If a linear regression has a correlation coefficient of 0.85, which of the following statements is true?

1.The data is too scattered to fit a function to it.
2.The data does not have linear association.
3.The data has a weak linear association.
4.The data has a strong linear association.

Answer:

iv. q/6E0

Step-by-step explanation:

Electric flux formula:

The electic flux formula, of a charge q is given by, through an entire cube, is given by:

[tex]E = \frac{q}{E_o}[/tex]

In which [tex]E_o[/tex] is a constant related to the material.

The electric flux through any one face of the cube is:

Key-word is face, and a cube has 6 faces, with the force distributed evenly throughout it. Thus

[tex]E_f = \frac{1}{6} \times \frac{q}{E_o} = \frac{q}{6E_o}[/tex]

And the correct answer is given by option iv.

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Answer:

  row 13

Step-by-step explanation:

The sum of row n is 2^n, so the row number with a particular sum is ...

  2^n = sum

  n·log(2) = log(sum)

  n = log(sum)/log(2)

The row with sum 8192 is ...

  n = log(8192)/log(2) = 13

The row of Pascal's triangle that has a sum of 8192 is row 13.

Answer:

[tex]P(6am-12\ noon) = 0.305[/tex]

[tex]P(12\ noon - 6pm) = 0.143[/tex]

[tex]P(6pm-12\ midnight) = 0.322[/tex]

[tex]P(12\ midnight - 6am) =0.230[/tex]

Step-by-step explanation:

Given

[tex]\begin{array}{cc}{Time} & {Inventors} & {6am - 12\ noon} & {295} & {12\ noon -6pm} & {138} & {6pm - 12\ midnight} & {311} & {12\ midnight - 6am} & {222} & {Total} & {966} \ \end{array}[/tex]

Required

The probability of each time interval

To do this, we simply divide the number of inventors in the interval by the total inventors (966)

So, we have:

[tex]P(6am-12\ noon) = \frac{6am-12\ noon}{Total}[/tex]

[tex]P(6am-12\ noon) = \frac{295}{966}[/tex]

[tex]P(6am-12\ noon) = 0.305[/tex]

[tex]P(12\ noon - 6pm) = \frac{12\ noon - 6pm}{Total}[/tex]

[tex]P(12\ noon - 6pm) = \frac{138}{966}[/tex]

[tex]P(12\ noon - 6pm) = 0.143[/tex]

[tex]P(6pm-12\ midnight) = \frac{6pm-12\ midnight}{Total}[/tex]

[tex]P(6pm-12\ midnight) = \frac{311}{966}[/tex]

[tex]P(6pm-12\ midnight) = 0.322[/tex]

[tex]P(12\ midnight - 6am) =\frac{12\ midnight - 6am}{Total}[/tex]

[tex]P(12\ midnight - 6am) =\frac{222}{966}[/tex]

[tex]P(12\ midnight - 6am) =0.230[/tex]

Answer:

Step-by-step explanation:

Answer:

227 is the 74th term of your question.

Answer:

35°

Step-by-step explanation:

From the sketch made, to obtain B we use the cosine angle formula :

We have 2 so des and an included angle

Cos B = (a² + c² - b²) / 2ac

First we obtain the side c

c² = a² + b² - 2ab CosC

c² = 11.2² + 6.7² - 2(11.7 * 6.7) * cos 72

c = 11.13

Using the value of c

Cos B = (a² + c² - b²) / 2ac

CosB = (11.2² + 11.13² - 6.7²) / (2*11.2*11.13)

Cos B = 204.4269 / 249.312

B = Cos^-1(204.4269 / 249.312)

B = 34.9°

Answer:

The answer is B

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

0.99218

Answer:

The opposite of a number is the number on the other side of 0 number line, and the same distance from 0.

Answer:

x=7

Step-by-step explanation:

take 30 degree as reference angle

using sin tan rule

tan 30=opposite/adjacent

[tex]\frac{1}{\sqrt{3} }[/tex]=x/[tex]7\sqrt{3}[/tex]

[tex]\frac{1}{\sqrt{3} }[/tex] *[tex]7\sqrt{3}[/tex]

[tex]7\sqrt{3} /\sqrt{3}[/tex]

7=x

Answer:

Hence the correct option is the distribution with n = 225 will have a smaller standard error.

Step-by-step explanation:

Now the standard deviation is

[tex]S.E=\frac{\sigma }{\sqrt{n}}[/tex]

If n = 100 then consider [tex]\sigma =6[/tex]

[tex]S.E=\frac{6}{\sqrt{100}}=0.6[/tex].

If n= 225 then consider [tex]\sigma =6[/tex]

[tex]S.E=\frac{6}{\sqrt{225}}=0.4[/tex].

Here the distribution with n = 225 will have a smaller standard error.

Answer:

the top one that's orange

Answer:

I think there is no solution.

Step-by-step explanation:

Substitute:

Z = -3y-5x+25

X = 3y-2z-13

Put into the last formula:

14(3y-2z-13)-2y+3(-3y-5x+25) = 48

Then:

14(3y-2(-3y-5x+25)-13)-2y+3(-3y-5(3y-2z-13)) = 48

So:

14(3y-2(-3y-5(3y-2z-13)+25)-13)-2y+3(-3y-5(3y-2(-3y-5x+25)-13)) = 48

And so on.

Answer:

hi, yes the option B is the correct answer

Step-by-step explanation:

[tex]\frac{( \csc x+1)( \csc x-1)}{ \csc ^2x} = \frac{ { \csc }^{2} x - 1}{ \csc^{2} x} \\ = 1 - \sin^{2} x = \cos^{2} x \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

b. Since csc theta = 1/sin theta, we can multiply both sides by sin theta and you will end up with

[tex] \cos^{2} \theta + \sin^{2} \theta = 1[/tex]

which is an identity.

Answer:

Step-by-step explanation:

Answer:

2262.0646

Step-by-step explanation:

the answer is 2262.0646

Answer:

Yes.

Step-by-step explanation:

When you add the different amounts needed together ( 1lb 3oz + 1lb 8oz + 2lb 4 oz ), you get 4lb 15oz. Since there are 16oz in a pound, you need less than 5 lb. Therefore, you need less than 5lb, the 5lb bag will be more than enough.

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Answer:

  C

Step-by-step explanation:

The step shown indicates that y was eliminated from the equations. For choices A, B, D, this is done by adding the equations together (the y-coefficients are opposites). The result of doing that gives x-terms of 4x, 0x, and 0x, respectively. These x-terms do not match the one given: 2x.

For choice C, the y-term is eliminated by subtracting twice the second equation from the first. Doing that gives ...

  (4x +2y) -2(x +y) = (14) -2(3)

  4x +2y -2x -2y = 14 -6 . . . . eliminate parentheses

  2x = 8 . . . . . . . . . . . . . . collect terms

Answer:

$66.3

Step-by-step explanation:

price of a ticket without discount = $78

discount  % = 15%

discount amount = ?

price of a discounted ticket = ?

discount amount = discount% of price of a original ticket

=15/100 * $78

=$1170/100

=$ 11.7

price of the discounted ticket = $78 - $11.7

=$66.3

The discounted price of the stadium's normal ticket is  $66.3

A percentage is a value per hundredth. Percentages can be converted into decimals and fractions by dividing the percentage value by a hundred.

Given, A stadium's normal ticket price is $78 and As a special promotion they offer 15% off.

Therefore, The discounted price of the ticket should be (100 - 15)% = 85% of the original price which is,

= (85/100)×78.

= $66.3 is the discounted price.

learn more about percentages here :

https://brainly.com/question/24159063

#SPJ6

Answer:

c

Step-by-step explanation:

Answer:

The p-value of the test is 0.1611>0.01, which means that there is not significant evidence at the 1% significance level that less than 34% of fathers take no responsibility for child care

Step-by-step explanation:

A journal article reports that 34% of fathers take no responsibility for child care. A group of fathers believes that this estimate is too high.

At the null hypothesis, we test if the proportion is of at least 34%, that is:

[tex]H_0: p \geq 0.34[/tex]

At the alternative hypothesis, we test if the proportion is less than that, that is:

[tex]H_1: p < 0.34[/tex]

The test statistic is:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.

0.34 is tested at the null hypothesis:

This means that [tex]\mu = 0.34, \sigma = \sqrt{0.34*0.66}[/tex]

In a random sample of 80 fathers, it was found that 23 of those fathers take no responsibility for child care.

This means that [tex]n = 80, X = \frac{23}{80} = 0.2875[/tex]

Value of the test statistic:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{0.2875 - 0.34}{\frac{\sqrt{0.34*0.66}}{\sqrt{80}}}[/tex]

[tex]Z = -0.99[/tex]

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion below 0.2875, which is the p-value of Z = -0.99.

Looking at the Z-table, Z = -0.99 has a p-value of 0.1611.

The p-value of the test is 0.1611>0.01, which means that there is not significant evidence at the 1% significance level that less than 34% of fathers take no responsibility for child care

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Answer:

  $55,085.44

Step-by-step explanation:

The formula for the account balance is ...

  A = P(1 +r/n)^(nt)

where principal P is invested at annual rate r compounded n times per year for t years. Using the given values, we find the balance to be ...

  A = $21,000(1 +0.082/2)^(2·12) = $21,000(1.041^24) ≈ $55,085.44

The balance is $55,085.44 after 12 years.

Perpendicular Definition:

[tex] \large \boxed{m_1m_2 = - 1}[/tex]

Slopes of two different equations multiply each others and must equal to -1. We can also say that the perpendicular occurs only if both equations are negative reciprocal to each others. For example, we are given the equation of y = 2x. The perpendicular to y = 2x would be y = (-1/2)x. See how both are reciprocal to each others.

From the equation below:

[tex] \large{x + 5y = - 2}[/tex]

Since the equation is in the form of Ax+By = C. It is better to use the another slope formula which is:

[tex] \large \boxed{m = - \frac{A}{B} }[/tex]

From the equation above, use the slope formula to find the slope.

[tex] \large{m = - \frac{1}{5} }[/tex]

Therefore the equation has a slope of -1/5. Next to find the perpendicular equation to the original equation. Since our slope is -1/5 - that means the negative reciprocal of -1/5 is 5. Therefore the slope of perpendicular line is 5.

Next we will be using the point-slope form below:

[tex] \large \boxed{y - y_1 = m(x - x_1)}[/tex]

Given the y1 and x1 or (x1,y1) are the points. Our perpendicular slope is 5 which passes through the point (3,0). Substitute both slope and the point in.

[tex] \large{y - 0 = 5(x - 3)}[/tex]

Simplify in the slope-intercept form as we get:

[tex] \large{y = 5x - 15}[/tex]

Answer

Hope this helps and let me know if you have any doubts!

Answer:

The answer is B

Step-by-step explanation:

I went on socratic and found the answer

Answer:

second graph

Step-by-step explanation:

took the test on edge

Answer:

Step-by-step explanation:

i hope you get this helpfull to get answer of this question take the qr code and scan it then you will get the answer

Given:

The equation of a line is:

[tex]2y+3x=10[/tex]

The line is dilated by factor 3.

To find:

The result of dilation.

Solution:

The equation of a line is:

[tex]2y+3x=10[/tex]

For [tex]x=0[/tex],

[tex]2y+3(0)=10[/tex]

[tex]2y+0=10[/tex]

[tex]y=\dfrac{10}{2}[/tex]

[tex]y=5[/tex]

For [tex]x=2[/tex],

[tex]2y+3(2)=10[/tex]

[tex]2y+6=10[/tex]

[tex]2y=10-6[/tex]

[tex]2y=4[/tex]

Divide both sides by 2.

[tex]y=\dfrac{4}{2}[/tex]

[tex]y=2[/tex]

The given line passes through the two points A(0,5) and B(2,2).

If the line dilated by factor 3 with origin as center of dilation, then

[tex](x,y)\to (3x,3y)[/tex]

Using this rule, we get

[tex]A(0,5)\to A'(3(0),3(5))[/tex]

[tex]A(0,5)\to A'(0,15)[/tex]

Similarly,

[tex]B(2,2)\to B'(3(2),3(2))[/tex]

[tex]B(2,2)\to B'(6,6)[/tex]

The dilated line passes through the points A'(0,15) and B'(6,6). So, the equation of dilated line is:

[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

[tex]y-15=\dfrac{6-15}{6-0}(x-0)[/tex]

[tex]y-15=\dfrac{-9}{6}(x)[/tex]

[tex]y-15=\dfrac{-3}{2}x[/tex]

Multiply both sides by 2.

[tex]2(y-15)=-3x[/tex]

[tex]2y-30=-3x[/tex]

[tex]2y+3x=30[/tex]

Therefore, the equation of the line after the dilation is [tex]2y+3x=30[/tex].