I am having trouble understanding how I got these wrong on my test. Is there something I am missing with xor?

Answer:

σ1, σ2 and σ3.

Explanation:

The three principal stresses are labelled or written as σ1, σ2 and σ3. The σ1 is the maximum principal stress or most tensile stress, σ2 is the intermediate principal stress and σ3 is the minimum or most compressive principal stress. Principal stresses are the maximum and minimum extensional stresses present in an object. The principal directions have no shear stresses connected with them.

Answer:

The correct answer is "25.03 mm".

Explanation:

Given:

Thickness of plate,

= 10 mm

On a side,

= 100 mm

Diameter hole,

= 25 mm

Coefficient of thermal expansion,

CTE = [tex]12\times 10^{-6} /^{\circ} C[/tex]

Now,

⇒ [tex]D_i\times (12\times 10^{-6}) \Delta \theta = \Delta D[/tex]

=  [tex]25\times 12\times 10^{-6} \Delta \theta[/tex]

= [tex]3\times 10^{-4} \Delta \theta[/tex]

= [tex]3\times 10^{-2}[/tex]

hence,

The final diameter of hole will be:

[tex]D_f=25.03 \ mm[/tex]    

Answer:

Titanium Alloy

Explanation:

Length ( L ) = 20 mm

D1 = 20 mm

d2 = 18 mm

l = 20 mm

Mechanical efficiency = 50%

power = 80 kW

cutting rake angle = 0°

cutting speed ( v ) = 10 m/s

Determine the material to be for the cylinder

In order to choose a material for the cylinder we have to calculate the cutting force

P = Fc * V

80  = Fc * 10 m/s

therefore Fc = 80 / 10 = 8 N

Hence the material we can use is Titanium Alloy   due to low cutting force value

Answer:

sorry , for my point

Explanation:

Answer:

[tex]D_o=11.9inch[/tex]

Explanation:

From the question we are told that:

Thickness [tex]T=0.5[/tex]

Internal Pressure[tex]P=2.2Ksi[/tex]

Shear stress [tex]\sigma=12ksi[/tex]

Elastic modulus [tex]\gamma= 35000[/tex]

Generally the equation for shear stress is mathematically given by

 [tex]\sigma=\frac{P*r_1}{2*t}[/tex]

Where

r_i=internal Radius

Therefore

 [tex]12=\frac{2.2*r_1}{2*0.5}[/tex]

 [tex]r_i=5.45[/tex]

Generally

 [tex]r_o=r_1+t[/tex]

 [tex]r_o=5.45+0.5[/tex]

 [tex]r_o=5.95[/tex]

Generally the equation for outer diameter is mathematically given by

 [tex]D_o=2r_o[/tex]

 [tex]D_o=11.9inch[/tex]

Therefore

Assuming that the thin cylinder is subjected to integral Pressure

Outer Diameter is

 [tex]D_o=11.9inch[/tex]

Answer:

Engineer A results will be more accurate

Explanation:

Analytical method is better than numerical method. Engineer A has used analytical method and therefore his results will be more accurate because he used simplified method. Engineer B has used software to solve the problem related to heat transfer his results will be approximate.

Answer:

[tex]\triangle V_0=0.08V[/tex]

Explanation:

From the question we are told that:

Incremental resistance  [tex]R=8ohms[/tex]

Resistor Feed [tex]R_f=82ohms[/tex]

Supply Change [tex]\triangle V=1[/tex]

Generally the equation for  voltage rate of change is mathematically given by

 [tex]\frac{dV_0}{dV}=\frca{R}{R_1r_3}[/tex]

Therefore

 [tex]\triangle V_0=\triangle V*\frac{R}{R_fR}[/tex]

 [tex]\triangle V_0=1*\frac{8}{8*82}[/tex]

 [tex]\triangle V_0=0.08V[/tex]

Answer: Hello the question is incomplete below is the missing part

Question:  determine the temperature, in °R, at the exit

answer:

T2= 569.62°R

Explanation:

T1 = 540°R

V2 = 600 ft/s

V1 = 60 ft/s

h1 = 129.0613  ( value gotten from Ideal gas property-air table )

first step : calculate the value of h2 using the equation below

assuming no work is done ( potential energy is ignored )

h2 = [ h1 + ( V2^2 - V1^2 ) / 2 ] * 1 / 32.2 * 1 / 778

∴ h2 = 136.17 Btu/Ibm

From Table A-17

we will apply interpolation

attached below is the remaining part of the solution

Answer:

True ❤️

-Solid by solid can make Cylindrical wire doubles Strengths in tension

Answer:

Tech A is correct.

Explanation:

If a person is doing something dangerous in a shop, he should wear safety glasses to protect his eyes from danger and also wear leather shoes to protect himself from any electric shock. Leather boots will disconnect a person with direct earth and therefore he can save himself if he gets a electric shock.

Explanation:

https://www.chegg.com/homework-help/questions-and-answers/iron-core-wish-design-transformer-part-dc-power-supply-moderately-high-current-rating-volt-q53186459?trackid=83dbc34cec2e&strackid=3efc9f324415

Answer:

Minimum area of rectangle = 24 cm²

Explanation:

Given:

Length of rectangle = 6 cm

Width of rectangle = 4 cm

Find:

Minimum area of rectangle

Computation:

Area of rectangle = Length of rectangle x Width of rectangle

Minimum area of rectangle = Length of rectangle x Width of rectangle

Minimum area of rectangle = 6 x 4

Minimum area of rectangle = 24 cm²

Answer:

A) L = 0.388 μm

B) D = 3.78 mm

Explanation:

We are given;

Characteristics impedance; Z_o = 75 ohms

Nominal capacitance; C = 69pF/m = 69 × 10^(-12) F/m

dielectric constant; k = 2.23

Inner diameter of conductor; d = 0.584 mm

A) Now formula for Characteristics impedance is given as;

Z_o = √(L/C)

Where L is the inductance per metre.

Making L the subject, we have;

L = (Z_o)²C

L = 75² × 69 × 10^(-12)

L = 0.388 × 10^(-6) m

L = 0.388 μm

B) To get the outer diameter, we will use the formula;

Z_o = (138/√k) log(D/d)

Where;

D is outer diameter.

Thus, Plugging in the relevant values;

75 = (138/√2.23) × log (D/0.584)

log (D/0.584) = 0.81158611538

(D/0.584) = 10^(0.81158611538)

D/0.584 = 6.48016576435

D = 6.48016576435 × 0.584

D = 3.78 mm

Answer:

[tex]U=\pm 0.382N[/tex]

Explanation:

From the question we are told that:

Resolution: 0.25 N

Range: 0 to 100 N

Linearity error: within 0.20 N over range

Hysteresis error: within 0.30 N over range

Generally the equation for Stage Uncertainty is mathematically given by

[tex]U=\sqrt{u_0^2+u_T^2}[/tex]

Where

[tex]u_0=Zero\ order\ uncertainty[/tex]

[tex]u_0=\pm 0.5*0.25[/tex]

[tex]u_0=\pm=0.125[/tex]

And

u_T=Total instrumental Uncertainty

[tex]u_T=\sqrt{l_e^2+h_e^2}[/tex]

Where

l_e=Error of linearity

h_e=Error due to hysteresis

Hence

[tex]u_T=\sqrt{0.20^2+0.30^2}[/tex]

[tex]u_T=\pm 0.36[/tex]

Therefore

[tex]U=\sqrt{(0.125)^2+0.36^2}[/tex]

[tex]U=\pm 0.382N[/tex]

Answer:

How to stop toilets  

Explanation:

I think

Hope this helps

Answer:

that

I am not sure that this is the answer

but i hopethis will help you

Karl and Susan agreed to come to our party, which made Maria very happy. The correct option is b.

Relative pronouns are words that are used to show the relation between two statements. Who/whom, whoever/whomever, whose, that, and which are the most common relative pronouns. "what," "when," and "where" might operate as relative pronouns.

Relative pronouns introduce dependent sentences called relative clauses. Happy is an emotion that is non-living things and with non-living things, which is used.

The relative pronouns "which" and "that" begin adjective clauses. Both provide additional information about the noun they follow.

Therefore, the correct option is b, which. Karl and Susan agreed to come to our party, which made Maria very happy.

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Answer:

you are good thx dedo please ❤️

Explanation:

please give me thx pls pls pls

Answer:

inductive reasoning

Explanation:

Inductive reasoning is one of the type of reasoning method in which generalized consequences are derived from limited observations. By observing few data, general conclusions are drawn. The conclusions drawn are false in inductive reasoning. In the given situation, the conclusion drawn by the elevator repairer has been drawn by inductive reasoning. His observation of some cables led him to draw the conclusion about all the cables. The result of the reasoning is false.

Answer:

a)  [tex]m_e= 3.05 Kg[/tex]

b)  [tex]\rho=1072.3kg/m^3[/tex]

c)  [tex]m_e= 3.05 Kg[/tex]

Explanation:

From the question we are told that:

Beaker Mass [tex]m_b=1.20[/tex]

Liquid Mass [tex]m_l=1.85[/tex]

Balance D:

Mass [tex]m_d=3.10[/tex]

Balance E:

Mass [tex]m_e=7.50[/tex]

Volume [tex]v=4.15*10^{-3}m^3[/tex]

a)

Generally the equation for Liquid's density is mathematically given by

[tex]m_e=m_b+m_l+(\rho*v)[/tex]

[tex]\rho=\frac{7.50-(1.2+1.85)}{4.15*10^{-3}}[/tex]

[tex]\rho=1072.3kg/m^3[/tex]

b)

Generally the equation for D's Reading at A pulled is mathematically given by

m_d = mass of block - mass of liquid displaced

[tex]m_d=m- (\rho *v )[/tex]

[tex]m=3.10+ (1072.30 *4.15*10^{-3}m^3 )[/tex]

[tex]m=18.10kg[/tex]

c)

Generally the equation for E's Reading at A pulled is mathematically given by

[tex]m_e=m_b+m_l[/tex]

[tex]m_e = 1.20 + 1.85[/tex]

[tex]m_e= 3.05 Kg[/tex]

Answer: check answers in pictures (2 p)

The resistance of the shunt required for a full-scale deflection of 20 A is 2.528 Ohm.

Resistance is a measure of an electrical circuit's resistance to current flow. Resistance is measured in ohms, which is represented by the Greek letter omega.

Full-scale deflection current = 0.015 A

Full-scale deflection current for 20 A = 20/0.015 = 1333.33 times full-scale deflection current

The current through the meter coil is given by:

Ic = Im * (Rm / (Rm + Rs))

At full scale, Ic = 1333.33 * 0.015 A = 20 A, Rm = 1.5 Ohm, and Rs = 3.5 Ohm.

Therefore:

20 A = Im * (1.5 Ohm / (1.5 Ohm + 3.5 Ohm))

Im = 20 A * (3.5 Ohm / 5 Ohm)

Im = 14 A

The current through the shunt resistor is therefore:

Ish = Im - Ic

Ish = 14 A - 20 A

Ish = -6 A

Since the shunt resistor is in parallel with the meter, its resistance can be calculated using the following formula:

Rs = Rm * (Im / Ish - 1)

Substituting the values, we get:

3.5 Ohm = 1.5 Ohm * (14 A / (-6 A) - 1)

3.5 Ohm = 1.5 Ohm * (-1.333 - 1)

3.5 Ohm = 1.5 Ohm * (-2.333)

Rs = 1.5 Ohm * (14 A / (-6 A) - 1) / (-2.333)

Rs = 2.528 Ohm

Therefore, the resistance of the shunt required for a full-scale deflection of 20 A is 2.528 Ohm.

Now, let's find the resistance required for a full-scale deflection of 250 V:

Full-scale deflection current = 0.015 A

Resistance required for full-scale deflection of 250 V = 250 V / 0.015 A

Resistance required for full-scale deflection of 250 V = 16666.67 Ohm

This resistance is in parallel with the meter coil, so the total resistance in the circuit will be:

Rtotal = Rm || Rext

Rtotal = (Rm * Rext) / (Rm + Rext)

Substituting the values, we get:

Rtotal = (1.5 Ohm * 16666.67 Ohm) / (1.5 Ohm + 16666.67 Ohm)

Rtotal = 1.43 Ohm

This resistance is in series with the meter coil, so the total resistance in the circuit will be:

Rtotal = Rm + Rext + Rs

Substituting the values we get:

1.43 Ohm = 1.5 Ohm + 16666.67 Ohm + Rs

Rs = 1.43 Ohm - 1.5 Ohm - 16666.67 Ohm

Rs = -16666.74 Ohm

Thus, the calculated value of Rs is negative, it means that the shunt resistor must be used instead of a series resistor to achieve a full-scale deflection of 250 V.

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Answer:

All the bonds in methane (CH4CH4) are equivalent, and all have the same dissociation energy.

The product of the dissociation is methyl radical (CH3CH3). All the bonds in methyl radical are equivalent, and all have the same dissociation energy.

The product of that dissociation is methylene (CH2CH2). All the bonds in methylene are equivalent, and all have the same dissociation energy.

The product of that dissociation is methyne (CHCH) .

The C-H bonds in methane do not have the same dissociation energy as C-H bonds in methyl radical, which in turn do not have the same dissociation energy as the C-H bonds in methylene, which are again different from the C-H bond in methyne.

If (by some miracle) you were able to get all four bonds in methane to dissociate absolutely simultaneously, they would all show the same dissociation energy… but that energy, per bond broken, would be different than the energy required to break just one C-H bond in methane, because the products are different.

(In this case, it’s CH4→C+4HCH4→C+4H versus CH4→CH3+HCH4→CH3+H.)

To alter hydrocarbons you add enough energy to break a C-H bond. Why does only one bond break? What concentrates the energy on one C-H bond?

the weakest CH bond is the one that breaks. in plain alkanes it has to do with the molecular orbital interactions between neighboring carbon atoms. look at propane for example. the middle carbon has two C-C bonds, and each of those C-C bonds is strengthened by slight electron delocalization from the C-H bonds overlapping with the antibonding orbitals of the adjacent carbons.

since the C-H bonds on the middle carbon donate electron density to both of its neighbors, those two are weakest.

one of them will break preferentially.

which one actually breaks depends on the reaction conditions (kinetics). frankly it's whichever one ramdomly approaches a nucleophile first. when the nucleophile pulls of one of the H's, the other C-H bonds start to share (delocalize) the negative charge across the whole molecule. so while the middle C feels the majority of the negative charge character, the other two C's take on a fair amount as well...

by the way, alkanes don't really like to break and form anions like that.

a better example would be something like isopropyl iodide, where the C-I bond breaks and the I carries away the electron pair, forming a carbocation (also not particularly stable, but more so than the carbanion).

Answer:

hi hello tata byebye nice

As per the given data, the maximum value of e2 such that the RM schedule is feasible is 0.985.

Fixed-priority scheduling is a scheduling algorithm used in real-time operating systems to assign priorities to tasks based on their relative importance or urgency.

In a fixed-priority scheduling algorithm, tasks with higher priority are assigned shorter periods.

Since task 1 has a period of 4 and task 2 has a period of 6, we can assume that task 1 has a higher priority than task 2. Therefore, we can apply the Rate Monotonic (RM) scheduling algorithm.

The RM scheduling algorithm states that a feasible schedule exists if the following condition is satisfied:

Σ (ei / pi) ≤ n(2^(1/n)-1)

Where Σ (ei / pi) is the sum of the ratio of execution time to period for all tasks, n is the total number of tasks, and the base of the exponential function is 2.

In this case, we have two tasks, so n = 2. We know that e1 = 1 and p1 = 4. For task 2, we need to find the maximum value of e2 such that the schedule is feasible. Therefore, we can set e2 = x and p2 = 6.

Substituting the values into the RM scheduling formula, we get

(e1/p1) + (e2/p2) ≤ 2^(1/2) - 1

(1/4) + (x/6) ≤ 0.4142

Multiplying both sides by 12, we get:

3 + 2x ≤ 4.97

2x ≤ 1.97

x ≤ 0.985

Therefore, the maximum value of e2 such that the RM schedule is feasible is 0.985.

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Answer:

1) B: Increase its length

2) True

3) True

Explanation:

1) Columns are compressive members and are subjected to primarily compressive stresses.

Now, there is what we call slender Ness ratio in columns which is basically used to check the ability of a column to resist buckling.

The formula is;

Slenderness ratio = Effective length of column/radius of gyration

Thus, the longer the column the more the Slenderness ratio and the more likely it is to buckle.

Thus, increasing the length is what makes columns likely buckle.

2) Compressive strength is the ability of a material to withstand loads that may reduce size or make the material crush under load.

Now, increasing the compressive strength simply means more ability to withstand loads that may lead to crushing under load.

Ultimate compressive strength is the maximum amount of compressive stress that a material can take before it crushes under load. Thus, increasing the ultimate compressive strength means it is less likely to crush under its own weight.

3) There are different factors that affect moment of inertia and they are;

- the mass of the body

- axis of rotation of the body

- shape and size of the body.

However, for area moment of inertia, what is most relevant to us is the shape of the body in question since we are dealing with area and not how big it is.

Answer:

 I = 1205.69 Lx

Explanation:

The irradiation or intensity of the solar radiation on the earth is maximum for the vertical fire, with a value I₀

          I = I₀ sin θ

in this case with the initial data we can calculate the initial irradiance

         I₀ = [tex]\frac{I}{sin \ \theta }[/tex]

         I₀ = 1600 /sin 53

         I₀ = 2003.42 lx

for when the angle is θ = 37º

         I = 2003.42 sin 37

         I = 1205.69 Lx