i need it! urgent! pls someone help!

Answer:

The 3rd one, 10.5+(-7.5)+12

Step-by-step explanation:

If something is +(-), the answer is minus.

So therefore 10.5-7.5+12 would be our answer

Which is equivalent to the original expression

Hope this helps!

Answer:

y=(5/6)x-6

Step-by-step explanation:

The slope intercept form of a line is y=mx+c. The equation of the line will be y=(5/6)x-6

This problem can be a bit confusing, so let's break it down:

First, let's take the area of the square (A = b · h):

A = 15 · 15

A = 225 cm²

Now comes the confusing part:

We can tell that the non-shaded area is 1/4 of a circle, so, if we take 1/4 of the area of a circle, we can subtract its area from the area of the square:

A = πr²

A = 15²π

A = 225π

1/4 A = 225π / 4

New Area = 56.25π

Or... about 176.7

Since we have both of the areas, all we have to do is subtract:

225 - 176.7 =

48.3.

Your final answer is 48.3 cm²

Answer:

37.7

Step-by-step explanation:

First, we have to divde 22/7 to find the scale factor. I chose 22 and 7 because those two sides are ocngruent. We get 3.14. We then have to multiply 12 by 3.14 beacuse that is the side that is congruent with the side y. When you multiply you should get 37.68. Since we have to round we get 37.7.

Answer:

20 books

Step-by-step explanation:

35/1.75

20

hopefully this answer can help you to answer the next question.

[tex]\\ \sf\longmapsto x+14+x=32[/tex]

[tex]\\ \sf\longmapsto 2x+14=32[/tex]

[tex]\\ \sf\longmapsto 2x=32-14[/tex]

[tex]\\ \sf\longmapsto 2x=18[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{18}{2}[/tex]

[tex]\\ \sf\longmapsto x=9[/tex]

Answer:

Step-by-step explanation:

The supplement of the exterior angle is 180 - 75 = 105

In a cyclic quadrilateral (a four sides figure where all the vertices touch the circumference of a circle), the opposite angles are supplementary. Therefore <a = 180 - 105 = 75

But I think you already knew that.

Answer:

we have to add (-b) to get (a)

Step-by-step explanation:

a+b+(-b)=a

a+b-b=a

a=a

Hence verified.

Hope this helps you. Have a nice day^_^

Answer:6

Step-by-step explanation: The rules of exponential says (a^x)^y=a^xy.

Therefore you will multiply 1/4 with 4 to get an exponent of 1. So the answer is 6^1 which is also written as 6

Answer:

Step-by-step explanation:

i don't understand this language but i think you want to simplify  it.

[tex]\frac{3x-3\sqrt{x} -3}{x+\sqrt{x} -2} -\frac{\sqrt{x} +1}{\sqrt{x} +2} +\frac{\sqrt{x} -2}{1-\sqrt{x} } \\=\frac{3x-3\sqrt{x} -3}{x+2\sqrt{x} -\sqrt{x} -2} -\frac{\sqrt{x} +1}{\sqrt{x} +2} -\frac{\sqrt{x} -2}{\sqrt{x} -1} \\=\frac{3x-3\sqrt{x} -3}{\sqrt{x} (\sqrt{x} +2)-1(\sqrt{x} +2)} -\frac{(\sqrt{x} +1)(\sqrt{x} -1)+(\sqrt{x} +2)(\sqrt{x} -2)}{(\sqrt{x} +2)(\sqrt{x} -1)} \\=\frac{3x-3\sqrt{x} -3}{(\sqrt{x} +2)(\sqrt{x} -1)} -\frac{(x-1)+(x-2)}{(\sqrt{x} +2)(\sqrt{x} -1)} \\[/tex]

[tex]=\frac{3x-3\sqrt{x} -3-2x+3}{(\sqrt{x} +2)(\sqrt{x} -1)} \\=\frac{x-3\sqrt{x} }{(\sqrt{x} +2)(\sqrt{x} -1)}[/tex]

Answer:

x = 59/10, z = 237/70, and y = -121/70

Step-by-step explanation:

[tex]\bf \large \rightarrow \: \:2x \: \: ( \: 4 {x}^{2} \: - \: 3xy \: + \: {y}^{2} \: )[/tex]

[tex]\bf \large \rightarrow \: \: 8 {x}^{3} \: - \: 6 {x}^{2}y \: + \: 2x {y}^{2} [/tex]

Option ( B) is the correct answer

Answer:

-3

Step-by-step explanation:

-8 - x =-5

Answer and Step-by-step explanation:

1.

Since we known how much money Jane and Mark have in total, we can subtract the amount Jane has to find the amount Mark has.

750 - 175 = $575

Mark has $575.

2.

We know how many cards Jamal sold, so if we add it to the amount he still has left, we can find the original amount of cards Jamal had.

17 + 83 = 100

Jamal had 100 cards.

#teamtrees #PAW (Plant And Water)

Answer:

Mark will have $575.

Step-by-step explanation:

Take the total amount ($750) and subtract Jane's contribution ($175) to get Mark's contribution($575).

$750-$175=$575

1.4

2.3

3.7

solution 1

2+2+=4

solution 2

3

Answer:

100/360

Step-by-step explanation:

A circle is 360 degrees

100/360

10/36

5/18

Answer: the answer to this is 3x-2

Step-by-step explanation:

Answer: Number of sociology books sold = 143 books

              Number of physics books sold = 143 + 45 = 188 books

Step-by-step explanation:

Let us take the number of sociology books sold = x

Number of physics books sold = x+45

So now we can form an equation

x+x+45 = 331

2x+45 = 331

2x = 331-45

2x = 286

x = 286 ÷ 2

x = 143

Answer: 90 points

Step-by-step explanation:

Team A's score = 72 points

Team B's score = 125% of A's

= 90 points

please click thanks and mark brainliest if you like :)

Answer:

320 minutes (5 hours and 20 minutes).

Step-by-step explanation:

2 hours and 17 minutes = 137 minutes

137 + 84 + 99 = 320

Therefore, they will spend 320 minutes (5 hours and 20 minutes) watching movies.

Answer:

c) 12/15 = 4/5

Step-by-step explanation:

imagine we mirror the triangle up, so that Z is on top.

then you can clearly see that 6 is cos(X) times r (and r is then 7.5).

XY is sin(X)×7.5

and again, 7.5 is r (the line making the X angle).

so, the cosine ratio of X is

6 = cos(X)×7.5

cos(X) = 6/7.5 or then 12/15. or simplified 4/5.

Answer:

j+2

Step-by-step explanation:

combine like terms

3k - 3k = 0

8j - 7j = 1j or j

6 - 4 = 2

put it all together

j + 2

Answer:

j + 2

Step-by-step explanation:

= 8j - 3k + 6 - 7j + 3k - 4

= 8j - 7j - 3k + 3k + 6 - 4

=j + 2

Answer from Gauth math

Answer:

Step-by-step explanation:

¾*90=67.5

180-67.5=112.5°

Answer:

60°

Step-by-step explanation:

You can see the explanation in the picture

Answer:

26

Step-by-step explanation:

Given: Lines J and H are parallel lines. O intersects both lines equally.

Since two angles equal 180, that will be what  (4y + 12) and 64 will be equal to.

(4y + 12) + 64 = 180

76 + 4y = 180

-76          -76

-------------------

    4y = 104

      y = 26

x and y is both 26 because they are vertical angles.

Hope this helped.

Let's do

[tex]\\ \sf\longmapsto 2sin^260cos60tan^245[/tex]

[tex]\\ \sf\longmapsto 2\left(\dfrac{\sqrt{3}}{2}\right)^2\times \dfrac{1}{2}\times (1)^2[/tex]

[tex]\\ \sf\longmapsto 2\times \dfrac{(\sqrt{3})^2}{2^2}\times \dfrac{1}{2}\times 1[/tex]

[tex]\\ \sf\longmapsto \dfrac{3}{2}\times \dfrac{1}{4}[/tex]

[tex]\\ \sf\longmapsto \dfrac{3}{4}[/tex]

Trigonometric values

[tex]\Large{ \begin{tabular}{|c|c|c|c|c|c|} \cline{1-6} \theta & \sf 0^{\circ} & \sf 30^{\circ} & \sf 45^{\circ} & \sf 60^{\circ} & \sf 90^{\circ} \\ \cline{1-6} $ \sin $ & 0 & $\dfrac{1}{2 }$ & $\dfrac{1}{ \sqrt{2} }$ & $\dfrac{ \sqrt{3}}{2}$ & 1 \\ \cline{1-6} $ \cos $ & 1 & $ \dfrac{ \sqrt{ 3 }}{2} } $ & $ \dfrac{1}{ \sqrt{2} } $ & $ \dfrac{ 1 }{ 2 } $ & 0 \\ \cline{1-6} $ \tan $ & 0 & $ \dfrac{1}{ \sqrt{3} } $ & 1 & $ \sqrt{3} $ & $ \infty $ \\ \cline{1-6} \cot & $ \infty $ &$ \sqrt{3} $ & 1 & $ \dfrac{1}{ \sqrt{3} } $ &0 \\ \cline{1 - 6} \sec & 1 & $ \dfrac{2}{ \sqrt{3}} $ & $ \sqrt{2} $ & 2 & $ \infty $ \\ \cline{1-6} \csc & $ \infty $ & 2 & $ \sqrt{2 } $ & $ \dfrac{ 2 }{ \sqrt{ 3 } } $ & 1 \\ \cline{1 - 6}\end{tabular}}[/tex]