If you run half a mathron in 2 hours 6 minutes how long does it take you to run 1km

A van can carry 12 students, and a bus can carry 36 students. The senior class at NAHS rented and filled 6 vans and 12 buses with 504 students.

To determine how many students a van can carry and how many students a bus can carry, we can use a system of equations based on the given information.

Let's assume that the number of students a van can carry is "v" and the number of students a bus can carry is "b".

According to the information provided:

The senior class at NAHS rented and filled 6 vans and 12 buses with a total of 504 students.

The senior class at FCHS rented and filled 2 vans and 5 buses with a total of 204 students.

Based on these conditions, we can form the following equations:

Equation 1: 6v + 12b = 504

Equation 2: 2v + 5b = 204

We now have a system of two equations with two unknowns (v and b). We can solve this system to find the values of v and b.

Let's solve the system using any preferred method, such as substitution or elimination.

Multiplying Equation 2 by 6, we get:

12v + 30b = 1224

Subtracting this equation from Equation 1, we can eliminate v:

6v + 12b - (12v + 30b) = 504 - 1224

-6v - 18b = -720

Simplifying this equation, we get:

-6v - 18b = -720

Dividing this equation by -6, we obtain:

v + 3b = 120

Now we have a new equation:

v + 3b = 120 -------------- Equation 3

We can now solve Equations 2 and 3 as a new system of equations.

Multiplying Equation 3 by 2, we get:

2v + 6b = 240

Subtracting this equation from Equation 2, we can eliminate v:

2v + 5b - (2v + 6b) = 204 - 240

b = -36

Dividing both sides of the equation by -1, we find:

b = 36

Now, substituting the value of b back into Equation 3:

v + 3(36) = 120

v + 108 = 120

v = 12

Therefore, a van can carry 12 students, and a bus can carry 36 students.

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The original price of the refurbished phone before the 35% discount was £120. If a refurbished phone is sold at a 35% discount with a final price of £78.

To find the original price of a refurbished phone before the discount of 35%, let's use the following formula:

discount = original price - discounted price

35% of the original price can be represented as 0.35 times the original price. This will result in the equation below:

0.35x = original price - 78

Where x is the original price. So, to find the value of x, we can rearrange the equation to get:

0.35x + 78 = original price

Now we substitute the given values into the equation above:

0.35x + 78 = original price

0.35x + 78 = x - 44.1 (if x represents the original price)

Let's subtract 0.35x from both sides to isolate the x variable:

78 = 0.65x

Then, let's divide both sides by 0.65 to solve for x (the original price):

x = £120

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A manufacturing company has determined that the daily revenue R(n) in thousands of dollars is given by the formula R(n) = 12n - 0.6n where n represents the number of palettes of product sold (0 < n < 500).

If the company wishes to make a revenue of 45 thousand dollars, we are supposed to find the number of palettes of product sold .Solution :Let us substitute the value of R(n) = 45 in the given equation and solve for n45 = 12n - 0.6n45 = 11.4n, n = 3.9474Hence, the manufacturing company has to sell either 3 or 4 palettes of product to make $45.000.

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The Apostle Paul demonstrates humility in Acts 15:36-39 and 2 Timothy 4:11 through his willingness to resolve differences. In these passages, Paul's actions and attitudes reflect his humility and his desire for reconciliation and unity among believers.


In Acts 15:36-39, Paul and Barnabas had a disagreement regarding taking John Mark on a missionary journey. Barnabas wanted to bring John Mark along, but Paul did not because John Mark had previously left them on a previous journey. Despite the disagreement, Paul shows humility by accepting Barnabas' decision and allowing him to take John Mark as his companion, while Paul chooses Silas as his own companion. This act demonstrates Paul's willingness to prioritize unity and reconciliation over personal preferences.

In 2 Timothy 4:11, Paul shows humility by reconciling with John Mark. He requests Timothy to bring Mark with him because Paul considers Mark to be helpful in his ministry. This shows a change in Paul's attitude towards Mark, indicating that he was willing to put aside any past differences and extend forgiveness and acceptance. Paul's willingness to reconcile and work alongside Mark reveals his humility and his understanding of the importance of resolving differences for the sake of the Gospel and the unity of believers.

Overall, both passages highlight Paul's humility through his willingness to resolve differences and prioritize unity, showcasing his desire for reconciliation and harmony among fellow believers.

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To find the ratio of the area of 11 million km² to the area of the Pacific Ocean (165 million km²), we can express it as a fraction:

Ratio = Area of 11 million km² / Area of the Pacific Ocean

Ratio = 11 million km² / 165 million km²

To simplify the fraction, we can divide both the numerator and the denominator by 11 million:

Ratio = (11 million km² / 11 million km²) / (165 million km² / 11 million km²)

Ratio = 1/15

Therefore, the ratio of the area of 11 million km² to the area of the Pacific Ocean is 1/15.

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a) The gradient of the line passing through the points (0,6) and (3,0) is -2. b) The gradient of the line perpendicular to this line is 1/2. c) The equation for the line passing through point a and perpendicular to the line ab can be determined using the point-slope form of a linear equation.

a) To find the gradient (slope) of the line passing through (0,6) and (3,0), we use the formula: gradient = (change in y) / (change in x). Substituting the coordinates, we get (-6) / (3-0) = -2.

b) The gradient of a line perpendicular to another line is the negative reciprocal of the original gradient. Therefore, the gradient of the line perpendicular to the given line is 1/2.

c) To find the equation of the line passing through point a and perpendicular to line ab, we can use the point-slope form of a linear equation: y - y1 = m(x - x1), where (x1, y1) is point a and m is the gradient of the perpendicular line. Substituting the values, we get y - 6 = (1/2)(x - 0), which simplifies to y = (1/2)x + 6.

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Answer:

for 1.

Step-by-step explanation:

the formula is pir2h

The cheetah can reach speeds of up to 70 miles per hour (112 kilometers per hour) in short bursts. Assuming the cheetah maintained its maximum speed throughout the entire 10-minute sprint, we can estimate the distance traveled.

To estimate the distance traveled by the cheetah, we can calculate the distance covered by assuming a constant speed. The maximum speed of a cheetah is typically cited as 70 miles per hour.

First, we need to convert the time from minutes to hours. Since there are 60 minutes in an hour, 10 minutes is equal to 10/60 = 1/6 hour.

Distance = Speed × Time

Distance = 70 miles per hour × (1/6) hour

Distance ≈ 11.67 miles

Therefore, if the cheetah maintained its maximum speed of 70 miles per hour throughout the entire 10-minute sprint, it would have traveled approximately 11.67 miles. It is important to note that this is an estimation, as actual sprinting distances may vary depending on factors such as terrain, fatigue, and acceleration patterns.

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Complete question: The cheetah sprinted at maximum speed for 10 minutes, how far would the cheetah have traveled?

To calculate the amount of sand Maija should order, we need to find the volume of the sandbox. The sandbox is in the shape of a cube, so its volume is determined by multiplying the length, width, and height.

Given that the sides of the square sandbox are 2 feet long and the desired depth of the sand is 1.55 feet, we can calculate the volume as follows:

[tex]\[ \text{Volume} = \text{Length} \times \text{Width} \times \text{Height} \][/tex]

Since all sides of the sandbox are equal in length (2 feet), the formula simplifies to:

[tex]\[ \text{Volume} = \text{Side}^3 \][/tex]

Substituting the values:

[tex]\[ \text{Volume} = 2 \, \text{ft} \times 2 \, \text{ft} \times 1.55 \, \text{ft} \][/tex]

[tex]\[ \text{Volume} = 6.2 \, \text{cubic feet} \][/tex]

Therefore, Maija should order 6.2 cubic feet of sand for her sandbox.

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To find out how much wire will be needed to put a double fence around a square plot with 50m, we first need to calculate the perimeter of the square plot.

Perimeter of a square = 4 x SideWhere Side = 50mPerimeter = 4 x 50m = 200mNow, since we need to put a double fence around the square plot, we will multiply the perimeter by 2. Therefore, the total length of wire needed for double fencing = 200m x 2 = 400m. Therefore, 400m of wire will be needed to put a double fence around a square plot with 50m.Long Answer:The given plot is a square with the side of the square being 50m. To find out the amount of wire needed to put a double fence around the square plot, we first need to calculate the perimeter of the square plot.A square is a 4 sided figure with all sides of equal length.

Therefore, the perimeter of a square can be calculated by multiplying the length of one side of the square with 4, as shown below.Perimeter of a square = 4 x SideWhere Side is the length of one side of the square plot.In this case, the side of the square plot is given as 50m. Therefore, the perimeter of the square plot can be calculated as shown below:Perimeter of a square = 4 x 50m = 200mTherefore, the perimeter of the square plot is 200m.Now, since we need to put a double fence around the square plot, we will multiply the perimeter by 2. This is because a double fence means that we will be putting two fences back to back around the perimeter of the square plot. Therefore, the total length of wire needed for double fencing can be calculated as shown below:Total length of wire needed for double fencing = 2 x Perimeter of the square plotTotal length of wire needed for double fencing = 2 x 200mTotal length of wire needed for double fencing = 400mTherefore, 400m of wire will be needed to put a double fence around a square plot with 50m.

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I agree with Rita. Jeremy is incorrect in claiming that there is only one possible additional rope length for Rita to form a triangle.

To form a triangle, the sum of the lengths of any two sides must be greater than the length of the third side. In this case, Rita has two rope lengths of 9 feet and 1 foot. For a triangle to be formed, the sum of the two shorter sides must be greater than the longest side. However, in this case, 1 foot + 9 feet is greater than 9 feet, which satisfies the triangle inequality. Therefore, Rita can form a triangle with these two rope lengths.

Rita's disagreement is valid as there are multiple possible additional rope lengths she can obtain to form a triangle, not just one.

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Mrs. Rodriguez sold 128.8 ounces of popcorn.We know that each bag of popcorn weighs 2.3 ounces. Therefore, to find out the total amount of popcorn Mrs. Rodriguez sold in 56 bags, we need to multiply 2.3 by 56. That is;2.3 × 56 = 128.8Therefore, there are 128.8 ounces of popcorn in 56 bags

We are given that Mrs. Rodriguez is selling popcorn at the snack stand. Each bag holds 2.3 ounces of popcorn. In one hour, she sold 56 bags of popcorn. Our task is to find out how many ounces of popcorn are in 56 bags.In order to find out how many ounces of popcorn are in 56 bags, we need to first find out the weight of one bag of popcorn. We are told that each bag holds 2.3 ounces of popcorn. So, we have:

Weight of one bag of popcorn = 2.3 ounces Now, we can use this information to calculate the total weight of popcorn Mrs. Rodriguez sold in 56 bags. To do this, we need to multiply the weight of one bag of popcorn (2.3 ounces) by the number of bags she sold (56). That is;Weight of 56 bags of popcorn = 2.3 × 56= 128.8Therefore, Mrs. Rodriguez sold 128.8 ounces of popcorn in one hour.

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The test procedure that should be used would be hypothesis testing and power analysis. The sample size would be 6.

The null hypothesis (H₀) is that the pH is equal to 8.20, and the alternative hypothesis (H₁) is that the pH differs from 8.20 by more than 0.03, i.e., pH < 8.17 or pH > 8.23.

To ensure a type I error probability (rejecting H₀ when it is true) of 0.05 (1-0.95), we set our significance level α = 0.05. Therefore, if we calculate a sample mean pH that falls into the critical regions (mean pH < 8.17 or mean pH > 8.23), we would reject the null hypothesis.

Given the standard deviation (σ) is 0.02, we can use the formula for calculating the sample size:

n = [(Z_α/2 + Z_β)σ/Δ]²

Let's substitute the values:

n = [(1.96 + 1.645) * 0.02 / 0.03]²

n = [3.605 * 0.02 / 0.03]²

n = [0.0721]²

n = 5.2

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To determine the measure of angle DAB, we need to use the congruence of quadrilaterals ABCD and AMCG.

Quadrilateral ABCD is congruent to quadrilateral AMCG.

Since the two quadrilaterals are congruent, their corresponding angles are equal. Therefore, we can write:

m∠DAB = m∠MAC

However, the measure of angle MAC is not given in the given information. Therefore, without additional information, we cannot determine the exact measure of angle DAB.

The options provided in the question do not correspond to the measure of angle DAB. Therefore, the correct answer cannot be determined based on the given information.

It is important to have additional information about the measures of angles or the side lengths in order to determine the measure of angle DAB accurately.

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The new pressure of the balloon at the higher altitude, when it occupies 1.5 L and is at 14.0 °C, is approximately 25.46 atm/°C.

To find the new pressure of the balloon when it is brought to a higher altitude, we can use the combined gas law equation:

P1V1/T1 = P2V2/T2

Given:

P1 = 0.945 atm (initial pressure)

V1 = 3 L (initial volume)

T1 = 39.0 °C (initial temperature)

V2 = 1.5 L (final volume)

T2 = 14.0 °C (final temperature)

Substituting the given values into the equation, we have:

(0.945 atm)(3 L)/(39.0 °C) = P2(1.5 L)/(14.0 °C)

Simplifying the equation:

2.727 atm/°C = 0.1071P2

To isolate P2, we divide both sides by 0.1071:

P2 = 2.727 atm/°C / 0.1071

P2 ≈ 25.46 atm/°C

Therefore, the new pressure of the balloon at the higher altitude, when it occupies 1.5 L and is at 14.0 °C, is approximately 25.46 atm/°C.

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There will be 22544 rabbits living in the neighbour's yard after 12 months.

The given problem states that the size of Marjorie and Harold Rabbit's family doubles one month later and continues to double every month thereafter.

It is required to find the number of rabbits that will be living in the neighbours yard after 12 months.

The given data can be organized in a tabular form as follows:

Time (in months)

Number of rabbits at the end of the month

01 (at birth)

2 (after one month)

24(after two months)

28(after three months)

216(after four months)

232(after five months)

264 (after six months)

2128(after seven months)

2256(after eight months)

24192(after nine months)

28384 (after ten months)

267,68 (after eleven months)

225,44 (after twelve months)

Yes, it is quite possible that they will notice this huge number of rabbits in their yard.

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To calculate the probability that the placekicker will make 4 out of 5 attempts from the 20-yard line, we can use the binomial probability formula:

[tex]\[ P(k) = \binom{n}{k} \cdot p^k \cdot (1-p)^{n-k} \][/tex]

Where:

- P(k) is the probability of getting exactly k successes,

- n is the number of trials or attempts (5 in this case),

- k is the number of desired successes (4 in this case), and

- p is the probability of success on a single trial (0.85 in this case).

Using the formula, we can calculate the probability as follows:

[tex]\[ P(4) = \binom{5}{4} \cdot 0.85^4 \cdot (1-0.85)^{5-4} \][/tex]

Simplifying the expression, we have:

[tex]\[ P(4) = 5 \cdot 0.85^4 \cdot 0.15^1 \][/tex]

Evaluating this expression, we find:

[tex]\[ P(4) \approx 0.311 \][/tex]

Therefore, the probability that the placekicker will make 4 out of 5 attempts from the 20-yard line is approximately 0.311 (or 31.1%) (option C).

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The mean train ride time for the week was 49.4 minutes, with a median of 48 minutes. The range of the train ride times was 3 minutes.

The mean, median, and range of Santos' train ride times for the week were as follows:

Mean: 49.4 minutes

The mean is calculated by adding up all the values and dividing the sum by the total number of values. In this case, the sum of the train ride times (48 + 51 + 48 + 48 + 50) is 245 minutes. Dividing this sum by the total number of days (5), we get the mean of 49.4 minutes.

Median: 48 minutes

The median is the middle value in a sorted list of numbers. To find the median, we arrange the train ride times in ascending order: 48, 48, 48, 50, 51. Since there is an odd number of values, the middle value is the median. In this case, the median is 48 minutes.

Range: 3 minutes

The range is the difference between the largest and smallest values in a set. To calculate the range, we subtract the smallest value (48 minutes) from the largest value (51 minutes). In this case, the range of the train ride times for the week is 3 minutes.

In summary, the mean train ride time for the week was 49.4 minutes, with a median of 48 minutes. The range of the train ride times was 3 minutes. These metrics provide insights into the average, central tendency, and variability of Santos' train rides throughout the week.

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The equation that can be used to determine the cost of a pound of oranges is 4.35x = 3.60 + (5/6) where x represents the cost of a pound of oranges.

Hence, the answer is "4.35x = 3.60 + (5/6)". Let's justify this. The cost of the gallon of milk is given as $3.60. The quantity of milk Kendra bought is not relevant in the context of the problem, but we are given the quantity of oranges Kendra bought. Kendra bought Start Fraction 5 over 6 End Fraction of a pound of oranges.

Now, let the cost of a pound of oranges be x. Kendra bought Start Fraction 5 over 6 End Fraction of a pound of oranges, hence the cost of Start Fraction 5 over 6 End Fraction of a pound of oranges is (5/6)x = $4.35 - $3.60 (the total amount spent subtracted by the amount spent on milk).Now, we simplify the equation 4.35x = 3.60 + (5/6). Therefore, we can write that the cost of a pound of oranges is 4.35x = 3.60 + (5/6). Hence, the answer is "4.35x = 3.60 + (5/6)".Therefore, the correct option is D: 4.35 x (5/6) = 3.60.

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The inverse operation used to solve the equation x/7 = 5 is multiplication

Inverse operations are mathematical operations that reverse or undo each other. To isolate the variable, inverse operations are used. For example, addition and subtraction are inverse operations, as are multiplication and division.

In an equation, inverse operations can be used to solve for a variable. In order to solve the equation x/7 = 5, we will use inverse operations.The inverse operation of division is multiplication. So, we can isolate x by multiplying both sides of the equation by 7.x/7 = 5Multiplying both sides by 7 gives:x = 7 × 5x = 35Therefore, x = 35 is the solution to the equation.

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In Part B, the expression developed was 10 + 6b. To rewrite it as a single term with a fractional coefficient, we need to combine 10 and 6b into a single term.

Let's begin by multiplying 6 by b, then adding the result to 10.6b can be expressed as 6/1 multiplied by b. Then, we add it to 10:10 + 6/1 × bCommon denominator is 1, so we can add 10 to 6b as follows:10 + 6/1 × b/1 = 10/1 + 6b/1 = (10 + 6b)/1Therefore, the expression 10 + 6b is the same as (10 + 6b)/1. Its single term with a fractional coefficient is (10 + 6b)/1 = 10/1 + 6b/1 = (10 + 6b)/1.

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We have to find the ratio of Ms Seema's annual spending to her annual savings given that Ms. Seema's annual salary is Rs 288000 and her annual savings is Rs 72000.

The first step is to determine the annual spending of Ms. Seema.Subtracting the annual savings of Ms. Seema from her annual salary, we can determine her annual spending. Annual spending = Rs 288000 - Rs 72000 = Rs 216000We now know that Ms. Seema's annual spending is Rs 216000 per year and her annual savings is Rs 72000 per year.

We can now compute the ratio of her annual spending to her annual savings. Annual spending : Annual savings= 216000 : 72000= 3 : 1Therefore, the ratio of Ms. Seema's annual spending to her annual savings is 3 : 1. It implies that her annual spending is three times the annual savings.In conclusion, the ratio of Ms. Seema's annual spending to her annual savings is 3 : 1.

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This means that the expression 10x² + 2x - 8  completely factored as 2(5x - 2)(x + 2).

The correct factored form of the expression 10x² + 2x - 8 is:

2(5x - 2)(x + 2).

To factor the quadratic expression completely for common factors first that the coefficient 2 is a common factor in all three terms. After factoring out 2, left with (5x² + x - 4).

An factor the trinomial (5x² + x - 4). However, this trinomial cannot be factored further using integer coefficients.

So, the factored form of the expression is 2(5x - 2)(x + 2).

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The missing side lengths are x = 4 and y = 4.The correct answer choice is D) x = 4, y = 4.

To find the missing side lengths in a triangle, we can use trigonometric ratios. In this case, we are given the length of one side (8) and the measure of one angle (30 degrees), and we need to find the lengths of the other two sides (x and y).

In a right triangle, the trigonometric ratios can be used to relate the angles and side lengths. In this case, we are not given that the triangle is a right triangle, so we will assume it is not.

The sine ratio relates the ratio of the length of the side opposite an angle to the length of the hypotenuse. In this case, the side opposite the 30-degree angle is y, and the hypotenuse is 8. So we can write:

sin(30 degrees) = y/8

Using the known value of sin(30 degrees) = 1/2, we can solve for y:

1/2 = y/8

Cross-multiplying, we get:

y = 4

So we have found the length of side y to be 4.

To find the length of side x, we can use the law of sines. The law of sines states that the ratio of the length of a side to the sine of its opposite angle is constant for all sides and angles in a triangle.

Using the law of sines, we can write:

sin(30 degrees)/x = sin(angle opposite x)/8

Since we know the sine of 30 degrees is 1/2, we can rewrite the equation as:

(1/2)/x = sin(angle opposite x)/8

Since the angle opposite x is 180 degrees - 30 degrees = 150 degrees, we have:

(1/2)/x = sin(150 degrees)/8

Using the known value of sin(150 degrees) = 1/2, we can solve for x:

(1/2)/x = 1/2/8

Cross-multiplying, we get:

x = 4

So we have found the length of side x to be 4.

Therefore, the missing side lengths are x = 4 and y = 4.

The correct answer choice is D) x = 4, y = 4.

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The two villages are approximately 225 kilometers apart.

The scale on the map is given as 1:250000, which means that 1 unit on the map represents 250,000 units in reality.

If the distance between the villages on the map is 9 cm, we can set up the following proportion:

1 cm / 250,000 km = 9 cm / x km

Cross-multiplying, we have:

1 * x km = 9 cm * 250,000 km

x km = 2,250,000 km / 1 cm

Simplifying the expression, we find:

x km = 225 km

Therefore, the two villages are approximately 225 kilometers apart.

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The inequality that represents the largest number of food Sammy can buy, given her budget, is 2.75x ≤ 43.75 - 9.25, where x represents the number of food items she can purchase.

To find the inequality representing the largest number of food items Sammy can buy, we need to consider her budget and the cost of admission and food. Let x be the number of food items she can purchase.

The cost of admission is $9.25, which needs to be subtracted from her total budget. The remaining amount can be used to purchase food. Each food item costs $2.75.

Therefore, the inequality can be written as 2.75x ≤ 43.75 - 9.25, where the left side represents the cost of the food (2.75x), and the right side represents the remaining budget after deducting the admission fee (43.75 - 9.25).

By solving this inequality, Sammy can determine the largest number of food items (represented by x) that she can afford to buy within her budget.

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Cindy has scores of 72, 82, 83 and 89 on her Biology tests. Cindy must score between 68 and 89 on her final exam to earn a C in Biology.

Cindy's current average score in Biology is:

(72 + 82 + 83 + 89) / 4 = 81.5

Since the final exam counts as two tests, we can calculate the total number of points Cindy can earn in the course as follows:

Total points = 4 tests + 2 tests = 6 tests

To earn a C in the course, her average score must be between 77 and 84. Let's assume she needs to score x on her final exam to achieve a C. Then her total points would be:

Total points = 72 + 82 + 83 + 89 + x + x

Simplifying this equation, we get:

Total points = 326 + 2x

To earn a C, Cindy's average score must be between 77 and 84. Therefore, we can set up an inequality:

77 <= (326 + 2x) / 6 <= 84

Multiplying both sides by 6, we get:

462 <= 326 + 2x <= 504

Subtracting 326 from all sides, we get:

136 <= 2x <= 178

Dividing by 2, we get:

68 <= x <= 89

Therefore, Cindy must score between 68 and 89 on her final exam to earn a C in Biology.

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The perimeter of the rectangle is 22 7/15 meters, and the area is 29 1/10 square meters.

To find the perimeter of a rectangle, we add the lengths of all four sides. In this case, the length of one side is 4 7/20 meters and the length of the adjacent side is 6 2/3 meters. To add these mixed numbers, we convert them to improper fractions. The first side becomes 87/20 meters and the second side becomes 20/3 meters. Adding the two lengths gives us a total of (87/20 + 20/3) meters. To add fractions with different denominators, we need to find a common denominator. The least common multiple of 20 and 3 is 60. Converting both fractions to have a denominator of 60, we get (261/60 + 400/60) meters, which simplifies to 661/60 meters. Finally, we can convert this improper fraction back to a mixed number, which is 11 1/60 meters. Since the perimeter of a rectangle is the sum of all four sides, the perimeter of this rectangle is 2 times 11 1/60 meters, which equals 22 2/60 meters or 22 7/15 meters.

To find the area of a rectangle, we multiply the length by the width. In this case, the length is 4 7/20 meters and the width is 6 2/3 meters. Converting both mixed numbers to improper fractions, we get a length of 87/20 meters and a width of 20/3 meters. Multiplying these two fractions gives us (87/20 * 20/3) square meters. Simplifying the fractions, we get (1740/60) square meters, which further simplifies to 29 square meters. Therefore, the area of this rectangle is 29 square meters.

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Answer:

Step-by-step explanation:

To enlarge a 4x6 photo with a ratio of 2:3, we can multiply the dimensions of the photo by the enlargement ratio to find the new dimensions.

Original photo dimensions: 4 inches x 6 inches

Enlargement ratio: 2:3

To find the new dimensions, we can multiply the original dimensions by the enlargement ratio:

New width = 4 inches x 2 = 8 inches

New height = 6 inches x 3 = 18 inches

Therefore, the new dimensions of the enlarged photo would be 8 inches x 18 inches.

The team's time on their final run, given the decrease in speed, would be 4. 33 minutes

On the next run, the time that the bobsled team would take is :

= 4. 85 - ( 4. 85 x 5. 5 % )

= 4. 85 - 0.26675

= 4. 58325 minutes

The run after that would see a time of :

= 4. 58325 - ( 4. 58325 x 5. 5 %)

= 4. 58325 - 0.25207875

= 4. 33 minutes

In conclusion, the  team's time on their final run, would be 4. 33 minutes.

Find out more on team runs at https://brainly.com/question/13584836

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The question is:

What was the team's time on their final run?