If a hypothetical future Earth has increased the amount of radiation emitted to 604 W/m, calculate the hypothetical global surface temperature in degrees Kelvin and then in Celsius

Answers

Answer 1

Answer:

Explanation:

For amount of radiation from a hot body there is Stefan's Boltzman's law which is given below .

E = e σ T⁴

E is amount emitted , e is emissivity , σ is stefan's constant = 5.67 X 10⁻⁸ W / m² . for earth e =.85 approx

E = .85 x 5.67 X 10⁻⁸ x T⁴

604 = .85 x 5.67 X 10⁻⁸ x T⁴

604 = 4.82 x 10⁻⁸ T⁴

T⁴ = 125.31 x 10⁸

T =  3.3457 x 10²

= 334.57K

Temperature in Celsius = 334.57 - 273

= 61.57 Celsius .


Related Questions

Many grasses and few trees characterize ____________ (tundras/temperate grasslands).

Answers

Temperate grasslands

If a strong base, like NaOH, is added to a strong acid, like HCl, the pH of the resultant solution will _________. A.) Go up B.) Go down C.) Stay the same

Answers

Answer:

B.) Go down

Explanation:

Hello,

In this case, a strong base like NaOH has a high pH based on the scale wherein 7 is neutral, above 7 is basic and below 7 is acid. In such a way, by adding an acid, having a low pH, once it is added, the pH will go down until the equivalence point, which for strong base and strong acid should be 7.

Best regards.

Answer:

B) Go down

Explanation:

pH is defined as -log [H⁺], that means when concentration of H⁺ increases the pH decreases and when concentration of H⁺ decreases, pH increases.

When a strong acid as HCl is added to a solution, it is dissolved, thus:

HCl → H⁺ + Cl⁻

Thus, addition of a strong acid decreases pH because concentration of H⁺ increases.

Right answer is:

B) Go down

what started the wildfires

Answers

Answer:

It is a typical fires that started out of a lightning strike, or people carelessly starting it, or accidentally, or even arson, that went un-noticed and got out of hand.

Answer:

Explanation:

Forest fires always start by one of two ways - naturally caused or human caused. Natural fires are generally started by lightning, with a very small percentage started by spontaneous combustion of dry fuel such as sawdust and leaves. On the other hand, human-caused fires can be due to any number of reasons.

Chloroform is a commonly used anesthetic with a density of 1.483 g/mL. Determine the volume of chloroform needed to deliver a 9.37 g sample of the anesthetic

Answers

Answer:

The correct answer is 6.32 ml

Explanation:

We have the following data:

Mass : m = 9.37 g

Density : d= 1.483 g/mL

The density a substance is equal to the mass of the substance divided into its volume. So, we calculate the volume (V) of chloroform from the mass and density as follows:

[tex]d=\frac{m}{V}[/tex]   ⇒  [tex]V = \frac{m}{d} = \frac{9.37 g}{1.483 g/ml} = 6.32 ml[/tex]

In a titration how much 0.50 M HCl is needed to neutralize 1 liter of a 0.75 M solution of NaOH?

1.5 L

2.25 L

1.0 L

0.75 L

Answers

Answer:

1.5 L

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

HCl + NaOH —> NaCl + H2O

From the balanced equation above, The mole ratio of the acid (nA) = 1

The mole ratio of the base (nB) = 1

Step 2:

Data obtained from the question. This includes the following:

Molarity of acid (Ma) = 0.5M

Volume of acid (Va) =..?

Volume of base (Vb) = 1L

Molarity of base (Mb) = 0.75M

Step 3:

Determination of the volume of the acid needed for the reaction.

Using the formula:

MaVa/MbVb = nA/nB

The volume of the acid needed for the reaction can be obtained as follow:

0.5 x Va / 0.75 x 1 = 1

Cross multiply

0.5 x Va = 0.75 x 1

Divide both side by 0.5

Va = 0.75 /0.5

Va = 1.5 L

Therefore, the volume of the acid, HCl needed for the reaction is 1.5L

Which correctly defines a basic solution? A. [H+] is not present. B. [H+] is equal to [OH−]. C. [H+] is less than [OH−]. D. [H+] is greater than [OH−].

Answers

Answer:  A basic solution is defined as a solution which has more hydroxide (OH-) ions than hydronium ions (H+)

Why does dew form on the outside of your glass filled with ice cold water?

Answers

when the warm air hits the cold surface, it reaches dew point causing condensation

There are 0.55 moles of carbon dioxide gas in a 15.0 L container. This container is at a temperature of 300 K. What is the pressure of the gas inside the container? Use 8.31 L*kPa/mol*K for the gas constant.


A.)760 mm Hg\

B.) 271 kPa

C.) 2 atm

D.) 91.4 kPa

Answers

Answer:

[tex]\large \boxed{\text{D.) 91 kPa}}[/tex]

Explanation:

We can use the Ideal Gas Law — pV = nRT

Data:

V = 15.0 L

n = 0.55 mol

T = 300 K

Calculation:

[tex]\begin{array}{rcl}pV & =& nRT\\p \times \text{15.0 L} & = & \text{0.55 mol} \times \text{8.31 kPa$\cdot$ L$\cdot$K$^{-1}$mol$^{-1}\times$ 300 K}\\15.0p & = & \text{1370 kPa}\\p & = & \textbf{91 kPa}\end{array}\\\text{The pressure in the container is $\large \boxed{\textbf{91 kPa}}$}[/tex]

what is the reason that dogs shed

does the temperature of water affect the time it takes a sugar cube to dissolve ​

Answers

Answer:

Dogs naturally lose old or damaged hair by shedding. Although shedding. and yes

I am a subatomic particle
that is positively charged what am I?

Answers

The right answer is Proton.

Additional Information:

There are three types of subatomic particles. They are:

ProtonElectronNeutron

Proton is a positively charged particle,Electron is negatively charged particle and Neutron is charge less.

Hope it will be helpful to you...

What mass of water will be collected if 20.0
grams of hydrogen are consumed
2H2+O2--->2H2O
358g
179g
44.7g
Or 89.4g

Answers

Answer: 179 of [tex]H_2O[/tex] will be produced.

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} H_2=\frac{20.0g}{2.01g/mol}=9.95moles[/tex]

[tex]2H_2+O_2(g)\rightarrow 2H_2O[/tex]

According to stoichiometry :

2 moles of [tex]H_2[/tex] give =  2 moles of [tex]H_2O[/tex]

Thus 9.95 moles of [tex]H_2[/tex] will require=[tex]\frac{2}{2}\times 9.95=9.95moles[/tex]  of [tex]H_2O[/tex]

Mass of [tex]H_2O=moles\times {\text {Molar mass}}=9.95moles\times 18g/mol=179g[/tex]

Thus 179 of [tex]H_2O[/tex] will be produced.

mutations that neither benefit nor harm the organism have (blank) effect on the organisms survival

Answers

Answer:

I would say that the mutation has no effect on the organism, as it doesn't help or harm it.

hope this helps :)

Explanation:

Answer:

its a neutral

Explanation:

i did the test

What is the oxidation half-reaction for this unbalanced redox equation? cr2o72– + fe2+ → cr3+ + fe3+ cr3+ → cr2o72– cr2o72– → cr3+ fe3+ → fe2+ fe2+ → fe3+?

Answers

Answer:

6Fe^2+(aq) -------> 6Fe^3+(aq) + 6e

Explanation:

The balanced oxidation half equation is;

6Fe^2+(aq) -------> 6Fe^3+(aq) + 6e

A redox reaction is actually an acronym for oxidation-reducation reaction. Since the both reactions are complementary, there can't be oxidation without reduction and there can't be reduction without oxidation.

The main characteristic of redox reactions is that electrons are transferred in the process. The number of electrons transferred is usually deduced from the balanced reaction equation. For this reaction, the balanced overall reaction equation is;

Cr2O7^2–(aq) + 6Fe^2+(aq) +14H^+(aq)→ 2Cr^3+(aq) + 6Fe^3+ (aq) + 7H2O(l)

It is clear from the equation above that six electrons were transferred. Thus six Fe^2+ ions lost one electron each in the oxidation half equation as shown in the balanced oxidation half equation above.

Why is fusion not used to generate electrical power ?

Answers

Answer:

Fusion doesn't produce runway chain reactions the way fission can, so there's no need to worry about meltdowns.

Way too much energy

5) Usted empuja muy fuerte un escritorio pesado e intenta moverlo. Usted efectúa trabajo sobre el escritorio: a.- Ya sea que lo mueva o no, siempre y cuando usted ejerza una fuerza. B.- Sólo si el escritorio se mueve. C.- Sólo si el escritorio no se mueve. D.- Nunca; el escritorio hace trabajo sobre usted. E.- Ninguna de las anteriores. ME AYUDAN PORFA?

Answers

Answer:

5) You push hard on a heavy desk and try to move it. You do work on the desk: A.- Whether you move it or not, as long as you exert a force. B.- Only if the desktop moves. C.- Only if the desktop does not move. D.- Never; the desk does work on you. E.- None of the above. CAN YOU HELP ME?

B.- Only if the desktop moves.

Explanation:

No work is done if a force is exerted but no displacement occurs. A force perpendicular to the displacement does no generate work.

How many grams of KF are in 2 liters of a 3.0 M solution of KF

Answers

Answer:

mass ( g ) = 348 g

Explanation:

First you know : M = mole / volume (L)

in question you have the M and V and the formula of SUBSTANCE ( KF )

first you get the number of mole from equation above

so 3 = no of mole / 2

no of mole = 3 × 2 = 6 moles

and the moles equation is no of moles = mass ( g ) / molecular weight ( g/mole )

so you have already calculate the moles and you can know the MW from the Question

Mw of KF = 39 + 19 = 58

so n = mass / MW

so 6 = mass / 58

mass ( g ) = 348 g

GOOD LUCK

What is the compounds of AICI3 and H+

Answers

Answer:

Aluminium Chloride and Hyrdron, also known as proton/

Explanation:

Which options identify what the arrows in the diagram
represent? Check all that apply.
D atoms
elements
energy
gas
particles

Answers

Answer:

D

Explanation:

Which one is it? Please help

Answers

Chemical properties can only be tested if you change the substance

Answer:

Chemical properties can be tested without changing the substance

Explanation:

What is the overall reduction potential for the reaction Agt (aq) + Cu(s)——>Ag(s) + Cu2+ (aq)?
-0.46 V
+0.46 V
+0.57 v
+1.14V

Answers

Answer:

it should be +0.46 :)

Explanation:

I just took the test and got it right.

Answer:

I think it's +1.14 V, but don't take my word for it..

A 0.223 mole sample of gas is held at 33.0 C and 2.00 atm, What's the volume of the gas? R = 0.0821 L atm / mol K answer soon il give brainiest.

Answers

Answer:

The volume of the gas is 2.80 L.

Explanation:

An ideal gas is a theoretical gas that is considered to be made up of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The Pressure (P) of a gas on the walls of the container that contains it, the Volume (V) it occupies, the Temperature (T) at which it is located and the amount of substance it contains (number of moles, n) are related from the equation known as Equation of State of Ideal Gases:

P*V = n*R*T

where R is the constant of ideal gases.

In this case:

P= 2 atmV= ?n=0.223 molesR= 0.0821 [tex]\frac{L*atm}{mol*K}[/tex]T=33 °C= 306 °K (being O°C= 273°K)

Replacing:

2 atm* V= 0.223 moles*0.0821 [tex]\frac{L*atm}{mol*K}[/tex]* 306 K

Solving:

[tex]V=\frac{0.223 moles*0.0821\frac{L*atm}{mol*K} * 306 K}{2 atm} \\[/tex]

V= 2.80 L

The volume of the gas is 2.80 L.

Describe the benefits of using nanoparticles instead of other, larger technology.

Answers

Answer:

it has  a huge surface-to-volume ratio, very high porosity and completely different physiochemical properties.

Explanation:

idk if the answer is good  !

sorry

How many grams of H2 can be produced from the reaction of 11.50 g of sodium with an excess of water? The equation for the reaction is 2 Na + 2 H2O -> 2 NaOH + H2 Ans: 0.504 2 g H2 I would like to know how to solve this problem, the teacher gave me the answer but I am unsure how to solve it thanks!

Answers

Answer:

[tex]m_{H_2}=0.504gH_2[/tex]

Explanation:

Hello,

In this case, since the reaction is:

[tex]2 Na + 2 H_2O \rightarrow 2 NaOH + H_2[/tex]

We notice that since there is an excess of water, we can directly compute the yielded grams of hydrogen by using the following stoichiometric procedure, considering the 2:1 molar ratio between sodium and hydrogen (notice the 2 before the sodium and the 1 before the hydrogen at the chemical reaction) and that gaseous hydrogen has a molar mass of 2 g/mol:

[tex]m_{H_2}=11.50gNa*\frac{1molNa}{22.98gNa} *\frac{1molH_2}{2.02molNa} *\frac{2gH_2}{1molH_2} \\\\m_{H_2}=0.504gH_2[/tex]

Best regards.

Answer:

0.503g of H₂ are produced

Explanation:

Based on the chemical reaction:

2 Na + 2 H₂O → 2 NaOH + H₂

2 moles of Na react with 2 moles of water to produce 2 moles of NaOH and 1 mole of H₂

11.50g of Na -limiting reactant, molar mass 22.99g/mol- are:

11.50g× (1mol / 22.99g) = 0.500 moles of Na.

As 2 moles of Na produce 1 mole of H₂:

0.500 moles of Na × (1 mole H₂ / 2 moles Na) = 0.250 moles of H₂

As molar mass of H₂ is 2.01g/mol:

0.250 moles of H₂ × (2.01g / 1mol) = 0.503g of H₂ are produced

How many milliliters of 0.2 M NaOH are required to exactly neutralize 40 milliliters of 0.1 M HCl?

A) 10
B) 20
C) 40
D) 80

Answers

Answer:

Option B. 20mL

Explanation:

Step 1:

Data obtained from the question.

Volume of base (Vb) =..?

Molarity of base (Mb) = 0.2M

Volume of acid (Va) = 40mL

Molarity of acid (Ma) = 0.1M

Step 2:

The balanced equation for the reaction.

HCl + NaOH —> NaCl + H2O

From the balanced equation above, the following were obtained:

Mole ratio of the acid (nA) = 1

Mole ratio of the base (nB) = 1

Step 3:

Determination of the volume of base, NaOH needed for the reaction. This is illustrated below:

MaVa/MbVb = nA/nB

0.1 x 40 / 0.2 x Vb = 1

Cross multiply

0.2 x Vb = 0.1 x 40

Divide both side by 0.2

Vb = 0.1 x 40 / 0.2

Vb = 20mL

Therefore, the volume of the base is 20mL.

Is the same reactant always the limiting reactant?

Answers

No because the limiting reactant is determined by calculating the amount of product therefore the limiting reactant will not be the same for a given reaction

Help me, I don’t understand

Answers

Answer:

option c

Explanation:

ffuunkie. tfnhc dhrhrjebrjeieie

opening c
Bssieehskwkbbshsi

Using the equation below, calculate the approximate moles of oxygen gas (O2) required to completely react with 719.68 moles of aluminum (Al). 4Al (s) + 3O2(g) -----> 2Al2O3(s)

Answers

Answer:

539.76 moles of O₂

Explanation:

Equation of reaction:

4Al + 3O₂ → 2Al₂O₃

From the equation of reaction above, 4 moles of Al will react with 3 moles of O₂

We can use mole-concept to find the number of moles of O₂.

4 moles of Al = 3moles of O₂

719.68 moles of Al = x moles of O₂

X = (3 × 719.68) / 4

X = 2159.04 / 4

X = 539.76 moles

539.76 moles of O₂ will react with 719.68 moles of Al

Answer:

[tex]n_{O_2}=959.57molO_2[/tex]

Explanation:

Hello,

In this case, given the reaction:

[tex]4Al (s) + 3O_2(g) \rightarrow 2Al_2O_3(s)[/tex]

Since aluminum and oxygen are in a 4:3 molar ratio, we compute the moles of oxygen that completely react as shown below:

[tex]n_{O_2}=719.68molAl*\frac{3molO_2}{4molAl} \\\\n_{O_2}=959.57molO_2[/tex]

Best regards.

Which of these is true concerning an endothermic reaction? *
When a system absorbs more energy than it releases and has a negative AH.
When a system absorbs more energy than it releases and has a positive AH.
When a system releases more energy than it absorbs and has a negative AH.
When a system releases more energy than it absorbs and has a positive AH.

Answers

Answer:

A system absorbs more energy than it releases and has a positive AH  

Explanation:

Answer:

Explanation:

Endothermic (endo = into + thermic = heat) means that heat energy is going into a system.

The products will have more energy than the reactants and ΔH will be positive.

A is wrong, because ΔH is positive.

C and D are wrong, because the system absorbs more energy than it releases.

What is the % of each element in Ni3{PO4) 2 ?​

Answers

Answer:

nickel 48.1063%

Phosphorus 16.9245%

Oxygen 34.9692%

The percent composition of each element like nitrogen, oxygen and phosphorous in Ni₃(PO₄)₂ are 48.03%, 34.97% and 16.93% respectively.

How do we calculate % composition?

Percent composition of any element present in any compound will be calculated as:
% comosition = (Mass of element / Mass of compound)×100%

Mass of Ni₃(PO₄)₂ compound = 366.02 g/mol

Molar mass of 3 Nitrogen atoms = 3×58.6 = 175.8 g/mol

Moar mass of 2 Phosphorous atoms = 2×31 = 62 g/mol

Moar mass of 8 Oxygen atoms = 8×16 = 128 g/mol

% comosition of Nitrogen = (175.8/366.02)×100% = 48.03%

% comosition of Oxygen = (128/366.02)×100% = 34.97%

% comosition of Phosphorous = (62/366.02)×100% = 16.93%

Hence % composition of nitrogen, oxygen and phosphorous is 48.03%, 34.97% and 16.93% respectively.

To know more about percent composition, visit the below link:

https://brainly.com/question/21044245

In CaSO4, the oxidation number of Ca is
that of S is
and that of O is

Answers

Answer: In CaF2, the oxidation number of Ca is +2

, and that of F is -1

. In H2SO4, the oxidation number of H is +1

, that of S is +6

, and that of O is -2

. In CaSO4, the oxidation number of Ca is +2

, that of S is +6

, and that of O is -2

. In HF, the oxidation number of H is +1

, and that of F is -1

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