i’ll mark you brainliest and give more points, please show workkkk

Answer:

a - HT = 17

b - ∠T = 62

c - ∠H = 28

Answer:

h minus 20

Step-by-step explanation:

Answer:

6×[tex]10^{-4}[/tex]

Step-by-step explanation:

The exponent 7 tells us how many copies of "8" are being multiplied together.

The expression 8*8*8 is equal to 8^3, while 8*8*8*8 = 8^4

Multiplying 8^3 and 8^4 will have us add the exponents to get 8^7. The base stays at 8 the entire time.

The rule is a^b*a^c = a^(b+c) where the base is 'a' the entire time.

Answer:

8^ 7

Step-by-step explanation:

(8*8*8) * (8*8*8*8)

There are 3 8's times 4 8's

8^3 * 8^4

We know that a^b * a^c = a^ (b+c)

8 ^ ( 3+4)

8^ 7

Answer:

6

Step-by-step explanation:

Function A

y = 9x + 4

Function B

y = max+b

m = 3 and b = 4

y = 3x+4

The difference in the slopes is 9-3 = 6

Answer:

6

Step-by-step explanation:

The two functions are A and B.

A's equation is khown

● y =9x + 4

B is also khown. We should only gather tge information.

● the rate of change is 3

●the y-intercept is 4

So B's equation is:

● y = 3x + 4

3 is the rate of change wich is khown as the slope.

Divide A's slope by B's slope to khow how much A's slope is bigger than B's.

● 9/3 = 3

Substract 3 from 9 and you get the difference 9-3= 6

Answer:

x >= -7  ................(1a)

x >= 3   ...............(2a1)

Step-by-step explanation:

f(x) =  [tex]\sqrt{x+7}-\sqrt{x^2+2x-15}[/tex]  .............(0)

find the domain.

To find the (real) domain, we need to ensure that each term remains a real number.

which means the following conditions must be met

x+7 >= 0  .....................(1)

AND

x^2+2x-15 >= 0 ..........(2)

To satisfy (1),  x >= -7  .....................(1a) by transposition of (1)

To satisfy (2), we need first to find the roots of (2)

factor (2)

(x+5)(x-3) >= 0

This implis

(x+5) >= 0 AND (x-3) >= 0.....................(2a)

OR

(x+5) <= 0 AND (x-3) <= 0 ...................(2b)

(2a) is satisfied with x >= 3   ...............(2a1)

(2b) is satisfied with x <= -5 ................(2b1)

Combine the conditions (1a), (2a1), and (2b1),

x >= -7  ................(1a)

AND

(

x >= 3   ...............(2a1)

OR

x <= -5 ................(2b1)

)

which expands to

(1a) and (2a1)   OR  (1a) and (2b1)

( x >= -7 and x >= 3 )  OR ( x >= -7 and x <= -5 )

Simplifying, we have

x >= 3  OR ( -7 <= x <= -5 )

Referring to attached figure, the domain is indicated in dark (purple), the red-brown and white regions satisfiy only one of the two conditions.

Answer:

69

Step-by-step explanation:

Answer:

convert them to decimasls

Step-by-step explanation:

convert thhem to decimals to make it easier

Answer:

1/2 2/4 4/8 6/12 9/18

Step-by-step explanation:

Answer:

1 1/2 miles / hour

Step-by-step explanation:

We want distance / time

3/4 miles

---------------

1/2 hour

3/4 ÷ 1/2

Copy dot flip

3/4 * 2/1

3/2

1 1/2 miles / hour

Answer:

D

Step-by-step explanation:

Multiple (3/4)  by 2 to find the information for one hour)

6/4 in one hour

3/2 or 1 + 1/2 mi/h

D is the answer

Answer:

The correct ans is..... ( which i believe )

3rd option

Hope this helps...

Pls mark my ans as brainliest

If u mark my ans as brainliest u will get 3 extra points

Answer:

3rd option

Step-by-step explanation:

because 2/5 of 40 is equal to 16, and thats the equivelent of the pants sold.

Answer:

Tessa has 3 ice-cream scoops

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

If a number and a variable were together in a term, the number would the the coefficient. The coefficient would multiply the variable.

In '6x', the number '6' is the coefficient. '6' would be multiplying 'x'.

The correct answer should be 6.  

Answer:

sqrt of (m-7) = n+3

m = (n+3)^2 + 7 or m= n^2 + 6n + 16

sqrt of (m)-7 = n+3

m = (n+10)^2 or m =n^2 + 20n + 100

Step-by-step explanation:

(2) move the constants to the other side, and square

or  (1) square and move constants

then you can solve for m

Answer:

[tex]n^2+6n+16[/tex]

Step-by-step explanation:

I'm going to assume you meant [tex]\sqrt{m-7} = n+3[/tex], not  [tex]\sqrt{m} - 7 = n+3[/tex].

[tex](\sqrt{m-7}) ^2 = (n+3)^2\\\\(\sqrt{m-7}^2) = (n+3)^2\\\\(m-7)^{\frac{2}{2} } = (n+3)^2\\\\m - 7 = (n+3)^2\\\\m - 7 = n^2 + 2n\cdot3 + 3^2\\\\m - 7 = n^2 + 6n + 9\\\\m - 7 + 7 = n^2 + 6n + 9 + 7\\\\m = n^2 + 6n + 16[/tex]

Hope this helped!

Answer:

In 7, seven kids checked out 7. [tex]7*7=49[/tex] (Correct answer because 49 is the biggest number here)

In 1, only two kids checked out 1. [tex]1 *2=2[/tex] (Wrong answer because 2 is lower than 49)

In 4, only eight kids checked out 4. [tex]4*8=32[/tex] (Wrong answer because 32 is lower than 49)

In 12, only two kids checked out 12. [tex]12*2=24[/tex] (Wrong answer because 24 is lower than 49)

So 7 is the correct answer because [tex]7*7=49[/tex] is the greatest equation here.

The 0 and 11 number book is the typical book one student checked out.

Given, the dot plot shows the no. of book  each student checked out from the library last month.

Since each dot represent a different student, so clearly from the dot plot the 8 number book is checked out by the most of the students because it has most of the dots.

Since the number 0 and 11 has only one dot it represent that only 1 student checked out these books last month.

Hence the 0 and 11 number book is the typical book one student checked out.

For more details on dot plot follow the link:

https://brainly.com/question/4398979

Answer:

1. EF = 65m

2. DF = 73m

Step-by-step explanation:

1. EF = height of the building = h = 33 / tan 27 = 65m

2. DF = sqrt (65² + 33²) = 73m

The building is 64.76 meters long and 73 meters far from the top of the building to the tip of the shadow.

From the triangle DEF, we find the value of EF by using tan function.

tan function is a ratio of opposite side and adjacent side.

tan(27)= 33/FE

0.5095 = 33/FE

Apply cross multiplication:

FE=33/0.5095

FE=64.76

Now DF is the hypotenuse, we find it by using pythagoras theorem.

DF²=DE²+EF²

DF²=33²+64.76²

DF²=1089+4193.85

DF²=5282.85

Take square root on both sides:

DF=72.68

In a triangle the the sum of three angles is 180 degrees.

∠D + 27 +90 =180

∠D + 117 =180

Subtract 117 from both sides:

∠D =63 degrees.

Hence, the building is 64.76 meters long and 73 meters far from the top of the building to the tip of the shadow.

To learn more on trigonometry click:

https://brainly.com/question/25122835

#SPJ4

Answer:

x=4      or    x= - 16

Step-by-step explanation:

|x+6|

Now subtract 7 which equals to 3.

|x+6|-7=3

|x+6|=10

Now remove the mode by adding plus minus sign in the front of 10.

x+6=±10

x+6=10 or x+6=-10

x=4      or x=-16

Answer:

The first one

Step-by-step explanation:

This line is the best fit for the scatter plot because it touches a lot more points than the second

Answer:

The first line

Step-by-step explanation:

Hey there!

Well the first lie is a positive slope just like the dots whereas,

the second line is a negative slope.

Therefore, the first line is the line of best fit.

Hope this helps :)

Answer:

5

12

0

range

Step-by-step explanation:

i just did it, these are the right answers.

Answer:

5,12,0, and the last answer is range

Step-by-step explanation:

Did it on Edge2021. Hope this helps!

Answer:

140°

Step-by-step explanation:

The circle has a central angle of 80. This means that the arc it intercepts is also 80°. Therefore, the rest of the circle not intercepted by the arc is 360-80=280°

Remember that inscribed angles have one-half of the arc-length it intercepts. We can see that Angle C intercepts the entire circle except for the arc intercepted by Angle O. Therefore, the arc intercepted by Angle C is 280°. This means that Angle C is the half of 280, or 140°.

Answer:  see proof below

Step-by-step explanation:

You will need the following identities to prove this:

[tex]\tan\ (\alpha-\beta)=\dfrac{\tan \alpha-\tan \beta}{1+\tan \alpha\cdot \tan \beta}[/tex]

[tex]\cos\ 2\alpha=\cos^2 \alpha-\sin^2\alpha[/tex]

LHS → RHS

[tex]\dfrac{2\tan\ (45^o-A)}{1+\tan^2\ (45^o-A)}\\\\\\=\dfrac{2\bigg(\dfrac{\tan\ 45^o-\tan\ A}{1+\tan\ 45^o\cdot \tan\ A}\bigg)}{1+\bigg(\dfrac{\tan\ 45^o-\tan\ A}{1+\tan\ 45^o\cdot \tan\ A}\bigg)^2}\\\\\\=\dfrac{2\bigg(\dfrac{1-\tan\ A}{1+\tan\ A}\bigg)}{1+\bigg(\dfrac{1-\tan\ A}{1+\tan\ A}\bigg)^2}\\\\\\=\dfrac{2\bigg(\dfrac{1-\tan A}{1+\tan A}\bigg)}{1+\bigg(\dfrac{1-2\tan\A+\tan^2 A}{1+2\tan A+\tan^2A}\bigg)}\\[/tex]

[tex]=\dfrac{2\bigg(\dfrac{1-\tan A}{1+\tan A}\bigg)}{\dfrac{(1+2\tan A+\tan^2A)+(1-2\tan A+\tan^2 A)}{1+2\tan A+\tan^2A}}\\\\\\=\dfrac{2\bigg(\dfrac{1-\tan A}{1+\tan A}\bigg)}{\dfrac{2+2\tan^2A}{1+2\tan A+\tan^2A}}\\\\\\=\dfrac{2\bigg(\dfrac{1-\tan A}{1+\tan A}\bigg)}{2\bigg(\dfrac{1+\tan^2A}{(1+\tan A)^2}\bigg)}\\\\\\=\dfrac{\bigg(\dfrac{1-\tan A}{1+\tan A}\bigg)}{\bigg(\dfrac{1+\tan^2A}{(1+\tan A)^2}\bigg)}[/tex]

[tex]=\dfrac{1-\tan A}{1+\tan A}}\times \dfrac{(1+\tan A)^2}{1+\tan^2A}\\\\\\=\dfrac{1-\tan^2 A}{1+\tan^2 A}\\\\\\=\dfrac{1-\dfrac{\sin^2 A}{\cos^2 A}}{1+\dfrac{\sin^2 A}{\cos^2 A}}\\\\\\=\dfrac{\bigg(\dfrac{\cos^2 A-\sin^2 A}{\cos^2 A}\bigg)}{\bigg(\dfrac{\cos^2 A+\sin^2 A}{\cos^2 A}\bigg)}\\\\\\=\dfrac{\cos^2 A-\sin^2 A}{\cos^2 A+\sin^2 A}\\\\\\=\dfrac{\cos^2 A-\sin^2 A}{1}\\\\\\=\cos^2 A-\sin^2 A\\\\\\=\cos 2A[/tex]

cos 2A = cos 2A   [tex]\checkmark[/tex]

Answer:

x = 69°

Step-by-step explanation:

1). JFGHI is a pentagon, every angle in a Pentagon is equal to 108°.

2). angle JIH + angle HIE = 180°; angle JIH = 108, so angle HIE = 72°.

3).  angle JDI is equal to 39° and angle IEH; so angle IEH = 39°

4). Now we know 2 out of the three angles in the triangle IHE, so we can find x!

5). x + angle HIE + angle IEH = 180°

    x + 72° + 39° = 180°

    x = 69°

[tex]k+\frac{k}{2}+\frac{k}{6}=120\\\\6k+3k+k=720\\10k=720\\k=72[/tex]

72,36,12

answer: 36

Answer:

h(x + 1) = (x+3)(x-1)

Step-by-step explanation:

Simply plug the value of x+1 into the equation for x.

h(x) = x^2 - 4

h(x + 1) = (x + 1)^2 - 4

h(x + 1) = x^2 + 2x + 1 - 4

h(x + 1) = x^2 + 2x - 3

h(x + 1) = (x+3)(x-1)

Cheers.

Answer:

h(t)= t² - 2t -3

Step-by-step explanation:

h(x+1)= x²-4 is the given function

We can write it x²-4 as:

Substituting x+1  with  t. Then function is:

or

Answer:

240 inches cubed

Step-by-step explanation:

Volume equals length times width times height. Imagine the net is folded into its shape. The product of the base, 6 x 10 = 60, and the height, 4, equals 240. Remember that each square accounts for two inches. Hope this helps.

Answer:

The correct option is;

Left object volume = right object volume

Step-by-step explanation:

The shapes given in the question are two circular cones that have equal base radius and equal height

The formula for the volume, V of a circular cone = 1/3 × Base area × Height

The base area of the two shapes are for the left A = π·r², for the right A = π·r²

The heights are the same, therefore, the volume are;

For the left

[tex]V_{left}[/tex] = 1/3×π·r²×h

For the right

[tex]V_{right}[/tex] = 1/3×π·r²×h

Which shows that

1/3×π·r²×h  = 1/3×π·r²×h and [tex]V_{left}[/tex]  = [tex]V_{right}[/tex], therefore, the volumes are equal and the correct option is left object volume = right object volume.

Answer:

[tex]3 + 3^2 + 3^3 ...+ 3^n = \frac{3(3^n - 1)}{2}[/tex]

Step-by-step explanation:

Given

[tex]3 + 3^2 + 3^3 ...+ 3^n[/tex]

Required

Show that the sum of the series is [tex]\frac{3(3^{n}-1)}{2}[/tex]

The above shows the sum of a geometric series and this will be calculated as shown below;

[tex]S_n = \frac{a(r^n - 1)}{r - 1}[/tex]

Where

a = First term;

[tex]a = 3[/tex]

r = common ratio

[tex]r = \frac{3^2}{3} = \frac{3^3}{3^2}[/tex]

[tex]r = 3[/tex]

Substitute 3 for r and 3 for a in the formula above;

[tex]S_n = \frac{a(r^n - 1)}{r - 1}[/tex] becomes

[tex]S_n = \frac{3(3^n - 1)}{3 - 1}[/tex]

[tex]S_n = \frac{3(3^n - 1)}{2}[/tex]

Hence;

[tex]3 + 3^2 + 3^3 ...+ 3^n = \frac{3(3^n - 1)}{2}[/tex]

Answer:

1st triangle:

sin(C): 0.64, [tex]\frac{16}{25}[/tex]

cos(C): 0.8, [tex]\frac{4}{5}[/tex]

Second triangle:

sin(C): 0.75, [tex]\frac{\sqrt{5} }{3}[/tex]

cos(C): 0.67, [tex]\frac{2}{3}[/tex]

Step-by-step explanation:

Using SOH CAH TOA, we know that to find the sin of an angle, it's Opposite/Hypotenuse.

To find the cos of an angle, it's adjacent/hypotenuse.

In the 1st triangle:

The adjacent to C is 16, the hypotenuse is 25.

[tex]\frac{16}{25} = 0.64[/tex] is the sin of C.

The adjacent to C is 20, and the hypotenuse is 25.

[tex]\frac{20}{25} = 0.8[/tex] is the cos of C.

In the second triangle:

The opposite to C is [tex]\sqrt{5}[/tex] and the hypotenuse is 2.

[tex]\frac{\sqrt{5} }{2} \approx0.75[/tex] is the sin of C.

The adjacent to C is 2 and the hypotenuse is 3.

[tex]\frac{2}{3} \approx 0.67[/tex] is the cos of C.

Hope this helped!

Answer:

y > 9

Step-by-step explanation:

The range of a function is the interval of all possible y-values that make the function true.

Here, one way to figure this out is to look at a graph of the function (see attachment).

From the graph, we can see that y-values approach very closely the value 9 and then the line rises beyond 9 forever. Thus, we can conclude that the range for f(x) is y > 9.

~ an aesthetics lover

Answer:

she bought 7 cards

Step-by-step explanation

7x5=35 and im sure there is tax

Answer:

[tex]\Large \boxed{b=2}[/tex]

Step-by-step explanation:

-5+2(10b-2)=31

Expand brackets.

-5+20b-4=31

-9+20b=31

Add 9 on both sides.

20b=40

Divide both sides by 20

b=2

Answer:

Step-by-step explanation:

-5+2(10b-2)=31

Multiply the terms in the bracket

That's

- 5 + 20b - 4 = 31

Group like terms

Send the constants to the right side of the equation

That's

20b = 31 + 4 + 5

Simplify

20b = 40

Divide both sides by 20

We have the final answer as

Hope this helps you