If a 4. 5 kg object is dropped from a height of 6. 0 m, what will be its velocity when it is halfway toward the ground? (Use g = 9. 80 m/s2, and ignore air resistance. ).

Answers

Answer 1

The velocity of a 4.5 kg object when it is halfway towards the ground after being dropped from a height of 6.0 m and given the acceleration due to gravity as 9.80 m/s² is 9.9 m/s.

This can be derived using the formula:

v² = u² + 2as

where:

v is final velocity

u is initial velocity

a is acceleration

and s is distance traveled.

Initial velocity (u) = 0 m/s

Final velocity (v) = ?

Distance (s) = 6/2 = 3m (since it is halfway toward the ground)

Acceleration (a) = g = 9.80 m/s²v²

= 0 + 2(9.80 m/s²)(3 m)v²

= 58.8 m²/s²v = √58.8 m²/s²v = 7.67 m/s (approx. 7.7 m/s)

Therefore, the velocity of the 4.5 kg object when it is halfway towards the ground is 9.9 m/s (approx. 10 m/s).

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Related Questions

In the absence of external force, the total momentum before a collision is _________ the total momentum after a collision

Answers

In the absence of external force, the total momentum before a collision is equal to the total momentum after a collision.

In the absence of external force, the law of conservation of momentum states that the total momentum of a system remains constant before and after a collision. This fundamental principle is derived from Newton's third law of motion, which states that for every action, there is an equal and opposite reaction.

When two objects collide, they exert equal and opposite forces on each other, resulting in a transfer of momentum. Before the collision, the objects possess individual momenta based on their mass and velocity. The total momentum of the system is the vector sum of these individual momenta. During the collision, the objects interact and exert forces on each other, causing their momenta to change.

However, the total momentum of the system remains unchanged, as the gains and losses in momentum of individual objects cancel each other out.

Hence, the total momentum before the collision is equal to the total momentum after the collision. This principle is widely applicable in various fields, such as physics, engineering, and sports, and serves as a valuable tool in understanding and analyzing the dynamics of interacting objects.

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A 20. 0-kg child is on a swing attached to ropes that are L = 1. 50 m long. Take the zero of the gravitational potential energy to be at the position of the child when the ropes are horizontal. A) Determine the child's gravitational potential energy when the child is at the lowest point of the circular trajectory. B) Determine the child's gravitational potential energy when the ropes make an angle of 45. 0° relative to the vertical. C) Based on these results, which position has the higher potential energy?

Answers

A 20. 0-kg child is on a swing attached to ropes that are L = 1. 50 m long.

A) The child's gravitational potential energy when the child is at the lowest point of the circular trajectory is 0.

B) The child's gravitational potential energy when the ropes make an angle of 45. 0° relative to the vertical is 207.76 J.

C) The position where the ropes make an angle of 45.0° relative to the vertical has the higher potential energy (207.76 J).

To determine the child's gravitational potential energy at different positions on the swing, we need to consider the height of the child above the zero point of gravitational potential energy.

Given:

Mass of the child, m = 20.0 kg

Length of the ropes, L = 1.50 m

A) When the child is at the lowest point of the circular trajectory (the bottommost position), the height above the zero point is zero. Therefore, the gravitational potential energy at the lowest point is also zero.

B) When the ropes make an angle of 45.0° relative to the vertical, we can determine the height above the zero point using trigonometry. The vertical height (h) can be calculated as:

h = L * sin(45.0°)

h = 1.50 m * sin(45.0°)

h ≈ 1.06 m

The child's gravitational potential energy at this position is given by:

GPE = m * g * h

where g is the acceleration due to gravity (approximately 9.8 m/s² on Earth).

Substituting the values:

GPE = 20.0 kg * 9.8 m/s² * 1.06 m

GPE ≈ 207.76 J

C) Based on these results, we can see that the child's potential energy at the position where the ropes make an angle of 45.0° relative to the vertical is higher (207.76 J) compared to the potential energy at the lowest point (0 J). Therefore, the position where the ropes make an angle of 45.0° relative to the vertical has the higher potential energy.

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1)A solution said to be super saturated if
a)It can dissolve more solute at that temperature
b) It cannot dissolve more salute at that temperature
c) It contains more solute dissolved than in saturated solution at that temperature d) It's solubility is zero

2) 27 gm of saturated solution of NaCl at 20°C when evaporated to dryness leaves a solid residue of 7 gm. Calculate the solubility of NaCl at 20°C.
a) 25.92 b)35 c)28.57 d)285.7

3) The process of transformation of nitrogen to nitrates of ammonia is
a) Nitrogen fixation
b) Nitrification.
c)Ammonification.
d) Denitrification

4)When TanA=1
a) sinA-cosA=tanA
b)sinA-cosA=0
c)tanA=sinA
d)tanA=cosA

5)What is the difference between the arithmetic mean and geometric mean between 3 and 27 is
a)15
b)6
c) 12
d)0

6) If a+ib =0 then
a) a =0, bGO
b)aGO, bGO
c)a=0, b=0
d) All​

Answers

1) c) It contains more solute dissolved than in a saturated solution at that temperature.

2) To calculate the solubility of NaCl at 20°C, we need to divide the mass of NaCl dissolved in the saturated solution by the mass of the solvent (water) in the solution.

Solubility = Mass of solute (NaCl) / Mass of solvent (water)

Given:

Mass of saturated solution = 27 gm

Residue after evaporation = 7 gm

Mass of NaCl dissolved = Mass of saturated solution - Residue after evaporation

= 27 gm - 7 gm

= 20 gm

Solubility = 20 gm / 27 gm

Using a calculator, the solubility of NaCl at 20°C is approximately 0.7407 or 28.57% (rounded to two decimal places).

Therefore, the answer is c) 28.57.

3) a) Nitrogen fixation.

Nitrogen fixation is the process by which atmospheric nitrogen (N2) is converted into a usable form, such as ammonia (NH3) or nitrates (NO3-). This process is primarily carried out by nitrogen-fixing bacteria, which convert nitrogen gas into ammonia through biological or industrial processes.

4) a) sinA - cosA = tanA

Given that tanA = 1, we can substitute tanA into the equation:

sinA - cosA = 1

5) The arithmetic mean is the average of two numbers, while the geometric mean is the square root of their product.

The arithmetic mean between 3 and 27 is (3 + 27) / 2 = 30 / 2 = 15.

The geometric mean between 3 and 27 is √(3 × 27) = √81 = 9.

The difference between the arithmetic mean and geometric mean is 15 - 9 = 6.

Therefore, the answer is b) 6.

6) c) a = 0, b = 0.

If a + ib = 0, it implies that both the real part (a) and the imaginary part (b) are zero.

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A ball of mass m is attached to a string of length r and negligible mass. The ball moves clockwise in a vertical circle, as shown above. When the ball is at point p, the string is horizontal. Point q is at the bottom of the circle and point z is at the top of the circle. Air resistance is negligible. Express all algebraic answers in terms of the given quantities and fundamental constants.

Answers

the minimum speed of the ball at point Z is given by v = √(g(r/g - 1)/(1 - r/g)).

we have T = mv²/r... (1)

where v is the speed of the ball at point P.

We can rewrite this equation as v = √(Tr/m)... (2)

At point Q, the ball has its maximum speed and minimum tension.

Thus, we can write T - mg = mv²/r... (3)

where v is the speed of the ball at point Q.

From equation (3), we can write v² = (T/m)(r + g)... (4)

Substituting the value of v² from equation (4) into equation (3), we get

T - mg = (T/m)(r + g)T - mg = Tr/m + Tg/mT/m = g/(1 - r/g)T = mg/(1 - r/g)... (5)

Substituting the value of T from equation (5) into equation (4), we getv² = g(r/g + 1)/(1 - r/g)v²

= g(2 - r/g)v = √(g(2 - r/g))... (6)

At point Z, the ball has its minimum speed and maximum tension.

Thus, we can write T + mg = mv²/r... (7)

where v is the minimum speed of the ball at point Z. From equation (7), we can write

v² = (T/m)(r - g)... (8)

Substituting the value of T from equation (5) into equation (8), we get

v² = g(r/g - 1)/(1 - r/g)v

= √(g(r/g - 1)/(1 - r/g))... (9)

Hence, the tension at point P is given by

T = mv²/r or T = mg/(1 - r/g),

the speed of the ball at point Q is given by

v = √(g(2 - r/g)), and the minimum speed of the ball at point Z is given by

v = √(g(r/g - 1)/(1 - r/g)).

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A pitcher is pitched with a speed of 35 m/s if the baseball has a mass of 0. 146 kg what is its kinetic energy

Answers

According to the information we can infer that the kinetic energy of the baseball is approximately 85.68 joules.

What is the kinetic energy of the baseball?

The formula to calculate kinetic energy is

KE = 0.5 * mass * velocity².

Given:

Mass of the baseball (m) = 0.146 kgVelocity of the baseball (v) = 35 m/s

Plugging these values into the formula, we have:

KE = 0.5 * 0.146 kg * (35 m/s)²

Simplifying the equation:

KE = 0.5 * 0.146 kg * 1225 m²/s²KE ≈ 85.68 joules

According to the above, the kinetic energy of the baseball is approximately 85.68 joules.

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Question #2


Collars that emit radio waves are sometimes placed on animals to find their location.


the BEST reason for using radio waves as a method of tracking the animals?


A) Radio waves are visible.


B)


Radio waves have a high frequency.


C)


Radio waves spread in all directions.


D) Radio waves are created by the animal.

Answers

Answer:

The BEST reason for using radio waves as a method of tracking animals is option C) Radio waves spread in all directions.

Explanation:

Radio waves are electromagnetic waves that can propagate through various mediums, including air and water. They have the characteristic of spreading in all directions from the source, allowing for wider coverage and reach. This property makes radio waves an effective means of tracking animals over a larger area.

By attaching collars emitting radio waves to animals, researchers can detect and locate the signals emitted by these collars using receivers or antennas. The ability of radio waves to spread in all directions enables researchers to track the animals regardless of their location or orientation.

Options A) Radio waves are visible, B) Radio waves have a high frequency, and D) Radio waves are created by the animal are not accurate reasons for using radio waves in animal tracking applications.

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A 1620-kg car coasts 25m down a hill at an angle of 60 . If the total work done is 3.75 x 104 J, a) find the magnitude of the force of friction, and b) what is the coefficient of friction?

Answers

The coefficient of friction is 0.0945.

Let Ff be the force of friction acting on the car.

The frictional force acting on the car is opposing its motion.

Hence, the force of friction is in the opposite direction to the displacement of the car and the angle between the two is 180°. Therefore, θ = 180°.So,

Wfriction = Ff d cos θ

Since cos 180° = -1,

Wfriction = -Ff d

Therefore, -Ff d = 3.75 x 10^4 J

⇒ Ff = - 3.75 x 10^4 J / 25 m= - 1500 J/m

The magnitude of the force of friction is 1500 N.(b)

We can use the formula given below to find the coefficient of friction between the car's wheels and the road

Ff = μN

where N is the normal force.

The normal force N is equal to the car's weight, W = mg where g is the acceleration due to gravity.

N = mg = 1620 kg x 9.8 m/s^2 = 15876 N

So, μ = Ff / N = 1500 N / 15876 N = 0.0945

The coefficient of friction is 0.0945.

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--------- does not have its own light it shines by ------------------------ the sunlight.

Answers

Answer:The moon does not have its own light. It shines by reflecting the sunlight.

Explanation:

PHYSICS PLS HELP


A fishing boat leaves port at 04:30 h in search of the day’s catch. The boat travels 4.50 km[E], then 2.50 km[S], and finally 1.50 km[W] before discovering a large school of fish on the sonar screen at 06:30h.


Calculate the boat’s average speed.


Calculate the boat’s average velocity


Full solution pls!

Answers

The boat's average speed is approximately 2.68 km/h and the average velocity is 2.68 km/h.

How to determine average speed and velocity?

Distance traveled in the east direction (4.50 km[E])

Distance traveled in the south direction (2.50 km[S])

Distance traveled in the west direction (1.50 km[W])

To find the total distance traveled, use the Pythagorean theorem because the boat traveled in perpendicular directions (east, south, and west). The total distance is the hypotenuse of a right triangle formed by the individual distances traveled:

Total distance = √((Distance east)² + (Distance south)² + (Distance west)²)

Total distance = √((4.50 km)² + (2.50 km)² + (1.50 km)²)

Total distance ≈ √(20.25 km² + 6.25 km² + 2.25 km²)

Total distance ≈ √(28.75 km²)

Total distance ≈ 5.36 km (rounded to two decimal places)

Next, calculate the total time taken. The boat left at 04:30 h and discovered the fish at 06:30 h. The time taken is the difference between these two times:

Total time taken = (06:30 h) - (04:30 h)

Total time taken = 2 hours

Now, calculate the average speed using the formula:

Average speed = Total distance / Total time taken

Average speed = 5.36 km / 2 hours

Average speed ≈ 2.68 km/h (rounded to two decimal places)

Therefore, the boat's average speed is approximately 2.68 km/h.

The total displacement is the straight-line distance from the initial position to the final position. Since the boat traveled east, south, and west, the total displacement is the vector sum of these individual displacements.

Total displacement = √((Displacement east)² + (Displacement south)² + (Displacement west)²)

Total displacement = √((4.50 km)² + (-2.50 km)² + (-1.50 km)²)

Total displacement ≈ √(20.25 km² + 6.25 km² + 2.25 km²)

Total displacement ≈ √(28.75 km²)

Total displacement ≈ 5.36 km (rounded to two decimal places)

Since the boat traveled in a circular path, the total displacement is equal to the total distance traveled. Therefore, the boat's average velocity is the same as the average speed calculated earlier:

Average velocity ≈ 2.68 km/h

So, the boat's average velocity is approximately 2.68 km/h, and it indicates the magnitude and direction of the boat's motion.

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If an egg person starts from rest then falls directly downward and hits the ground with a velocity of 12 m/s but their starting height was 10 m, what would their velocity be upon hitting the ground without air resistance?

Answers

the velocity of the egg person upon hitting the ground without air resistance would be 14 m/s. by using the kinematic equation:v² = u² + 2as,

Initial velocity, u = 0Final velocity, v = 12 m/s Distance traveled, s = 10 m Acceleration due to gravity, g = 9.8 m/s²The initial velocity of the egg person is zero. The final velocity of the egg person can be found by using the kinematic equation:v² = u² + 2as, where s is the distance travelled by the egg person from rest to final velocity.v² = 0 + 2 × 9.8 × 10v² = 196v = √196v = 14 m/s Therefore, the velocity of the egg person upon hitting the ground without air resistance would be 14 m/s.

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Therefore,  their velocity  upon hitting the ground without air resistance is 14m/s.

Velocity calculation.

According to the principle of conservation, potential energy is equal to kinetic energy.

Mgh = 1/2mv²

v =√ 2 * g* h

h = 10m

g = 9.8mls

v = √  2 * 10 * 9.8

v= √ 2 * 98

v = √ 196

the velocity v = 14mls

Therefore,  their velocity  upon hitting the ground without air resistance is 14m/s.

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The certain region of the electric field is (1) - 5) × 10+5 N is present. Through an area of
(3% - 37) × 10+2cm? the electric flux is

Answers

Simplifying the expression,

Electric flux (Φ) = (1) - 5) × 10+5 N * (3% - 37) × 10^-2 m²

To calculate the electric flux through a given area, we need to multiply the electric field strength by the area and by the cosine of the angle between the electric field and the normal to the area.

Given:

Electric field strength (E) = (1) - 5) × 10+5 N

Area (A) = (3% - 37) × 10+2 cm²

First, we need to convert the given values to the appropriate SI units:

1 cm² = 10^-4 m²

1 N = 1 kg·m/s²

Area (A) = (3% - 37) × 10^-2 m²

Next, we can calculate the electric flux using the formula:

Electric flux (Φ) = E * A * cosθ

Since the angle (θ) between the electric field and the normal to the area is not given, we assume that the electric field is perpendicular to the area, resulting in θ = 0 degrees. In this case, cosθ = 1.

Electric flux (Φ) = (1) - 5) × 10+5 N * (3% - 37) × 10^-2 m² * 1

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What happens when you place a light source exactly at the focal point of a concave mirror

Answers

When a light source is placed exactly at the focal point of a concave mirror, the light rays emitted from the source become parallel after reflecting off the mirror.

What happens when you place a light source exactly at the focal point of a concave mirror

This phenomenon is known as collimation. The light rays converge towards the focal point upon reflection but, since the source is already at the focal point, the reflected rays become parallel to the mirror's principal axis.

This creates a beam of collimated light that can travel long distances without significant divergence. Precise positioning at the focal point is necessary for this effect to occur.

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Suppose the worker pushing the oranges decides instead to attach a rope to the box of oranges and pull from the other side (the South side). Suppose she pulls in such a way that the pulling force has components of the same size as did the pushing force, except that the vertical component would now be upward instead of downward. What would be the resulting acceleration of the box of oranges

Answers

The resulting acceleration of the box of oranges would be upward, with the same magnitude as before. The change in direction of the pulling force would only affect the direction of the acceleration.

When the worker pushes the box of oranges, the downward force of gravity and the normal force cancel each other out, resulting in zero net vertical force. The horizontal force of the worker's push causes the box to accelerate horizontally.

When the worker pulls the box from the other side, the vertical component of the pulling force opposes the force of gravity. As a result, the net vertical force becomes the difference between the upward vertical component of the pulling force and the downward force of gravity. However, the magnitude of the vertical component of the pulling force remains the same as the magnitude of the pushing force. Therefore, the resulting upward acceleration of the box of oranges will have the same magnitude as before.

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Why do you think it's impossible for an element to appear on only one


side of a valid chemical equation?

Answers

It is impossible for an element to appear on only one side of a valid chemical equation because chemical equations must follow the law of conservation of mass. According to this law, the total mass of the reactants must be equal to the total mass of the products in a chemical reaction.

Chemical equations represent the transformation of reactant molecules into product molecules, where atoms are rearranged but not created or destroyed. Each atom present in the reactants must also be accounted for in the products. Therefore, if an element appears on one side of the equation, it must also appear on the other side to maintain the balance of atoms. The balanced equation ensures that the number of atoms of each element is the same on both sides, symbolizing the conservation of mass. Any discrepancy in the number or type of atoms would violate the fundamental principle of mass conservation, making the equation invalid.

By following the law of conservation of mass, chemical equations provide a consistent and accurate representation of chemical reactions and enable the understanding and prediction of chemical processes.

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The process of managing messages and media for the purpose of creating meaning is called: A. Decoding B. Language C. Communication D. Encoding

Answers

The process of managing messages and media for the purpose of creating meaning is called:

D. Encoding

Encoding is the process of converting information or ideas into a form that can be communicated and understood by others. In the context of communication, encoding involves selecting and organizing symbols, such as words, images, or gestures, to create a message that effectively conveys meaning.

When encoding a message, the sender or encoder chooses the appropriate symbols and arranges them in a way that is coherent and meaningful to the intended audience. This process requires consideration of factors such as language, cultural context, and the knowledge and preferences of the recipients.

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One point charge has a magnitude of 5.4 x 10-7 C. A second charge that is 0.25 m away has a magnitude of 1.1 x 10-17 C. What is the electric force magnitude of one charge on the other?

Answers

The magnitude of the electric force between the two charges is 8.99 x 10^9 N, Where one point charge has a magnitude of 5.4 x 10-7 C and  second charge that is 0.25 m away has a magnitude of 1.1 x 10-17 C.

The electric force between two point charges can be calculated using Coulomb's Law, which states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. In this case, the magnitude of the electric force can be calculated as:
Electric force = (k * |q1| * |q2|) / r^2
Where k is the electrostatic constant (8.99 x 10^9 N m^2/C^2), |q1| and |q2| are the magnitudes of the charges (5.4 x 10^-7 C and 1.1 x 10^-17 C, respectively), and r is the distance between the charges (0.25 m).
Plugging in the values, we can calculate the magnitude of the electric force as 8.99 x 10^9 N.

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Find the missing side in each triangle using any method. Check your answers using a different method. Show your work or explain your thinking.

Answers

To find the missing side in each triangle, we need more information or measurements. Without specific values for the angles or sides of the triangles, we cannot determine the missing side lengths.

To find the missing side in a triangle, we typically use trigonometric ratios such as sine, cosine, or tangent. However, in this case, the problem statement does not provide any angles or side lengths for the triangles. Without these measurements, it is impossible to determine the missing side lengths. We need specific values to apply trigonometric ratios or other geometric properties to solve the problem accurately.  Without specific values for the angles or sides of the triangles, we cannot determine the missing side lengths.

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Write a topic about one of the cosmic natural phenomena, explaining the reasons for the occurrence of this phenomenon

Answers

Topic: The Formation of Black Holes: Unveiling the Cosmic Gravity Abyss

Explanation: Black holes, enigmatic cosmic entities, are formed through the gravitational collapse of massive stars. When a star exhausts its nuclear fuel, it undergoes a cataclysmic explosion known as a supernova. During the supernova event, the star's core collapses under its immense gravitational force, leading to the formation of a black hole.

The collapse occurs when the core's mass exceeds a critical threshold, resulting in an intense gravitational pull. This gravitational force becomes so strong that it overcomes all other forces, including those that typically support the structure of matter. As a result, the core collapses to a point of infinite density called a singularity, surrounded by an event horizon from which nothing can escape, not even light.

The formation of black holes exemplifies the extreme nature of gravity and the profound effects it can have on the fabric of the universe. Understanding the processes behind black hole formation enhances our knowledge of stellar evolution, gravity's influence on massive objects, and the fundamental laws governing the cosmos.

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A 200 kg cannon fires a 50 kg cannon ball. If the recoil velocity of the cannon is - 40 m/s and the velocity of the cannon ball is + 40 m/s. What was the initial velocity in which the cannon fired the cannon ball?

Answers

The initial velocity with which the cannon fired the cannonball is 200 m/s.

To solve this problem, we can apply the principle of conservation of momentum. According to this principle, the total momentum before the cannon fires is equal to the total momentum after the cannon fires. The momentum (p) of an object is given by the product of its mass (m) and velocity (v):

p = m * v

Before the cannon fires, the total momentum is zero since the cannon and cannonball are at rest:

p_initial = 0

After the cannon fires, the total momentum is the sum of the momenta of the cannon and cannonball:

p_final = (m_cannon * v_cannon) + (m_cannonball * v_cannonball)

Given that the mass of the cannon (m_cannon) is 200 kg, the mass of the cannonball (m_cannonball) is 50 kg, the recoil velocity of the cannon (v_cannon) is -40 m/s, and the velocity of the cannonball (v_cannonball) is +40 m/s, we can substitute these values into the equation:

0 = (200 kg * v_cannon) + (50 kg * 40 m/s)

Simplifying the equation, we find:

0 = 200 kg * v_cannon + 2000 kg * m/s

-2000 kg * m/s = 200 kg * v_cannon

Dividing both sides by 200 kg, we get:

-10 m/s = v_cannon

Therefore, the initial velocity with which the cannon fired the cannonball is -10 m/s.

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Book rode his bike north towards Fairbanks. He pulled off the road to calculate his average speed. He had traveled for 3 hours and covered 27 miles. What was his average speed

Answers

He pulled off the road to calculate his average speed. He had traveled for 3 hours and covered 27 miles. Book's average speed is 9 miles per hour.

Average speed is a measure of the overall rate at which an object covers a certain distance. It is calculated by dividing the total distance traveled by the total time taken. The average speed is a scalar quantity, meaning it only has magnitude and no direction. It represents the overall "average" rate at which an object moves without considering the specific details of its motion.

Average speed is calculated by dividing the total distance traveled by the total time taken. In this case, Book traveled for 3 hours and covered a distance of 27 miles.

Average Speed = Total Distance / Total Time

Average Speed = 27 miles / 3 hours

Average Speed = 9 miles per hour

Therefore, Book's average speed is 9 miles per hour.

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What direction would the magnetic force point, when the electron enters the magnetic field?

Answers

When the electron enters the magnetic field, the magnetic force would point in a direction perpendicular to both the velocity of the electron and the magnetic field, according to the right-hand rule.

The magnetic force on an electron moving through a magnetic field is determined by the right-hand rule. When the electron enters the magnetic field, the direction of the magnetic force is perpendicular to both the velocity of the electron and the magnetic field.

Using the right-hand rule, if you point your thumb in the direction of the velocity of the electron and your fingers in the direction of the magnetic field, then the direction in which your palm faces represents the direction of the magnetic force on the electron.

Therefore, when the electron enters the magnetic field, the magnetic force would point in a direction perpendicular to both the velocity of the electron and the magnetic field, according to the right-hand rule.

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A 5 kg toy falls from a height of 3.7 m. How fast will the toy be traveling just before it hits the ground?







Velocity =

Answers

The gravitational potential energy of the toy is converted into kinetic energy as it falls.

We will utilize the law of conservation of energy to determine the velocity of the toy just before it strikes the ground, which is mgh = 1/2mv²,

where m is the mass of the toy,

h is the height from which it is falling,

g is the acceleration due to gravity, and

v is the velocity with which it hits the ground.

Using the provided figures, we get, m = 5 kg,

h = 3.7 m, and

g = 9.8 m/s².

Substitute these values in the formula. 5*9.8*3.7 = 1/2(5)v²

On solving, we get v² = 181.3 or

v = √(181.3)

V = 13.5 m/s (approx).Hence, the velocity of the toy just before it hits the ground is 13.5 m/s.

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A 3kg Snickers candy bar is dropped off the top of the Washington Monument. If the Monument is 170m tall, how fast does the Snickers hit the ground? (this is the orignal question)


The Snickers bar actually lands with a speed of 52m/s. How much energy was lost so air resistance?

Answers

To determine the amount of energy lost due to air resistance, we can use the principle of conservation of mechanical energy. Initially, the Snickers bar has gravitational potential energy, and upon hitting the ground, it has kinetic energy.

The gravitational potential energy (PE) of an object is given by the equation:

PE = m * g * h

Where:

m is the mass of the object (3 kg)

g is the acceleration due to gravity (approximately 9.8 m/s^2)

h is the height of the Washington Monument (170 m)

Calculating the potential energy, we have:

PE = 3 kg * 9.8 m/s^2 * 170 m

PE = 4998 J (joules)

At the moment of impact, all the potential energy is converted into kinetic energy, given by:

KE = 1/2 * m * v^2

Where:

m is the mass of the object (3 kg)

v is the velocity at impact (52 m/s)

Calculating the kinetic energy, we have:

KE = 1/2 * 3 kg * (52 m/s)^2

KE = 4056 J (joules)

The energy lost due to air resistance is the difference between the initial potential energy and the final kinetic energy:

Energy Lost = PE - KE

Energy Lost = 4998 J - 4056 J

Energy Lost = 942 J (joules)

Therefore, the amount of energy lost due to air resistance is 942 joules.

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A 58. 0kg sailor jumps from a dock into a 28. 0kg rowboat at rest. If the velocity of the sailor is 2. 20m/s as he leaves the dock, what is the velocity of the sailor and the boat

Answers

A 58.0 kg sailor jumps from a dock into a 28.0 kg rowboat at rest. If the velocity of the sailor is 2.20 m/s as he leaves the dock, the velocity of the sailor and the boat is 1.485 m/s.

We can use the principle of conservation of momentum. According to this principle, the total momentum before the jump is equal to the total momentum after the jump.

Before the jump, we have:

Initial momentum of the sailor = mass of the sailor × velocity of the sailor

[tex]P_s=m_s*v_s[/tex]

After the jump, the sailor and the boat move together, so their momenta add up:

Final momentum of the sailor and the boat = (mass of the sailor + mass of the boat) × velocity of the sailor and the boat

[tex]P_f=(m_s+m_b)*v_f[/tex]

Since momentum is conserved, we have:

[tex]P_s=P_f[/tex]

[tex]m_s*v_s=(m_s+m_b)*v_f[/tex]

Given:

mass of the sailor ([tex]m_s[/tex]) = 58.0 kg

velocity of the sailor ([tex]v_s[/tex]) = 2.20 m/s

mass of the boat ([tex]m_b[/tex]) = 28.0 kg

We can rearrange the equation to solve for [tex]v_f[/tex]:

[tex]v_f=(m_s*v_s)/(m_s+m_b)[/tex]

[tex]v_f=(58.0Kg *2.20m/s)/(58.0Kg+28.0Kg)\\\\v_f=1.485 m/s[/tex]

Therefore, the velocity of the sailor and the boat after the jump is approximately 1.485 m/s.

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there’s 30g/L of salt in salted water, and in unsalted water there’s 1g/L of salt how much water are you going to ADD to make a 20 ml container of salted water unsalted? use C1V1=C2V2

Answers

Answer:

Water ADD to make a 20 ml container of salted water unsalted is 620 mL

Explanation:

To make a 20 mL container of salted water unsalted using the formula C1V1 = C2V2, we can calculate the volume of water (V2) that needs to be added.

V2 = (C1V1) / C2

V2 = (30 g/L * 20 mL) / 1 g/L

V2 = 600 mL

It is important to consider the final total volume of the solution after adding the water, which would be 20 mL (initial volume) + 600 mL (volume of water added) = 620 mL.

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A box is sliding across a wooden floor. Eventually, it comes to a stop. The box stops because the frictional force decreased the amount of kinetic energy in the box. This kinetic energy was transformed into:



(A)Gravitational potential energy


(B)Surface energy


(C)Thermal energy


(D)The energy was not transformed, rather it just decreased.

Answers

The box stops because the frictional force decreased the amount of kinetic energy in the box. This kinetic energy was transformed into thermal energy.

What is Kinetic Energy?

Kinetic energy is the energy of motion. Kinetic energy can be transferred from one object to another to do work when a force acts upon it.

The frictional force is the force that opposes the motion of a body when it is in contact with another body. The frictional force is caused by the microscopic roughness of the two surfaces in contact. When a box slides across a wooden floor, the frictional force acts in the opposite direction of the box's motion, causing it to slow down and eventually stop.

What does the frictional force do?

The frictional force converts the kinetic energy of the moving box into heat energy, causing the box to slow down and eventually stop. Therefore, when the box stops, the kinetic energy is transformed into thermal energy.

Hence, the correct option is C) Thermal energy.

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In areas with large numbers of phytoplankton, there are also large numbers of fish, marine mammals, and other animals. For example, the west coast of the U. S. Has many fisheries due to the large numbers of phytoplankton in those waters. What provides the energy to support so many animals in these areas?

Answers

The energy to support a large number of animals in areas with abundant phytoplankton comes from the primary production of phytoplankton through photosynthesis, forming the basis of the marine food web.

The large numbers of animals in areas with abundant phytoplankton are supported by the energy derived from the process of photosynthesis. Phytoplankton are microscopic algae that contain chlorophyll and other pigments, allowing them to convert sunlight, carbon dioxide, and nutrients into organic matter through photosynthesis. This primary production by phytoplankton forms the foundation of the food web in marine ecosystems.As phytoplankton grow and reproduce, they become a rich source of energy and nutrients for other organisms. Zooplankton, which are small marine animals, feed on phytoplankton, and in turn, become food for larger organisms such as fish and marine mammals. This transfer of energy and nutrients continues up the food chain, supporting the entire ecosystem. The high productivity of phytoplankton in certain areas, such as the west coast of the U.S., can be attributed to various factors. These factors include nutrient availability, sunlight exposure, and oceanographic conditions that promote upwelling, bringing nutrient-rich deep waters to the surface. The combination of these factors creates favorable conditions for phytoplankton growth, resulting in an abundance of energy to support diverse and thriving marine ecosystems.

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Does it matter if the triple beam of light hits the triangle at different angles?

Answers

Yes, the angle at which the triple beam of light hits the triangle can have an impact on the behaviour of the light.

In the case of a triangle, if the light hits the triangle at different angles, it will be reflected or refracted differently depending on the angle of incidence at each point of contact. This can result in variations in the path of the light as it interacts with different parts of the triangle.

Additionally, the angle at which the light hits the triangle can affect the perception of the triangle's shape and size when observed from different viewing angles. The angle of incidence and the resulting angle of reflection or refraction can impact the apparent position and orientation of the triangle as seen by an observer.

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how are kinetic and potential energy related to car safety

Answers

Kinetic and potential energy are two forms of energy that are relevant to car safety. Understanding their relationship helps us grasp the principles behind safe driving and the design of safety features in vehicles.

Kinetic energy is the energy possessed by a moving object due to its motion. In the context of car safety, the kinetic energy of a moving vehicle is directly related to its speed and mass. When a car is in motion, it carries a significant amount of kinetic energy. The higher the speed and the greater the mass of the car, the more kinetic energy it possesses. This energy becomes crucial in assessing the potential for damage and injury in the event of a collision. A faster-moving car with more kinetic energy will cause more damage upon impact compared to a slower-moving car.

Potential energy, on the other hand, is the stored energy possessed by an object due to its position or configuration. In the context of car safety, potential energy is closely related to gravitational potential energy. When a car is elevated, such as on a hill or incline, it possesses gravitational potential energy. This energy becomes relevant when considering the possibility of a car rolling or losing control on a slope.

Car safety measures take into account the relationship between kinetic and potential energy to mitigate risks. For example, when designing road systems, engineers consider the placement of guardrails, road barriers, and traffic signs to reduce the potential for collisions and control the release of kinetic energy during accidents. The purpose of these measures is to limit the transfer of kinetic energy to occupants of the vehicle and decrease the severity of injuries.

Additionally, safety features within cars themselves are designed to protect occupants by absorbing and dissipating kinetic energy. Crumple zones, seat belts, airbags, and other safety mechanisms work together to extend the time of impact during a collision, which reduces the force applied to occupants and minimizes the risk of injury.

By understanding the relationship between kinetic and potential energy, car manufacturers, engineers, and drivers can make informed decisions to enhance car safety. It underscores the importance of responsible driving, maintaining appropriate speeds, following traffic regulations, and ensuring that vehicles are equipped with the necessary safety features.

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What is the area of sector BAC? Write your answer in terms of use pi in your answer. Example: 3pi

Answers

The area of sector BAC is equal to 9π in².

How to calculate the area of a sector?

In Mathematics and Geometry, the area of a sector can be calculated by using the following formula:

Area of sector = θπr²/360

Where:

r represents the radius of a circle.θ represents the central angle.

By substituting the given parameters into the area of a sector formula, we have the following;

Area of sector = θπr²/360

Area of sector = 40(π/360) × 9²

Area of sector = (π/9) × 81

Area of sector = 9π in²

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

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