If I have 46 $ and the taxi cab charges 0.60$ plus 7$ fee how far can I ride

Answer:

(D) is equal to 8 so that means that u have to divide and multiply all in one

Answer:

Reflection

Step-by-step explanation:

Answer:

y = -4x + 14

Step-by-step explanation:

using the slope intercept form of a line

y = mx + c

Given points

slope (m) =

[tex] = \frac{y2 - y1}{x2 - x1} \\ = \frac{2 - 10}{3 - 1} \\ = \frac{ - 8}{2} \\ = - 4[/tex]

taking one point as for filling x and y and finding the y intercept (c)

y =mx + c

10 = (-4) × 1 + c

10 + 4 = c

14 = c

therefore the equation is

y = -4x + 14

Answer:

2y + 8x = 28

Step-by-step explanation:

Hi there

So we are going to solve this together

m = y - y1/y2- y1 =x - x1/x2 - x1

y - 10/ 2- 10 =x - 1/ 3 -1

y -10/-8 =x - 1/2

cross multiply

2(y - 10) =-8(x -1)

2y - 20= -8x + 8

Collect terms

2y +8x = 8 +20

ANSWER = 2y + 8x = 28

Hope this helps you!

Bye , have a nice day :-)

Answer:

It depends on what shape you have. Here are some formulas for different shapes.

Step-by-step explanation:

Rectangular prism: 2lw + 2lh + 2wh

Cylinder: 2 pi r² + 2 pi rh

Sphere: 4 pi r²

Cone: pi r² + pi rl

Square-based pyrimid: 1/2lp +B

I hope this helps!

Answer:

Step-by-step explanation:

2143.57

Answer:

dx/dt = 4c - 4x/15

Step-by-step explanation:

a. Find a formula for the rate of change in the amount of salt, dx/dtdx/dt, in terms of the amount of salt in the solution

Let c be the concentration of the incoming brine in grams per liter. Since it flows in at a rate of 4 liters per minute, the mass flow in is thus 4m.

Let x be the mass of salt present at time, t. The concentration of salt present at time, t is thus mass of salt/volume of tank = x/15. Since the well mixed solution is drained at 4 liters per minute, the mass flow out is thus 4x/15.

The net rate of change of amount of salt dx/dt = mass flow in - mass flow out

dx/dt = 4c - 4x/15

Answer:

sqrt(1^2 + 2^2)

[tex]\sqrt{2}[/tex]

Step-by-step explanation:

Answer:

1.14male studying biology

Answer:

B. √2^5

Step-by-step explanation:

(2^½. 2^¾)²

= 2¹ . 2^(1½)

= 2^(2½)

= 2^(5/2)

=√2^5

Answer:

1) x  =  [ - (12/1000)*  e∧ ( - 15/1000)*t  + 12/1000 ] /e∧ - (15/1000)*t

2) x =  - 0,012 * ( e ∧ 0.18 + 0,012 ) / e∧-0,18

Step-by-step explanation:

1.-Quantity of salt in the tank after t minutes

The rate  of change of the quantity of salt in the tank is:

dx(t) /dt   =  original quantity (0) + input quantity - output quantity  (1)

quantity = concentration* rate   Then

input quantity   =  0.04 Kg/lt * 5 Lt/min + 0.06 Kg/lt * 10Lt/min  =  0.2 Kg/min

+ 0.6  Kg/min  =  0,8 Kg/lt

output quantity =  Output concentration * rate of draining

rate of draining = 15 Lt/min

The input quantity and the output quantity occur at the same rate therefore the volume in the tank is constant  1000Lt.

output quantity = (x/1000 )*15

Plugging these values in equation (1) we get.

dx/dt  =  0,8  -  ( x/1000)* 15

The last one is a differential first-order equation like

x´ +  P(t)*x = q(t)

and the solution is:

x*μ   =  ∫ q(t)*μ*dt  + C

where    μ  is the integration factor   e ∧ ∫p(t)*dt

let´s call  b = -15/1000

μ = e ∧ ∫p(t)*dt  =  e∧∫ b*dt  =  e∧ b*t = e∧ ( -15/1000)*t

μ  =  e∧ - (15/1000)*t

Then  x*μ    =   x *  e∧ - (15/1000)*t

∫ q(t)*μ*dt  = ∫  0.8 * e∧ - (15/1000)*t*dt  =  0.8 * ∫ e∧bt * dt  

 ∫ q(t)*μ*dt  = 0.8 * ( 1/b ) e∧bt  = - 0,8 *( 15/1000) * e∧ ( - 15/1000)*t

∫ q(t)*μ*dt  = - (12/1000)*  e∧ ( - 15/1000)*t

x *  e∧ - (15/1000)*t  =   - (12/1000)*  e∧ ( - 15/1000)*t + C

Initial condition  t = 0  x = 0

0  =  - (12 / 1000 )* e⁰ = C

C = 12/1000

x *  e∧ - (15/1000)*t  =   - (12/1000)*  e∧ ( - 15/1000)*t  + 12/1000

x  =  [ - (12/1000)*  e∧ ( - 15/1000)*t  + 12/1000 ] /e∧ - (15/1000)*t

When t = 60 min

x =   [ - (12/1000)*  e∧ ( - 15/1000)*12 + 12/1000 ] / e∧ - (15/1000) * 12

x =  - 0,012 * ( e ∧ 0.18 + 0,012 ) / e∧-0,18

Answer:

Step-by-step explanation:

[tex]hope \: \: it \: \: helps} \beta \alpha \infty [/tex]

The length of B'C' is 0 units.

It is the movement of the shape in left, right, up, and down direction.

The translated shape will have the same shape and shape.

There is a positive value when translated to the right and up.

There is a negative value when translated to the left and down.

We have,

The length of AD = 5 units.

Since the rectangle translates down by 4 units,

The length of A'D' =5 units.

The width of the original rectangle is AB, which is 3 units.

Since the rectangle translates to the right by 2 units,

The width of the new rectangle = 3 units.

Now,

The length of B'C' is the same as the length of AD', which is 5 units.

Subtracting 5 units from 5 units gives us a length of 0 units.

Thus,

The length of B'C' is 0 units.

Learn more about translation here:

https://brainly.com/question/12463306

#SPJ7

Answer:

x = 5

Step-by-step explanation:

a) The third interior angle of this triangle is 180 - 20 x.  

The three interior angles must sum up to 180 degrees.

Therefore,  60 + 7x + 5 + 180 - 20x = 180, or

                       65  + 180 - 13x = 180, or

                               65 -  13x     = 0

Finally, 13x = 65, and so x = 5

Answer:

3q + 2p =

Step-by-step explanation:

Perimeter refers to the outside lines only so hence, 3q + 2p =

Answer: Fran's speed while swimming​ upstream = 1.4 km/h

Step-by-step explanation:

Given: Fran's swimming speed = 2.1 ​km/h

Speed of river = 0.7 km/h

The direction against the stream is called upstream.

Speed in Upstream = Fran's swimming speed - Speed of river

= 2.1-0.7  km/h

= 1.4 km/h

hence, Fran's speed while swimming​ upstream = 1.4 km/h

Answer:

The answer is

[tex]2 {x}^{2} + 3x - 1 = 0[/tex]

Why? Below I explain

Step-by-step explanation:

That formula has three variables a, b and c.

So, a = 2, b = 3 and c = -1

Because the formula is written like

[tex] \frac{ - b + - \sqrt{ {b}^{2} - 4 \times a \times c} }{2 \times a} [/tex]

Given:-

To find:-

Answer:-

Mass defect arises when the mass of the atom differs from the sum of masses of nucleons . As we know that the nucleus of an atom is made up of neutrons(n) and protons (p) , and the total mass of a atom is the mass of nucleons ( protons and neutrons ) as electrons have mass very low as compared to that of n or p .

If we denote mass number by [tex]\green{A}[/tex] , then ;

[tex]\implies A = n_{\rm neutrons} + n_{\rm protons} [/tex]

Let [tex] Z[/tex] be the atomic number, then ;

[tex]\implies n_p = Z [/tex]

So, the number of neutrons will be;

[tex]\implies n_n = (A-Z) [/tex]

Therefore total mass would be ;

[tex]\implies M = m_pZ +m_n (A-Z) [/tex]

Then the mass defect would be ,

[tex]\implies\underline{\underline{\green{ \Delta M = [Zm_p + (A-Z)m_n - M ] }}} [/tex]

where ,

_______________________________________

Now we know that the Atomic number of Nitrogen is 7(Z) and its mass number is 14(A) .

Now substitute the respective values,

[tex]\implies \Delta M = 7(1.007825) + (14-7)1.008665 - 14.0031 \\ [/tex]

[tex]\implies \Delta M = 7.054775 + 7(1.008665) - 14.00 31 [/tex]

[tex]\implies \Delta M = 7.054775 + 7.060655 - 14.0031 [/tex]

[tex]\implies \Delta M = 14.11543 - 14.0031 [/tex]

[tex]\implies \underline{\underline{\green{ \Delta M = 0.11233 \ u }}}[/tex]

Hence the mass defect is 0.11233 u .

Also this mass defect appears as energy which is responsible for the binding of nucleons together.

and we are done!

Answer:

it says round to the nearest 10th so it wouldn't be 81, it would be 81.8%

Answer:

f(-3) = -12

g(-2) = -19

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

f(x) = 3x - 3

g(x) = 3x³ + 5

f(-3) is x = -3 for function f(x)

g(-2) is x = -2 for function g(x)

Step 2: Evaluate

f(-3)

g(-2)

Answer:

f(-3) = -12

g(-2) = -19

Step-by-step explanation:

1.

f(x) = 3x - 3

One is asked to find (f(-3)), substitute (-3) into the given function (f) in place of (-3), and solve to evaluate,

f(-3) = 3(-3) - 3

Simplify,

= -9 - 3

= -12

2.

g(x) = [tex]3x^3+5[/tex]

The problem asks one to find (g(-2)), subtitute (-2) into the function in place of (x) and solve to find tis value,

g(-2) = [tex]3(-2)^3+5\\[/tex]

Remember any number raised to an exponent is equal to the base (the number that is being raised to the exponent) times itself the number of times that the exponent indicates,

[tex]=3(-8)+5\\=-24+5\\=-19[/tex]

Answer:

P(r ≥ 15) = 0.9943.

Step-by-step explanation:

We use the normal approximation to the binomial to solve this question.

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex].

625 trials and a probability of a 4.4% success on a single trial.

This means that [tex]n = 625, p = 0.044[/tex]

Mean and standard deviation:

[tex]mu = E(X) = np = 625*0.044 = 27.5[/tex]

[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{625*0.044*0.956} = 5.13[/tex]

P(r ≥ 15)

Using continuity correction, this is [tex]P(r \geq 15 - 0.5) = P(r \geq 14.5)[/tex], which is 1 subtracted by the p-value of Z when X = 14.5. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{14.5 - 27.5}{5.13}[/tex]

[tex]Z = -2.53[/tex]

[tex]Z = -2.53[/tex] has a p-value of 0.0057

1 - 0.0057 = 0.9943

So

P(r ≥ 15) = 0.9943.

Answer:

m(arc CD) = 112°

Step-by-step explanation:

Use the property of intersecting chords and angles between these chords,

m∠CED = [tex]\frac{1}{2}(\text{arc CD}+\text{arc}AB)[/tex]

m∠CED + m∠AED = 180°

80° + m∠CED = 180°

m∠CED = 100°

Now substitute the measure of angle CED and arc AB in the expression,

100° = [tex]\frac{1}{2}(88^{\circ}+\text{arc CD})[/tex]

200° = 88° + m(arc CD)

m(arc CD) = 112°

Answer:

3 1/2 hours

Step-by-step explanation:

time = distance/speed

440/110 = 4 hours

440/880 = 1/2 hours

4 minus 1/2 is 3 1/2

Answer:

hi

Step-by-step explanation:

i just need some points sorry not sorry

Answer:

[tex]a \frac{x}{n} = \sqrt[n]{a}^x .

\sqrt[3]{x}^4 \sqrt[3]{y} \sqrt[5]{z}^2 [/tex]

Answer:

2 1/2

Step-by-step explanation:

4 7/8= 39/8

2 2/8= 19/8

39/8 - 19/8 = 20/8 = 2 4/8 = 2 1/2

Answer:

g(-1 )=-1 and g(2)+g(1)=7

Step-by-step explanation:

If g(x) = x^3+x^2-x-2 find g(-1)

if we find g(-1)

we substitute all the x's in the function with -1

-1^3+-1^2-(-1)-2

-1^3 = -1

-1^2 = 1

-1+1+1-2

(two minuses make a plus)

-1+1 = 0

0+1 = 1

1-2 = -1

if x=-1, g(-1) is -1

g(2)+g(1)

substitute the x's in the function with 2 and 1 and add your results

2^3+2^2-2-2

2^3 = 8, 2^2 = 4

8+4-2-2

8+4= 12, 12-2 = 10, 10-2 = 8

g(2)=8

g(1) now

1^3 + 1^2-1-2

1^3=1, 1^2 = 1

1+1-1-2

1+1 = 2, 2-1 = 1, 1-2 = -1

g(3) = -1

g(2) (which equals 8) + g(3) (which equals -1) =

8+(-1) = 7

g(2)+g(3)=7

Answer:

The plane travelled for [tex]\text{$2$ hours}[/tex] at an average of speed [tex]120\; \rm mph[/tex] and [tex]\text{$3$ hours}[/tex] at an average speed of [tex]130\; \rm mph[/tex].

Step-by-step explanation:

Let [tex]x[/tex] denote the number of hours that the plane travelled at an average speed of [tex]120\; \rm mph[/tex].

Given that the trip is [tex]5\; \text{hours}[/tex] long in total, the plane would have travelled at an average speed of [tex]130\; \rm mph[/tex] for [tex](5 - x)\; \text{hours}[/tex].

The plane would have travelled [tex]120\, x[/tex] miles after [tex]x\; \text{hours}[/tex] at an average speed of [tex]120\; \rm mph[/tex]. Likewise, the plane would have travelled [tex]130\, (5 - x)\; \text{miles}[/tex] after [tex](5 - x)\; \text{hours}[/tex] at an average of [tex]130\; \text{mph}[/tex].

The plane has travelled [tex]630\; \text{miles}[/tex] in total. In other words:

[tex]120\, x + 130\, (5 - x) = 630[/tex].

Solve this equation for [tex]x[/tex]: [tex]x = 2[/tex].

In other words, the plane has travelled for [tex]\text{$2$ hours}[/tex] at an average of speed [tex]120\; \text{mph}[/tex]. It would have travelled for [tex](5 - x)\; \text{hours} = (5 - 2)\; \text{hours} = 3 \; \text{hours}[/tex] for the other part of the trip (at an average speed of [tex]130\; \text{mph}[/tex].)

Answer:

- 2+8x/x

Step-by-step explanation:

See image below:)

FYI you can use the app photo math you just take a pic of the problem and it gives you the answer and explains the steps and it is free

Answer:

(8x-2) / (x-8)

Step-by-step explanation:

8x/x-8 - 2/x-8

Since the denominator is the same, we can add the numerators

(8x-2) / (x-8)

Answer:

26=x

Step-by-step explanation:

-15 from both sides

3x=78 /:3

x=26

Answer:

17

Step-by-step explanation:

_____________ Hair color

Eye color ___ Brown ___ Black ___ total

Green _____ 22 ________ 15 ____ 37

Blue _______ 18 ________ 19 ____ 37

Total _______40 ________34 ____ 74

Calculate the expected frequency of Blue Eyes and Black Hair?

The expected frequency Count ;

(row total * column total) / total number of observations

Expected frequency ;

Blue eye n black hair = (37 * 34) / 74

Expected frequency count = 1258 / 74 = 17

Expected count = 17

Answer:

The row total of blue eyes is 18 + 19 = 37.

The column total of black hair is 15 + 19 = 34.

The total of the whole table is 22 + 15 + 18 +19 = 74.

Step-by-step explanation:

E=(37)(34)/74=1258/74=17