If the true mean is 50 and we reject the hypothesis that μ = 50, what is the probability of Type II error? Hint: This is a trick question.

Answer:  a=24

Step-by-step explanation:

Lets find the line's  formula (equation of the line).

As known the general formula of any straight line (linear function) is

y=kx+b

Lets find the coefficient k= (Yb-Ya)/(Xb-Xa)=(9-7)/(-4-3)=-2/7

(Xb;Yb)- are the coordinates of point B

(Xa;Ya) are the coordinates of point A

Now lets find the coefficient b.  For this purpose we gonna use the coordinates of any point A or B.

We will use A

7=-2/7*3+b

7=-6/7+b

b=7 6/7

So the line' s  equation is y= -2/7*x+7 6/7

Now we gonna find the value of a usingcoordinates of point C.

Yc=1,  Xc=a

1=-2/7*a+7 6/7

2/7*a= 7 6/7-1

2/7*a=6 6/7

(2/7)*a=48/7

a=48/7: (2/7)

a=24

Answer:

a=24

Step-by-step explanation:

If the expression has only two variables [tex] x[/tex] and $y$, or if there's just one variable out of these two, then the answer is yes.

If the expression has more variables (other than X and y), then the answer is no.

Answer:

6x-3=21

6x=24

x=4

........

6x+27=39

6x=39-27

6x=12

x=2

........

8x-10=14

8x=24

x=3

.........

6+6x=22

6x=22-6

x=3

......

12x-2=28

12x=26

x=3

.....

8-4x=16

-4x=8

x=-2

.....

4x-24=3x-3

4x-3x=24-3

x=21

....

9x+6=6x+12

9x-6x=12-6

3x=6

x=2

Answer:

Step-by-step explanation:

1. 3(2x - 1) = 21

 = 6x - 3 = 21

 = 6x = 24

 = x = 24/6 = 4

------------------------------

2. 3(2x+9) = 39

   = 6x + 27 = 39

   = 6x = 39 - 27

   = 6x = 12

   = x = 12/6 = 2

--------------------------------

3. 2(4x - 5) = 14

  = 8x - 10 = 14

  = 8x = 14+10

 = x = 3

-------------------------------

Answer:

B. The graph of function f is stretched horizontally by a scale factor of 3 to create the graph of function g.

Step-by-step explanation:

The rules for linear transformations are that

 g(x) = a·f(b·(x-c)) +d

stretches the graph vertically by a factor of "a" (before the shift)

compresses the graph horizontally by a factor of "b" (before the shift)

shifts it to the right by amount "c"

shifts it up by amount "d".

Your equation has b=1/3, so the graph is compressed by a factor of 1/3, which is equivalent to a stretch by a factor of 3.

The appropriate choice of description is ...

 b) the graph of g(x) is horizontally stretched by a factor of 3

Answer:

B

Step-by-step explanation:

Correct on Plato

Answer:

Step-by-step explanation:

Hello, please consider the following.

[tex]x=x(t)=2cos(t)\\\\dx=\dfrac{dx}{dt}dt=x'(t)dt=-2sin(t)dt[/tex]

and

[tex]y=y(t)=2sin(t)\\\\dy=\dfrac{dy}{dt}dt=y'(t)dt=2cos(t)dt[/tex]

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

The values of dx and dy are give as -2sin(t)dt and 2cos(t)dt respectively. The answer to the given problem can be stated as,

dy = 2cos(t)dt

And,  dx = -2sin(t)dt.

The integration can be defined as the inverse operation of differentiation. If a function is the integration of some function f(x) , then differentiation of that function is f(x).

The given integral over C is ∫ (x − y) dx + (x + y) dy.

And, the parameters for C are as follows,

x = 2cos(t)

y = 2sin(t)

0 ≤ t ≤ 2π

Now, on the basis of these parameters dx and dy can be found as follows,

x =  2cos(t)

Differentiate both sides with respect to t as follows,

dx/dt = 2d(cos(t))/dt

=> dx/dt = -2sin(t)

=> dx =  -2sin(t)dt

And, y = 2sin(t)

Differentiate both sides with respect to t as follows,

dy/dt = 2d(sin(t))/dt

=> dy/dt = 2cos(t)

=> dy = 2cos(t)dt

Hence, the value of dx and dy as per the given parameters is -2sin(t)dt and 2cos(t)dt respectively.

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Answer:

Step-by-step explanation:

Hello, if I take the following

2, 2, -5, 2, 2, -5, 2, 2, -5, 2, 2

The sum is 8*2-5*3=16-15=1 > 0

and

2 + 2 -5 < 0

2 - 5 + 2 < 0

-5 + 2 + 2 < 0

2 + 2 -5 < 0

2 - 5 + 2 < 0

-5 + 2 + 2 < 0

2 + 2 -5 < 0

2 - 5 + 2 < 0

-5 + 2 + 2 < 0

2 + 2 -5 < 0

2 - 5 + 2 < 0

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

[tex] 1.2\times3.5\times4.1=[(1+0.2)(3+0.5)](4+0.1)[/tex]

$=[1\times3+1\times0.5+0.2\times3+0.2\times0.5](4+0.1)$

$=(3+0.5+0.6+0.1)(4+0.1)$

$=(4.2)(4+0.1)=(4+0.2)(4+0.1)$

$=4\times4+4\times0.1+0.2\times4+0.2\times0.1$

$=16+0.4+0.8+0.02=17.22$

Answer:

choice 1,2,4,5 from top to bottom

Step-by-step explanation:

1:the points given are in the line where both planes intersect

2:point H is not on any plane

3:in the diagram point F is on plane R so false

4:if you connect the points given they will intersect so not collinear

5:the points F and G are on the plane R

6:so F is on plane R but H is not on any do false

Answer:

Distributive property, addition property

Answer:

additive identity

associative property of addition

distributive property

Step-by-step explanation:

Answer:

81.432 minutes

Step-by-step explanation:

Given the following :

Video Games (Mins) - - - Time with Family(Mins)

40 - - - - - - - - - - - - - - - - - - - 80

55 - - - - - - - - - - - - - - - - - - - 75

70 - - - - - - - - - - - - - - - - - - - 69

85 - - - - - - - - - - - - - - - - - - - 64

Best fit line:

ý = -0.363x +94.5

For someone who spent 36 minutes playing video games, the predicted number of minutes spent with family according to the best fit line will be:

Here number of minutes playing video games '36' is the independent variable

ý is the dependent or predicted variable ;

94.5 is the intercept

ý = -0.363(36) +94.5

ý = −13.068 + 94.5

ý = 81.432 minutes

Which is about 81 minutes to the nearest whole number.

[tex] 24 = 3 \cdot 2^3 [/tex]

[tex]96=3\cdot 2^5 [/tex]

[tex] 384=3\cdot2^7[/tex]

hence it is a geometric progression, with a multiplied constant [tex]3[/tex]

Sum of G.P. of [tex]n[/tex] terms [tex] S_n = a\dfrac{r^n-1}{r-1}\quad \text{where } r \text{ is the common ratio and } a \text{ is the first term} [/tex]

and [tex] r=-2^2=-4[/tex]

Note that the constant should be separated, so

[tex] a= -8 [\tex]

after plugging the values, you'll get the answer

[tex] -26216 \times 3 [/tex]

which option C

Answer:

C

Step-by-step explanation:

-24+96-384+...

a=-24

r=96/(-24)=-4

[tex]s_{7}=a\frac{1-r^7}{1-r} \\=-24\frac{1-(-4)^7}{1-(-4)}\\=-24\frac{1+4^7}{1+4} \\=-24\frac{1+16384}{5} \\=-24\frac{16385}{5} \\=-24 \times 3277\\=-78648[/tex]

Answer:

A. 55, 89

Step-by-step explanation:

In a Fibonacci sequence, you start with 2 given numbers. Then each subsequent number is the sum of the last two numbers.

12, 21, 34

12 + 21 = 34

34 + 21 = 55

55 + 34 = 89

Answer: 55, 89

This sequence converges to 0.

Proof: Recall that

[tex]\displaystyle\lim_{n\to\infty}\frac1{\sqrt n}=0[/tex]

is to say that for any given [tex]\varepsilon>0[/tex], there is some [tex]N[/tex] for which [tex]\left|\frac1{\sqrt n}-0\right|=\frac1{\sqrt n}<\varepsilon[/tex] for all [tex]n>N[/tex].

Let [tex]N=\left\lceil\frac1{\varepsilon^2}\right\rceil[/tex]. Then

[tex]n>\left\lceil\dfrac1{\varepsilon^2}\right\rceil\ge\dfrac1{\varepsilon^2}[/tex]

[tex]\implies\dfrac1n<\varepsilon^2[/tex]

[tex]\implies\dfrac1{\sqrt n}<\varepsilon[/tex]

as required.

Answer:

Step-by-step explanation:

Hello, the slope of the tangent is the value of the derivative.

f'(x) = 2*0.2x + 5 = 0.4x + 5

So we are looking for

[tex]-1\leq f'(x) \leq 1 \\ \\<=> -1\leq 0.4x+5 \leq 1 \\ \\<=> -1-5=-6\leq 0.4x \leq 1-5=-4 \\ \\<=> \dfrac{-6}{0.4}\leq 0.4x \leq \dfrac{-4}{0.4} \\\\<=> \boxed{-15 \leq x\leq -10}[/tex]

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

Using derivatives, it is found that the x-values in which the slope belong to the interval (-1,1) are in the following interval is (-15,-10).

It is given by the derivative at x = x_0, that is:

m = f'(x_0)

In this problem, the function is:

f(x) = 0.2x^2 + 5x − 12

Hence the derivative is:

f'(x) = 0.4x + 5

For a slope of -1, we have that,

0.4x + 5 = -1

0.4x = -6

x = -15.

For a slope of 1, we have that,

0.4x + 5 = 1.

0.4x = -4

x = -10

Hence it is found that the x-values in which the slope belong to the interval (-1,1) are in the following interval is (-15,-10).

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Answer: B. Always

Explanation:

Two points always create a line. The correct answer is option B.

A line has length but no width, making it a one-dimensional figure. A line is made up of a collection of points that can be stretched indefinitely in opposing directions.

If there are two points A(x₁,y₁) and B(x₂,y₂) then the distance between the two points will be the length of the line. The formula to calculate the distance is given as below:-

Distance = [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Therefore, the two points always create a line. The correct answer is option B.

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Answer:

v (m/s) a(m/s2). √. ½. 0. ¼. √. -¼. Movimiento circular y M.A.S. Un punto se mueve ... como la que se ilustra en la figura, llamada onda cuadrada. ... Movimiento Armónico Simple I. Una partícula cuya masa es de 1 g vibra con movimiento ... Multiplicando por el Periodo de oscilación del sistema T (con ... distancia de 10 m?

Step-by-sv (m/s) a(m/s2). √. ½. 0. ¼. √. -¼. Movimiento circular y M.A.S. Un punto se mueve ... como la que se ilustra en la figura, llamada onda cuadrada. ... Movimiento Armónico Simple I. Una partícula cuya masa es de 1 g vibra con movimiento ... Multiplicando por el Periodo de oscilación del sistema T (con ... distancia de 10 m?tep explanation:

Answer:

2 sqrt(41) = x

Step-by-step explanation:

This is a right triangle so we can use the Pythagorean theorem

a^2 + b^2 = c^2

8^2 + 10 ^2 = x^2

64+ 100 = x^2

164 = x^2

Take the square root of each side

sqrt(164) = sqrt(x^2)

sqrt(4) sqrt(41) = x

2 sqrt(41) = x

Answer:

- At any time t, the population is:

P = 375t² + 3000t + 1000

- At time t = 3 days, the population is:

P = 13,375

Step-by-step explanation:

Given the rate of change of the population of bacteria as:

dP/dt = 3000/(1 + 0.25t)

we need to rewrite the given differential equation, and solve.

Rewriting, we have:

dP/3000 = (1 + 0.25t)dt

Integrating both sides, we have

P/3000 = t + (0.25/2)t² + C

P/3000 = t + 0.125t² + C

When t = 0, P = 1000

So,

1000/3000 = C

C = 1/3

Therefore, at any time t, the population is:

P/3000 = 0.125t² + t + 1/3

P = 375t² + 3000t + 1000

At time t = 3 days, the population is :

P = 375(3²) + 3000(3) + 1000

= 3375 + 9000 + 1000

P = 13,375

Answer:

Hey there!

The slope is -1/3, because the rise over run is -1/3.

Let me know if this helps :)

Answer:

[tex] \sqrt{4 {}^{2} + ( - 4) {}^{2} } [/tex]

[tex] \sqrt{32} [/tex]

and the angle

[tex] \tan( \alpha ) = - 4 \div 4 = - 1[/tex]

and since the sin component is -ve, we have our angle on 4th quadrant, which equals 315 degrees

Options:

Determine two pairs of polar coordinates for the point (-4, 4) with 0° ≤ θ < 360°. (5 points)

Group of answer choices

(4  , 135°), (-4  , 315°)

(4  , 45°), (-4  , 225°)

(4  , 315°), (-4  , 135°)

(4  , 225°), (-4  , 45°)

Step-by-step explanation:

The guy asking forgot to provide the options you can comment the awnswe in the comments just do it before brainly turns off comments to try and prevent people from learning

Answer:

√(x)

Step-by-step explanation:

(1)/(x^-(1/2)) that's 3 goes into -3 leaving 1 and goes into 6 leaving 2

1/2 is same as 2^-1

so therefore we can simplify the above as

x^-(-1/2)

x^(1/2)

and 4^(1/2)

is same as √(4)

so we conclude as

√(x)

Answer:

ig

Step-by-step explanation:

[tex](9-\sqrt{-8} )- (5 + \sqrt{-32} ) \\(9-5) + (-\sqrt{-8}- \sqrt{-32} )\\4 - \sqrt{-8} -\sqrt{-32} \\4-2i\sqrt{2} -4i\sqrt{2} \\4-6i\sqrt{2}[/tex]

Answer:

Note that orthogonal to the plane means perpendicular to the plane.

Step-by-step explanation:

-1x+3y-3z=1 can also be written as -1x+3y-3z=0

The direction vector of the plane -1x+3y-3z-1=0 is (-1,3,-3).

Let us find a point on this  line for which the vector from this point to (0,0,5) is perpendicular to the given line. The point is x-0,y-0 and z-0 respectively

Therefore, the vector equation is given as:

-1(x-0) + 3(y-0) + -3(z-5) = 0

-x + 3y + (-3z+15) = 0

-x + 3y -3z + 15 = 0

Multiply through by - to get a positive x coordinate to give

x - 3y + 3z - 15 = 0

Answer:

Step-by-step explanation:

Hello, first, let's use the product rule.

Derivative of uv is u'v + u v', so it gives:

[tex]f(x)=(x^3-2x+1)(x-3)=u(x) \cdot v(x)\\\\f'(x)=u'(x)v(x)+u(x)v'(x)\\\\ \text{ **** } u(x)=x^3-2x+1 \ \ \ so \ \ \ u'(x)=3x^2-2\\\\\text{ **** } v(x)=x-3 \ \ \ so \ \ \ v'(x)=1\\\\f'(x)=(3x^2-2)(x-3)+(x^3-2x+1)(1)\\\\f'(x)=3x^3-9x^2-2x+6 + x^3-2x+1\\\\\boxed{f'(x)=4x^3-9x^2-4x+7}[/tex]

Now, we distribute the expression of f(x) and find the derivative afterwards.

[tex]f(x)=(x^3-2x+1)(x-3)\\\\=x^4-2x^2+x-3x^3+6x-4\\\\=x^4-3x^3-2x^2+7x-4 \ \ \ so\\ \\\boxed{f'(x)=4x^3-9x^2-4x+7}[/tex]

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

Answer:

If a polygon has 3 sides, then the polygon is a triangle.

Step-by-step explanation:

Bold = hypothesis

Italic = conclusion

Statement:

If p, then q.

Converse: If q, then p.

To find the converse, switch the hypothesis and conclusion.

Statement:

If a polygon is a triangle, then it  has 3 sides.

Now we switch the hypothesis and the conclusion to write the converse of the statement.

If it  has 3 sides, then a polygon is a triangle.

We fix a little the wording:

If a polygon has 3 sides, then it is a triangle.

Answer: If a polygon has 3 sides, then the polygon is a triangle.

The converse statement will be;

⇒ If a polygon has 3 sides, then the polygon is a triangle.

A triangle is a three sided polygon, which has three vertices and three angles which has the sum 180 degrees.

Given that;

The statement is,

''If a polygon is a triangle, then it has 3 sides. ''

Now,

Since, The statement is,

''If a polygon is a triangle, then it has 3 sides. ''

We know that;

The converse of statement for p → q will be q → p.

Thus, The converse statement is find as;

⇒ If a polygon has 3 sides, then the polygon is a triangle.

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Aswer:I am sure of the answer it is 6 and 42

Step-by-step explanation:

Answer:

Problem 1)       [tex] m = \dfrac{1}{4} [/tex]     [tex] slope_{perpendicular} = -4 [/tex]

Problem 2)      [tex] m = \dfrac{1}{3} [/tex]     [tex] slope_{perpendicular} = -3 [/tex]

Step-by-step explanation:

[tex] slope = m = \dfrac{y_2 - y_1}{x_2 - x_1} [/tex]

[tex] slope_{perpendicular} = \dfrac{-1}{m} [/tex]

Problem 1) M(9,6), N(1,4)

[tex] slope = m = \dfrac{6 - 4}{9 - 1} = \dfrac{2}{8} = \dfrac{1}{4} [/tex]

[tex] slope_{perpendicular} = \dfrac{-1}{\frac{1}{4}} = -4 [/tex]

Problem 2) M(-2,2), N(4,-4)

[tex] slope = m = \dfrac{4 - 2}{4 - (-2)} = \dfrac{2}{6} = \dfrac{1}{3} [/tex]

[tex] slope_{perpendicular} = \dfrac{-1}{\frac{1}{3}} = -3 [/tex]

Answer:

Linear, Quadratic, Radical, Absolute Value, Cubic, Cube Root

Step-by-step explanation:

To find:

Which functions have an intercept at (0, 0).

That means, when we put a value [tex]x=0[/tex] in the [tex]y =f(x)[/tex], value of [tex]y=0[/tex].

Let us discuss each parent function one by one:

1. Linear:

[tex]y = x[/tex]

When we put x = 0, y = 0

Therefore, it has intercept at (0, 0).

2. Quadratic:

[tex]y = x^2[/tex]

When we put x = 0, y = 0

Therefore, it has intercept at (0, 0).

3. Radical:

[tex]y = \sqrt x[/tex]

When we put x = 0, y = 0

Therefore, it has intercept at (0, 0).

4. Absolute Value:

[tex]y = |x|[/tex]

When we put x = 0, y = 0

Therefore, it has intercept at (0, 0).

5. Rational:

[tex]y = \dfrac{1}{x}[/tex]

When we put [tex]x = 0\Rightarrow y \rightarrow \infty[/tex]

Therefore, it does not have intercept at (0, 0).

6. Exponential:

[tex]y = b^x[/tex]

b is any base

When we put [tex]x = 0\Rightarrow y =1[/tex]

Therefore, it does not have intercept at (0, 0).

7. Logarithmic:

[tex]y = logx[/tex]

When we put [tex]x = 0 \Rightarrow y\rightarrow[/tex] Not defined

Therefore, it does not have intercept at (0, 0).

8. Cubic:

[tex]y = x^3[/tex]

When we put [tex]x = 0\Rightarrow y =0[/tex]

Therefore, it has intercept at (0, 0).

9. Cube Root:

[tex]y = \sqrt[3]x[/tex]

When we put [tex]x = 0\Rightarrow y =0[/tex]

Therefore, it has intercept at (0, 0).

Assuming the cup is a right circular cylinder, it's volume is [tex]V=\pi r^2 h[/tex]

$h=10$, $r=\frac 42$

So the volume is $\pi\cdot(2)^2\cdot10=125.66$

hence you can fill up to 125.66 cubic Inches of milkshake

.