Answer:
There is 7642 grams of CO2 released
Explanation:
Step 1: Data given
carbon dioxide = CO2
Molar mass of carbon dioxide = 44.01 g/mol
Mass of ethanol = 4 kg = 4000 grams
Molar mass of ethanol = 46.07 g/mol
Step 2: The reaction
Combustion of ethanol means there is oxygen (O2) added. The products are CO2 and H2O.
C2H5OH + 3O2 → 2CO2 + 3H2O
Step 3: Calculate number of moles of ethanol
Moles ethanol = mass ethanol / molar mass ethanol
Moles ethanol = 4000 grams / 46.07 g/mol
Moles ethanol = 86.82 moles
Step 4: Calculate number of moles CO2
For 1 mol ethanol we need 3 moles to produce 2 moles CO2 and 3 moles H2O
For 86.82 moles of ethanol we'll have 2*86.82 = 173.64 moles CO2
Step 5: Calculate mass of CO2
Mass CO2 = moles CO2 * molar mass CO2
Mass CO2 = 173.64 moles * 44.01 g/mol
Mass CO2 = 7642 grams
There is 7642 grams of CO2 released
What element on the periodic table has 5 protons, 5 electrons, and 5 neutrons?
Answer:
Boron
Explanation:
this is your answer
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Both aldehydes and ketones contain a carbonyl group a functional group with a carbon oxygen double bond, hence the carbonyl in aldehydes and ketones forms sp²hybridization.
Answer:
Both aldehydes and ketones contain a carbonyl group a functional group with a carbon oxygen double bond, hence the carbonyl in aldehydes and ketones forms sp²hybridization.
Explanation:
The structure of carbonyl group is -C=O-
The hybridization of carbon can be identified by couting the number of surrounding atoms.
In carbonyl compounds, carbon is directly bonded with three atoms.
One is oxygen, and the other two are other carbons.
With oxygen carbon has a double bond.
Hence, this three corresponds to sp2 hybridization.
Thus, the given statement is correct.
Consider this equilibrium:
HCO3- + H2PO4-HPO42- + H2CO3.
What are the Brønsted-Lowry acids in this equilibrium?
A. HCO3- and H2CO3
B. HCO3 and HPO42-
C. H2PO4! and H2CO3
D. H2PO4' and HPO4-
E. HCO3 and H2PO4!-
Answer:
the answer is option E they are bronsted lowry acid
There are two types of automatic exposure control: photodiode and the more common parallel plate ionization chamber. How are they positioned
Answer:
Following are the response to the given question:
Explanation:
In the given question the automatic exposure is used as the management which is offered in two distinct methods: photodiode as well as the parallel ionizing tank. In both are positioned as the absolute pressure type is between the patient as well as the receptor, behind the image receptor the photoelectric is placed.
Which refers to substances that are complex molecules and contain carbon atoms bonded to hydrogen atoms?
o
O organic
O inorganic
ionic
metallic
Answer:
organic
Explanation:
Organic substances are those which contains covalently linked carbon to hydrogen (C-H) bonds in their structure. In other words, organic compounds or substances are uniquely composed of carbon and hydrogen atoms covalently linked together.
These substances usually contain a long chain of these bonds, hence, making them complex. Therefore, according to this question, substanves that are complex molecules and contain carbon atoms bonded to hydrogen atoms are referred to as ORGANIC SUBSTANCES.
Answer:
A. Organic
Explanation:
Select the structure that corresponds
to the name:
decanoic acid
COOH
A.
B. CH3(CH2)7COOH
C. both
Answer:
b
Explanation:
Molecular formula of Decanoic Acid is C₁₀H₂₀O₂ therefore Option A is the right answer.
What is Decanoic Acid ?Decanoic Acid is a C10 , straight chain , saturated fatty acid . Its general formula is C₁₀H₂₀O₂ .
In the first option we can see a straight chain , saturated fatty acid and the molecular formula is also same as decanoic acid .
In second option the molecular formula is C₉H₁₈O₂ which is not same as Decanoic Acid.
Hence option A is the right answer.
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Balance the equation of. _C + _O2 -- _CO
Explanation:
2C +O2 = 2CO
this will be the answer
Name the following structure:
HOCH2CH2CH2OH
Answer:
I'm pretty sure this is propanediol
Explanation:
I'm not sure how to explain it, but I believe this is the structure for propanediol. Please let me know if I misunderstood and don't hesitate to reach out with questions!
1,3-propan-diol is the chemical name the given structure: [tex]HOCH_2CH_2CH_2OH[/tex].
Chemical names are orderly systems for classifying and identifying various chemical compounds. They act as a benchmark for international scientific and research communication. For the development of many scientific domains, a standardised nomenclature system for chemicals must be created and adopted. Chemical names, which are made up of a combination of words and symbols, include detailed information on the make-up and structure of a certain substance. They frequently contain constituents, functional groups, and distinct modifiers that aid in describing the compound's varied attributes. 1,3-propan-diol is the chemical name the given structure: [tex]HOCH_2CH_2CH_2OH[/tex].
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Which of the following elements has three valence electrons? (2 points)
Li
C
Al
Mg
Answer:
Al
Explanation:
It has 3.
True or false, The atomic number of an element is a whole number that decreases as you read across each row of
the periodic table from left to right.
Answer:
I believe it's false because the atomic number is the number of protons in the nucleus of an atom.
ionisation potential of the element increases across a period from left to right
Answer:
False
Explanation:
It actually decreases.
Gallium has two natural occuring isotopes: Ga-69 with 68.9256 amu and a natural abundance of 60.11%, and Ga-71 with mass 70.9247 amu and a natural abundance of 39.8%. Calculate the atomic mass of gallium.
Using the following samples below, elaborate on the practical uses of concave and convex
mirrors. Write your answer on a separate sheet of paper.
1. Car rear view mirror
2. Security
3. Street light reflectors
4. Shaving facial hair
5. Car light
Answer: Convex mirror is curved in the outward direction and concave mirror in the inward direction.
Explanation:
1. Car rear view mirror: It is a convex mirror which gives the indication of large field of view and it allows the driver to view the traffic behind the car.
2. Security: The reflective bulge surfaces of the convex mirrors reflect the light outwards and provides an expanded field of view of the entire view of shops and other places useful for security.
3. Street light reflectors: They use convex mirrors because they are able to spread the light over the wider area.
4. Shaving facial hair: Concave mirror is used in shaving facial hair. It gives a bigger view of face when it is at the position of pole and focal point of the mirror.
5. Car light: It uses concave mirror because of the converging power it can focus more light rays at a particular point.
Consider the following reaction, where A and
E are hypothetical elements.
A + 3E --> AE3
The atomic mass of A is 42.1 amu.
The atomic mass of E is 56.2 amu.
If 42.6 g of A fully reacts, how many grams of
AE3 are expected to form?
Enter your numerical answer to 1 decimal
place. Do not include the units of "g".
Answer:
Enter your numerical answer to 1 decimal place. Do not include the units of "g". Question: Question 14 1 pts Consider the following reaction, where A and E are hypothetical elements. A+3E --> AE The atomic mass of A is 42.1 amu. The atomic mass of Eis 56.2 amu. If 42.6 g of A fully reacts, how many grams of AE, are expected to form?
can someone do this step by step
Answer:
No
Can't understand.
Pls follow me and Mark as brainliest Plsssssssss.
Which of the following is the best thermal insulator to reduce the transfer of
heat by convection?
A. Air
B. Water
C. Alcohol
D. A vacuum
Answer:
A
Explanation:
If I have 9.7 moles of gas at a pressure of 0.12 atm and at a temperature of 46°C, what is the volume of the
container that the gas is in?
Answer:
2117.02 litres
Explanation:
Using the ideal gas equation as follows;
PV = nRT
Where:
P = pressure of the gas (atm)
V = volume of the gas (L)
n = number of moles (mol)
R = gas law constant (Latm/molK)
T = temperature (K)
According to the information given in this question,
P = 0.12 atm
V = ?
n = 9.7moles
T = 46°C = 46 + 273 = 319K
R = 0.0821 Latm/molK
Using PV = nRT
0.12 × V = 9.7 × 0.0821 × 319
0.12V = 254.04
V = 254.04 ÷ 0.12
V = 2117.02 litres
Which general equation shows a double-displacement reaction?
O A. AB + CD + AC + BD
O B. AB → A+B
O C. AB + CD → AD + CB
O D. A+B → AB
Answer:
O A. AB + CD + AC + BD
explanation:
Explanation:
A.ab+cd+ac+bd is your answer
For the equilibrium
2H2S(g) ⇋ 2H2(g) + S2(g) Kc = 9 .0X 10-8 at 700°C
the initial concentrations of the three gases are 0.300 M H2S, 0.300 M H2, and 0. 1 50 M S2' Determine the equilibrium concentrations of the gases.
Answer:
Equilibrium concentrations of the gases are
[tex]H_2S=0.596M[/tex]
[tex]H_2=0.004 M[/tex]
[tex]S_2=0.002 M[/tex]
Explanation:
We are given that for the equilibrium
[tex]2H_2S\rightleftharpoons 2H_2(g)+S_2(g)[/tex]
[tex]k_c=9.0\times 10^{-8}[/tex]
Temperature, [tex]T=700^{\circ}C[/tex]
Initial concentration of
[tex]H_2S=0.30M[/tex]
[tex]H_2=0.30 M[/tex]
[tex]S_2=0.150 M[/tex]
We have to find the equilibrium concentration of gases.
After certain time
2x number of moles of reactant reduced and form product
Concentration of
[tex]H_2S=0.30+2x[/tex]
[tex]H_2=0.30-2x[/tex]
[tex]S_2=0.150-x[/tex]
At equilibrium
Equilibrium constant
[tex]K_c=\frac{product}{Reactant}=\frac{[H_2]^2[S_2]}{[H_2S]^2}[/tex]
Substitute the values
[tex]9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}[/tex]
[tex]9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}[/tex]
[tex]9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}[/tex]
By solving we get
[tex]x\approx 0.148[/tex]
Now, equilibrium concentration of gases
[tex]H_2S=0.30+2(0.148)=0.596M[/tex]
[tex]H_2=0.30-2(0.148)=0.004 M[/tex]
[tex]S_2=0.150-0.148=0.002 M[/tex]
What does physics study
Answer:
Physics is the branch of science that deals with the structure of matter and how the fundamental constituents of the universe interact. It studies objects ranging from the very small using quantum mechanics to the entire universe using general relativity.
True or false, The atomic number of an element is a whole number that decreases as you read across each row of
the periodic table from left to right.
HELP ASAP Choose three sections of the electromagnetic spectrum. Rank them in order of energy. Give an example of how they are used for each.
What is the cause of acid precipitation?
1) ozone
2) nitrogenous oxides
3) ammonia
4) chlorofluorocarbons (CFCs)
Answer:
nitrogenous oxides
Explanation:
Acid rain is caused by a chemical reaction that begins when compounds like sulfur dioxide and nitrogen oxides are released into the air. ... In addition, the exhaust from cars, trucks, and buses releases nitrogen oxides and sulfur dioxide into the air. These pollutants cause acid rain.
The correct answer in you question is 2) nitrogenous oxide
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#CarryOnLearningMatch the factors which affect the rate of dissolving/dissociation/diffusion.
1. increased surface area
2. like dissolves like
3. temperature
4. stirring spreads
rate proportional to kinetic energy
matching polarity
finely divided solute
solute throughout solution
Answer:
Increased surface area - finely divided solute
like dissolves like - matching polarity
temperature - rate proportional to kinetic energy
stirring spreads - solute throughout solution
A mixture of gases contains 0.320 mol CH4, 0.240 mol C2H6, and 0.300 mol C3H8. The total pressure is 1.45 atm. Calculate the partial pressures of the gases.
Answer:
pCH₄ = 0.540 atm
pC₂H₆ = 0.405 atm
pC₃H₈ = 0.505 atm
Explanation:
Step 1: Calculate the total number of gaseous moles
n = n(CH₄) + n(C₂H₆) + n(C₃H₈)
n = 0.320 mol + 0.240 mol + 0.300 mol = 0.860 mol
Step 2: Calculate the partial pressure of each gas
We will use the following expression.
pi = P × Χi
where,
pi: partial pressure of the gas "i"P: total pressureΧi: mole fraction of the gas "i"pCH₄ = 1.45 atm × 0.320 mol/0.860 mol = 0.540 atm
pC₂H₆ = 1.45 atm × 0.240 mol/0.860 mol = 0.405 atm
pC₃H₈ = 1.45 atm × 0.300 mol/0.860 mol = 0.505 atm
calculate the mass of solute in 500cm³ of 1.5mol/dm³ sodium hydroxide solution
Answer: The general formulae for moles is n=m/mr so now we have being given to find the mass so all we have to do is to change subject
Explanation: so we have to change subject in this question to m= n× mr . so in the question below we have being given the mole as 1.5mol/dm³ so all we have to do is to find the molecular relative mass(mr) .
to find the molecular relative mass of sodium hydroxide (NAOH) we add all of the atomic masses of all the atoms present so here we have sodium oxygen and hydrogen atoms present.
NA=23 O=16 H=1 so we add 23+16+1=40 so 40 is our molecular relative mass
now we fix it in our formulae which is m=n× mr
m=1.5× 40 =60 so our mass is 60grams or 60g
HOPE THIS HELPS!!!! if i made a mistake our MAY answer may be wrong feel free to comment
during the extraction of iron from iron oxide in the Blast Furnace state the function of limestone
Answer:
Redox reactions are involved in the extraction of metals from their ores, eg extracting iron by reduction within the blast furnace. Transition metals have high melting points and densities, form coloured compounds and act as catalysts
During a process called photoact, ________ give up an electron as a part of the light-dependent reactions.
Answer:
Chloroplasts?
Explanation:
What are the prefixes for molecular compounds?
Answer:
In nomenclature of simple molecular compounds, the more electropositive atom is written first and the more electronegative element is written last with an -ide suffix.
The Greek prefixes are used to dictate the number of a given element present in a molecular compound.
Prefixes can be shortened when the ending vowel of the prefix “conflicts” with a starting vowel in the compound.
Common exceptions exist for naming molecular compounds, where trivial or common names are used instead of systematic names, such as ammonia (NH3) instead of nitrogen trihydride or water (H2O) instead of dihydrogen monooxide.
Terms
nomenclatureA set of rules used for forming the names or terms in a particular field of arts or sciences.
electronegativeTending to attract electrons within a chemical bond.
electropositiveTending to not attract electrons (repel) within a chemical bond.
Chemical Nomenclature
The primary function of chemical nomenclature is to ensure that a spoken or written chemical name leaves no ambiguity concerning to what chemical compound the name refers. Each chemical name should refer to a single substance. Today, scientists often refer to chemicals by their common names: for example, water is not often called dihydrogen oxide. However, it is important to be able to recognize and name all chemicals in a standardized way. The most widely accepted format for nomenclature has been established by IUPAC.
Molecular compounds are made when two or more elements share electrons in a covalent bond to connect the elements. Typically, non-metals tend to share electrons, make covalent bonds, and thus, form molecular compounds.
Rules for Naming Molecular Compounds:
Remove the ending of the second element, and add “ide” just like in ionic compounds.
When naming molecular compounds prefixes are used to dictate the number of a given element present in the compound. ” mono-” indicates one, “di-” indicates two, “tri-” is three, “tetra-” is four, “penta-” is five, and “hexa-” is six, “hepta-” is seven, “octo-” is eight, “nona-” is nine, and “deca” is ten.
If there is only one of the first element, you can drop the prefix. For example, CO is carbon monoxide, not monocarbon monoxide.
If there are two vowels in a row that sound the same once the prefix is added (they “conflict”), the extra vowel on the end of the prefix is removed. For example, one oxygen would be monooxide, but instead it’s monoxide. The extra o is dropped.
Generally, the more electropositive atom is written first, followed by the more electronegative atom with an appropriate suffix. For example, H2O (water) can be called dihydrogen monoxide (though it’s not usually). Organic molecules (molecules made of C and H along with other elements) do not follow this rule.
Here are the prefixes in naming molecular compounds:
Mono- 1
Di- 2
Tri- 3
Tetra- 4
Penta- 5
Hexa- 6
Hepta- 7
Octa- 8
Nona- 9
Deca- 10
Molecular compounds are named using a systematic approach of prefixes to indicate the number of each element present in the compound.
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