I need help pls and thank you

220 cubic units.

Answer:

Solution given:

for small cylinder

r=1

and for large cylinder

R=5+1=6

height for both [h]=2

Now

Volume of solid=πR²h-πr²h=πh(R²-r²)

=3.14*2(6²-1²)=219.8 =220 units ³.

Small cylinder is r=1

Large cylinder is R= 5+1 =6

Height (h) =2

Volume of solid,

→ πR²h-πr²h

→ πh(R²-r²)

→ 3.14 × 2(6²-1²)

→ 219.8

→ 220 cubic units

I hope it will help you.

Answer:

x = 9

Step-by-step explanation:

angle <1 and angle <2 is complementary and their sum is 90 degrees

3x + 5x + 18 = 90 add like terms

8x + 18 = 90 subtract 18 from both sides

8x = 72 divide both sides by 8

x = 9 to find the measure of angle <1 replace x with the value we found

Step-by-step explanation:

Are you using a particular calculator for the class? For this class, is the payment expected to be compounded monthly?

There is a function in Microsoft Excel that will calculate the payment for you, but the answer is going to be slightly different for a business math class than a calculus-based statistics class.

The excel formula to calculate a payment is

=PMT(0.04/12,60,25000,0)

.04/12 is the interest APR on a monthly basis

60 is the number of months

25000 is the current amount owed

0 is the future balance after 60 payments

The answer from Excel is $460.41 -- ignore the negative sign for these purposes.

Multiply that number by the 60 months you pay and you get a total paid of $27,624.78

Remove the initial 25K and $2,624.78 is your interest amount.

By the way, I used the simplifying assumptions that the problem meant "interest rate" when it said "APR", and that the rate would compound monthly. In the actual loan industry, the interest rate is only part of the calculation for APR, a

146.08

Step-by-step explanation:

Let's start by figuring out the payment

effective rate: .035/12= .002916667

\begin{gathered}2000=x\frac{1-(1+.002916667)^{-48}}{.002916667}\\x=44.71\end{gathered}

2000=x

.002916667

1−(1+.002916667)

−48

x=44.71

then it's just

44.71*48-2000=146.08

Answer:

146.08

Step-by-step explanation:

Let's start by figuring out the payment

effective rate: .035/12= .002916667

[tex]2000=x\frac{1-(1+.002916667)^{-48}}{.002916667}\\x=44.71[/tex]

then it's just

44.71*48-2000=146.08

Answer:

B.10

Step-by-step explanation:

15=1/2b(3)

30=3b

10= base

Answer:

I think B

Step-by-step explanation:

121.346° is more close to 121.3°, than 121.4°

if i'm wrong, the i'm sorry

Answer:

Well, 10% of 6640 is $664, and $332 is half of that, so 5%

Missing: ​$9850 ‎​$591.

Step-by-step explanation:

Answer:

espero ayudarte ..............

Answer:

2

Proof:

x^2 + 6x + 7 + 2 = x^2 + 6x + 9 = x^2 + 6x + 3^2 = (x + 3)^2

The value can you add in the blank in the expression [tex]x^2 + 6x + 7 +\textunderscore\textunderscore[/tex] to complete the square is 2

"It is a polynomial which consists of three terms."

"A square trinomial is a perfect square, if and only if it satisfies the condition b² = 4ac"

For given question,

We have been given a square trinomial.

[tex]x^2 + 6x + 7 +\textunderscore\textunderscore[/tex]

We need to find the number in the blank space, so that the given trinomial would be complete square.

Let 'm' be the required number.

So, the trinomial would be [tex]x^2 + 6x + (7 +m)[/tex]

Comparing above square trinomial with [tex]ax^{2} +bx+c[/tex],

we have a = 1, b = 6, c = 7 + m

We know, a square trinomial is a perfect square, if and only if it satisfies the condition b² = 4ac

⇒ b² = 4ac

⇒ 6² = 4 × 1 × (7 + m)

⇒ 36 = 4 × (7 + m)

⇒ 9 = 7 + m

⇒ m = 2

This means, we need to add 2 in the blank space.

So, the square trinomial would be,

[tex]x^2 + 6x + 7 + \underline {2}\\\\= x^2 + 6x + 9\\\\= (x + 3)^2[/tex]

Therefore, the value can you add in the blank in the expression [tex]x^2 + 6x + 7 +\textunderscore\textunderscore[/tex]  to complete the square is 2

Learn more about perfect square trinomial here:

https://brainly.com/question/16615974

#SPJ2

Answer:

The value of h(g(3)) is 17.

Step-by-step explanation:

We are given these following functions:

[tex]g(x) = x^2 - 5[/tex]

[tex]h(x) = 7x - 11[/tex]

h(g(3)) ?

[tex]h(g(x)) = h(x^2-5) = 7(x^2-5) - 11 = 7x^2 - 35 - 11 = 7x^2 - 46[/tex]

At x = 3

[tex]h(g(3)) = 7(3)^2 - 46 = 63 - 46 = 17[/tex].

The value of h(g(3)) is 17.

Answer:

L(f(t)) = [tex]\frac{5s - 60\sqrt{3} }{s^2 + 144}[/tex]

Step-by-step explanation:

f ( t ) = 10 cos ( 12t + 60°) u(t)

attached below is a detailed solution of the given problem

L(f(t)) = [tex]\frac{5s - 60\sqrt{3} }{s^2 + 144}[/tex]

Answer:

0.872

Step-by-step explanation:

Given that :

P(cloudy) = P(C) = 0.94

P(cloudy and rainy) = P(C n R) = 0.82

Probability that a given day will be rainy if it is cloudy ; this is a conditional probability problem:

Recall ; P(A|B) = P(AnB) / P(B)

P(R|C) = P(C n R) / P(C) = 0.82 / 0.94 = 0.872

Answer:

y = 1.19x

Step-by-step explanation:

y is the dependent variable (total cost)

x is the independent variable (number of pounds)

Answer:

[tex]A_1 = 12[/tex]

[tex]A_n = A_{n-1} + 3[/tex]

Step-by-step explanation:

Given

[tex]A_n =12+(n-1)3[/tex]

Required

Write as recursive

We have:

[tex]A_n =12+(n-1)3[/tex]

Open bracket

[tex]A_n =12+3n-3[/tex]

[tex]A_n =12-3+3n[/tex]

[tex]A_n =9+3n[/tex]

Calculate few terms

[tex]A_1 =9+3*1 = 9 + 3 = 12[/tex]

[tex]A_2 =9+3*2 = 9 + 6 = 15[/tex]

[tex]A_3 =9+3*3 = 9 + 9 = 18[/tex]

The above shows that the rule is to add 3.

So, we have:

[tex]A_1 = 12[/tex]

[tex]A_n = A_{n-1} + 3[/tex]

Answer:

k>1.25

Step-by-step explanation:

The given quadratic equation is :

(k – 1)x² + x + 1 = 0

We need to find all values of k for which the above equation has two real and unequal roots.

For a quadratic equation ax²+bx+c=0, for real and unequal roots,

b²-4ac>0

Here, a = (k-1), b = 1 and c = 1

Put all the values,

1²-4×(k-1)1>0

1-4k+4>0

5-4k>0

k>1.25

S, k can take values more than 1.25. Hence, it can take values 1.5, 1.75.

9514 1404 393

Answer:

Step-by-step explanation:

1. The finance charge is found from the simple interest formula;

  I = Prt

where P is the principal amount, r is the annual rate, and t is the number of years.

24 months is 2 years, so the interest charged is ...

  I = $1900×0.08×2 = $304

The finance charge is $304.

__

2. The monthly payment will be the total amount due, divided by the number of months.

  payment = ($1900 +304)/24 = $2204/24 ≈ $91.83

The monthly payment is $91.83.

Answer:

d

Step-by-step explanation:

Answer:

The grapefruit is 18% heavier than the apple.

Step-by-step explanation:

Orange defines the 100% in this situation.

We know that grapefruit is 8% heavier than an orange, so the weight of a grapefruit   (in percentage)  will be: 100% + 8% = 108%

And an apple is 10% lighter than the orange, then the weight (in percentage) of the apple will be: 100% - 10% = 90%

The difference between the two weights is then:

grapefruit - apple

108% - 90% = 18%

So the grapefruit is 18% heavier than the apple.

Answer:

Step-by-step explanation:

Soooo, by looking at the picture we can tell that it is a right trapezoid

The formula for the area is

(b1+b2)/2*h

(Base 1+ Base 2)/ 2 * height

Now we can plug in the numbers:

(5+15)/2*6

20/2*6

10*6

=60

1 gallon of paint per sq. foot

So Isha needs 60 gallons of paint

Answer:

x = 14

Step-by-step explanation:

Please note, the word trapezium is a synonym for the word trapezoid.

This problem gives one the area of the trapezoid, a well as one of the measurements of a base and the height of the figure. One is asked to find the length of the other base. This can be done by using the formula to find the area of a trapezoid. This formula is the following,

[tex]A=(h)(\frac{b_1+b_2}{2})[/tex]

Where (A) represents the area of a trapezoid, ([tex]b_1[/tex]) and ([tex]b_2[/tex]) represents the bases and (h) represents the height. Substitute in the given values and solve for the unknown base.

[tex]b_1=7\\h=6\\A=84[/tex]

[tex]A=(h)(\frac{b_1+b_2}{2})\\[/tex]

Substitute,

[tex]84=6(\frac{7+b_2}{2})\\[/tex]

Inverse operations,

[tex]84=6(\frac{7+b_2}{2})[/tex]

[tex]14=\frac{7+b_2}{2}[/tex]

[tex]28=7+b_2[/tex]

[tex]14=b_2[/tex]

9514 1404 393

Answer:

  (a)  64/25

Step-by-step explanation:

The relevant properties of exponents are ...

  a^0 = 1 . . . . a ≠ 0

  (a^b)^c = a^(bc)

  (ab)^c = (a^c)(b^c)

__

Your expression simplifies to ...

  [tex]\left(\dfrac{2^3\cdot3^0}{5}\right)^2=\dfrac{2^{3\cdot2}\cdot1^2}{5^2}=\dfrac{2^6}{5^2}=\boxed{\dfrac{64}{25}}[/tex]

9514 1404 393

Answer:

  65°, 35°, 90°, 115°, 80°

Step-by-step explanation:

There are 9 of the longer tick marks in 90°, so each of them represents 10°. The shorter tick marks are halfway between, so are on multiples of 5°. This lets us make a list of the angle value associated with each of the letters.

A: 0 or 180

B: 65 or 115

C: 90

D: 145 or 35

E: 180 or 0

__

Using this list, we can find the measure of each angle by finding the positive difference of the corresponding angle values associated with each of its rays.

arc AOB = 65 -0 = 65°

arc DOE = 35 -0 = 35°

arc AOC = 90 -0 = 90°

arc EOB = 115 -0 = 115°

arc DOB = 145 -65 = 80°

Answer:

24 months

Step-by-step explanation:

Given :

Mean = 48

Standard deviation = 8

Zscore = - 3

Using the relation :

Zscore = (x - mean) / standard deviation

Where, x = score

-3 = (x - 48) / 8

-3 * 8 = x - 48

-24 = x - 48

-24 + 48 = x

24 = x

Score = 24

Answer:

Step-by-step explanation:

Answer:

x= -4

y= -8

This will be the solution

Answer:

[tex]{ \tt{3 \frac{4}{9} \div (5 \frac{1}{3} - 2 \frac{3}{4}) + 5 \frac{9}{10} }} \\ \\ = { \tt{ \frac{31}{9} \div ( \frac{16}{3} - \frac{11}{4} ) + \frac{59}{10} }} \\ \\ = { \tt{ \frac{31}{9} \div ( \frac{31}{12} ) + \frac{59}{10} }} \\ \\ { \tt{ = \frac{4}{3} + \frac{59}{10} }} \\ \\ { \bf{ = \frac{217}{30} }} \\ \\ { \boxed{ \tt{answer : 7 \frac{7}{30} }}} \\ \\ { \underline{ \blue{ \tt{becker ⚜jnr}}}}[/tex]

Answer:

[tex]7 \frac{7}{30}[/tex]

Step-by-step explanation:

[tex]3 \frac{4}{9} \div ( 5\frac{1}{3} - 2 \frac{3}{4}) + 5 \frac{9}{10}\\\\\frac{31}{9} \div (\frac{16}{3} - \frac{11}{4} ) + \frac{59}{10} \\\\\\Solving \ using \ BODMAS\\\\First \ Solve \ expression \ inside \ Bracket \\\\\frac{31}{9} \div (\frac{(16 \times 4) - ( 11 \times 3)}{12}) + \frac{59}{10} \\\\\frac{31}{9} \div (\frac{64- 33)}{12}) + \frac{59}{10} \\\\\frac{31}{9} \div \frac{31}{12} + \frac{59}{10} \\\\\\ \\\\\\Next \ solve \ Dvision \\\\\frac{\frac{31}{9}}{\frac{31}{12}} + \frac{59}{10}\\\\[/tex]

[tex](\frac{31}{9}} \times {\frac{12}{31}) + \frac{59}{10}[/tex]

[tex]\frac{4}{3} + \frac{59}{10}\\\\ Now \ solve \ final \ expression \\\\\\\frac{(4 \times 10) + ( 59 \times 3)}{30}\\\\\frac{40 + 177}{30}\\\\\frac{217}{30}\\\\7 \frac{7}{30}[/tex]