Given that 1/5 of 100 oranges is given to Olu and 1/4 of the remaining oranges is given to Ade. We have to find what fraction of the oranges are left.
We have 100 oranges.1/5 of 100 oranges is given to Olu= 1/5 × 100= 20 orangesLet's find out how many oranges are remaining after giving 1/5 of 100 oranges to Olu.Therefore, the number of oranges left is = 100 - 20 = 80Now, 1/4 of the remaining oranges is given to Ade= 1/4 × 80= 20 oranges
Now, we have given a total of 20+20= 40 oranges.Hence, the fraction of oranges left is: 60/100 or 3/5.Here, the final answer is "The fraction of oranges left is 3/5.
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A poll of 1,000 randomly selected registered voters was taken and 584 responded that they favor candidate X for governor (p 1 = 0.5840). Just before the election, another poll of 950 registered voters was taken and 401 individuals responded that they favor candidate X (p 2 = 0.4221). A 95% two-proportion z confidence interval for the true difference between p 1 and p 2 was found to be (0.1181, 0.2057). What is the meaning of the interval in the context of the problem?
The 95% two-proportion z confidence interval (0.1181, 0.2057) in the given problem indicates that there is a 95% probability that the true difference in proportions between the two polls falls within the range of 0.1181 to 0.2057.
This means that the proportion of registered voters who favor candidate X in the first poll is estimated to be between 11.81% and 20.57% higher than the proportion in the second poll.
The confidence interval is a statistical tool that provides a range of values within which the true difference between the proportions is likely to lie. The interval is constructed based on the sample data and takes into account the variability in the estimates. In this case, it suggests that there is evidence to support the claim that candidate X was more favored by registered voters in the first poll compared to the second poll.
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Mr fisher remembered that he had one more exam to grade. The extra student scored 25 points higher than the student who was absent for 6 days. This extra student was absent for 5 fewer days than the student who scored 55. Which shows the location of the new point Mr. Fisher must plot?
The correct answer is B (31,50), which shows the location of the new point Mr. Fisher must plot.
To determine the location of the new point Mr. Fisher must plot, let's analyze the given information:
The extra student scored 25 points higher than the student who was absent for 6 days.
This extra student was absent for 5 fewer days than the student who scored 55.
Let's assign variables to the relevant values:
Let "A" represent the number of days the absent student was absent for.
Let "S" represent the score of the student who scored 55.
From the given information, we can determine the following relationships:
The extra student's score = S + 25.
The extra student's number of absent days = A - 5.
Now, let's analyze the answer choices:
A (3,80): This point does not match the given information, as it does not fulfill the conditions related to the absent days and scores.
C (80,3): This point does not match the given information, as it does not fulfill the conditions related to the absent days and scores.
B (31,50): This point satisfies the given conditions: the extra student was absent for 5 fewer days than the student who scored 55, and the extra student's score is 25 points higher.
D (90,3): This point does not match the given information, as it does not fulfill the conditions related to the absent days and scores.
The correct option is b.
The complete question is:
Mr. Fisher remembered that he had one more exam to grade. The extra student scored 25 points, higher than the student who was absent for 6 days. This extra student was absent for 5 fewer days than the student who scored 55. Which shows the location of the new point Mr. Fisher must plot?
A (3,80)
C (80,3)
B (31,50)
D (90,3)
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A sporting goods store is deciding which type of baseball glove they should carry for the upcoming season. Which group should the story survey to achieve the most valid results?A. Every tenth person who enters the grocery store beside the sporting goods store.B. Every parent whose child played middle school sports last year.C. The players of last year's middle school and high school baseball and softball teams.D. Every person who buys a pair of running shoes at the sporting goods store.
Answer:
Step-by-step explanation:
ms.watson wants to join planet fitness. she paid a flat fee of $110 and $10 monthly. how much does ms.watson have to pay for her membership for the year
Ms. Watson paid a flat fee of $110 for the first year and $10 monthly for the membership. As we know, Ms. Watson has to pay for 12 months of membership. The total cost of membership for the year is $230. We can calculate the cost of membership for the year as follows:
Yearly cost = Flat fee + Monthly fee for 12 months
Yearly cost = $110 + ($10 x 12)
Yearly cost = $110 + $120
Yearly cost = $230
Therefore, Ms. Watson has to pay $230 for her membership for the year. Ms. Watson is planning to join Planet Fitness for the first time. She has to pay a flat fee for the first year and a monthly fee for the membership. The flat fee is $110, and the monthly fee is $10. Ms. Watson needs to know the total membership cost for the year. We can calculate the total cost of the membership by using simple arithmetic.
The membership for the first year is a flat fee of $110. This fee is payable only once for the first year. After that, Ms. Watson needs to pay a monthly fee of $10. The membership is valid for 12 months. Therefore, we need to calculate the total cost of 12 months of membership for Ms. Watson.
We can do this by multiplying the monthly fee of $10 by 12 months. Ms. Watson must pay a flat fee of $110 for the first year and a monthly fee of $10. She needs to pay this fee for 12 months of membership. Therefore, the total cost of membership for the year is $230.
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Bob’s Burgers has started a franchise and needs to mass produce theirburgers. Through analysis they determine that the production function forburgers is(, ) = 60^0. 75^0. 25Where P is the number of burgers produced each day with x units of laborand y units of capital. (10 points)a. Find the number of units produced with 300 units of labor and 200 unitsof capitalb. Find the marginal productivitiesc. Evaluate the marginal productivities with x = 300 and y = 200d. Interpret* the meanings of the marginal productivities found in part ce. If they can afford at most 500 units of capital and labor together thenthere is a constraint x + y = 500. Use this constraint and LaGrangemultipliers to find the number of units of labor and capital that willmaximize production and find the maximum production. F. Find λ and interpret* its meaning in the context of the problem
a. To find the number of units produced with 300 units of labor (x) and 200 units of capital (y), we substitute these values into the production function:
P = (60^0.75)(200^0.25) = 60^0.75 * 200^0.25 ≈ 31.62 * 5 ≈ 158.10
Therefore, approximately 158 burgers would be produced with 300 units of labor and 200 units of capital.
b. The marginal productivity of labor (MPL) is the partial derivative of the production function with respect to labor (x), while the marginal productivity of capital (MPK) is the partial derivative with respect to capital (y). Taking the partial derivatives, we have:
MPL = 0.75 * 60^0.75 * 200^0.25 / 60 ≈ 0.75 * 31.62 ≈ 23.72
MPK = 0.25 * 60^0.75 * 200^0.25 / 200 ≈ 0.25 * 31.62 ≈ 7.90
c. Evaluating the marginal productivities with x = 300 and y = 200:
MPL = 0.75 * 60^0.75 * 200^0.25 / 60 ≈ 0.75 * 31.62 ≈ 23.72
MPK = 0.25 * 60^0.75 * 200^0.25 / 200 ≈ 0.25 * 31.62 ≈ 7.90
d. The marginal productivity of labor (MPL) represents the additional output gained by increasing the amount of labor while keeping capital constant. In this case, for every additional unit of labor, approximately 23.72 burgers will be produced.
The marginal productivity of capital (MPK) represents the additional output gained by increasing the amount of capital while keeping labor constant. For every additional unit of capital, approximately 7.90 burgers will be produced.
e. If the constraint x + y = 500 is applied, we can use the Lagrange multiplier method to find the maximum production. By maximizing the production function subject to this constraint, we can determine the optimal combination of labor and capital that yields the maximum production.
f. The Lagrange multiplier (λ) represents the rate of change of the production function subject to the constraint x + y = 500. Its value indicates how the maximum production is affected by changes in the constraint. The interpretation of λ in this context is that it quantifies the trade-off between labor and capital to achieve the highest production level while satisfying the given constraint of limited labor and capital resources.
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The cost in dollars to produce x shovels in a factory is given by the function f(x)=23x+590.The number of shovels that can be produced in h hours is given by the function N(h)=40h
The cost of producing x shovels in a factory is given by the function f(x) = 23x + 590. The number of shovels that can be produced in h hours is given by the function N(h) = 40h.
The function f(x) = 23x + 590 represents the cost in dollars to produce x shovels in the factory. The coefficient 23 represents the cost per shovel, and the constant term 590 represents additional fixed costs.
On the other hand, the function N(h) = 40h represents the number of shovels that can be produced in h hours. The coefficient 40 indicates the production rate, which means 40 shovels can be produced per hour.
These two functions represent different aspects of the production process. While f(x) calculates the cost of producing a given number of shovels, N(h) determines the maximum number of shovels that can be produced in a specific time frame.
It's important to note that the given information provides separate functions for cost and production rate and does not directly relate the two.
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carbon-11 has half-life of 20 minutes. If a 50 gram sample of carbon -11 begins to decay, write a model for the amount, A, that is still radioactive after m-minutes. Then, use your model to determine how much of the original sample is still radioactive after a half- hour. Round to the nearest tenth of a gram
Rounded to the nearest tenth of a gram, the amount of the original sample that is still radioactive after half an hour is approximately 17.7 grams.
To model the decay of carbon-11 over time, we can use the exponential decay formula A = A₀ * (1/2)^(t/h), where A is the amount remaining, A₀ is the initial amount, t is the time elapsed, and h is the half-life. In this case, the initial amount is 50 grams and the half-life is 20 minutes. Using this model, we can determine the amount of carbon-11 remaining after a half-hour (30 minutes). Using the exponential decay model A = A₀ * (1/2)^(t/h), we can calculate the amount of carbon-11 remaining after a certain time. For a half-life of 20 minutes, the equation becomes A = 50 * (1/2)^(t/20). To find the amount remaining after half an hour (30 minutes), we substitute t = 30 into the equation:
A = 50 * (1/2)^(30/20)
A = 50 * (1/2)^(3/2)
A = 50 * (√1/2)^3
A = 50 * (√1/8)
A = 50 * (1/2√2)
A = 25/√2
To determine the decimal value of the amount remaining, we can approximate √2 as 1.414. Therefore:
A ≈ 25/1.414 ≈ 17.68 grams
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A compound shape has a triangle and a rectangle and its total area is 52square cm. If the area of the triangle is 20square cm, then find the longest side of the rectangle.
The height of the rectangle is 16 cm. Finally, substituting the height into the equation b = 32 / h, we find b = 32 / 16 = 2 cm. Hence, the longest side of the rectangle in the compound shape is 2 cm.
The longest side of the rectangle in the compound shape can be found by subtracting the area of the triangle from the total area of the shape, and then dividing it by the base of the rectangle. The resulting value will give the length of the longest side of the rectangle.
Let's denote the base of the rectangle as 'b' and the height as 'h'. The area of a triangle is given by the formula (1/2) * base * height. In this case, we are given that the area of the triangle is 20 square cm, so we have (1/2) * b * h = 20.
The total area of the compound shape is given as 52 square cm, which consists of the triangle and the rectangle. Therefore, the area of the rectangle can be obtained by subtracting the area of the triangle from the total area: 52 - 20 = 32 square cm.
Now, we can find the length of the longest side of the rectangle by dividing the area of the rectangle by its base. Since the area of the rectangle is equal to the product of its base and height (32 = b * h), we can rearrange the equation to solve for the base: b = 32 / h.
Substituting this value of b into the equation (1/2) * b * h = 20, we get (1/2) * (32 / h) * h = 20. Simplifying the equation further, we have 16 = h. Therefore, the height of the rectangle is 16 cm.
Finally, substituting the height into the equation b = 32 / h, we find b = 32 / 16 = 2 cm. Hence, the longest side of the rectangle in the compound shape is 2 cm.
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Two congruent squares overlap, as shown, so that vertex A of one square lies at the intersection of the diagonals of the other square. The side of each square has length 12 inches. Find the number of square inches enclosed by the shaded region.
Thus, the number of square inches enclosed by the shaded region is 72√6 square inches.
Given, two congruent squares overlap, as shown, so that vertex A of one square lies at the intersection of the diagonals of the other square.
The side of each square has length 12 inches.
To find: The number of square inches enclosed by the shaded region.
Solution: It is given that, two squares are congruent and side of each square is 12 inches.
Let's find the shaded area.
By Pythagorean theorem, in ΔABO, we have:
OB² = AO² + AB²
We know that, side of square is 12 inches.
So, AO = BO = 6√2 inches
AB = 12 inches
Therefore,
OB² = (6√2)² + 12²
OB² = 72 + 144
OB² = 216
OB = 6√6 inches
Area of ΔABO = 1/2 × base × height= 1/2 × AB × OB= 1/2 × 12 × 6√6= 36√6 sq. inches
Area of shaded region = 2 × Area of ΔABO= 2 × 36√6= 72√6 sq. inches
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Triangle 1 has an angle that measures 62° and an angle that measures 14°. Triangle 2 has an angle that measures 14° and an angle that measures x°, where x ≠ 62º. Based on the information, Bob claims that triangle 1 and triangle 2 cannot be similar.
Bob claims that Triangle 1 and Triangle 2 cannot be similar based on the information given. To determine whether Bob's claim is valid, we need to understand the conditions for similarity between triangles.
For two triangles to be similar, their corresponding angles must be congruent. However, the information provided does not specify the measure of the third angle in Triangle 1 or the second angle in Triangle 2. Without this additional information, we cannot definitively conclude whether Triangle 1 and Triangle 2 are similar or not.
Let's consider the possibilities:
If the third angle in Triangle 1 is 104° (180° - 62° - 14°), then Triangle 1 and Triangle 2 would have corresponding angles measuring 62° and 14°. In this case, Triangle 1 and Triangle 2 would indeed be similar.
If the third angle in Triangle 1 is any other value, then the corresponding angles between Triangle 1 and Triangle 2 would not match. Consequently, Triangle 1 and Triangle 2 would not be similar.
In conclusion, without the knowledge of the third angle in Triangle 1 or the second angle in Triangle 2, we cannot definitively determine whether the triangles are similar or not based solely on the given information. Therefore, Bob's claim cannot be determined as either true or false.
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E
Learning Task 1
A. Make each pair of radicals similar by reducing the radicand.
To make each pair of radicals similar by reducing the radicand, we need to simplify the radicands to their lowest terms. Simplifying radicals involves finding the largest perfect square factor of the number under the radical sign and rewriting it. Let's take an example:
Pair 1: √50 and √32
To make these radicals similar, we simplify the radicands:
√50 = √(25 × 2) = 5√2
√32 = √(16 × 2) = 4√2
Now, both radicals have the same simplified radicand, which is √2. The pair becomes 5√2 and 4√2, making them similar.
Similarly, you can apply the same process to any other pairs of radicals, simplifying the radicands to their lowest terms and making the pairs similar by having matching simplified radicands.
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It's the end of the budgeting period for a person and he has $450 left in his budget for car rental expenses. He plans to spend this budget on a sales trip throughout a city. He will rent a car that costs $45 per day and 0.25 per mile and he can spend no more than $450
The person can rent the car for 5 days and drive a maximum of 1800 miles within the $450 budget.
To determine the number of days the person can rent the car, we divide the remaining budget of $450 by the daily rental cost of $45. This gives us 10, indicating that the person can rent the car for up to 10 days. However, the goal is to spend the entire budget, so renting the car for the maximum number of days would exceed the budget.
Next, we need to calculate the maximum distance the person can drive within the budget. Since the cost is $0.25 per mile, we divide the remaining budget by $0.25 to find the maximum number of miles. This results in 1800 miles.
Therefore, the person can rent the car for 5 days and drive a maximum of 1800 miles within the $450 budget. By renting the car for 5 days and driving within this mileage limit, the person will spend the entire budget without exceeding it.
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Cara deposited x dollars in a bank paying 8. 5% interest and y dollars at a second bank paying 10. 75% interest. If the x amount was $4,000 less than twice the y amount, and the total interest income for one year was $1,880, how much money did she invest at each rate?
Cara invested $6,000 at 8.5% interest and $3,000 at 10.75% interest.
Let's solve the problem step by step.
Let's assume that Cara invested x dollars at 8.5% interest and y dollars at 10.75% interest. According to the given information, the total interest income for one year was $1,880.
We know that interest is calculated as the product of the principal amount, the interest rate, and the time period. Using this formula, we can write the equation:
0.085x + 0.1075y = 1,880 (equation 1)
The second given information states that x is $4,000 less than twice the y amount. Mathematically, we can express this as:
x = 2y - 4,000 (equation 2)
Now we have a system of two equations (equation 1 and equation 2) with two variables (x and y). We can solve this system of equations to find the values of x and y.
By substituting equation 2 into equation 1, we get:
0.085(2y - 4,000) + 0.1075y = 1,880
Simplifying the equation, we have:
0.17y - 340 + 0.1075y = 1,880
Combining like terms, we get:
0.2775y = 2,220
Dividing both sides by 0.2775, we find that y ≈ 8,000.
Substituting this value back into equation 2, we can solve for x:
x = 2(8,000) - 4,000
Simplifying, we get x ≈ 12,000.
Therefore, Cara invested $6,000 at 8.5% interest (x = $12,000 - $4,000) and $3,000 at 10.75% interest (y = $8,000).
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Describe how to determine whether the parabola y=−2x2 + 2x +1 is opening downward. A.Open downward because the leading coefficient is an integer. B.Open downward because the constant term is not a fraction. C.Open downward because the leading coefficient is a negative real number. D.Open downward because the middle term is a positive .
The correct answer is C. The parabola y = -2x^2 + 2x + 1 opens downward because the leading coefficient (-2) is a negative real number.
To determine the direction in which a parabola opens, we look at the leading coefficient of the quadratic term (the coefficient of x^2).
If the leading coefficient is positive, the parabola opens upward.
If the leading coefficient is negative, the parabola opens downward.
In this case, the leading coefficient is -2, which is a negative real number. Therefore, the parabola y = -2x^2 + 2x + 1 opens downward.
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Which statement about the relationship between a function and its inverse is NOT true?
A. The graph of the inverse of a function is the reflection across the line y = x of the graph of the function.
B. The domain of a function is the range of the inverse of the function.
C. The range of a function is the domain of the inverse of the function.
D. The inverse of a function is always a function.
The statement that is NOT true about the relationship between a function and its inverse is option B: "The domain of a function is the range of the inverse of the function."
In general, the domain of a function consists of all possible input values, while the range represents the set of all possible output values. When finding the inverse of a function, the roles of the domain and range are interchanged. Therefore, the range of the original function becomes the domain of its inverse, and vice versa.
The other options are true:
A. The graph of the inverse of a function is indeed the reflection across the line y = x of the graph of the function. This means that if you plot the function and its inverse on a coordinate plane, they will be symmetric with respect to the line y = x.
C. The range of a function does correspond to the domain of its inverse. The outputs of the original function become the inputs of its inverse.
D. The inverse of a function is not always a function. For a function to have an inverse, it must be one-to-one, meaning that each input value maps to a unique output value and vice versa. If a function fails to satisfy this criterion, it does not have an inverse. Here, option B is the statement that is not true. Therefore, Option B is correct.
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Apply a dilation to AC with a scale factor of 2 and center at the point 0.
To apply a dilation to AC with a scale factor of 2 and a center at the point 0, we first need to understand what a dilation is. A dilation is a transformation that stretches or shrinks an object without changing its shape.
It is defined by a scale factor, which determines how much the object is scaled, and a center of dilation, which is the fixed point about which the object is enlarged or reduced. In this case, AC is a line segment, and the scale factor is 2 with the center at the point 0. To perform the dilation, we multiply the length of AC by the scale factor of 2. The center at 0 means that AC is being stretched or shrunk relative to the origin The result of the dilation would be a new line segment, let's call it A'C', where the length of A'C' is twice the length of AC, and the orientation and direction of the line segment remain the same. The points A' and C' would be located at positions that are twice the distance from the origin compared to the original points A and C, respectively.
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A researcher measures the amount of food consumed by each dog in her lab. She finds that the mean amount eaten by the 10 dogs is 14 oz. The sum of squared deviations is 220. What is the standard deviation for this data set
The standard deviation for the amount of food consumed by the dogs in the lab is approximately 4.69 oz, indicating the spread or dispersion of the data set.
To calculate the standard deviation, we need to follow these steps:
1. Calculate the variance: The variance is the average of the squared deviations from the mean. It is calculated by dividing the sum of squared deviations by the number of observations. In this case, the sum of squared deviations is 220, and the number of observations is 10. So, the variance is 220/10 = 22.
2. Take the square root of the variance: The standard deviation is the square root of the variance. Using the calculated variance of 22, we find that the standard deviation is the square root of 22, which is approximately 4.69 oz.
Therefore, the standard deviation for the amount of food consumed by the dogs in the lab is approximately 4.69 oz. The standard deviation measures the spread or dispersion of the data set, indicating how much the individual observations deviate from the mean value.
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If AE= X+2 and BD = 4x-16, then the length of Line AC is?
Explain briefly which properties of rectangles helped you arrive at your solution.
The property of rectangles where opposite sides are equal in length to determine the length of Line AC. By equating AE and BD and solving for X, we found that X = 6. Substituting this value back into AE, we found that Line AC has a length of 8 units.
To determine the length of Line AC, we need to consider the properties of rectangles.
In a rectangle, opposite sides are equal in length. Since AE and BD are opposite sides of the rectangle, they must be equal.
Given that AE = X + 2 and BD = 4X - 16, we can set up an equation:
AE = BD
X + 2 = 4X - 16
To solve for X, we can simplify the equation:
2 + 16 = 4X - X
18 = 3X
Dividing both sides by 3:
X = 6
Now that we have the value of X, we can substitute it back into the expression for AE to find its length:
AE = X + 2
AE = 6 + 2
AE = 8
Therefore, the length of Line AC, which is equal to AE, is 8 units.
In summary, we utilized the property of rectangles where opposite sides are equal in length to determine the length of Line AC. By equating AE and BD and solving for X, we found that X = 6. Substituting this value back into AE, we found that Line AC has a length of 8 units.
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It costs £3.20 to ride to Vominator for 23 minutes. To the nearest penny, how much will it costs for 47 minutes?
The cost of riding to Vominator for 47 minutes, to the nearest penny, is £6.56.
It costs £6.56 to ride to Vominator for 47 minutes.
Given, the cost of riding to Vominator for 23 minutes is £3.20.
Hence, the cost of riding for 1 minute is;`1 min = £3.20/23 = £0.13913...`
To the nearest penny, the cost of riding for 1 minute is £0.14.
To find the cost of riding to Vominator for 47 minutes, we multiply the cost of riding for one minute by 47.`
Cost for 47 minutes = 47 × £0.14 = £6.58`
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Adler and Erika solved the same equation using the calculations below.Adler’s WorkErika’s WorkStartFraction 13 over 8 EndFraction = k + one-half. StartFraction 13 over 8 EndFraction minus one-half = k + one-half minus one-half. StartFraction 9 over 8 EndFraction = k.StartFraction 13 over 8 EndFraction = k + one-half. StartFraction 13 over 8 EndFraction + (negative one-half) = k + one-half + (negative one-half). StartFraction 9 over 8 EndFraction = k.Which statement is true about their work?Neither student solved for k correctly because K = 2 and StartFraction 1 over 8 EndFraction.Only Adler solved for k correctly because the inverse of addition is subtraction.Only Erika solved for k correctly because the opposite of One-half is Negative one-half.Both Adler and Erika solved for k correctly because either the addition property of equality or the subtraction property of equality can be used to solve for k.
Neither student solved the equation for k correctly because k = 2 and 1/8.
Both Adler and Erika made errors in their calculations. Adler incorrectly equated 13/8 with k + 1/2, and then subtracted 1/2 from both sides, resulting in 9/8 = k. This is incorrect because k should be equal to 2 and 1/8, not 9/8. On the other hand, Erika correctly set up the equation as 13/8 = k + 1/2, but she made an error when subtracting 1/2 from both sides. Instead of obtaining 9/8 as she claimed, it should be 12/8 or simply 3/2. Therefore, neither student solved for k correctly, and the correct answer is that k is equal to 2 and 1/8, which was not obtained by either of them.
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Two trains, Train A and Train B, weigh a total of 274 tons. Train A is heavier than Train B. The difference of their weights is 204 tons. What is the weight of each train?
Two trains, Train A and Train B weigh a total of 274 tons. It is known that Train A is heavier than Train B and the difference between their weights is 204 tons.
We are to determine the weight of each train .To solve the problem, we can use the following system of equations :Let the weight of Train A be "x" tons Let the weight of Train B be "y" tons x + y = 274 [Equation 1]x - y = 204 [Equation 2]To solve for the weight of each train, we will add Equations 1 and 2 as follows:(x + y) + (x - y) = 274 + 2042x = 478Divide both sides by 2:2x/2 = 478/2x = 239 tons This means that Train A weighs 239 tons. Substitute this value of "x" into Equation 1:x + y = 274239 + y = 274y = 274 - 239y = 35 , Train B weighs 35 tons. In summary, Train A weighs 239 tons while Train B weighs 35 tons.
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Question
A dilation with a scale factor of 1/5 and centered at the origin is applied to MN with endpoints M(−2, −4) and N(1, 5).
Drag and drop to match the correct coordinates with the point.
The coordinates after applying a dilation with a scale factor of 1/5 and centered at the origin to the line segment MN with endpoints M(-2, -4) and N(1, 5) are as follows:
M: (-2, -4) → (-2/5, -4/5)
N: (1, 5) → (1/5, 1)
So, the matching coordinates for the points are:
M (-2, -4) → (-2/5, -4/5)
N (1, 5) → (1/5, 1)
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Write 6.373 x 10 to the fifth power in standard notation
The number 6.373 x 10^5 can be written in standard notation as 637,300. This can be explained by understanding the concept of scientific notation and converting it back to its standard form.
Scientific notation is a way to represent very large or very small numbers using powers of 10. In scientific notation, a number is expressed as a coefficient multiplied by 10 raised to a certain power.
In the given number, 6.373 x 10^5, the coefficient is 6.373, and the exponent is 5. This means that we take the coefficient and multiply it by 10 raised to the power of 5.
To convert it back to standard notation, we perform the following calculation:
6.373 x 10^5 = 6.373 * 10 * 10 * 10 * 10 * 10
Simplifying the calculation, we get:
6.373 * 10 * 10 * 10 * 10 * 10 = 6.373 * 100,000
Multiplying 6.373 by 100,000, we obtain:
6.373 * 100,000 = 637,300
Therefore, the number 6.373 x 10^5 can be expressed in standard notation as 637,300, which is the final result.
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What is the range of the data below? A box-and-whisker plot. The number line goes from 100 to 125. The whiskers range from 102 to 115, and the box ranges from 109 to 114. A line divides the box at 111. 2 5 12 13.
Based on the information provided by the box-and-whisker plot, the range of the given data (2, 5, 12, 13) is 5.
To determine the range of the data from the given box-and-whisker plot, we need to consider the highest and lowest values represented in the plot.
The whiskers in the plot extend from 102 to 115. This means that the lowest value in the data is 102, and the highest value is 115.
The box in the plot ranges from 109 to 114. The lower boundary of the box represents the 25th percentile (Q1), which is the median of the lower half of the data. In this case, Q1 is 109. The upper boundary of the box represents the 75th percentile (Q3), which is the median of the upper half of the data. In this case, Q3 is 114.
The line dividing the box at 111 represents the median (Q2), which is the middle value when the data is sorted in ascending order. So, Q2 is 111.
Now, let's analyze the given data values: 2, 5, 12, and 13.
Based on the box-and-whisker plot, we can see that the data range from the lowest whisker (102) to the highest whisker (115). However, the given data values fall within the range of the box, which is from 109 to 114.
Therefore, the range of the given data is from the lowest value within the box (109) to the highest value within the box (114). The range can be calculated as:
Range = Highest value - Lowest value
Range = 114 - 109
Range = 5
So, the range of the given data is 5.
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Find the value of c so that the polynomial p(x) is divisible (x-4)
To find the value of c such that the polynomial p(x) is divisible by (x - 4), we can use the remainder theorem. According to the theorem, if p(x) is divisible by (x - a), then p(a) = 0. Therefore, we need to find the value of c such that p(4) = 0.
Let's assume the polynomial p(x) is given by p(x) = ax^2 + bx + c.
To find the value of c, we substitute x = 4 into the polynomial and set it equal to 0:
p(4) = a(4)^2 + b(4) + c = 0
16a + 4b + c = 0
Since we want the polynomial to be divisible by (x - 4), we need p(4) to be equal to 0.
Therefore, we can set up the equation:
16a + 4b + c = 0
Solving this equation will give us the value of c.
Answer: The value of c can be found by solving the equation 16a + 4b + c = 0.
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Michael was at the library and then drove 8 miles east to the coffee shop. He knows that the distance from the library to his house is 17 miles. How far is it from the coffee shop to his house?
To determine the distance from the coffee shop to Michael's house, we need to subtract the distance he traveled from the library to the coffee shop (8 miles) from the total distance between his house and the library (17 miles).
Using the information provided, we can calculate the distance from the coffee shop to his house as follows:
Distance from coffee shop to house = Total distance - Distance from library to coffee shop
Distance from coffee shop to house = 17 miles - 8 miles
Distance from coffee shop to house = 9 miles
Therefore, the distance from the coffee shop to Michael's house is 9 miles. This calculation is derived by subtracting the distance he traveled from the library to the coffee shop from the total distance between his house and the library.
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One number is 5 more than another number. Three times the first plus twice the second in 30. What is the number?
Let's represent the two numbers as variables. Let the first number be x and the second number be y.
According to the given information, one number is 5 more than the other, so we can write the equation x = y + 5.
The second piece of information states that three times the first number plus twice the second number equals 30, which can be expressed as the equation 3x + 2y = 30.
To find the values of x and y, we can solve this system of equations simultaneously. By substituting the value of x from the first equation into the second equation, we have 3(y + 5) + 2y = 30.
Simplifying the equation, we get 3y + 15 + 2y = 30, which can be further simplified to 5y + 15 = 30.
By subtracting 15 from both sides of the equation, we have 5y = 15, and dividing both sides by 5, we get y = 3.
Substituting this value of y back into the first equation x = y + 5, we find x = 3 + 5, which gives x = 8.
Therefore, the two numbers are 8 and 3.
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If the pressure exerted on a sample of gas is increased from 0. 428 atm to 0. 72338 atm what is the final volume of the gas in ml if the inital volume was 240 ml?
The final volume of the gas, when the pressure is increased from 0.428 atm to 0.72338 atm with an initial volume of 240 ml, is approximately 142.55 ml.
The final volume of the gas in milliliters, when the pressure is increased from 0.428 atm to 0.72338 atm with an initial volume of 240 ml, is unknown ml.
To solve this problem, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature. The equation for Boyle's Law is:
P1 * V1 = P2 * V2
where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.
Given that P1 = 0.428 atm, V1 = 240 ml, and P2 = 0.72338 atm, we can plug these values into the equation and solve for V2:
(0.428 atm) * (240 ml) = (0.72338 atm) * V2
103.2 atm * ml = 0.72338 atm * V2
V2 = (103.2 atm * ml) / 0.72338 atm
V2 ≈ 142.55 ml
Therefore, the final volume of the gas, when the pressure is increased from 0.428 atm to 0.72338 atm with an initial volume of 240 ml, is approximately 142.55 ml.
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Rolando is making buttons that are shaped like circles. Each button has an area of
36 square centimeters. Which measurement shows the circumference of each of the buttons in centimeters?
Rolando is making buttons that are shaped like circles. Each button has an area of 36 square centimeters. This article explains the measurement that shows the circumference of each of the buttons in centimeters.
The area of a circle is given by the formula: A = πr²where A is the area and r is the radius of the circle.The problem statement says that each button has an area of 36 square centimeters. So,36 = πr²Or,r² = 36/πSolving for r, we get:r = √(36/π)Thus, the radius of each button is given by:r = 3 √π square centimeters Circumference is given by the formula:C = 2πr.
So, substituting the value of r we get:C = 2π * 3 √π= 6 π √π cm Therefore, the measurement that shows the circumference of each of the buttons in centimeters is 6 π √π cm which is approximately equal to 10.85 cm.
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13 f
In the same circle or in congruent circles:
Congruent arcs determine ... chords,
Congruent arcs determine
choices -
Equidistant
chords.
Central
Congruent
Distinct
Equidistant
Infinitely many
IF U DONT KNOW THE ANSWER DONT ANSWER
Congruent arcs determine equidistant chords in the same circle or in congruent circles.
This means that if two arcs in a circle are congruent, then any chords associated with those arcs will also be equidistant from the center of the circle. In other words, the distance from the center of the circle to any point on the chord will be the same for both chords.
So, the correct choice is "Equidistant".Let's break down the concept of congruent arcs and equidistant chords in more detail.
In a circle, an arc is a curved section of the circumference. When two arcs in the same circle or in congruent circles are congruent, it means they have the same measure or length. In other words, they span the same angle or distance along the circumference.
Now, when we talk about chords, we are referring to line segments that connect two points on the circle. A chord is formed by selecting any two points on the circle and joining them with a straight line.
When we say that congruent arcs determine equidistant chords, it means that if two arcs in a circle are congruent, then any chords associated with those arcs will have the same distance from the center of the circle.
In simpler terms, imagine you have two congruent arcs in a circle. Now, draw a chord for each of those arcs. The key point is that the distance from the center of the circle to any point on one chord will be equal to the distance from the center to any point on the other chord.
This property holds true because congruent arcs subtend the same angle at the center of the circle. Since the distances from the center to the chords are equal, the chords themselves are said to be equidistant.
To summarize, when two arcs in a circle are congruent, the chords associated with those arcs will be equidistant from the center of the circle. This is a fundamental property of circles and is true for any pair of congruent arcs in the same circle or in congruent circles.
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