I
Graph the direct variation equation. Y=1/3x
Which graph is correct

Based on the information given the number of plates that the baker will need is 61 plates.

Using this formula

Number of plates=Number of cookies arranged/Each plates number of cookies

Where:

Number of cookies arranged=487

Each plates number of cookies=8

Let plug in the formula

Number of plates=487/8

Number of plates=60.9

Number of plates=61 plates (Approximately)

Inconclusion the number of plates that the baker will need is 61 plates.

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Step-by-step explanation:

(10+5)³-1 = 3375-1 = 3374.

Answer:

A

Step-by-step explanation:

5 times 10= 50

5 times -5= -25

50-25=25

Answer:

In point-slope form the equation is:

[tex]y - 2 = \binom{1}{3} \times (x - 1)[/tex]

Answer:

Y=x+8

Step-by-step explanation:

[tex] \frac{1}{2} \: to \: the \: power \: of \: 5 \: is \: \frac{1}{32} or \: 0.03125 [/tex]

Answer:

[tex] \ {\boxed{ \tt ( \frac{1}{2}) ^{5} = \frac{1}{32} }}[/tex]

Step-by-step explanation:

[tex] \\ \tt( \frac{1}{2} )^{5} [/tex]

[tex] \\ \tt= \frac{ {1}^{5} }{ {2}^{5} } [/tex]

[tex] \\ \tt = \frac{1 \times 1 \times 1 \times 1 \times 1}{2 \times 2 \times 2 \times 2 \times 2} [/tex]

[tex] \\ \tt = \frac{1}{32} [/tex]

cyclist a speed is d = v × t

so you can find velocity of a and b.

then compare them both.

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Explanation:

The notation [tex]P(\text{blue, not 2})[/tex] is asking for the probability of landing on a blue space and having the dice show a value that isn't 2. That means we can roll any of the following: {1,3,4,5,6}.

The probability of landing on blue is 1/4 since there's one blue space out of four total. This is assuming all four spaces are equal in area. The probability of landing on anything but "2" is 5/6 because there are five sides that aren't labeled "2" out of six sides total.

Multiply the fractions found: (1/4)*(5/6) = (1*5)/(4*6) = 5/24

Answer:

Mixed Number = 2 9/10

Improper Fraction = 29/10

Step-by-step explanation:

Mixed Number = 29/10 = 2 9/10

Improper Fraction = 29/10

Answer:

The end behavior of a polynomial function is the behavior of the graph of f(x) as x approaches positive infinity or negative infinity

Step-by-step explanation:

hope this help

dont know if this is correct

The end behavior of the polynomial function is as x -> ∞, y -> -∞

From the graph of the polynomial, we have the following highlight:

The above highlights mean that:

As x -> ∞, y -> -∞

Hence, the end behavior of the polynomial function is as x -> ∞, y -> -∞

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Answer:

Hello!

Judging by the link you provided I have come up with the correct solution:

x= 61°

y= 29°

Step-by-step explanation:

I will link my work below:

The first step to finding the two solutions it to first identify one of them.

I chose to identify x first.

To identify the value of x in this problem you have to notice that the x value corresponds with the value "29°" to form a perfect right angle, being 90°.

Thus you can simply find the value of x by doing this formula:

x+29°=90°

You then subtract 29° from both sides to simplify, and you come up with the solution

x=61°

Now we need to find the value of y.

To find the value of y I noticed that again, like x, y corresponds with another variable (being x) to form a perfect right angle (90°).

The way I realized this is a perfect right angle is because, as you can see in the picture you provided, the y+x angle are alternate exterior angles with another angle that is 90°.

Thus you can assume that:

x+y=90°

x= 61°

61°+y=90°

You then subtract 61° from both sides to get:

y=29°

Answer:

7 boys to 10 all children

Step-by-step explanation:

10 1

20 miles car travel 65t hb

Answer:

I believe it's 9 hope this helps

The answer is D, the last one

Answer:

Place the numbers in their places. b=base h=height.

Step-by-step explanation:

11 minutes + 4 minutes more yesterday = 15 total minutes

Answer: 15 minutes

Answer:

Emilia waited 11 minutes wich was 4 minutes earlier so 11+4 because it was 4 miutes earlier so 11 minutes + 4 minutes = 15 minutes so this means Emilia wait 15 minutes for the bus yesterday

Step-by-step explanation:

Answer:

Step-by-step explanation:

would be nice to have a look at the options.

Here's a few I could come up with

44

32 + 12

8(4) + 3(4)

11(4)

Answer:

Are the following two logical statements equivalent?

p

∨

q

q

∨

p

Answer:

9 mm

Step-by-step explanation:

90*0.1=9

Answer:

? = 32

Step-by-step explanation:

Because 8 times 4=32 plus 2 = 34 and therefore t=4 8 times 4 again plus 2 = 34 so 32 plus 2 =34

Plz give brainliest

Answer:

a) 2400m on the 20th day for Charlie.

1) 728.41m of 20th day for Daniella.

Didn't find n, sorry.

Charlie ran 2400m on day 20 of his fitness program and Daniella ran 728m on day 20 of her fitness program.

It is given that Charlie and Daniella on day one both ran 500m on each subsequent day.

Charlie ran 100m more than the previous day.

Daniella increased her distance by 2% of the distance run on the previous day.

It is required to calculate how far Charlie and Daniella ran on day 20 and the value of n.

It is defined as the systematic way of representing the data that follows a certain rule of arithmetic.

Charlie ran 500m on the first day:

[tex]\rm a_1 = 500[/tex]

[tex]\rm a_2 =600[/tex] ( because charlie ran 100m more than the previous day)

It is an arithmetic progression in which the difference between two consecutive terms:

d = 600 - 500 ⇒ 100

and [tex]\rm a_n = a+d(n-1)[/tex]

[tex]\rm a_2_0 = 500+100(20-1)\\\\\rm a_2_0 = 2400m[/tex]( ∵ n = 20 )

Daniella ran 500m on the first day:

[tex]\rm b_1 = 500[/tex]

[tex]\rm b_2 = 500+ 500\times2 \%[/tex]  (because Daniella increased her distance by 2% of the distance run on the previous day)

We can write [tex]\rm n^t^h[/tex] terms:

[tex]\rm b_n= 500(1+2\%)^n^-^1[/tex]

[tex]\rm b_2_0= 500(1+2\%)^2^0^-^1[/tex]

[tex]\rm b_2_0= 500(1+0.02)^1^9\\\\\rm b_2_0 = 500\times 1.02^1^9\\\\\rm b_2_0 = 500\times1.456 \Rightarrow 728.40 \approx 728 m[/tex]

[tex]\rm b_n > a_n[/tex]  (given in the question)

[tex]\rm500(1+2\%)^n^-^1 > 500+100(n-1) \ \ or \\\\\rm500(1+2\%)^n^-^1 > 100n+400[/tex]

The above expression is not true for all the values of 'n' ie. 'n' can not be determined.

Thus, Charlie ran 2400m on day 20 of his fitness program and Daniella ran 728m on day 20 of her fitness programme.

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Answer:

it would be c because its moved 2x up

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

B. Y= (x - 10) ^ 4 - 81 OR y = x^4 - 20x +91

Answer:

3m

Step-by-step explanation:

A heptagon has 7 sides so 21÷7=3m

Answer:

3m

Step-by-step explanation:

3m X 7 is 21m

make me brainlist.

The area of the rectangular field is 0.07 square kilometers (km²).To find the area of the rectangular field in square kilometers, we need to convert the given dimensions from meters to kilometers.

To find the area of the rectangular field in square kilometers, we need to convert the given dimensions from meters to kilometers and then calculate the area.

Given:

Length of the field = 350 meters

Width of the field = 200 meters

To convert from meters to kilometers, we divide the measurements by 1000, since there are 1000 meters in a kilometer.

Length in kilometers = 350 meters / 1000 = 0.35 kilometers

Width in kilometers = 200 meters / 1000 = 0.2 kilometers

Now that we have the dimensions of the field in kilometers, we can calculate the area.

Area of the field = Length in kilometers * Width in kilometers

Area of the field = 0.35 kilometers * 0.2 kilometers

Multiplying the values, we get:

Area of the field = 0.07 square kilometers

Therefore, the area of the rectangular field is 0.07 square kilometers.

It's important to include the correct unit in the answer, which is "square kilometers" (km²). This represents the unit for measuring the two-dimensional area. In this case, the area of the field is 0.07 km².

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[tex](\stackrel{x_1}{-4}~,~\stackrel{y_1}{6})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{5}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{5}-\stackrel{y1}{6}}}{\underset{run} {\underset{x_2}{-2}-\underset{x_1}{(-4)}}}\implies \cfrac{-1}{-2+4}\implies \cfrac{-1}{2}\implies -\cfrac{1}{2}[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{6}=\stackrel{m}{-\cfrac{1}{2}}[x-\stackrel{x_1}{(-4)}] \\\\\\ y-6=-\cfrac{1}{2}(x+4)\implies y-6=-\cfrac{1}{2}x-2\implies \underset{\textit{slope-intercept form}}{y=-\cfrac{1}{2}x+4}[/tex]