Answer:
First) X-ray
Second) I think sound waves
Explanation:
Based on the figure shown, about how far can sound travel in water in 2.5 s if the water temperature is 25°?
O a. 3,750 m
Oc. 600 m
Ob. 375 m
O d. 875 m
Answer:
A
Explanation:
3,000ml of an unknown liquid has a mass of 3 kg. What is its density?
Answer:
Ro = 1000 [kg/m³]
Explanation:
We must remember that density is defined as the relationship between mass and volume.
[tex]Ro=m/V\\[/tex]
where:
Ro = density [kg/m³]
m = mass = 3 [kg]
V = volume = 3000 [ml]
We must convert the volume of milliliters to cubic meters
[tex]3000[ml]*\frac{0.001Lt}{1ml}*\frac{1m^{3} }{1000Lt} = 0.003m^{3}[/tex]
Now replacing:
[tex]Ro=3/0.003\\Ro=1000[kg/m^{3} ][/tex]
Please help thanks
Most wind erosion is caused by _____.
1. saltation
2. abrasion
3. traction
4. plucking
Romeo traveled by a 900 kg horse from Manitua to Verona accelerating at the rate of 20 km/hr. With what force is Romeo moving at?
Answer:
Force(Romeo moving) = 5,000 N
Explanation:
Given:
Mass of horse = 900 kg
Acceleration = 20 km/hr
Find:
Force(Romeo moving)
Computation:
Acceleration = 20 km/hr
Acceleration in m/s = 20 / 3.6 = 5.555556 m/s²
Force = m x a
Force(Romeo moving) = 900 x 5.555556
Force(Romeo moving) = 5,000 N
A badminton player hits a 0.010 kg shuttlecock that is initially at rest in his hand. The net force on the shuitlecock over time is shown below. What is the shuttlecock's speed at t = 30ms ?
Answer: 10 m/s
Explanation: I got the answer wrong, then it showed it to me
HELP PLS MARKING BRANLIST 100 PTS TAKING TEST RN
How long will your trip take if you travel 890 km at an average speed of 92 km/hr?
81,880 hrs
9.67 s
9.67 hrs
81,880 s
Explain how are position time, velocity, and acceleration related to each
other?
A car has a mass of 1500 kg and accelerates at a rate of 15 m/s^. What was the force applied?
Answer:
22500N
Explanation:
Given parameters:
Mass of the car = 1500kg
Acceleration = 15m/s²
Unknown:
Force applied = ?
Solution:
From Newton's second law of motion:
Force = mass x acceleration
So
Force = 1500 x 15 = 22500N
When power and current are known use R = P/I^2 to calculate the resistance.
P = 300 watts
C = 30amps
R = ?
R = resistance, P = Power, 1 = Current
[tex] \sf• \: Power \:( P) = 300 \: watts[/tex]
[tex] \sf• \: Current \: (I) = 30 \: amps[/tex]
[tex] \\ [/tex]
[tex]\bf{ \underline{To \: Find:- }}[/tex][tex] \sf• \: The \: Resistance [/tex]
[tex] \\ [/tex]
[tex] \huge\bf{ \underline{Solution :-:- }}[/tex]
[tex] \bf \red {\bigstar{ Formula \: of \: Power \: (P) = \frac{ {I}^{2} }{R}}}[/tex]
[tex] \sf \rightarrow 300= \frac{ {30}^{2} }{ R} [/tex]
[tex] \sf \rightarrow 300 = \frac{900}{ R} [/tex]
[tex] \rightarrow \sf R = \frac{300}{900} [/tex]
[tex] \rightarrow \sf R = \frac{1}{3} [/tex]
[tex] \rightarrow \sf R = 0.33[/tex]
[tex] \bf \purple{Hence, \: the \: resistance \: is \: 0.33 \: Ω \: . }[/tex]
Go to your backyard or to your high school’s basketball court or tennis court and try out this experiment to see if you can predict motion and inertia accurately. Bring a friend or classmate. Take along a ball.
Select two spots roughly 10 meters apart. Mark each of them clearly. The first spot will be the starting point and the second will be the target.
Ask a friend to run as fast as possible (sprint) carrying the ball from the starting point to the target. Have your friend release the ball when he or she is immediately over the target trying NOT to swing arms when dropping the ball.
Record the results in the table below.
Repeat the sprint at least five times. Record where the ball lands each time.
Next, ask your friend to jog to the target with the ball and drop it. In the table, again record where the ball lands. Do two trials.
For the final test, ask your friend to walk to the target and drop the ball. Also record these results in the table. Do two trials
Answer:1 Sprint 54 cm Beyond
2 Sprint 41 cm Beyond
3 Sprint 68 cm Beyond
4 Sprint 32 cm Beyond
5 Sprint 44 cm Beyond
6 Jog 31 cm Beyond
7 Jog 22 cm Beyond
8 Walk 17 cm Beyond and left
9 Walk 6 cm Beyond
Explanation:
Answer:
1 Sprint 54 cm Beyond
2 Sprint 41 cm Beyond
3 Sprint 68 cm Beyond
4 Sprint 32 cm Beyond
5 Sprint 44 cm Beyond
6 Jog 31 cm Beyond
7 Jog 22 cm Beyond
8 Walk 17 cm Beyond and left
9 Walk 6 cm Beyond
Explanation: edmentum sample answer
Wavelength in one full standing wave
Answer: one complete wave in a standing wave pattern consists of two loops. Thus, one loop is equivalent to one-half of a wavelength
Explanation: I hope that helped- Please mark me as brainliest!
Answer:
the standing wave within =1 oscillates at the fundamental frequency and has a wavelength that is twice the length of the string . Higher integer value of n correspond to mode of oscillation called harmonics or overtones . Any standing waves on the string will have n +1 node including the fixed end and n anti-nodes.
I hope that helped.Plzz mark me as brainliest
Wave A is being decreased in temperature, and Wave B is moving from a liquid to a gas medium.
Which statement can be made about both waves?
They will speed up.
They will increase the density of their medium.
They will slow down.
They will decrease the density of their medium.
Answer:b
Explanation:
Answer:
B
Explanation:
edg
what voltage produces a current of 100 amps with a resistance of 50 ohms
[tex] \sf• \: Current \: (I) = 100 \: Amps.[/tex]
[tex] \sf• \: Resistance \: (R) = 50 \: ohms[/tex]
[tex] \\ [/tex]
[tex]\bf{ \underline{To \: Find:- }}[/tex][tex] \sf• \: Voltage \: (V)[/tex]
[tex] \\ [/tex]
[tex] \huge\bf{ \underline{Solution:- }}[/tex]
[tex] \bf \red{ \bigstar{ \: The \: formula \: of \: Voltage \: (V) = IR}}[/tex]
[tex] \rightarrow \sf V = 100 \times 50[/tex]
[tex] \rightarrow \sf V = 5000[/tex]
[tex] \\ [/tex]
[tex] \bf \purple{Therefore, \: Volatage \: is \: 5000 \: v.}[/tex]
Which of the following is not necessary for the creation of fossil fuels?
A. Organic matter
B Heat
C Pressure
D. Wind
A highway speed limit is posted as 90 km/hr. Is this average speed or instantaneous speed? Explain your answer.
help please fast + i dont want an answer from g**gle .
A 2 cm object is 10 cm from a convex lens that has a focal length of 4.4 cm. The image is 8 cm from the lens.
The height of the image, to the tenths place, is
cm.
Answer:
-1.6
Explanation:
e2021
The Height of an Image for a Convex Mirror is calculated by using magnification equation
m = h(i) / h(o) = − d(i) / d(o) ,where
the magnification index of the mirror, m
the height of the object, h(o)
the height of the image, h(i)
the distance between the object and the mirror, d(o)
the distance between the image and the mirror, d(i)
h(i)/ 2 = -8 / 10
h(i) = -1.6 cm.
What is convex mirror ?"Convex Mirror is a curved mirror where the reflective surface bulges out towards the light source. This bulging out surface reflect light outwards and are not used to focus light."
What is magnification equation ?"The formula for magnification is m=h(i)/h(o)=-d(i)/d(o). m is the total magnification; h(i) is the height of the image; h(o) is the height of an object; d(i) is the distance from the lens to the in focus projected image; d(o) is the distance of the object to the lens. The negative sign represents that the image is inverted."
Know more about convex mirror here
https://brainly.com/question/3627454
#SPJ2
While driving his sports car at 20.0 m/s through a residential neighborhood, Royston
comes up behind a slow-moving grandma and decides to pass her on the left. If
Royston can accelerate at 6.00 m/s2, how long will it take for him to reach a velocity of
30.0 m/s?
Answer:
1.67s
Explanation:
Given parameters:
Initial velocity = 20m/s
Acceleration = 6m/s²
Final velocity = 30m/s
Unknown:
Time taken = ?
Solution:
Acceleration is the rate of change of velocity with time. It is mathematically expressed as;
Acceleration = [tex]\frac{v - u }{t}[/tex]
v is the final velocity
u is the initial velocity
t is the time taken
6 =[tex]\frac{30 - 20}{t}[/tex]
6 = [tex]\frac{10}{t}[/tex]
10 = 6t
t = 1.67s
A roller coaster, traveling with an initial speed of 23 m/s, decelerates
uniformly at -4 m/s2 to a full stop. How far does the roller coaster travel
during its deceleration?
I NEED STEP BY STEP EXPLANATION
Answer:
5 and 3/4 meters
Explanation:
This is because if it is slowing down by 4 meters and it was moving at 23, then you would figure out how many times 4 can go into 23 and you'd get 5 and 3/4 meters.
What is the cost of operating a 100 W light bulb for "4 hrs per day" for 30 days, if the cost of electricity is 6 cents kW•h
Answer:
the cost of operating the light bulb is 72 cents.
Explanation:
Given;
cost of electricity, C = 6 cents / kW.h
power of light bulb, P = 100 W
time of light power consumption, t = 4 hours per day for 30 days
total time = 4 hours x 30 = 120 hours
Power consumed by the light bulb is calculated as;
P = 100 x 120 = 12000 w.h = 12 kW.h
Cost of power consumption = 6 cents/kWh x 12 kWh
= 72 cents
Therefore, the cost of operating the light bulb is 72 cents.
10)A car is moving from rest and attained a velocity of 80 m/s. Calculate the
acceleration of the car after 5 s?
Explanation:
the velocity graph of a ball mass 20mg moving along a straight line
16m/s^2
Explanation:
initial velocity (u) =0
final velocity (v) =80
acceleration =?
Now,
acceleration = (v-u)/t
=(80-0)/5
= 80/5
= 16m /s^2
A boy is running at -8 m/s and a girl running at -2 m/s. Who is running faster? How do you know?
Answer:
the girl is running faster because -2 is greater than -8
Explanation:
The speed of the wooden bar is changed so that the bar hits the water fewer times each second.
What happens to the frequency of the waves produced?
A. Increases
B. Does not change
C. Decreases
Answer:
c - the frequency of the waves decreases
what force acts between earth and the moon
Explanation:
Gravity
Gravity is one major force that creates tides. In 1687, Sir Isaac Newton explained that ocean tides result from the gravitational attraction of the sun and moon on the oceans of the earth (Sumich, J.L., 1996).
a girl pushes her little brother down a snowy hill on a sled and he rides quickly to the bottom of the hill
which one of Newton's Laws is this
Answer:
Newton's First Law of Motion.
Explanation:
Inertia can be defined as the tendency of an object or a body to continue in its state of motion or remain at rest unless acted upon by an external force.
In physics, Sir Isaac Newton's First Law of Motion is known as law of inertia and it states that, an object or a physical body in motion will continue in its state of motion at continuous velocity (the same speed and direction) or, if at rest, will remain at rest unless acted upon by an external force.
In this scenario, a girl pushes her little brother down a snowy hill on a sled and he rides quickly to the bottom of the hill. The push from the little boy's sister is the external force acting on him and consequently, causing him to be in motion down the snowy hill.
What did the Dakota believe about Bdote?
Answer Bdote means “where two waters come together.” While bdote can refer to any place where waters converge, many Dakota people consider this location as a sacred place of creation, identifying themselves as the Wicahpi Oyate (Star Nation) who originated in the sky and came into being on this land.
I hope it helpful
7. An object with a weight of 19.6 N moves with a constant velocity of 20.0 m/s. A net
force of 6.00 N is applied to the object in the direction of its motion for 4.00 seconds.
What is the final momentum of the object?
Answer:
118.4kgm/s
Explanation:
Given parameters:
Weight of object = 19.6N
mass of object = 19.6/9.8 = 2kg
Constant velocity = 20m/s
Force applied = 6N
Time taken = 4s
Unknown:
Final momentum of the object = ?
Solution:
To solve this problem, we use Newton's second law of motion;
Ft = m (v - u)
F is the force applied
t is the time taken
m is the mass
v is the initial velocity
u is the time taken
Ft = mv - mu
mv is the final momentum;
So;
Final momentum = Ft + mu
Final momentum = (19.6 x 4) + (2 x 20) = 118.4kgm/s
An object of mass m is placed on Spring A, which is compressed by distance x. The spring is released and the velocity of the pushed object as it leaves the spring is measured. The experiment is repeated with the same object on Spring B, which is compressed by the same distance x. The object travels faster when pushed by Spring B. What can be concluded?
A .Spring A had a higher elastic potential energy than Spring B.
B. Spring A's spring constant is higher than Spring B's.
C. Spring A's spring constant is lower than Spring B's.
D. Spring A has more mass than Spring B.
Answer:
C
Explanation:
please help! you are amazing! brainliest too!
NASA helps fund science education.
Which statement about scientific knowledge is false?
A. Understanding science can help people make wiser purchases.
B. People with more knowledge of science are always healthier.
C. People with college degrees in science often earn high salaries.
D. Science education can help people understand the universe.
Answer:
I think its B and I don't know why my words are like this
Explanation:
the gravitational force produced between any two
objects kept at 2.5*10^km apart is 580N. at what distance
should they be kept so that the gravitational force becomes
half?
Answer:
The two objects should be kept at a distance of [tex]3.535\times 10^{4}[/tex] kilometers.
Explanation:
From Newton's Law of Gravitation, gravitational force ([tex]F[/tex]), measured in newtons, between two objects is inversely proportional to the square of distance ([tex]r[/tex]), measured in meters. That is:
[tex]F \propto \frac{1}{r^{2}}[/tex] (1)
[tex]F = \frac{k}{r^{2}}[/tex] (2)
Where [tex]k[/tex] is the proportionality ratio, measured in newtons-square meter.
Now we eliminate the proportionality by constructing the following relationship:
[tex]\frac{F_{2}}{F_{1}} = \left(\frac{r_{1}}{r_{2}}\right)^{2}[/tex] (3)
If we know that [tex]\frac{F_{2}}{F_{1}} = \frac{1}{2}[/tex] and [tex]r_{1} = 2.5\times 10^{7}\,m[/tex], then the distance between the two objects so that gravitational force becomes half is:
[tex]\frac{1}{2} = \frac{(2.5\times 10^{7}\,m)^{2}}{r_{2}^{2}}[/tex]
[tex]r_{2}^{2} = 1.25\times 10^{15}\,m^{2}[/tex]
[tex]r_{2} = 3.535\times 10^{7}\,m[/tex]
[tex]r_{2} = 3.535\times 10^{4}\,km[/tex]
The two objects should be kept at a distance of [tex]3.535\times 10^{4}[/tex] kilometers.
