In 2021, you were given a 100. g wine sample to verify its age. Using tritium dating you observe that the sample has 0.688 decay events per minute. Tritium has a half life of 12.3 and fresh water exhibits 5.5 decay events per minute per 100. g. What year was the wine produced

Answers

Answer 1

Answer:

1984

Explanation:

Given the formula;

0.693/t1/2 = 2.303/t log (Ao/A)

Where;

t1/2 = half life of the radioactive isotope

t= age of the wine

Ao= initial activity of the wine

A= activity of the at time = t

0.693/12.3 = 2.303/t log (5.5/0.688)

0.693/12.3 = 2.079/t

0.056 = 2.079/t

t= 2.079/0.056

t= 37 years

The wine was produced 37 years ago which means that it was produced in the year 1984

Answer 2

The wine has been produced in the year 1984.

Half-life can be defined as the time required by the substance to reduce to half of its initial concentration.

The decay of wine per minute has been = 0.688/minute

The half-life of the sample has been = 12.3

The decay of freshwater has been= 5.5 decay/minute

k can be given as:

k = [tex]\rm \dfrac{0.693}{Half-life}[/tex]

k = [tex]\rm \dfrac{0.693}{12.3}[/tex]

k = 0.056 years

The time for the decay can be calculated as:

t = [tex]\rm \dfrac{2.303}{k}\;log\; \dfrac{a}{a\;-\;x}[/tex]

t = [tex]\rm \dfrac{2.303}{0.056}\;\times\;log\;\dfrac{5.5}{0.688}[/tex]

t = 37 years

The wine has been produced 37 years ago. The present year has been 2021. The year of wine production has been:

Year of wine production = 2021 - 37

Year of wine production = 1984.

The wine has been produced in the year 1984.

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Related Questions

Is pre ap chemistry hard in high school?

Answers

If you don't practice enough it's obviously going to be hard but if you practice enough it's going to be a piece of cake so don't think if it's going to be hard or not just think it's going to be worth the try at the very end

Depends on how good u are at studying or taking notes if your good at that you should be fine

Carboxylic acids and alcohols react via dehydration and condensation to produce a/an _______ and water.

Question options:



amine




ether




polymer




ester

Answers

Answer:

ester

Explanation:

Carboxylic acids and alcohols react in the presence of strong acid to produce an ester and water. The two carbon chains come together, which is the condensation, and then water is generated, which is dehydration. The resulting compound is an ester.

Each 5-ml teaspoon of Extra Strength Maalox Plus contains 450 mg of magnesium hydroxide and 500 mg of aluminum hydroxide. How many moles of hydronium ions H3O are neutralized by 1 teaspoon of antacid product?

Answers

Answer:

0.0347 moles of hydronium ions

Explanation:

The equation of the neutralization reaction between hydroxide and hydronium ions is given below:

H₃O+ (aq) + OH- (aq) ----> 2 H₂O (l)

From the equation above, 1 mole of hydroxide ions will neutralize one mole hydronium ions.

The moles of hydroxide ions present in 1 teaspoon or 5 mL of antacid product is calculated as follows:

Number of moles = mass / molar mass

Molar mass of Magnesium hydroxide, Mg(OH)₂ = 58 g/mol

Molar mass of aluminium hydroxide, Al(OH)₃ = 78 g/mol

Mass of magnesium hydroxide = 450 g = 0.45 g

Mass of aluminium hydroxide = 500 mg = 0.5 g

Moles of magnesium hydroxide = (0.45/58) moles

Moles of aluminium hydroxide = (0.5/78) moles

Equation of the ionization of magnesium hydroxide and aluminium hydroxide is given below:

Mg(OH)₂ (aq) ----> Mg²+ (aq) + 2 OH- (aq)

Al(OH)₃ (aq) ---> Al³+ (aq) + 3 OH- (aq)

Number of moles of hydroxide ions present in (0.45/58) moles of magnesium hydroxide = 2 × (0.45/58) moles = 0.0155 moles

Number of moles of hydroxide ions present in (0.5/78) moles of aluminium hydroxide = 3 × (0.5/78) moles = 0.0192 moles

Total moles of hydroxide ions = 0.0155 + 0.0192 = 0.0347 moles hydroxide ions

Therefore, 0.0347 moles of hydroxide ions will neutralize 0.0347 moles of hydronium ions.

What minimum mass of HCl in grams would you need to dissolve a 2.2 g iron bar on a
padlock?

Answers

I think your answer should be 2.8 g

2.8 g is the minimum mass of HCl in grams that would you need to dissolve a 2.2 g iron bar on a padlock.

What is dissolution?

When a solute is dissolved in a solvent, a solution is created. Dissolution is the process through which solutes, or dissolved parts, combine to form a solution inside a solvent. In this procedure, the gas, liquid, or solid dissolves inside the original solvent and forms a solution.

In some polymer applications, dissolution is also an issue since it results in swelling, a loss of strength and stiffness, and a change in volume. Whether a chemical process is man-made or natural, dissolution is crucial. Catalysts are tested using dissolution. 2.8 g is the minimum mass of HCl in grams that would you need to dissolve a 2.2 g iron bar on a padlock.

Therefore, 2.8 g is the minimum mass of HCl in grams that would you need to dissolve a 2.2 g iron bar on a padlock.

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Manganese-55 has _____neutrons.
55 Mn
25

A. 55
B. 30
C. 25​

Answers

QUESTION:- Manganese-55 has _____neutrons.

OPTIONS :-

A. 55

B. 30

C. 25

ANSWER:- NUMBER OF NEUTRONS IS EQUAL TO THE DIFFERENCE BETWEEN THE MASS IF THE ATOM AND ATOMIC NUMBER

SO DIFFERENCE IS EQUAL TO :- 55-25 = 30 NEUTRONS.

SO THERE IS 30 NEUTRONS IN SINGLE ATOM OF THE MANGANESE-55 ATOM.

Answer:

the mass of an atom is the sum of proton and neutron which are both concentrated in nocleus of an atom. from the question the mass is given as 55 and the proton is 25.

6) Hydrogen gas can be generated from the reaction between aluminum metal and hydrochloric acid:
2 Al(s) + 6 HCl(aq) + 2 AICI3, (aq) + 3 H2(g)
a. Suppose that 3.00 grams of Al are mixed with excess acid. If the hydrogen gas produced is directly collected
into a 850 mL glass flask at 24.0 °C, what is the pressure inside the flask (in atm)?
b. This hydrogen gas is then completely transferred from the flask to a balloon. To what volume (in L) will the
balloon inflate under STP conditions?
c. Suppose the balloon is released and rises up to an altitude where the temperature is 11.2 °C and the pressure is
438 mm Hg. What is the new volume of the balloon (in L)?

Answers

Stoichiometry refers to the relationship between the moles of reactants and products.

This question must be solved using both stoichiometry and the gas laws

The reaction equation is;

2 Al(s) + 6 HCl(aq) --------> 2 AICI3, (aq) + 3 H2(g)

Using stoichiometry

Number of moles of Al = 3g/27g/mol = 0.11 moles

According to the reaction equation;

2 moles of Al yields 3 moles of H2

0.11 moles of Al yields 0.11 * 3/2 = 0.165 moles

Using the gas laws

From the ideal gas equation;

PV=nRT

P = ?

n= 0.165 moles

V = 0.85 L

T = 297 K

R = 0.082 atmLK-1mol-1

P= nRT/V

P = 0.165 * 0.082 * 297/0.85

P= 4.73 atm

Under STP conditions;

P1 = 4.73 atm

T1 = 297 K

V1 = 0.85 L

P2 = 1 atm

T2 =273 K

V2 =?

From the general gas equation;

P1V1/T1 = P2V2/T2

P1V1T2 = P2V2T1

V2 = P1V1T2/P2T1

V2 =  4.73 * 0.85 * 273/1 * 297

V2 = 3.69 L

P1 = 760 mmHg

T1 = 273 K

V1 = 3.69

P2 = 438 mm Hg

T2 = 284.2 K

V2 =?

P1V1/T1 = P2V2/T2

P1V1T2 = P2V2T1

V2 = P1V1T2/P2T1

V2 = 760 * 3.69 * 284.2/438 *273

V2 = 797010.48/119574

V2= 6.67 L

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What is the biggest cause of change in Earth's systems?
A. Heat
B. Motion
C. Friction
D. Plate tectonics

Answers

Answer:

heat

Explanation:

because it's the cause of change

Answer:

heat

Explanation:

because it is a natural factor that causes the change in Earth's system

Answer EIGHT questions.
1(a) Whai do you mean by generation of computer? Describe brieíly
5
about third and fourth generations of computer.
B
moga dele​

Answers

Answer:

Generation in computer terminology is a change in technology a computer is/was being used. Initially, the generation term was used to distinguish between varying hardware technologies. Nowadays, generation includes both hardware and software, which together make up an entire computer system.

5 generation of computer  

Main electronic component: based on artificial intelligence, uses the Ultra Large-Scale Integration (ULSI) technology and parallel processing method.

ULSI – millions of transistors on a single microchip

Parallel processing method – use two or more microprocessors to run tasks simultaneously.

Language – understand natural language (human language).

Power – consume less power and generate less heat.

Speed – remarkable improvement of speed, accuracy and reliability (in comparison with the fourth generation computers).

Size – portable and small in size, and have a huge storage capacity.

Input / output device – keyboard, monitor, mouse, trackpad (or touchpad), touchscreen, pen, speech input (recognise voice / speech), light scanner, printer, etc.

Example – desktops, laptops, tablets, smartphones, etc.

3 generation of computer

Main electronic component – integrated circuits (ICs)

Memory – large magnetic core, magnetic tape / disk

Programming language – high level language (FORTRAN, BASIC, Pascal, COBOL, C, etc.)

Size – smaller, cheaper, and more efficient than second generation computers (they were called minicomputers).

Speed – improvement of speed and reliability (in comparison with the second generation computers).

Input / output devices – magnetic tape, keyboard, monitor, printer, etc.

Examples – IBM 360, IBM 370, PDP-11, UNIVAC 1108, etc.

4 generations of computer

Main electronic component – very large-scale integration (VLSI) and microprocessor.

VLSI– thousands of transistors on a single microchip.

Memory – semiconductor memory (such as RAM, ROM, etc.)

RAM (random-access memory) – a type of data storage (memory element) used in computers that temporary stores of programs and data (volatile: its contents are lost when the computer is turned off).

ROM (read-only memory) – a type of data storage used in computers that permanently stores data and programs (non-volatile: its contents are retained even when the computer is turned off).

Programming language – high level language (Python, C#, Java, JavaScript, Rust, Kotlin, etc.).

How many moles of Cl− are in 5.76 mg of FeCl3?

Answers

Answer:

0.0061650760770388 mole

How many moles of Al are needed to react exactly with 10.00 moles of Fe2O3 according to the following
equation?
Fe2O3 + 2 Al → Al2O3 + 2Fe
A) 15.0 moles
1
B) 20.0 moles
C) 30.0 moles
D) 60.0 moles
E) 35.0 moles

Answers

Answer:

Answer is B) 20.0 moles

Explanation:

From the equation,

1 mole of Fe2O3 = 2 moles of Al

therefore 10.0 moles of Fe2O3 = 10×2

= 20.0 moles.

Choose the most correct answer: The endothermic (∆H > 0) reaction:
a) Cannot occur at all temperature.
b) Can occur with the positive ∆S at high temperature.
c) Can occur with the negative ∆S at low temperature.
d) Cannot occur with the positive ∆S at high temperature.

Answers

Answer:

B

Explanation:

In order to create spontaneity, an endothermic process has to occur along with positive entropy and high temperature

A substance which is made up of the same kind
of atom is known as?

Answers

Answer:

Element

Element : A pure substance composed of the same type of atom throughout. Compound : A substance made of two or more elements that are chemically combined in fixed amounts.

Explanation:

Explain the working principle of a clinical thermometer ​

Answers

Answer:

A clinical thermometer is a thermometer used to measure human body temperature. Most made in the 20th century are mercury-in-glass thermometers. They are accurate and sensitive, having a narrow place where the mercury level rises very fast. A kink in the tube stops the mercury level from falling on its own.

Read the following statement:

Energy cannot be created or destroyed.

Does the statement describe a scientific law? (3 points)

a
No, because it universally applies to all objects

b
No, because it is not true in all circumstances

c
Yes, because it universally applies to all objects

d
Yes, because it is not true in all circumstances

Answers

Answer:

C. yes, because it is universally applies to all objects

2. Calculate the wavelength of the emitted photon from hydrogen for the transition from ni = 3 to nf = 2. What part of the visible spectrum is this wavelength? Visible wavelengths are: Red  700 - 620 nm, Yellow  620 - 560 nm, Green  560 - 500 nm, Blue 500 - 440 nm, and Violet  440 - 400 nm.

Answers

Answer:

The correct answer is "654.54 nm".

Explanation:

According to the question,

⇒ [tex]\frac{1}{\lambda}= Rh(\frac{1}{n1^2} -\frac{1}{n2^2} )[/tex]

By substituting the values, we get

       [tex]=1.1\times 10^7(\frac{1}{4} -\frac{1}{9} )[/tex]

       [tex]=1.1\times 10^7(\frac{9-4}{36} )[/tex]

       [tex]=1.1\times 10^7(\frac{5}{36} )[/tex]

       [tex]=654.54\ nm[/tex]

Thus the above is the right solution.

Explain why you get a basic solution when you dissolve NaF in water.

Answers

Answer:

The fluoride ion is capable of reacting, to a small extent, with water, accepting a proton. The fluoride ion is acting as a weak Brønsted-Lowry base. The hydroxide ion that is produced as a result of the above reaction makes the solution slightly basic.

So

we get a basic solution when you dissolve NaF in water.

Na is a alkaline earth metal

Metallic compound dissolved in water acts as base

Also there is another reason

Na F is ioniC

Fluorine is known as having highest electron affinity in world

It can accept a line pair of OH-

So it's Bronsted Lowry base .

It can also acts as Arrhenius base

Hence its basic

Dylan has a coworker who is always showing up late and then not finishing his work on time . It's frustrating the other members of the team . What can he do that might help the situation ? a ) Complain about the coworker to other team members b ) Ask his coworker if he understands his job responsibilities c ) Tell his boss that the coworker is slacking off d ) Complete his coworker's work for him

Answers

The answer should be C I think that’s the best answer but I’m not sure.

Forcus on the yellow highlighted texts, your help is appreciated.
[tex]{ \sf{ \red{no \: pranks}}}[/tex]

Answers

Answer:

Transition temperature is the temperature at which a substance changes from one state to another.

Allotropy is the existence of an element in many forms.

What volume of water is produced when 38.5 g of ethanol reacts with oxygen at 500°C at 1.75 atm?
CH3CH2OH(g) + 3 O2(g)→ 2 CO2(g) + 3 H2O(g)

Answers

Answer:

90.99 or 91.0

Explanation:

Using the balanced equation, you convert 38.5g of ethanol to moles of water. From there, you plug the values into the Ideal Gas Equation: PV=nRT.

Answer: The volume of oxygen gas is 91.4 L.

Explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)

Given mass of ethanol = 38.5 g

Molar mass of ethanol = 46 g/mol

Plugging values in equation 1:

[tex]\text{Moles of ethanol}=\frac{38.5g}{46g/mol}=0.840 mol[/tex]

The given chemical equation follows:

[tex]CH_3CH_2OH(g)+3O_2(g)\rightarrow 2CO_2(g)+3H_2O(g)[/tex]

By stoichiometry of the reaction:

If 1 mole of ethanol produces 3 moles of water

So, 0.840 moles of ethanol will produce = [tex]\frac{3}{1}\times 0.840=2.52mol[/tex] of water

The ideal gas equation is given as:

[tex]PV=nRT[/tex] .......(2)

where

P = pressure = 1.75 atm

V = volume of oxygen gas = ?

n = number of moles= 2.52 moles

R = Gas constant = 0.0821 L.atm/mol.K

T = temperature of the tank = [tex]500^oC=[500+273]K=773K[/tex]

Putting values in equation 2, we get:

[tex]1.75 atm\times V=2.52mol\times 0.0821L.atm/mol.K\times 773K\\\\V=\frac{2.52\times 0.0821\times 773}{1.75}=91.4L[/tex]

Hence, the volume of oxygen gas is 91.4 L.

The elementary reaction 2H2O(g)↽−−⇀2H2(g)+O2(g) proceeds at a certain temperature until the partial pressures of H2O, H2, and O2 reach 0.0900 bar , 0.00100 bar , and 0.00350 bar respectively. What is the value of the equilibrium constant at this temperature?

Answers

Answer:

3.89 ×10^-5

Explanation:

Since they are gaseous reactants, we obtain the equilibrium constant from the given partial pressures;

p(H2O) = 0.0900 bar

p(H2) = 0.00100 bar

p(O2) = 0.00350 bar

The equation of the reaction is;2H2O(g)⇄2H2(g)+O2(g)

Kp= p(H2) . p(O2)/p(H2O)

Kp= 0.00100 × 0.00350/0.0900

Kp= 3.89 ×10^-5

Lewis Structures are used to describe the covalent bonding in molecules and ions. Draw a Lewis structure for NO3- and answer the following questions based on your drawing.

1. For the central nitrogen atom:

The number of lone pairs = ________
The number of single bonds=_______
The number of double bonds= ______

2. The central nitrogen atom :

Answers

Answer:

The lewis structure for NO₃⁻ is shown in the attachment below

For the central nitrogen atom:

The number of lone pairs = 0

The number of single bonds = 2  

The number of double bonds= 1

Explanation:

The lewis structure for NO₃⁻ is shown in the attachment below.

From the Lewis structure

For the central nitrogen atom:

The number of lone pairs = 0

The number of single bonds = 2  

The number of double bonds= 1

một chất hữu cơ có cấu tạo c2h2 cho khí br2 vào ta được hỗn hợp khí

Answers

Answer:

C2H2 + Br2 → C2H2Br2

Explanation:

Critique this statement: Electrons can exist in any position
outside of the nucleus.

Answers

Answer:

However, there has to be 2 electrons on the first shell, and 8 on the others.

Explanation:

Hope this helps :)

What is the oxidation state for bh3

Answers

Answer:

As hydrogen is more electronegative than boron, in BH3 the oxidation number of hydrogen should be taken as -1. (E. N. of B = 2.0 & E. N. of H = 2.1)

Suppose, oxidation number of B is x.

So, we can write, x + 3*(-1) = 0

=> x = +3

Therefore, oxidation num

Explanation:

As hydrogen is more electronegative than boron, in BH3 the oxidation number of hydrogen should be taken as -1. (E. N. of B = 2.0 & E. N. of H = 2.1)

Suppose, oxidation number of B is x.

So, we can write, x + 3*(-1) = 0

=> x = +3

Therefore, oxidation num

equal volumes 50.0 ml of 0.54897 m solution of HCL and 0.9573 M NaOH solution have an initial temperature of 18.5 degrees Celsius react in a coffee cup calorimeter the resulted Solutions records a temperature of 22.9 degrees Celsius since the solutions are mostly water the solution are assumed to have a density of 1.0 g per ml and a specific heat of 4.184 joules per gram degree celsius the heat capacity of the Colorimeter is 1.0 x 10 to power 1 joules per degrees Celsius calculate the heat and gained or released by the solution at a constant pressure in J

Answers

Answer:

Explanation:

ok

Consider the reaction: A(aq) + 2B (aq) === C (aq). Initially 1.00 mol A and 1.80 mol B
were placed in a 5.00-liter container. The mole of B at equilibrium was determined to
be 1.00 mol. Calculate K value.
0.060
5.1
25
17
Ugh

Answers

Answer:

17

Explanation:

Step 1: Calculate the needed concentrations

[A]i = 1.00 mol/5.00 L = 0.200 M

[B]i = 1.80 mol/5.00 L = 0.360 M

[B]e = 1.00 mol/5.00 L = 0.200 M

Step 2: Make an ICE chart

        A(aq) + 2 B(aq) ⇄ C(aq)

I       0.200    0.360        0

C        -x           -2x         +x

E     0.200-x  0.360-2x   x

Then,

[B]e = 0.360-2x = 0.200

x = 0.0800

The concentrations at equilibrium are:

[A]e = 0.200-0.0800 = 0.120 M

[B]e = 0.200 M

[C]e = 0.0800 M

Step 3: Calculate the concentration equilibrium constant (K)

K = [C] / [A] × [B]²

K = 0.0800 / 0.120 × 0.200² = 16.6 ≈ 17

Amphiphilic molecule: ___________

a. have both oxidizing and reducing groups.
b. are micelles.
c. have chromophores in two different wavelength regions.
d. have both acidic and basic groups.
e. have both hydrophilic and hydrophobic groups.

Answers

The answer is E - have both hydrophilic and hydrophobic groups.

H2+O=???????????????????

Answers

Answer:

H₂O

Explanation:

Two molecules of Hydrogen and one molecules of Oxygen, when mixed, create H₂O, or water. There is no scientific name for H₂O due to it's common name. It is just refereed to as "water" or H₂O.

Draw a formula for Thr-Gly-Ala (T-G-A) in its predominant ionic form at pH 7.3. You may assume for the purposes of this question that the pKa values of the acidic groups of amino acid residues in the peptide are the same as in the amino acid itself.

Answers

Answer:

gggggggggg

Explanation:

gggggggg

The tripeptide formed from threonine, glycine and alanine is neutral at the pH of 7.3. The carboxylic end is negative charged by donating its proton to form the NH₃⁺ group.

What is peptide?

Peptides are protein units formed from two or more amino acids bonded through peptide bonds. There are essential and non-essential amino acids. Essential amino acids have to be uptake from food and non-essential amino acids are synthesized inside the body.

Threonine is an essential amino acid with a CH₃CHOH side group. Glycine has the simplest side group hydrogen and alanine has  CH₃ side chain. Both glycine and alanine are non-essential amino acids.

Each amino acids are represented with a three letter code or one letter symbol. Thus threonine is T,  G for glycine and A for alanine. At a pH of 7.3 the peptide formed from these amino-acids contains a negatively charged carboxylic end.

A positively charged amino end made by protonation from the acid group make the overall charge zero. The structure of the peptide is given in the uploaded image.

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Determine the number of moles of aluminum in 2.154 x 10-1 kg of Al. Group of answer choices 5816 mol 7.984 mol 6.02 X 1023 mol 4.801 mol 8.783

Answers

Answer:

Avogadro's number is 1 mol  = 6.02 * 10^23 elements

It means that 1 mol of atoms is 6.02 * 10^23 atoms

1 mol of atoms = 6.02 * 10^23 atoms

From there, if you divide both sides by 1 mol of atoms, you get

1 = 6.02 * 10^23 atoms / 1 mol of atoms.

That means, that to pass from a number of moles of atoms to number of atoms you have to multipby by the conversion factor

         6.02*10^23  atoms Al/ 1 mol Al

That is the second option of the list.

Explanation:

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A farmer has an orchard that covers an area of 40 acres. He grows apples on 25 acres, peaches on 7 acres, nectarines on 5 acres, and plums on 3 acres. The fruit trees are equally distributed within the orchard. A tree is chosen at random. Rounded to the nearest tenth of a percent, what is the theoretical probability that the tree is not within the acres of apple trees A rectangle with a perimeter of 113 units is dilated by a scale factor of 3. Find theperimeter of the rectangle after dilation. Round your answer to the nearest tenth, ifnecessary. "Development activities help to improve the status of technology" justify 15 . A scientist who studies the whole environment as a working unit . Botanist Chemist Ecologist Entomologist Lauren bought 15 rainbow and balloon stickers for her little sister. The rainbow stickers cost 3 cents apiece and the balloon stickers cost 6 cents apiece. If Lauren spent exactly 81 cents, how many of each type of sticker did she buy? 7. Which substances are produced by the hydrolysis of anoil?(1) water and nucleic acids(2) amino acids and dipeptides(3) fatty acids and glycerol(4) glucose and water which has a steeper slope y=-2x or y=-3x Qu significa que un gen se exprese?: I. Que se hagan copias de l en forma de ARNm. II, Que se posibilite la sntesis de protenas. III. Que genere caractersticas visibles. The masses of two heavenly bodies are 21016 and 410 22 kg respectively and the distance between than is 30000km. find the gravitational force between them ? ans. 2.668 10-9N Zupiter Corp. follows a culture that requires strict adherence to rules and regulations with fixed time schedules for daily activities. The firm is highly efficient and places emphasis on being economical. It conducts its business in a methodical manner. In the given scenario, Zupiter Corp. is said to have the what carbon compound stores energy for the cell and sometimes provides structural support find and correct one spelling mistake in each of these sentencesthe machine was installed sucessfully Question 1 of 10Submit Submit An independent clause _________________________.A) is true in any situationB) is true independent of who is saying itC) makes sense by itself, whether its true or falseD) doesnt make sense, because meaning depends on all words Various shareholders' equity topics; comprehensivePart AIn late 2010, the Nicklaus Corporation was formed. The corporate charter authorizes the issuance of 5,000,000 shares of common stock carrying a $1 par value, and 1,000,000 shares of $5 par value, noncumulative, nonparticipating preferred stock. On January 2, 2011, 3,000,000 shares of the common stock are issued in exchange for cash at an average price of $10 per share. Also on January 2, all 1,000,000 shares of preferred stock are issued at $20 per share.Required:1. Prepare journal entries to record these transactions.2. Prepare the shareholders' equity section of the Nicklaus balance sheet as of March 31, 2011. (Assume net income for the first quarter 2011 was $1,000,000.)Part BDuring 2011, the Nicklaus Corporation participated in three treasury stock transactions:a. On June 30, 2011, the corporation reacquires 200,000 shares for the treasury at a price of $12 per share.b. On July 31, 2011, 50,000 treasury shares are reissued at $15 per share.c. On September 30, 2011, 50,000 treasury shares are reissued at $10 per share.Required:1. Prepare journal entries to record these transactions.2. Prepare the Nicklaus Corporation shareholders' equity section as it would appear in a balance sheet prepared at September 30, 2011. (Assume net income for the second and third quarter was $3,000,000.)Part COn October 1, 2011, Nicklaus Corporation receives permission to replace its $1 par value common stock (5,000,000 shares authorized, 3,000,000 shares issued, and 2,900,000 shares outstanding) with a new common stock issue having a $.50 par value. Since the new par value is one-half the amount of the old, this represents a 2-for-1 stock split. That is, the shareholders will receive two shares of the $.50 par stock in exchange for each share of the $1 par stock they own. The $1 par stock will be collected and destroyed by the issuing corporation.On November 1, 2011, the Nicklaus Corporation declares a $.05 per share cash dividend on common stock and a $.25 per share cash dividend on preferred stock. Payment is scheduled for December 1, 2011, to shareholders of record on November 15, 2011.On December 2, 2011, the Nicklaus Corporation declares a 1% stock dividend payable on December 28, 2011, to shareholders of record on December 14. At the date of declaration, the common stock was selling in the open market at $10 per share. The dividend will result in 58,000 (.01 5,800,000) additional shares being issued to shareholders.Required:1. Prepare journal entries to record the declaration and payment of these stock and cash dividends.2. Prepare the December 31, 2011, shareholders' equity section of the balance sheet for the Nicklaus Corporation. (Assume net income for the fourth quarter was $2,500,000.)3. Prepare a statement of shareholders' equity for Nicklaus Corporation for 2011. Find the equation of the linear function represented by the table below in slope-intercept form. Solve for y in terms of x.2/3y-4=x A y= 3/2x+6B y=-2/3x+4 C y=-3/2x+6 D 2/3x+4 COULD A KIND SOUL PLEASE HELP ME OUT???!!!!!!Determine the measure of x in the figure below.show how you go the answer so I can see if it makes sense!!! another word for gasping gasping Discuss any two elements of a One-Act play providing examples from Enigma by Floyd Dell in your course book.The elements are setting, characters, conflict and theme. Choose any two elements. Which of the following statements is not true about metabolism?A. Older people tend to burn more calories than younger individuals.B. Basal metabolic rate is the number of calories your body needs to perform basic daily tasks.C. Muscle on the body burns more energy than body fat does.D. One pound of muscle may lead to an extra 3,500 calories being used each month.