if you are given the graph of h(x)=log6x, how could you graph m(x)=log6(x+3)

Answer:

280 miles

Step-by-step explanation:

175/2.5

= 70

70 x 4

= 280

Answer:

5 ≤ x ≤ 10             5 ≤ y ≥ -1

Step-by-step explanation:

Answer:

A. p+q

B. (p)(q)

Step-by-step explanation:

A. The sum of the variables will be p+q, since we are just adding the two variables together.

B. The product of the variables will be (p)(q), or just pq, since you are simply multiplying the two variables.

Hope this Helps!!

Answer:

y = -x+3

Step-by-step explanation:

Slope intercept form =>  y = mx+b

To find 'm', the slope, pick 2 coordinates.

(0,3)

(2,1)

Use this equation to find the slope using these 2 coordinates: (y1 - y2)/(x1 - x2)

(3 - 1)/(0 - 2) = -1

m = slope = -1

'b' is the y-intersept, or the point when a line passes through the y-axis. That's (0,3).

b = y-intercept = 3

So the equation will be y = -1x + 3, or y = -x + 3

Answer:

19.27

Step-by-step explanation:

To find :-

Answer :-

As we know that ,

→ cos ∅ = b/h

→ cos 33° = 16/x

→ 0.83 = 16/x

→ x = 16/0.83

→ x = 19.27

Answer:

(7x + 18) or 60 Mangoes

Step-by-step explanation:

Let the no. of mangoes Kubie possesses be x

So,

Cyril has mangoes = 2x + 6  ...(i)

So,

Maxine has = 2 * (2x + 6)

= 4x + 12

Given that,

Kubie has mangoes = 6

∵ The combined mangoes they have in terms of x,

= Cyril + Kubie + Maxine

= (2x + 6) + x + (4x + 12)

= 7x + 18

A.T.Q.

Cyril has = 2x + 6

∵ Cyril has mangoes = 2 * (6) + 6

= 18 mangoes

∵ Maxine has = 2 * Cyril's mangoes

= 2 * 18

= 36

Thus,

Total mangoes = Cyril + Kubie + Maxine

= 18 + 6 + 36

= 60 Mangoes

Answer:

30 clocks

Step-by-step explanation:

Set up an equation:

Variable x = number of clocks

1200 + 20x = 60x

Isolate variable x:

1200 = 60x - 20x

1200 = 40x

Divide both sides by 40:

30 = x

Check your work:

1200 + 20(30) = 60(30)

1200 + 600 = 1800

1800 = 1800

Correct!

Answer:

-4/25

Step-by-step explanation:

3x=y+z

y=6-7=-1

z+x=8

y/z=?

solution

3x=-1 + z

x= -1 + z\3 ...eq(*)

then, z= 8- x

z= 8 - (-1 +z)\3

z= 8 +(1- z )\3

z= 8+1\3 -z \3

= 24+1\3 - z\3

z=25\3-z\3

z+z\3=25\3

4z\3=25\3

4z=25

z=25/4

then,

25/4 +x = 8

x=8- 25/4

x= 32 - 25/4

x=7/4

so that,

y/z=-1 /25/4

=-4/25

Answer:

3/2,  -1.1

Step-by-step explanation:

the probability cannot be greater than 1. probability is between 0 and 1

Answer:

Step-by-step explanation:

D is the answer. You shift the function to the left 5 units, hence the term |x+5|, and move it down 1, hence the term -1.

Answer:

z= 1.70 Since the test statistic is less than the critical​ value, we can conclude that the average length of an online video is not more than 8 minutes

Answer:

1.  c. Poisson

2. 0.9592 = 95.92% probability that in any one minute at least one purchase is​ made.

3. 0.0017 = 0.17% probability that no one makes a purchase in the next 2​ minutes.

Step-by-step explanation:

We have only the mean, which means that the Poisson distribution is used to solve this question, and thus the answer to question 1 is given by option c.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

In which

x is the number of sucesses

e = 2.71828 is the Euler number

[tex]\mu[/tex] is the mean in the given interval.

Mean of 3.2 minutes:

This means that [tex]\mu = 3.2n[/tex], in which n is the number of minutes.

2. What is the probability that in any one minute at least one purchase is​ made?

[tex]n = 1[/tex], so [tex]\mu = 3.2[/tex].

This probability is:

[tex]P(X \geq 1) = 1 - P(X = 0)[/tex]

In which

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-3.2}*3.2^{0}}{(0)!} = 0.0408[/tex]

So

[tex]P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0408 = 0.9592[/tex]

0.9592 = 95.92% probability that in any one minute at least one purchase is​ made.

3. What is the probability that no one makes a purchase in the next 2​ minutes?

2 minutes, so [tex]n = 2, \mu = 3.2(2) = 6.4[/tex]

This probability is P(X = 0). So

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-6.4}*6.4^{0}}{(0)!} = 0.0017[/tex]

0.0017 = 0.17% probability that no one makes a purchase in the next 2​ minutes.

Answer:

101 cm

Step-by-step explanation:

Add all the side lengths up to get 101 cm.

Answer:

Hello

Step-by-step explanation:

The domain is limited with 2 lines parallel: -1 ≤ x ≤ 1

and the disk ? (inside of a circle) of center (0,0) and radius 2

[tex]dom\ f(x,y)=\{(x,y) \in \mathbb{R} ^2 | \ -1\leq x \leq -1\ and \ ( -\sqrt{4-x^2} \leq \ y \leq \sqrt{4-x^2}\ ) \ \}\\[/tex]

Answer:

Step-by-step explanation:

Answer:

1/4

Step-by-step explanation:

White = w

Black = B

Blue = b1

Tan = t

Wb1

Wt

Bbi

Bt

The answer will be 1/4, because there are 4 ways it can work and only 1 way it can be white shirt and tan pants.

Answer:

1/4

Step-by-step explanation:

it would be 1/4 because there are 4 different clothing pieces in total and there is only one way it would work the way the problem says.

Answer:

(1238.845 ;1285.376)

Step-by-step explanation:

Conditions for constructing a confidence interval :

Data must be random

Distribution should be normal and independent ;

Based on the conditions above ; data meets initial conditions ;

C. I = sample mean ± margin of error

Given the data :

1241 1210 1267 1314 1211 1299 1246 1280 1291

Mean, xbar = Σx / n = 11359 / 9 = 1262.11

The standard deviation, s = [√Σ(x - xbar)²/n - 1]

Using a calculator ; s = 37.525

The confidence interval :

C.I = xbar ± [Tcritical * s/√n]

Tcritical(0.10 ; df = n - 1 = 9 - 1 = 8)

Tcritical at 90% = 1.860

C. I = 1262.11 ± [1.860 * 37.525/√9]

C.I = 1262.11 ± 23.266

(1238.845 ;1285.376)

± 23.266

The margin of error :

[Tcritical * s/√n]

[1.860 * 37.525/√9]

C.I = ± 23.266

The statement is totally false.

[tex]\neg P\lor\neg Q \equiv \neg(P \land Q) \not\equiv P\land Q[/tex]

because (P and ¬P) is a contradiction.

Answer:

Step-by-step explanation:

Number of electronic systems = 6

(a) Number of defected systems = 2

Probability of getting at least one system is defective

1 defective and 1 non defective + 2 defective

= (2 C 1 ) x (4 C 1) + (2 C 2) / (6 C 2)

= 3 / 5

(b) four defective

Probability of getting at least one system is defective

2 defective and 2 non defective + 3 defective and 1 non defective + 4 defective  

= (4 C 2 ) x (2 C 2) + (4 C 3 )(2 C 1) + (4 C 4) / (6 C 4)

= 1

Answer:

(a)P(At least one defective)[tex]=0.6[/tex]

P(Both are defective)[tex]=0.067[/tex]

(b)P(At least one defective)[tex]=14/15[/tex]

P(Both are defective)[tex]=0.4[/tex]

Step-by-step explanation:

We are given that

Total number of complex electronic system, n=6

(a)Defective items=2

Non-defective items=6-2=4

We have to find the  probability that at least one of the two systems tested will be defective.

P(At least one defective)=[tex]\frac{2C_1\times 4C_1}{6C_2}+\frac{2C_2\times 4C_0}{6C_2}[/tex]

Using the formula

[tex]P(E)=\frac{favorable\;cases}{total\;number\;of\;cases}[/tex]

P(At least one defective)[tex]=\frac{\frac{2!}{1!1!}\times \frac{4!}{1!3!} }{\frac{6!}{2!4!}}+\frac{\frac{2!}{0!2!}\times \frac{4!}{4!}}{\frac{6!}{2!4!}}[/tex]

Using the formula

[tex]nC_r=\frac{n!}{r!(n-r)!}[/tex]

P(At least one defective)[tex]=\frac{2\times \frac{4\times 3!}{3!}}{\frac{6\times 5\times 4!}{2\times 1\times 4!}}+\frac{1}{\frac{6\times 5\times 4!}{2\times 1\times 4!}}[/tex]

P(At least one defective)[tex]=\frac{2\times 4}{3\times 5}+\frac{1}{3\times 5}[/tex]

P(At least one defective)[tex]=\frac{8}{15}+\frac{1}{15}=\frac{9}{15}[/tex]

P(At least one defective)[tex]=\frac{3}{5}=0.6[/tex]

Now, the probability that both are defective

P(Both are defective)=[tex]\frac{2C_2\times 4C_0}{6C_2}[/tex]

P(Both are defective)=[tex]\frac{\frac{2!}{0!2!}\times \frac{4!}{4!}}{\frac{6!}{2!4!}}[/tex]

P(Both are defective)[tex]=\frac{1}{\frac{6\times 5\times 4!}{2\times 1\times 4!}}[/tex]

P(Both are defective)[tex]=\frac{1}{3\times 5}[/tex]

P(Both are defective)[tex]=0.067[/tex]

(b)

Defective items=4

Non- defective item=6-4=2

P(At least one defective)=[tex]\frac{4C_1\times 2C_1}{6C_2}+\frac{4C_2\times 2C_0}{6C_2}[/tex]

P(At least one defective)[tex]=\frac{\frac{4!}{1!3!}\times \frac{2!}{1!1!} }{\frac{6!}{2!4!}}+\frac{\frac{4!}{2!2!}\times \frac{2!}{2!}}{\frac{6!}{2!4!}}[/tex]

P(At least one defective)[tex]=\frac{2\times \frac{4\times 3!}{3!}}{\frac{6\times 5\times 4!}{2\times 1\times 4!}}+\frac{\frac{4\times 3\times 2!}{2!\times 2\times 1}}{\frac{6\times 5\times 4!}{2\times 1\times 4!}}[/tex]

P(At least one defective)[tex]=\frac{2\times 4}{3\times 5}+\frac{2\times 3}{3\times 5}[/tex]

P(At least one defective)[tex]=\frac{8}{15}+\frac{6}{15}=\frac{8+6}{15}[/tex]

P(At least one defective)[tex]=\frac{14}{15}[/tex]

P(Both are defective)[tex]=\frac{4C_2\times 2C_0}{6C_2}[/tex]

P(Both are defective)[tex]=\frac{\frac{4\times 3\times 2!}{2\times 1\times 2!}\times \frac{2!}{2!}}{\frac{6\times 5\times 4!}{2\times 1\times 4!}}[/tex]

P(Both are defective)[tex]=\frac{\frac{4\times 3\times 2\times 1}{2\times 1\times 2\times 1}}{3\times 5}[/tex]

P(Both are defective)[tex]=\frac{6}{15}=0.4[/tex]

P(Both are defective)[tex]=0.4[/tex]

Answer: y=2x - 48

Step-by-step explanation: y (total profit) = 2x (2 dollars times hotdogs sold) - 48 ( 48 dollars starting cost)

Answer:

Answer: y=2x - 48

Step-by-step explanation:

The value of a that would make the data in the table represent a linear function with a rate of change of -8 is a = 19.

Option D is the correct answer.

A function has an input and an output.

A function can be one-to-one or onto one.

It simply indicated the relationships between the input and the output.

Example:

f(x) = 2x + 1

f(1) = 2 + 1 = 3

f(2) = 2 x 2 + 1 = 4 + 1 = 5

The outputs of the functions are 3 and 5

The inputs of the function are 1 and 2.

We have,

The rate of change of a linear function is also known as the slope of the function.

To determine the slope of the function represented by the given table, we need to calculate the change in Y for a unit change in X.

Using the values given in the table, we can calculate the slope as follows:

Slope = (Change in Y) / (Change in X)

So,

(a - 27) / (11 - 10) = (11 - 27) / (12 - 10) = -8

Setting this equation equal to -8, we get:

= (a - 27) / 1

= -8

Simplifying the equation, we get:

a - 27 = -8

a = 19

Therefore,

The value of a that would make the data in the table represent a linear function with a rate of change of -8 is a = 19.

Learn more about functions here:

https://brainly.com/question/28533782

#SPJ7

9514 1404 393

Answer:

  a. 0.28

  b. 0.125

Step-by-step explanation:

a) We recognize 25 as a divisor of 100, a power of 10, so we can convert the fraction to one that has 100 as a denominator.

  [tex]\dfrac{7}{25}=\dfrac{7}{25}\cdot\dfrac{4}{4}=\dfrac{28}{100}=0.28[/tex]

__

b) We can convert this fraction to a decimal by dividing the numerator by the denominator. The work is shown in the attached.

  1/8 = 0.125

9514 1404 393

Answer:

  4x+10

Step-by-step explanation:

For parallelogram adjacent sides a and b, the perimeter is ...

  P = 2(a +b)

For the given sides, the perimeter is ...

  P = 2((x +3) +(x +2)) = 2(2x +5)

  P = 4x +10 . . . perimeter of the parallelogram

Answer:

im not too sure but try using a cartesuan plane and measure it precisely using a protractor then key in the measurements. Im not entirely sure its the correct method tho

Answer:

106 people.

Step-by-step explanation:

Logistic equation:

The logistic equation is given by:

[tex]P(t) = \frac{K}{1+Ae^{-kt}}[/tex]

In which

[tex]A = \frac{K - P_0}{P_0}[/tex]

K is the carrying capacity, k is the growth/decay rate, t is the time and P_0 is the initial value.

Suppose a rumor is going around a group of 191 people. Initially, only 38 members of the group have heard the rumor.

This means that [tex]K = 191, P_0 = 38[/tex], so:

[tex]A = \frac{191 - 38}{38} = 4.03[/tex]

Then

[tex]P(t) = \frac{191}{1+4.03e^{-kt}}[/tex]

3 days later 68 people have heard it.

This means that [tex]P(3) = 68[/tex]. We use this to find k.

[tex]P(t) = \frac{191}{1+4.03e^{-kt}}[/tex]

[tex]68 = \frac{191}{1+4.03e^{-3k}}[/tex]

[tex]68 + 274.04e^{-3k} = 191[/tex]

[tex]e^{-3k} = \frac{191-68}{274.04}[/tex]

[tex]e^{-3k} = 0.4484[/tex]

[tex]\ln{e^{-3k}} = \ln{0.4484}[/tex]

[tex]-3k = \ln{0.4484}[/tex]

[tex]k = -\frac{\ln{0.4484}}{3}[/tex]

[tex]k = 0.2674[/tex]

Then

[tex]P(t) = \frac{191}{1+4.03e^{-0.2674t}}[/tex]

How many people are expected to have heard the rumor after 6 days total have passed since it was initially spread?

This is P(6). So

[tex]P(6) = \frac{191}{1+4.03e^{-0.2674*6}} = 105.52[/tex]

Rounding to the nearest whole number, 106 people.

Answer:

22

Step-by-step explanation:

m1 + m2 = 180

3x - 17 + 5x + 21 = 180

3x + 5x + 21 - 17 = 180

8x + 4 = 180

8x = 180 - 4

8x = 176

x = 176 / 8

x = 22

Answer:

Step-by-step explanation:

pq = 27 = 3³

qr = 51 = 3×17

q = 3

p = 9

r = 17

Answer:

The answer is "0.7794".

Step-by-step explanation:

Please find the complete question in the attached file.

Given:

[tex]\to n_{1}=n_{2}=25\\\\[/tex]

Hypotheses:

[tex]\to H_{0}:\mu_{B}-\mu_{A}\geq 0\\\\\to H_{a}:\mu_{B}-\mu_{A}< 0\\\\[/tex]

Testing statistics:

[tex]\to z=\frac{(\bar{x}_{B}-\bar{x}_{A})-(\mu_{B}-\mu_{A})}{\sqrt{\frac{\sigma^{2}_{B}}{n_{1}}+\frac{\sigma^{2}_{A}}{n_{2}}}}=\frac{3.5-(0)}{\sqrt{\frac{16^{2}}{25}+\frac{16^{2}}{25}}}=0.77[/tex]

The test is done just so the p-value of a test is

[tex]\to p-value = P(z < 0.77) = 0.7794[/tex]

Because the p-value of the management is large, type B can take it.

Answer:

5

Step-by-step explanation: