If the rate of inflation is 2.6% per year, the future price p(t) (in dollars) of a certain item can be modeled by the following exponential function, where t is the number of years from today.
p(t)=600(1.026)t
Find the current price of the item and the price 9 years from today.
Round your answers to the nearest dollar as necessary.

Answers

Answer 1

Answer:

The current price of the item is $600.

The price of the item 9 years from today will be of $756.

Step-by-step explanation:

Price of the item:

The price of the item, in dollars, after t years, is given by:

[tex]p(t) = 600(1.026)^t[/tex]

Current price of the item

This is p(0). So

[tex]p(0) = 600(1.026)^0 = 600[/tex]

The current price of the item is $600.

9 years from today.

This is p(9). So

[tex]p(9) = 600(1.026)^9 = 756[/tex]

The price of the item 9 years from today will be of $756.


Related Questions

Which expression is equivalent to 9+y+y+3

Answers

Answer:

b

Step-by-step explanation:

You only need to add the real numbers and the ys.

Answer:

12 + 2y

Step-by-step explanation:

9+y+y+3

Combine like terms

9+3   + y+y

12 + 2y

Solve 8x + c = k for x

Answers

Answer:

x = 1/8(k-c)

Step-by-step explanation:

8x + c = k

Subtract c from each side

8x +c-c = k-c

8x = k-c

Divide each side by 8

8x/8 = (k-c)/8

x = 1/8(k-c)

Answer:

x-1/8(k-c)

Step-by-step explanation:

A presidential candidate plans to begin her campaign by visiting the capitals in 3 of 47 states. What is the probability that she selects the route of three specific​ capitals?

Answers

Answer:

1 / 97290

Step-by-step explanation:

The number of ways of selecting 3 specific route capitals from 47 states can be obtained thus :

Probability = required outcome / Total possible outcomes

Total possible outcomes = 47P3

Recall :

nPr = n! / (n-r)!

47P3 = 47! / (47-3)! = 47! / 44! = 97290

Hence, probability of selecting route if 3 specific capitals is = 1 / 97290

How would yo expand ln (1/49k)?

Answers

Answer:

Step-by-step explanation:

It depends on whether you mean ln(1/49k) or ln(1/(49k)).

When a fridge is imported, a customs value of 10% must be paid for its value. If the value of the fridge after paying the customs value is rs. 55,000/-. What is the value before paying customs duty?

Answers

Answer:

55000×100/90

61,111.111

Which graph represents y = RootIndex 3 StartRoot x + 6 EndRoot minus 3? in a test plese help fast

Answers

Answer:

Graph (a)

Step-by-step explanation:

Given

[tex]y = \sqrt[3]{x+ 6} -3[/tex]

Required

The graph

First, calculate y, when x = 0

[tex]y = \sqrt[3]{0+ 6} -3[/tex]

[tex]y = \sqrt[3]{6} -3[/tex]

[tex]y = -1.183[/tex]

The above value of y implies that the graph is below the origin when x = 0. Hence, (c) and (d) are incorrect because they are above the origin

Also, only the first graph passes through point (0,-1.183). Hence, graph (a) is correct

Answer:

the answer is A

Step-by-step explanation:

what 30 + 30+60+(56)-82=?

Answers

94 is the correct answer for that question

Step-by-step explanation:

30+30+60+56-82=94

Complete the sentence that explains why Write an Equation is a reasonable strategy for solving this problem. Because the answer may be _________ the numbers in the problem.

Answers

Answer:

4 e

Step-by-step explanation:

dz6dxrx xrrx6 xz33x4xr4x xrx

Rate of change or rate of change

A farmer has 80 feet of wire mesh to surround a rectangular pen.
A) Express the area A of the pen as a function of x, also draw the figure of A indicating the admissible values ​​of x for this problem.
B) What are the dimensions of the maximum area pen?

Answers

Answer:

Step-by-step explanation:

A). Let the dimensions of the rectangular pen are,

Length = l

Width = x

Since, farmer has the wire measuring 80 feet to surround the the pen.

Perimeter of the pen = 80 feet

2(l + x) = 80

l + x = 40

l = 40 - x ------(1)

Area of the rectangular pen = Length × width

                                               = lx

By substituting the value of l from equation (1),

Area (A) of the pen will be modeled by the expression,

A = (40 - x)

A = 40x - x²

B). For maximum area of the pen,

Derivative of the area = 0

[tex]\frac{d}{dx}(A)=0[/tex]

[tex]\frac{d}{dx}(A)=\frac{d}{dx}(40x-x^2)[/tex]

         = 40 - 2x

And (40 - 2x) = 0

x = 20

Therefore, width of the pen = 20 feet

And length of the pen = 40 - 20

                                     = 20 feet

Dimensions of the pen should be 20 feet by 20 feet.

A rope is 56 in length and must be cut into two pieces. If one piece must be six times as long as the other, find the length of each piece. Round your answers to the nearest inch, if necessary.

Answers

Answer:

48, 6

Step-by-step explanation:

The ratio of the pieces is 6 to 1

Add them together to get the total

6+1 = 7

Divide the total length by 7

56/7 = 8

Multiply the ratios by 8

6*8 = 48

 1*8 = 6

The peices are 48 and 6

Please help on this initial amount problem

Answers

Initial amount: 27,500
Growth
Value of car change 28% each year

Bill invested $4000 at 6%
compounded annually. Find the
accumulated amount at the end of
12 years.

Answers

Answer:

$ 8048.79

Step-by-step explanation:

P = $4000t = 12 yearsr = 6% = 0.06

Formula:

A = P(1 + r)^t

The total amount:

A = 4000*(1 + 0.06)^12 = 8048.79

We have to find the,

Accumulated amount at end of 12 years.

The formula we use,

→ A = P(1+r)^t

It is given that,

→ P = $4000

→ t = 12 years

Then r will be,

→ 6%

→ 6/100

→ 0.06

Then the total amount is,

→ P(1+r)^t

→ 4000 × (1 + 0.06)^12

→ 8048.79

Thus, $ 8048.79 is the amount.

Suppose you make napkin rings by drilling holes with different diameters through two wooden balls (which also have different diameters). You discover that both napkin rings have the same height 5h. Use cylindrical shells to compute the volume V of a napkin ring of height 5 h created by drilling a hole with radius r through the center of a sphere of radius R and express the answer in terms of h .

Answers

Answer:

V = 1/6 π ( 5h)^3

Step-by-step explanation:

Height of napkin rings = 5h

Compute the volume V of a napkin ring

let a = 5

radius = r

express answer in terms of h

attached below is the detailed solution

which of the following is not an asymptote of the hyperbola xy = -42? y = 0 x = 0 y = x

Answers

Given:

The equation of the hyperbola is:

[tex]xy=-42[/tex]

To find:

The the equation which is not an asymptote of the hyperbola.

Solution:

We have,

[tex]xy=-42[/tex]

It can be written as:

[tex]y=\dfrac{-42}{x}[/tex]

Equating denominator and 0, we get

[tex]x=0[/tex]

So, the vertical asymptotic is [tex]x=0[/tex].

The degree of numerator is 0 and the degree of denominator is 1.

Since the degree of numerator is greater that the degree of denominator, therefore the horizontal asymptote is [tex]y=0[/tex] and there is no oblique asymptote.

Therefore, [tex]y=x[/tex] is not an asymptote of the given hyperbola and the correct option is C.

Ethan buys a video game on sale. If the video game usually costs $60, and it was on sale for 20% off, how much did Ethan pay? Round to the nearest whole dollar.

Answers

Ethan will pay $31.99 with the discount.

How? This is the answer because:

If 39.99 is 100%, and you are trying to find 20%...

1. you need to set it up as a ratio (of course, you do not need to do this, but it is easier for me to do it this way)

2. the ratio will look like this: 39.99/100% x/20%

3. all we need to do from here is to cross multiply!

4 39.99 x

---------- = ----------

100 20

-price is on the top and percent on the bottom

-you would now do 39.99 times 20

-then divide by 100

5. once you have 20% of 39.99, you need to subtract that answer from the total

6. 39.99 - 7.998 = 31.992 (you need to round to the nearest hundredth)

Hope this helps <3

help help me please!!!!!!!​

Answers

9514 1404 393

Answer:

  a) 3092.5 (rounded to tenths)

  b) 39,600

  c) ₹28,755

Step-by-step explanation:

These are all simple calculator problems. The arithmetic involved is something you learned in 2nd or 3rd grade.

__

a) Since we divide using the division algorithm, it isn't clear what "check your answer by division algorithm" is intended to mean. The result of the division (stopping at 1 decimal place) is 3092.5.

The usual method of checking a division problem is to multiply the quotient by the divisor to see if the dividend value is the result. Here, we have ...

  13×3092.5 = 40202.5

This differs by from the dividend of 40203 by 0.5, which is the remainder showing in our long division. In short, the answer checks OK.

__

b) The value of each 4 is found by setting other digits to 0.

  Most significant 4: 40,000

  Least significant 4: 400

Difference in place value: 40,000 -400 = 39,600

__

c) The balance in the account is found by subtracting withdrawals from deposits:

  ₹35000 -6245 = ₹28,755

 

this khan academy problem confuses me... (5/3)^3= can anyone help me solve it?

Answers

Answer:

4.629

Step-by-step explanation:

(5/3)³5×5×5/3×3×3125/274.629.

Hope it is helpful to you

Hshejoffpeowhwbwbwhjskfofofoekwwoksnfnf Helppp

Answers

Answer:

Step-by-step explanation:

3. ZW ≅ WX

Find the missing length indicated

Answers

Answer:

x = 175

Step-by-step explanation:

The stem-and-leaf plot above shows house sale prices over the last week in Tacoma. What was the most
expensive house sold? Give your answer in dollars
$

Answers

Answer:

the answer is 2

Step-by-step explanation:

If 800g of a radioactive substance are present initially and 8 years later only 450g remain, how much of the substance will be present after 16 years? (Round answer to a whole number)

Answers

A=Pe^(rt)

P = 800g

t = 8 years

A = 450g

r = This is what we will try and find to start with

450=800e^(r*8)

After running the math through a calculator, we end with r = -0.07192

Now we just re-input this information into our equation: A=800e^(-0.07192*16)

A=800e^(1.15072)

Now we will re-write the equation using the negative exponent rule:

A = 800 1/e^1.15072

Combine right side:

A = 800/e^1.15072

Then do the math:

A = 253.12709836......

That will give us A = 253 (rounded to the whole number)

I hope this helps! :)

The substance that should be presented after 16 years is 253.

Given that,

If 800g of a radioactive substance are present initially and 8 years later only 450g remain.

Based on the above information, the calculation is as follows:

We know that

[tex]A=Pe^{rt}[/tex]

Here

P = 800g

t = 8 years

A = 450g

[tex]450=800e^{r\times 8}\\\\A=800e^{-0.07192\times 16}\\\\A=800e^{1.15072}\\\\A = 800 \ 1 \div e^{1.15072}\\\\A = 800\div e^{1.15072}[/tex]

A = 253

Therefore we can conclude that the substance that should be presented after 16 years is 253.

Learn more: brainly.com/question/16115373

After the booster club sold 40 hotdogs at a football game, it had $90 in profit.
After the next game, it had sold a total of 80 hotdogs and had a total of $210
profit. Which equation models the total profit, y, based on the number of
hotdogs sold, X?

Answers

Step-by-step explanation:

x = goods y = $

x Sold = 40, Y = $90

x Sold = 80, Y = $210

sum of xHotdogs = 40+80 = 120 Hotdogs

Sum of Y$ = $90 + 210 = 300

so

X = 2A & Y = 3 its mean one hotdogs can sold for one each = $2.25 and we round it to $3

So = XY = 2A + 3

sorry if i wrong

Help please!! Based on Pythagorean identities, which equation is true ??

Answers

Answer:

Last answer: [tex]cot^{2} \alpha - csc^{2} \alpha = -1[/tex]

sorry couldn't find theata so I just used alpha.

A researcher surveyed 8 people to see if there is a
relationship between years of education and starting
salaries. The data points are shown on the graph.
Which best represents the equation of the trend line
shown on the graph? (Note that the graph has a break
on the x-axis.)
O y = 0.25x + 15
O y = 0.25x + 17.5
* y = 1.25x - 10
O y = 1.25x + 7.5

Answers

Answer:

[tex]y=1.25x+7.5[/tex]

Step-by-step explanation:

We can see that the trend line is the line of best fit to the data points.

The equation of a straight line is given by:

y = mx + b:

where y, x are variables, m is the slope of the line and b is the y intercept.

From the graph, we can see that the line passes through the points (10, 20) and (14, 25). Therefore the equation of the line is given by:

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-20=\frac{25-20}{14-10}(x-10)\\\\y-20=1.25(x -10)\\\\y-20=1.25x-12.5\\\\y=1.25x+7.5[/tex]

13) What is 4 1/2 subtracted from 5.33?
A. 0.43
B. 0.53
C. 0.83
D. 1.08

Answers

Given:

[tex]4\dfrac{1}{2}[/tex] subtracted from 5.33.

To find:

The value for the given statement.

Solution:

[tex]4\dfrac{1}{2}[/tex] subtracted from 5.33 can be written as:

[tex]5.33-4\dfrac{1}{2}[/tex]

On simplification, we get

[tex]=5.33-\dfrac{8+1}{2}[/tex]

[tex]=5.33-\dfrac{9}{2}[/tex]

[tex]=5.33-4.5[/tex]

[tex]=0.83[/tex]

Therefore, the correct option is C.

Riley wants to make 100ml of 25% saline but only has access to 12% and 38% saline mixtures. x= 12% y=38%

Answers

Answer:

x = 50

y = 50

Step-by-step explanation:

[tex]\begin{bmatrix}x+y=100\\ 0.12x+0.38y=25\end{bmatrix}[/tex]

.12(100-y) + .38y = 25

x = 50

y = 50

Solve the equation
P=100x-0.1x^2

Answers

Answer:

100x - 0.01x

Step-by-step explanation:

100x-0.1x^2

100x - 0.01x

use the function to find f(-2) f(x)=[tex]3^{x}[/tex]

Answers

Answer:

[tex] \frac{1}{9} [/tex]

Step-by-step explanation:

[tex]f( - 2) = {3}^{ - 2} [/tex]

[tex]1 \div 9 = .111[/tex]

A random sample of 64 students at a university showed an average age of 25 years and a sample standard deviation of 2 years. The 98% confidence interval for the true average age of all students in the university is

Answers

Answer:

24.4185<x<25.5815

Step-by-step explanation:

Given the following:

n = 64

mean x = 25

s = 2

z is the z score at 98% CI = 2.326

Get the Confidence Interval:

CI = x±z*s/√n

CI = 25±2.326*2/√64

CI = 25±2.326*2/8

CI = 25±0.5815

CI = (25-0.5815, 25+0.5815)

CI = (24.4185, 25.5815)

CI = 24.4185<x<25.5815

Hence the 98% confidence interval for the true average age of all students in the university is 24.4185<x<25.5815

The quadratic equation [tex]x^2+3x+50 = 0[/tex] has roots r and s. Find a quadratic question whose roots are r^2 and s^2.

Answers

According to the question, our quadratic equation is :

\begin{gathered} \bf {x}^{2} - ( {r}^{2} + {s}^{2} )x + {r}^{2} {s}^{2} = 0 \\ \bf \implies \: {x}^{2} - ( - 91)x + {(rs)}^{2} = 0 \\ \bf \implies \: {x}^{2} + 91x + {(50)}^{2} = 0 \\ \bf \implies \: {x}^{2} + 91x + 2500 = 0\end{gathered}

x

2

−(r

2

+s

2

)x+r

2

s

2

=0

⟹x

2

−(−91)x+(rs)

2

=0

⟹x

2

+91x+(50)

2

=0

⟹x

2

+91x+2500=0

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