I have 50 kVA delta-wye transformer with 3 single phases secondary (line-neutral) delivered to 3 houses, So if one of the 3 houses drown more power would that affect another 2 houses, or each phase can only handle certain amount of power separately?

Answer:

The outer diameter of the spacers that yields the most economical and safe design is 25.03 mm

Explanation:

For steel bolt

Stress = 210 MPa or 210 N/mm2

Pressure = Stress* Area

Pbolt = 210 N/mm2 * 16^2 *(pi)/4

Pbolt = 210 N/mm2 * 200.96 mm^2 = 42201.6  N

For Brass spacer

Pressure = 42201.6  N

Area of Brass spacer = Pressure/Stress

Area of Brass spacer = 42201.6  N/145 N/mm^2 = 291.044 mm^2

Area of Brass spacer = (pi) (d^2 - 16^2)/4 =  291.044 mm^2

d^2 - 16^2 = 291.044 mm^2* 4/(pi) = 370.758

d^2 =  370.758 + 16^2

d^2 =   626.758

d = 25.03 mm

The outer diameter of the spacers that yields the most economical and safe design is 25.03 mm

Answer:

In a parallel circuit, the voltage across each of the components is the same, and the total current is the sum of the currents flowing through each component. ... In a series circuit, every device must function for the circuit to be complete. If one bulb burns out in a series circuit, the entire circuit is broken.

Explanation:

Answer:

equal amounts of inversion and retention at the center undergoing substitution

Explanation:

In an SN1 reaction, the rate determining step is the formation of a carbonation which is flat and planar.

This means that both faces of the carbo cation are equally available for attack by the nucleophile.

Attack on either of the faces may occur equally thereby yielding a racemic mixture.

Answer:

it’s IGS

Explanation:

because i read

Answer:

snap trap baits

Explanation: its kind of obvi, but i took the test and got it right.

Answer:

a) 156 meters

b) 58 m/s

c) 9.8 m/s^2

Explanation:

a) The horizontal displacement X = V *t

X = 50 * 3 = 150 meters

Vertical displacement = y = – g * t² / 2

Y = -9.8 *3*3/2 = -4.9*9 = 44.1

Net Displacement = Sqrt (X^2 +Y^2) = 156.34 = 156 meters

b) Speed of the projectile

vx = 50 m/s

vy = t*g = 9.8*3 = 29.4

V = Sqrt (vx^2 + vy^2) = 58 m/s

c) Acceleration is the acceleration due to gravity = 9.8 m/s^2

The magnitude of the displacement of the projectile is equal to 156 meters.

Given the following data:

Scientific data:

Mathematically, the magnitude of the displacement of a projectile is given by this formula:

[tex]Horizontal\;displacement = Vt\\\\Horizontal\;displacement = 50.0 \times 3.00[/tex]

Horizontal displacement = 150.0 meters.

[tex]Vertical displacement =\frac{1}{2} gt^2\\\\Vertical displacement =\frac{1}{2} \times 9.8 \times 3^2\\\\Vertical displacement =\frac{1}{2} \times 9.8 \times 9[/tex]

Vertical displacement = 44.1 meters.

[tex]D^2 = X^2 +Y^2\\\\D =\sqrt{44.1^2+150^2}[/tex]

D = 156.34 ≈ 156 meters.

b. For the speed of the projectile:

Vertical speed = tg

[tex]V_y = tg = 9.8\times3\\\\ V_y = 29.4\;m/s[/tex]

[tex]D^2 = V_x^2 +V_y^2\\\\D =\sqrt{50^2+29.4^2}[/tex]

D = 58 m/s.

c) The magnitude of the acceleration of the projectile is equal to the acceleration due to gravity ([tex]9.8 \;m/s^2[/tex]).

Read more on acceleration here: brainly.com/question/247283

Answer:

Timing Diagrams 15 pts. A 10 MHz clock that generates a 0 to 5V pulse train with a 30% duty cycle is connected to input X of a two input OR gate that has a 20nS propagation delay. The clock also goes to an inverter with a 10 ns propagation delay. The output of the inverter goes to the Y input of the OR gate. a) Draw the circuit. 2 pts. b) Plot the output of the clock for two cycles. Show times and voltages. 5 pts. c) On the same page as part (b) plot the output of the inverter. Show times and voltages. 3 pts. d) On the same page as parts (b & c) plot the output of the OR gate. Show times and voltages. 5 pts.

Answer:

the energy is sgdrh35679

Answer:

do you have to make the right decisions to be a person who has been a member who is not the first time a great person who has a job in a day of his life or

Answer:

The answer is below

Explanation:

Both a gage and a manometer are attached to a gas tank to measure its pressure. If the reading on the pressure gage is 65 kPa, determine the distance between the two fluid levels of the manometer if the fluid is a) mercury b) water

Solution:

A manometer is a device used to measure pressure. A manometer is made up of a U shaped tube containing liquid. The difference of pressure in the two arms causes the liquid to reach different heights.

a) The density of mercury ([tex]\rho_{Hg}[/tex]) = 13600 kg/m³, Pressure (P) = 65 kPa and g = 9.8 m/s², h = distance between the two fluid levels

[tex]P=\rho_{Hg}*g*h\\\\h=\frac{P}{\rho_{Hg}*g} =\frac{65*10^3\ Pa}{13600*9.81}=0.487\ m[/tex]

b) For water, [tex]\rho_w[/tex] = 1000 kg/m³, hence:

[tex]P=\rho_{w}*g*h\\\\h=\frac{P}{\rho_{w}*g} =\frac{65*10^3\ Pa}{1000*9.81}=6.6\ m[/tex]

Keywords Are Reserved Words Which Are Not Use As Normal Cases But Used For Special Purpose In Our Program whereas, Data Type Tells The Compiler And Interpreter How The Program Is Going To Be Executed And Can Be Used At Every Cases.

Based on how they are stored in the computer, the types produced by these keywords can be categorized into two families, integer types and floating-point types.

Bit, byte, and word are terminology that can be used to refer to either memory or data storage units in computers.

The main distinction between text fields and keyword fields is that text fields are examined during indexing, whereas keyword fields are not.

This means that while keyword fields are indexed exactly as is, text fields are split down into their constituent phrases at indexing to allow for partial matching.

A word or collection of words that an Internet user enters into a search engine or search bar to conduct a search is referred to as a keyword in the context of digital marketing.

Therefore, All data types are keywords, but all keywords are not data types.

Learn more about data and keywords here:

https://brainly.com/question/9588905

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Answer:

Take a 3 to 8 decoder with active low outputs

Assuming you are familiar with the functioning of decoders,

The three inputs of decoder of course are the first, second and the carry bit which you feed to the subtractor.

Next we examine the truth table of the full subtractor i formatted in the picture.

Then write the minterms for the difference output and borrow output from the given truth table picture I have mentioned before!!

Explanation:

hopi it to help you!!

Answer:

c. Although PM and FM techniques are classified as angular modulation techniques, they cannot be used interchangeably i.e., modulated with FM and demodulated with PM, and vice versa.

Explanation:

Phase modulation is modulation pattern for conditioning communication signals for transmission. PM signals appears to change frequency with message wave. Both PM and FM are angular modulation techniques. The message in PM wave is captured in phase changes.

so long so long so long so long so long

Explanation:

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Answer:

127.58 ft

Explanation:

We need first to calculate the length from corner to corner of the story, L.

Since the length of each floor is 75 ft and its width 50 ft, and since each floor is a rectangle with diagonal, L, using Pythagoras' theorem, we have

L² = (75 ft)² + (50 ft)²

= 5625 ft² + 2500 ft²

L² = 8125 ft²

L = √(8125 ft²)

L = 90.14 ft

Since the crane is 5 ft off the southwesterly corner of the building, the working radius, R = L + 5 ft = 90.14 ft + 5 ft = 95.14 ft.(since the diagonal length of the floor plus the distance of the crane from the south westerly corner add to give the working radius)

The boom tip height, H = height of building h + clearance of boom, h'

h = height of each story, h" × number of stories, n

Since h" = 15 ft and n = 5

h = 15 ft × 5 = 75 ft

Also, h' = 10 ft

So, H = h + h'

H = 75 ft + 10 ft

H = 85 ft

So, the minimum boom length, L' = √(H² + R²)

substituting the values of the variables into the equation, we have

L' = √(H² + R²)

L' = √((85 ft)² + (95.14 ft)²)

L' = √(7225 ft² + 9051.6196 ft²)

L' = √(16276.6196 ft²)

L' = 127.58 ft

Answer:

2,160,000

Explanation:

8/100 × 200000/1 = 8/1 × 2000/1

2000 × 8 = 16,000 = interest

200,000 + 16,000 = 216,000

216,000 × 10 = 2,160,000 = amount in bank account

Answer:

C. Low viscosity for Maine in the winter and high viscosity for Florida in the summer.

Explanation:

The choice of motor oil or engine oil depends on the type of engine and also on the type of climate on which the engine runs.

In winter climates, we should use oil with low viscosity as at lower temperatures, the it flows more readily if its viscosity is low.

But the summer season needs a relatively thicker oil so as to reduce the thinning effect of the oil out of the engine.

Thus for Maine in the winter season, we need a low viscosity oil and for Florida a high viscosity oil in the summer season.

Therefore, option (c) is correct.

Answer:

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Explanation:

Answer:

Following are the program to the given question:

#include <stdio.h>//header file

double square_root(double N, double initialGuess)//defining a method square_root that takes two variable in parameters

{

double NG, LG = initialGuess,diff;//defining double variable

while(1)//use loop to calculate square root value

{

NG = 0.5 * (LG + N / LG);//using given formula

diff = NG - LG;//calculating difference

if(diff < 0)//use if to check difference is less than 0

diff = -diff;//decreaing difference

if(diff < 0.005)//use if that check difference is less than 0.005

break;//using break keyword  

else//defining else block

{

LG = NG;//holding value

}

}

return NG;//return value

}

int main()//defining main method

{

double ans, n,initialguess = 1.0;//defining double variable

n = 4;//use n to hold value

ans = square_root(n, initialguess);//calculating the square root value and print its value

printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number

n = 120.5;//use n to hold value

ans = square_root(n, initialguess);//calculating the square root value and print its value

printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number

n = 36.01;//use n to hold value

ans = square_root(n, initialguess);//calculating the square root value and print its value

printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number

n = 0.25;//use n to hold value

ans = square_root(n, initialguess);//calculating the square root value and print its value

printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number

printf("\nEnter a number: ");//print message

scanf("%lf", &n);//input value

ans = square_root(n, initialguess);//calculating the square root value and print its value

printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number

}

Output:

Please find the attachment file.

Explanation: