how to solve (n^(3)+3n^(2)+3n+28)-:(n+4) in long polynomial division?

9514 1404 393

Answer:

  5.7·10^-3

Step-by-step explanation:

The expanded scale shows point P lies 7/10 of the way between 5 and 6 times 10^-3. Its value is 5.7·10^-3.

Answer:

second x -1,-3,-5 y 1 3 5 for proportional relation

Answer:

There were 44 students in each bus.

Step-by-step explanation:

357 - 5 = 352

352/8 = 44

Answer:

Step-by-step explanation:

Total students = 357

Total buses filled = 8

No of students traveled in car = 5

Remaining students = 357 - 5 = 352

Students in each bus = 352 ÷ 8 = 44 students

Step-by-step explanation:

[tex]x + 3y = 7 \\ 2x + 4y = 8 \\ x = 7 - 3y \\ 2(7 - 3y) + 4y = 8 \\ 14 - 6y + 4y = 8 \\ 14 - 2y = 8 \\ - 2y = - 6 \\ y = 3 \\ x = 7 - 3(3) \\ x = 7 - 9 \\ x = - 2[/tex]

Answer:

2x+3y=7x4

x+4y=8x3

8x+12y=27

3x+12y=24

8x-3x =5x

+12y-+12y=0

27-24=3

5x/5 3/5x

answer = x = 3/5

y=1.85

Answer:

A=29.12ft^2

Step-by-step explanation:

first, find the area of the triangle and semicircle separately, then add them together to find the total area of the figure:

area of a triangle: 1/2bh

1/2(6)(8)=24ft^2

area of a circle: πr^2

(**we're using 3.14 instead of pi, and it's a semicircle)

1/2(3.14)(4)^2

1/2(3.14)(16)

1/2(50.24)

25.12ft^2

total area of the figure:

24+25.12=29.12ft^2

Answer: 49.12 ft²

Step-by-step explanation:

This figure is composed of

First, find the area of the half-circle.

The area of a full circle is π · r², but since it's only half a circle, we divide that by half, resulting in (π · r²)/2

Therefore, the area of the half-circle is:

(3.14 · 4²)/2 = (3.14 · 16)/2 = 50.24/2 = 25.12 ft²

Second, find the area of the right triangle.

The area of a triangle = ½bh.

Therefore, the area of the triangle is:

½ · 6 · 8 = ½ · 48 = 24 ft²

Add the two areas together:

24 + 25.12 = 49.12 ft²

Answer:

5 cm

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

let h be the hypotenuse , then

h² = 3² + 4² = 9 + 16 = 25 ( take the square root of both sides )

h = [tex]\sqrt{25}[/tex] = 5

Answer: When f(x)=g(x) , x equal to -2 or -1

Step-by-step explanation:

Answer:

cannot be determined

Step-by-step explanation:

We do not know if any of the angles are equal and are only given two sides.

We cannot determine if the two triangles are similar

Answer:

[tex]\text{1) }\\\text{Circumference: }24\pi \text{ m}},\\\text{Length of bolded arc: }18\pi \text{ m}\\\\\text{3)}\\\text{Circumference. }4\pi \text{ mi},\\\text{Length of bolded arc: } \frac{3\pi}{2}\text{ mi}[/tex]

Step-by-step explanation:

The circumference of a circle with radius [tex]r[/tex] is given by [tex]C=2\pi r[/tex]. The length of an arc is makes up part of this circumference, and is directly proportion to the central angle of the arc. Since there are 360 degrees in a circle, the length of an arc with central angle [tex]\theta^{\circ}[/tex] is equal to [tex]2\pi r\cdot \frac{\theta}{360}[/tex].

Formulas at a glance:

Question 1:

The radius of the circle is 12 m. Therefore, the circumference is:

[tex]C=2\pi r,\\C=2(\pi)(12)=\boxed{24\pi\text{ m}}[/tex]

The measure of the central angle of the bolded arc is 270 degrees. Therefore, the measure of the bolded arc is equal to:

[tex]\ell_{arc}=24\pi \cdot \frac{270}{360},\\\\\ell_{arc}=24\pi \cdot \frac{3}{4},\\\\\ell_{arc}=\boxed{18\pi\text{ m}}[/tex]

Question 2:

In the circle shown, the radius is marked as 2 miles. Substituting [tex]r=2[/tex] into our circumference formula, we get:

[tex]C=2(\pi)(2),\\C=\boxed{4\pi\text{ mi}}[/tex]

The measure of the central angle of the bolded arc is 135 degrees. Its length must then be:

[tex]\ell_{arc}=4\pi \cdot \frac{135}{360},\\\ell_{arc}=1.5\pi=\boxed{\frac{3\pi}{2}\text{ mi}}[/tex]

The value of COS Cx sin A by the given data is V3/4.

Trigonometric identities are the functions that include trigonometric functions such as sine, cosine, tangents, secant, and, cot.

Trigonometric ratio can be defined in terms of ratios of perpendicular, bases and hypotenuse. These are defined only in right angled triangles (triangles whose one angle is of 90 degree measure).

We are given that;

AB = 1, AC = 2 and BC = V3

Now,

To find the value of cos C x sin A, we need to use the trigonometric ratios of the right triangle.

We know that cos C = adjacent/hypotenuse = AB/AC = 1/2 and sin A = opposite/hypotenuse = BC/AC = V3/2.

cos C x sin A = (1/2) x (V3/2) = V3/4.

Therefore, by the trigonometric ratio the answer will be V3/4.

Learn more about trigonometric ratios;

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Answer:

i can help you i know this answer

Answer:

5 up and 2 to the right

Step-by-step explanation:

The center will be at the same spot as circle D, dilate by 3, then the dilation maps circle C into circle D.

Answer: 1:3

Step-by-step explanation:

The odds are 2/6 because you’re given 2 choices from the 6 side die you can then simplify that fraction to 1:3

Answer:

Hello,

answer B

2

Step-by-step explanation:

[tex]\dfrac{2}{x} -\dfrac{x}{x+5} =\dfrac{10}{x^2+5x} \\\\we\ suppose\ x\neq 0\ and\ x\neq -5\\\\\text{Reducing to the same denominator}\\\dfrac{2(x+5)-x^2}{x(x+5)} =\dfrac{10}{x^2+5x} \\\\Simplify\ by\ x^2+5x\\\\2x+10-x^2=10\\\\-x^2+2x=0\\\\-x(x-2)=0\\\\roots\ are\ 2 \ and\ 0\ (to\ be\ excluded)\\\\Root=2\\[/tex]

Answer:

d talking into microphone

The answer is

w + c ≤ 32

w < 11

w - the number of acres of wheat

c - the number of acres of corn

Johanna will plant up to 32 acres on her farm with wheat and corn:

w + c ≤ 32

Fewer than 11 acres will be planted with wheat:

w < 11

The two inequalities are:

w + c ≤ 32

w < 11

Answer:

The Tasty Beans Coffee House being planned for the corner of SE 12th and Main will ruin a perfectly nice neighborhood. Besides the fact that Tasty Beans already has coffee shops all over the city, it will pull business away from local coffee houses that have been here for decades. In addition, there is already a parking problem on that street, and the new business will just add to the congestion. They're planning a drive-up window, too, and that will mean a steady stream of traffic in a very high-volume area. Ask anyone walking down the street, and they'll tell you this is a bad idea. I speak for my whole neighborhood when I say, "Go away, Tasty Beans!"

Step-by-step explanation:

Answer:

siis  corretoed

Step-by-step explanation:

Answer:

$14722.14

Step-by-step explanation:

We are given that

In 2015

The value of jewel=$17500

Rate of appreciation, r=2.5%

We have to find the initial value of the jewel when it was first bought.

Time, n=7 years

Final value=[tex]Initial\;value (r/100+1)^n[/tex]

Using the formula

[tex]17500=Initial\;value(2.5/100+1)^7[/tex]

[tex]17500=Initial\;value(1.025)^7[/tex]

[tex]Initial\;value=\frac{17500}{(1.025)^7}[/tex]

Initial value=$14722.14

Hence, the the initial value of the jewel when it was first bought=$14722.14

Answer:

-23/9  or -2 5/9

Step-by-step explanation:

w+(-x) - 2/3

Let w = -5/9  and x = 4/3

-5/9+(- 4/3) - 2/3

Get a common denominator of 9

-5/9 - 4/3 *3/3 - 2/3 *3/3

-5/9 - 12/9 - 6/9

-23/9

-2 5/9

Answer:

-2 5/9

Step-by-step explanation:

Answer:

119?

Step-by-step explanation:

Answer:

32 = <4

Step-by-step explanation:

The exterior angle of a  triangle is equal to the sum of the opposite interior angles

15+17 = <4

32 = <4

Answer:

17 lb I guess 8 don't think the question is full

Step-by-step explanation:

the question is half

Answer:

56

Step-by-step explanation:

that is the procedure above

The missing segment in the image below is 8.

The missing segment is the side length of the small triangle that is formed by the two red lines and the green line. We can find the length of this side length by using the Pythagorean Theorem.

The Pythagorean Theorem states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. In this case, the hypotenuse is the missing segment, and the other two sides are 4 and 5.

missing [tex]segment^2[/tex] = [tex]4^2[/tex] + [tex]5^2[/tex]

missing [tex]segment^2[/tex] = 16 + 25

missing [tex]segment^2[/tex] = 41

missing segment = √41

Therefore, the missing segment is √41.

Here are the steps in detail:

Identify the small triangle that is formed by the two red lines and the green line.

Label the sides of the triangle with the letters A, B, and C, where C is the missing segment.

Substitute the known side lengths into the Pythagorean Theorem.

Solve for the length of the missing segment.

To learn more about segment here:

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Answer:

61

Step-by-step explanation:

45/3 = 15

2*8 = 16

15+16-12+42 = 61

Answer:

15 + 16 + 30

and that is in total 61

Step-by-step explanation:

45/3 = 15

2×8 = 16

-12 + 42 = 30

you simplify an expression by calculating the part expressions, to be left only with the main terms and main operations.

Answer:

Step-by-step explanation:

This is quite a doozy, my friend. We will set up a d = rt table, fill it in...and pray.

The table will look like this before we even fill anything in:

            d        =        r        *        t

SUV

sedan

Ok now we start to pick apart the problem. Motion problems are the hardest of all story problems ever. This is because there are about 100 ways a motion problem can be presented. So far what we KNOW for an indisputable fact is that the distance from Georgetown to Greenville is 120 km. So we fill that in, making the table:

             d      =      r      *      t

SUV     120

sedan  120

The next part is derived from the sentence "After an hour, the SUV was 24 km ahead of the sedan." This tells us the rate of the SUV in terms of the sedan. If the SUV is 24 km ahead of the sedan in 1 hour, that tells us that the rate of the sedan is r and the rate of the SUV is r + 24 km/hr. BUT we have other times in this problem, one of them being 25 minutes. We have a problem here because the times either have to be in hours or minutes, but not both. So we will change that rate to km/min. Doing that:

24 [tex]\frac{km}{hr}[/tex] × [tex]\frac{1hr}{60min}=.4\frac{km}{min}[/tex] So now we can fill in the rates in the table:

            d      =      r      *      t

SUV    120    =   r + .4

sedan 120    =     r

They left at the same time, so now the table looks like this:

             d      =      r      *      t

SUV    120     =   r + .4  *      t

sedan  120    =      r      *      t

We will put in the time difference of 25 minutes in just a sec.

If d = rt, then the equation for each row is as follows:

SUV:   120 = (r + .4)t

sedan:   120 = rt

Since the times are the same (because they left at the same time, we will set the equations each equal to t. The distances are the same, too, I know that, but if we set the distances equal to each other and then solve the equations for a variable, the distances cancel each other out, leaving us with nowhere to go. Trust me, I tried that first! Didn't work.

Solving the first equation for time:

sedan:  [tex]\frac{120}{r}=t[/tex]  That's the easy one. Now the SUV. This is where that time difference of 25 minutes comes in from the last sentence. Let's think about what that sentence means in terms of the times of each of these vehicles. If the sedan arrived 25 minutes after the SUV, then the sedan was driving 25 minutes longer; conversely, if the sedan arrived 25 minutes after the SUV, then the SUV was driving 25 minutes less than the sedan. The latter explanation is the one I used in the equation. Again, if the SUV was driving 25 minutes less than the sedan, and the equations are solved for time, then the equation for the SUV in terms of time is

[tex]\frac{120}{r+.4}=t-25[/tex] and we solve that for t:

[tex]\frac{120}{r+.4}+25=t[/tex]

Again, going off the fact that times they both leave are the same, we set the equations equal to one another and solve for r:

[tex]\frac{120}{r+.4}+25=\frac{120}{r}[/tex]

I began by first multiplying everything through by (r + .4) to get rid of it in the denominator. Doing that:

[tex][r+.4](\frac{120}{r+.4}) +[r+.4](25)=[r+.4](\frac{120}{r})[/tex] which simplifies very nicely to

[tex]120+25(r+.4)=\frac{120}{r}(r+.4)[/tex]  So maybe it's not so nice. Let's keep going:

[tex]120+25r+10=\frac{120r}{r}+\frac{48}{r}[/tex] and keep going some more:

[tex]130+25r=120+\frac{48}{r}[/tex] and now we multiply everything through by r to get rid of THAT denominator:

[tex]r(130)+r(25r)=r(120)+r(\frac{48}{r})[/tex] giving us:

[tex]130r+25r^2=120r+48[/tex] Now we have a second degree polynomial we have to solve by factoring. Get everything on one side and factor using the quadratic formula.

[tex]25r^2+10r-48=0[/tex]

That factors to

r = 1.2 and r = -1.6 and both of those rates are in km/minute. First of all, we cannot have a negative rate (this is not physics where we are dealing with velocity which CAN be negative) so we throw out the -1.6 and convert the rate of 1.2 km/minute back to km/hr:

[tex]1.2\frac{km}{min}[/tex] × [tex]\frac{60min}{1hr}[/tex] and we get

r = 72 km/h, choice B.

Wow...what a pain THAT was, right?!

Answer:

...-243, 729, -2187

Step-by-step explanation:

-3, 9, -27, 81, -243, 729, -2187

Everytime ×(-3)

-3×(-3)=9

9×(-3)=-27

-27×(-3)=81

Etc.