Answer:
The solution to the inequality is [tex](-\infty, 0) \cup (3, \infty)[/tex]
Step-by-step explanation:
We have a product, which is positive if both terms is positive or if both is negative.
Both positive:
[tex]x > 0[/tex]
[tex]x - 3 > 0 \rightarrow x > 3[/tex]
Then the intersection of these two is: [tex]x > 3[/tex]
Both negative:
[tex]x < 0[/tex]
[tex]x - 3 < 0 \rightarrow x < 3[/tex]
Then the intersection of those two is: [tex]x < 0[/tex]
Then:
Union of two solutions:
[tex]x < 0[/tex] or [tex]x > 3[/tex]
Then
[tex](-\infty, 0) \cup (3, \infty)[/tex]
Simplify the expression
Answer:
6
Step-by-step explanation:
3 sqrt(20) / sqrt(5)
We know that sqrt(a) /sqrt(b) = sqrt(a/b)
3 sqrt(20/5)
3 sqrt(4)
3 *2
6
21(2-y)+12y=44 find y
Answer:
[tex]\textbf{HELLO!!}[/tex]
[tex]21\left(2-y\right)+12y=44[/tex]
[tex]42-21y+12y=44[/tex]
[tex]~add ~similar\:elements[/tex]
[tex]42-9y=44[/tex]
[tex]Subtract~42~from~both~sides[/tex]
[tex]42-9y-42=44-42[/tex]
[tex]-9y=2[/tex]
[tex]Divide\:both\:sides\:by\:}-9[/tex]
[tex]\frac{-9y}{-9}=\frac{2}{-9}[/tex]
[tex]y=-\frac{2}{9}[/tex]
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hope it helps...
have a great day!
Express the following repeating decimal as a fraction in simplest form.
Answer:
[tex]0.\overline{369} = \frac{41}{111}[/tex]
Step-by-step explanation:
x = 0.369369369...
10x = 3.69369369...
100x = 36.9369369...
1000x = 369.369369...
1000x - x = 369
999x = 369
[tex]x = \frac{369}{999} \\\\x = \frac{123}{333}\\\\x = \frac{41}{111}[/tex]
