helppp ASPPP plzz Select the correct answer.

9514 1404 393

Answer:

  f(7) = 154

Step-by-step explanation:

The basic idea is you put 7 where x is and do the arithmetic.

Polynomial evaluation is sometimes easier if you rewrite it to Horner form.

  f(x) = (4x -7)x +7

  f(7) = (4·7 -7)(7) +7 = 21(7) +7 = 147 +7

  f(7) = 154

Answer:

0

Step-by-step explanation:

-18-(-18)

= -18+18 [(+) + (+)=(+)]

=0 [(-) + (-)=(-)]

Answer:

A

Step-by-step explanation:

Given that the cones are similar then corresponding dimensions are in proportion, that is

[tex]\frac{12}{2}[/tex] = [tex]\frac{3}{x}[/tex] ( cross- multiply )

12x = 6 ( divide both sides by 12 )

x = 0.5 → A

Answer:

3

Step-by-step explanation:

3 - 3/x

----------------

1 - 1/x

Multiply the top and bottom by x

x(3 - 3/x)

----------------

x(1 - 1/x)

3x -3

------------

x-1

Factor the numerator

3(x-1)

-------

x-1

Cancel like terms

3

-----

1

3

Answer:

The p-value of the test is 0.2262 > 0.02, which means that the decision is to fail to reject the null hypothesis.

Step-by-step explanation:

An automobile manufacturer has given its jeep a 51.3 miles/gallon (MPG) rating.

At the null hypothesis, we test if the mean is of 51.3, that is:

[tex]H_0: \mu = 51.3[/tex]

An independent testing firm has been contracted to test the actual MPG for this jeep since it is believed that the jeep has an incorrect manufacturer's MPG rating.

This means that at the alternative hypothesis, we test if the mean is different of 51.3, that is:

[tex]H_0: \mu \neq 51.3[/tex]

The test statistic is:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.

51.3 is tested at the null hypothesis:

This means that [tex]\mu = 51.3[/tex]

After testing 230 jeeps, they found a mean MPG of 51.1. Assume the population variance is known to be 6.25.

This means that [tex]n = 230, X = 51.1, \sigma = \sqrt{6.25} = 2.5[/tex]

Value of the test statistic:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{51.1 - 51.3}{\frac{2.5}{\sqrt{230}}}[/tex]

[tex]z = -1.21[/tex]

P-value of the test and decision:

The p-value of the test is the probability of the sample mean differing from 51.1 by at least 0.2, which is P(|z| > 1.21), which is 2 multiplied by the p-value of z = -1.21.

Looking at the z-table, z = -1.21 has a p-value of 0.1131.

2*0.1131 = 0.2262

The p-value of the test is 0.2262 > 0.02, which means that the decision is to fail to reject the null hypothesis.

For this question, we need to simplify some radicals and combine like terms. One thing for sure that should be noticed is the fact that both of these radicals are going to be imaginary, as they both have negatives inside of them.

Let's simplify the radicals:

√-2 =                   ← Note the negative

i√2

√-18 =                  ← Note the negative here as well

i√18 =

i√2·3·3 =

i√2·3² =

3i√2

Now, all we have to do is combine like terms:

i√2 + 3i√2 = 4i√2

Answer:

(3 × 25)/5 marbles can go in each bag

Explanation:

Number of bags Regina has = 3

Number of marbles in each bag = 25

So, total number of marbles = 3 × 25

Number of marbles in each bag, if divided equally into 5 bags = (3 × 25)/5

Further:

Solving the expression,

(3 × 25)/5

= 75/5

= 15

So, the each bag has 15 marbles if they are equally divided into 5 bags.

Answer:

(25 x 3) / 5

Step-by-step explanation:

you have to do 25 x 3 to get the total amount of marbles. Then you have to divide that by the amount of bags.

Answer:

C

Step-by-step explanation:

r=1+2sin(theta)

r^2=r+2*r*sin(theta)

x^2+y^2=±sqrt(x^2+y^2)+2y

Answer:

0

2

-1

Step-by-step explanation:

from f(0) we find that

y = mx - 1

from f(-1) we find that the equation is

y = -3x - 1

1)

inverse f(x) :

x = -3y - 1

y = -(x + 1) / 3           x = -1

y = -(-1 + 1) / 3

y = 0

2)

y also equal to 0 since x = -1

3)

f^-1(2) = -(2+1) / 3

          = -3/3

          = -1

f(-1) =  2

Answer:

no solution to the question

Answer:

4 2/3

Step-by-step explanation:

The two-step equation is solved regularly. The answer is 4 2/3.

Answer:

a. 0.4129 = 41.29% of the bank's Visa cardholders pay more than 29 dollars in interest.

b. 0.1867 = 18.67% of the bank's Visa cardholders pay more than 35 dollars in interest.

c. 0.0742 = 7.42% of the bank's Visa cardholders pay less than 14 dollars in interest.

d. An interest payment of $35.2 is exceeded by only 18% of the bank's Visa cardholders.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 27 dollars and a standard deviation of 9 dollars.

This means that [tex]\mu = 27, \sigma = 9[/tex]

A. What proportion of the bank's Visa cardholders pay more than 29 dollars in interest?

This is 1 subtracted by the p-value of Z when X = 29, so:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{29 - 27}{9}[/tex]

[tex]Z = 0.22[/tex]

[tex]Z = 0.22[/tex] has a p-value of 0.5871.

1 - 0.5871 = 0.4129

0.4129 = 41.29% of the bank's Visa cardholders pay more than 29 dollars in interest.

B. What proportion of the bank's Visa cardholders pay more than 35 dollars in interest?

This is 1 subtracted by the p-value of Z when X = 35, so:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{35 - 27}{9}[/tex]

[tex]Z = 0.89[/tex]

[tex]Z = 0.89[/tex] has a p-value of 0.8133.

1 - 0.8133 = 0.1867

0.1867 = 18.67% of the bank's Visa cardholders pay more than 35 dollars in interest.

C. What proportion of the bank's Visa cardholders pay less than 14 dollars in interest?

This is the p-value of Z when X = 14. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{14 - 27}{9}[/tex]

[tex]Z = -1.445[/tex]

[tex]Z = -1.445[/tex] has a p-value of 0.0742.

0.0742 = 7.42% of the bank's Visa cardholders pay less than 14 dollars in interest.

D. What interest payment is exceeded by only 18% of the bank's Visa cardholders?

This is the 100 - 18 = 82nd percentile, which is X when Z has a p-value of 0.82, so X when Z = 0.915.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]0.915 = \frac{X - 27}{9}[/tex]

[tex]X - 27 = 0.915*9[/tex]

[tex]X = 35.2[/tex]

An interest payment of $35.2 is exceeded by only 18% of the bank's Visa cardholders.

Answer:

Step-by-step explanation:

3 times 8= 24 • 24 = 576 - 1 =575

or

3•8=24•2=48-1=47

not sure

Answer:

The answer is [tex]x=\frac{4(+-)\sqrt{19} }{3}[/tex] in exact form or [tex]x=2.7863[/tex], [tex]x=-0.1196[/tex] in decimal form.

Step-by-step explanation:

To solve this equation, start by moving all expression to the left side of the equation, which will include subtracting [tex]3x^2[/tex] and adding 1 to both sides of the equation. The equation will look like [tex]8x-3x^2+1=0[/tex].

Then, use the quadratic formula to find the solutions to the equation. The quadratic formula looks like [tex]\frac{-b(+-)\sqrt{b^2-4ac} }{2a}[/tex].

For this problem, the quadratic variables are as follows:

[tex]a=-3\\b=8\\c=1[/tex]

The next step is to substitute the values [tex]a=-3[/tex], [tex]b=8[/tex], and [tex]c=1[/tex] into the quadratic formula and solve for x. The quadratic formula will look like [tex]\frac{-8(+-)\sqrt{8^2-4(-3)(1)} }{2*-3}[/tex]. To simplify the equation, start by simplifying the numerator, which will look like [tex]x=\frac{-8(+-)2\sqrt{19} }{2*-3}[/tex]. Then, multiply 2 by -3 and simplify the equation, which will look like [tex]x=\frac{4(+-)\sqrt{19} }{3}[/tex]. The final answer is [tex]x=\frac{4(+-)\sqrt{19} }{3}[/tex] in exact form. In decimal form, the final answer is [tex]x=2.7863[/tex], [tex]x=-0.1196[/tex].

This value is approximate.

=============================================================

Explanation:

To find the perimeter, we simply add up the lengths of the three external sides.

The horizontal side from D to E is 16 units long since |-10-6| = 16. I subtracted the x coordinates of the points and applied absolute value. You could also count out the spaces and you should count 16 spaces from D to E.

Unfortunately, the diagonal lengths aren't as straight forward. We have two options here: The pythagorean theorem, or the distance formula.

I'll go with the distance formula.

Let's find the distance from C to D, aka the length of side CD

[tex]C = (x1,y1) = (-1,-2)\\\\D = (x2,y2) = (-10,0)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-1-(-10))^2 + (-2-0)^2}\\\\d = \sqrt{(-1+10)^2 + (-2-0)^2}\\\\d = \sqrt{(9)^2 + (-2)^2}\\\\d = \sqrt{81 + 4}\\\\d = \sqrt{85}\\\\d \approx 9.2195\\\\[/tex]

Side CD is roughly 9.2195 units long.

Repeat this idea to find the length of CE

[tex]C = (x1,y1) = (-1,-2)\\\\E = (x2,y2) = (6,0)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-1-6)^2 + (-2-0)^2}\\\\d = \sqrt{(-7)^2 + (-2)^2}\\\\d = \sqrt{49 + 4}\\\\d = \sqrt{53}\\\\d \approx 7.2801\\\\[/tex]

Side CE is roughly 7.2801 units long

The perimeter of triangle CDE is approximately...

P = DE+CD+CE

P = 16 + 9.2195 + 7.2801

P = 32.4996

This then rounds to 32.5 units. The answer is choice C.

Answer:

? = 5

Step-by-step explanation:

Recall: when 2 transversal lines cuts across 3 parallel lines, the parallel lines are divided proportionally by the transversals.

Therefore:

?/10 = 3/6

Cross multiply

?*6 = 3*10

?*6 = 30

Divide both sides by 6

? = 30/6

? = 5

Answer:

e = 44/5 = 8.800

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    e/22-(6/15)=0

Step by step solution :

STEP

1

:

           2

Simplify   —

           5

Equation at the end of step

1

:

  e    2

 —— -  —  = 0

 22    5

STEP

2

:

            e

Simplify   ——

           22

Equation at the end of step

2

:

  e    2

 —— -  —  = 0

 22    5

STEP

3

:

Calculating the Least Common Multiple :

3.1    Find the Least Common Multiple

     The left denominator is :       22

     The right denominator is :       5

       Number of times each prime factor

       appears in the factorization of:

Prime

Factor   Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

2 1 0 1

11 1 0 1

5 0 1 1

Product of all

Prime Factors  22 5 110

     Least Common Multiple:

     110

Calculating Multipliers :

3.2    Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M

   Denote the Left Multiplier by  Left_M

   Denote the Right Multiplier by  Right_M

   Denote the Left Deniminator by  L_Deno

   Denote the Right Multiplier by  R_Deno

  Left_M = L.C.M / L_Deno = 5

  Right_M = L.C.M / R_Deno = 22

Making Equivalent Fractions :

3.3      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      e • 5

  ——————————————————  =   —————

        L.C.M              110

  R. Mult. • R. Num.      2 • 22

  ——————————————————  =   ——————

        L.C.M              110  

Adding fractions that have a common denominator :

3.4       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

e • 5 - (2 • 22)     5e - 44

————————————————  =  ———————

      110              110  

Equation at the end of step

3

:

 5e - 44

 ———————  = 0

   110  

STEP

4

:

When a fraction equals zero :

4.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 5e-44

 ————— • 110 = 0 • 110

  110

Now, on the left hand side, the  110  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  5e-44  = 0

Solving a Single Variable Equation:

4.2      Solve  :    5e-44 = 0

Add  44  to both sides of the equation :

                     5e = 44

Divide both sides of the equation by 5:

                    e = 44/5 = 8.800

One solution was found :

e = 44/5 = 8.800

Answer:

e =44/5

Step-by-step explanation:

e          6

----- = --------

22         15

Using cross products

e * 15 = 6 *22

15e = 132

Divide by 15

15e/15 = 132/15

e =44/5

Answer:

3/56

Step-by-step explanation:

Probability is the ratio of the number of possible outcome to the number of total outcome.

Given that two marbles are drawn without replacement from a box with 1 blue, 3 white, 2 green, and 2 red marbles.

The total number of marbles in the box

= 1 + 3 + 2 + 2

= 8 marbles

The probability that the first marble is white and the second marble is blue

= 3/8 * 1/7

= 3/56

Answer:

10th term

Step-by-step explanation:

The equation of the arithmetic sequence is an=-7+(n-1)*1=-8+n, plugging in 2 and solving for n we have

2=-8+n, n=10

Answer:

73.5 Percent ...........

Answer:

The closest percentage of shots you made is 75%. Please mark brainliest.

I believe the choices are:

60%

70%

75%

80%

Therefore the answer 75%

Step-by-step explanation:

59/80 = 0.7375

Rounded up is 0.75

0.75 x 100 = 75%

Hope this helps.

Have a nice day amazing person there.

MAY GOD RICHLY BLESS YOU!!

Answer:

y = 1/3x - 7/3

Step-by-step explanation:

y2 - y1 / x2 - x1

-1 - (-3) / 4 - (-2)

2/6

= 1/3

y = 1/3x + b

-1 = 1/3(4) + b

-1 = 4/3 + b

-7/3 = b

Answer:

[tex] \frac{(3) ^{2} + 3}{3 - 1} [/tex]

[tex] \frac{9 + 3}{3 - 1} [/tex]

[tex] \frac{12}{2} [/tex]

= 6

9514 1404 393

Answer:

  (d)  360°

Step-by-step explanation:

The sum of exterior angles of any convex polygon is 360°.

Answer:

3 ways

Step-by-step explanation:

Answer:

-1.87 (B)

865.93 - [968-3.34(30)] = -1.87

ED2021

The average weekly allowance of a 5th grade student as calculated using direct variation with the information provided by Fidelity Investment Vision Magazine is 5.367 dollars per week.

The question given is a direct variation problem:

Let:

• Average weekly allowance = [tex]a[/tex]

• Grade level = [tex]g[/tex]

If Average weekly allowance varies directly as grade level , then , then the direct variation between the variables can be expressed as :

[tex]a = k * g[/tex]

Where ,  [tex]k[/tex] = constant of proportionality

We can obtain the value of k from the given values of a and g

[tex]9.66 = k * 9\\9.66 = 9k\\k = 9.66/9[/tex]

Our equation becomes:

[tex]a = (9.66/9) * g[/tex]

[tex]a = (9.66/9) * 5\\a = 5.367[/tex] (rounded to 3 decimal places)

Hence, using proportional relationship, the average weekly allowance for a 5th grade student is [tex]5.367[/tex] per week

Learn more about direct variation here:

https://brainly.com/question/17257139

Answer:

JK=12

KI=16

Step-by-step explanation:

[tex]K\in\ [JI]\ \Rightarrow\ |JK|+| KI |=|KI|\\\\x^2-4x+3x-2=28\\\\\Longleftrightarrow\ x^2-x-30=0\\\\\\\Longleftrightarrow\ x^2+5x-6x-30=0\\\\\\\Longleftrightarrow\ x(x+5)-6(x+5)=0\\\\\\\Longleftrightarrow\ (x+5)(x-6)=0\\\\x=-5\ (excluded)\ or\x=6\\\\\\\Longleftrightarrow\ \\|JK|=x^2-4x=6^2-4*6=36-24=12\\|KI|=3x-2=3*6-2=18-2=16\\\\Proof: 12+16=28\\[/tex]

9514 1404 393

Answer:

  4.18 square units

Step-by-step explanation:

The area is given by the formula ...

  A = 1/2bh

where b is the length of the base, and h is the perpendicular distance from the base to the opposite vertex.

  A = 1/2(2.2)(3.8) = 4.18 . . . square units

Hi ;-)

[tex]x=7 \ and \ y=3\\\\y-y:1+x=3-3:1+7=3-3+7=0+7=\boxed7[/tex]