If John deposits this entire paycheck into his checking account, how much money will go into his account?

A. $1,524.74
B. $2,000.00
C. $30,494.81
D. $40,000.00

The area of the painted face with vertices at (-4, 2), (-4, -11), (4, 2), and (4, -11) which represents a rectangle is 104 square inches

A rectangle is a quadrilateral with the four interior angles that are each right angles, and opposite sides that are congruent and parallel.

The specified vertices of the face of the brick are;

(-4, 2), (-4, -11), (4, 2), and (4, -11)

The graph of the above point used to draw the quadrilateral representing the shape of the face in the question, created with MS Word, is attached

From the attached graph and drawing, we get;

Shape of the face of the doorstop = A rectangle

Length of the sides of the quadrilateral (rectangle)

Length = 2 - (-11) = 13

Width = 4 - (-4) = 8

Area of a rectangle  Length × Width

Area of the painted face of the brick, A = 13 × 8 = 104

The area of the rectangular painted face of the brick = 104 square inches

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The value of width will be;

⇒ 18.5 cm

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

The volume of a rectangular prism = 6,618.375 cm³

The height is 13.25 cm and the length is 27 cm.

Now,

We know that,

The volume of rectangular prism = Length x Width x Height

Substitute all the values, we get;

⇒ 6,618.375 = 27 × x × 13.25

⇒ 6,618.375 / 357.75 = x

⇒ x = 18.5 cm

Thus, The value of width = 18.5 cm

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The same thing on both the circles is that they both have the same diameter, the length of AD is 4 cm and the segment which represents the diameter is EB.

An irregular plane figure is a circle. Every spot on the circle is equally distant from the circle's fixed center. It has a radius of 1, making it a 2D shape. The Latin word "circulus," which means "little ring," is the source of the English word "circle."

As per the given information in the question,

1.

There are two circles given,

The radius of the first circle = 4 cm

Then, its diameter will be,

D = 2r = 2 × 4 = 8 cm

And, the diameter of the second circle is also 8 cm. It means that both are same on this aspect.

The second has three segments whereas the first only has two, hence the segments are distinct.

2.

The length of the segment AD will be equal to 4 cm because it is from the center of the circle to the circumference of the circle then it becomes equal to the radius, so the segment must be of 4 cm.

3.

On the first circle, the segment which represents the diameter is EB. Because as per the definition of diameter, a line connected with two points which passes through the center of circle is said to be the diameter.

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Using trigonometry identity the value of cosθ is 0.942.

What is round to 3 decimal?

Rounding to three decimal places is equivalent to rounding to the closest thousandth. Take 3.3685 as an example and round to the nearest thousandth. It is possible to round up to 3.369 or down to 3.368 because the third digit following the decimal point is 8 instead of 3.

Given that sinθ=3/9

Divide the denominator and numerator by 3:

sinθ=1/3

To find the value of cosθ, use trigonometry identity.

The trigonometry identity is sin²θ + cos²θ = 1

Solve the identity for  cosθ:

Subtract both side by sin²θ:

cos²θ = 1 - sin²θ

Take square root on both sides:

cos θ = √(1 - sin²θ)

Putting sinθ = 1/3 in the above equation:

cos θ = √(1 - (1/3)²)

cos θ = √(1 - 1/9)

cos θ = √((9 - 1)/9)

cos θ = √(8/9)

cos θ = 0.9428

cos θ = 0.943 (round to 3 decimal places)

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The perimeter of the given square is 4x-36 units which have a side length of x- 9 units.

The perimeter of a square is defined as the addition of the lengths of the square.

The perimeter of a square is the sum of all its sides.

Since a square has four sides of equal length, the perimeter is four times the length of one side.

Therefore, the perimeter of a square with a side length of x-9 units is :

⇒ 4(x-9) units.

This can be simplified to 4x-36 units.

Hence, the perimeter of the given square is 4x-36 units.

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Answer:

$22.50

Step-by-step explanation:

The lines that carry the rectangle onto itself are x = 0 and y = 1

The graph that completes the question is added as an attachment

From the question, we have the following parameters that can be used in our computation:

The rectangular graph

The coordinates of one end of the graph are

(-3, 3) and (-3, -1)

Next, we calculate the midpoint of these ends

So, we have

Midpoint = 1/2(x₁ + x₂, y₁ + y₂)

Substitute the known values in the above equation, so, we have the following representation

Midpoint = 1/2(-3 + 3, -1 + 3)

Evaluate the like terms

Midpoint = 1/2(0, 2)

So, we have

Midpoint = (0, 1)

So, we have

x = 0 and y = 1

Hence, the reflection lines are x = 0 and y = 1

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Answer:

a = 4

Step-by-step explanation:

Step 1: Find two numbers that multiply to give 16 and add to give -8.

t²-8t+16 = 0

t² -4t -4t + 16 = 0

The two numbers are 4 and -4.

Step 2: Rewrite the equation in the form (t + 4)(t - 4).

t² - 8t + 16 = (t + 4)(t - 4)

Step 3: Factor the equation to get (t + 4)².

(t + 4)² = (t + 4)(t + 4)

Therefore, a = 4.

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Answer:

-2

Step-by-step explanation:

The line appears to cross through (2,3) and (4,-1)

You can subtract the x values and y values to determine the difference:

[tex]2 - 4= - 2 \\ 3 - ( - 1) = 4[/tex]

These can be used as the y and x values in y over x to find the slope:

[tex] \frac{4}{ - 2} = - 2[/tex]

The slope is -2

The measures of the lengths of the sides and angles of the triangles found using the law of cosines and the law of sines are presented as follows;

Question 1

∠A = 47.35°

∠B = 78.65°

c = 3.3

Question  2

∠B = 78.24°

∠C = 29.76°

a = 67.03

Question 3

∠A = 45.77°

∠B = 86.417°

∠C = 47.813°

Question 4

∠A = 36.15°

∠B = 60.48°

∠C = 93.37°

Question 5

a = 258.98

b = 327.41

∠C = 53°

Question 6

a = 34.11

b = 73.987

∠C = 53°

The law of cosines is a relationship between two sides (b and c) and the included angle, (∠A) and the third side (a) of the triangle.

Mathematically; a² = b² + c² - 2·b·c·cos(A)

Question 1

The dimensions of the triangle ΔABC are;

a = 3.0, b = 4.0, ∠C = 54°

The law of cosines indicates that we get;

c² = b² + a² - 2·b·a·cos(∠C)

Therefore;

c² = 3.0² + 4.0² - 2 × 3.0 × 4.0 × cos(54°) ≈ 10.893

The law of sines indicates that we get;

sin(54°)/3.3 = sin(∠A)/3.0

Question 2

b = 69, c = 35, ∠A = 72°

a² = 69² + 35² - 2 × 69 × 35 × cos(72°) ≈ 4493.45

The law of sines indicates that we get;

sin(72°)/67.03 = sin(∠B)/69

∠B = arcsine(69 × sin(72°)/67.03) ≈ 78·24°

∠C = 180° - 72° - 78.24° ≈ 29.76°

Question 3

a = 28, b = 39, c = 29

a² = b² + c² - 2·b·c·cos(A)

cos(A) = (a² - (b² + c²)) ÷ (2·b·c)

Therefore; cos(A) = (28² - (39² + 29²)) ÷ (-2 × 39 × 29) ≈ 0.6976

sin(45.77)/28 = sin(B)/39

sin(B) = 39 × sin(45.77)/28 ≈ 0.998

Question 4

a = 13, b = 17, c = 22

cos(A) = (13² - (17² + 22²)) ÷ (-2 × 17 × 22) ≈ 0.807

sin(36.15)°/13 = sin(∠B)/17

sin(∠B) = 17 × sin(36.15)°/13

Question 5

The parameters of the triangle are; ∠A = 50°, ∠B = 77°, c = 270

Please find attached the sketch of the triangle in the correct option created with MS Word

a/sin(50°) = 270/sin(53°)

a = sin(50°) × 270/sin(53°) ≈ 258.98

b = sin(77°) × 270/sin(53°) ≈ 329.41

Question 6

The parameters of the triangle are;

∠A = 27°, ∠B = 100°, c = 60

Please find attached the drawing of the correct triangle

∠C = 180° - 27° - 100° = 53°

∠C = 53°

60/sin(53°) = a/sin(27°)

a = sin(27°) × 60/sin(53°) ≈ 34.11

b = sin(100°) × 60/sin(53°) ≈ 73.987

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Por lo tanto, el discriminante es = 8/3.

Generalmente, El discriminante de una ecuación cuadrática es el término que se encuentra bajo la raíz cuadrada en la fórmula general de la ecuación cuadrática. Para encontrar el discriminante de una ecuación en la forma ax^2 + bx + c = 0, debemos calcular el término b^2 - 4ac.

En el caso de la ecuación que has proporcionado, 3x^2+3 y^2+2x-2y-15=0, no podemos utilizar la fórmula general para encontrar el discriminante, ya que la ecuación no está en la forma ax^2 + bx + c = 0. Sin embargo, podemos reescribir la ecuación en esa forma para poder aplicar la fórmula.

Para hacer esto, podemos reescribir la ecuación de la siguiente manera:

3(x^2+y^2) + 2x - 2y - 15 = 0

Luego, podemos reordenar los términos para obtener la forma ax^2 + bx + c = 0:

(x^2 + y^2) + (2/3)x - (2/3)y - 5 = 0

En esta forma, podemos ver que a = 1, b = 2/3 y c = -5.

Por lo tanto, el discriminante es b^2 - 4ac = (2/3)^2 - 4(1)(-5) = 4/9 + 20 = 24/9 = 8/3.

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The average rate of change of the given function from x equals -7 to x equals 2 is calculated as: B. 101/90.

If we are given a function, f(x), to find the average rate of change of the function within the interval from a to b, the formula to use is:

Average rate of change = f(b) - f(a) / b - a.

Given the table that represents  function, we have the following:

a = -7

b = 2

f(a) = f(-7) = -2.7

f(b) = f(2) = 7.4

Plug in the values into the formula:

Average rate of change = (7.4 - (-2.7)) / (2 - (-7))

= (7.4 + 2.7) / 2 + 7)

= 10.1 / 9

= 101/90

Therefore, the average rate of change is: B. 101/90.

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a) The number alive after 7 years is given as follows: 48.

b) The percentage of herd that dies each year is of 10%.

The exponential function in the context of this problem is defined as follows:

N(t)=100(0.9)^t.

The parameters of the function are defined as follows:

The amount of herd alive after 7 years is found with the numeric value at t = 7, replacing the lone instance of t in the function by 7, hence:

N(7) = 100 x (0.9)^7 = 48.

(rounding to the nearest whole number).

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Answer:

non-violence and kindness with animals

Step-by-step explanation:

A)

A manufacturer of banana chips would like to know whether its bag-filling machine works correctly at the 414-gram setting.

So, Null hypothesis: [tex]H_{0}[/tex] : μ < 414

It is believed that the machine is underfilling the bags.

So, Alternate hypothesis: [tex]H_{1}[/tex] : μ < 414

Given,

n= 8

Population standard deviation (б) = 18

x= 407

We will use the t-test since n > 8 and we are given the population standard deviation.

t=x-μ / (б/[tex]\sqrt{n-1}[/tex])

t= [tex]\frac{407-414}{\frac{18}{\sqrt{7} } }[/tex]

t= -1.028

Use the t table to find p value

p-value = 12.706

Level of significance α = 0.025

p-value>α

It is a two-tailed test.

So, we fail to reject the null hypothesis.

So, its bag-filling machine works correctly at the 414-gram setting.

B)

Let μ be the population mean amount of ozone in the upper atmosphere.

As per the given, we have

[tex]H_{0}[/tex]    : μ = 4.8

[tex]H_{1}[/tex] : μ ≠ 4.8

Sample size: n= 26

Sample mean = 4.6

Standard deviation = 1.2

Since population standard deviation is now given, so we use a t-test.

t= [tex]\frac{4.6-4.8}{\frac{1.2}{\sqrt{25} } }[/tex]

t= -0.2/0.24

t= -0.833

It is a two-tailed test.

We are accepting the null hypothesis.

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Answer:

x=38

Step-by-step explanation:

linear par

180-134=46

180-84=96

sum of a triangle is 180

96+46+x=180

142+x=180

x=180-142

x=38

The correct matrix for this system of equations in row reduced echelon form amongst the given options is none of the above.

The given system of equations to get the reduced row echelon form is:

x1 - 3x2 - x3 +3x4 = 2

-x1 - 2x2 - x3 +4x4 = 2

-2x1 + 4x2 + 4x3 +4x4 = -3

To get the reduced row echelon form we need to form the matrix:

[tex]\left[\begin{array}{ccccc}1&-3&-1&3&2\\-1&-2&-1&4&2\\-2&4&4&4&-3\end{array}\right][/tex]

Row reduced echelon form of a matrix is one in which the pivot points equal 1, go from top left to bottom right, there are 0's above and below each pivot point.

R2-R1:

[tex]\left[\begin{array}{ccccc}1&-3&-1&3&2\\-2&1&0&1&0\\-2&4&4&4&-3\end{array}\right][/tex]

R3-R2 then R2+2R1 then R1+R3 then R2+2R3 then R3-3R2

[tex]\left[\begin{array}{ccccc}1&0&3&6&-1\\0&1&6&13&-2\\0&0&-14&-36&3\\\end{array}\right]\\[/tex]

(-1/14)R3 then R2-6R3 then R1-3R3

[tex]\left[\begin{array}{ccccc}1&0&0&-12/7&-5/14\\0&1&0&-17/7&-5/7\\0&0&1&18/7&-3/14\\\end{array}\right]\\[/tex]

which is the reduced row echelon form of the given system of equations.

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The difference of the given polynomials 8x³+5x+6 and 2x²+3x is 8x³-2x²+2x+6. So, the correct answer is D.

To subtract polynomials from another, we should change the signs (from '+' to '-' or from '-' to '+') of all the terms of the expression which is to be subtracted and then the two expressions are added.

Given that, 8x³+5x+6-(2x²+3x)

Group the like terms are perform the addition or subtraction

= 8x³+5x+6-2x²-3x

= 8x³+(5x-3x)-2x²+6 (Here, like terms are 5x and 3x)

= 8x³+2x-2x²+6

= 8x³-2x²+2x+6

So, the standard form of obtained polynomial is 8x³-2x²+2x+6.

The polynomials difference is 8x³-2x²+2x+6. Therefore, option D is the correct answer.

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"Your question is incomplete, probably the complete question/missing part is:"

Which polynomial represents the difference below?

8x³ + 5x+6-(2x² + 3x)

A. 10x+ 8x² +6

B. -2x² + 8x³ + 8x+6

C. 6x¹⁰+2x+6

D. -2x²+ 8x³+2x+6

Answer:

x=9

Step-by-step explanation:

these 2 angles are supplementary angles meaning added together they will equal 180 degrees

so we can add them together and set it equal to 180

(8x-3)+(16x-33)=180

combine like terms

(8x+16x)+(-3-33)=180

24x-36=180

     +36. +36

24x=216

/24.  /24

x=9

hopes this helps

The answer is to (-4)(-4)(-4)(-4)(-4)(-4) 4096

There is an attachment that includes the graph for the inequality 8x + 5y 100.

How do you calculate the scenario's graph?

The parameters are as follows, taken from the query:

The customer's purchase must not exceed $100.

Each bath towel costs $8.

Each hand towel costs $5.

Inequality among the available combinations is another factor that we have.

8x + 5y ≤ 100

like that

x is the quantity of bath towels, while y is the quantity of hand towels.

Plotting the inequality's graph is the following step.

A graphing tool can be used for this.

In order to attach the graph, we enter the inequality in the graphing tool.

Keep in mind that the inequality is provided as

8x + 5y ≤ 100

See the inequality graph in the attached. 8x + 5y ≤ 100

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polynomial function for  x = 4, - 1 & 2. are

 [tex]x^{3}[/tex] - [tex]x^{2}[/tex] - 10x - 8

Given data :

Given the zeroes (roots) of a polynomial are:  4, - 1 & 2.

Here, we are given three roots of the polynomial. That means, the polynomial must be of third degree.

Also, (x - a) is a factor of the polynomial if and only if x = a is a root of the polynomial.

Here, 4, - 1 & 2. are roots. So, the factors are: ( x - 4 ) ( x + 1 ) ( x - 2 )

Multiplying them will result in the polynomial.

= ( x - 4 ) ( x + 1 ) ( x - 2 )

= ( [tex]x^{2}[/tex] - 3x - 4 ) ( x + 2 )

=  Distribute parentheses : [tex]x^{2}[/tex] . x + [tex]x^{2}[/tex] . 2 - 3xx - 3x . 2 - 4x - 4 . 2

= Simplify [tex]x^{2}[/tex] .x - [tex]x^{2}[/tex] . 2 - 3xx - 3x . 2 - 4x - 4 . 2

=  [tex]x^{3}[/tex] - [tex]x^{2}[/tex] - 10x - 8

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The needed 3rd-degree polynomial function with real coefficients matching the specified constraints will be y=2x³-8x²+8x-32.

A polynomial is a mathematical statement made up of indeterminates and coefficients that solely includes the operations of addition, subtraction, multiplication, and positive-integer powers of variables. x2 4x + 7 is an example of a polynomial with a single indeterminate x. Polynomials are sums of kxn terms, where k can be any number and n can be any positive integer. 3x+2x-5, for example, is a polynomial. Polynomials are introduced. This video defines words such as degree, standard form, monomial, binomial, and trinomial.

Here,

y=a(x-4)(x-2i)(x+2i)

y=-30

x=1

-30=a(1-4)(1-2i)(1+2i)

-30=a*-3*(1+4)

-30=-15a

a=2

y=2(x-4)(x²+4)

y=2(x³-4x²+4x-16)

y=2x³-8x²+8x-32

The required 3rd-degree polynomial function with real coefficients satisfying the given conditions will be y=2x³-8x²+8x-32.

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Answer: O B. Quadrilateral PQRS is a rectangle.

Step-by-step explanation: The image should help you picture my answer.  Good luck with your end of semester test!

Have a great day! :)

The required supply function is p = 3q - 300 and the required demand function is p = -3q + 1110. The equilibrium quantity is 235 and the equilibrium price is $405.

a) Find an equation for the supply function's price p as a function of q as follows.

Let p = mq + b be the required linear supply function.

From the given information, the supply function passes through points (125, 75) and (150,150).

Find the slope m using the points (125, 75) and (150,150) as shown below.

m = (p2-p1)/(q2-q1)

m = (150-75)/ (150-125) = 75/25 = 3

Now find the value of b using the point (125, 75) and slope m = 3 as follows.

p = mq + b

75 = 3(125) + b

b = - 375 + 75 = -300

Therefore, the required supply function is p = 3q - 300.

b) Find an equation for the demand function's price p as a function of q as follows.

Let p = mq + b be the required linear supply function.

From the given information, the demand function passes through points (355, 45) and (330,120).

Find the slope m using the points (355, 45) and (330,120) as shown below.

m = (p2-p1)/(q2-q1)

m = (120-45)/ (330-355) = 75/-25 = -3

Now find the value of b using the point (355, 45) and slope m = -3 as follows.

p = mq + b

45 = -3(355) + b

b = 1065 + 45 = 1110

Therefore, the required demand function is p = -3q + 1110.

Find the equilibrium quantity and equilibrium price as follows.

In order to find the equilibrium quantity, equate the demand function and supply function and solve the equation solve for q as shown below as p is common.

3q - 300 = -3q + 1110

=> 6q = 1410

=> q = 235

Thus, the equilibrium quantity is 235.

Find the equilibrium price by substituting q = 235 in p = 3q -300.

p = 3 x 235 - 300

p = 705 -300 = 405

Hence, the equilibrium price is $405.

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The sum of the elements of S is 360

Let S be the set of real numbers that can be represented as repeating decimals

The form of the repeating decimal is 0.abc cap

Where a, b and c are distinct digits

If x = 0.abcabc

1000x = abc.abc

1000x - x = abc

999x = abc

x = abc/999

a, b, c are distinct digits

Number of combinations possible = 10 × 9 × 8

= 720 combinations

Therefore each value appear is each place value = 720/10

= 72

Sum of the digits from 0 to 9 = 45

Sum of the elements of S = (45 × 72 × 111 / 999)

= 360

Therefore, the sum of the element is 360

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Resulting box has the greatest volume for the values  (25 ± 5√7)/6 .

This is a problem that can be solved using derivatives , maxima & minima and common logic.

Hence , going by logic :

Creating a flap of 'a' inches in width, the base of the box will be

 (10 - 2a) by (15 - 2a)

and the depth of the box will be the width of the fold-up flap: a.

Then the volume of the box is

 v = [tex]a(10 -2a)(15 -2a) = 150a -50a^2 +4a^3[/tex]

Using the derivative of the volume will be zero at the maximum volume.

 0 = [tex]dv/da = 150 -100a +12a^2[/tex]

This has roots at

 a = (100 ±√(100² - 4(12)(150)))/(2·12)

 a = (100 ± √2800)/24 = (25 ± 5√7)/6

Only the smaller of these solutions gives a maximum volume.

You should cut (5/6)(5-√7) ≈ 1.962 inches to obtain the greatest volume.

Similarly , replacing the values of 10 by A and 15 by B , a generalized solution can be formed .

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If a store decides to spend $1500 on Sunday TV ads for all-terrain tires, we can predict that 95% of the values for the revenue in those weeks from the sale of these will be between $21863.59 and $25617.41.

A company can use regression analysis to determine statistical relationships between the total sales of its products and the costs associated with promotions and advertising. The outcomes of these analyses can then be used to determine how best to allocate spending funds among, say, various products or sales regions.

n = 41

df = n - 2

df = 41 - 2 = 39

SSₓₓ = (n - 1)S²ₓ

SSₓₓ = (41 - 1) * (400)²

SSₓₓ = 6400000

y = 15531.3086 + 5.4728 * x

If, x = 1500 then:

y = 15531.3086 + 5.4728 * 1500

y = 23740.51

Prediction range of y at 95% = [tex]y + t_{\frac{0.05}{2},39 } * S_{e} * \sqrt{1 + \frac{1}{n} + \frac{(x - x_{1} )^{2}}{SS_{xx} } }[/tex]

Prediction range of y at 95% = [tex]23740.51 + 2.022691 * 915.247 * \sqrt{1 + \frac{1}{41} + \frac{(1500 - 1700)^{2} }{6400000}[/tex]

Prediction range of y at 95% = (2186.1 , 25619.92)

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Answer:

The Rate of return would then be 192 / 273 ≈ 70.32%