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The functions f(x) and g(x) are described using the following equation and table:
f(x)=-4(1.09)x

Answer:

the answer is -299.808 well that's what I think it's

Answer:

-299.808

Step-by-step explanation:

= 10700/100 + 5192/100 - 412

= 107 + 5.192 - 412

= -299.808

Answer:

2nd option

Step-by-step explanation:

Given f(x) then f(x + a) is a horizontal translation of f(x)

• If a > 0 then a shift left of a units

• If a < 0 then a shift right of a units

Here g(x) = (x - 6)²

The base graph has been shifted right 6 units

Answer:

B

Step-by-step explanation:

x -> x and y -> y+5

-1 -> - 1 and - 3 -> 2, so b is the correct answer.

Answer:

she baked 3 times as many cranberry than blueberry muffins

Step-by-step explanation:

i think that because 9×3=27

the amount of the cranberry muffins are 9

Answer:

B. 4/5

Step-by-step explanation:

Sin = Opposite/Hypotenuse

Sin∠A = 8/10 = 4/5

Answer:

b) 6

Step-by-step explanation:

x - 4 = 2

x = 2 + 4

x = 6

Answer:

wyatt

Step-by-step explanation:

4:30 mins is 270 seconds

Answer:

it will take 5days to reach a total of 180meters

Step-by-step explanation:

80m+20+20+20+20+20

=180meters

=5days

Hi.

Let's call X number of visits.

so members pay for a year : membership 24 and reduce entrance at 3 dollars.

so you member pay : 3X+24

a non member pay entrance fee of 6 for each visit.

so 6X

Question : for how many visit would a membership will be more intresting than standar entrance ?

3X+24 = 6X

3X-6X = -24

-3X=-24

X= -24/-3

X =24/3

X= 8

Under 8 visit a year, it's cheaper non being a member.

at 8 entrance cost is the same for members and non member. After it better to choose membership as

9 entrances for member is : 3x9 +24 = 27+24= 51

non member : 9x6 = 54

And so on for each supplementary visits.

The depth of the mirror of the cross-section of a searchlight would be 8.33 cm if the light bub has a vertex at 3 cm and the mirror is 20 centimeters across at the origin.

A cross-section is perpendicular to the axis of the symmetry goes through the vertex of the parabola. The cross-sectional shape of the mirrored section of most searchlights or spotlights is parabolic.

Given:

a = 3

y = [tex]\frac{20}{2}[/tex] cm = 10 cm

Solution:

from the equation [tex]y^{2} = 4ax[/tex]

[tex]y^{2} = 4*3*x\\ y^{2} = 12x[/tex]

putting x, 10 cm in the equation

[tex]x=\frac{10^{2} }{12} \\\\x= \frac{100}{12} \\\\x= 8.33 cm[/tex]

thus, the depth of the mirror would be - 8.33 cm

Learn more about other problems of the parabola:

https://brainly.com/question/12793264

Answer:

The answer is 2.)

Step-by-step explanation:

Given initial velocity=135 ft/s

& cliff=76 foot

Given quadratic equation

⇒                      (let h=0 it is given)

⇒  

⇒  

⇒    t=8.96≈9 s (the other root is negative)

Hence, rocket will take 9 s to hit the ground after launched.

Answer:  Choice D

0 = 16t^2 + 135t + 76;  9 s

==============================================

Explanation:

The equation we start with is

[tex]h = -16t^2 + vt + c\\\\[/tex]

where v is the starting or initial velocity, and c is the starting height.

We're told that v = 135 and c = 76

We let h = 0 to indicate when the object hits the ground, aka the height is 0 ft.

That means the equation updates to [tex]0 = -16t^2 + 135t + 76\\\\[/tex]

Based on that alone, the answer is between A or D

-------------------

We'll use the quadratic formula to solve for t

We have

So,

[tex]t = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\\\\t = \frac{-135 \pm \sqrt{135^2 - 4(-16)(76)}}{2(-16)}\\\\t = \frac{-135 \pm \sqrt{23,089}}{-32}\\\\t \approx \frac{-135 \pm 151.9506}{-32}\\\\t \approx \frac{-135 + 151.9506}{-32} \ \text{ or } \ t \approx \frac{-135 - 151.9506}{-32}\\\\t \approx \frac{16.9506}{-32} \ \text{ or } \ t \approx \frac{-286.9506}{-32}\\\\t \approx -0.52971 \ \text{ or } \ t \approx 8.96721\\\\[/tex]

We ignore the negative t value because a negative time duration makes no sense.

The only practical solution here is roughly 8.96721 which rounds to 9.0 or simply 9 when we round to the nearest tenth (one decimal place).

In short, the object will hit the ground at the 9 second mark roughly. Or put another way: the object is in the air for about 9 seconds.

From this, we can see that the final answer is choice D.

Keep in mind that we aren't accounting for any wind resistance. Considering this variable greatly complicates the problem and requires much higher level mathematics. So we just assume that there is no wind at this moment.

Answer:

hope it helps

Step-by-step explanation:

Answer:

Step-by-step explanation:

S is the midpoint of QR.

⇒ RS = QS    

QR ⊥ PS

⇒ ∠RSP = ∠QSP = 90°

In ΔPSR & ΔPSQ,

Statement                     Reason

RS ≅ QS                       S is midpoint of QR

∠RSP ≅ ∠QSP              QR ⊥ PS

PS ≅ PS                         Reflexive property

ΔPSR ≅ ΔPSQ               Side Angle Side - S A S Congruent

PR≅  PQ                        CPCTC

Answer:

D

Step-by-step explanation:

I took the quiz

Refer the attached image for the answer

HOPE SO IT HELPS YOU

Answer:

-13 1/2 < -6/8

Step-by-step explanation:

*Any negative in either the numerator or denominator will make the entire fraction negative.

1/2  = .5

-13 1/2 = -13.5

-6/8 = -3/4

-3/4 = -0.75

-6/8 = -0.75

-13 1/2 = -13.5

Which means:

-13 1/2 < -6/8

Hope this helped.

Answer:

[tex] < [/tex]

Step-by-step explanation:

[tex] \frac{6}{8} [/tex]

Is close to 0 (to positive) you can use a time line to determine which is a correct answer

Answer:

Individual package would be 3.83

Hope this helps <3 Comment if you want more thanks and be sure to give brainliest (4 left) <3

Answer:

[tex]area \: of \: a \: squre = {a}^{2} \\ {a}^{2} = 176 \\ a = 13.26m \\ perimeter = 4a = 4 \times 13.26 = 53.04m^2 \\ thank \: you[/tex]

Answer:

Concept:

Here, we need to know how to find the area and perimeter of the square.

Area (square) = s²

Perimeter (square) = 4s

Solve:

Given information

Area = 1764 m²

Given formula

A = s²

Substitute values into the formula

1764 = s²

Square root both sides

√s² = √1764

[tex]\boxed{s=42m}[/tex]

--------------------------------------------------------------------------------------------------------

Given information

s = 42 m

Given formula

P = 4s

Substitute values into the formula

P = 4 (42)

Simplify by multiplication

[tex]\boxed{P=168m}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

c on edge

Step-by-step explanation:

Answer: the answer to your question is 7

Step-by-step explanation:

Answer:

8 hours 10 minutes

I hope this answers your question

Answer: paul has been away from home for 7 hours and 50 minutes.

Step-by-step explanation:

Answer:

[tex]we \: know \: that \: commutative \: prop \\ = x + y = y + x \\ then \\ 4xy + 0 = 0 + 4xy \\ thank \: you[/tex]

Answer:

c) 21

Step-by-step explanation:

[tex] \sqrt{169} + \sqrt{64} [/tex]

13+8

answer is 21

Answer:

It is 3/2, I got it right on my exam.

Step-by-step explanation:

Dilation is a transformation that allows you to resize an object. The dilation factor of the given point is 3/2.

Dilation is a transformation that allows you to resize an object. Dilation is a technique for making items bigger or smaller. This transformation yields a picture that is identical to the original shape. However, there is a size discrepancy in the form.

Given the dilation of the k around the origin as K = (2,4) → (3,6), therefore, the point k is dilated 1 unit to the right and 2 units upwards.

Let the dilation factor be represented by a, then,

2 × a = 3

a = 3/2

Similarly for the y-axis,

4 × a = 6

a = 6/4 = 3/2

Hence, the dilation factor of the given point is 3/2.

Learn more about Dilation:

https://brainly.com/question/13176891

#SPJ2

Answer:

x = - 1, x = - 0.5

Step-by-step explanation:

Given

2x(x + 1.5) = - 1 ← distribute parenthesis on left side

2x² + 3x = - 1 ( add 1 to both sides )

2x² + 3x + 1 = 0 ← in standard form

(2x + 1)(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 1 = 0 ⇒ x = - 1

2x + 1 = 0 ⇒ 2x = - 1 ⇒ x = - 0.5

Answer:

1.9

Step-by-step explanation:

You round when the numbers behind the decimal are 5 or greater. This being said, you need to round from the number furthest away from the decimal. In this case it would be 9. 9 is greater than 5 so we round 8 up to 9 and get rid of the number behind it. We are left with 1.9

Answer:  Choice A

y=2x+3; y=-1/3x+3

==================================================

Explanation:

The left portion of the blue curve is y = 2x+3 but it is only graphed when x < 0 (we could argue that [tex]x \le 0[/tex] but I'll set that aside for the other portion).

The right portion is the line y = -1/3x + 3 and it's only graphed when [tex]x \ge 0[/tex]

So we could have this piecewise function

[tex]f(x) = \begin{cases}2x+3 \ \text{ if } x < 0\\-\frac{1}{3}x+3 \ \text{ if } x \ge 0\\\end{cases}[/tex]

Or we could easily swap the "or equal to" portion to move to the first part instead like this

[tex]f(x) = \begin{cases}2x+3 \ \text{ if } x \le 0\\-\frac{1}{3}x+3 \ \text{ if } x > 0\\\end{cases}[/tex]

Either way, we're involving the equations mentioned in choice A

Answer:

The values of [tex]a[/tex] and [tex]b[/tex] are [tex]5[/tex] and [tex]-\frac{15}{7}[/tex], respectively.

Step-by-step explanation:

There are mistakes in the statement, correct form is presented below:

[tex]5+\frac{\sqrt{3}}{7} + 2\sqrt{3} = a - b\cdot \sqrt{3}[/tex].

By direct comparison we have the following system of equations:

[tex]a = 5[/tex] (1)

[tex]\frac{\sqrt{3}}{7}+2\sqrt{3} = -b\cdot \sqrt{3}[/tex] (2)

In (2) we solve for [tex]b[/tex]:

[tex]\left(\frac{1}{7}+2 \right)\cdot \sqrt{3} = -b\cdot \sqrt{3}[/tex]

[tex]b = -\frac{15}{7}[/tex]

The values of [tex]a[/tex] and [tex]b[/tex] are [tex]5[/tex] and [tex]-\frac{15}{7}[/tex], respectively.

Answer:

Step-by-step explanation:

Let the amount of gas in the tank before filling was x.

We have:

let the amount of gas be x

[tex]\\ \sf\longmapsto x+2\dfrac{4}{7}=4[/tex]

[tex]\\ \sf\longmapsto x+\dfrac{18}{7}=4[/tex]

[tex]\\ \sf\longmapsto x=4-\dfrac{18}{7}[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{28-18}{7}[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{10}{7}[/tex]

[tex]\\ \sf\longmapsto x=1\dfrac{3}{7}[/tex]