I need help anyone?

Answer:

Domain: [tex][3,\infty)[/tex]

Range: [tex][6,\infty)[/tex]

Step-by-step explanation:

I assume you mean [tex]y=\sqrt{x-3} +6[/tex]?

Take note of how x cannot be less than 3 because it would result in a negative number under the radical, which isn't real. However, x CAN be 3 because [tex]\sqrt{3-3}+6=\sqrt{0}+6=0+6=6[/tex] which is real.

Therefore, the domain of the function is [tex][3,\infty)[/tex]

As for the range of the function, we saw previously that the minimum of the domain resulted in the minimum of the range, which was 6.

Therefore, the range of the function is [tex][6,\infty)[/tex]

See attached graph below for a visual.

Answer:

2/3

Step-by-step explanation:

to the the slope of the perpendicular line we must first find the slope of line given in the problem. To do this we must transform this equation into the slope intercept format

The slope intercept form of a liner equation is:

Y = mx + b

Where m is slope and b is the y - intercept value.

solving the equation in the problem for y produces :

3x - 3x + 2y = -3x - 5

0 + 2y = 3x - 5

2y = - 3x - 5

2y = -3x - 5

2 2

y = - 3 x - 5

2. 2

Therefore the slope of this line is m = - 3

2

the slope of perpendicular line is the negative inverse of the slope of the line we are given,or

- 1

m

so for our problem the slope of a perpendicular line is - - 2 = 2

3. 3

Answer:

127.53 liters left after 10 minutes

Step-by-step explanation:

Let

[tex]A \to Amount[/tex]

[tex]t \to time[/tex]

Given

[tex]A(0) = 200[/tex] --- initial

[tex]A(5) = 200 * (1 - 20\%) = 160[/tex] --- the amount left, after 5 minutes

Required

[tex]A(10)[/tex] --- amount left after 5 minutes

To do this, we make use of:

[tex]A(t) = A(0) * e^{kt}[/tex]

[tex]A(5) = 160[/tex] implies that:

[tex]160 = 200 * e^{k*5}[/tex]

Divide both sides by 200

[tex]0.80 = e^{k*5}[/tex]

Take natural logarithm of both sides

[tex]\ln(0.80) = \ln(e^{k*5})[/tex]

[tex]\ln(0.80) = \ln(e^{5k})[/tex]

[tex]\ln(0.80) = 5k\ln(e)[/tex]

So, we have:

[tex]-0.223 = 5k[/tex]

Divide by 5

[tex]k = -0.045[/tex]

So, the function is:

[tex]A(t) = A(0) * e^{kt}[/tex]

[tex]A(t) = 200 * e^{-0.045t}[/tex]

The amount after 10 minutes is:

[tex]A(10) = 200 * e^{-0.045*10}[/tex]

[tex]A(10) = 200 * e^{-0.45}[/tex]

[tex]A(10) = 127.53[/tex]

Answer:

F(x) = -1/3 x^2 - 7x + C

Answer:

Circle basic concepts: Chords, arcs, tangents, cyclic quadrilateral, angle subtended by a chord and secant of a circle with examples and exercise. Contents are, Definition of a circle.

Answer:

-(a-b) (3-4x). hope this helps

Answer:

y = -4x + 25

Step-by-step explanation:

[tex](x_1, y_1) = (5, 5) \ ; \ slope ,\ m = -4[/tex]

Equation of line :

 [tex](y - y_1) = m(x - x_1)[/tex]

 [tex](y - 5) = -4(x-5)\\y - 5 = -4x + 20\\y = -4x +20 + 5\\y = -4x + 25[/tex]

Answer:

0=4x+y-5

Step-by-step explanation:

slope(m)=-4

y-intercept(c)=5

now, the equation joining the straight line satisfy the equation,

y=mx+c

or, y= -4x+5

or, 4x+y-5=0

or, 0=4x+y-5

it is the required equation.

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is [tex]\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}[/tex].

Now we will solve this expression with the help of law of exponents.

[tex]\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}[/tex]

           [tex]=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}[/tex]

           [tex]=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}[/tex]

           [tex]=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}[/tex]

           [tex]=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}[/tex]

           [tex]=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}[/tex]

           [tex]=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }[/tex] [Option 2]

[tex]2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2[/tex] [Option 1]

[tex]2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2[/tex]

                [tex]=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }[/tex]

                [tex]=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }[/tex] [Option 3]

[tex]2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }[/tex]

               [tex]=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}[/tex] [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

1.) The answers:

A) BME

B) MER

C) Mm

D) xBy

E) Straight

F) REB

G) MEB and BER

H) xBy

Answer: The answer is C.

Step-by-step explanation:

It is definitely not B because the average of the numbers compared to what that shows don't make sense.

The biggest number that you gave us is 34 but on option A, it looks like its 30 or 31. So that's not correct.

Finally, it can't be D because the biggest number shown there is 35 when it actually is 34.

I hope I was able to help!

Good luck and have a great day :)

Answer:

True

Step-by-step explanation:

Answer:

Your answer is B

Step-by-step explanation:

Answer:

the equation has no solution

Answer:   [tex]\frac{3}{2} e-\frac{3}{4} f-\frac{3}{16}[/tex]

Step-by-step explanation: Everything in the parenthesis has to be multiplied by one fourth so we can do something like this: [tex](\frac{1}{4} )(6e)-(\frac{1}{4} )(3f)-(\frac{1}{4} )((\frac{3}{4} )[/tex]

That's distrubiting the one fourth into all of them

Now we simplify

[tex]\frac{3}{2} e-\frac{3}{4} f-\frac{3}{16}[/tex]

Answer:

z is greater than 27/14

z € ( 37/14 ∞)

Answer:

Challenge B is 1.827

Step-by-step explanation:

I need more letters to submit this.

Answer:

12 and 12.5

Step-by-step explanation:

Answer: d

Step-by-step explanation:

Answer:

The correct answer is A

Step-by-step explanation:

Answer:

The colder it is, the more cups of hot chocolate will be sold.

Step-by-step explanation:

When it was 15 degrees Fahrenheit, 80 cups of hot chocolate were sold. When it was a 90 degree summer day, only 4 cups of hot chocolate were sold.

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Explanation:

Each square has a side length of 5 inches, so each square has area 5*5 = 25 square inches. We have 6 such squares to give a total surface area of 6*25 = 150 square inches.

Effectively, this is the same as using the formula below

S = 6x^2

S = 6*5^2

S = 6*5*5

S = 150

x = 5 refers to the side length and S is the surface area. It might help to cut the figure from the paper, and fold it up and you should find that a 3D box will form. There are 6 faces with area of 5*5 each, hence the 6*5*5

Answer:

d. employed individuals aged 25-29

Step-by-step explanation:

"Population" in a research study is the comprehensive group that the experimenter or the researcher is interested in.

It is given that US Census Bureau, showed that percentage of the employed individual who are of age group 25 years to 29 years are college educated and is at all time high.

The research study focuses on the specific age group of individuals those who graduated form college or at least have a bachelor degree.

Thus the population of the research study those who studied in each of the four years are the employed individuals aged from 25-29.

Answer:

The desired data-set is: {12,12,12,12,12,12,12}

Step-by-step explanation:

n = 7

Data set of 7 elements.

x = 12

Mean of 12

S = 0

Standard deviation of 0.

Desired data-set:

Since the desired standard deviation is 0, all the elements in the data-set will be the same. Since the mean is 12, all elements is 12. 7 elements.

The desired data-set is: {12,12,12,12,12,12,12}

Answer: it is a linear line

Step-by-step explanation:

They both together make 0

Answer:-244

Step-by-step explanation:

I think you subtract -290 from -46.

Sorry If I am wrong.

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Explanation:

Imagine reflecting everything so that location A is above location B. Effectively all you're doing is erasing the negative signs.

That would place A at 290 feet and B would be at 46 feet. The difference in elevation is 290-46 = 244 feet

Instead of reflecting, you can turn the page upside down and just ignore the negative signs, and then subtract like normal.

This trick only works if both elevations A and B are below sea level.

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Or you could subtract like so:

|A-B| = |-290-(-46)| = |-290+46| = |-244| = 244

The absolute value is used to ensure the result is not negative. A negative difference makes no sense. In this case, "difference" and "distance" mean the same thing more or less.

Answer:Ping Pong Balls

Step-by-step explanation: