If you are aware of the separation between nodes and antinodes, the string (or pipe) length, and the harmonic that is present.
What is harmonic?
A harmonic wave, such as a sinusoidal wave, has a frequency that is an integer multiple of the fundamental frequency, or the frequency of the initial periodic signal. The first harmonic of the original signal is also referred to as that; higher harmonics are the other harmonics.
Use this equation if you know the separation between nodes and antinodes:
2
λ \s \s =D
D stands for the separation between adjacent nodes or antinodes.
Also
The formula v = f gives the wavelength. Since the frequency is fixed, the only way to alter the wavelength of the waves is to alter their speed.
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if an object producing sound is moving away from you, you would observe a wavelength than an object moving toward you. group of answer choices
If an object producing sound is moving away from us, the wavelength of the sound heard is longer than the actual wavelength. The conclusion is from the concept of Doppler effect.
What is the Doppler effect?The Doppler's effect is a phenomenon when the source of a wave and an observer move relative to each other, the frequency heard is not the same with the actual frequency.
The equation of the Doppler effect is
f₀ = [(v ± v₀)/(v ± vs)] × fs
Where
f₀ = observer frequency of soundv = speed of sound waves (340 m/s)v₀ = observer velocityvs = source velocityfs = actual frequency of sound wavesNote:
v₀ (+) if the observer moves closer to the sound source.vs (+) if the sound source moves away from the observer.When an object producing sound is moving away from us, the frequency of the sound we heard changed.
Let's say we are at rest, it means v₀ = 0. The sound source is moving away makes vs (+).
With the Doppler's effect, we get
f₀ = [(v+0) / (v+vs)] × fs
f₀/fs = v/(v+vs)
v < v+vs
f₀ < fs
The frequency of sound we heard is lower that the actual frequency.
The wavelength is inversely proportional to the frequency. It is described in the equation:
λ = c/f
It means that the lower the frequency, the longer the wavelength.
Hence, the phenomenon which the wavelength of the sound we heard is longer than the actual wavelength when the sound source is moving away from us is called the Doppler's effect.
Here is the group of answer choices:
(a) Band width
(b) Doppler's effect
(c) Sound refraction
(d) Vibrations
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programmable array logic (pal) has fixed or and programmable and array gates.group of answer choicestruefalse
Programmable Array Logic (PAL) has a programmable AND array and a fixed OR array.
Programmable Array Logic (PAL) is a logic device.
It is used to implement a logical function.It is an easy to use device because only AND gates are programmable, but it has a limited programming for AND gate.A PAL consists of a small programmable read-only memory (PROM) and additional output logic used to implement the specific logic function required with limited components.In PAL, a programmable AND gate is followed by a fixed OR gate.A typical PAL IC may have eight inputs, eight outputs, and eight sections, each consisting of eight wide AND-OR arrays.Hence PAL has programmable AND array and a fixed OR array.
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Suppose we observe a Cepheid variable in a distant galaxy. The Cepheid brightens and dims with a regular period of about 10 days. What can we learn from this observation?We can learn the distance to the galaxy.
We can find out how far away the galaxy is. By comparing the actual luminosity with the expected luminosity, which is affected by the inverse square law of light traveling through the great expanses of space.
How can the distance of Cepheid variables be determined from observations of those variables?
Astronomers have measured the distances to distant galaxies by observing Cepheid variables. They compare the apparent brightness with the intrinsic brightness of the Cepheid variable. The distance can be determined by comparing the observed and actual brightness.
How far can we measure in space using Cepheid variables?
Unlike Earth-based parallax measurements, which can only be made up to a maximum of 65 light years, cepheid variables can be observed and measured out to a distance of around 20 million light years.
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A small box of mass m is kicked up an inclined plane with an initial velocity v, and slides up the incline a distance L before it stops. The inclined plane makes an angle a with the horizontal, and the friction coefficient is u. What is the distance L the box slides up the ramp before it stops? (Hint: The known quantities are the mass, the initial speed, the angle, the coefficient of friction, and the acceleration of gravity:{m, Vo, a,u,9). Solve for the distance L in terms of these quantities.)
Main Answer:
The distance of L is [tex]v^{2} /2g(sin\alpha +ucos\alpha )[/tex]
Explanation:
if the block will slide a distance 'L' then syoped;
The initial velocity given to the block is V m/s
So, Total K.E given will goes to gain in potential energy and work done by friction .
K.E=1/2mv^2
P.E at hight (Lsin[tex]\alpha[/tex]) will be = mgh
And work done by the Friction Force is given as = w.r = force*displacement= - uNL= -uMgGcos[tex]\alpha[/tex]L
so,
KE+WD by friction = gain in P.E
[tex]1/2mv^{2} +(-uMgGcos\alpha L)=MgLsin\alpha \\1/2V^{2} =glsin\alpha +uglcso\alpha \\v^{2} /2= Gl(sin\alpha +ucos\alpha )[/tex]
Hence by solving we get :
[tex]v^{2} /2g(sin\alpha +ucos\alpha )[/tex]=L
So the distance = L
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short 10g rope is used to pull a 50g toy across a horizontal surface without friction. if a force of 3.0 x 10 -2 n is applied horizontally to the free
0.025 N the force of the string on the toy, at the other end of the rope.
What is friction?Friction is a force that resists the relative motion of two objects that are in contact with each other. It is caused by the interaction of the surfaces of the two objects and the molecules that make them up. Friction can be either static or kinetic. Static friction occurs when the two surfaces are not moving relative to each other, while kinetic friction occurs when the two surfaces are moving relative to each other. Friction is a type of force that can be both beneficial and detrimental.
Mass of the string (m) = 10 grams or 10⁻² kg
Mass of the toy (M) = 50 g or 5 x10⁻² kg
Mass of the system = M + m
= 10⁻² + 5 x 10⁻²
= 6 x 10⁻² kg
Force applied (F) = 3.0 x 10⁻² N
Acceleration of toy + string = (0.03/6) x 10⁻²
= 0.5m/s²
Thus force on the toy = 5 x10⁻² x 0.5
= 0.025 N
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The complete question is as follows:
A short 10g string is used to pull a 50g toy across a frictionless horizontal surface. if a 0.03N force is applied horizontally to the free end, the force of the string on the toy, at the other end, is:
a 5 kg block is suspended from the pulley system as shown. pulley a has a mass of 15 kg, a radius of 103 mm, and radius of gyration of 77 mm. pulley b has a mass of 3 kg, a radius of 32 mm, and a radius of gyration of 31 mm. determine the speed of the block after it has decended 3 meters. give your answer rounded to 2 decimal places.
The speed of the block after it has descended is 3 meters is 3.54 m/s.
To determine the speed of the block after it has descended 3 meters, we need to consider the energy conservation principle. The initial potential energy of the block is equal to the final kinetic energy of the block plus the work done on the block by the pulleys.
The initial potential energy of the block is given by:
U = mgh
where m is the mass of the block, g is the acceleration due to gravity, and h is the height of the block.
The final kinetic energy of the block is given by:
K = (1/2) × m × v²
where m is the mass of the block and v is the velocity of the block.
The work done on the block by the pulleys is given by:
W = F × d
where F is the force exerted on the block by the pulleys and d is the distance traveled by the block.
The force exerted on the block by the pulleys is equal to the tension in the rope. The tension in the rope can be calculated using the following formula:
T = (m × g) / (1 + (Ia/Ib))
where T is the tension in the rope, m is the mass of the block, g is the acceleration due to gravity, Ia is the moment of inertia of pulley A, and Ib.
where I is the moment of inertia, m is the mass of the pulley, and r is the radius of the pulley.
Substituting the given values into the formulas above, we get:
U = 5 × 9.81 × 3 = 146.1 J.
Ia = (1/2) × 15 × (77)² = 70,245 [tex]mm^4[/tex]
Ib = (1/2) × 3 × (31)² = 2,871 [tex]mm^4[/tex]
T = (5 × 9.81) / (1 + (70,245/2,871)) = 33.4 N
W = T × 3 = 100.2 J
K = (1/2) × 5 × v²
Substituting the values for U, W, and K into the energy conservation equation, we get:
146.1 J = 100.2 J + (1/2) × 5 × v²
v² = (146.1 J - 100.2 J) / (1/2) × 5
v² = 45.9 J / 2.5
v = √(45.9 J / 2.5) = 3.54 m/s
Therefore, the speed of the block after it has descended 3 meters is approximately 3.54 m/s, rounded to two decimal places.
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A 2.2-mm-diameter and 10-m-long electric wire is tightly wrapped with a 1-mm-thick plastic cover whose thermal conductivity is k = 0.15 W/m.K. Electrical measurements indicate that a current of 13 A passes through the wire and there is a voltage drop of 8 V along the wire. If the insulated wire is exposed to a medium at T = 30°C with a heat transfer coefficient of h = 24 W/m2.K, determine (a) the temperature (in °C) at the interface of the wire and the plastic cover in steady operation. Electrical wire To = 30°C Insulation 10 m (c). Continue the previous questions. Determine if doubling the thickness of the plastic cover will increase or decrease this interface temperature. will increase interface temperature because of heat transfer from interface decrease will decrease interface temperature because of heat transfer towards interface decrease will decrease interface temperature because of heat transfer from interface increase will increase interface temperature because of heat transfer towards interface increase will have no effect on interface temperature
Doubling the thickness of the plastic cover increases the rate of heat loss and decreases the interface temperature.
Given:
The diameter of the electric wire t=1mm
The diameter of plastic cover ro=1+1.1=2.1
Internal conductivity of plastic cover k=0.15w/MK
the current passed through circle I=13A
voltage drop v=8v
temperature T=30c
Heat transfer fluid h=24w/m^2k
Let To be the temperature of the wire and T1 is the temperature of the plastic cover.
the heat generated Q=>v*I=13*8=104 watt
Now the heat generated is connected and converted through wire
Q= To-T1/ln(ro/rc)/2pi*KL+1/hAo
104=To-30/ln(2.2/1.1)/2pi*0.15*10+1/24*20*0.00021*16
104=To-30/0.38439
To=69.9768c
To=70c
The temperature at the Interface of the wire is 70c
Now, the heat generated is connected to the wire
Q=To-T1/ln(ro/rc)/2piKL
104=70-T1/ln(2.1/1.1)/2pi*0.15*10
7.13536=10-T1
T1=6.2864c
The critical radius of Isolation:
rc=k/h=0.5/24
rc=6.25*10^-3m
rc=6.25mm
Now the thickness of isolation is increased to double
ro=1.1+2=3.1mm
Now,rc>ro ie critical radius of isolation is greater than the outer radius of the circle.
∴doubling the thickness of the plastic cover increases the rate of heat loss and decreases the interface temperature.
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During the collision, the car and truck exert forces on each other. Which of the following is a correct statement about these forces and gives evidence to support this statement? The forces the truck and car exert on each other must be external to the truck-car system because the momentum of the truck changes. B The forces the truck and car exert on each other must be external to the truck-car system because the momentum of the car changes. С The forces the truck and car exert on each other must be external to the truck-car system because the momentum of both the truck and car change. D The forces the truck and car exert on each other must be internal to the truck-car system because the momentum of the center of mass of the truck-car system stays the same E The forces the truck and car exert on each other must be internal to the truck-car system because the momentum of the center of mass of the truck-car system changes.
The forces the truck and car exert on each other must be internal to the truck-car system because the momentum of the center of mass of the truck-car system stays the same. Option D
What is the Collison?We know that it is possible for an object to be able to bump into another object when this occurs, we would have to apply the law of the conservation of linear momentum. Recall that from the law of the conservation of linear momentum, momentum before collision is equal to the momentum after collision.
We would also have to consider the fact that the weight of the truck is much lager than the weight of the car. The forces that the two vehicles would exert on each other can not be the same. It is clear that the truck is going to exert more force than the car.
With that said, we must have in mind that the total momentum of the system does not change because we are going to approximate the system to function as a closed system.
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if your answer is a vector, give answer in the form ai bj ck with no spaces between symbols.if your answer is a scalar, then give your scalar answer.
scalar, any physical quantity whose magnitude serves as its sole description.Volume, density, velocity, energy, weight, and time are a few examples of scalars.Other quantities, like as velocity and force are referred to as vectors since they have both direction and magnitude.
How can you recognize a scalar?While vector quantities have had both magnitude and direction, scalar values simply have magnitude.Time is a scalar that is entirely independent of direction.It lacks direction and just possesses magnitude.Acceleration, displacement, and force all happen in a specific direction.
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how does the final temperature of the gas compare with its initial temperature? express your answer using two significant figures. tcta
Step 1: Calculate the ratio of the final and beginning temperatures using the ideal gas law solved for temperature.
Step 2: Calculate the ratio after eliminating any constant values.
Step 3:Solve for the final temperature after substituting the beginning temperature into the ratio.
Perfect Gas Law: According to the ideal gas law, a gas's pressure, P, is inversely proportional to its volume, V, temperature, T, and the number of moles it contains, n, in the sample. The equivalent statement is: For these issues, we'll use the ratio of two temperatures. Because the ratio of starting to end volume and pressure will be the same regardless of the units used to express them, the volume and pressure can be expressed in any form. exhibited in (as long as the initial and final of each are expressed in the same units).PV= nRT
However, for this method to work properly, the temperature must be stated in Kelvin. This is true because Kelvin's zero point is absolute zero. Theoretically, molecules are entirely immobile at 0 Kelvin.
T = PV/nR
The ideal gas law equivalency is used to compute the final temperature in the next two issues.
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The top of a 240 foot vertical tower is to be anchored by cables that make an angle with a measure of 54 degrees with the ground. How long must each cable be? ___ feet
How far from the base of the tower should the anchors be placed? ___ feet
Each cable must be 300 feet long and the base must be at 179 feet.
The vertical tower, cables and distance between ground and tower will form a right angled triangle. So, we will use Pythagoras theorem to find the length of each cable and base.
sin 54 = height of vertical tower ÷ length of cables
sin 54 = 240 ÷ length
Length = 240/sin 54
Length = 240/0.8
Length = 300 foot
tan 54 = height of vertical tower ÷ distance of base of tower
Distance = 240/tan 54
Distance = 240/1.38
Distance = 173.9 foot
Hence, length should be 300 foot and distance should be 173.9 foot.
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The table lists the kinetic energy of a 4.0 kilogram mass as it travels in a straight line for 12.0 seconds.
Time
(seconds) Kinetic Energy
(joules)
0.0 0.0
2.0 8.0
4.0 18
6.0 32
10.0 32
12.0 32
Calculate the speed of the mass at 10.0 seconds.
m/s
So the speed of object of mass 4 Kg and kinetic energy of 32 j at 10 second is 4 m/s.
What is kinetic energy?Kinetic energy is the energy that an object has when it moves or changes its position. As long as an object is moving at the same speed, it maintains the same kinetic energy.
The kinetic energy of an object is calculated from the object's velocity and mass. As can be seen from the equation below, velocity is quadratic and can have a large effect on kinetic energy.
KE = ¹/₂ mv²
v = √(2KE/m)
Where, v = velocity
M = Mass of object (4.0 Kg)
KE = Kinetic energy (32 j)
v = √(2 × 32/4)
v = √16
v = 4 m/s
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When the turntable is turned on and rotates at 45.0 rev/min, calculate the centripetal force needed to keep the fly from slipping?
The centripetal force needed to keep the fly from sleeping will be zero point 0.00176 Newton in magnitude.
The mass of the fly is 2 gram and it is selling itself on a phonograph turntable.
The fly is at a distance of 4 cm away from the center of the phonograph turntable and when the turntable is turned on and retreats with 45 Revolution per minute the centripetal force that would be working on the fly will be given by,
F = Mw²R
Where,
M is mass of the fly,
w is the angular speed of the fly and,
R is the radius of the turnable.
Putting all the values,
F = 0.002×(4.7)²×0.04
F = 0.00176N.
So, a centripetal force of magnitude 0.00176 Newton will be required in order to keep the fly from slipping.
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Complete question- A fly of mass 2.00 g is sunning itself on a phonograph turntable at a location that is 4.00 cm from the center. When the turntable is turned on and rotates at 45.0 rev/min, calculate the centripetal force needed to keep the fly from slipping?
two objects of unequal masses, m and m (m > m), are connected by a very light cord passing over an ideal pulley of negligible mass. when released, the system accelerates, and friction is negligible.
M will experience a net downward force, which will cause it to accelerate downhill, while M will experience a net upward force, which will cause it to accelerate upward.
As the same string is attached to both the blocks, it applies the same upward force = tension in the string.
Hence the length of the upward arrows should be the same.
Secondly, the weight of m is lesser than M. Hence, the arrow below m will be smaller than that below M.
This also means that the net force on M will be downwards, and hence, it will accelerate downwards and that on m will be upwards and hence it will accelerate upwards.
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which of the following sequences lists methods for determining distance in the correct order from nearest to farthest?
Parallax, main-sequence fitting, cepheid variables, Tully-Fisher relation, and Hubble's law are the sequence lists methods for determining distance.
Parallax is the closest method for determining distance. This method uses the principle of triangulation to measure the distance of a nearby star relative to Earth. Main-sequence fitting is another method used to measure the distance of stars. This method compares the brightness of a star to other stars of known distance and luminosity to determine its distance.
Cepheid variables are stars whose brightness varies in a predictable way over time. This method uses the period of the star's brightness to determine its intrinsic luminosity, and then its distance. The Tully-Fisher relation is a method for measuring the distance of galaxies. This method uses the rotation speed of the galaxy and its brightness to calculate its distance.
Finally, Hubble's law is the most distant method for determining distance. This law states that the farther away a galaxy is, the faster it moves away from us. This allows us to calculate the distance of galaxies by measuring their rate of recession.
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An object of mass m is launched from planet of mass and radius R. E v 50 % Part (a) Derive and enter an expression for the minimum launch spced needed for the object to escape gravity, i.. to be able to just reach v=M(2GMR ) Correct_ 50 % Part (b) Calculate this minimum launch speed (called the escape speed) , in meters per second for a planet of mass M = 7 x 1024kg and R = 82 102 km_ Grad Summart v( 2 * 6.67 10-11 * 7 * 1024/( 82 10- Dcducuons Porentual 985
An expression for the minimum launch speed needed for the object to escape gravity, i.. to be able to just reach v=M(2GMR ) The minimum launch speed is V = 0.08 × 10¹¹ J.
A property of a body that is a measure of inertia is usually viewed as a measure of the amount of matter contained in the body that causes it to have weight in a gravitational field. Mass is a dimensionless quantity that describes the amount of matter in a particle or object.
Calculation:-
minimum launch speed
M = 7 x 1024kg
R = 82 102
v=M(2GMR )
v = 2 * 6.67 10-11 * 7 * 1024
v = 0.08 × 10¹¹ J.
The mass of an object is a measure of its inertial properties or the amount of matter it contains. The weight of an object is a measure of the force exerted on it by gravity, or the force required to support it. Mass can best be understood as the amount of matter present in an object or body. Everything around us has mass.
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In the figure, a climber leans out against a vertical ice wall that has negligible friction. Distance a is 0.945 m and distance L is 1.95 m. His center of mass is distance d = 0.89 m from the feet-ground contact point. If he is on the verge of sliding, what is the coefficient of static friction between feet and ground?
The coefficient of static friction between feet and ground is 0.2522.
What is static friction?Static friction is defined as when there is no motion between the two surfaces, the force that one surface applies to another. The friction that exists between two or more objects when they are not moving relative to one another is referred to as static friction.
The coefficient of static friction between his feet and the ground, denoted by the symbol s, determines how to express the frictional force as
fs =μsFN1
The μs can be calculated as
μs = a / √L² - a² x d / L
μs = 0.945 / √(1.95)² - (0.945)² x 0.89 / 1.95
μs = 0.945 / √2.91225 x 0.89 / 1.95
μs = 0.2522
Thus, the coefficient of static friction between feet and ground is 0.2522.
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Calibration of a bomb calorimeter is performed with: Select the correct answer below: a. a specific volume of water b. a specific mass of copper c. a reaction with known.
d. manually entered data
A reaction with a known q, such as a measured amount of benzoic acid ignited by a spark from a nickel fuse wire that is weighed before and after the reaction, is used to calibrate bomb calorimeters.
How is a bomb calorimeter calibrated?By releasing a known amount of thermal energy through an electric heater and measuring the subsequent rise in temperature, the calorimeter is calibrated. The energy released when a certain amount (for example, 1 mol, 1 g, or 1 L) of a substance burns entirely in oxygen is known as the heat of combustion.
What type of fuel is the reference fuel for bomb calorimeter calibration?A typical standard used in Bomb calorimeters, which keep a constant volume, is benzoic acid. If. Burning 1.2 g of benzoic acid at a temperature of 24 degrees, with excess oxygen present, releases 31.723 J of energy.
What does calorimeter calibration entail?When calibrating CALORIMETERS, a known electric current is frequently generated inside of them, and the measuring device is then watched for deflection while the system is in a steady condition. Heat loss along the leads through which the calibrating current is injected could be a drawback for this procedure.
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A wire loop, 2 meters by 4 meters, of negligible resistance is in the plane of the page with its left end in a uniform 0.5-tesla magnetic field directed into the page, as shown above. A 5-ohm resistor is connected between points X and Y. The field is zero outside the region enclosed by the dashed lines.
If wire loop is being pulled to the right with a constant velocity of 3 meters per second , then the potential difference induced between points X and Y is 3V .
it is given that a 5Ω resistor is connected between points X and Y ;
the magnetic field (B) = 0.5 ;
length of wire (l) [tex]=[/tex] 2 ;
velocity of the wire loop (v) = 3 m/s ;
the potential difference will be induced because charge separation on the vertical hand wire of wire loop.
Points X and Y are the same as the top and bottom of left wire.
The EMF(potential difference) induced in wire is given by
EMF = B*l*v
substituting the values ,
we get
= (0.5)(2)(3) = 3V
Therefore , the induced potential difference between points X and Y is 3V .
The given question is incomplete , the complete question is
A wire loop, 2 meters by 4 meters, of negligible resistance is in the plane of the page with its left end in a uniform 0.5-tesla magnetic field directed into the page. A 5-ohm resistor is connected between points X and Y. The field is zero outside the region enclosed by the dashed lines. The loop is being pulled to the right with a constant velocity of 3 meters per second. Make all determinations for the time that the left end of the loop is still in the field, and points X and Y are not in the field.
Determine the potential difference induced between points X and Y.
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A 2.0-m-long string vibrates at its second-harmonic frequency with a maximum amplitude of 2.0 cm. One end of the string is at x = 0 cm. Find the oscillation amplitude at x = 10, 20, 30, 40, and 50 cm.
At x = 10, 20, 30, 40, & 50 cm, the oscillation's amplitude is 8.83 mm.The length of time required for a motion to complete one cycle.
How do you define oscillatory amplitude?The greatest deviation from the mean position is the magnitude of oscillation for a body that oscillates. It is the length between peak or trough of the wave and its mean position. The loudness of a sound will increase with increasing sound wave amplitude.
In an oscillating pendulum, what is amplitude?Amplitude: The distance between the motion's center and either extremity. Period: The length of time required for a motion to complete one cycle.
A(x)=A(max)sin(2pix/L)
A(x)=0.015sin(2pix/2)
A(x) =0.015sin (pix)
where x=20cm = 0.2m
A(x)=0.015sin(pi*0.2)
8.83 mm or A(x)=8,82*10-3 m
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Matt Calvani hits a golf ball with an initial velocity of 88m/s at an angle of 10° with the ground.
(a) Find the total flight time of the golf ball.
(b) Find the range of the golf ball
(c) Find the speed of the golf ball at the instant before it hits the ground
Bonus +3) Find the maximum height above the ground that the ball reaches
A golfer travels 80 meters horizontally when striking the ball. The ball took 1.8 seconds to go through the air. Using a 10° angle with the ground or an initial velocity exceeding 88m/s, Matt Calvani smashes a golf ball.
What is an easy way to define velocity?A particle or object's displacement with regards to time is expressed vectorially as velocity. The meter per second (m/s), also referred to as speed, is the accepted unit of velocity magnitude.
What do you call 0 velocity?From the pickup location to the destination, passenger cars are driving. uniform constant velocity motion The term "zero uniform velocity motion" refers to uniform motion with no acceleration. given that
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schedules of reinforcement farm workers are paid x amount of dollars for every basket of fruit that they pick
Schedules of reinforcement farm workers are paid x amount of dollars for every basket of fruit that they pick is based on the concept of fixed ratio.
A strengthening timetable, during which an answer or reaction is only strengthened after yet another given reaction can be determined, could be determined as a fixed ratio schedule. The particular topic gives a variety of questionnaires/solutions and therefore is subsequently rewarded by the educator or coach.
The man is under a fixed interval schedule of reinforcement, while the woman is under a fixed ratio schedule of reinforcement. Fixed interval reinforcement is a type of reinforcement that gives reward only after a specific period of time has passed. A fixed ratio reinforcement is a type of reinforcement that is based on production rate.
The other type is variable ratio. Variable Ratio schedule of reinforcement will give a person rewards after he/she fulfil a specific amount of works.
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A 2.0 kg mass attached to an ideal spring oscillates horizontally with an amplitude of 0.15 m.
N
The spring constant is 85
N/m.
What is the period of the mass’s motion?
Anything parallel to the horizon is called horizontal.
What is the period of the motion?The period of the object's motion is defined as the time for the object to complete one full cycle. Being a time, the period is measured in units such as seconds, milliseconds, days or even years. The standard metric unit for period is the second. An object in periodic motion can have a long period or a short period.Given that,The period of a spring-mass system is proportional to the square root of the mass and inversely proportional to the square root of the spring constant.“Period” is rooted in the Greek words “peri” and “hodos” (periodos) meaning “around” and “way/path.” This eventually turned into the Latin “periodus” meaning “recurring cycle.” Use of the English term “period” to describe menstruation began in the early 1800s (1).A mass m suspended by a wire of length L is a simple pendulum and undergoes simple harmonic motion for amplitudes less than about 15º. The period of a simple pendulum is T=2π√Lg T = 2 π L g , where L is the length of the string and g is the acceleration due to gravity.
The mass attached to the spring, m = 1.5 kg
The amplitude of the spring, A = 0.3 m
The spring constant of the spring, k = 85 N/m
We need to find the period of the mass's motion. The time period in spring mass system is given by :
[tex]T=2\pi \sqrt{\frac{M}{K} }[/tex]
[tex]T=2\pi \sqrt{} \frac{1.5}{85}[/tex]
[tex]T=0.83s[/tex]
So, the period of the mass's motion is 0.83 seconds.
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Answer: 0.96s
Explanation:
Khan
Two frequency generators are creating sounds of frequencies 460 and 471 Hz simultaneously. Randomized Variables f1 = 460 Hz f2 = 471 Hz Part (a) What average frequency will you hear in Hz?
The average frequency will be 465.5 Hz.
The frequency of light can be described as the number of waves passing through a point in a medium (or vacuum) per second.
It is measured in units of Hertz (Hz). Electromagnetic radiation propagates through space as a wave, and one type of radiation differs from another in the frequency of this wave. Electromagnetic radiation is categorized using the electromagnetic spectrum, which is usually organized by frequency.Frequency generated by generator 1 = f1 = 460 Hz
Frequency produced by generator 2 = f2 = 471 Hz
the average frequency will be (f1 + f2) / 2
f1 + f2 = 460 + 471
f1 + f2 = 931 Hz
Average frequency = A = 931/2
A = 465.5 Hz
The average frequency we hear will be 465.5 Hz.
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a long, straight, thin-walled cylindrical shell of radius r carries a current i. find the magnetic field outside the cylinder (r > r) and inside the cylinder (r < r).
The magnetic field inside the cylinder is zero and outside the cylinder is
B = μ₀ I/(2*π*r)
The circulation of the magnetic field along a circular path of radius, r , is given by:
⇒ B cosθ (2* π* r)
where, cos θ is 1 if the field forms circles. Now that the Amperian loop is closed, we may analyze the current inside of it. The net current that travels across the surface defined by the Amperian loop determines the enclosed current. The enclosed current is denoted by the letter I since the loop completely encloses the wire. Making use of Ampere's Law,
B cosθ (2* π* r) = μ₀ I
Since, the right-hand side of the equation is not zero at this moment, it is obvious that cos cannot be zero. As a result, we can draw the conclusion that, as we had previously predicted, the magnetic field must form concentric rings. The magnetic field's strength is determined by:
B = μ₀ I/(2*π*r)
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supply drop design proposal
compare the time it takes for light to travel 1000 m on the surface of the earth and in outer space.
Since light is faster in space, it takes less time for light to travel a distance of 1000m, a time difference of 0.977ns.
Light travels more slowly in a transparent medium than in the vacuum of empty space. The speed of light in any medium (air, water, glass) is determined by the refractive index of the medium. However, this exponent itself may be wavelength dependent (ie different colored rays travel at different speeds). In fact, this is why a prism splits white light into the colors of the rainbow.
The main reason that a light beam slows down in a medium has to do with the fact that the photons, or 'raw light beams', are excited by an electromagnetic field. When the field is in the ground state (vacuum), these excitations actually propagate at the vacuum speed of light. However, when there are positively charged atoms and negatively charged electrons, the electromagnetic field does not go to the ground state. There are many virtual photons. Yes, some of the photons of the passing light beam can be absorbed. After all, no material is completely transparent. But even those who aren't are moving in an environment so different from the vacuum that their paths will be different. It also depends on the structure that the molecule forms.
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The reynolds number is an important number in fluid mechanics. it is the ratio of the intertial forces to viscous forces. T/F
True. A Reynolds number is an important number in fluid mechanics. it is the ratio of the inertial forces to viscous forces.
The Reynolds number is a dimensionless quantity that is used to determine whether the flow pattern in a pipe is laminar or turbulent. The ratio of inertial forces to viscous forces defines the Reynolds number.
If the value of Nr is between 0 and 2000, the liquid flow is streamlined or laminar. The flow is turbulent above 4000, and the flow of the liquid is unstable between 2000 and 3000, alternating between the laminar and turbulent flow.
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The Sun's evolution from youngest to oldest stage is:
A) white dwarf, red giant, main-sequence, protostar
B) red giant, main-sequence, white dwarf, protostar
C) protostar, red giant, main-sequence, white dwarf
D) protostar, main-sequence, red giant, white dwarf
D) The Sun's evolution from youngest to the oldest stage is protostar, main-sequence, red giant, a white dwarf.
A protostar is the very beginning stage of a star's life. It is a cloud of gas and dust that starts to collapse due to its own gravitational pull. As it collapses, the gas and dust heat up, and eventually, nuclear fusion begins, creating a star.
The main-sequence stage is the longest and most stable period of a star's life. During this stage, the star is converting hydrogen into helium in its core, producing energy and light. This stage can last for billions of years.
Once a star has used up its hydrogen fuel, it enters the red giant phase. This is when the star expands, becoming much larger and much brighter. The star is now converting helium into other elements in its core, such as carbon and oxygen.
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For a particular nonlinear spring, the relationship betweem the magnitude of the applied force F and the resultant displacement x from equilibrium is given by the equation F = k x^2 What is the amount of work done by stretching the spring a distace x0? A) kx0^3 B) (1/2)kx0 C) (1/2)kx0^3 D) (1/3)kx0^2 E) (1/3)kx0^3
To get the work, you have to integrate the force as a function of [tex]$x$[/tex] from zero displacement to Xo
[tex](Integral of) $\mathrm{k} \mathrm{x}^{\wedge} 2 \mathrm{dx}$ from 0 to $\mathrm{Xo}_{\mathrm{o}}=(1 / 3) \mathrm{k}\left(\mathrm{Xo}^{\wedge}\right)^{\wedge} 3$[/tex]
The work done by stretching the spring to the given distance is [tex]W=\frac{k x_0}{3}[/tex]
The given parameters:
- Applied force on the spring [tex]$=F$[/tex]
- Extension of the spring [tex]$=x_0$[/tex]
The work done by stretching the spring to the given distance is calculated as follows;
[tex]W=\frac{k x_0}{3}[/tex]
[tex]$$\begin{aligned}& W=\int_{x_a}^{x_b} F d x \\& W=\int_{x_a}^{x_b} k x^2 d x \\& W=k \int_{x_a}^{x_b} x^2 d x \\& W=k\left[\frac{x^3}{3}\right] \\& W=k\left[\frac{x_b-x_a}{3}\right] \\& W=k\left[\frac{x_0-0}{3}\right] \\& W=\frac{k x_0}{3}\end{aligned}[/tex]
Thus, the work done by stretching the spring to the given distance is
[tex]W=\frac{k x_0}{3}[/tex]
measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement.
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