L ≈ 35.8 ,the length of the arc to the nearest tenth is 35.8 units
The formula for calculating the length of an arc intercepted by a central angle is L=, where L is the arc's length, is the circle's radius, and is the central angle in radians. The length of the arc to the nearest tenth is 35.8 units. Given, In a circle with radius r = 6.5, an angle measuring = 5.5 radians intercepts an arc. We know that the formula for calculating the length of an arc intercepted by a central angle is L=, where L is the arc's length, is the circle's radius, and is the central angle in radians. Substituting the values in the formula, we get:
L = rL = 6.5(5.5)L = 35.75 ≈ 35.8 (to the nearest 10th)
Therefore, the length of the arc to the nearest tenth is 35.8 units.
In a circle, the length of an arc intercepted by a central angle is determined by the central angle's size and the circle's radius. This is known as the arc's length formula. L=where L is the arc length, is the radius of the circle, and is the central angle in radians. We can use this formula to find the length of an arc intercepted by a central angle in a circle. Let's consider the following illustration to understand the concept better. In a circle with a radius of 6.5, an angle of 5.5 radians intercepts an arc. We'll use the arc length formula to find the arc's length, L.L= (Length of arc formula)Substitute the given value of r and in the formula. L = 6.5 × 5.5L = 35.75The length of the arc is 35.75 units. We'll round this answer to the nearest tenth to get the final answer. L ≈ 35.8Therefore, the length of the arc to the nearest tenth is 35.8 units.
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You start at (-3, 5). You move left 1 unit and right 8 units. Where do you end?
The point where you end after moving is (4, 5)
How to determine the point where you endFrom the question, we have the following parameters that can be used in our computation:
Start = (-3, 5)
Direction: 1 unit left and 8 units right
using the above as a guide, we have the following:
New point = (-3, 5) + (-1 + 8, 0)
So, we have
New point = (-3 - 1 + 8, 5 + 0)
Evaluate
New point = (4, 5)
Hence, the point where you end is (4, 5)
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PLEASE HELP FAST!! WILL GIVE BRAINLIEST! The rectangle ABCD has diagonals that intersect at point O and ABD = 30. Find BC if AC = 16 in
The length of BC in the rectangle ABCD is 16 units.
To find the length of BC in the rectangle ABCD, we can use the properties of rectangles and the intersecting diagonals.
Let's consider the given information:
AC = 16 (given)
ABD = 30° (given)
In a rectangle, the diagonals are equal in length. Therefore, AO = CO and BO = DO.
Since ABD is a right triangle, we can use trigonometric ratios to find the length of AO. In triangle ABD, the angle ABD is 90°, and we know ABD = 30°. Therefore, the remaining angle BDA is 180° - 90° - 30° = 60°.
Using the trigonometric ratio for a right triangle:
sin(BDA) = AO / AB
sin(60°) = AO / AB
√3 / 2 = AO / AB
Since AB is the length of the diagonal of the rectangle, we can represent it as d:
√3 / 2 = AO / d
Now, we can find AO:
AO = (√3 / 2) * d
Since AO = CO and BO = DO, we can conclude that BO and CO also have lengths of (√3 / 2) * d.
Now, let's consider triangle AOC. We know that AC = 16, and AO = CO = (√3 / 2) * d. We can use the Pythagorean theorem to find OC:
OC^2 = AC^2 - AO^2
OC^2 = 16^2 - [(√3 / 2) * d]^2
OC^2 = 256 - (3/4) * d^2
OC = √(256 - (3/4) * d^2)
Similarly, in triangle BOC, we have BO = (√3 / 2) * d and OC = √(256 - (3/4) * d^2). We can again use the Pythagorean theorem to find BC:
BC^2 = BO^2 + OC^2
BC^2 = [ (√3 / 2) * d ]^2 + [ √(256 - (3/4) * d^2) ]^2
BC^2 = (3/4) * d^2 + 256 - (3/4) * d^2
BC^2 = 256
Taking the square root of both sides:
BC = √256 = 16
Therefore, BC = 16.
So, the length of BC in the rectangle ABCD is 16 units.
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