If 128x is a perfect square number what is the least value of x

Please answer the question fast​

Step-by-step explanation:

Double t

t+t=2t

Subtract v

2t-v

Subtract u

2t-v-u

9514 1404 393

Answer:

  D

Step-by-step explanation:

Any equation that does not have y2 as the first term in the second set of parentheses will be incorrect.

The correct usage is shown in equation D.

Answer:

D = all reals (or -7 to 7)

Step-by-step explanation:

If the line continues on for infinity, then the domain is all reals, or negative infinity to positive infinity. If the line ends on the graph that we can see, though, the domain would be [-7 , 7]

Answer:

7/4

Step-by-step explanation:

(4/7)^-1

We know a^-b = 1/a^b

1/ (4/7)^1

7/4

Answer:

(4/7)^-1

=1/(4/7)^1

=1÷4/7

=1×7/4

=7/4

Therefore 7/4 is equal to 1.75 as a rational number

Answer:

Ask me

Step-by-step explanation:

Tell me dear ask..

9514 1404 393

Answer:

  (p -9q)/(4p² +12pq)

Step-by-step explanation:

The least common denominator will be the product of the denominators.

  [tex]\dfrac{-3}{4p}+\dfrac{1}{p+3q}=\dfrac{-3(p+3q)+1(4p)}{(4p)(p+3q)}=\boxed{\dfrac{p-9q}{4p^2+12pq}}[/tex]

Answer:

Option A

Step-by-step explanation:

Histogram shows the range of data on the x-axis while the frequency of occurrence is on the y-axis.

We have the following ranges from the Histogram ;

0 to 11

11 to 22

22 to 33

33 to 44

44 to 55

55 to 66

66 to 77

77 to 88

88 to 99

99 to 110

From the given set of data, the frequency according to the range is as follows;

0 to 11; 4

11 to 22; 8

22 to 33; 7

33 to 44; 6

44 to 55; 4

55 to 66; 2

66 to 77; 2

77 to 88; 1

88 to 99; 0

99 to 110; 1

The only Histogram that corresponds to these frequency is option A

Given:

so, total cost fir 200 masks=

200×5

= 1000

therefore, Joe paid Rs. 1000 altogether.

Answer:

[tex]{ \tt{ = \frac{50}{1 \times 60} }}[/tex]

Step-by-step explanation:

50 miles=50 miles

1 hour=60 minutes

50÷60

0.8333333333333333mile per minute

~1.0 mile per minute

Answer: the first part is 1.25. The second part is y=1.25x

Step-by-step explanation: edge 2021

Answer:

The answer is below

Step-by-step explanation:

The bar chart to the question is attached below.

The distance traveled by Paolo = 210 m, The distance traveled by Lucas = 150 m, The distance traveled by Jashua = 175 m, The distance traveled by Topher = 190 m

1) The farther distance walk by Paolo = The distance traveled by Paolo - The distance traveled by Topher = 210 m - 190 m = 20 m

2) The farther distance walk by Jasha = The distance traveled by Jashua - The distance traveled by Lucas = 175 m - 150 m = 25 m

3) The farther distance walk by Topher = The distance traveled by Topher - The distance traveled by Lucas = 190 m - 150 m = 40 m

4) Combined distance of Paolo's and Lucas = 210 m + 150 m = 360 m

Combined distance of Jashua and Topher = 175 m + 190 m = 365 m

Therefore the Combined distance of Jashua and Topher is more

5) Average distance = (210 + 150 + 175 + 190)/4 = 181.25 m

Answer:

- Bar Gaps should be the same

Y-axis up in units of 5 would help out

Step-by-step explanation:

Answer:

y=1

Step-by-step explanation:

Answer:

SEESH thanks for the points

Step-by-step explanation:

Answer:

{B} travelling costs paid in connection with a temporary work assignment

Answer:

Step-by-step explanation:

Total no. of goods, n = 200

no. of defective units in the goods, d = 20

hence the no. of proper units,

g = n-d

g = = 200-20

g = 180

a)

ways in which a vending company buys fifteen of these microwaves and receive no defective units be:

[tex]^{180}C_{15}=\frac{180!}{15!\times (180-15)!}[/tex]

[tex]\approx 2.83\times 10^{21}[/tex]

b)

ways in which a vending company buys fifteen of these microwaves and receive exactly two defective units be:

[tex]^{20}C_2\times ^{180}C_{13}=\frac{20!}{2!\times (20-2)!} \times \frac{180!}{13!\times (180-13)!}[/tex]

[tex]\approx 190\times (2.146\times 10^{19})[/tex]

[tex]\approx 4.076\times 10^{21}[/tex]

c)

ways in which a vending company buys fifteen of these microwaves and receive at least one defective units be:

[tex]^{20}C_{1}\times ^{199}C_{14}=\frac{20!}{1!\times (20-1)!} \times \frac{199!}{13!\times (199-13)!}[/tex]

[tex]\approx 20\times (8.258\times 10^{19})[/tex]

[tex]\approx 1.652\times 10^{21}[/tex]

Answer:

The average rate of change of the cost of a pack is 22 cents per year.

Another name for the average rate of change is slope.

Step-by-step explanation:

The average rate of change of the cost of a pack ([tex]r[/tex]), in monetary units per year, is equal to the change in the average cost of a pack ([tex]\Delta c[/tex]), in monetary units, divided by the change in time ([tex]\Delta t[/tex]), in years. Then, the average rate of change is:

[tex]r = \frac{\$\,5.31-\$\,0.88}{2000-1980}[/tex]

[tex]r = \$\,0.22\,\frac{1}{yr}[/tex]

The average rate of change of the cost of a pack is 22 cents per year.

Another name for the average rate of change is slope.

Answer:

radius of 80cm is the answer

Answer:

DGF = 106

Step-by-step explanation:

Bisects means to divide in half, with two equal parts

DGF = DGE + EGF

DGE = EGF

DGF = DGE + DGE

DGF = 53+53

DGF = 106

GE bisects ∠DGF, so it divides ∠DGF into 2 equal parts.

So, m∠EGF = m∠DGE

=> m∠EGF = 53°

m∠DGF = m∠EGF + m∠DGE

=> m∠DGF = 53° + 53°

=> m∠DGF = 106°

Step-by-step explanation:

solved in the diagram above

I hope it helps you

Answer:

g(x) = x^3 - 2

Step-by-step explanation:

As you can see on the graph, the line has been translated down 2 units.

If the graph of f has the same shape as the graph of g, then the slope remains the same. The y intercept (k) changes by -2 units, so the k value is -2

g(x) = x^3 - 2

Hope this helps!!

Answer:

answer is in the picture above

Answer:

Step-by-step explanation:

Since EF = 20 and E is at 4

F is at:

Answer:

You can go ahead with this!

Step-by-step explanation:

Option A

Is the write answer

Answer:

0,00567×10¹

Step-by-step explanation:

Para convertir a notación decimal:

0.00567×10¹

Answer:

3b^2 + 2b -8

Step-by-step explanation:

* means multiply

^ means exponent

3b * b = 3b^2

3b * 2 = 6b

-4 * b = -4b

-4 * 2 = -8

3b^2 + 6b -4b -8

3b^2 + 2b -8

Answer:

Step-by-step explanation:

Polynomial f(x) has the following conditions: zeros of -2 (multiplicity 3), 3 (multiplicity 1), and with f(0) = 120.

The first part zeros of -2 means (x+2) and multiplicity 3 means (x+2)^3.

The second part zeros of 3 means (x-3) and multiplicity 1 means (x-3).

The third part f(0) = 120 means substituting x=0 into (x+2)^3*(x-3)*k =120

(0+2)^3*(0-3)*k = 120

-24k = 120

k = -5

Combining all three conditions, f(x)

= -5(x+2)^3*(x-3)

= -5(x^3 + 3*2*x^2 + 3*2*2*x + 2^3)(x-3)

= -5(x^4 + 6x^3 + 12x^2 + 8x - 3x^3 - 18x^2 - 36x - 24)

= -5(x^4 + 3x^3 - 6x^2 - 28x -24)

= -5x^4 - 15x^3 + 30x^2 + 140x + 120

Answer:

0.8996 = 89.96% probability that the sample proportion will be between 0.2 and 0.4

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

The manager of a donut store believes that 35% of the customers are first-time customers.

This means that [tex]p = 0.35[/tex]

Sample of 150 customers

This means that [tex]n = 150[/tex]

Mean and standard deviation:

[tex]\mu = p = 0.35[/tex]

[tex]s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.35*0.65}{150}} = 0.0389[/tex]

What is the probability that the sample proportion will be between 0.2 and 0.4?

p-value of Z when X = 0.4 subtracted by the p-value of Z when X = 0.2.

X = 0.4

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{0.4 - 0.35}{0.0389}[/tex]

[tex]Z = 1.28[/tex]

[tex]Z = 1.28[/tex] has a p-value of 0.8997

X = 0.2

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{0.2 - 0.35}{0.0389}[/tex]

[tex]Z = -3.85[/tex]

[tex]Z = -3.85[/tex] has a p-value of 0.0001

0.8997 - 0.0001 = 0.8996

0.8996 = 89.96% probability that the sample proportion will be between 0.2 and 0.4

2x^2 + 8x - 12 = 0..divide by 2

x^2 + 4x - 6 = 0

x^2 + 4x = 6...add 4 to both sides of the equation

x^2 + 4x + 4 = 6 + 4

(x + 2)^2 = 10....<== ur constant is 10

x + 2 = (+-)sqrt 10

x = -2 (+ - ) sqrt 10

x = -2 + sqrt 10

x = -2 - sqrt 10