How many grams of H20 will be formed when 32.0 g H2 reacts with 16.0 g
O2? *
2H2 + O2 + 2H2O
9.00 g
16.0 g
18.0 g
32.0g

Answers

Answer 1

Answer:

18.0 g

Explanation:

M(H2) = 2.0 g/mol

32.0g * 1 mol/2 g= 16 mol H2

M(O2) = 32 g/mol

16.0 g * 1mol/32 g= 0.5 mol O2

                                      2H2 + O2 ---> 2H2O

from reaction              2 mol    1 mol

given                         16 mol     0.5 mol

We see that O2 is a limiting reactant.

                                    2H2 + O2 +-------> 2H2O

from reaction                         1 mol            2 mol

given                                      0.5 mol        x mol

x =(0.5*2)/1= 1 mol H2O

M(H2O)= 18 g/mol

18 g/mol* 1 mol = 18 g H2O


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MRCORRECT has answered the question

Explanation:

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So... for the element of ALUMINUM, you already know that the atomic number tells you the number of electrons. That means there are 13 electrons in a aluminum atom. you can see there are two electrons in shell one, eight in shell two, and three in shell three.

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So... for the element of NITROGEN, you already know that the atomic number tells you the number of electrons. That means there are 7 electrons in a nitrogen atom. Looking at the picture, you can see there are two electrons in shell one and five in shell two.

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Answers

Answer:

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Explanation:

Think about it this way: there are 4N's 4O's and 12H's and 10O's on both sides that's what makes it balanced

Hope this helps :)

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