d meters. At the bottom of the ramp, the box has zero potential energy and maximum kinetic energy.
To determine the distance the box slides along the rough surface, we need to consider the conservation of energy and the effects of friction.
Initially, the box is at a height of 0.25 m and has potential energy given by mgyo, where m is the mass of the box (2.0 kg) and yo is the initial height (0.25 m). As the box slides down the frictionless ramp, the potential energy is converted into kinetic energy. At the bottom of the ramp, the box has zero potential energy and maximum kinetic energy.
Upon reaching the rough horizontal surface, the box encounters friction. The work done by friction results in the conversion of kinetic energy into thermal energy, reducing the box's speed.
To calculate the distance the box slides on the rough surface, we need to determine the work done by friction. The work done by friction is given by the equation work = force × distance. The force of friction can be calculated using the equation force = friction coefficient × normal force, where the normal force is equal to the weight of the box (mg).
Using the given friction coefficient (μ = 0.50) and the mass of the box (m = 2.0 kg), we can calculate the force of friction. Once we have the force of friction, we can calculate the work done by friction.
The work done by friction is equal to the change in kinetic energy of the box. We can equate this work to the initial kinetic energy and solve for the distance traveled (d). The initial kinetic energy is given by (1/2)mv², where v is the velocity of the box at the bottom of the ramp.
By solving the equation for the work done by friction and equating it to the initial kinetic energy, we can determine the distance the box slides along the rough surface (d).
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A gas can is shaped like a cylinder. It has a height of 14 inches and a base diameter of 8 inches. What is the volume of the gas can? Round to the nearest tenth
The volume of the gas can is approximately 703.36 cubic inches when rounded to the nearest tenth.
To find the volume of the gas can, we need to use the formula for the volume of a cylinder, which is given by:
V = π * r^2 * h
where V is the volume, r is the radius of the base, and h is the height of the cylinder.
Given that the base diameter of the gas can is 8 inches, we can calculate the radius by dividing the diameter by 2:
r = 8 / 2 = 4 inches
The height of the gas can is given as 14 inches.
Now, we can substitute the values into the formula to calculate the volume:
V = π * (4^2) * 14
V = π * 16 * 14
V = 224π
To round the volume to the nearest tenth, we need to substitute the value of π with its approximation, which is commonly taken as 3.14:
V ≈ 224 * 3.14
V ≈ 703.36 cubic inches
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Mr dlamini transport people between Butterworth and East London using a bus with
has a capacity of 100 people
Mr Dlamini will earn R960 for a full bus from Butterworth to East London. The distance between Butterworth and East London is 100 kilometres.
Mr Dlamini transports people between Butterworth and East London using a bus with a capacity of 100 people. The transport charge starts with a minimum charge of R8 and thereafter it is increased by R2 for each kilometre.
On a particular day, the bus was full with passengers from Butterworth. In each and every kilometre, there was a passenger getting off while no new passenger entered the bus.
The distance between Butterworth and East London is 100 kilometres. Therefore, the total transport charge for the journey is 100 x (R8 + R2/km) = R960.
It is important to note that this is just the transport charge. Mr Dlamini may also incur other costs, such as fuel, maintenance, and insurance. Therefore, his actual profit may be less than R960.
Here is a table showing the transport charge for each kilometre:
Kilometers | Transport charge
------- | --------
0 | R8
1 | R10
2 | R12
... | ...
100 | R960
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A certain game involves tossing 3 fair coins, and it pays 12 cents for 3 heads, 7 cents for 2 heads, and 4 cents for 1 head. Is 7 cents a fair price to pay to play this game? That is, does the 7 cents cost to play make the game fair?
The expected payout is 5.625 cents, and the cost to play the game is 7 cents, it can be concluded that paying 7 cents to play this game is not fair. The expected payout is lower than the cost, resulting in a disadvantage for the player.
In this game, tossing 3 fair coins results in different payouts for the number of heads obtained. The payouts are 12 cents for 3 heads, 7 cents for 2 heads, and 4 cents for 1 head. The question is whether paying 7 cents to play this game is fair.
To determine if the game is fair, we need to compare the expected payout with the cost to play. Let's calculate the probabilities and payouts for each outcome. There are a total of 8 possible outcomes when tossing 3 coins: HHH, HHT, HTH, THH, TTH, THT, HTT, and TTT (H denotes a head, and T denotes a tail).
The probability of getting 3 heads is 1/8, so the payout for this outcome is 12 cents. The probability of getting 2 heads is 3/8 (HHH, HHT, HTH), so the payout for this outcome is 7 cents. The probability of getting 1 head is also 3/8 (TTH, THT, HTT), resulting in a payout of 4 cents. The probability of getting 0 heads (3 tails) is 1/8, resulting in a payout of 0 cents.
Now, let's calculate the expected payout by multiplying each outcome's probability with its corresponding payout and summing them up:
Expected payout = (1/8 * 12) + (3/8 * 7) + (3/8 * 4) + (1/8 * 0) = 1.5 + 2.625 + 1.5 + 0 = 5.625 cents.
Since the expected payout is 5.625 cents, and the cost to play the game is 7 cents, it can be concluded that paying 7 cents to play this game is not fair. The expected payout is lower than the cost, resulting in a disadvantage for the player.
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Jordan rides a bike at 8&2/3 mph. How many miles will he bike in 3 hours and 6 mins?
The distance Jordan will bike in 3 hours and 6 minutes is approximately 28.33 miles.
In order to find the distance that Jordan will bike in 3 hours and 6 minutes, we need to use the formula;distance = speed × timeGiven that Jordan rides a bike at 8&2/3 mph, we convert the speed into an improper fraction.8&2/3 = 8 + 2/3 = 24/3 + 2/3 = 26/3 mphSubstituting the values given into the formula;distance = 26/3 × 3.1 (3 hours and 6 minutes converted to hours)= 26/3 × 3 1/17= 26/3 × (52/17)= 28.33 miles (approx.)
Therefore, Jordan will bike approximately 28.33 miles in 3 hours and 6 minutes.
Given that Jordan rides a bike at 8&2/3 mph, we can calculate how many miles he will bike in 3 hours and 6 minutes by using the formula;distance = speed × timeThe first step is to convert the speed given into an improper fraction.8&2/3 = 8 + 2/3 = 24/3 + 2/3 = 26/3 mphTo find the distance that Jordan will bike in 3 hours and 6 minutes, we need to convert the time given into hours.3 hours and 6 minutes is equivalent to 3.1 hours (We divide the minutes by 60 to convert them into hours; 6/60 = 0.1).Substituting the values given into the formula;distance = 26/3 × 3.1 (3 hours and 6 minutes converted to hours)=[tex]26/3 × 3 1/17= 26/3 × (52/17)= 28.33 miles[/tex](approx.)
Therefore, Jordan will bike approximately 28.33 miles in 3 hours and 6 minutes.
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I GIVE BRAINIEST
Does the equation y-250x=500 represent the same relationship between the distance from the start of the trail and the elevation? Explain your reasoning pls
Yes, the equation y - 250x = 500 represents the same relationship between the distance from the start of the trail and the elevation.
The given equation is y - 250x = 500.
The above equation is of the form y = mx + c, where m = slope of the line and c = y-intercept of the line.
Let us convert the given equation into the form y = mx + c, y - 250x = 500, y = 250x + 500. Now, we can see that this equation is of the form y = mx + c, where m = 250, which means that the slope of the line is 250 and the value of y-intercept is 500.
Thus, the equation y - 250x = 500 represents the relationship between the distance from the start of the trail and the elevation.
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A recipe has a ratio of 1 1/2 cups of cheese to 6 ounces of pasta based on this recipe which statement is true
The statement that holds true is that for every 1 1/2 cups of cheese used, there should be 6 ounces of pasta.
Based on the given ratio of 1 1/2 cups of cheese to 6 ounces of pasta in the recipe, the following statement is true:
For every 1 1/2 cups of cheese used, there should be 6 ounces of pasta.
The ratio indicates the proportion or relationship between the amounts of cheese and pasta in the recipe. In this case, for each 1 1/2 cups of cheese, the recipe calls for 6 ounces of pasta. This means that the quantities of cheese and pasta are in a consistent and proportional relationship.
To illustrate this further, if you were to double the amount of cheese used in the recipe, you would also need to double the amount of pasta. For example, if you use 3 cups of cheese, you would need 12 ounces of pasta (2 times 6 ounces).
Therefore, based on the given ratio, the statement that holds true is that for every 1 1/2 cups of cheese used, there should be 6 ounces of pasta.
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Patty is ordering vests for her scout troop to wear in the Veterans Day parade. She ordered 12 vests from the Festive Features clothing shop. Since this was a bulk order, Festive Features reduced the price of each vest by $6. The total came to $132. Which equation can you use to find the amount, v, Festive Features normally charges for a vest?
6v–12=132
12(v–6)=132
12v–6=132
6(v–12)=132
The equation that can be used to find the amount Festive Features normally charges for a vest is 12(v-6)=132.
Let's break down the equation step by step. The total amount Patty paid for the 12 vests after the discount was $132. This means that the reduced price of each vest is $132 divided by 12, which is $11.
Now, let's consider the original price Festive Features charges for a vest, denoted as "v." Since the price was reduced by $6 for the bulk order, the reduced price is v - $6. According to the information given, the reduced price of each vest is $11.
Therefore, we can set up the equation: 12(v - 6) = 132. Here, 12 represents the number of vests Patty ordered, and (v - 6) represents the reduced price of each vest. By multiplying the reduced price by the quantity, we should get the total amount Patty paid, which is $132.
Simplifying the equation: 12v - 72 = 132. Adding 72 to both sides of the equation gives us 12v = 204. Finally, dividing both sides by 12, we find that v = 17. Hence, Festive Features normally charges $17 for a vest before the bulk order discount.
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Thomas drew a line of best fit for the scatter plot as shown.
120
103
96
34
72
60
36
24
0
10
12
16
19 20
Enter an equation for the line of best fit in slope-intercept form.
The line of best fit equation in slope-intercept form is y =
The line of best fit equation in slope-intercept form is y = -4x + 120.
The line of best fit is used in mathematics, it is also known as a trend line or regression line. It is a straight line that is most likely to represent the given data and is used to summarize or describe a relationship between two variables.In order to get the equation of the line of best fit in slope-intercept form from the given data, we need to calculate the slope and the y-intercept.Using the given data, we can plot a scatter plot as shown below: scatter plot.
Therefore, we can see that there is a negative correlation between the variables. This means that as one variable increases, the other variable decreases.
Thus, the slope of the line of best fit can be calculated as:
Slope = rise/run = Δy/Δx
where Δy is the change in y (vertical change) and Δx is the change in x (horizontal change).
Let's choose two points on the line of best fit: (0,120) and (30,0).
Then, we can calculate the slope as:
Slope = Δy/Δx = (0 - 120)/(30 - 0) = -4
Therefore, the slope of the line of best fit is -4.
Now, let's find the y-intercept by using one point on the line of best fit: (0,120).
Then, we can use the point-slope form of a line:
y - y1 = m(x - x1)
where m is the slope and (x1, y1) is a point on the line of best fit.
Substituting
m = -4, x1 = 0, and y1 = 120
y - 120 = -4(x - 0)y - 120 = -4xy = -4x + 120
Thus, the equation of the line of best fit in slope-intercept form is: y = -4x + 120.
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Say that Australia has a working population of 11,565,470 people, and that the average salary is $26,450 annually. How much tax revenue would Australia generate each year by instituting a 31. 4% income tax? a. $81,528,467,671 b. $90,224,333,274 c. $96,054,697,991 d. $209,851,983,509.
The tax revenue that Australia generate each year by instituting a income tax is $96,054,697,991. The Option C.
How much tax revenue would Australia generate each year by instituting a 31.4% income tax?
Tax revenue is the income that is collected by governments through taxation. To know the tax revenue, we will multiply the working population by the average salary and then multiply that by the tax rate.
Tax Revenue = (Working population) * (Average salary) * (Tax rate)
Tax Revenue = 11,565,470 * $26,450 * 0.314
Tax Revenue = $96,054,697,991
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LAST SEMESTER
Lelia and Saige are selling pies for a school fundraiser. Customers can
buy cherry pies and pumpkin pies.
Lelia sold 12 cherry pies and 11 pumpkin pies for a total of $227.
Saige sold 2 cherry pies and 3 pumpkin pies for a total of $53.
What is the cost each of one cherry pie and one pumpkin pie?
The cost of one cherry pie is $7 and the cost of one pumpkin pie is $13. To find the cost of each cherry pie and each pumpkin pie, we can set up a system of equations based on the given information. Let's represent the cost of a cherry pie as 'c' and the cost of a pumpkin pie as 'p'.
From Lelia's sales, we can write the equation: 12c + 11p = 227.
From Saige's sales, we can write the equation: 2c + 3p = 53.
To solve this system of equations, we can use various methods such as substitution or elimination. Let's use the elimination method in this case.
Multiplying the second equation by 6 to make the coefficients of 'c' the same in both equations, we get:
12c + 18p = 318.
Now, subtracting the first equation from this new equation, we have:
(12c + 18p) - (12c + 11p) = 318 - 227,
7p = 91.
Dividing both sides by 7, we find p = 13.
Substituting this value of p back into either of the original equations, we can solve for c. Let's use the first equation:
12c + 11(13) = 227,
12c + 143 = 227,
12c = 227 - 143,
12c = 84,
c = 7.
Therefore, the cost of one cherry pie is $7 and the cost of one pumpkin pie is $13.
In conclusion, based on the given information and by setting up a system of equations, we found that one cherry pie costs $7 and one pumpkin pie costs $13.
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the value of a polynomial is 0 when x=5 which expression must be a factor of the polynomial
If the value of a polynomial is 0 when x=5, then (x-5) must be a factor of the polynomial.
A polynomial is a mathematical expression consisting of variables (or indeterminates) and coefficients, combined using addition, subtraction, and multiplication operations.
Polynomials are widely used in mathematics and various fields such as physics, engineering, computer science, and economics. They play a crucial role in solving equations, interpolation, approximation, and modeling various phenomena. Polynomial equations are also studied extensively in algebra, and techniques like factoring, long division, synthetic division, and the quadratic formula are used to analyze and solve them.
Given that the value of a polynomial is 0 when x=5.
To find the expression which must be a factor of the polynomial we can use the factor theorem which states that:
If x-a is a factor of polynomial f(x), then f(a) = 0.So, if the value of a polynomial is 0 when x=5, then (x-5) must be a factor of the polynomial.
Hence, the required expression which must be a factor of the polynomial is (x - 5).
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Susie spent $4. 57 on color and black-and-white copies for her project. She made 7 more
black-and-white copies than color copies. If color copies cost $0. 44 per page and black-and-
white copies cost $0. 07 per page, how many color copies did she make?
If Susie spent $4. 57 on color and "black-white" copies for her project, then she made 8 color-copies.
Let us assume that Susie made "x" "color-copies",
The cost of each color copy is $0.44, so, total cost of color copies would be = 0.44x,
She made 7 more black-and-white copies than color copies, which means she made (x + 7) black-and-white copies.
The cost of each black-and-white copy is $0.07, so the total cost of black-and-white copies would be = 0.07(x + 7).
According to the information, Susie spent a total-amount of $4.57 on both color and black-and-white copies, which can be represented in equation form as :
So, 0.44x + 0.07(x + 7) = 4.57
0.44x + 0.07x + 0.49 = 4.57
0.51x + 0.49 = 4.57
0.51x = 4.57 - 0.49
0.51x = 4.08
x = 4.08 / 0.51
x = 8
Therefore, Susie made 8 color-copies for her project.
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Sheri bought flowers for centerpieces for a party. Which estimation strategies could she use to find the gratuity for the florist quickly?
To find the gratuity for the florist quickly, Sheri could use estimation strategies. Two estimation strategies that Sheri could use are the front-end estimation method and the rounding method. Using these methods, Sheri can quickly find an estimate for the gratuity amount without having to calculate the exact total amount.
Sheri can use the front-end estimation method to find the gratuity for the florist quickly. In this method, she would look at the front digits of the total amount. For example, if the total amount is $47.25, she would look at the front digits 47. Then she can estimate the gratuity amount by multiplying 47 by a percentage. For example, if she wants to tip 20%, she can estimate the gratuity by multiplying 47 by 0.20 to get $9.40. This would give her an estimate for the gratuity amount.
To find the gratuity for the florist quickly, Sheri could use estimation strategies. Two estimation strategies that Sheri could use are the front-end estimation method and the rounding method. Using these methods, Sheri can quickly find an estimate for the gratuity amount without having to calculate the exact total amount. The front-end estimation method involves looking at the front digits of the total amount. For example, if the total amount is $47.25, she would look at the front digits 47. Then she can estimate the gratuity amount by multiplying 47 by a percentage. For example, if she wants to tip 20%, she can estimate the gratuity by multiplying 47 by 0.20 to get $9.40. This would give her an estimate for the gratuity amount.In conclusion, Sheri can use the front-end estimation method or the rounding method to estimate the gratuity for the florist quickly. These methods can help her find an estimate without having to calculate the exact total amount.
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Construction projects often use the Pythagorean Theorem. If you are building a sloped roof and you
know the height of the roof and the length for it to cover, you can use the Pythagorean Theorem to find
the diagonal length of the roof's slope.
You can use this information to calculate the area of the roof that you would need to shingle.
BREATHE
DEFEND
SEAL
The roof has a vertical height of 8 feet. The house has a width of 20 feet.
What is the diagonal length of the roof top? Round your answer to the nearest whole number.
feet
8 feet
Diagonal Length
20 feet
30 feet
The horizontal length of the roof is 30 feet.
What is the total area of the roof that will need shingles?
square feet
The total area of the roof that will need shingles is 660 square feet.
Construction projects often use the Pythagorean Theorem.
If you are building a sloped roof and you know the height of the roof and the length for it to cover, you can use the Pythagorean Theorem to find the diagonal length of the roof's slope.
In order to find the diagonal length of the roof's slope, we must use the
Pythagorean Theorem which is: a² + b² = c²,
where a and b are the sides of a right triangle, and c is the hypotenuse.
Given that the roof has a vertical height of 8 feet and the house has a width of 20 feet, we need to calculate the diagonal length of the roof top.
We can use the Pythagorean Theorem to find the length of the roof's diagonal, which is represented by the hypotenuse of the right triangle.
Therefore,
a = 8 feet and b = 20 feet
c² = a² + b²
c² = 8² + 20²
c² = 64 + 400
c² = 464
c ≈ 21.54
The diagonal length of the roof top is ≈ 22 feet.
The horizontal length of the roof is 30 feet.
The total area of the roof that will need shingles can be calculated by multiplying the horizontal length of the roof by the diagonal length of the roof.
Therefore,
Total area of the roof that will need shingles = Horizontal length × Diagonal length
Total area of the roof that will need shingles = 30 feet × 22 feet
Total area of the roof that will need shingles = 660 square feet
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Derrick grows vegetables on a circular patch of land. The radius of the patch is 16 meters. What is the approximate area of the patch of land? A. 25. 12 square meters B. 100. 48 square meters C. 452. 16 square meters D. 803. 84 square meters.
The approximate area of the circular patch of land with a radius of 16 meters is D. 803.84 square meters.
To determine the approximate area of the circular patch of land, we need to apply the formula for the area of a circle, which is A = π * r^2. In this formula, A represents the area, π (pi) is a mathematical constant approximately equal to 3.14, and r is the radius of the circle.
Given that the radius of the patch is 16 meters, we can substitute this value into the formula. Calculating the area, we have A = 3.14 * (16^2) = 3.14 * 256 = 803.84 square meters.
Therefore, the approximate area of the circular patch of land with a radius of 16 meters is 803.84 square meters. This means that option D, 803.84 square meters, is the correct answer.
It's important to note that the result is an approximation since we used the value of π as approximately 3.14. In more precise calculations, the value of π can be taken to more decimal places for increased accuracy.
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the average weight of a , b and c is 45 kg if the average of a and b is 40 kg that of b and c is 43 hen the weght of b is?
Therefore, the weight of B is 31 kg.
Let's solve the problem step by step.
1.Let's assign variables to the weights of the three individuals:
Weight of A = a
Weight of B = b
Weight of C = c
2.We are given that the average weight of A, B, and C is 45 kg:
(a + b + c) / 3 = 45
3.We are also given that the average of A and B is 40 kg:
(a + b) / 2 = 40
4.Additionally, we are given that the average of B and C is 43 kg:
(b + c) / 2 = 43
5.From equation 3, we can solve for a + b:
a + b = 2 * 40
a + b = 80
6.Substituting this value into equation 1:
(80 + c) / 3 = 45
7.Solving equation 6 for c:
80 + c = 3 * 45
80 + c = 135
c = 135 - 80
c = 55
8.Substituting the value of c into equation 4:
(b + 55) / 2 = 43
9.Solving equation 8 for b:
b + 55 = 2 * 43
b + 55 = 86
b = 86 - 55
b = 31
Therefore, the weight of B is 31 kg.
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Cynthia had a credit card with a 17% APR and a $3,265 balance. She had budgeted to have the credit card paid off in 24 months. But after missing a single monthly payment, Cynthia’s credit card company has increased her interest rate to 21%. How much extra will Cynthia have to pay in finance charges (interest) because of the increase in her APR if she still pays off the credit card in 24 months? a. $152. 16 b. $272. 08 c. $609. 32 d. $761. 48 Please select the best answer from the choices provided A B C D.
The answer is option C: $609.32.
To calculate the extra amount Cynthia will have to pay in finance charges due to the increased APR, we need to compare the interest charged at the original rate (17%) with the interest charged at the new rate (21%).
Using the formula for calculating compound interest, we can determine the interest charges for both rates over the 24-month period. The original interest charges would be 17% of the $3,265 balance, while the new interest charges would be 21% of the same balance.
By subtracting the original interest charges from the new interest charges, we find that Cynthia will have to pay an extra $609.32 in finance charges due to the increase in her APR.
Therefore, the correct answer is option C: $609.32.
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To balance a seesaw, the distance, d (in feet), a person is from the fulcrum is inversely proportional to his or her weight, w (in pounds). Roger, who weighs 120 pounds, is sitting 6 feet away from the fulcrum. If Ellen is sitting 5. 76 feet away from the fulcrum, how much must she weigh to balance the seesaw?
A. 120 lbs
B. 125 lbs
C. 140 lbs
D. 180 lbs
Ellen must weight approximately 125 pounds to balance the seesaw.
To solve this problem, we can set up an inverse variation equation:
d₁ * w₁ = d₂ * w₂
where d₁ and w₁ are the distance and weight of Roger, and d₂ and w₂ are the distance and weight of Ellen.
Given:
d₁ = 6 feet
w₁ = 120 pounds
d₂ = 5.76 feet
w₂ = ?
Plugging in the values into the equation, we get:
6 * 120 = 5.76 * w₂
720 = 5.76 * w₂
Now, let's solve for w₂:
w₂ = 720 / 5.76
w₂ ≈ 125
Therefore, Ellen must weight approximately 125 pounds to balance the seesaw.
So, the answer is B. 125 lbs.
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A measure is given as 2.0 km correct to
the nearest 500 m. What is the upper
bound?
Answer:
The upper bound for the measure given as 2.0 km correct to the nearest 500 m is 2.25 km.
Step-by-step explanation:
If the measure is given as 2.0 km correct to the nearest 500 m, it means that the measure has been rounded to the nearest 500 m increment.
To find the upper bound, we need to determine the highest possible value within that rounding interval.
The nearest 500 m increment means that any value between 1.75 km to 2.25 km would round to 2.0 km.
Since we want to find the upper bound, the highest value within this range is 2.25 km.
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Six times the smaller of two numbers minus the larger number is –15. Thirteen more than twice the smaller number is three times the larger number.
The equations smaller number is -2 and the larger number is 3.
The smaller number as "x" and the larger number as "y". Based on the given information the following equations:
Six times the smaller number minus the larger number is -15:
6x - y = -15
Thirteen more than twice the smaller number is three times the larger number:
2x + 13 = 3y
A system of two equations use various methods, such as substitution or elimination.
use the substitution method to solve the system:
From equation 2),
2x - 3y = -13
express 6x from equation 1) in terms of y:
6x = -15 + y
x = (-15 + y) / 6
Substituting this value of x into equation 2)
2((-15 + y) / 6) - 3y = -13
Simplifying and solving this equation
(-30 + 2y) - 18y = -78
-16y = -48
y = 3
Substituting the value of y back into equation 1), find the value of x:
6x - 3 = -15
6x = -12
x = -2
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the 9th and 1st term of an arithmetic progress are 50 and 65 respectively find the sum of its first two terms
The function between the given functions f(x) = x² + 5x and
g(x) = 8x² - 1 can be found by adding the two functions together.
The function between f(x) and g(x) is,
f(x) + g(x) = x² + 5x + 8x² - 1
= 8x² + x² + 5x - 1
= 9x² + 5x - 1
Given,
f(x) = x² + 5x
and
g(x) = 8x² - 1
We need to find the function between the given functions.
Since f(x) and g(x) are polynomials, we can find their greatest common factor.
f(x) can be written as x(x + 5), and g(x) can be written as (2x)²- 1.
The greatest common factor of the two polynomials is,
x(x + 5) + (2x - 1)(2x + 1)
= x² + 5x + 4x - 1
= x² + 9x - 1
Therefore, the function between f(x) and g(x) is,
f(x) + g(x) = x² + 5x + 8x² - 1
= 8x² + x² + 5x - 1
= 9x² + 5x - 1
In conclusion, the function between the given functions f(x) = x² + 5x
and g(x) = 8x² - 1 is represented by the equation
f(x) + g(x) = 9x² + 5x - 1
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Select the correct answer. A group of astronomers observed light coming from a star located a distance of 331,000,000,000,000,000,000,000,000 light-years from Earth. What is this distance expressed in scientific notation? A. 3. 31 × 1026 light-years B. 3. 31 × 10-26 light-years C. 3. 31 × 1024 light-years D. 3. 31 × 10-24 light-years E. 3. 31 × 1025 light-years.
The distance can be expressed in scientific notation as A. 3.31 × 10^27 light-years.
The distance of 331,000,000,000,000,000,000,000,000 light-years can be expressed in scientific notation by moving the decimal point to the left or right to create a number between 1 and 10. And then multiplying it by a power of 10. To determine the appropriate power of 10, we count the number of places the decimal point was moved. In this case, the decimal point needs to be moved 27 places to the left to create a number between 1 and 10. Therefore, the distance can be expressed in scientific notation as 3.31 × 10^27 light-years.
The correct answer is A. 3.31 × 10^26 light-years.
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Araceli had 20 minutes to a three problem quiz, She spent 11 7/10 minutes on question A and 3 2/5 on question B, what did she get for question C
Araceli had 20 minutes for a 3-problem quiz. She spent 11 7/10 minutes on question A and 3 2/5 minutes on question B, leaving her 5 1/5 minutes for question C. Effective time management is important during tests.
Araceli had 20 minutes to complete a three-problem quiz, and she spent 11 7/10 minutes on question A and 3 2/5 minutes on question B. To find out how much time she spent on question C, we can subtract the time she spent on question A and question B from the total time of 20 minutes:
20 minutes - 11 7/10 minutes - 3 2/5 minutes = 5 1/5 minutes
Therefore, Araceli spent 5 1/5 minutes on question C.
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If a man walks 3 miles east from his house and then turns around and walks 3 miles west back to his house, what is his displacement? also define displacement!
Displacement is a term used in physics to describe the overall change in position of an object or person, taking into account both the direction and magnitude.
It is a vector quantity and is typically represented as a straight line from the initial position to the final position, regardless of the actual path taken.
In the given scenario, the man walks 3 miles east from his house and then turns around and walks 3 miles west back to his house. Since he ends up back at his starting point, the displacement is zero.
Although the man walked a total distance of 6 miles (3 miles east and 3 miles west), the displacement considers the straight-line distance between the starting and ending points. Since these points coincide in this case, the overall displacement is zero miles.
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How to determine if an integral converges or diverges.
The function being integrated and considering convergence at individual points and behavior at infinity, one can determine whether an integral converges or diverges.
To determine if an integral converges or diverges, one must analyze the behavior of the function being integrated and evaluate certain criteria.
When dealing with improper integrals (integrals with infinite limits or integrals of unbounded functions), there are two key criteria to consider: convergence at a single point and behavior at infinity.
Convergence at a single point: If the function being integrated has a finite value at a particular point within the integration limits, then the integral converges at that point. However, if the function approaches infinity or oscillates without settling on a specific value at that point, the integral diverges.
Behavior at infinity: For integrals with infinite limits, it is crucial to determine the behavior of the function as the variable approaches infinity. If the function approaches zero or a finite value as the variable grows indefinitely, the integral converges. However, if the function approaches infinity or oscillates without settling on a specific value, the integral diverges.
To apply these criteria effectively, it may be necessary to use additional techniques such as comparison tests (e.g., the limit comparison test, integral comparison test), the ratio test, the root test, or other methods tailored to specific functions or situations. These techniques allow for a more rigorous analysis of convergence or divergence.
Overall, by carefully examining the behavior of the function being integrated and considering convergence at individual points and behavior at infinity, one can determine whether an integral converges or diverges.
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Which two rational numbers does 14 lie between?
On 19 and
?
OB.
3. 17 and 3. 71
Ос.
V4 and 9
O D.
3. 70 and 3. 75
The rational numbers 3.70 and 3.75 lie between 14, forming a range or interval in which 14 is situated.
To determine the rational numbers between 14, we need to find two numbers that are greater than 14 and two numbers that are less than 14. From the given options, 3.70 and 3.75 are the two rational numbers that lie between 14. They are both less than 14 but greater than the other options provided. These numbers form a range or interval in which 14 is situated.
The rational number 3.70 is less than 14, but it is closer to 14 compared to the other options provided. Similarly, 3.75 is also less than 14 but closer to it compared to the other options. Thus, both 3.70 and 3.75 form a range that includes 14 as a rational number between them.
In conclusion, the rational numbers 3.70 and 3.75 lie between 14, forming a range or interval in which 14 is situated.
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Triangle ABC has the coordinates A(8,4) B(12,4) C(16,12) if the triangle is dilated with a scale factor of 1/4 what are the new coordinates
After dilating Triangle ABC with a scale factor of 1/4, the new coordinates of A', B', and C' are A'(2,1), B'(3,1), and C'(4,3), respectively.
To dilate Triangle ABC with a scale factor of 1/4, we need to multiply the coordinates of each vertex by the scale factor.
Let's apply the scale factor to each coordinate:
A' = (8 * 1/4, 4 * 1/4)
= (2, 1)
B' = (12 * 1/4, 4 * 1/4)
= (3, 1)
C' = (16 * 1/4, 12 * 1/4)
= (4, 3)
Therefore, after dilating Triangle ABC with a scale factor of 1/4, the new coordinates of A', B', and C' are (2,1), (3,1), and (4,3) respectively. The scale factor of 1/4 shrinks the original triangle by a factor of 1/4 in both the x and y directions, resulting in a smaller triangle with the new coordinates.
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Tell whether or not f(x)= pi(sin) 3x - 4x sin 2x is a sinusoid.
a.
Yes
b. No
No, the function f(x) = πsin(3x) - 4xsin(2x) is not a sinusoid. A sinusoid is a function that can be represented by a sine or cosine function with certain characteristics.
In the given function f(x) = πsin(3x) - 4xsin(2x), we can see that there are two sine terms with different frequencies, 3x and 2x. This indicates that the function does not have a constant frequency, which is a requirement for a sinusoid. Additionally, the presence of the term -4x introduces a linear term, which further deviates from the sinusoidal form.
Therefore, due to the varying frequencies and the inclusion of a linear term, the function f(x) = πsin(3x) - 4xsin(2x) does not meet the criteria to be classified as a sinusoid.
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Jocelyn is training for a race by running several miles each day. She tracks her progress by recording her average
speed in minutes per mile for each day since she started training
1
2
3
4
5
6
Number of Days, x
Average Speed (min/mile), y
8.2
8.1
7.5
7.8
7.4
7.5
Based on the information given, what could Jocelyn expect to have for her average speed on the 9th day?
O 8.5 minutes per mile
O 7.2 minutes per mile
6.9 minutes per mile
O 6.2 minutes per mile
Based on the given data, Jocelyn could expect to have an average speed of approximately 6.9 minutes per mile on the 9th day.
To determine the expected average speed on the 9th day, we can analyze the trend in Jocelyn's average speed over the first six days. From the data provided, it can be observed that her average speed is gradually decreasing, indicating an improvement in her running performance.
By examining the given values, we can see that there is a consistent decrease in the average speed from 8.2 minutes per mile to 7.5 minutes per mile over the initial six days. Assuming this trend continues, we can expect Jocelyn's average speed to continue to decrease on the 9th day.
Therefore, it is reasonable to predict that Jocelyn's average speed on the 9th day would be approximately 6.9 minutes per mile, as the trend suggests a gradual improvement in her running speed. However, it's important to note that this is an estimation based on the given data, and actual results may vary.
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